i need help me please :(

Answer:

a^2=b^2+c^2- 2bc cosA

64= 36+ 49 - 2(6)(7)cos A

64- 85 = 84cos A

84 cosA= -21

cos A= -21/84

cosA= -0.25

The function is called an if/else statement function lets you test if something is true or false and then do different things depending on which result you get.

An if/else statement is a type of control flow statement that allows a program to execute different instructions depending on the result of a logical expression. The statement begins with an if condition, followed by a set of instructions to be performed if the condition is true. If the condition is false, the program executes the instructions after the optional else statement. The syntax for an if/else statement looks like this: if (condition) { // Instructions to execute if condition is true } else { // Instructions to execute if condition is false } By using an if/else statement, a program can make decisions and perform different actions based on the results of a logical expression.

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Answer:

\( (x - 5)^2 + (y + 2)^2 = 81 \)

Step-by-step explanation:

Standard form of the equation of a circle with center (h, k) and radius r:

\( (x - h)^2 + (y - k)^2 = r^2 \)

Compare it to the given equation, and you get:

\( (x - 5)^2 + (y - (- 2))^2 = 9^2 \)

\( (x - 5)^2 + (y + 2)^2 = 81 \)

Answer:

whole number is the answer

The probabilities of selecting a blue marble and then a red marble, a red marble and then a blue marble, one blue and one red marble, and two red marbles are \($\frac{4}{30}$\), \($\frac{8}{30}$\), \($\frac{12}{30}$\), and \($\frac{2}{30}$\), respectively.

29. The probability of selecting a blue marble and then a red marble is \($\frac{4}{6} \times \frac{2}{5} = \frac{4}{30}$\).

30. The probability of selecting a red marble and then a blue marble is \($\frac{2}{6} \times \frac{4}{5} = \frac{8}{30}$\).

31. The probability of selecting one blue marble and one red marble is \($\frac{4}{6} \times \frac{2}{5} + \frac{2}{6} \times \frac{4}{5} = \frac{12}{30}$\).

32. The probability of selecting two red marbles is

\($\frac{2}{6} \times \frac{1}{5} = \frac{2}{30}$\).

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The equation for the plane consisting of all points that are equidistant from the points (−7, 1, 1) and (3, 3, 5) is 20x + 4y + 8z = -9.

In order to determine the distance of this plane (x, y, z) with the given points, we would use the distance formula.

Mathematically, the distance between three (2) points that are on a coordinate plane can be calculated by using this formula:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

For these points (x, y, z) and (−7, 1, 1), the distance is given by:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Distance = √[(x₂ - (-7))² + (y₂ - 1)² + (z₂ - 1)²]

Distance = √[(x₂ + 7)² + (y₂ - 1)² + (z₂ - 1)²]

By using the algebraic formulas, the expanded expression is given by:

(a - b)² = a² - b² - 2ab

(a + b)² = a² + b² + 2ab

Distance = √[(x² + 14x + 49) + (y² - 2y + 1) + (z² - 2z + 1)]   .......equation 1.

For these points (x, y, z) and (3, 3, 5), the distance is given by:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Distance = √[(x - 3)² + (y - 3)² + (z - 5)²]

Distance = √[(x² - 6x + 9) + (y² - 6y + 9) + (z² - 10z + 25)]    .....equation2.

Since both distances are equidistant, we would equate eqn. 1 and eqn. 2 and then simplify:

√[(x² + 14x + 49) + (y² - 2y + 1) + (z² - 2z + 1)] = √[(x² - 6x + 9) + (y² - 6y + 9) + (z² - 10z + 25)]

(x² + 14x + 49) + (y² - 2y + 1) + (z² - 2z + 1) = (x² - 6x + 9) + (y² - 6y + 9) + (z² - 10z + 25)

x² + 14x + 49 + y² - 2y + 1 + z² - 2z + 1 = x² - 6x + 9 + y² - 6y + 9 + z² - 10z + 25

14x + 6x - 2y + 6y - 2z + 10z + 52 - 43 = 0

20x + 4y + 8z + 9 = 0

20x + 4y + 8z = -9.

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The probability that the sample mean will be less than 200 pounds is approximately 0.9015 or 90.15%.

Step-by-step explanation:

To solve this problem, we can use the central limit theorem, which states that the sampling distribution of the mean of a large sample (n >= 30) will be approximately normal, regardless of the distribution of the population.

We are given that the population mean is 196 pounds and the standard deviation is 22 pounds. The sample size is 50, which is large enough to apply the central limit theorem.

