I need help with four answers! Will mark brainliest : )!
Q.1:Which symbol replaces the box to make the statement true?

4⋅16−16□4⋅[24−2⋅(4+8)]



Q.2: Which expression has a value less than the given expression when x = 5?

3x + 15
-----------------------------------
Answers options:
2x²

x² + 5

3(x + 5)

4x + 5
Q.3:Let m = 4 and n = 5.

Select from the drop-down menu to create a true statement.

4m+4n ​ = 2m2+
----------------------------
Answer options:
M
N
MN 2
Q.4: Which expression completes the statement to form a true equation?

28–3+2=
----------------------------------------------------
Answer options:
3³

5(4 + 2)

3² + 19

44–24

According to the information we can infer that the total yardage traveled from 0 to 120 seconds is 140 yards.

To calculate the total yardage traveled we have to consider the movement of the O'Connor Panthers. In this case we have to consider that the movement in the y axis.

In this case we can conclude that the total yardage traveled was 140 yards because:

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Answer:

Emma types at a rate of 45 words per minute.

Step-by-step explanation:

I know this because if you divide 90/2 you can get 45 because as you see on the graph, every two minutes is 90 words, so just divide 90/2.

A. The distributions of the periods is that using the five number summary is that

B. The box and whisker plot of the periods is attached

From the question, we have the following parameters that can be used in our computation:

7th Period

66, 72, 77, 78, 78, 80, 82, 84, 84, 87, 88, 88, 89, 89, 90 92, 92, 93, 94, 94 96, 96

3rd Period

52, 60, 62, 64, 64, 65, 68, 71, 72, 74, 75, 76, 78, 79, 83, 84, 85, 88, 89, 93, 94, 97

The distributions of the periods will be compared using the five-number summaries

Using a graphing tool, the five-number summaries are:

7th Period

3rd Period

The box and whisker plot of the periods is added as an attachment

From the box and whisker plot attached, we can see the five-number summaries of the periods

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Answer:

in a region with a letter.

Step-by-step explanation:

All the letters are in the circle, so if a point is in the circle, it will be in a region with a letter.

The value of f(3) in the given function f(x) = x² + 2 is 11.

The function is defined as a mathematical expression that defines a relationship between one variable and another variable.

The given function f(x) = x² + 2 is defined for all real numbers x greater than zero.

To determine the value of f(3), substitute x=3 into the given function.

f(3) = 3² + 2

f(3) = 9 + 2

Apply the addition operation, and we get

f(3) = 11

Therefore, the value of f(3) in the function f(x) = x² + 2 is 11.

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The complete question is below.

What is the value of f(3) in the function below? explain

f(x) = x² + 2, x∈R, x>0

Answer:

$52

Step-by-step explanation:

first you find out what 60% of 130. all you need to do is put a decimal before the percent and multiply it with the cost, in this case 0.6 x 130, which results in 78. next you subtract the percentage result from the total cost to get your answer of $52.

The length of the rectangle is twice its width. If its perimeter is 7 1/3 cm, its length will be 22/9 cm, and the width is 11/9 cm.

Let's assume the width of the rectangle is "b" cm.

According to the given information, the length of the rectangle is twice its width, so the length would be "2b" cm.

The formula for the perimeter of a rectangle is given by:

Perimeter = 2 * (length + width)

Substituting the given perimeter value, we have:

7 1/3 cm = 2 * (2b + b)

To simplify the calculation, let's convert 7 1/3 to an improper fraction:

7 1/3 = (3*7 + 1)/3 = 22/3

Rewriting the equation:

22/3 = 2 * (3b)

Simplifying further:

22/3 = 6b

To solve for "b," we can divide both sides by 6:

b = (22/3) / 6 = 22/18 = 11/9 cm

Therefore, the width of the rectangle is 11/9 cm.

To find the length, we can substitute the width back into the equation:

Length = 2b = 2 * (11/9) = 22/9 cm

So, the length of the rectangle is 22/9 cm, and the width is 11/9 cm.

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We are given the expression B=3Mn/2 and told to express M in terms of B and n. This means that we should apply mathematical operations on both sides of the equation so we "isolate " M on one side of the equality sign. We begin with the given equation

First, we multiply both sides by 2, so we get

Next, we divide by 3 on both sides, so we get

Finally, we divide both sides by n, so we get

In this case, we have succesfully expressed M in terms of B and n

Answer:

n = 9 is the answer.

