i need help please
Points A, B, and C are collinear and B lies between A and C. If AC = 48, AB = 2x + 2, and BC = 3x + 6, what is BC?

The domain of f¯¹ is [-2, 00).

If f(3) = 23 and f is one-to-one, it means that the input value of 3 maps to the output value of 23.

To find f¯¹(23) (the inverse function of f) for a given value of 23, we need to determine the input value that maps to 23. Since f is a one-to-one function, each output value corresponds to a unique input value.

So, f¯¹(23) = 3.

The given domain of the one-to-one function f is [2,00), which means it includes all real numbers greater than or equal to 2. However, based on the notation you provided, it seems like the intended domain is [2, 100), not [2, 00).

The domain of f¯¹ (the inverse function of f) will be the range of the original function f. The given range of f is [-2,00), which means it includes all real numbers greater than or equal to -2.

Therefore, the domain of f¯¹ is [-2, 00).

Regarding the question about the domain of f¹², it is not clear what is meant by "f¹²." If you meant to ask about the domain of f composed with itself 12 times, it would depend on the specific function f and cannot be determined without additional information.

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Answer:80100

Step-by-step explanation:

Since "per cent" means parts per hundred, if we can convert the fraction to have 100 as the denominator, we then know that the top number, the numerator, is the percentage. Our percent fraction is 80/100, which means that 80100 as a percentage is 80%.

We need to find the inverse of the function gof (x). First we need to find the composite function gof (x) which is given by:

\(g(f(x)) = g(3x - 6)\)

= \((1/3)(3x - 6) + 1\)

= x - 1 + 1

= x

Thus,

gof (x) = x.

Now we need to find the inverse of the function gof (x) to obtain

\((gof)^-1 (x).\)

We have gof (x) = x

which implies\((gof)^-1 (x)\)

= gof (x)^-1

= x^-1

= 1/x,

x ≠ 0

Therefore,

\((gof)^-1 (x) = 1/x\)

which is option (3) (x+1) since 1/x can be written as 1/(x+1-1), where (x+1-1) is the denominator of 1/x.

Hence, the correct option is (3).

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To find (g(f))^-1 (x), substitute the expression for f(x) into g(x) and simplify. The composition of g(f) is x and its inverse is also x. Therefore, (g(f))^-1 (x) equals x.

To find (g(f))^-1 (x), we need to first find the composition of g(f) and then find its inverse. Start by substituting the expression for f(x) into g(x): g(f(x)) = g(3x-6) = \frac{1}{3}(3x-6) + 1 = x - 1 + 1 = x. So, g(f(x)) = x. Now, to find the inverse of g(f), we switch the x and y variables and solve for y: y = x. Therefore, (g(f))^-1 (x) = x.

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(x-3y=9\implies -3y=-x+9\implies y=\cfrac{-x+9}{-3} \\\\\\ y=\cfrac{-x}{-3}+\cfrac{9}{-3}\implies y=\cfrac{1}{3}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so we're really looking for the equation of a likne whose slope is 1/3 and it passes through (-10 , 9)

\((\stackrel{x_1}{-10}~,~\stackrel{y_1}{9})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{ \cfrac{1}{3}}(x-\stackrel{x_1}{(-10)}) \implies y -9= \cfrac{1}{3} (x +10) \\\\\\ y-9=\cfrac{1}{3}x+\cfrac{10}{3}\implies y=\cfrac{1}{3}x+\cfrac{10}{3}+9\implies {\Large \begin{array}{llll} y=\cfrac{1}{3}x+\cfrac{37}{3} \end{array}}\)

Answerh

Step-by-step explanation:

huh

In other words, the triangles are consistent if the hypotenuse and one of the legs of one right triangle agree with the hypotenuse and one of the legs of another right triangle.

Congruent triangles are two triangles that are the same size and shape. Two congruent triangles remain congruent even if we flip, turn, or rotate one of them. Two triangles must have the same angles and, as a result, must be congruent if their sides are the same.

Two right triangles are supposed to be consistent on the off chance that they are of a similar shape and size. All in all, two right triangles are supposed to be consistent in the event that the proportion of the length of their comparing sides and their relating points is equivalent.

Right triangles are harmonious in the event that both the hypotenuse and one leg are a similar length. These triangles are harmonious by HL or hypotenuse leg.