To find the probability that the mean of the sample will be less than 200 pounds, we need to standardize the sample mean using the formula:

z = (x - mu) / (sigma / sqrt(n))

where x is the sample mean, mu is the population mean, sigma is the population standard deviation, and n is the sample size.

Plugging in the values we get:

z = (200 - 196) / (22 / sqrt(50)) = 1.59

Now we need to find the probability that a standard normal variable is less than 1.59. We can use a standard normal table or calculator to find this probability, which is approximately 0.944.

Therefore, the probability that the mean of the sample will be less than 200 pounds is 0.944 or 94.4% (rounded to one decimal place).

So, we can say that there is a 94.4% chance that the mean weight of 50 randomly selected individuals will be less than 200 pounds.

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P(X = 7), λ = 6: The Poisson probability of X = 7, with a parameter (λ) value of 6, is 0.1446. P(X = 11), λ = 12: The Poisson probability of X = 11, with a parameter (λ) value of 12, is 0.0946. P(X = 6), λ = 8: The Poisson probability of X = 6, with a parameter (λ) value of 8, is 0.1206.

The Poisson probability is used to calculate the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate of occurrence (parameter λ). The formula for Poisson probability is P(X = k) = (e^-λ * λ^k) / k!, where X is the random variable representing the number of events and k is the desired number of events.

To calculate the Poisson probabilities in this case, we substitute the given values of λ and k into the formula. For example, for the first case (a), we have λ = 6 and k = 7: P(X = 7) = (e^-6 * 6^7) / 7!

Using a calculator, we can evaluate this expression to find that the probability is approximately 0.1446. Similarly, for case (b) with λ = 12 and k = 11, and for case (c) with λ = 8 and k = 6, we can apply the same formula to find the respective Poisson probabilities.

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The degree measure in radians is -π/4 and the radian measure in degrees is -45°.

To convert a degree measure to radians, we can use the formula: radians = degrees * (π/180).
To convert a radian measure to degrees, we can use the formula: degrees = radians * (180/π).

For the given measure of -45°, we can convert it to radians using the formula:
radians = degrees * (π/180)
radians = -45° * (π/180)
radians = -45π/180
radians = -π/4

To convert -π/4 radians to degrees, we can use the formula:
degrees = radians * (180/π)
degrees = -π/4 * (180/π)
degrees = -45°

Therefore, the degree measure in radians is -π/4 and the radian measure in degrees is -45°.

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Answer:

No, not always. Yes in some cases, like 100 is greater than 0. But -100 is less than zero. So it depends on the number.

Step-by-step explanation:

Answer:

no because any number multiplied by zero is zero

Let the first number be x.

The second number is 5 times less than x => x - 5

Therefore, we can write the statement as

Solving the quadratic equation:

Let us replace -5x in the equation with -4x and -x to be able to factorize.

Hence,

Hence,

Therefore, the number can be 1 or 4.

The second number can be

Therefore, the pair of numbers can be

Answer:

a line with points A and B is True

Answer:

100/360 * 2\(\pi\)5

1000\(\pi\)/360 = 25\(\pi\)/9 = 8.722

Step-by-step explanation:

Answer:

60 because their a 2 induivedinal in 1 sock.

Step-by-step explanation:

30 x 2 = 60

The given quadratic equation is 3x²=2+8xLet’s put this equation in standard form by transposing all the terms on one side.3x²-8x-2=0The standard quadratic equation is ax²+bx+c=0. Therefore, here a=3, b=-8 and c=-2.Let’s substitute these values in the quadratic formula to obtain the solutions of the given equation.

x= {-b±√(b²-4ac)}/2aLet’s plug in the values.x= {-(-8)±√((-8)²-4(3)(-2))}/2(3)x= {8±√(64+24)}/6x= {8±√88}/6x= {8±9.38}/6Now, let’s solve for x by adding and subtracting. x= {8+9.38}/6 and x= {8-9.38}/6x= 2.563 and x= -0.305These are the solutions of the given equation using quadratic formula, correct to the nearest tenth. The solutions are 2.6 and -0.3.

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Answer:  Graph is below

=============================================================

Explanation:

We divide both sides by -4 to isolate p. This will flip the inequality sign.

-16 > -4p

-16/(-4) < -4p/(-4)

4 < p

p > 4

The graph has an open hole at 4 and shading to the right. See below.

The solution of the inequality - 16 > - 4p is shown in number line as given below in figure.

Number line is a horizontal line where numbers are marked at equal intervals one after another form smaller to greater.