Step-by-step explanation:

Given a Triangle \(\triangle KLM\) with its perpendicular bisectors intersecting at a point A.

AK = 25 units and

AM = 3n -2

To find:

Value of n = ?

Solution:

First of all, let us learn about perpendicular bisectors and their intersection points.

Perpendicular bisector of a line PQ is the line which divides the line PQ into two equal halves and is makes an angle of \(\bold{90^\circ}\) with the line PQ.

And in a triangle, the perpendicular bisectors of 3 sides meet at one point and that point is called Circumcenter of the triangle.

We can draw a circle from circumcenter so that the circle passes from the three vertices of the triangle.

i.e.

Circumcenter of a triangle is equidistant from all the three vertices of the triangle.

In the given statement, we are given that A is the circumcenter of the \(\triangle KLM\).

Please refer to the attached image for the given triangle and sides.

The distance of A from all the three vertices will be same.

i.e. AK = AM

\(\Rightarrow 25 = 3n-2\\\Rightarrow 3n =25+2\\\Rightarrow 3n =27\\\Rightarrow \bold{n = 9}\)

Therefore, n = 9 is the answer.

Answer:

\(132cm^{3}\)

Step-by-step explanation:

The volume formula for a rectanglur prism is V = lwh where l is the length, w is the width, and h is the height.

In this image the length is 11 cm so l = 11. The width is 4 cm so w = 4. The height is 3 cm so h = 3.

Plugging these values into the formula gives the equation to solve which is V = 11 x 4 x 3.

When simplified through multiplication the product of the final equation is V = 132 so the answer is \(132cm^{3}\).

Answer:

Step-by-step explanation:

Hello,

qop(2)=q(p(2))

p(2) = 4+3=7

\(q(7) = \sqrt{7+2}=\sqrt{9}=3\)

so

qop(2)=3

and poq(2)=p(q(2))

\(q(2)=\sqrt{2+2} = \sqrt{4}=2\)

p(2) = 7

so poq(2)=7

thanks

The answer is "\(\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}\)" and the further explanation can be defined as follows;

Given:

\(\to \bold{p(x)=x^2+3}\\\\\to \bold{q(x)=\sqrt{x+2}}\)

Find:

\(\bold{(q \circ p)(2)=?}\\\\\bold{(p \circ q)(2)=?}\)

Solve the value for \(\bold{(q \circ p)(2)}\\\\\):

\(\to \bold{(q \circ p)(2)= q \circ p(2) =q(p(2))}\\\\\)

\(\therefore\\\\ \to \bold{p(2)=2^2+3= 4+3=7}\\\\\ \because \\\\ \to \bold{q(p(2))=\sqrt{7+2}=\sqrt{9}=3}\)

Solve the value for \(\bold{(p \circ q)(2)}\\\\\):

\(\to \bold{(p \circ q)(2)= p \circ q(2)= p (q(2))}\\\\\)

\(\therefore\\\\ \to \bold{q(2)=\sqrt{2+2}=\sqrt{4}=2}\\\\\ \because \\\\ \to \bold{p(q(2))=2^2+3= 4+3=7}\)

Therefore the final answer of "\(\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}\)"

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Answer:

Step-by-step explanation:

There are several things we need to know to solve this: the perimeter formula of a rectangle, the area formula of a rectangle, and how to complete the square to find the answer. First of all, if the farmer has 148 feet of fencing to enclose 3 sides of a rectangle, the perimeter formula we need will include only 3 sides, the 2 widths and the 1 length:

P = 2w + l; solving for l and filling in our length of fencing gives us:

l = 148 - 2w

The area then for this will be:

A = (148 - 2w)(w) which is the same thing as length times width (area for a rectangle). Multiplying that out gives us:

\(A=148w-2w^2\). Let's rearrange that and put it into descending order so we can complete the square on it:

\(A=-2w^2+148w\)

The reason we want to complete the square is because the answer that results from that will give us the dimensions of the rectangle (the width and the length) and also the area. Completing the square maximizes (or minimizes) area.