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If 5.625 tins of paint are used out of 6 tins bought, the amount wasted can be calculated by subtracting the used amount from the total amount bought. Therefore, approximately 0.375 tins of paint are wasted.

If 5.625 tins of paint are used and 6 tins were bought, we can find the amount wasted by subtracting the used amount from the total amount bought.

The amount wasted can be calculated as follows:

Wasted amount = Total amount bought - Used amount

Wasted amount = 6 tins - 5.625 tins

To subtract the decimal values, we need to convert both amounts to the same denominator. Since there are four decimal places in 5.625, we can multiply both numbers by 10000 to eliminate the decimals:

Wasted amount = (6 * 10000) - (5.625 * 10000)

Simplifying the expression, we get:

Wasted amount = 60000 - 5625

Wasted amount = 54375

Converting the wasted amount back to the original decimal form, we have:

Wasted amount = 54375 / 10000

Wasted amount ≈ 0.375 tins

Therefore, approximately 0.375 tins of paint are wasted.

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Answer:

Step-by-step explanation:

Equation: y = 20x

y = # of gallons

x = minutes

6.

So, you substitute (0, 1, 2, 3 and 4 minutes) for x, to find the number of gallons:

x = 0 mins:

y = 20x

y = 20(0)

y = 0 gallons

(0, 0)

x = 1 min.

y = 20x

y = 20(1)

y = 20 gallons

(1, 20)

x = 2 mins.

y = 20x

y = 20(2)

y = 40 gallons

(2, 40)

x = 3 mins.

y = 20x

y = 20(3)

y = 60 gallons

(3, 60)

x = 4 mins.

y = 20x

y = 20(4)

y = 80 gallons

(4, 80)

7. View the attached graph

8. Predict the amount of water in the tank after 6 mins.

We use the same equation, y = 20x for this question

y = 20x

y = 20(6)

y = 120 gallons

(6, 120)

8. Linear ==> straight line

   Non-linear ==> anything other than a straight line (curved line)

As you can see from my attached graph, the relationship between x and y and linear, because the graph has a straight line.

Hope this helps!

Answer:

11

Step-by-step explanation:

Answer:

x= 13.333333

Step-by-step explanation: 12x = 160 & 160/12 = x

Answer:$342

Step-by-step explanation: First we convert to yards: which gives us 14/3 yards and 20/3 yards. We multiply these to find a combined area of 280/9 yards, which we then multiply to get 280*11/3. Simplify to get 342.22 repeating, which rounds to 342.

Answer:

-2x -1 if f(x) is reflected along the x axis and translated 1 unit downward

Step-by-step explanation:

A function can either be reflected along the x axis or along the y axis. If a function is reflected along the x axis, the new reflected equation g(x) is given by:

g(x) = -f(x) = -2x

g(x) = -2x

If a function is reflected along the y axis, the new reflected equation g(x) is given by:

g(x) = f(-x) = 2(-x)

g(x) = -2x

Translation means the shifting of the curve either up or down in a graph. If the reflected function is shifted 1 unit upward, the function becomes:

g(x) + 1 = -2x + 1

If the reflected function is shifted 1 unit downward, the function becomes:

g(x) - 1 = -2x - 1

Answer:

The answer is C.

Step-by-step explanation:

did the test

a) The area of rectangle ABCD in terms of x and y = 4xy.

b) xy = 10

c) area of triangle EBF​ = 5 m².

Part A) The area of rectangle ABCD:

See the diagram;

The length of rectangle is 2x.

The width of breadth is 2y.

Area = length×breadth

Area = 2x × 2y

Area of ABCD = 4xy m².

Part b) value of xy.

The area of the triangle DEF is 15m².

area ΔDEF = area ABCD - area ΔADE - area ΔBEF - area ΔDFC.

Put the values;

area ΔDEF = 4xy - 2xy/2 - 2xy/2  - xy/2

area ΔDEF = 3xy

equate;

ΔDEF = 3xy and DEF = 15m².

3xy/2 = 15

xy = 10

Thus, the value of xy = 10.

Part c) area of triangle EBF​:

area ΔEBF = xy/2

Put the value of xy = 10.

area ΔEBF = 10/2  = 5

Thus, the area of the triangle EBF 10m².

