I need help quick I’ll give brainliest

Answer:

The probability of picking an orange is 8/18, or 4/9.

8/18 of the fruits are oranges, so 10/18 of the fruits are not oranges. The complement of picking an orange is 10/18 or 5/9.

Step-by-step explanation:

There are 4 apples, 6 pears, and 8 oranges. That adds up to 18 fruits. 8 of those are oranges, so the probability of picking an orange is 8/18, or 4/9 simplified.

The complement means all outcomes that are NOT the favorable outcome, or in this case, all outcomes that are not oranges. There are 8 oranges out of 18, so there are 10 fruits that are not oranges. This makes the complement 10/18, or 5/9 simplified.

Answ2/6 or 33% chance of getting an apple, 3/24 or 13% of getting a pear and 13/24 or 54% chance of getting an orange hope that helps.er:

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Hope this Helped! Please tell me if I'm wrong!

Answer:A

Step-by-step explanation:

Answer:

point-slope form, standard form, and slope-intercept form

Step-by-step explanation:

The three main types of linear functions are: point-slope form, standard form, and slope-intercept form.

Here is an image with each form

Answer:

x=9

Step-by-step explanation:

Answer:

C and E

Hope this help!

The ratio [CH3CO2H]/[CH3CO2-] in the buffer solution is approximately 2.70 x 10^-3, or you can also write it as 1:370.

To calculate the ratio of the concentration of acetic acid (CH3CO2H) to sodium acetate (CH3CO2-) in the buffer solution, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

Where:
pH is the given pH of the buffer solution, which is 5.05.
pKa is the negative logarithm of the acid dissociation constant, Ka, which is given as 1.80 x 10^-5 for acetic acid (CH3CO2H).
[A-] is the concentration of the conjugate base (CH3CO2-), which is the sodium acetate.
[HA] is the concentration of the acid (CH3CO2H), which is the acetic acid.

Let's plug in the values into the equation and solve for the ratio [HA]/[A-].

5.05 = -log(1.80 x 10^-5) + log([A-]/[HA])

Next, rearrange the equation to solve for the ratio [A-]/[HA]:

log([A-]/[HA]) = 5.05 + log(1.80 x 10^-5)

Now, we need to convert the logarithmic expression back into exponential form:

[A-]/[HA] = 10^(5.05 + log(1.80 x 10^-5))

Simplifying the right side of the equation:

[A-]/[HA] = 10^5.05 * 10^(log(1.80 x 10^-5))

Using the property of logarithms (log(a) + log(b) = log(ab)):

[A-]/[HA] = 10^5.05 * 1.80 x 10^-5

[A-]/[HA] = 150 * 1.80 x 10^-5

[A-]/[HA] = 2.70 x 10^-3

Therefore, the ratio [CH3CO2H]/[CH3CO2-] in the buffer solution is approximately 2.70 x 10^-3, or you can also write it as 1:370.

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The ratio of the concentration of CH₃CO₂H to CH₃CO₂⁻ in the buffer is approximately 2.03.

The ratio of the concentration of acetic acid (CH₃CO₂H) to sodium acetate (CH₃CO₂⁻) in the buffer can be determined using the Henderson-Hasselbalch equation:

pH = pKa + log ([A-]/[HA])

In this case, acetic acid (CH₃CO₂H) is the weak acid (HA) and sodium acetate (CH₃CO₂⁻) is the conjugate base (A-).

First, let's calculate pKa using the Ka value given:

pKa = -log(Ka)
    = -log(1.80 x 10^-5)
    = 4.74

Now, we can rearrange the Henderson-Hasselbalch equation to solve for the ratio of [CH₃CO₂H] to [CH₃CO₂⁻]:

pH - pKa = log ([CH₃CO₂⁻]/[CH₃CO₂H])

Since the pH is given as 5.05 and pKa is 4.74, we can substitute these values:

5.05 - 4.74 = log ([CH₃CO₂⁻]/[CH₃CO₂H])

0.31 = log ([CH₃CO₂⁻]/[CH₃CO₂H])

To find the actual ratio, we need to convert the logarithm in the  exponential form:

10^0.31 = [CH₃CO₂⁻]/[CH₃CO₂H]

2.03 = [CH₃CO₂⁻]/[CH₃CO₂H]

Therefore, the ratio of the concentration of CH₃CO₂H to CH₃CO₂⁻ in the buffer is approximately 2.03.

