I need help with my homework I need help with number 1

Answer:

             287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

Answer: Final temperature for given mass of water is \(24.6^o C\).

Explanation:

Given: mass = 630.1 g, specific heat = 418 \(J/g^{o} C\), q = 950 J, T = \(24.2^o C\)

Formula used:  \(q = mC \Delta T\)

where, q = heat energy

            m = mass

            C = specific heat

            \(\Delta T\) = change in temperature = \((T_2 - T_1)\)

  950 J = \(630.1 g \times 4.18 J/g^o C \times (T_2 - 24.2^o)\)

          \(T_2 = 24.6^o C\)

Answer:

T2 = 24.56°C

Explanation:

Given data:

Mass of water = 630.1 g

Specific heat of water = 4.18 J/g.°C

Initial temperature = 24.2°C

Heat absorbed = 950 J

Final temperature = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values

950 J = 630.1 g × 4.18 J/g.°C ×  (T2 - 24.2°C)

950 J = 2633.82 j/°C ×  (T2 - 24.2°C)

950 J / 2633.82 j/°C =  (T2 - 24.2°C)

0.36°C  + 24.2°C = T2

T2 = 24.56°C

At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.

If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.

When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.

If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.

Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.

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Answer:

Preventing erosion – Land Reclamation

Protecting nesting areas – Protecting Biodiversity

Preventing littering – Land Reclamation

Preventing habitat disruption – Protecting Biodiversity

Protecting native species – Protecting Biodiversity

Preventing contamination of soil – Land Reclamation

Explanation:

I really hope I'm right! I tried my hardest, please give me brainliest :)

have a good day!

Answer:

1. D excess fertilizer use

2.A cutting down trees

3.D bacterial

Hydronium ion concentration, [H3O+], in a solution of pH = 1.76 is

[H3O+] = 0.01737800828M = 0.02M

pH is calculated using the expression :

\(Therefore : H_3O^+=10^(-pH)\)

\(Thus, H_3O^+=10^(-1.76) = 0.02M\)

Therefore, there are 0.02 moles of hydronium (H3O+ ) ions present in each liter of the solution.

Or, the concentration of the solution is about 0.02 M.

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Answer:

\(V=0.200L\)

Explanation:

Hello,

In this case, since the volumetric capacity of the beaker is 200 cm³, by considering that 1000 cm³ equals 1 L, the liters are then computed via the following unit conversion:

\(V=200cm^3*\frac{1L}{1000cm^3}\\ \\V=0.200L\)

Best regards.

In order to prepare the solution required by this question, we would employ the use of 375mg of protein.

Here we are given the ratio of protein to solution that we wish to achieve. Said ratio is 15mg/ml. This means that there should be 15mg of protein for every ml of solution. Since we have 25ml of the solution, we can multiply these values to reach our answer of 375mg of protein.

Therefore, we can confirm that In order to prepare the solution required by this question, we would employ the use of 375mg of protein.

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The value that is going to show us that there a large amount of B at equilibrium is 9×105 and 5000.

The term reversible reaction is a reaction that could go in either direction. This implies that the reaction could go either in the forward or in the reverse direction as we can see from the equation that we have in the question above.

If the reaction is such that does go in a reversible manner, we know that there would be more B if the equilibrium constant is high and this means that the value that would give a level of B is 9×105 and 5000. This is because these values are large and positive and show a complete conversion of reactants to products.

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Answer: metal turn orange and weaker as it gets oxidised

Explanation:

Answer:

The Humboldt Current or the peru current

Explanation:

This is an example of a double displacement reaction where chloride ions replace sulphate ions and vice versa.

When a portion of two ionic compounds is swapped, a double displacement reaction takes place, creating two new components. In aqueous solutions, where ions precipitate and exchange occurs, double displacement processes are most common.

For instance, a white precipitate of barium sulphate quickly forms when a solution of barium chloride and sodium sulphate are combined. These are ionic-based reactions. When the reactants are dissolved in water, they turn into ions, and when ions exchange in the solution, a product molecule is created.

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Answer:

71.5g

Explanation:

The reaction equation is given as:

               C  +  O₂  →  CO₂

Mass of C = 42g

Mass of O₂  = 52g

Unknown:

Mass of CO₂ produced  = ?

