I have found a small piece of rock that I believed is actually gold. The density of gold is 19.3 g/cc. Is there a way that I could find the density of the piece of rock I found? How would I find the density?

Answers

Answer 1

You can measure its mass and volume and use the equation density=mass/volume


Related Questions

You dip your finger into a pan of water twice each second, producing waves with crests that are separated by 0.19 m. (a) Determine the frequency of the water waves. Hz (b) Determine the period of the water waves. s (c) Determine the speed of the water waves.

Answers

Answer:

a) The frequency of the waves are = 2 Hz (since you are making two pulses every second)

b)The period of the waves is 0.19 m (as the consecutive crests are separated by 0.19 m)

c) V = L x f

v = 0.19 m x 2 S-1 (Hz is actually per second)

v = 0.38 ms-1

pe nis

how do the conditions in tube c prevent air reaching the iron nail​

how do the conditions in tube c prevent air reaching the iron nail

Answers

Answer:

The conditions stop air from getting to the nail is the oil

Explanation:

Would the phases of the moon be affected if the moon did not make one rotation for each revolution of earth. Explain .

Answers

Answer:

No. If the moon did not rotate at all we would still see the same visible "fraction" of the moon's surface.

At the full moon  phase we would still the entire surface of  1/2 of the moon regardless of which side of the moon we were observing.

Actually the moon does not make one rotation for each revolution of the earth, but rather, one rotation for each complete revolution of the moon around the the earth. That's why we always see the same side of the moon from earth. The back side of the moon is never visible from earth.

on a particular day the following appliances are used for the Times indicated a 1600 watt coffee maker 10 minutes and the 1100 watt microwave oven 4 minutes with these power requirements find how much it cost to use the appliances at an electrical cost of $0.08 per kwh

Answers

Given:

Power for coffee maker = 1600 watts

Time indicated for the cofee maker = 10 minutes

Power for microwave = 1100 watts

Time indicated for the microwave = 4 minutes

Cost per hour of electrical appliances = $0.08 kwh

Let's find the total cost to use the appliances.

First convert the power to from watts to kilowatts by dividing by 1000.

\(\begin{gathered} P_{coffemaker}=\frac{1600}{1000}=1.6\text{ kw} \\ \\ P_{microwave}=\frac{1100}{1000}=1.1\text{ kw} \end{gathered}\)

Next step is to convert the time from minutes to hours:

\(\begin{gathered} T_{coffeemaker}=\frac{10}{60}=\frac{1}{6}\text{hour} \\ \\ T_{microwave}=\frac{4}{60}=\frac{1}{15}hour \end{gathered}\)

Thus, to find the total cost to use the appliances, we have:

\(\text{Total cost = \lbrack(1.6}\ast\frac{1}{6})+(1.1\ast\frac{1}{15})\rbrack\ast0.08\)

Solving further:

\(\begin{gathered} \text{Total cost = \lbrack{}0.2}67+0.073\rbrack\ast0.08 \\ \\ \text{Total cost = }(0.340)\ast0.08 \\ \\ \text{Total cost = }0.0272 \end{gathered}\)

Therefore, the cost to use the appliances is $0.0272 which is approximately $0.03

ANSWER:

$0.0272

A piston with stops containing water goes through an expansion process through the addition of heat. State 1 the pressure is 200 kPa and the volume is 2 m3. After half of the heat has been delivered the piston hits the stops corresponding to a volume of 5 m3. After all the heat has been delivered, state 2, the pressure is 1000 kPa with the piston resting on the stops. What is the work?

Answers

Answer:

The work will be "600 kJ/kg".

Explanation:

(1-a) ⇒ Constant Pressure

(a-2) ⇒ Constant Volume

The given values are:

In state 1,

Pressure, P₁ = 200 kPa

Volume, V₁ = 2m³

In state 2,

Pressure, P₂ = 1000 kPa

Volume, V₁ = 5m³

Now,

In process (1-a), work will be:

W₁₋ₐ = P₁(Vₐ - V₁)

On putting the values, we get

⇒ W₁₋ₐ = 200(5-2)

⇒         = 200(3)

⇒         = 600 kJ/kg

In process (a-2), work will be:

Wₐ₋₂ = 0

∴ (The change in the volume will be zero.)

So,

Total work = (W₁₋ₐ) + (Wₐ₋₂)

⇒                    = 600 + 0

⇒                    = 600 kJ/kg

A frog is riding on the top of a cylindrical piece of wood floating in still water. Half of the wood, with a diameter of 4 cm and length 20 cm, is immersed in water. The density of water is 1 gm/cc. a) What is the mass of the wood along with the frog? b) After the frog slowly goes into the water only one third of the wood remains immersed in water. Calculate the mass of the frog. c) Calculate x, the distance between the water level and the center of the circular end of the wooden piece. d) Briefly describe the motion of the wood after the instance the frog moves into the water. Give a rough sketch of x as a function of time.​

Answers

The total mass of the wood along with the frog is 120π gm.

The mass of the frog is (160/3)π gm.

