I need help :( pleeeaase

Answer:

y=-9x+9

Step-by-step explanation:

There are only two like terms in the equation which I have underlined.

y= 3x - 12x +9

To simplify it, you combine the like terms and get your equation in standard form.

The temperature at 2:00 PM will be 73 degrees

What is temperature ?

Coldness and hotness is measured by temperature which is one of the fundamental units of measurements.

Here, it is given that the temperature at sunrise was 61 degrees and it is find the temperature at 2 P.M which as increase by 12 degrees. Now calculating it by adding 61 degree with 12 degrees :

the temperature at 2:00 PM = 61 degrees + 12 degrees = 73 degrees

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Answer:

Step-by-step explanation:

Find equations of each line using two points on each and then determine the inequalities.

Points

The slope is:

The y -intercept is 2.

The line is:

The shaded region is to the right and the line is solid, so the inequality is:

Points:

The slope is:

The line is:

The shaded region is to the left and the line is not solid, so the inequality is:

Answer:Note:  This symbol ≈ means approximately.

629 ≈ 600

215 ≈ 200

111 ≈ 100

588 ≈ 600

Now, we add the simplified numbers up: 600 + 200 + 100 + 600 = 1500. So, your answer is D or 1,500.

Step-by-step explanation:PLZZZ GIVE BRAINLYEST HOPE IT HELPS

Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

Answer:

-1/3

Hope this helps also I would appreciate brainliest is possible please :)

Answer:

c

Step-by-step explanation:

Answer:

X = 15

Step-by-step explanation:

We move all terms to the left:

x+8+2x-(2x+13)=0

We add all the numbers together, and all the variables:

3x-(2x+13)+8=0

We get rid of parentheses:

3x-2x-13+8=0

We add all the numbers together, and all the variables:

x-5=0

We move all terms containing x to the left, all other terms to the right:

x=5

The value of df, when x = π/4 and dx = 1/24, is (-5π - 5√2)/(96√2).

To find the derivative of the function f(x) = -5cos(x) + xtan(x), we'll use the sum and product rules of differentiation. Let's start by finding df/dx.

Apply the product rule:

Let u(x) = -5cos(x) and v(x) = xtan(x).

Then, the product rule states that (uv)' = u'v + uv'.

Derivative of u(x):

u'(x) = d/dx[-5cos(x)] = -5 * d/dx[cos(x)] = 5sin(x) [Using the chain rule]

Derivative of v(x):

v'(x) = d/dx[xtan(x)] = x * d/dx[tan(x)] + tan(x) * d/dx[x] [Using the product rule]

= x * sec^2(x) + tan(x) [Using the derivative of tan(x) = sec^2(x)]

Applying the product rule:

(uv)' = (5sin(x))(xtan(x)) + (-5cos(x))(x * sec^2(x) + tan(x))

= 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Simplify the expression:

df/dx = 5xsin(x)tan(x) - 5xcos(x)sec^2(x) - 5cos(x)tan(x)

Now, we need to evaluate df/dx at x = π/4 and dx = 1/24.

Substitute x = π/4 into the derivative expression:

df/dx = 5(π/4)sin(π/4)tan(π/4) - 5(π/4)cos(π/4)sec^2(π/4) - 5cos(π/4)tan(π/4)

Simplify the trigonometric values:

sin(π/4) = cos(π/4) = 1/√2

tan(π/4) = 1

sec(π/4) = √2

Substituting these values:

df/dx = 5(π/4)(1/√2)(1)(1) - 5(π/4)(1/√2)(√2)^2 - 5(1/√2)(1)

Simplifying further:

df/dx = 5(π/4)(1/√2) - 5(π/4)(1/√2)(2) - 5(1/√2)

= (5π/4√2) - (10π/4√2) - (5/√2)

= (5π - 10π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

= (-5π - 5√2)/(4√2)

Now, to evaluate df/dx when dx = 1/24, we'll multiply the derivative by the given value:

df = (-5π - 5√2)/(4√2) * (1/24)

