Answers
In scientific notation, the correct format is a x 10ᵇ, where an is an integer or decimal number whose absolute value is more than or equal to one and less than ten, or 1 ≤ |a| ≤ 10. In order for the scientific notation to be mathematically identical to the original number, b must be a power of 10.
For (a),
1 / 0.00032 = ( 1 / 32 × 10⁻⁵ )
1 / 0.00032 = 10⁵ / 32
1 / 0.00032 = 0.03125 × 10⁵
1 / 0.00032 = 3.125 × 10
(b) 10³ / 10⁻³
10³ / 10⁻³ = [ 10³ / (1 / 10³) ]
10³ / 10⁻³ = 10³ × 10³
10³ / 10⁻³ = 1 × 10⁶
(c) 10³ / 10³
10³ / 10³ = 10³ × 10⁻³
10³ / 10³ = 10⁰
10³ / 10³ = 1 × 10⁰
(d) 1/55000
1/55000 = 1 / (55 × 10³)
1/55000 = 0.01818 × 10⁻³
1/55000 = 1.818 × 10⁻⁵
(e) (10⁵)(10⁴)(10⁻⁴) / 10⁻²
(10⁵)(10⁴)(10⁻⁴) / 10⁻² = ( 10⁵ ⁺ ⁴ ⁻ ⁴ ) / 10⁻²
(10⁵)(10⁴)(10⁻⁴) / 10⁻² = ( 10⁵ ) / (1/10²)
(10⁵)(10⁴)(10⁻⁴) / 10⁻² = ( 10⁵) × (10²)
(10⁵)(10⁴)(10⁻⁴) / 10⁻² = 10⁵ ⁺ ²
(10⁵)(10⁴)(10⁻⁴) / 10⁻² = 1 × 10⁷
(f) 43.2 / (4.32 × 10⁻⁵ )
43.2 / (4.32 × 10⁻⁵ ) = 43.2 / (4.32 × 10 × 10⁻⁶ )
43.2 / (4.32 × 10⁻⁵ ) = 43.2 / (43.2 × 10⁻⁶ )
43.2 / (4.32 × 10⁻⁵ ) = 1 / 10⁻⁶
43.2 / (4.32 × 10⁻⁵ ) = 1 / (1/10⁶)
43.2 / (4.32 × 10⁻⁵ ) = 1 × 10⁶
(g) (4.32 × 10⁻⁵ ) / 432
(4.32 × 10⁻⁵ ) / 432 = ( 432 × 10⁻² × 10⁻⁵ ) / 432
(4.32 × 10⁻⁵ ) / 432 = ( 10⁻² × 10⁻⁵ )
(4.32 × 10⁻⁵ ) / 432 = 10⁻²⁻⁵
(4.32 × 10⁻⁵ ) / 432 = 10⁻⁷ = 1 × 10⁻⁷
(h) 1 / (10⁵)(10⁻⁶)
1 / (10⁵)(10⁻⁶) = 1 / ( 10⁵⁻⁶ )
1 / (10⁵)(10⁻⁶) = 1 / 10⁻¹
1 / (10⁵)(10⁻⁶) = 1 / ( 1/10)
1 / (10⁵)(10⁻⁶) = 10
1 / (10⁵)(10⁻⁶) = 1 × 10¹
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Related Questions
The modernization of tennis occurred in which
country?
Answers
Answer:
The International Lawn Tennis Federation, now known simply as the International Tennis Federation, the sport's governing body, was founded in 1913, composed of 13 national tennis associations. The Modern Olympics , growing out of the ancient tradition, resurfaced under the direction of the International Olympic Committee in Athens in 1896.
Explanation:
8. Does the independent variable or dependent variable affect
an experiment more? Why?
Answers
Answer: In an experiment, both the independent variable and the dependent variable play crucial roles, but they have different impacts.
The independent variable is the variable that is manipulated or controlled by the experimenter. It is intentionally changed or varied to observe its effect on the dependent variable. The independent variable is typically seen as having a greater influence on the experiment because it is intentionally altered to determine the cause or influence of the observed changes.
On the other hand, the dependent variable is the variable that is measured or observed to determine the outcome or response in relation to the independent variable. It is considered the outcome or the result of the changes made to the independent variable. While the dependent variable is influenced by the independent variable, its changes are typically a consequence of the alterations made to the independent variable.