Given that;

The inequality is,

⇒ - 16 > - 4p

Now, Solve the inequality as;

⇒ - 16 > - 4p

Multiply by -1;

⇒ 16 < 4p

Divide by 4;

⇒ 4 < p

Thus, The solution of the inequality is,

⇒ 4 < p

And, This is shown in number line.

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Answer:

it has to equal -1 x= to -1 parenthesees

1 times -1= -1 its true for that 1 answer but not the others

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Explanation:

For this problem, we can make a lattice multiplication diagram. Place the digits of 124 across the top of the lattice multiplication box. Then place the digits along the right hand side of the box. Refer to figure 1 in the diagram below. I've color-coded the alternating bands of diagonals to help be able to add the values we need.

In figure 2, I multiplied all of the outer header single-digit values to get two-digit results. For instance, in the bottom right corner we have 4*3 = 12. Note how the 1 and the 2 of "12" is broken up like you see in figure 2. It's important to separate out the digits like this.

This is because we'll be adding along the diagonal color bands. The 2 in the white triangle in the very bottom right corner is the last digit of the product. This matches with 64086e2 having 2 as the last digit.

Then we add along the diagonal pink color band getting 6+1+2 = 9. This is the digit e. So e = 9 (refer to figure 3). The number 64086e2 updates to 6408692

We could keep going with the lattice process, but I'll stop here and move onto the next section below.

---------------------------------------------

Let m = 6408692

We can do trial and error to determine what d must be equal to. The list of choices we have are {0,1,2,3,4,5,6,7,8,9}

So let's go through those possible values of d

Since d = 6 and e = 9, this means d+e = 6+9 = 15.

The particular solution to the given initial value problem is given by y(x) = -65/22\(e^{4x}\) + 137/18\(e^{2x}\) + 34/99\(e^{-7x}\)

The initial value problem is y''' - 8y'' + 23y' - 28y = 0, y(0) = 5, y'(0) = 1.

Let y' = r, y'' = r², y''' = r³.

The characteristic equation of the given differential equation is r³ - 8r² + 23r - 28 = 0.

Factoring the characteristic equation yields (r - 4)(r - 2)(r + 7) = 0.

Equating the all factor equal to zero.

This yields the three roots r₁ = 4, r₂ = 2, and r₃ = -7.

The general solution to the given differential equation is then given by y(x) = c₁\(e^{4x}\) + c₂\(e^{2x}\) + c₃\(e^{-7x}\)..............(1)

At y(0) = 5, put x = 0 in equation 1

y(0) = c₁\(e^{4\cdot 0}\) + c₂\(e^{2\cdot 0}\) + c₃\(e^{-7\cdot 0}\)

c₁\(e^{0}\) + c₂\(e^{0}\) + c₃\(e^{0}\) = 5

c₁ + c₂ + c₃ = 5..............(A)

Now differentiate the equation 1

y'(x) = 4c₁\(e^{4x}\) + 2c₂\(e^{2x}\) - 7c₃\(e^{-7x}\)..............(2)

At y'(0) = 1, put x = 0 in equation 2

y'(0) = 4c₁\(e^{4\cdot 0}\) + 2c₂\(e^{2\cdot 0}\) - 7c₃\(e^{-7\cdot 0}\)

4c₁\(e^{0}\) + 2c₂\(e^{0}\) - 7c₃\(e^{0}\) = 1

4c₁ + 2c₂ - 7c₃ = 1..............(B)

Now differentiate the equation 2

y''(x) = 16c₁\(e^{4x}\) + 4c₂\(e^{2x}\) + 49c₃\(e^{-7x}\)..............(3)

At y''(0) = 0, put x = 0 in equation 2

y''(0) = 16c₁\(e^{4\cdot 0}\) + 4c₂\(e^{2\cdot 0}\) + 49c₃\(e^{-7\cdot 0}\)

16c₁\(e^{0}\) + 4c₂\(e^{0}\) + 49c₃\(e^{0}\) = 0

16c₁ + 4c₂ + 49c₃ = 0..............(C)

Using the initial conditions, we get the following system of equations:

c₁ + c₂ + c₃ = 5

4c₁ + 2c₂ - 7c₃ = 1

16c₁ + 4c₂ + 49c₃ = 0

Solving this system of equations yields c₁ = -65/22, c₂ = 137/18, and c₃ = 34/99.