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Answer: 31.3 square feet

Step-by-step explanation:

Jacob has a tree growing in his yard. if the tree grows 9.5 feet per year, 9.5 inches  does it grow in a month.

From the question, we have

Tree grows 9.5 feet per year

9.5 feet = 114 inches

Tree grows in one month = 114/12

= 9.5 inches

Divide:

Repetitive subtraction is the process of division. It is the multiplication operation's opposite. It is described as the process of creating equitable groups. When dividing numbers, we divide a larger number down into smaller ones such that the larger number obtained will be equal to the multiplication of the smaller numbers. One of the four fundamental mathematical operations, along with addition, subtraction, and multiplication, is division. Division is the process of dividing a larger group into smaller groups so that each group contains an equal number of things. It is a mathematical operation used for equal distribution and equal grouping.

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Answer:

$758 per week

Step-by-step explanation:

15.16 x 50 = 758

Answer:$758 per week

Step-by-step explanation:Answer:15.16 x 50 = 758

x = y -8 hope this helps?

Answer:

23

Step-by-step explanation:

(x+4) ²-3 (Question)

x²+4x+16-3

x²+4x+13

(2)²+4(2)+13 (since x=2)

4+6+13

23

Therefore, the correct answer is c) 3, as there are three F ratios calculated in a 2x2 factorial design.

In a two-way analysis of variance (ANOVA) known as a 2x2

factorial design, there are three F ratios or F statistic values calculated. This design involves two independent variables, each with two levels or categories.

The three F ratios represent the main effects of each independent variable and the interaction between the two variables.The main effects F ratios determine whether there are significant differences between the levels of each independent variable individually, ignoring the other independent variable.

There will be two main effects F ratios, one for each independent variable.The interaction F ratio examines whether there is a significant interaction between the two independent variables. It determines whether the effect of one independent variable differs across the levels of the other independent variable.

This F ratio assesses the joint influence of both independent variables.

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Answer:

18.84 square centimeters

Step-by-step explanation:

\(C =\) \(\pi\)\(d\)

\(C = (3.14)(6)\)

\(C = 18.84\) \(cm^{2}\)

P.S: Diameter is radius + radius so that means that diameter is 3 + 3 for this problem.

The Transitive Property of Parallel Lines Theorem states that if two lines are parallel to the same line, then they are parallel to each other, which can be proven using angle properties.

The Transitive Property of Parallel Lines Theorem asserts that if line AB is parallel to line CD, and line CD is parallel to line EF, then line AB must also be parallel to line EF. This can be proven using the properties of angles formed by parallel lines cut by a transversal.

When two lines are parallel and intersected by a transversal, various pairs of angles are formed, including corresponding angles, alternate interior angles, and alternate exterior angles. By using the properties of these angles, we can establish relationships between the given lines.

Through logical deductions based on the congruence or equality of corresponding angles, we can show that if two lines are parallel to the same line, they must be parallel to each other. Thus, proving the Transitive Property of Parallel Lines Theorem.

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In order to maximize utility, Jade has to follow various steps such as assessing the weight of each exam, evaluating proficiency and difficulty, etc.

The factors that influence this decision include Jade's current knowledge and proficiency in each subject, the weight of each exam, and the time she has available for studying.

1. Assess weight of each exam: Determine the percentage or points allocated to the economics and astronomy exams. This information will help prioritize the subjects.
2. Evaluate proficiency and difficulty: Consider Jade's current knowledge and skills in economics and astronomy. If she is already proficient in one subject but struggling with the other, it may be wise to allocate more time to the challenging subject.
3. Allocate study time proportionately: Based on the weight of each exam, divide the total study time between economics and astronomy. For example, if the economics exam is worth 40% and the astronomy exam is worth 60%, Jade could spend 40% of her study time on economics and 60% on astronomy.
4. Consider the time available: Take into account Jade's schedule and other commitments. If she has limited study time available, she may need to allocate more time to the subject she finds most challenging or where she has lower proficiency
5. Regular practice and review: Regardless of the time allocation, it's crucial for Jade to engage in regular practice and review sessions for both subjects. This will help reinforce concepts and improve understanding.

