Answers
We are given that a block is pushed upwards vertically by a force that has an angle of 25 degrees. To determine the work done by the force "F" we will first add the forces in the vertical direction:
\(\Sigma F_v=F_v-mg-F_f\)Where:
\(\begin{gathered} F_v=\text{ vertical component of the force} \\ m=\text{ mass of the block} \\ F_f=\text{ friction force} \\ g=\text{ acceleration of gravity} \end{gathered}\)Now, we determine the vertical component of the force. To do that we will use the trigonometric function sine since it is defined as:
\(\sin 25=\frac{F_v}{F}\)Now we multiply both sides by the force "F":
\(F\sin 25=F_v\)Now we replace this in the sum of vertical forces:
\(\Sigma F_v=F\sin 25-mg-F_f\)To determine the friction force we will use the following relationship:
\(F_f=\mu N\)Where:
\(\begin{gathered} \mu=\text{ coefficient of friction} \\ N=\text{ normal force} \end{gathered}\)The coefficient of friction is given therefore, we need to determine the magnitude of the normal force. To do that we will add the forces in the horizontal direction:
\(\Sigma F_h=N-F_h\)We determine the horizontal component of the force using the trigonometric function cosine:
\(\cos 25=\frac{F_h}{F}\)Now we multiply both sides by "F":
\(F\cos 25=F_h\)Now we substitute in the sum of forces:
\(\Sigma F_h=N-F\cos 25\)Since there is no movement in the horizontal direction the sum of the forces must be equal to zero:
\(N-F\cos 25=0\)Now we solve for N by adding "Fcos25" to both sides:
\(N=F\cos 25\)Now we substitute this value in the relationship for friction:
\(F_f=\mu F\cos 25\)Now we substitute the friction force in the vertical sum of forces:
\(\Sigma F_v=F\sin 25-mg-\mu F\cos 25\)Since the velocity is constant this means that the acceleration is zero and therefore, the sum of the forces is zero:
\(F\sin 25-mg-\mu F\cos 25=0\)Now we solve for "F". To do that we will add "mg" to both sides:
\(F\sin 25-\mu F\cos 25=mg\)Now we take "F" as a common factor:
\(F(\sin 25-\mu\cos 25)=mg\)Now we divide by the factor of "F":
\(F=\frac{mg}{\sin25-\mu\cos25}\)Now we substitute the given values:
\(F=\frac{(5kg)(9.8\frac{m}{s^2})}{\sin 25-(0.3)\cos 25}\)Solving the operations:
\(F=325.42N\)Now, to determine the work done by the force we use the following formula:
\(W=Fd\)Where:
\(\begin{gathered} F=\text{ force} \\ d=\text{ distance} \end{gathered}\)Substituting the values we get:
\(W=(325.42N)(3m)=976.27J\)Therefore, the work done by the force is 976.27 Joules.
Now we determine the work done by gravity. This is equivalent to the work done by the weight therefore, it is:
\(W_g=\text{mgd}\)Where "m" is mass, and "g" is the acceleration of gravity. Their product is the weight.
Substituting the values:
\(W_g=(5\operatorname{kg})(9.81\frac{m}{s^2})(3m)\)Solving we get:
\(W_g=147.15J\)The magnitude of the work done by gravity is 147.15 Joules.
Finally, to determine the normal force we use the equation we got from the sum of forces in the horizontal direction:
\(N=F\cos 25\)Now we substitute the value we found for "F":
\(N=(325.42N)(\cos 25)=294.93N\)Therefore, the normal force is 294.93 Newtons.
Related Questions
A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block
Answers
1. Calculating the horizontal component of the applied force:
Horizontal component = 3.07 N * cos(32.0°)
Horizontal component ≈ 2.597 N
2. Calculating the acceleration of the block:
Acceleration = Horizontal component / Mass
Acceleration = 2.597 N / 1.35 kg
Acceleration ≈ 1.925 m/s²
Therefore, the acceleration of the block is approximately 1.925 m/s².