Therefore, the particular solution to the given initial value problem is given by

y(x) = -65/22\(e^{4x}\) + 137/18\(e^{2x}\) + 34/99\(e^{-7x}\)

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The complete question is:

Solve the given initial value problem y'''-8y''+23y'-28y = 0; y(0)=5, y'(0)=1, y''(0)=0.

Answer: Answer is 7.00

Step-by-step explanation: i did this i got right answer...  please likes, 5 star     have great day :)

The diameter of Earth in kilometers is approximately 12,682 km, making option D the correct answer.

To convert the diameter of Earth from miles to kilometers, we can multiply the given diameter in miles by the conversion factor of 1.6 kilometers per mile.

Given that Earth's diameter is 7,926 miles, we can calculate its diameter in kilometers as follows:

Diameter in kilometers = Diameter in miles × Conversion factor

Diameter in kilometers = 7,926 miles × 1.6 kilometers/mile

Diameter in kilometers = 12,681.6 kilometers

Rounding this value to the nearest whole number, we get 12,682 kilometers.

Therefore, the correct answer is option D: 12,682 km.

Option A: 49,553 km is not the correct answer. It is not consistent with the given diameter of Earth.

Option B: 120,586 km is also not the correct answer. It is not consistent with the given diameter of Earth.

Option C: 1,392,650 km is significantly larger than the actual diameter of Earth and is not a plausible value.

In conclusion, the diameter of Earth in kilometers is approximately 12,682 km, making option D the correct answer.

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The value of f(5 + h) - f(5)h when h =0 is 60.

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

f(x) = 12x

Now,

f(5 + h) = 12 (5 + h) = 60 + 12h

f(5) = 12 x 5 = 60

Now,

f(5 + h) - f(5)h

= 60 + 12h - 60h

h = 0

= 60 + 0 - 0

= 60

Thus,

The value of the limit is 60.

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The average rate of change in horsepower per unit speed when race car increases its speed from 80 mph to 100 mph is option B. 0.61.

Function H(s) = 0. 003s² + 0. 007s - 0. 027

H(s) is the horsepower.

The average rate of change in horsepower per unit speed is ,

Slope of line that passes through two points on graph of the function H(s) corresponding to speeds of 80 mph and 100 mph.

The horsepower at 80 mph is,

H(80) = 0.003(80)² + 0.07(80) - 0.027

          = 24.773

And the horsepower at 100 mph is,

H(100) = 0.003(100)² + 0.07(100) - 0.027

           = 36.973

So, the change in horsepower over the interval of speeds from 80 mph to 100 mph is,

ΔH = H(100) - H(80)

     = 36.973 - 24.773

      = 12.2

The change in speed over the same interval is equal to,

Δs = 100 - 80

    = 20

The average rate of change in horsepower per unit speed over this interval is equal to

ΔH/Δs = 12.2/20

           = 0.61

Therefore, the average rate of change in horsepower per unit speed is equal to option B. 0.61.

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The above question is incomplete, the complete question is:

The horsepower, H(s), required for a racecar to overcome wind resistance is given by the function: H(s) = 0.003s²+0.07s-0.027, where (s) is the speed of the car in miles per hours. What is the average rate of change in horsepower per unit speed if the race car increases in speed from 80 mph to 100 mph?

A 1.64 B. 0.61 C. 12.2 D. 20.0

Step-by-step explanation:

The real part (red) and imaginary part (blue) of the Riemann zeta function along the critical line Re(s) = 1/2. The first non-trivial zeros can be seen at Im(s) = ±14.135, ±21.022 and ±25.011. The Riemann hypothesis, a famous conjecture, says that all non-trivial zeros of the zeta function lie along the critical line.

It will take 5 months for Eduardo and Peta to weigh the same.

Eduardo weighs 120 pounds and is gaining 5 pounds each month, so after 1 month he will weigh 120 + 5 = 125 pounds.

After 2 months he will weigh 125 + 5 = 130 pounds.

This pattern continues, so after n months he will weigh 120 + 5n pounds.

Peta weighs 160 pounds and is losing 3 pounds each month, so after 1 month she will weigh 160 - 3 = 157 pounds.

After 2 months she will weigh 157 - 3 = 154 pounds.

This pattern continues, so after n months she will weigh 160 - 3n pounds.

We want to find the number of months it will take for Eduardo and Peta to weigh the same, so we set the expressions for their weights equal to each other and solve for n:

120 + 5n = 160 - 3n

8n = 40

n = 5

It will take 5 months for Eduardo and Peta to weigh the same.

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Answer:

It's 5,-5 because you always put the x axis numbers first.

Step-by-step explanation: