I need help please and thank you

I Need Help Please And Thank You

Answers

Answer 1

Answer:

  3.33×10⁴

Step-by-step explanation:

You can use the hint, or you can use a common exponent. Here is the latter case.

  (3.9×10⁴) -(5.7×10³) = (3.9×10⁴) -(0.57×10⁴) = (3.9 -0.57)×10⁴

  = 3.33×10⁴

_____

With a little practice, you can see the effect on exponents of moving the decimal point. Here, we have ...

  5.7×10³ = (0.57×10)×10³ = 0.57×(10×10³) = 0.57×10⁴

__

When adding or subtracting in scientific notation, all that is required is that the exponents of all the numbers be the same. The hint says make all the exponents be 0. Above, we have chosen to make them all be 4. You could also use 3:

  (3.9×10⁴) -(5.7×10³) = (39×10³) -(5.7×10³) = (39 -5.7)×10³

  = 33.3×10³ = 3.33×10⁴


Related Questions

Review the graph.

On a coordinate plane, a circle has center (4, 0) and radius 4. Another circle has center (2, negative 3) and radius 6. The area inside of the first circle and outside of the second circle between the 2 circles is shaded.

Which system of inequalities is shown in the graph?

36 > (x + 3)2 + (y – 2)2 and 16 > (x – 4)2 + y2
36 > (x – 2)2 + (y + 3)2 and 16 > (x – 4)2 + y2
36 < (x + 3)2 + (y – 2)2 and 16 > (x – 4)2 + y2
36 < (x – 2)2 + (y + 3)2 and 16 > (x – 4)2 + y2

Review the graph.On a coordinate plane, a circle has center (4, 0) and radius 4. Another circle has center

Answers

Answer:

36 < (x - 2)² + (y + 3)² and 16 > (x - 4)² + y²

Step-by-step explanation:

This is because the shaded area is inside the first circle (centered at (4, 0) with a radius of 4) but outside the second circle (centered at (2, -3) with a radius of 6). The inequalities reflect these conditions by setting the inequality signs accordingly. The inequality with "<" for the first circle ensures that the shaded area is within the circle, and the inequality with ">" for the second circle ensures that the shaded area is outside the circle.

Draw an angle in standard position such that the terminal side passes through the given point. (-4, -3)

Answers

Explanation

We are told to draw the angle in the standard position that passes through the point (-4, -3)

In this case,

\(\begin{gathered} x=-4 \\ y=-3 \end{gathered}\)

Draw an angle in standard position such that the terminal side passes through the given point. (-4, -3)

Prove the following

please help

Prove the followingplease help

Answers

Step-by-step explanation:

3. (1 + cos x) (1 − cos x)

Distribute using FOIL.

1 − cos²x

Use Pythagorean identity.

sin²x

4. sin x / (1 − cos x)

Multiply by the conjugate.

sin x (1 + cos x) / ((1 − cos x) (1 + cos x))

Distribute using FOIL.

sin x (1 + cos x) / (1 − cos²x)

Use Pythagorean identity.

sin x (1 + cos x) / sin²x

Divide.

(1 + cos x) / sin x.

Split the fraction.

(1 / sin x) + (cos x / sin x)

csc x + cot x

Let g(x) = -2(3x + 4)(x - 1)(x – 3) be a polynomial function.Part A: Sketch a graph of the polynomial.Part B: Name all the horizontal and vertical intercepts of the graph Part C: State the end behavior of g

Answers

A.

In order to sketch this function, let's first find its zeros, by equating each term in the product with zero:

\(\begin{gathered} -2\mleft(3x+4\mright)\mleft(x-1\mright)\mleft(x-3\mright)=0 \\ \begin{cases}3x+4=0\to x=-\frac{4}{3} \\ x-1=0\to x=1 \\ x-3=0\to x=3 \\ \end{cases} \end{gathered}\)

So the zeros are -4/3, 1 and 3. Since the coefficient of the higher order term is negative (multiplying -2, 3x, x, and x we have -6x^3), the function will decrease after the last zero and increase before the first zero.