Solution

Now to solve this problem, we have to find limiting reactant which is the one given in short supply in this reaction.

 The extent of the reaction is controlled by this reactant.

Find the number of moles of the given species;

 Number of moles  = \(\frac{mass}{molar mass}\)

      Number of moles of C  = \(\frac{42}{12}\)   = 3.5mol

     Number of moles of O₂   = \(\frac{52}{32}\)   = 1.63mol

Now;

   From the balanced reaction equation;

           1 mole of C reacted with 1 mole of O₂

We see that C is in excess and O₂ is the limiting reactant.

            1 mole of O₂ will produce 1 mole of CO₂

 So;      1.63mole of O₂ will produce 1.63 mole of CO₂

Mass of CO₂ = number of moles x molar mass

       Molar mass of CO₂ = 44g/mol

Mass of CO₂ = 1.63 x 44 = 71.5g

Answer:

English Language Learners Definition of number. (Entry 1 of 2) : a word or symbol (such as "five" or "16") that represents a specific amount or quantity. : a number or a set of numbers and other symbols that is used to identify a person or thing.

Explanation:

79 is the number of protons gold has.

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The number of mole of carbon dioxide, CO₂, produced from the reaction is 26 moles

The balanced equation for the reaction is given below:

2C₄H₁₀(g) + 13O₂(g) → 8CO₂(g) + 10H₂O(l)

From the balanced equation above,

2 moles of C₄H₁₀ reacted to produce 8 moles of CO₂

From the question given, we can see that O₂ is the excess reactant.

Thus, we can determine the number of moles of CO₂ produced from the reaction of 6.5 moles of C₄H₁₀ with excess O₂ by doing the following:

From the balanced equation above,

2 moles of C₄H₁₀ reacted to produce 8 moles of CO₂

Therefore,

6.5 moles of C₄H₁₀ will react to produce = (6.5 × 8) / 2 = 26 moles of CO₂

Thus, the number of moles of CO₂ produced from the reaction is 26 moles

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Answer:1950-200

Explanation:

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

The whole number of people or inhabitants in a country or region.

The world's population increased from 2.5 billion in 1950 to around 7.3 billion in 2015 and is expected to continue to rise until 2050/2100 under most UN.

During 1950-2000​ of the following 50-year intervals has the world's population increased the most. Hence, option D is correct.

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By dissolving 44.2 mg of aspirin in 0.358 L of water at 25 °C, an osmotic pressure of 0.00578 atm is created.

When aspirin is dissolved in water, osmotic pressure ( π ) = iMRT

Where,

Molar mass of aspirin (C9H8O4) = 180.16 g/mol

44.2 mg = 0.0442 g

Moles of aspirin = 0.0442 g / 180.16 g/mol

= 0.000245 moles

Molarity of aspirin solution

= moles / volume = 0.000245 moles / 0.358 L

= 0.000685 M

π = iMRT  {on equating both the equations}

= (1)(0.000685 M)(0.08206 L·atm/(mol·K))(25 + 273.15 K)

= 0.00578 atm

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Answer: 682 grams

Explanation:

The balanced chemical reaction is:

\(4Fe+3O_2\rightarrow 2Fe_2O_3\)

\(O_2\) is the limiting reagent as it limits the formation of product and \(Fe\) is the excess reagent.

According to stoichiometry :

3 moles of \(O_2\) produce = 2 moles of \(Fe_2O_3\)

Thus 6.40 moles of \(O_2\) will produce=\(\frac{2}{3}\times 6.40=4.27moles\)  of \(Fe_2O_3\)

Mass of \(Fe_2O_3=moles\times {\text {Molar mass}}=4.27moles\times 159.69g/mol=682g\)

Thus 682 g of \(Fe_2O_3\) will be produced from 6.40 moles of oxygen

H2SO4(aq)+NaOH(s)----->NA2SO4 + H20

When acid and base reaction takes place, it will form salt formation takes place. I.e., neutralization reaction. H₂SO₄+2NaOH→ Na₂SO₄+ 2H₂O.

A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products.

H₂SO₄ is an acid and NaOH is a base. Acid react with base to form salt and water. Salt will be neutral charge and net ionic charge is zero.