How do you know that light travels faster than
sound? (Hint: Give an example of something that
produces sound and light at the same time.)
Answers
Answer:
Explanation:
Answer
How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.# Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.
#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.
50 Joules of work in 25 seconds. How much power did she use?
Answers
P(W) = E(J) / t(s)
50/25=2
A basketball is thrown for a free throw at 10m/s an angle of 20 degrees, makes it into the hoop and lands on the ground. Find the initial velocity in the y direction. ??????????
Answers
Answer:
2
Explanation:
because uWU
Answer:no answer
Explanation:
Cause ur weird
how would you define an ocean current?
Answers
Answer:
i would describe an ocean current like a pull of the water
Explanation:
water
Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life. Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life
Answers
Memoir is a type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life.
Because it combines elements of creative writing with the relation of facts required to produce a work of nonfiction, narrative nonfiction is a type of writing that is occasionally referred to as creative nonfiction. This genre comprises of writing that is factually accurate yet written with a creative flair that contributes to improving the work's flow and appeal. The genre of narrative nonfiction can include journalism and some genres of biography, essay, memoir, and personal essay. When compared to plain nonfiction, this genre is very new, and as the genre has developed, so too has the scrutiny that is applied to this kind of writing.
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What is the difference between sounds that have the same pitch and loudness?
PLEASE HURRY
A)the standing wave
B) the natural frequency
C) the sound quality
D) the resonance
Answers
Answer:
B) the natural frequency
Explanation:
The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
sound quality
Explanation:
The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
PLEASE HELP ASAP
a boy swings a bucket containing 2.4 kg of water in a vertical circle of radius 0.6 m at a constant rotational rate of 1 revolution every 1.4 seconds. Find the following quantities:
the angular speed of water in rad/sec
the tangential speed of the water in meters/sec
Answers
Answer:
a) ω = 4.49 rad/s
b) v = 2.69 m/s
Explanation:
a) The angular speed can be found by using the rotational rate:
\( \omega = \frac{1 rev}{1.4 s}*\frac{2\pi rad}{1 rev} = 4.49 rad/s \)
Hence, the angular speed is 4.49 rad/s.
b) The tangential speed is given by:
\( v = \omega*r = 4.49 rad/s*0.6 m = 2.69 m/s \)
Therefore, the tangential speed is 2.69 m/s.
I hope it helps you!
The surface of the exit road is horizontal, not banked. (See figure.) If the static
friction between the tires and the surface of the road is us = 0.688 and the
maximum speed with which the car can exit the highway safely without sliding is
25.2 m/s, what is the radius of curvature of a highway exit, r?
Answers
The radius of curvature of the highway exit is approximately 220 km.
To find the radius of curvature of the highway exit, we can use the centripetal force equation:
F = mv^2 / r
where F is the maximum static friction force, m is the mass of the car, v is the maximum safe speed, and r is the radius of curvature.
We can solve for r by rearranging the equation:
r = mv^2 / F
Substituting the given values, we have:
r = (1000 kg)(25.2 m/s)^2 / (0.688)
r = 2.20 x 10^5 m
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Select the statement(s) that accurately illustrate examples of energy transfer by radiation.
Heat emitted from a candle
Ocean waves on the surface of the sea Microwaves from a microwave oven
Radio waves transmitted between towers Sound waves from a car radio
Answers
Heat emitted from a candle, Microwaves from a microwave oven, Radio waves transmitted between towers, Sound waves from a car radio.