In summary, the independent variable is typically seen as having a more direct and significant effect on the experiment because it is intentionally manipulated to observe its impact on the dependent variable. The dependent variable, while influenced by the independent variable, is more of a response or outcome that is measured or observed as a result of the changes made to the independent variable.
What is the first job u do on the ISS if u were an astronaut
Answers
If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.
What is expected at ISS?I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.
Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.
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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
Answers
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
Answers
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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Please help I’m confused on this
Answers
Answer:
inversely proportional to
Choose the correct definition of angular momentum.
the product of the object’s moment of inertia and the object’s angular velocity
the product of the object’s momentum and the object’s angular velocity
the product of the object’s momentum and the object’s moment of inertia
the product of the object’s momentum and the object’s angle through space
Answers
The answer is "the product of the object's moment of inertia and the object's angular velocity.
The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem we have to find the correct definition of angular momentum,
The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle
The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.
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In the decomposition of water, why is twice as much hydrogen as oxygen formed?
A. Some oxygen gas escapes the reaction, and hydrogen gas is conserved.
B. There are two atoms of hydrogen and one atom of oxygen in a water molecule.
C. Hydrogen atoms are twice the size of oxygen atoms.
D. Hydrogen gas has two atoms, and oxygen gas has one atom.
Answers
Answer:
It's B yall I know I got 100%
Explanation:
In the decomposition of water, There is twice as much hydrogen as oxygen formed because there are two atoms of hydrogen and one atom of oxygen in a water molecule, therefore the correct answer is option B.
What is a Chemical compound?A chemical compound is a combination of two or more either similar or dissimilar chemical elements.
For example, H₂O is a chemical compound made up of two hydrogen atoms and a single oxygen atom.
A single H₂O molecule = two hydrogen atoms + single oxygen atom
Because a water molecule contains two hydrogen atoms and one oxygen atom, option B is the right response because, during the breakdown of water, two times as much hydrogen as oxygen is produced.
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Someone tries to tell you that a freezer cools food by transferring cold to the particles in the food. (has to be 1 sentence)
How would you respond? Construct an argument.
am in 8th grade
pls explain as well bc I’m like rlly slow
Answers
Freezing keeps food safe by slowing the movement of molecules, causing microbes to enter a dormant stage. Freezing preserves food for extended periods because it prevents the growth of microorganisms that cause both food spoilage and foodborne illness.
What is freezing food?
Food is preserved when frozen, keeping it fresh from preparation until consumption.Farmers, fishers, and trappers have traditionally stored their produce and grains over the winter months in unheated structures.By turning any remaining moisture in food into ice, freezing it slows the breakdown process and prevents the majority of bacterial species from proliferating.Mechanical and cryogenic techniques are used in the food commodities industry (or flash freezing).To maintain the food's flavour and texture, freezing kinetics is crucial. Smaller ice crystals are produced more quickly, preserving cellular structure.To know more about the freezing food, click the link given below:
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Which of the following actions will increase the current induced in a wire by a
magnetic field?
Answers
Answer:
The induced current can be increased in the coil in the following ways: By increasing the strength of the magnet. By increasing the speed of the magnet through the coil.
Explanation:
A bus is moving with
a velocity of lom/s. After 2 sec its velocity
becames 20/s find the distance from travelled
by a bus at that this time of interval
Answers
Answer:
30 m
__________________________________________________________
Explanation:
We are given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 2 seconds
Distance travelled by the bus (s) = s meters
Solving for the distance travelled:
Solving for the acceleration:
v = u + at [first equation of motion]
20 = 10 + a(2) [replacing the given values]
2a = 10 [subtracting 10 from both sides]
a = 5 m/s² [dividing both sides by 2]
Solving for the distance:
s = ut + 1/2 (at²) [second equation of motion]
s = 10(2) + 1/2(5)(2)² [replacing the given values]
s = 20 + 10
s = 30 m
Therefore, the bus travelled 30 m in the given time interval
in a hockey game, player A passes the puck to player B, who is standing on the blue line, as shown in the diagram. The puck travels distance d1=24.1m on its way to player B, making an angle = 52.5 degrees with the x axis. Player B then passes the puck so that it moves d2=7.9m on the blue line in the negative x direction. A) What is the magnitude of the total displacement in meters? B) What angle, in degrees, does the total displacement make with the x axis?