Sketching the function, we have:

B.

The horizontal intercepts are the zeros of the function: -4/3, 1 and 3

The vertical intercept is the point where the graph intersects the y-axis, that is, when x = 0:

\(\begin{gathered} g\mleft(0\mright)=-2\mleft(4\mright)\mleft(-1\mright)\mleft(-3\mright) \\ g(0)=-24 \end{gathered}\)

So the vertical intersect is -24.

C.

The end behavior of g(x), since the coefficient of the higher order term is negative, is going to minus infinity.

Let g(x) = -2(3x + 4)(x - 1)(x 3) be a polynomial function.Part A: Sketch a graph of the polynomial.Part

9. A has some amount of money with him. He gave one half of one third from that amount One half of the amount received by B is 20. What is the amount that A originally had?​

Answers

Using the expression 5x/12 = 20, the amount that A originally had was $48.

We have,

Let x be the amount of money that A originally had.

Then, A gave away 1/2 x 1/3 = 1/6 of the amount, which is equal to x/6.

The amount received by B is 1/2 of the remaining amount,

which is (x - x/6)/2 = 5x/12.

We know that 5x/12 = 20,

Solving for x.

5x/12 = 20

5x = 240

x = 48

Therefore,

The amount that A originally had was $48.

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I need help with this question

I need help with this question
I need help with this question

Answers

Answer:

\(sin\theta = \frac{5}{14}\\\\\theta = sin^-1 \frac{5}{14}\\\\\theta = 20.9\)

Option B: 20.9°

help me please

Indicate the method you would use to prove the two triangles. If no method applies, enter "none".
AAS
SSS
NONE
SAS
ASA

help me pleaseIndicate the method you would use to prove the two triangles. If no method applies, enter

Answers

ASA is the correct answer

Based on the information given, we know that the two triangles have two pairs of congruent angles. This is sufficient to prove that the two triangles are congruent using the AAS (Angle-Angle-Side) postulate. Therefore, the method I would use to prove the two triangles congruent is **AAS**.

What equation could be solved using the application of the quadratic formula

I will give brainlest

What equation could be solved using the application of the quadratic formulaI will give brainlest

Answers

Answer:

C   x² - 2x - 1 = 3

Step-by-step explanation:

x² - 2x - 1 = 3

x² - 2x - 4 = 0

a = 1

b = -2

c = -4

x = (-b ±√(b² - 4ac)) / 2a

Answer:

-1+\(\sqrt{x} 5\)

Step-by-step explanation:

Which of the following equations has
infinitely many solutions?
A. 2x + 3 = 5 + 2x
B. 2x + 3 = 5 + 3x
C. 3x - 5 = -5 + 2x
D. 3x - 5 = -5 + 3x

Answers

The One With Inifinetely Many Solutions is D. 3x-5=-5+3x are both the same.Meaning that no matter Which Value u Put For X u will get the same Answer On Both Side
D
Hope this helps you

During tug of war, team A pulls to the East with 24N of force and team B pulls to the West with 32N of force. Which team will win and what is the net force?
Team B, 8N

Team B, 56N

Team A, 56N

Team A, 8N

Answers

Answer: Team B, 8N

Step-by-step explanation: I think it's team be because when doing the problem team a is 24 n to the right while Team B is 32 n to the left, and since they are pointing different directions you would subtract those and then get your answer. Since Team B has the larger force it will be the one to win.

Using the formula for simple interest and the given values, find I.P = $200; r = 9%; t = 3 years; I = ?

Answers

Step 1:

Write interest (I) formula

\(\begin{gathered} I\text{ = }\frac{Prt}{100} \\ P\text{ = principal = \$200} \\ \text{r = rate = 9\%} \\ t\text{ = time = 3 years} \end{gathered}\)

Step 2

\(\begin{gathered} \text{I = }\frac{200\text{ }\times\text{ 9 }\times\text{ 3}}{100} \\ I\text{ = \$54} \end{gathered}\)

Final answer

I = $54

A newspaper article indicated that 43 percent of cars with black seats are white, 46 percent of cars with black seats are blue, 7 percent of cars with black seats are red, and 4 percent of cars with black seats are black. A test was conducted to investigate whether the color of cars with black seats was consistent with the newspaper article. A random sample of cars of these colors was selected, and the value of the chi-square test statistic was x = 8.2. Which of the following represents the p-value for the test?
A) P(x2 ≥ 8.2) = 0.08
B) P(x2 ≥ 8.2) = 0.04
C) P(x2 ≤ 8.2) = 0.96
D) P (x2 = 8.2) = 0.00
E) The p-value cannot be calculated because the sample size is not given.