= (-5π - 5√2)/(96√2)

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Answer:

32

Step-by-step explanation:

Solve the RHS first:

8(12) = 96

64 + ? = 96

64 + 32 =96

Answer:

-8

Step-by-step explanation:

x+2=2(x-1)

_

3

3x+6=2x-2

3x-2x=-2-6

x=-8

Answer:

Number of dollar = 28.28 (Approx)

Step-by-step explanation:

Given:

176 dollar = 140 pound

1 pound = Rs.130

Find:

Number of dollars in Rs 2925

Computation:

1 pound = Rs.130

Number of pound = 2925 / 130

Number of pound = 22.5 pound

1 pound = 176 / 140

Number of dollar = [176 / 140]22.5

Number of dollar = 28.28 (Approx)

Answer:

150 miles

Step-by-step explanation:

speed = 120 km per hour

1 mile = 1.6 km

speed = 120 km per hr

divide 120 with 1.6 to get in miles=120/1.6

= 75 miles per hour

speed = 75 miles per hour

So, in 1 hr, it can travel 75 miles

the distance traveled by car in 2 hours = 75 * 2 = 150

Result : Speed = 75 miles per hour , distance = 150 miles

The adjusting journal entry will include a debit to the allowance for credit losses of R4,400.

the correct answer is C. debit to allowance for credit losses of R4,400.

To determine the adjusting journal entry for J&L Electrical Services, we need to calculate the ending balance of accounts receivable and the necessary adjustment for the allowance for credit losses.

Beginning balance of accounts receivable: R200,000

Services delivered on credit: R660,000

Collections from debtors: R640,000

To find the ending balance of accounts receivable, we subtract the collections from the sum of the beginning balance and services delivered on credit:

Ending accounts receivable = (Beginning balance + Services delivered) - Collections

Ending accounts receivable = (R200,000 + R660,000) - R640,000

Ending accounts receivable = R220,000

Now, we need to calculate the adjustment for the allowance for credit losses. J&L Electrical Services estimates that 2% of the ending accounts receivable will not be collected:

Allowance for credit losses adjustment = Ending accounts receivable * Estimated uncollectible percentage

Allowance for credit losses adjustment = R220,000 * 2% = R4,400

Since the allowance for credit losses has a beginning balance of R4,000, we need to increase it by R4,400 to match the estimated uncollectible amount:

the correct answer is C. debit to allowance for credit losses of R4,400.

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We have the next inequality

we need to clear x because we have a negative number the sign of the inequality will change

as we can see the mistake was option c.

The value of the expression 18 + 4(28) will be 130.

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

PEMDAS rule means for the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

The expression is given below.

⇒ 18 + 4(28)

Simplify the expression, then the value of the expression will be

⇒ 18 + 4 x (28)

⇒ 18 + 4 x 28

⇒ 18 + 112

⇒ 130

Thus, the value of the expression 18 + 4(28) will be 130.

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The approximate margin of error for a survey based on 2,700 adults, when rounded to nearest thousand is 0.021.

In statistical surveys, the margin of error is a measure of the expected amount of random sampling error that is present in a survey's results. It is a range of values that is likely to contain the true value of the population parameter being estimated, with a certain degree of confidence.

In other words, the margin of error is the amount by which the sample estimate may differ from the true value of the population parameter.

The margin of error is affected by several factors, such as the size of the sample and the level of confidence. A larger sample size typically results in a smaller margin of error because larger samples provide more accurate estimates of the population parameter.

Similarly, a higher level of confidence requires a larger margin of error, since the interval of values that could contain the true population parameter becomes wider as the level of confidence increases.

Assuming a 95% level of confidence, the formula for calculating the margin of error is:

Margin of error = z * sqrt(p * (1 - p) / n)

where:

z is the z-score for the desired level of confidence (1.96 for 95%)

p is the sample proportion, which is the proportion of the sample that exhibits a particular characteristic of interest (e.g., the proportion of respondents who support a certain political candidate)

n is the sample size, which is the number of observations in the sample.