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The solutions are;

1) m^6/2

2) a^4b^2/4

3) 27x^5y/4

4) 4x^12/9

5) 8y^9/27

6) x^4y^2/4

The simplify means to write is the lowest possible form of the expression.

Let us now simplify each expression;

1) (-2m^4)^2/8m^2

4m^8/8m^2

m^6/2

2) (2a^3b^4)^3/(2ab^2)^5

2^3a^9b^12/2^5a^5b^10

a^4b^2/4

3) (3x^5y^3)^5/(6x^10y^7)^2

243x^25y^15/36x^20y^14

27x^5y/4

4) (4x^7/6x)^2

16x^14/36x^2

4x^12/9

5) (2y^5/3y^2)^3

8y^15/27y^6

8y^9/27

6) (5x^6y^2/10x^4y)^2

25x^12y^4/100x^8y^2

x^4y^2/4

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Answer:

-90

Step-by-step explanation:

Answer:

width = 14.14 sq.miles

Step-by-step explanation:

We are told that the city is square.. We are also told that the area of the city is 200 sq.miles.

Now,formula for area of square if a side is x is given as;

A = x²

Where x is both the length and width.

Thus;

x² = 200

x = √200

x = 14.14 sq.miles

Thus,length = 14.14 sq.miles and width = 14.14 sq.miles

Answer:

Step-by-step explanation:

for c it would be 1\8

for E it would be 3\8

Answer:

Step-by-step explanation:

1/8+3/8= 4/8

Answer:

2.5 meter

Step-by-step explanation:

in a right triangle, tan of an angle  = opposite side /adjacent side

tan 70° = x/ 0.9 , multiply both sides by 0.9

0.9 * tan 70° = x, solve on a calculator

x ≈ 2.5 m

The IUPAC formulas of the given complexes are as follows:

(i) Pentaamminethiocyanatochromium(III) tetrachlorozincate(II)

(ii) Potassium pentachloro(phenyl)antimonate(V)

(iii) mer-triamminetrichlorocobalt(III)

(i) Pentaamminethiocyanatochromium(III) tetrachlorozincate(II): In this complex, the central metal ion is chromium in the +3 oxidation state. It is coordinated to five ammonia ligands (NH₃) and one thiocyanate ligand (SCN). The complex also contains a tetrachlorozincate(II) ion, which consists of a zinc ion (Zn²⁺) coordinated to four chloride ions (Cl⁻). Therefore, the IUPAC formula for this complex is pentaamminethiocyanatochromium(III) tetrachlorozincate(II).

(ii) Potassium pentachloro(phenyl)antimonate(V): In this complex, the central metal ion is antimony in the +5 oxidation state. It is coordinated to five chloride ligands (Cl⁻) and one phenyl ligand (C₆H₅). The complex is further associated with a potassium ion (K⁺). Hence, the IUPAC formula for this complex is potassium pentachloro(phenyl)antimonate(V).

(iii) mer-triamminetrichlorocobalt(III): In this complex, the central metal ion is cobalt in the +3 oxidation state. It is coordinated to three ammonia ligands (NH₃) and three chloride ligands (Cl⁻). The arrangement of these ligands in a meridional geometry gives the complex its name. Therefore, the IUPAC formula for this complex is mer-triamminetrichlorocobalt(III).
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Answer:

I think the answer is the blue box

Hi!

I will help you with joy!

Let's take a look at our pattern.

12, 11, 15, 14, _

Here, we subtract 1, then add 4, then subtract 1, then add 4.

Thus, the next number in the pattern will be 18.

12, 11, 15, 14, 18

The next number will be 17, and so on...

I hope it helps!

Ask me if you have any queries.

Misty ~

\(\bf{Grace}\sf{ful\rm{Teen\)

Enjoy your day!

Answer:

See below

Step-by-step explanation:

The magnitude of a line can simply be found by the distance formula:

Distance = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

Exact answer: 1/3   Decimal Form : 0.3

Step-by-step explanation:

Answer: the answer is 2.85 x 10^-4

Step-by-step explanation:

or u can just look up  Mathway and that will give you the answer and a much quicker way too https

Answer:

Step-by-step explanation:

place a point at (0,0)- the starting point

next point at (2,1) - in 2 minutes she is 1 block away

Next point (4,2)- in 4 minutes she will be 2 blocks away

Connect those 3 points

then place a point at (9, 2)- 5 minutes later she was still at the store

Connect points

Point at (11,1) and (12,0) and connect

Deon's Coffee Shop used 26 pounds of type A coffee.