Answers

Answer:

C) P (X2 ≤ 8.2) = 0.96

Step-by-step explanation:

P value for the test is the probability of obtaining results that have been observed in the null hypothesis statement. A very small value of p indicates that there is unlikely chance of null hypothesis being true which means that we cannot accept null hypothesis based on the small p value.

Answer:

P(χ2≥8.2)=0.04

Step-by-step explanation:

Just took the test. This was correct

a pharagraph on water

Answers

Answer:

Water is the only molecule because of which life is possible on Earth. In outer space, the conditions are so hostile that Water cannot be found in its natural form- liquid. This liquid Water has been giving us sustenance throughout billions of years.

Step-by-step explanation:

mark me brainleit plss

A store bought a sofa wholesale for 200 and marked it up 15% when the sofa did int sell they reduced the price 15% show why the current price is not 200

Answers

Answer:

The current price of sofa is $195.50.

Step by Step explanation:Cost price of the sofa for the store = $200

Now, the store marked it up 15%.

So, marked price of sofa = $200 + 15% of $200

=200 + 30

=$230

Now, it is given that the sofa could not sell at this price. So, the store reduces its price by 15% now.

So, current price of sofa = $230 - 15% of $230

= 230 - 34.5

=$195.5

So, the current price of the sofa is $195.50.

Assume that K and M are two unlinked genes that affect hearing. The dominant K allele is necessary for hearing, and the dominant M allele causes deafness regardless of the other genes present. What fraction of the offspring of parents with the genotypes KkMm and Kkmm will most likely be deaf?

**Please draw the punnet sqaure and explain the answer in detail.

a) 1/4

b) 3/8

c) 1/2

d) 5/8

Answers

The dominant K allele is necessary for hearing, and the dominant M allele causes deafness regardless of the other genes present. What fraction of the offspring of parents with the genotypes KkMm and Kkmm will most likely be deafi is 1/2 so c option is correct

The percentage that the offspring will be deaf is 75%. Two punnet squares are needed each for km and Kkmm individuals. In punnet square 1, half of the genotypes are Km and km while half are Mm and kk in punnet square 2. The two punnet squares are then combined to form a final one where a quarter of the offspring is deaf.

What does genotype mean?

In a wide sense, the word"genotype" refers to the genetic makeup of an organism;  it defines an organism's complete set of genes. In a more thin sense, the term can be used to guide the alleles, or variant forms of a gene, that are carried by an organism.

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High School Geometry

High School Geometry

Answers

The answer is Option E) 11. Since AK and KC are tangents.

We can solve this problem using the property that a tangent to a circle is perpendicular to the radius drawn to the point of tangency.

We have:

\(AK^2\) = AB x AC, and

\(KC^2\) = KB x KC.

Substituting the given values, we get:

\(3^2\) = AB x AC, and

\(4^2\)= KB x 7.

Simplifying, we get:

9 = AB x AC, and

28 = KB x 7.

Dividing the second equation by 7, we get:

KB = 4.

Since BC = KB + KC, we have:

BC = 4 + 7.

Simplifying, we get:

BC = 11.

Therefore, the answer is: e) 11.

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Y / -7 = -3

What does the Y equal​

Answers

Answer:

y=21

Step-by-step explanation:

-3 * -7 = 21

Answer:

21

Step-by-step explanation:

For this question multiply 7  to 3

2. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i and 2-2i.

Review Andrew’s work, identify the error and correct all work from that point forward that is affected by this error. Include at least one sentence explaining his error. Use proper mathematical vocabulary, appropriately.

2. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3,

Answers

The polynomial equation for the given roots is x³-7x²+20x-24=0.

Given that, the polynomial equation of the smallest degree whose roots are 3, 2+2i and 2-2i.

Now, we need to write the polynomial equation.

What is a polynomial equation?

A polynomial equation is an equation where a polynomial is set equal to zero. i.e., it is an equation formed with variables, non-negative integer exponents, and coefficients together with operations and an equal sign. It has different exponents. The highest one gives the degree of the equation. For an equation to be a polynomial equation, the variable in it should have only non-negative integer exponents. i.e., the exponents of variables should be only non-negative and they should neither be negative nor be fractions.

Now, x=3, x=2+2i and x=2-2i

x-3, x-2-2i and x-2+2i

So, the polynomial equation is (x-3)(x-2-2i)(x-2+2i)=0

⇒(x-3)(x(x-2-2i)-2(x-2-2i)+2i(x-2-2i))=0

⇒(x-3)(x²-2x-2xi-2x+4+4i+2xi-4i-4i²)=0

⇒(x-3)(x²-2x-2x+4-4i²)=0

⇒(x-3)(x²-4x+4+4)=0 (∵i²=-1)

⇒(x-3)(x²-4x+8)=0

⇒x(x²-4x+8)-3(x²-4x+8)=0

⇒x³-4x²+8x-3x²+12x-24=0

⇒x³-7x²+20x-24=0

Therefore, the polynomial equation for the given roots is x³-7x²+20x-24=0.

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Answer these questions please i need to pass my grade but i dont know this

Answer these questions please i need to pass my grade but i dont know this

Answers

Ok guys don’t worry I will help you

Here’s a pic

First you got to find the area which is length x width x height.


I can’t attach two papers sorry but here’s the bottom
Answer these questions please i need to pass my grade but i dont know this

How would I complete these answers?

How would I complete these answers?

Answers

so, we can say that therefore, the sample of 20 cheerleaders used for the study provides the solution to the issue.

Describe sample.

A sample is a controlled, abridged version of a bigger group. It is a demographic subset containing characteristics from a larger population. Samples are used in statistical testing when population sizes are too large to accommodate all prospective participants or observers in the experiment.

The 20 cheerleaders that are used as a sample for this study are.

Explanation: Because only 20 cheerleaders were chosen from high schools in California for the research of the banana influence on speed and endurance, the sample available was limited to those 20 cheerleaders. As a result, the sample's results were based on those 20 cheerleaders.

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A total of 27 students are in your class. There are nine more males than females.

How many females are in your class?

Answers

9 females. 18 males.

6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.

Answers

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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List the terms of the polynomial. Give the coefficient of the second term. -4y5 + 6x4 +9w³ - 4w - 1 Separate terms using commas. Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c . Make sure your variables match those in the question. Terms Coefficient​

Answers

The coefficient of the second term, 6x⁴, is 6.

The terms of the polynomial are:

-4y⁵, 6x⁴, 9w³, -4w, -1

The coefficient of the second term, which is 6x⁴, we look at the number in front of the variable term.

The coefficient is 6.

Therefore, the list of terms is:

-4y⁵, 6x⁴, 9w³, -4w, -1

Each term represents a separate component of the polynomial, where the variable is raised to a certain power and multiplied by its coefficient.

The coefficients indicate the scalar value by which each term is multiplied.

The polynomial's terms are -4y5, 6x4, 9w3, -4w, and -1.

Looking at the number in front of the variable term, we can determine the second term's coefficient, which is 6x4.

There is a 6 coefficient.

As a result, the terms are as follows: -4y5, 6x4, 9w3, -4w, and -1.

Each term represents a different part of the polynomial, where the variable is multiplied by its coefficient and raised to a given power.

The scalar value by which each phrase is multiplied is shown by the coefficients.

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It’s takes an aero plane 3.2 hours to fly from Mumbai to Seoul. It takes the same aero plane 1 1/3 hours to fly from Seoul to Tokyo. How many hours does it take the aero plane to travel from Mumbai to Tokyo if it flies through Seoul?

