i just need help making sure i’m right could somebody help

The measures of the angles in the completed table of the question can be presented as follows;

Angle AFB \({}\)        \({}\)Angle BFC      Angle DFE   Angle EFA

48          \({}\) \({}\)             42                    48                132

36 \({}\)                       54                    36                144

40\({}\)                        50                    40                140

An angle is a geometric figure formed by the opening (space) at the point where two rays meet.

The specified angle measurement indicates that we get;

Angle AFB and angle BFC are complementary angles

Angle AFB and angle DFE are vertical angles

Vertical angles are congruent

Angle EFA and angle BFD are vertical angles

Angle BFD = Angle BFC + Angle CFD

Therefore;

Angle EFA = Angle BFC + Angle CFD

Angle CFD = 90°

The completed table can be presented as follows;

Angle AFB \({}\)             Angle BFC         Angle DFE              Angle EFA

48 \({}\)                             42                          48                       132

AFB = DFE = 36 \({}\)    BFC=90-36 =54       36                        90 + 54 = 144

90-50 = 40\({}\)      \({}\)      140 - 90 = 50            40                        140

The possible question, obtained from a similar question on the internet can be presented as follows;

The rows in the following table represent a complete set of angle measurement in the attached drawing created with MS Excel

Make use of the drawing and the angle measurements in each row on the table to find the missing (required) angle measurement

Angle AFB \({}\)         Angle BFC             Angle DFE               Angle EFA

48                   \({}\)     42                           48                            132

                                                          36                                

\({}\)                                                                                           140

Learn more on vertical angles here: https://brainly.com/question/4282601

#SPJ1  

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\(x + y = 6\)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\(y + 14 = 3 - x\)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

seven

Step-by-step explanation:

if the triangles are equal then the hypotenuse is the same meaning you just add four and four then subtract eight from fifteen getting seven

Step-by-step explanation:

According to the Question , diameter of circle is 16 inches. We need to find the area in terms of pi (π) . We know the area of circle as product of pi and square of radius . Therefore ,

\(\to\tt \orange{ Area = \pi r^2 } \\\\\tt \to Area = \pi (8 \ in.)^2 \\\\\tt\to \boxed{\orange{\tt Area = 64\pi in^2 }}\)

Answer:

\(64\pi\)

Step-by-step explanation:

diameter => D = 2r

r = D/2 = 16/2 = 8

area =

\(\pi \times r {}^{2} \)

=

\(64\pi\)

Step-by-step explanation:

PQR = PRQ = 2x ° ( base angle of an isosceles are equal ) .

therefore

PQR + PRQ + QPR = 180° ( sum of angles in a triangle )

2x + 2x + 40 = 180

4x + 40 = 180

subtract 40 from both sides

4x = 140

divide through by 4

x = 35°

Answer:

88 inches

Step-by-step explanation:

The given bicycle has a tyre that is 28 inches in diameter.

How far the bicycle moves forward each time the wheel goes around is the circumference of the bicycle tyre.

This is calculated using the formula:

C =\pi \: d

We substitute the diameter and

\pi =  \frac{22}{7}

C =  \frac{22}{7}  \times 28

This simplifies to

C =22 \times 4

88 \: inches

Answer:

-2

Step-by-step explanation:

I'm not sure but I think you just need to make them the same

Answer:

The answer is 104

Step-by-step explanation:

I’m guessing the shape is a triangle so if you have to angels you add them up and minus then from 180 what you get is your missing angle.

Answer:

n=24.

Step-by-step explanation:

1/4 of 24 is 6, and 6+18= 24.

The transpose of A⁻¹ is the inverse of the transpose of A⁻¹, which implies that if A⁻¹ is orthogonal, then A is orthogonal. Therefore, we have shown that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.

To find the orthogonal projection of vector w into the plane spanned by vectors u and v, we need to calculate the projection vector proj_w(uv).