To complete the square, first factor out the -2 since the leading coefficient when you complete the square has to be a +1. When we do that we get:

\(A=-2(w^2-74w)\). Set it equal to 0 so we can factor it:

\(-2(w^2-74w)=0\)

The idea now is to take half the linear term (the term stuck to the w), divide it in half, then square that number. Our linear term is 74. Half of 74 is 37, and 37 squared is 1369. So we add 1369 to both sides, the left side first:

\(-2(w^2-74w+1369)=...\)

But we didn't just add in 1369. There's a -2 out front there that refuses to be ignored. It's a multiplier. What we ACTUALLY added in was -2 times 1369 which is -2738; therefore:

\(-2(w^w-74w+1369)=-2738\)

The left side can be simplified down to a perfect square binomial:

\(-2(w-37)^2=-2738\)

Now we'll add over the -2738:

\(-2(w-37)^2+2738=y\) and from there determine our answer. The (w-37) term is the width of the rectangle; therefore, the length is 148 - 2(37) which is 74; the total area if the 2738. Completing the square gives us the vertex form of the parabola; the vertex is (37, 2738) where 37 is the width of the rectangle and 2738 is the max area.

Expanding the desired form, we have

\(A \sin(\omega t + \phi) = A \bigg(\sin(\omega t) \cos(\phi) + \cos(\omega t) \sin(\phi)\bigg)\)

and matching it up with the given expression, we see that

\(\begin{cases} A \sin(\omega t) \cos(\phi) = 2 \sin(4\pi t) \\ A \cos(\omega t) \sin(\phi) = 5 \cos(4\pi t) \end{cases}\)

A natural choice for one of the symbols is \(\omega = 4\pi\). Then

\(\begin{cases} A \cos(\phi) = 2 \\ A \sin(\phi) = 5 \end{cases}\)

Use the Pythagorean identity to eliminate \(\phi\).

\((A\cos(\phi))^2 + (A\sin(\phi))^2 = A^2 \cos^2(\phi) + A^2 \sin^2(\phi) = A^2 (\cos^2(\phi) + \sin^2(\phi)) = A^2\)

so that

\(A^2 = 2^2 + 5^2 = 29 \implies A = \pm\sqrt{29}\)

Use the definition of tangent to eliminate \(A\).

\(\tan(\phi) = \dfrac{\sin(\phi)}{\cos(\phi)} = \dfrac{A\sin(\phi)}{\cos(\phi)}\)

so that

\(\tan(\phi) = \dfrac52 \implies \phi = \tan^{-1}\left(\dfrac52\right)\)

We end up with

\(y(t) = 2 \sin(4\pi t) + 5 \cos(4\pi t) = \boxed{\pm\sqrt{29} \sin\left(4\pi t + \tan^{-1}\left(\dfrac52\right)\right)}\)

where

• amplitude:

\(|A| = \boxed{\sqrt{29}}\)

• angular frequency:

\(\boxed{4\pi}\)

• phase shift:

\(4\pi t + \tan^{-1}\left(\dfrac 52\right) = 4\pi \left(t + \boxed{\frac1{4\pi} \tan^{-1}\left(\frac52\right)}\,\right)\)

The required length of the base of the triangular pane of glass is 22 inches.

We know that the formula for the area of a triangle is:

Area = 1/2 * base * height

We are given that the height of the triangular pane of glass is 32 inches and the area is 352 square inches. Substituting these values into the formula, we get:

352 = 1/2 * base * 32

Multiplying both sides by 2 and dividing by 32, we get:

base = 22

Therefore, the length of the base of the triangular pane of glass is 22 inches.

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Answer: A

because slope are

The function is an exponential growth function

The function is given as

y=2(1.06)^9

We can begin by rewriting the given equation as:

y = 2 * 1.06t

So, we have

y = 2 * (1 + 0.06)^t

Now we can see that the equation is in the form y = a*b^t,

where a = 2 and b = 1.06^9

This equation represents exponential growth because the base of the exponent, b = 1.06, is greater than 1.

We can re-write it in the form y = a(1+r)t,

we can find the value of r by subtracting 1 from 1.06 which is 0.06 and the value of a is 2.

so we have y = 2(1+0.06)^t

So, the equation represents exponential growth with a = 2 and r = 0.06

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Step-by-step explanation:

f(x) = 3√x /4

x=0 => y = 0

x=1 => y = 0.75

x=4 => y = 1.5 ==> (4, 1.5)

x=16=>y= 3

the right answer is the second graph

Answer:

i think 80

Step-by-step explanation:

Answer: the value of y is 1

Step-by-step explanation: 6=2 x 1+2

Answer:

14

Step-by-step explanation:

Slope of BC = AB/AC, and Slope of EF = DE/DF

BC and EF both lie on the same line t, therefore the slope of BC equals the slope of EF.