Answers
The magnitude of the total displacement is 20.28 m.
The angle of the total displacement with the x axis is 70.5⁰.
Total displacement
The total displacement of the player is calculated as follows.
Apply cosine rule as shown below;
d² = d₁² + d₂² - 2d₁d₂ cos(θ)
d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)
d² = 411.42
d = √411.42
d = 20.28 m
Angle of the displacement with horizontalApply sine rule as shown below;
d/sinD = d₂/sinD₂
20.28/sin(52.5) = 7.9/sinD₂
25.562 = 7.9/sinD₂
sinD₂ = 7.9/25.562
sinD₂ = 0.309
D₂ = sin⁻¹(0.309)
D₂ = 18⁰
angle with x axis = 18⁰ + θ
= 18⁰ + 52.5⁰
= 70.5⁰
Thus, the magnitude of the total displacement is 20.28 m.
The angle of the total displacement with the x axis is 70.5⁰.
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A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance
of 0.5m, how high does the rock move?
Pls help and can you tell me the energy conversions too!!
Answers
Answer:
h = 17.83[m]
Explanation:
By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.
\(W=F*d\)
where:
W = work [J]
F = force = 3500 [N]
d = distance = 0.5 [m]
Now replacing:
\(W= 3500*0.5\\W=1750[J]\)
Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.
\(W=E_{kin}=E_{pot}\)
where:
Ekin = kinetic energy [J]
Epot = potential energy [J]
Therefore:
\(1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m]\)
Evenly timed disturbances in a medium create a n) O A. periodic wave O B. pulse O c. electromagnetic wave D. compression wave
Answers
Answer: periodic wave
Explanation:
i just took a test and got it right
A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 59.4 m/s and returns the shot with the ball traveling horizontally at 37.2 m/s in the opposite direction. (Take the direction of the ball's final velocity (toward the net) to be the +x-direction).
(a) What is the impulse delivered to the ball by the racket?
(b) What work does the racket do on the ball?
Answers
5 9 . 4
- 3 7 . 2
2 2 . 2
Explanation:
Use the algorithm method.
5 9 . 4
- 3 7 . 2
2 2 . 2
2 Therefore, 59.4-37.2=22.259.4−37.2=22.2.
22.2
22.2
List 1 of the 3 reasons we eat
Answers
Answer:
to get energy and nutrients
Explanation:
It you balance a weight of 20 N at the 15 cm MARK and want to balance a weight of on the other side of the meter stick at 70 cm MARK, what weight should you place there
Answers
Answer:
The weight that will balance the meter stick at 70 cm mark is 35N
Explanation:
Given;
first weight at 15 cm mark, W₁ = 20 N
second weight at 70 cm mark, W₂ = ?
A sketch of the question in diagram form;
The center of gravity of the meter stick is 50 cm
15cm 50cm 70cm
0---------------------------------------Δ------------------------------------------100cm
↓ ↓
20N W₂
<------------------>|<--------------->
35cm 20cm
Take moment about the pivot;
Clockwise moment = anticlockwise moment
W₂(20cm) = 20N(35 cm)
W₂ = (20 x 35) / (20)
W₂ = 35 N
Therefore, the weight that will balance the meter stick at 70 cm mark is 35N
How do you find the centripetal acceleration without the radius???? I genuinely don’t know what to do.
Answers
Answer:
In order to calculate the value of force without radius, you may need the circumference whose formula is C=2πr. You can also find this force by calculating just acceleration using the formula: And this is also called Newton’s second law of motion, which can be calculated by entering acceleration and mass of the object.
hope this is what you want
Explanation:
The following is an example of what type of reaction?
Answers
Answer:
Single Displacement Reaction
Explanation:
Here, only one element is getting replaced during the reaction, that is, silver gets replaced by copper, hence, single displacement reaction.
Hope it helps :)
A torque of T= 4Nm is required to rotate the intermediate cylinder at W= 30 rad/min .
Calculate the viscosity of the
oil. All cylinders are 450 mm long. Neglect the end effects.