Neutralization takes place when, complete dissociation takes place. If any partial dissociation, it will form acidic salt or neutral salt.

Thus complete dissociation neutral reaction is

H₂SO₄+2NaOH→ Na₂SO₄+ 2H₂O.

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Before administering eye drops, make sure to wash your hands thoroughly with soap and water to minimize the risk of introducing any contaminants.

Tilting your head back or lying down can help create a better angle for administering the eye drops and prevent them from running out of your eye.

Use your index finger to gently pull down the lower eyelid, creating a small pocket.

Carefully hold the dropper tip close to your eye, without touching your eye or eyelashes.

Follow the specific instructions provided with your eye drops to determine the appropriate number of drops to use. Squeeze the dropper to release the drops into the pocket created by pulling down your lower eyelid.

If any excess solution has spilled onto your skin, gently wipe it away with a clean tissue or cloth to avoid irritation.

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Simply multiplying the oxygen molar mass by two yields the molar mass of oxygen gas.

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Answer:

The maximum mass of carbon dioxide, CO₂ produced is 2.64 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

Next, we shall determine the masses of C₈H₁₈ and O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₈H₁₈ = (8×12) + (18×1)

= 96 + 18

= 114 g/mol

Mass of C₈H₁₈ from the balanced equation = 2 × 114 = 228 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 25 × 32 = 800 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 16 × 44 = 704 g

SUMMARY:

From the balanced equation above,

228 g of C₈H₁₈ reacted with 800 g of O₂ to produce 704 g of CO₂.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

228 g of C₈H₁₈ reacted with 800 g of O₂.

Therefore, 3.43 g of C₈H₁₈ will react with = (3.43 × 800)/228 = 12.04 of O₂

From the calculations made above, we can see that a higher mass (i.e 12.04 g) of O₂ than what was given (i.e 3 g) is needed to react completely with 3.43 g of C₈H₁₈. Therefore, O₂ is the limiting reactant and C₈H₁₈ is the excess reactant.

Finally, we shall determine the maximum mass of carbon dioxide, CO₂ produced from the reaction.

To obtain the maximum mass of carbon dioxide, CO₂ produced, the limiting reactant will be used because all of it is consumed in the reaction.

The limiting reactant is O₂ and the maximum mass of carbon dioxide, CO₂ produced can be obtained as follow:

From the balanced equation above,

800 g of O₂ reacted to produce 704 g of CO₂.

Therefore, 3 g of O₂ will react to produce = (3 × 704)/800 = 2.64 g of CO₂.

Thus, the maximum mass of carbon dioxide, CO₂ produced is 2.64 g

Answer:

letter: B

Explanation:

thats is the true answer.

pleas heart my heart my answer

The oxidation and reduction half reactions are

Mg(s) → Mg²⁺(aq) + 2e⁻

and

Ni²⁺(aq) + 2e⁻ → Ni(s)

respectively

From the question, we are to write the half reactions for the oxidation and reduction taking place

The given reaction is

Mg(s) + NiSO₄(aq) → MgSO₄(aq) + Ni(s)

To write the oxidation and reduction half reactions, first we will write the ionic equation for the reaction.

The ionic equation for the reaction is

Mg(s) + Ni²⁺(aq) → Mg²⁺(aq) + Ni(s)

Recall:

Oxidation is the loss of electron(s) while reduction is the gain of electron(s)

Therefore,

The oxidation half reaction is

Mg(s) → Mg²⁺(aq) + 2e⁻

and the reduction half reaction is

Ni²⁺(aq) + 2e⁻ → Ni(s)

Hence, the oxidation and reduction half reactions are

Mg(s) → Mg²⁺(aq) + 2e⁻

and

Ni²⁺(aq) + 2e⁻ → Ni(s)

respectively.

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Answer:

80.5%

Explanation:

The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.

To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.