Answers

To find the total time it takes for the airplane to travel from Mumbai to Tokyo via Seoul, we need to add the time taken for the Mumbai-Seoul leg and the Seoul-Tokyo leg.

The airplane takes 3.2 hours to fly from Mumbai to Seoul.

The airplane takes 1 1/3 hours to fly from Seoul to Tokyo, which is equivalent to 1.33 hours.

To find the total time, we add the two durations:

3.2 hours + 1.33 hours = 4.53 hours

Therefore, it takes approximately 4.53 hours for the airplane to travel from Mumbai to Tokyo if it flies through Seoul.

If a new movie is selling for $20, and the local city charges 8% sales tax, how much tax will be charged? $_____

Answers

Answer: $1.6

Step-by-step explanation:

price × percentage of tax=amount of tax

$20 × 8%=20 × 0.08= $1.6

Hope this helps!! :)

The point (0,0) is located on a line with slope of 3/4. which point could also be located on the line?​

Answers

Answer:

Below

Step-by-step explanation:

The equation of the line will be   y = 3/4 x     pick ANY value of 'x' to find the corresponding 'y' value

  Say x = 8    then y = 6        8,6  is  a point on the line

Answer:

(1 , 0.75)

(2 , 1.5)

(3 , 2.25)

(4 , 3)

(5 , 3.75)

(4 , 3)

(6 , 4.5)

(7 , 5.25)

(8 , 6)

(9 , 6.75)

(10 , 7.5)

(11 , 8.25)

(12 , 9)

Step-by-step explanation:

To find the other points we must put the given information into the slope-intercept form: \(y=mx+b\)    m = slope and  b =  y-intercept

                                      \(y=\frac{3}{4} x+0\)  or  \(y=\frac{3}{4} x\)

Then just simply start inputting any numbers for x so you can solve for \(y=\frac{3}{4} x\) to get the other points of the line.

The point (0,0) is located on a line with slope of 3/4. which point could also be located on the line?

ANSWER PLS QUESTION ATTACHED

ANSWER PLS QUESTION ATTACHED

Answers

A parallelogram is an easy quadrilateral with two pairs of parallel aspects. the other or dealing with facets of a parallelogram are of equal length and the other angles of a parallelogram are of equal measure. Hence, proved  p + q = r.

A parallelogram has four sides overall and two pairs of facets that might be parallel. A square is a parallelogram that has four equal sides. the other facets are parallel and all corners of the rectangular shape the right attitude. A rectangle is a parallelogram that has 4 contrary, parallel, congruent aspects.

proving p + q = r;

q = ∠OCD = ∠BAO   ( alternate angle)

In Δ AOB

∠OAb  + ∠DBA = p + q -------------------(1)

& ∠AOD + ∠BOA = 180° ------------(2)

Also,

∠OAB + ∠OBA + ∠BOA = 180° --------- some of angle in a triangle.

⇒ ( p + q) + (180° - ∠BOA) = 180° --------using 1 & 2

⇒  p + q - r = 0

⇒  p + q = r

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Finding Missing Angles in a Polygon

Finding Missing Angles in a Polygon

Answers

The value of x° is 133°.

Given,

Pentagon with angles 107° , 120° , 90° , 90° , x° .

A pentagon is formed by combining three triangles and thus have total of interior angles to be 540°.

Now, to calculate the value of x:

Sum of all interior angles of pentagon = 540°

Put the values of all the angles given in the figure,

120° + 107° + 90° + 90° + x° = 540°

407° + x = 540°

x = 133°

Hence the missing angle is of 133° .

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what are the fact family of 8,9,72

Answers

Answer:

i thinks its 8 times nine or 8x9

Step-by-step explanation:

nan takes 3 minutes to drive the course of a car- rally video game and return to the starting point Claudio takes 4 minutes if they start at the same time, how many minutes will pass until they cross the starting point at the same time​

Answers

Answer:

12 min

Step-by-step explanation:

that's how much time would put nan 1 lap ahead of claudio and them crossing the starting line at the same time

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