R=0.15m, t=0.003 m.
Result: 1.258 N.s/m
Answers
The viscosity of the oil with a torque 4Nm and a rotational speed is 30 rpm is 0.2003 N.s/m.
From the given,
torque = 4Nm
rotational speed = 30 rpm = (30 × 3.14)/60 = 3.14 rad/sec
radius = 0.15 m
thickness (h) = 0.003 m
To find linear velocity,
V = R×ω
= 0.15×3.14
V =0.471 m/s
The dragging force,
F = 2μA(V/h) (V is linear velocity and h is the thickness )
Area = area of cylinder = 2πRH, R is radius and H is the height of the cylinder.
F = 2μ(2πRH) (V/h)
= 2μ(2×3.14×0.15×0.45) (0.471/0.003)
= 133.10 μ (μ is the viscosity of the oil)
F = 133.1μ
Torque (τ) = Force × radius
4 Nm = 133.1μ × 0.15
μ = 4 / (133.1×0.15)
= 0.2003 N.s/m
The viscosity of the oil is 0.2003 N.s/m.
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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing vehicle and parachute is 2270 kg, the drag coefficient is effectively 0.5, the atmosphere density is 0.71 that of Earth (take Earth atmosphere density as 1.2 kg/m3), and the Martian gravitational acceleration is 3.689 m/s2, find the required total frontal area (in m2) of the lander plus a parachute to land at the given velocity. Assume the landing vehicle has achieved terminal velocity as it falls through the Martian atmosphere.
Answers
Answer:
The value is \(A = 39315 \ m^2\)
Explanation:
From the question we are told that
The velocity which the rover is suppose to land with is \(v = 1 \ m/s\)
The mass of the rover and the parachute is \(m = 2270 \ kg\)
The drag coefficient is \(C__{D}} = 0.5\)
The atmospheric density of Earth is \(\rho = 1.2 \ kg/m^3\)
The acceleration due to gravity in Mars is \(g_m = 3.689 \ m/s^2\)
Generally the Mars atmosphere density is mathematically represented as
\(\rho_m = 0.71 * \rho\)
=> \(\rho_m = 0.71 * 1.2\)
=> \(\rho_m = 0.852 \ kg/m^3\)
Generally the drag force on the rover and the parachute is mathematically represented as
\(F__{D}} = m * g_{m}\)
=> \(F__{D}} = 2270 * 3.689\)
=> \(F__{D}} = 8374 \ N\)
Gnerally this drag force is mathematically represented as
\(F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}\)
Here A is the frontal area
So
\(A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }\)
=> \(A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }\)
=> \(A = 39315 \ m^2\)
If you have completely polarized light of intensity 150 W/m2, what will its intensity be after passing through a polarizing filter with its axis at an 89.0º angle to the light’s polarization direction?
Answers
Answer:
0.04569 W/m^2
Explanation:
I=150cos^2(89.0)
=0.04569W/m^2
Planet RMM-1 has a mass of 28,500 kg and the star it revolves around has
a mass of 2.20 x 10^8 kg. If the star emits a gravitational force of 39 N how
far away are the two objects from each other?
Answers
Gravitational force = G · (mass₁) · (mass₂) / (distance)
(distance²) = G · (mass₁) · (mass₂) / (Gravitational force)
G = 6.67 x 10⁻¹¹ n-m² / kg² (the "gravitational constant")
Distance² = (6.67 x 10⁻¹¹ n-m² / kg²) (28,500 kg) (2.2 x 10⁸ kg) / (39 N)
Distance² = (6.67 · 28,500 · 2.2 x 10⁻³ N-m²) / (39N)
Distance² = (418.209 N-m²) / (39N)
Distance² = 10.72 m²
Distance = 3.275 meters
An absurd scenario, but that's by golly what the math says with the numbers provided. I guess it's a teeny tiny planet orbiting 3.275 meters outside a teeny tiny black hole.
The prefix "cardio" refers to
aerobic
heart
with oxygen
anaerobic
Answers
Explanation:
The prefix "cardio" refers to HEART
Answer:
Even just looking up the meaning of the prefix "cardo" we can determine that it has to do something with the heart. The word cardio comes from the Greek kardía, which means "heart".
