I Need Help! Please!
A local grocery store buys fresh carrots from a nearby farm for $0.65 per pound and sells them for $0.88 per pound. What markup rate does the grocery store use? Round to the nearest whole percent.

The markup rate that the grocery store uses is _____ % (Round to the nearest whole percent.)

Answer: 1008 quarts in 36 hours

672 quarts per day

Step-by-step explanation:

280/10=28 quarts per hour

28*36=1008 quarts in 36 hours

28*24=672 quarts per day

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below

\((\stackrel{x_1}{1}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{9}-\stackrel{y1}{5}}}{\underset{\textit{\large run}} {\underset{x_2}{3}-\underset{x_1}{1}}} \implies \cfrac{ 4 }{ 2 } \implies 2\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{ 2}(x-\stackrel{x_1}{1}) \\\\\\ y-5=2x-2\implies {\Large \begin{array}{llll} y=2x+3 \end{array}}\)

Answer:

£288

Step-by-step explanation:

Kathy bought a TV for the cost of 360 pounds, including VAT (taxes).

Since the taxes are 20% of the TV's value, we can calculate 20% of 360.

20% of 360 = 72

360 - 72 = 288

Therefore, the cost of the TV before taxes was £288.

For the matrix the true statement is given by option d. Both A and B are false.

Let's analyze each statement of the matrix as follow,

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R⁵.

This statement is false.

The domain of the transformation T is not R⁵.

The domain of T is determined by the dimensionality of the vectors x that can be input into the transformation.

Here, the matrix A is a 3 times 5 matrix, which means the transformation T(x) = Ax can only accept vectors x that have 5 elements.

Therefore, the domain of T is R⁵, but rather a subspace of R⁵.

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto.

This statement is also false.

The transformation x → Ax can still be onto (surjective) even if A is a 3 times 2 matrix.

The surjectivity of a transformation depends on the rank of the matrix A and the dimensionality of the vector space it maps to.

It is possible for a 3 times 2 matrix to have a rank of 2,

and if the codomain is a vector space of dimension 3 or higher, then the transformation can be onto.

Therefore, as per the matrix both statements are false, the correct answer is d. Both A and B are false.

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The above question is incomplete, the complete question is:

Which of the following best characterizes the following statements:

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R^5

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto

a. Only A is true

b. Only B is true

c. Both A and B are true

d. Both A and B are false

Answer:

x = -4.5

Step-by-step explanation:

In order to solve for x, we need to get x alone. We do this by adding 5 to each side, then dividing both sides by -2. Like this:

-2x - 5 = 4

+5          +5

-2x = 9

÷ -2  ÷ -2

x = -4.5

I hope this helps! Please feel free to let me know if you need any more help. Have a great afternoon! :}

Answer:

x= -4.5

Step-by-step explanation:

-2x - 5 = 4

-2x = 4+5

-2x = 9

-2x÷ (-2) = 9÷ (-2)

x= -9/2

x= -4.5

Answer:

r=7 my

answer needs to be 20 characters long

Using the area formula for a rectangle and considering the geometric properties of a trapezoid, we have derived the formula for finding the area of a trapezoid.

The formula for the area of a trapezoid can be derived by using the area formula for a rectangle and some mathematical properties.

Let's consider a trapezoid with bases of lengths b1 and b2, and a height h. To find the area of the trapezoid, we can break it down into two parts: a rectangle and two right triangles.

Start by drawing a straight line parallel to the bases of the trapezoid to create a rectangle.

The length of the rectangle is the average of the lengths of the two bases: (b1 + b2) / 2.

The width of the rectangle is equal to the height of the trapezoid: h.

The area of the rectangle is given by the formula: Area_rectangle = length * width = ((b1 + b2) / 2) * h.

Now, we need to subtract the areas of the two right triangles formed outside the rectangle.

Each right triangle has a base equal to the difference between one of the trapezoid bases and the length of the rectangle: (b1 - ((b1 + b2) / 2)) and (b2 - ((b1 + b2) / 2)).