Illustrate examples of energy transfer by radiation?The examples of energy transfer by radiation mentioned above are heat, microwaves, radio waves, and sound waves. Heat is the transfer of thermal energy from one object to another, usually through the process of convection, conduction, or radiation. Heat emitted from a candle is an example of energy transfer by radiation.Microwaves are electromagnetic waves that are used to heat food in a microwave oven. The microwaves are generated by an oscillating electric current and then radiated into the oven, where they are absorbed by the food. This energy is then converted into heat, which cooks the food. Radio waves are used to transmit information between towers, such as those used for cellular phone communication. The towers emit radio waves, which travel through the air, and the information they contain is then picked up by the towers on the other end. Sound waves are also a form of energy transfer by radiation. When a car radio is playing, sound waves are emitted from the radio, which then travel through the air to your ears. The process of energy transfer by radiation is called electromagnetic radiation. This is the process by which energy is transferred from one place to another in the form of electromagnetic waves. Examples of electromagnetic radiation include visible light, infrared radiation, ultraviolet radiation, x-rays, and gamma rays.To learn more about the examples of energy transfer by radiation refer to:
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If an astronaut was on a planet 9*10^10 meters away, how long would it take a radio signal (in seconds) to travel from them to Earth? (Be sure to give your answer to two decimal places)
Answers
The time taken a radio signal to travel form the given distance to Earth is \(2.65 \times 10^8 \ s\).
The given parameters;
distance between the astronaut and Earth, d = 9 x 10¹⁰ mThe time taken a radio signal to travel form the given distance to Earth is calculated by using Echo formula as shown below;
\(2d = v \times t\\\\t = \frac{2d}{v}\)
where;
v is the speed of sound sound in air = 340 m/st is the time taken for the signal to be heard (to and fro)The time taken for the signal to travel in a single forward motion is calculated as;
\(t = \frac{1}{2} \times \frac{2d}{v} = \frac{d}{v} \\\\t = \frac{9\times 10^{10}}{340} \\\\t = 2.65 \times 10^8 \ s\)
Thus, the time taken a radio signal to travel form the given distance to Earth is \(2.65 \times 10^8 \ s\).
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Suppose that at point A the object traveled in a straight line at constant speed towards B'. In what direction must a force be applied to force the object back towards B? Draw an arrow on the diagram in the direction of the required force.
Answers
By knowing how circular motion works, we know that the force must point radially inwards, a diagram can be seen at the end of the answer.
In order to go from A to B, the object should travel along the circle shown.
So the acceleration must be applied in order to have circular motion, this means that the force (thus the acceleration) must be centripetal, so it must point radially inwards (perpendicular to the velocity of at point A, which is tangential to the circle)
The diagram is shown below, the force just must point radially inwards, and the magnitude of the force will depend on the radius of the circle and the mass of the object.
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A car with a 450 kg mass is accelerated at 2.5 m/s2. (a) What is the force causing this acceleration
Answers
Answer:
The answer is 1125 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × accelerationFrom the question we have
force = 450 × 2.5
We have the final answer as
1125 NHope this helps you
Answer: 1125 N
Remember the formula: force = mass x acceleration.
The car has a mass of 450 kilograms.
We have to multiply this number by 2.5.
450 x 2.5 = 1125
Put the N sign at the end for North, and you have an answer.
1125 N
A 3250 kg car slows down from 20.0 m/s to a stop in 5.33 s. How much force would be required to stop the car?
Answers
The force required to stop the car of mass 3250 kg is -12195.12 N.
What is force?Force is the product of mass and acceleration.
To calculate the force required to stop the car, we use the formula below
Formula:
F = m(v-u)/t.....................Equation 1Where:
F = Force required to stop the carm = Mass of the carv = Final speedu = Initial speedt = TimeFrom the question,
Given:
m = 3250 kgv = 0 m/su = 20 m/st = 5.33 sSubstitute these values into equation 1
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How does solar weather affect Earth’s magnetosphere? Select the two correct answers.
It causes geomagnetic storms.
It generates auroras.
It develops solar wind.
It forms radiation belts.
Answers
A geomagnetic storm occurs when the solar wind collides with the electromagnetic field of the earth generating disturbances in the Earth's magnetosphere.
An aurora is a luminescent formation produced by the interaction of charged solar particles and the terrestrial electromagnetic field. The solar wind pushes these particular to the terrestrial electromagnetic field that later transports them to the poles, where they are seen in different colors according to the type of particle.