It's important to note that these steps provide a general framework, but the specific allocation of study time may vary depending on individual circumstances. Jade should also consider her learning style and preferences when making a study plan

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The transformations that could be used is option D) ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS.

A geometric transformation known as a stiff transformation of a Euclidean space maintains the Euclidean distance between each pair of points. Stiff transformations include rotations, translations, reflections, or any combination of these. A rotation is known as a rigid transformation or isometry when the image and the pre-image are of the same size and shape. Despite the fact that the figures may be in different positions, an object's size, form, and rotation are all the same. These are the two different categories of transformations: The rigid transition does not change the size or shape of the preimage. The preimage's size but not its shape will change as a result of the non-rigid transformation.

Note that the full question is:

Is there a series of rigid transformations that could map ΔQRS to ΔABC? If so, which transformations could be used?

A No, ΔQRS and ΔABC are congruent but ΔQRS cannot be mapped to ΔABC using a series rigid transformations.

B No, ΔQRS and ΔABC are not congruent.  

C Yes, ΔQRS can be translated so that R is mapped to B and then rotated so that S is mapped to C.

D Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS.

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The table with the scale measurements is given by the image shown at the end of the answer.

The measurements are obtained applying the proportion given for each table.

The symbols are given as follows:

For the first table, we have that every inch on the table represents one feet in real life, hence:

For the second table, we have that every inch on the paper represents two feet in real life, hence the measurements are given as follows:

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Answer: Z<4

Step-by-step explanation:

Rearrange the equation

-3(z-6) - (2z-2)>0

-3z+18-2z+2>0

-5z +20>0

-5(z-4)>0

divide  both side by -5

z-4<0

z<4

Answer:

The value of \(gof (-2)=79\)

Step-by-step explanation:

We have

\(f(x) = x^2 -5x +1 \\\\f(-2) = (-2)^2 -5\times-2 +1 \\\\=15\)

Now we need to find

\(gof (-2)=g(15)\)

\(g(15) =5\times15+4\\\\=79\)

Answer:

I believe it's (2d - 1) • (d + 2)

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   2 • -2 = -4

Step-2 : Find two factors of  -4  whose sum equals the coefficient of the middle term, which is   3 .

     -4    +    1    =    -3

     -2    +    2    =    0

     -1    +    4    =    3    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  4

                    2d2 - 1d + 4d - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

                   d • (2d-1)

             Add up the last 2 terms, pulling out common factors :

                   2 • (2d-1)

Step-5 : Add up the four terms of step 4 :

                   (d+2)  •  (2d-1)

            Which is the desired factorization

Answer -  (2d - 1) • (d + 2)

Answer:

Step-by-step explanation:

please tell me what is -9d×2-d×2

-9d×2-d×2

-18d -2d

-20d

Answer:  b

Step-by-step explanation:

I think

If Station 1 (at 74, 41) is 44 km away and Station 2( at 0,43 ) is 38 km away. The required approximate location of the GPS receiver is (42, 10).

The location of the GPS receiver can be determined with the help of trilateration. Trilateration is a process of determining absolute or relative locations of points by measurement of distances, using the geometry of circles, spheres, or triangles. If three stations (or more) are in known locations, with a known distance from the point of interest, we can determine the position of the GPS receiver with the help of trilateration.

It can be determined by the following method:

1: Plot the given stations on a coordinate plane. Stations are:

Station 1: (74, 41)

Station 2: (0, 43)

2: Calculate the distance of the GPS receiver from each station using the distance formula.

Distance Formula: The distance formula is used to find the distance between two points in the coordinate plane. The distance between points (x1,y1) and (x2,y2) is given by

d = √[(x2 - x1)² + (y2 - y1)²]

Station 1: Distance from station 1 = 44 kmSo, d1 = 44 km

Station 2: Distance from station 2 = 38 kmSo, d2 = 38 km

3: Plot the given distances as the circle on the coordinate plane.

Circle 1: Centred at (74, 41) with a radius of 44 km.

Circle 2: Centred at (0, 43) with a radius of 38 km.

4: The intersection of two circles. Circle 1 and Circle 2 intersect at point P (approx) (42, 10). So, the approximate location of the GPS receiver is (42, 10).

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Answer:

8a+32

Step-by-step explanation:

8(a+4)= 8a+32

Hope helps :D

Answer: 8a+32.

Step-by-step explanation:

A graph of quadrilateral ABCD whose vertices are A (0, 0) B(5, 0), C(3, 2) and D (0, 2) is shown in the image attached below.

In Geometry, there are different types of quadrilateral and these include the following:

Next, we would use an online graphing calculator to construct (plot) quadrilateral ABCD on a cartesian coordinate based on the given vertices. Also, you should enter the value for each vertices of quadrilateral ABCD on the x-coordinate and y-coordinate respectively as shown in the table.

By critically observing the graph of quadrilateral ABCD, we can reasonably infer and logically deduce that it represents a trapezium.

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To find the series solution for the differential equation y'' + 2xy' + 2y = 0, we can assume a power series solution of the form:

Now, substitute y(x), y'(x), and y''(x) into the differential equation:

∑(n=0 to ∞) aₙn(n-1) xⁿ⁻² + 2x ∑(n=0 to ∞) aₙn xⁿ⁻¹ + 2 ∑(n=0 to ∞) aₙxⁿ = 0

We can simplify this equation by combining the terms with the same powers of x. Let's manipulate the equation step by step:

We can combine the three summations into a single summation:

∑(n=0 to ∞) (aₙ₊₂(n+1)n + 2aₙ₊₁ + 2aₙ) xⁿ = 0

Since this equation holds for all values of x, the coefficients of the terms must be zero. Therefore, we have:

This is the recurrence relation that determines the coefficients of the power series solution To find the series solution, we can start with initial conditions. Let's assume that y(0) = y₀ and y'(0) = y'₀. This gives us the following initial terms:

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The limit of the sequence (1) {2}, (2) {(-1)^n}, and (3) {n sin(n)}, converges to DNE (does not exist) or the sequence diverges. The limit of the sequence (4) {sin(nπ)} is undefined, as it oscillates between -1 and 1.

In the case of sequence (1) {2}, the limit is a constant value, and the sequence converges to that value. However, in the case of sequence (2) {(-1)^n}, the sequence oscillates between -1 and 1, and there is no single value that it approaches as n tends to infinity. Therefore, the limit does not exist, and the sequence diverges.

Sequence (3) {n sin(n)} also does not have a limit as n tends to infinity. The term n sin(n) oscillates between positive and negative values without approaching a specific value. Hence, the limit of this sequence is DNE, and it diverges.

In the case of sequence (4) {sin(nπ)}, the term sin(nπ) oscillates between -1 and 1 as n varies. Since there is no convergence to a specific value, the limit of this sequence is undefined.

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The point estimate of the difference in malaria admission rates between January and May can be calculated by comparing the proportions of patients treated for malaria in each month.

In January, out of 192 patients, 32 were treated for malaria, giving a proportion of 32/192 = 0.1667. In May, out of 403 patients, 34 were treated for malaria, giving a proportion of 34/403 = 0.0844.

The point estimate of the difference in malaria admission rates is obtained by subtracting the proportion in May from the proportion in January: 0.1667 - 0.0844 = 0.0823. Therefore, the point estimate of the difference in malaria admission rates between January and May is approximately 0.0823.

This means that the estimated difference in the proportion of malaria patients admitted in January compared to May is approximately 8.23 percentage points. However, it's important to note that this is just a point estimate based on the given sample data. To determine the statistical significance of this difference and draw more conclusive insights, further statistical analysis, such as hypothesis testing, would be required.

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Answer:

-7.6

Step-by-step explanation:

there are many correct answers for this problem

The number that is greater than -7.81 and less than -7 is -7.41. This can be written as -7.81 < -7.81 < -7. This is obtained by taking the midpoint or middle integer of the given integers.

Given that a number that is greater than -7.81

so, we can write -7.81 <?

And it is also given that the same number which is less than -7. we can write it as -7 >?

So, from this two we can state that the number which is required lies in between the given two integers.

so, we can write -7.81 <?< -7

To find this, we are applying the average for the two integers.

⇒ -7.81 - 7 = -14.81

⇒ -14.81/2 =-7.405 ≅ -7.41

The obtained number satisfies the given conditions

-7.81 < -7.41 and -7 > -7.41

Therefore, the required number is -7.41.

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