The height of each right triangle is equal to the height of the trapezoid: h.

The area of a right triangle is given by the formula: Area_triangle = (base * height) / 2.

Therefore, the combined area of the two right triangles is: 2 * [(b1 - ((b1 + b2) / 2)) * h / 2].

Simplifying the expression: (b1 - ((b1 + b2) / 2)) * h = (b1 - b1/2 - b2/2) * h = (b1/2 - b2/2) * h = ((b1 - b2) / 2) * h.

Adding the area of the rectangle and subtracting the combined area of the two right triangles, we get the formula for the area of the trapezoid:

Area_trapezoid = ((b1 + b2) / 2) * h - ((b1 - b2) / 2) * h.

Simplifying further, we can factor out the common factor of h:

Area_trapezoid = (b1 + b2 - (b1 - b2)) * h / 2.

Finally, simplifying the expression within the parentheses:

Area_trapezoid = (2b2) * h / 2.

This simplifies to the formula for the area of a trapezoid:

Area_trapezoid = (b1 + b2) * h / 2.

Therefore, using the area formula for a rectangle and considering the geometric properties of a trapezoid, we have derived the formula for finding the area of a trapezoid.

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Answer:

My calculator says 165.789

Answer:

D: 50

Step-by-step explanation:

Count them one by one!

The number of bicycles they need to sell to make equal money is 5. The amount they would make is $500.

In contrast to variable costs, which change depending on the volume of production or sales, fixed costs are expenses that remain constant. Rent, insurance, and salary are examples of fixed costs that are constant regardless of the volume of output or sales. Materials, labour, and shipping expenses are examples of variable costs that change according to the volume of output or sales.

Let us suppose the number of bicycle sold = x.

Then the equation for Jimmy is:

$250 + 50x

The equation for Tom is:

$400 + 20x

To make the same amount we equate the two equations as follows:

250 + 50x = 400 + 20x

30x = 150

x = 5

Substituting the value of x in equation 1 we have:

J = 250 + 50(5)

J = 250 + 250

J = 500

Hence, the number of bicycles they need to sell to make equal money is 5. The amount they would make is $500.

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The probability that the first student Mr. Beal selects has a pass or has completed the homework assignment is 23/33.

Let us denote the following:

A  student has a pass =  P

A student has completed the homework assignment =  H.

The given parameters are:

Probability of (P) = 11/33

Probability of (H) = 19/33

Probability of (P and H) = 7/33

We apply the  principle of inclusion-exclusion and have that the  Probability of (P or H) = P(P) + P(H) - P(P and H)

We then substitute values

Probability of (P or H) = (11/33) + (19/33) - (7/33)

= 23/33

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There were total 276 guests in the wedding that Joy organised.

Given,

fraction of the guest that chose beef = 1/3

fraction of the guest that chose chicken = 5/12

fraction of the guest that chose vegetarian = 1  - 1/3 - 5/12 = 1/4

we are asked to find the total number of guests in the wedding:

guests that chose vegetarian = 1/4

guests that chose vegetarian = 69

1/4 of the guest = 69

4/4 of the guest = 69 x 4 = 276

Hence there are total 276 guests in the wedding.

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There are 66 ways Kim can put the 10 identical lamps on the 3 identical tables

The given parameters are:

The combination involving identical objects is calculated using:

(n + r - 1)C(r - 1)

So, we have:

n + r - 1 = 10 + 3 - 1

Evaluate the sum

n + r - 1 = 13 - 1

Evaluate the difference

n + r - 1 = 12

Also, we have:

r - 1 = 3 - 1

Evaluate the difference

r - 1 = 2

So, we have:

(n + r - 1)C(r - 1) = 12C2

Apply the following combination formula:

nCr = n!/((n - r)!r!)

So, we have:

12C2 = 12!/((12 - 2)! * 2!)

Evaluate the difference

12C2 = 12!/(10! * 2!)

Expand the numerator

12C2 = 12 * 11 * 10!/(10! * 2!)