Similar triangles are two triangles having the same shape but different sizes, however, the ratio of their corresponding sides are equal.

Given:

ΔABC ~ ΔDEF

Slope of BC = AB/AC

Slope of EF = DE/DF

BC and EF both lie on the same line t, therefore the slope of BC equals the slope of EF.

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Answer:

this list

Step-by-step explanation:

1×12000=12000

2×6000=12000

3×4000=12000

4×3000=12000

5×2400=12000

6×2000=12000

8×1500=12000

10 ×1200=12000

12 ×1000=12000

By solving a linear equation for the concentration we will see that the guy needs to use 18 ounces.

We know that the guy used 10 ounces of 6% solution with x ounces of a 12% solution to make a 8% solution, then we can write the concentration equation:

0.06*12 + 0.12*x = (12 + x)*0.08

So we just need to solve a linear equation for x.

0.06*12 + 0.12*x = (12 + x)*0.08

0.06*12 + 0.12*x = 12*0.08 + x*0.08

0.12*x - 0.08*x = 12*0.08 - 0.06*12

0.04*x = 0.06*12

x = 0.06*12/0.04 = 18

Which means that the guy needs to use 18 ounces of the 12% substance.

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Answer:

the difference of m and 5 is graeter than 10

Answer:

0.4

0.004

0.04

4

Step-by-step explanation:

Answer:

the 1st one is 40

the 2nd on is 1/4

the 3rd one is 4

the 4th one is 4

Step-by-step explanation:

the 1st one is 40

the 2nd on is 1/4

the 3rd one is 4

the 4th one is 4

don't completly trust me but this is what know!!

Answer:

15/14 or 1 1/14

Step-by-step explanation:

3/7* 2 1/2

3/7*5/2

15/14

1 1/14

The park's attendance on the 30th day of June will be significantly higher than on the 31st day of August.

The amusement park in question has a starting attendance of 2000 guests on the first day of both June and August.

The park's attendance in June increases by 10% each day, while its attendance in August decreases by 10% each day.

The rate of change of the attendance in June and August can be calculated as follows:

Let's assume the attendance on the first day in June is equal to A.

Therefore, the attendance in June can be calculated as follows: On the 2nd day, the attendance would be 1.1A.

On the 3rd day, the attendance would be 1.1 × 1.1A = 1.21A

On the 4th day, the attendance would be 1.1 × 1.1 × 1.1A = 1.331A

And so on, until the 30th day of June.A = 2000

Therefore, on the 30th day of June, the attendance will be equal to:

Attendance on the 30th day = 2000 × 1.1^29 = 20,062.46 guests (rounded to the nearest whole number)

The attendance in August can be calculated in the same way, except that the rate of change will be negative (i.e., a decrease of 10% per day):

Attendance on the 2nd day = 0.9A

Attendance on the 3rd day = 0.9 × 0.9A = 0.81A

Attendance on the 4th day = 0.9 × 0.9 × 0.9A = 0.729A

And so on, until the 31st day of August.A = 2000

Therefore, on the 31st day of August, the attendance will be equal to: Attendance on the 31st day = 2000 × 0.9^30 = 49.28 guests (rounded to the nearest whole number)

Therefore, the park's attendance on the 30th day of June will be significantly higher than on the 31st day of August.

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By using the table of values, a graph of the exponential function is shown in the image below.

In Mathematics and Geometry, an exponential function can be modeled by using this mathematical equation:

\(f(x) = a(b)^x\)

Where:

Based on the information provided above, we can logically deduce the following exponential function;

\(y = 2^x\)

Next, we would create a table of values based on the exponential function;

when x = 0, the y-value is given by;

y = 2⁰

y = 1

when x = 1, the y-value is given by;

y = 2¹

y = 2

x                     y____

-2                 0.25

-1                  0.5

0                   1

1                    2

2                   4

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The number of small rooms reserved is 4.

The number of large rooms reserved is 8.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

Small rooms are denoted as S.

Large rooms are denoted as L.

Now,

We will make two equations.
L = 2S _____(1)

8L + 6S = 88 ______(2)

Putting (1) in (2) we get,

8L + 6S = 88

8 x (2S) + 6S = 88

16S + 6S = 88

22S = 88

S = 88/22

S = 8/2

S = 4

Now,

Putting S = 4 in (1) we get,

L = 2 x 4

L = 8

Thus,

The number of small rooms and large rooms reserved is 4 and 8.

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