(Steps 1 - 3)

Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)

Molar Mass (C₃H₈): 44.11 g/mol

Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)

Molar Mass (CO₂): 44.01 g/mol

1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O

296 g C₃H₈           1 mole            3 moles CO₂           44.01 g
-------------------  x  ----------------  x  ----------------------  x  ----------------  =  886 g CO₂
                               44.11 g            1 mole C₃H₈            1 mole

(Step 4)

                                  Actual Yield
Percent Yield  =  ------------------------------  x  100%
                              Theoretical Yield

                                713 g CO₂
Percent Yield  =  ----------------------  x  100%
                                886 g CO₂

Percent Yield  =  80.5%

Answer:

Rank from lowest to highest - c<a<d<b

Explanation:

Molarity is basically the moles of the solute dissolved in a solvent. Molar mass of NaOH = 39.997 g/mol

a) 6.625 g NaOH dissolved in 250. mL of water

Molarity = 6.625 grams */( 0.250 *39.997) g/mol = 0.66

b) 63.0 g of NaOH dissolved in 1.00 L of water

Molarity = 63 grams */( 1 *39.997) g/mol = 1.575

c) 8.00 g of NaOH dissolved in 500. mL of water

Molarity = 8 grams */( 0.5 *39.997) g/mol = 0.331

d) 0.0530 of NaOH in 100 mL of water = 0.53

Rank from lowest to highest - c<a<d<b

A sample of the male sex hormone testosterone C₁₉H₂₈O₂, contains 3.58 × 10²¹ atoms of hydrogen. It contain 2.42 × 10²¹ carbon atoms.

To find the number of moles use this formula

Number of moles = Number of atoms / Avogadro's Number

Here,

Number of atoms = 3.58 × 10²¹

Avogadro's Number = 6.022 × 10²³

Now, put the values in above formula we get

Number of moles = Number of atoms / Avogadro's Number

                             =  3.58 × 10²¹ / 6.022 × 10²³

                             = 5.94 × 10⁻³

1 mol testosterone C₁₉H₂₈O₂ contains 28 mole of hydrogen atoms

Now, 5.94 × 10⁻³ moles contains = (1/28) × 5.94 × 10⁻³

                                                      = 2.12 × 10⁻⁴ mol

To find the number of atoms use this formula

Number of atoms = Number of moles × Avogadro's Number

Here,

1 mol testosterone C₁₉H₂₈O₂ contains 19 mole of carbon atoms

Number of moles = 19 moles

Avogadro's Number = 6.022 × 10²³

Now put the value in above formula we get

Number of atoms = Number of moles × Avogadro's Number

                              = 19 ×  6.022 × 10²³

                              = 1.14 × 10²⁵

Now the no. of C-atoms =  1.14 × 10²⁵ × 2.12 × 10⁻⁴ mol

                                        = 2.42 × 10²¹ carbon atoms.

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Note: The given question is incomplete on the portal here is the complete question.

Question: A sample of the male sex hormone testosterone C₁₉H₂₈O₂, contains 3.58 × 10²¹ atoms of hydrogen. How many carbon atoms does it contain ?

Answer:

1a. 0.89 gcm¯³

1b. Yes.

1c. Tetrahydrofuran.

2. 0.54 g/mL

Explanation:

1. Data obtained from the question include:

Volume = 0.988 L = 988 cm³

Mass = 879 g

1a. Determination of the density

Density = mass /volume

Density = 879/ 988

Density = 0.89 gcm¯³

Therefore, the density of the liquid is 0.89 gcm¯³

1b. From the given data, it is possible to determine the identity of the liquid.

1c. The density of the liquid is 0.89 gcm¯³. Comparing the density of the liquid obtained with those given in the table, the liquid is tetrahydrofuran

2. Data obtained from the question include:

Mass of empty cylinder = 5.25 g

Mass of cylinder and sodium thiosulfate = 75.82 g

Volume = 130.63 mL

Next, we shall determine the mass of sodium thiosulfate. This can be obtain as follow:

Mass of empty cylinder = 5.25 g

Mass of cylinder and sodium thiosulfate = 75.82 g

Mass of sodium thiosulfate =.?

Mass of sodium thiosulfate = Mass of cylinder and sodium thiosulfate – Mass of empty cylinder

Mass of sodium thiosulfate = 75.82 – 5.25

Mass of sodium thiosulfate = 70.57 g

Finally, we shall determine the concentration of the sodium thiosulfate as follow:

Mass = 70.57 g

Volume = 130.63 mL

Concentration =?

Concentration = mass /volume

Concentration = 70.57/130.63

Concentration = 0.54 g/mL

The concentration of the solution is 0.54 g/mL