Evaluate the quotient

12C2 = 12 * 11/2!

Expand the denominator

12C2 = 12 * 11/2 * 1

Evaluate the product

12C2 = 132/2

Evaluate the quotient

12C2 = 66

Hence, there are 66 ways Kim can put the 10 identical lamps on the 3 identical tables

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Options A and B

Hope it helps.

Do comment if you have any query.

Answer:

x>4

Step-by-step explanation:

-5x+6<2(-3-x)

-5x+6<-6-2x

-5x+6+2x<-6-2x+2x

-3x+6<-6

-3x<-12

Answer:

Rule 1: Adding positive numbers to positive numbers—it's just normal addition.

Rule 2: Adding positive numbers to negative numbers—count forward the amount you're adding.

Rule 3: Adding negative numbers to positive numbers—count backwards, as if you were subtracting.

B) 5x-4 = 3\(x^2\) has no real solution

To check real solution of a quadratic equation we have to check for discriminant value of each equation a\(x^2\) + bx +c is given by :

D =b^2 - 4ac.

if D<0 then equation have no solution.

now we need to check for each option the D value

Option A:

Therefore, the discriminant of the equation x^2 - 3x - 7 is (-3)^2 - 4(1)(-7) = 9 + 28 = 37.

Option B:

The discriminant of the quadratic equation 3x^2 - 5x + 4 is the value of b^2 - 4ac, which is (5)^2 - 4(3)(4) = 25 - 48 = -23. A negative discriminant (-23) would indicate that the equation has no real solutions, meaning it has no solutions in real numbers.

so option B  which is 5x-4 = 3\(x^2\) have no real solution.

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Complete question:

Which of the following equations has no real solutions?

A. \(x^2\) +3x=7

B. 5x-4 = 3\(x^2\)

C. \(x^2\) +1 = 3x

D. 2\(x^2\) +5x=3

Answer:

5300

Step-by-step explanation:

7420 /1.40 = 5300

Answer:

2(4+3) or undefined

Step-by-step explanation:

lmk if this helped

Answer:

24

Step-by-step explanation:

Answer:

Round to the nearest tenth. The diagram is not drawn to scale. Solution: We know that. cosθ = adjacent/hypotenuse. Substituting the values. cos22 = x/11.

Step-by-step explanation

hope this helps

Answer: As the two cylinders have the same height, the cylinder with the greater radius will have the greater volume. Therefore, the statement "The cylinder with radius has a greater volume than the cylinder with radius /2" is true.

Step-by-step explanation:

The corresponding angles and sides of the two triangles need to be given in order to prove congruence by side-angle-side.

In order to prove congruence by side-angle-side, the corresponding angles and sides of the two triangles must be given. The sides must be proportional, which means that two sides of one triangle must be equal to two sides of the other triangle, and the angles between these two sides must also be equal. In other words, if two sides of one triangle are equal to two sides of the other triangle, and the angle between those two sides is also equal, then the two triangles are congruent. This can be expressed as “If two sides and the included angle of one triangle are equal to the corresponding sides and angle of a second triangle, then the two triangles are congruent.” In order to prove congruence by side-angle-side, all of the corresponding sides and angles must be given in order to show that they are equal.

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The additional information that is needed to prove the triangles are congruent by Side-Angle -Side us that the corresponding angles and sides of the two triangles need to be given .

What is Side-Angle-Side Congruence ?

The Two Triangles can be called as  Congruent by Side-Angle-Side rule  if any 2 sides and angle included between sides of one triangle is equivalent to corresponding 2 sides and angle between sides of second triangle .

In order to prove the Congruence by Side-Angle-Side, the corresponding angles and the sides of the 2 triangles must be given.

The sides must also be in proportional, that means that the two sides of one triangle must be equal to two sides of other triangle, and

the angles between these two sides of the triangle must  be equal.

So , In order to prove a triangle congruent by Side-Angle-Side, all of the corresponding sides and angles must be given in order to prove  that they are equal.