When putting the ball on the tee you want half of the golf ball to _________.
Question 1 options:
be above the club
be below the club
be in front of the club
be behind the club
Answers
Answer:
be in front of the club
Explanation:
The ball should be highest off the ground for a driver. The general recommendation is that the bottom of the golf ball on a tee should be level with the top of the driver; for long and mid-irons, push the tee into the ground so that only about a quarter-inch is above ground.
On the average, in a ferromagnetic domain, permanent atomic magnetic moments are aligned ____ to one another.a. antiparallel b. parallel c. perpendicular d. alternately parallel and antiparallel e. randomly relative
Answers
Answer:
b. parallel
Explanation:
Ferromagnetism is a magnetism that is associated with iron and cobalt and nickel. Ferromagnetisms material are magnetics easily and in strong magnetic fields are magnetized by a defined limit called a situation. The force keeps magnetic moments of many atoms parallel to each other.One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?
Answers
Answer:
The diameter is \(d = 8.18*10^{-19} \ m\)
Explanation:
From the question we are told that
The value of one atomic mass unit is \(u = 1.66 *10^{-27} \ kg\)
The density of the proton is \(\rho = 5.8 *10^{27} \ kg/m^3\)
Generally the volume of the proton (sphere)is mathematically represented as
\(V = \frac{4}{3} * \pi * r^3\)
Generally this volume can also be evaluated as
\(V = \frac{u}{\rho}\)
=> \(V = \frac{1.66 *10^{-27}}{5.8*10^{27}}\)
=> \(V = 2.862 *10^{-55} \ m^3\)
So
\(2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3\)
=> \(r^3 = 6.832 *10^{-56}\)
=> \(r = 4.088 *10^{-19} \ m\)
Now the diameter is mathematically represented as
\(d = 2 * r\)
=> \(d = 2 * 4.088 *10^{-19}\)
=> \(d = 8.18*10^{-19} \ m\)
If a bicyclist, with initial speed of zero, steadily gained speed until reaching a final speed of 13m/s, how far would she travel during the race (in the same amount of time)?
Answers
Answer:
The distance travel during race is 13 m.
Explanation:
Given that,
Initial speed = 0
Final speed = 13 m/s
Unit time = 1 sec
We need to calculate the distance travel during race
Using formula of distance
\(d=vt\)
Where, d = distance
v = velocity
t = time
Put the value into the formula
\(d=13\times1\)
\(d=13\ m\)
Hence, The distance travel during race is 13 m.
The kinetic energy possessed by an object in motion is determined by which factor(s)?
A.The object's velocity and mass
B.The object's height and mass
C.The object's velocity only
D.The object's mass only
Answers
Answer:hiii
Explanation:
A lorry of mass 2000kg moving with a speed of 50kmh' collides with a drum of mass 25kg at a police checkpoint. The velocity of the lorry after the impact is 34kmh'. What is the velocity of the drum?
Answers
The velocity of the drum after the collision with a lorry of 2000 kg mass is determined as 1,280 km/h.
What is the velocity of the drum?The velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the lorrym₂ is the mass of the drumu₁ and u₂ are the initial velocitiesv₁ and v₂ are the final velocitiesThe velocity of the drum after the collision is calculated as;
2000 (50) + 25(0) = 2000(34) + 25v₂
100,000 = 68,000 + 25v₂
25v₂ = 32,000
v₂ = 32,000/25
v₂ = 1,280 km/h
Thus, the final velocity of the drum after the collision is calculated by applying the principle of conservation of linear momentum.