If the sample proportion is not known, it is common to use a value of 0.5, which corresponds to the maximum possible margin of error for a given sample size. This is because the maximum sampling error occurs when the sample proportion is closest to 0.5, which gives the least amount of information about the true population parameter.

To calculate the margin of error for a survey of 2,700 adults, we can assume a sample proportion of 0.5 and a 95% level of confidence. Plugging these values into the formula, we get:

Margin of error = 1.96 * sqrt(0.5 * (1 - 0.5) / 2700)

= 1.96 * sqrt(0.25 / 2700)

= 1.96 * 0.008

= 0.016

Rounding to the nearest thousandth, the approximate margin of error is 0.021. This means that we can expect the survey results to be within plus or minus 2.1 percentage points of the true population parameter, with a 95% level of confidence.

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Answer:

-17-4y

Step-by-step explanation:

You just have to add the numbers:

-13+7-11=-17

=17-4y

The sum of the terms -13 + 7 and  - 11 -4y is -4y - 17.

A summation, also known as a sum, is the outcome of adding two or more numbers or quantities. There are always an even number of terms in a summation. There could be only two terms, or there could be one hundred, a thousand, or a million.

Given:

-13 + 7 and  - 11 -4y

Calculate the sum of the expression as shown below,

(-13 + 7) + (-11 - 4y)

-13 + 7 - 11 - 4y  [In sum, the sign convention will be (+) + (-) = (-)]

Arrange the term as shown below,

-4y + 7 - 13 - 11

Apply the operation as shown below,

-4y + 7 - 24

-4y - 17

Thus, the sum will be -4y - 17.

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Answer:

Step-by-step explanation:

the consecutive are 39,40,41 and the smallest here is 39

Hope this helped

The method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

In order to enhance strong number sense in children, there are various methods that can be used.

In the given scenario, Mme Potatana asked the children to count as a whole class from 1 to 20 while Ntate Mafodi asked the children in his class to count seeds from the school's ground in a pile by touching each as they count.

Both methods have their own benefits, but the method of counting seeds by touching each can be more effective in enhancing strong number sense in children.

The method of counting seeds by touching each can be more effective in enhancing strong number sense in children because it allows them to experience each number physically.

This helps them in developing a strong sense of numbers. By touching each seed as they count, children can feel and see each number, which helps them in understanding numbers better. Additionally, it helps in developing the concept of one-to-one correspondence and counting by rote.

Here are some appropriate examples for enhancing strong number sense using the method of counting seeds by touching each:

1. Use counters: Provide children with counters such as small objects, blocks, or toys. Ask them to count the number of counters by touching each as they count.

2. Counting on fingers: Encourage children to count on their fingers. This helps them in developing a strong sense of numbers and helps them in understanding the concept of one-to-one correspondence.

3. Counting objects in a pile: Ask children to count objects in a pile by touching each as they count. This helps in developing the concept of counting by rote and helps in enhancing strong number sense.

Overall, the method of counting seeds by touching each can be more effective in enhancing strong number sense in children as it allows them to experience each number physically and helps them in developing a strong sense of numbers.

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\((8.2 \times 10^(^-^1^0^))\)\((5.3\times 10^(^-^9^))\)The sum of \((5.3 \times 10^(^-^9^))\) and \((8.2 \times 10^(^-^1^0^))\) in scientific notation is 1.35 x 10^−8.

To find the sum of \((5.3 \times 10^(^-^9^))\) and \((8.2 x 10^(^-^1^0^))\), we can add the coefficients and keep the same base, which is 10. Adding 5.3 and 8.2 gives us 13.5. Since both numbers are expressed in scientific notation, we need to adjust the decimal point to have one digit to the left of it.

The exponent in scientific notation represents the number of decimal places we need to move the decimal point to the left (for negative exponents) or to the right (for positive exponents). In this case, the exponents are -9 and -10.