First, we calculate the normal vector n of the plane. The normal vector is obtained by taking the cross product of vectors u and v:

n = u x v

= (1, 0, -1) x (4, 3, -2)

The cross product can be calculated as follows:

n = ((0)(-2) - (-1)(3), (-1)(4) - (1)(-2), (1)(3) - (0)(4))

= (-3, -6, 3)

Next, we normalize the normal vector n to obtain the unit normal vector n:

n = n / ||n||

= (-3, -6, 3) / √(9 + 36 + 9)

= (-3, -6, 3) / √54

= (-1/√6, -2/√6, 1/√6)

Now, we can calculate the projection of vector w onto the plane using the formula:

proj_w(uv) = w - ((w · n) / (n · n)) * n

The dot product of w and n is given by:

w · n = (2)(-1/√6) + (3)(-2/√6) + (-2)(1/√6)

= -2/√6 - 6/√6 - 2/√6

= -10/√6

The dot product of n and n is:

n · n = (-1/√6)(-1/√6) + (-2/√6)(-2/√6) + (1/√6)(1/√6)

= 1/6 + 4/6 + 1/6

= 6/6

= 1

Substituting these values into the projection formula, we have:

proj_w(uv) = (2, 3, -2) - ((-10/√6) / 1) * (-1/√6, -2/√6, 1/√6)

= (2, 3, -2) + (10/√6)(-1/√6, -2/√6, 1/√6)

= (2, 3, -2) + (-10/6, -20/6, 10/6)

= (2, 3, -2) + (-5/3, -10/3, 5/3)

= (2 - 5/3, 3 - 10/3, -2 + 5/3)

= (1/3, 1/3, -1/3)

Therefore, the orthogonal projection of vector w into the plane spanned by vectors u and v is (1/3, 1/3, -1/3).

Now, let's prove the statement that the matrix A is orthogonal if and only if its transpose A⁻¹ is orthogonal.

To prove this, we need to show two conditions:

If A is orthogonal, then A⁻¹ is orthogonal:

If A is orthogonal, it means that A · A⁻¹ = I, where I is the identity matrix.

Taking the transpose of both sides, we have (A · A⁻¹)ᵀ = Iᵀ, which simplifies to (A⁻¹)ᵀ · Aᵀ = I.

This shows that the transpose of A⁻¹ is the inverse of the transpose of A, which implies that if A is orthogonal, then A⁻¹ is orthogonal.

If A⁻¹ is orthogonal, then A is orthogonal:

If A⁻¹ is orthogonal, it means that (A⁻¹) · (A⁻¹)ᵀ = I, where I is the identity matrix.

Taking the transpose of both sides, we have ((A⁻¹) · (A⁻¹)ᵀ)ᵀ = Iᵀ, which simplifies to ((A⁻¹)ᵀ) · (A⁻¹) = I.

Learn more about transpose at: brainly.com/question/32293193

#SPJ11

Answer:

8

Step-by-step explanation:

8-15=-7

-7/7=-1

The value of the expression is r'(t) = (4, 6t, 12t²), T(1) = (2/7, 3/7, 6/7), r''(t) = (0, 6, 24t), r'(t) ร r''(t) = 144t³.

We are given the vector-valued function r(t) = (4t, 3t², 4t³).

To find r'(t), we need to take the derivative of each component of r(t) with respect to t:

r'(t) = (d/dt)(4t), (d/dt)(3t²), (d/dt)(4t³)

r'(t) = (4, 6t, 12t²)

To find T(1), we need to evaluate r'(t) at t = 1 and then divide by the magnitude of r'(1):

r'(1) = (4, 6(1), 12(1)²) = (4, 6, 12)

| r'(1) | = sqrt(4² + 6² + 12²) = sqrt(196) = 14

T(1) = r'(1) / | r'(1) | = (4/14, 6/14, 12/14) = (2/7, 3/7, 6/7)

To find r''(t), we need to take the derivative of each component of r'(t) with respect to t:

r''(t) = (d/dt)(4), (d/dt)(6t), (d/dt)(12t²)

r''(t) = (0, 6, 24t)

Finally, to find r'(t) ร r''(t), we need to take the dot product of r'(t) and r''(t):

r'(t) ร r''(t) = (4, 6t, 12t²) ร (0, 6, 24t)

r'(t) ร r''(t) = 0 + 6t(6t) + 12t²(24t)

r'(t) ร r''(t) = 144t³

Therefore, we have:

r'(t) = (4, 6t, 12t²)

T(1) = (2/7, 3/7, 6/7)

r''(t) = (0, 6, 24t)

r'(t) ร r''(t) = 144t³

Learn more about expression here

https://brainly.com/question/1859113

#SPJ11

Answer:

1000 km^3

Step-by-step explanation:

1 km=1000m

1 cubic kilometer is equivalent to 1,000,000,000 cubic meters, due to cubing the conversion factor of 1,000 (meters per kilometer).