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The velocity of the drum after the collision, given that a 2000 kg lorry moving with a speed of 50 Km/h collides with it, is 1280 Km/h
How do I determine the velocity of the drum after collision?The following data were obtained from the question given above:
Mass of lorry (m₁) = 2000 KgInitial velocity of car (u₁) = 50 Km/hMass of drum (m₂) = 25 KgInitial velocity of truck (u₂) = 0 Km/hFinal velocity of lorry (v₁) = 34 Km/hFinal velocity of drum (v₂) = ?The law of conservation of linear momentum states as follow:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Inputting the given parameters, the velocity of the drum after the collision can be obtain as follow:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2000 × 50) + (25 × 0) = (2000 × 34) + (25 × v₂)
100000 + 0 = 68000 + 25v₂
Collect like terms
25v₂ = 100000 - 68000
25v₂ = 32000
Divide both sides by 25
v₂ = 32000 / 25
v₂ = 1280 Km/h
Thus, the velocity of the drum after collision is 1280 Km/h
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Jacob Grena raises a spoon 0.210 m above a table . If the spoon and its contents have a mass of 30.0 g, what is the gravitational potential energy associated with the spoon at that height relative to the table's surface?
Answers
Explanation:
The spoon is raised so it gains Gravitational potential energy. Formula to find Gravitational potential energy;
Gravitational potential energy = mass × Gravitational field strength × height of the body from the surface (table in this scenario)
In symbols; E = m×g×h
Substitute values:
m = 30g = 0.03kg (don't forget to convert grams to kg)
g = 10N/kg
h = 0.210 m
So it's;
0.03kg × 10N/kg × 0.210m = 0.063 Joules
SI Unit of energy is joules
HELP ASAP PLS!!!
when you see a full moon, what type of tides do you expect there to be?
Answers
Answer:
Spring High Tide
When the moon is full or new, the gravitational pull of the moon and sun are combined. At these times, the high tides are very high and the low tides are very low.
How much force is necessary to raise a 150n crate up a ramp to a 4m loading dock if 600 j or work are performed
Answers
Answer:
To solve this problem, you can use the formula for work, which is work = force x distance. In this case, the distance the crate is moved is the height of the loading dock, or 4 meters. The amount of work performed is given as 600 joules. So, you can set up the equation like this:
600 joules = force x 4 meters
To solve for the force, you can divide both sides of the equation by 4 meters:
600 joules / 4 meters = force x 4 meters / 4 meters
This simplifies to:
150 newtons = force
So, the force necessary to raise the 150-newton crate up the ramp to the 4-meter loading dock is 150 newtons.
An object is moving to the right and experiencing a net force that is Directed to the right .the magnitude of force is decreasing with time the speed of object is
Answers
Answer:
hdggdskjn ijwzsa
Explanation:
how often the earth magnetism change
Answers
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
Answers
Advantages of Components Arranged in Series:
1. Increased resistance: Connecting components in series increases the overall resistance in the circuit. This can be advantageous in situations where you want to limit the flow of current or control the amount of power being dissipated.
2. Voltage sharing: In a series circuit, the total voltage of the power supply is divided among the components. This can be useful when you want to ensure that each component receives a specific voltage.
3. Current consistency: The current remains the same throughout the series circuit, which can be beneficial when you need to ensure a consistent current flow through multiple components.
Disadvantages of Components Arranged in Series:
1. Reduced brightness or performance: As mentioned in the question, when light bulbs are connected in series, the increased resistance reduces the flow of current, resulting in dimmer bulbs or reduced performance in other electrical devices.
2. Single point of failure: If one component in a series circuit fails, it can disrupt the entire circuit and cause all components to stop functioning.
Advantages of Components Arranged in Parallel:
1. Brightness and performance: When components such as light bulbs are connected in parallel, each component receives the full voltage, resulting in brighter bulbs and better performance in other devices.
2. Redundancy: In a parallel circuit, if one component fails, the other components can continue to function independently. This provides redundancy and ensures that the failure of one component does not affect the others.
3. Increased current capacity: Parallel arrangement allows the circuit to handle higher currents, which can be useful in situations where high power or heavy loads are required.
Disadvantages of Components Arranged in Parallel:
1. Increased complexity: Parallel circuits require more wiring and connections, which can make the circuit more complex and harder to manage.
2. Higher cost: Parallel circuits may require more components and wiring, resulting in higher costs for materials and installation.
It's important to consider the specific requirements and constraints of the application when deciding whether to arrange components in series or parallel. Each configuration has its advantages and disadvantages, and the choice depends on factors such as desired current flow, voltage distribution, and reliability.I
Very large forces are produced in joints when a person jumps from some height to the ground. (a) Calculate the magnitude of the force (in N) produced if a 62.0 kg person jumps from a 0.800 m-high ledge and lands stiffly, compressing joint material 1.50 cm as a result. (Be certain to include the weight of the person.) N (b) In practice the knees bend almost involuntarily to help extend the distance over which you stop. Calculate the magnitude of the force (in N) produced if the stopping distance is 0.300 m. N (c) Compare both forces with the weight of the person.
Answers
Answer:
a) F = 3.3 10⁴ N, b) F = 2.2 10³ N, c) force when rigid is 15 times greater than when bending the knees
Explanation:
For this exercise we can use the relationship between work and the variation of kinetic energy
K₀ = ½ m v²
the final kinetic energy is zero because the person is stationary
W = (∑ F) x
W = W x - F w
the weight is in the same direction of the displacement therefore the work is positive and the force applied, by the floor, is in the opposite direction to the displacement, consequently the work is negative
we substitute
( W- F ) x = 0-K₀
F = W + K₀ /x
F = mg + \(\frac{1}{2} \frac{mv^2 }{2x}\)
F = m ( g+ \(\frac{v^2 }{2x }\) )
Let's use kinematics to find the velocity of the person when reaching the floor
v² = v₀² - 2g (y + y₀)
the initial velocity is true and when reaching the ground y = 0
v² = -2 g (0-yo)
we calculate
v = \(\sqrt{2 ] 9.8 \ 0.800}\)
v = - 3.96 m/s
the direction of this velocity is vertical down
let's calculate
a) x = 1.50 cm = 0.0150 m
F = 62.0 (3.96² / 2 0.0150 + 9.8)
F = 3.3 10⁴ N
b) x = 30 cm = 0.30 m
F = 62.0 (3.96² / 2 0.30 + 9.8)
F = 2.2 10³ N
c) to compare the force let's look for the relationship between the two
\(\frac{F_{rigid} }{ F_{flexible} }\) = 3.3 10⁴ / 2.2 10³
\frac{F_{rigid} }{ F_{flexible} } = 15
therefore see that the force when rigid is 15 times greater than when bending the knees
A string with a length of 6.2 m is vibrated at its natural frequency (first harmonic). What is the wavelength of the produced standing wave?
3.1 m
6.2 m
12.4 m
18.6 m
Answers
Answer:
12.4m
Explanation:
Given
Length of string = 6.2m
L = λ/2 (for natural frequency (first harmonic)
λ = 2L
λ = 2(6.2)
λ = 12.4m
Hence the wavelength of the produced standing wave is 12.4m
Your new weed-cutter requires, as fuel, a gas-to-oil mixture of 20-to-1 (20 parts of gas mixed with one part of oil). You have 1/2 of a gallon of gas. How much oil, in gallons, should you add to make it all into fuel for the weed-cutter?
Answers
This ratio specifies how much oil should be added to how much new, standard unleaded gasoline (having no more than 10% ethanol). There is a 40:1 ratio for all Remington 2-cycle products.
How much oil should I put in a gallon of gas?This ratio specifies how much oil should be added to how much new, standard unleaded gasoline (having no more than 10% ethanol). There is a 40:1 ratio for all Remington 2-cycle products.Accordingly, for every gallon of gasoline you need add 3.2 oz of oil.Every two-cycle gas trimmer under the Weed Eater brand uses a 40:1 gas to oil ratio.This is equivalent to 3.2 ounces of oil to a gallon of standard fuel.With no more than 10% alcohol, the gas must be 87 octane.Once all of this is considered, especially the possibility of a lengthy oil change, many automobile owners find it wise to add oil whenever the dipstick indicates a low level.Don't wait until it has completely descended.To lean more about gallon of gas refer
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