Option B, heart
Q17: A quantity has a unit of Kg.m-1.s-1, then its dimension is:
(a) [M2 L2 T?]
(b) M L?T
(c) (M2 LT]
(d) [M L-1 T-1]
(e) [M L-11-2]
Answers
Answer:
It's dimension is (d) [M L-1 T-1]
Batman shoots a grappling hook
34.6 m/s at an 80.2° angle. What is the magnitude only (no direction) of the velocity of the hook 1.09 s later?
(Unit = m/s)
Answers
Answer:
24.132 m/s
Explanation:
Note
\(U\) = Initial Velocity
\(U_x\) = Initial Horizontal Velocity
\(U_y\) = Initial Vertical Velocity
\(V\) = Final Velocity
\(V_x\) = Final Horizontal Velocity
\(V_y\) = Final Vertical Velocity
\(B\) = launch angle
\(g\) = gravity
\(t\) = time
\(U_x=U*cos(B)\)
\(U_y=U*sin(B)\)
The horizontal component of the velocity is constant throughout the flight. So \(U_x=V_x\) It can be defined as
\(V_x=U*cos(B)\)
We can use the kinematics equation
\(V=U+at\)
Gravity is acting downwards; gravity would be negative
\(V_y=U_y-gt\)
The magnitude of the velocity can be defined as
\(V=\sqrt{V_x^2+V_y^2}\)
Inserting some of the other equations gives us an equation at a given time (t).
\(V=\sqrt{(U*cos(B))^2+(U*sin(B)-gt)^2}\)
\(V=\sqrt{(UcosB)^2+(UsinB)^2+(gt)^2-2gtU*sinB\)
\(V=\sqrt{U^2+g^2*t^2-2*t*g*U*sinB}\)
\(V(t)=\sqrt{U^2+g^2t^2-2tgUsinB}\)
We are given
\(U=34.6\)
\(B=80.2\)
\(t=1.09\)
\(g=9.81\)
\(V(1.09)=\sqrt{34.6^2+9.81^2*1.09^2-2*1.09*9.81*34.6*sin80.2}\)
\(V(1.09)=\sqrt{34.6^2+114.338-2*1.09*9.81*34.6*sin80.2}\)
\(V(1.09)=\sqrt{34.6^2+114.338-739.94868*sin80.2}\)
\(V(1.09)=\sqrt{34.6^2+114.338-729.151}\)
\(V(1.09)=\sqrt{1197.16+114.338-729.151}\)
\(V(1.09)=\sqrt{582.347}\)
\(V(1.09)=24.132\)
A rating/review would be much appreciated. Hope this helps!
Let me know if you have any questions about my work
An object is traveling at a constant velocity of 8.6 m/s (v0) when it experiences a constant acceleration of 2.1 m/s^2 (a) for a time of 17 s (t). What will its velocity (v) be after that acceleration?
Answers
Answer:
velocity = 44.3m/s
Explanation:
From the law of motion.
v = u + at
v = 8.6 + (2.1 x 17)
v = 8.6 + (35.7)
v = 44.3m/s after 2.1m/s²
The deepest part of the ocean is the Challenger Deep, at 10,900 m. The depth was first measured in 1875 by the HMS Challenger by depth sounding (which does not involve sound waves). If you were to measure the depth by echo sounding (which does involve sound), what would you expect the time for a sound pulse at the surface to return in s, naively assuming a constant sound velocity throughout the ocean
Answers
Answer:
t = 14.53 s
Explanation:
The speed of a wave is constant and is given by
v = \(\sqrt{ \frac{B}{ \rho} }\)
in this exercise they indicate that we assume the constant velocity, therefore we can use the uniform motion relations
v = x / t
t = x / v
in this case the sound pulse leaves the ship and must return so the distance is
x = 2d
where d is the ocean depth d = 10900m and the speed of sound in seawater is v = 1500 m / s
let's calculate
t = 2 10900/1500
t = 14.53 s
(ii) In two parts of the graph in Figure 1 the forces are balanced.
State the letters of the two parts of the graph where the horizontal forces
acting on the car are balanced.
121
part
and part
this is the graph:
Answers
Answer:
Hii I m Indian.......♥️
A soccor ball lies still on the grass until it is kicked by a player. This desribes which of Newton's Laws?