1 cubic kilometer is equivalent to 1,000,000,000 (one billion) cubic meters. When converting units, you need to remember the relationships between those units. In this case, 1 kilometer is equivalent to 1000 meters. Therefore, to convert from cubic kilometers to cubic meters, you need to cube the conversion factor (1000 meters/kilometer). Hence, 1 cubic kilometer = 1,000^3 cubic meters = 1,000,000,000 cubic meters.

https://brainly.com/question/32030244

#SPJ2

Function that models the situation is f(x) = 1/2(x-6)²+2.

A parabola is a plane curve that is mirror-symmetrical and is approximately U-shaped.

Given parabola is of concave upward type.

So, the parabola will be of form f(x)=p(x-q)²+r....(1)

As vertices of parabola are (6,2)

So, we can put q=6 and r =2 in (1)

So, (1) becomes f(x) = p(x-6)²+2.....(2)

The y-intercept of the parabola is 20

This means, (2) becomes 20 = p(0-6)²+2

i.e. p = 1/2

So, function will be f(x) = 1/2(x-6)²+2

Therefore, Function that models the situation is f(x) = 1/2(x-6)²+2.

To get more about parabola visit:

brainly.com/question/4148030

Answer:

It's A

Step-by-step explanation:

Edge 2022

The average of F(x, y, z) = z over the region F which is bounded on the top by the hemisphere z /6-x2-y2 and on the bottom by the paraboloid x2 + y-z is 8π/3.

To use cylindrical coordinates, we need to express the surfaces defining the region F in terms of cylindrical coordinates. The equation of the hemisphere is:

z = 6 - \(r^2\)

where r is the distance from the z-axis, and the equation of the paraboloid is:

z = \(r^2 + rcos\theta\)

To find the limits of integration, we need to find the intersection of these two surfaces. Setting the two equations equal to each other, we get:

\(6 - r^2 = r^2 + rcos\theta\)

Rearranging, we get:

\(2r^2 + rcos\theta - 6 = 0\)

Using the quadratic formula, we get:

\(r = [-cos\theta \± \sqrt{(cos^2\theta + 24)]/4\)

Since r can't be negative, we take the positive square root:

\(r = [-cos\theta + \sqrt{(cos^2\theta + 24)]/4\)

The limits of integration for theta are 0 to 2π, and for r are 0 to [-\(cos\theta + \sqrt{(cos^2\theta + 24)]/4.\)

To find the average value of F(x, y, z) = z over this region, we need to compute the triple integral:

(1/V) * ∭F(x, y, z) dV

where V is the volume of the region F. Using cylindrical coordinates, the volume element is:

dV = r dz dr dθ

The limits of integration for z are given by the equations of the surfaces, so we have:

z = \(r^2 + rcos\theta\) to z = 6 - r^2

Substituting z = \(r^2 + rcos\theta\) in the equation of F, we get:

F(r,\(\theta\),z) = z = \(r^2 + rcos\theta\)

The average value of F over the region is:

(1/V) * ∭F(r, \(\theta\), z) dV

= (1/V) * ∫∫∫ \(r^2 + rcos\theta\) r dz dr dθ

= (1/V) * ∫\(0^{2\pi\) ∫\(0^{[-cos\theta + \sqrt{(cos^2\theta + 24)]/4}\) ∫\(r^2 + rcos\theta to 6 - r^2 (r^2 + rcos\theta )\) r dz dr dθ

where V is the volume of the region, which we can compute by integrating the volume element over the region:

V = ∫∫∫ dV

= ∫\(0^{2\pi\) ∫\(0^{[-cos\theta + \sqrt{(cos^2\theta + 24)]/4\) ∫\(r^2 + rcos\theta to 6 - r^2\) r dz dr dθ

= 8π/3

Evaluating the integral, we get:

(1/V) * ∭F(r,\(\theta\), z) dV

= (3/8π) * ∫\(0^{2\pi\) ∫\(0^{[-cos\theta + \sqrt{(cos^2\theta + 24)]/4\) ∫\(r^2 + rcos\theta\) to 6 - \(r^2\) (\(r^3 + r^2cos\theta)\) dz dr dθ

= (3/8π) * ∫\(0^{2\pi\) ∫\(0^{[-cos\theta + \sqrt{(cos^2\theta + 24)]/4} (r^5/2 + r^4cos\theta/2) - (r^{3/2 + r^2cos\theta/2)(r^2 + rcos\theta)\) dr dθ

For more such questions on Paraboloid.

https://brainly.com/question/2061621#

#SPJ11

Porosity calculated as ratio of pore to total vol. Plot of porosity vs averaging length scale (edge of square used for averaging). Rep. elemental vol = vol of square used for averaging.