Let's consider Deon's Coffee Shop, which used "a" pounds of type A coffee and "4a" pounds of type B coffee. The total cost of the blend is $578.50, so we can equate the total cost of the type A and type B coffee to that amount. This leads us to the following equation: 5.45a + 4.20(4a) = 578.50.

To solve the equation, we simplify it: 5.45a + 16.80a = 578.50. Combining like terms, we get 22.25a = 578.50.

To find the value of "a," we divide both sides of the equation by 22.25. Therefore, a = 26. Hence, Deon's Coffee Shop used 26 pounds of type A coffee.

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Answer:

x = 7 ,  y= - 6

Step-by-step explanation:

4x = -2 - 5y ___(1)

4x= 10 - 3y ___(2)

so, now by simultaneous equations,

10 - 3y = - 2 - 5y

2y = -12

y = -6

if y = -6

then, 4x= 10 -3(-6)

4x =28

x = 7

The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).

a) Here the area of the parallelogram determined by d and e is given as 10. The area of the parallelogram is given as `|d×e|`.

We have,

d=(2,4)

and e=(4k,3k)

Then,

d×e= (2 * 3k) - (4 * 4k) = -10k

Area of parallelogram = |d×e|

= |-10k|

= 10

As we know, area of parallelogram can also be given as,

|d×e| = |d||e| sin θ

where, θ is the angle between the two vectors.

Then,10 = √(2^2 + 4^2) * √((4k)^2 + (3k)^2) sin θ

⇒ 10 = √20 √25k^2 sin θ

⇒ 10 = 10k sin θ

∴ k sin θ = 1

Therefore, sin θ = 1/k

Hence, the value of k is 1.

Part(b) The volume of the parallelepiped determined by vectors a, b and c is given as,

| a . (b × c)|

Here, a=(1,1,2),

b=(5,3,λ), and

c=(4,4,0)

Therefore,

b × c = [(3 × 0) - (λ × 4)]i + [(λ × 4) - (5 × 0)]j + [(5 × 4) - (3 × 4)]k

= -4i + 4λj + 8k

Now,| a . (b × c)|=| (1,1,2) .

(-4,4λ,8) |=| (-4 + 4λ + 16) |

=| 12 + 4λ |

Therefore, the volume of the parallelepiped is 12 + 4λ.

Part(c) The vector component of a + c orthogonal to c is given by [(a+c) - projc(a+c)].

Here, a=(1,1,2) and

c=(4,4,0).

Then, a + c = (1+4, 1+4, 2+0)

= (5, 5, 2)

Now, projecting (a+c) onto c, we get,

projc(a+c) = [(a+c).c / |c|^2] c

= [(5×4 + 5×4) / (4^2 + 4^2)] (4,4,0)

= (4,4,0.5)

Therefore, [(a+c) - projc(a+c)] = (5,5,2) - (4,4,0.5)

= (1,1,1.5)

Therefore, the vector component of a + c orthogonal to c is (1,1,1.5).

Conclusion: The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).

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Answer:

75 cm

Step-by-step explanation:

I used the formula and my calculator. Hope this helps! if you are still confused please comment!

Answer:

Step-by-step explanation:

The factorise quadratic equation x² + 18x + 45 = 0 is (x + 3)(x + 15)

A quadratic equation is a polynomial equation that contains the second degree, but no higher degree, of the variable.

Therefore, quadratic equation can be represented as follows:

ax² + bx + c

where

Hence, let's factorise x² + 18x + 45 = 0

x² + 18x + 45 = 0

Let's find the two numbers to add to get 18 and multiply to get 45

Therefore, the numbers are 3 and 15

x² + 18x + 45 = 0

x² + 3x + 15x + 45 = 0

x(x + 3) + 15(x + 3) = 0

(x + 3)(x + 15) = 0

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Given: the sides of the right angles triangle is given as 35 and 30.

We have to find the leg of the triangle.

Now, since it is a right angled triangle, so we can apply Pythagoras Theorem here.

It states,

Now, as per our question, we have;

hypotenuse=35 and base=30 perpendicular=a

We have to find this 'a'

Therefore,