Since -9 is larger than -10, we need to adjust the decimal point by 1 place to the left. Therefore, the sum of \((5.3 x 10^(^-^9^))\) and \((8.2 \times 10^(^-^1^0^))\) in scientific notation is \(1.35 \times 10^-^8^\).

Note: Scientific notation is a concise way of representing very large or very small numbers by using powers of 10. It consists of a coefficient (a decimal number between 1 and 10) multiplied by 10 raised to an exponent.

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Answer:

Step-by-step explanation:

-7-9=-16

The formula for this linear function is f(x) = mx + b, where m is the slope (in this example, -350), and b is indeed the y-intercept (750,000 in this case).

An equation expressing the connection between the expressions on either side of a sign. Normally, it has an equal sign and just one variable. such as: 2x - 4 is equal to 2. The variable x is present in the example above.

Workers who complete the computer security course will each receive a reimbursement of $350.

We deduct $350x from of the initial $750,000 to determine how much money will remain inside the education fund once x employee gets the reimbursement.

Thus, f(x) = 750,000 - 350x is the equation again for function that describes that amount of money still in the fund when x employees receive the refund.  

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The equation formed after the transformations is given as follows:

\(g(x) = \frac{1}{6}\sqrt{x + 3}\)

The parent function in this problem is defined as follows:

\(f(x) = \sqrt{x}\)

For the vertical shrink by a factor of 1/6, the function is multiplied by 1/6, hence it is given as follows:

\(g(x) = \frac{1}{6}\sqrt{x}\)

For the translation left 3 units, we have that x -> x + 3, hence:

\(g(x) = \frac{1}{6}\sqrt{x + 3}\)

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Answer:

To convert euros to pounds, we have to multiply the amount in euros by the exchange rate. So, the sunglasses cost 90 * 0.875 = 78.75 pounds.

To use a suitable approximation, we can round the exchange rate to the nearest hundredth, which is 0.88. This makes the calculation easier and gives a close estimate of the actual value.

Using the rounded exchange rate, the sunglasses cost 90 * 0.88 = 79.2 pounds.

We can see that both the exact and the approximate values are greater than 70 pounds, so Elyas is wrong. The sunglasses cost more than 70 pounds

Step-by-step explanation:

Answer: 11:45 am

Step-by-step explanation:

10:15

toget back down 10

;15          

Maci and 2 appointments and Logan had 3 appointments.

The linear equation that represents the total amount earned by Maci is:

Total amount earned = (amount per appointment x number of appointments)  + tips

$170 = ($60 x a) + $50

$170 = $60a + $50

$170 - $50 = $60a

$120 = $60a

a = $120 / $60

a = 2

The linear equation that represents the total amount earned by Logan is:

Profit = total revenue - total cost

Profit = (fee per appointment  x number of appointments) + amount received in tips - (rental fee x number of appointments)

$235 = ($75 x a) + $40 - ($10 x a)

$235 = $75a + $40 - $10a

$235 = $65a + $40

$235 - $40 = $65a

$195 = $65a

a = $195 / 65

a = 3

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The function opertaion f(x) - g(x) in the functions f(x) = log₂ (3x - 9) and g(x) = log₂ (x-3) is log₂(3).

Given the functions in the questions:

f(x) = log₂ (3x - 9)

g(x) = log₂ (x-3)

f(x) - g(x) = ?

To find the function operation f(x) - g(x), we need to subtract the equation for g(x) from the equation for f(x).

f(x) - g(x)

Plug in the values of f(x) and g(x)

f(x) - g(x)

f(x) - g(x) = log₂(3x - 9) - log₂(x - 3)

We can use the logarithmic identity : log₂(a) - log₂(b) = log₂(a/b) to combine the logarithms:

f(x) - g(x) = log₂[ (3x - 9) / (x - 3) ]

Now we can simplify the expression in the parentheses:

f(x) - g(x) = log₂[(3(x - 3))/(x - 3)]

f(x) - g(x) = log₂(3)

Therefore, the function opertaion f(x) - g(x) = log₂(3).

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