The porosity as a function of the averaging length scale can be calculated as follows:

Learn more about geometry :

https://brainly.com/question/10700399

#SPJ4

We may build up a proportion and solve for the scale model radius of Neptune using the ratio between the radii of the two planets and the known scale model radius of the Earth. The scale model of Neptune that is produced has a radius of around 9.7 cm.

We may take advantage of the fact that the ratio between the two planets' radii and the ratio between their respective scale model radii is the same. Let's name the Neptune scale model radius "r" Then, we may set up the ratio shown below:

Neptune's radius is equal to the product of Earth's radius and its scale model.

With the provided values, we may simplify and obtain:

24620 km / 6370 km equals 2.5 cm / r

We obtain the following when solving for "r":

r = (24620 km * 2.5 cm) / (6370 km)

r ≈ 9.7 cm

Therefore, a scale model of Neptune would have to be drawn with a radius of approximately 9.7 cm.

Learn more about scale models here:

https://brainly.com/question/17581605

#SPJ4

Ans .: The dimensions of the container that will minimize the cost are a base with sides of length 16.7 cm and a height of 8.35 cm.

To minimize the cost of the container, we need to find the dimensions that will use the least amount of material. Let's call the length of one side of the square base "x" and the height of the container "h".

The volume of the container is given as 2000 cm^3, so we can write:

V = x^2h = 2000

We need to find the dimensions that will minimize the cost, which is determined by the amount of material used. We know that it costs twice as much per square centimeter to make the top and bottom as it does the sides.

Let's call the cost per square centimeter of the sides "c", so the cost per square centimeter of the top and bottom is "2c". The total cost of the container can then be expressed as:

Cost = 2c(x^2) + 4(2c)(xh)

The first term represents the cost of the top and bottom, which is twice as much as the cost of the sides. The second term represents the cost of the four sides.

To minimize the cost, we can take the derivative of the cost function with respect to "x" and set it equal to zero:

dCost/dx = 4cx + 8ch = 0

Solving for "h", we get:

h = -0.5x

Substituting this into the volume equation, we get:

x^2(-0.5x) = 2000

Simplifying, we get:

x^3 = -4000

Taking the cube root of both sides, we get:

x = -16.7

Since we can't have a negative length, we take the absolute value of x and get:

x = 16.7 cm

Substituting this into the equation for "h", we get:

h = -0.5(16.7) = -8.35

Again, we can't have a negative height, so we take the absolute value of "h" and get:

h = 8.35 cm

Therefore, the dimensions of the container that will minimize the cost are a base with sides of length 16.7 cm and a height of 8.35 cm.

Learn more about :

volume : brainly.com/question/28058531

#SPJ11

Step-by-step explanation:

Area = ½ b × h

height = √(13²-5²)

=12

Area = ½ × 10 × 12

= 60 cm²

Answer:

intersection

is your answer

Answer:

intersection is write i think .

Answer:

Forth term = x + 6

Fifth term = x + 8

Sixth term = x + 10

Formular for nth term:

\({ \tt{n _{th} = a + (n - 1)d}} \\ { \tt{{n _{th} = x + (n - 1) \times 2}}} \\ { \tt{{n _{th} =x + 2n - 2 }}}\)

Answer:

Hello,

Step-by-step explanation:

First term of this aritmetical sequence is x+0*2

\(U_1=x+0*2\\U_2=x+2=x+1*2\\U_3=x+4=x+2*2\\U_4=x+6=x+3*2\\\\n^{th}\ term\ is\ U_n=x+(n-1)*2\\\)

Means that the derivative of A at a, dA(a), is equal to L. Hence, A is differentiable at a with dA(a) = L.

To prove that the function A is differentiable at a with dA(a) = L, we need to show that:

lim(x→a) [A(x) - A(a) - L(a)(x-a)] / ||x-a|| = 0

We know that A(x) = c + L(x) for all x in RP, where c is a constant and L is a linear transformation from RP to R9.

Then, we have:

A(a) = c + L(a)

L(a)(x-a) = L(x-a) + L(a-a) = L(x-a)

Substituting these into the limit expression, we get:

lim(x→a) [c + L(x) - c - L(a) - L(x-a)] / ||x-a||

= lim(x→a) [L(x) - L(a)] / ||x-a||

Since L is a linear transformation, it is continuous. Therefore, we can write:

lim(x→a) [L(x) - L(a)] / ||x-a|| = L( lim(x→a) [x-a] / ||x-a|| )

But lim(x→a) [x-a] / ||x-a|| = u, a unit vector in the direction of x-a.