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\(\textit{Law of sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\sin(x)}{5}=\cfrac{\sin(53^o)}{7}\implies \sin(x)=\cfrac{5\sin(53^o)}{7} \\\\\\ x=\sin^{-1}\left( \cfrac{5\sin(53^o)}{7} \right)\implies x\approx 34.8^o\)

Answer:  

Home 30, visitor 17.

Step-by-step explanation:

Visiting team score is x. Home score is then x+13. Total of both is 47 so...

x+(x+13)=47

2x+13=47

2x-34

x=17

x+13=30

The score of  Home Team is 30 points.

The score of Visiting team is 17 points.

Here,

During the last schools football game, the Home Team scored 13 more points than the Visiting team.

The total of their scores was 47.

We have to find points of each team score.

What is Number system?

A number system is a system representing numbers. It is also called the system of numeration.

Now,

Let Visiting team score x points.

Then, Home team score is 13 more points than the Visiting team.

Home team score x + 13 points.

The total of their scores was 47.

Hence,

x + (x + 13) = 47

2x + 13 = 47

2x = 47 - 13

2x = 34

x = 17

So, The score of Visiting team is 17 points.

And, The score of  Home Team = 17 + 13 = 30 points.

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Answer: 50 miles

Step-by-step explanation:

Let the miles that she is trying to run by the end of the month be denoted by x.

Since she is 80% of the way to achieving her goal and she has already run 40 miles. This can be expressed as:

80% of x = 40

80/100 × x = 40

0.8x = 40

x = 40/0.8

x = 50

The miles that she is trying to run by the end of the month is 50 miles.

Answer:

55 degrees

Step-by-step explanation:

one triangle has 180 degrees

deg=35 degrees so subtract 35 from 180=145 dgrees.

the square at the bottom center means a 90 degree angle, so subtract 90 from 145=55

Answer:

28

Step-by-step explanation:

Given:

The vertices of a polygon are A (−1, 1), B (4, 1), C (4,−2), and D(−1,−2).

To find:

The perimeter of ABCD.

Solution:

Distance formula:

\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Using distance formula, we get

\(AB=\sqrt{(4-(-1))^2+(1-1)^2}\)

\(AB=\sqrt{(4+1)^2+(0)^2}\)

\(AB=\sqrt{(5)^2}\)

\(AB=5\)

Similarly,

\(BC=\sqrt{(4-4)^2+(-2-1)^2}=3\)

\(CD=\sqrt{(-1-4)^2+(-2-(-2))^2}=5\)

\(AD=\sqrt{(-1-(-1))^2+(-2-1)^2}=3\)

Now, perimeter of ABCD is

\(P=AB+BC+CD+AD\)

\(P=5+3+5+3\)

\(P=16\)

Therefore, the perimeter of ABCD is 16 units.

The perimeter of polygon ABCD is 16 units

The coordinates are given as:

\(\mathbf{A = (-1,1)}\)

\(\mathbf{B = (4,1)}\)

\(\mathbf{C = (4,-2)}\)

\(\mathbf{D = (-1,-2)}\)

Start by calculating the distance between the coordinates using the following distance formula

\(\mathbf{d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}\)

So, we have:

\(\mathbf{AB = \sqrt{(-1 - 4)^2 + (1 - 1)^2} = 5}\)

\(\mathbf{BC = \sqrt{(4 - 4)^2 + (-2 - 1)^2} = 3}\)

\(\mathbf{CD = \sqrt{(4 - -1)^2 + (-2 - -2)^2} = 5}\)

\(\mathbf{AD = \sqrt{( -1- -1)^2 + (-2 - 1)^2} = 3}\)

The perimeter is then calculated as:

\(\mathbf{Perimeter = AB + BC + CD + AD}\)

Substitute values for AB, BC, CD and DA

\(\mathbf{Perimeter = 5+ 3 + 5 + 3}\)

\(\mathbf{Perimeter = 16}\)

Hence, the perimeter of the polygon is 16 units

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