Therefore, we have:

lim(x→a) [L(x) - L(a)] / ||x-a|| = Lu

This means that the derivative of A at a, dA(a), is equal to L. Hence, A is differentiable at a with dA(a) = L.

To learn more about differentiable  visit:

https://brainly.com/question/31251286

#SPJ11

These adjusting journal entries are prepared as of October 31st to reflect the appropriate account balances and ensure accurate financial reporting.

1. Prepaid insurance totaling $400 expired during the month:
  - Debit Insurance Expense $400
  - Credit Prepaid Insurance $400
2. Salaries of $500 are unpaid at the end of the month:
  - Debit Salaries Expense $500
  - Credit Salaries Payable $500
3. Services performed but unbilled at the end of the month $800:
  - Debit Accounts Receivable $800
  - Credit Service Revenue $800

4. Supplies of $100 were used during the month:
  - Debit Supplies Expense $100
  - Credit Supplies $100

5. Cash of $200 was received from a customer during October for work to be done starting on November 15:
  - Debit Unearned Revenue $200
  - Credit Cash $200

To know more about journal entries visit:

brainly.com/question/33748350

#SPJ11

Answer:

It would be $13 as the original bill

But the correcy answer is D  

Step-by-step explanation:

The running time wοrst case οf deleting a minimum element frοm a (min) binary heap with N elements is O(lοgN). Therefοre, the cοrrect answer is c. O(lοgN).

When deleting the minimum element frοm a binary heap, the heap needs tο be restructured tο maintain its heap prοperty. This restructuring prοcess invοlves mοving elements within the heap and pοtentially swapping elements tο maintain the heap's structure and οrdering.

Since a binary heap is a cοmplete binary tree and has a height οf lοgN, the wοrst-case running time fοr deleting the minimum element is prοpοrtiοnal tο the height οf the heap, which is O(lοgN). This is because the number οf cοmparisοns and swaps required during the restructuring prοcess is dependent οn the height οf the heap.

Therefοre, the cοrrect answer is c. O(lοgN).

Learn more about binary heap

https://brainly.com/question/32260955

#SPJ4

Answer:

$10/hour

Step-by-step explanation:

Solving

Take two points and find slope

Slope

Pay rate 10$/h

The given integral is: ∫∫R 5/√(2) xy dA, where R is the region in the xy-plane bounded by the curves y = 0, x = √(25 - y^2) and x = 0. The volume of the solid is (5^5/8) cubic units.

Converting to polar coordinates, we have:

x = r cos(θ), y = r sin(θ), and the limits of integration become:

0 ≤ θ ≤ π/2, 0 ≤ r ≤ 5.

Also, the differential of area becomes dA = r dr dθ.

Substituting for x and y, and dA, we have:

∫∫R 5/√(2) xy dA = ∫θ=0π/2 ∫r=0^5 5/√(2) (r cos(θ)) (r sin(θ)) r dr dθ

= 5/√(2) ∫θ=0π/2 ∫r=0^5 r^3 cos(θ) sin(θ) dr dθ

= 5/√(2) ∫θ=0π/2 [sin(θ)/4] ∫r=0^5 r^4 cos(θ) dr dθ

= 5/√(2) ∫θ=0π/2 [sin(θ)/4] [(5^5 cos(θ))/5] dθ

= (5^5/4√(2)) ∫θ=0π/2 sin(θ) cos(θ) dθ

= (5^5/8)

Learn more about volume at: brainly.com/question/28058531

#SPJ11

If two lines intersect, then the vertical angles formed must be both equal in measure.

The  intersection of a line can be described as when two or more lines cross each other in a plane as a result of this they are been referred to as   intersecting lines.

Therefore, intersecting lines share a common point, hence , If two lines intersect, then the vertical angles formed must be both equal in measure.

Learn more about intersection of a line on:

https://brainly.com/question/1542819

#SPJ4

Answer:

the equation of the line is y = -1/-30 - 3⅙ and the y intercept is -3⅙.

Step-by-step explanation:

Using, the formula y1+y2/x1-x2,

Choosing any two points, make the expression:

1-2/125-155

simplify:

-1/-30

the slope of the equation is -1/-30.

to find y intercept, using the function y=mx+b, plug in the slope and one of the two points that you used:

y would be 2

x would be 155

b is the y intercept

2= -1/-30•155 + b

2=5⅙+b

b = - 3⅙

the equation of the line is y = -1/-30 - 3⅙ and the y intercept is -3⅙.