How to calculate the Mass

The volume of the wood that is immersed in water is given by the volume of a cylinder with a radius of 2 cm and a height of 10 cm, which is V1 = π(2cm)²(10cm) = 40π cm³. The mass of the water displaced by this volume of wood is m1 = V1ρ = 40π gm. The mass of the remaining part of the wood above water is m2 = ρV2 = ρ(π(2cm)²(10cm)) = 80π gm.

mTherefore, the total mass of the wood along with the frog is m1 + m2 = 120π gm.

b) After the frog goes into the water, the volume of the wood that is immersed decreases to V3 = (1/3)π(2cm)^2(20cm) = (80/3)π cm^3. The mass of the water displaced by this volume of wood is m3 = V3ρ = (80/3)π gm. Therefore, the mass of the frog is (m1 + m2) - m3 = (120π - (80/3)π) gm = (240/3)π - (80/3)π = (160/3)π gm.

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What must you know about a nuclear reaction to calculate the amount of
energy it will produce?
OA. The sum of the total nuclear mass before and after the reaction
OB. The difference between the total nuclear mass before and after
the reaction
OC. The ratio of total nuclear mass before the reaction to the total
nuclear mass after the reaction
D. The product of the total nuclear mass before and after the
reaction

Answers

B. The difference between total nuclear mass before and after the reaction.

This is because you can see how much nuclear matter had actually been used in the reaction by finding the difference between the initial mass and final mass.

A student walks up a hill. The student’s friend has the same mass and walks up the same hill, but completes the journey in less time. Which statement is true about the situation?

Answers

Since they both expended the same amount of energy, the statement that is true about the situation is: The student's friend developed more power than the student.

The correct option is C.

What is mechanical power?

The rate at which mechanical energy can be given to a system is known as mechanical power. Remember that power is the transfer of energy over a given period of time. Although it can also be measured in watts, mechanical power is frequently expressed in horsepower.

Mathematically;

Power = work done/time taken

Since the student's friend walks up the hill at a faster rate, he developed more power than the student.

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Complete question:

A student walks up a hill. The student’s friend has the same mass and walks up the same hill, but completes the journey in less time. Which statement is true about the situation?

a. The student developed more power than the friend

b. The student expended more energy than the friend

c. The student's friend developed more power than the student

d. The student's friend expended more energy than the student

When an object is placed within the focal length of a convex lens, the image appears on the same side as the object itself. This situation is shown below. In this situation, which of the following statements is true?

When an object is placed within the focal length of a convex lens, the image appears on the same side

Answers

Answer:

the image formed is virtual, this means that it is the prolongations of the rays that form the image. It is straight and magnified by the quantity

Explanation:

In a lens there is a relationship between the focal length, the distance to the object and to the image given by the constructor equation

          1 / f = 1 / o + 1 / i

where is the focal length, or and i are the distance to the object and the image respectively.

In the case presented, the object is within the focal length, so the image formed is virtual, this means that it is the prolongations of the rays that form the image. It is straight and magnified by the quantity

         m = - i / o

Answer:A

Explanation:Got it right :)

The magnetic field perpendicular to a single wire loop of diameter 10.0 cm decreases from 0.50 T to zero. The wire is made of copper and has a diameter of 2.0 mm and length 1.0 cm. How much charge moves through the wire while the field is changing?

I know how to do the calculations, but can someone please explain what is the 10cm diameter and 2mm diameter? Why is there one wire and two diameters? I understand this problem mathematically but not conceptually.

Answers

Hi there!

We can begin by using Lenz's Law:
\(\epsilon = -N\frac{d\Phi _B}{dt}\)

N = Number of Loops

Ф = Magnetic Flux (Wb)
t = time (s)

Also, we can rewrite this as:
\(\epsilon = -NA\frac{dB}{dt}\)

A = Area (m²)

Since the area is constant, we can take it out of the derivative.

This is a single wire loop, so N = 1.

Now, we can develop an expression for the induced emf.

We can begin by solving for the area:

\(A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2\)

We can also express dB/dt as:
\(\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}\)

Now, we can create an equation.

\(\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}\)

To solve the system, we must now develop an expression for current given an emf and resistance.

Begin by calculating the resistance of the copper wire:
\(R = \frac{\rho L}{A}\)

ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)

A = cross section area (m²)

Solve:
\(R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m\)

Now, we can use the following relation (Ohm's Law):

\(\epsilon = iR\\\\\epsilon = \frac{Q}{t}R\)

*Since current is equivalent to Q/t.

Plug in the value of R and set the two equations equal to each other.

\(\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}\)

Cancel out 't'.

\(Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}\)

When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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A child at the top of a slide has a gravatational store of 1800j what is the childs maximum kinetic store as he slides down explain your answer

Answers

Answer:

1800 J

Explanation:

Energy is conserved, so the maximum kinetic energy equals the change in gravitational energy.

Consider a river flowing toward a lake at an average speed of 3 m/s at a rate of 550 m3/s at a location 58 m above the lake surface. Determine the total mechanical energy of the river water per unit mass (in kJ/kg) and the power generation potential of the entire river at that location (in MW). The density of water is 1000 kg/m3, and the acceleration due to gravity is 9.81 m/s2. The total mechanical energy of the river per unit mass is kJ/kg. The power generation potential of the entire river at that location is MW..

Answers

Answer:

1. 0.574 kJ/kg

2. 315.7 MW

Explanation:

1. The mechanical energy per unit mass of the river is given by:

\( E_{m} = E_{k} + E_{p} \)

\( E_{m} = \frac{1}{2}v^{2} + gh \)

Where:

Ek is the kinetic energy

Ep is the potential energy

v is the speed of the river = 3 m/s

g is the gravity = 9.81 m/s²

h is the height = 58 m

\( E_{m} = \frac{1}{2}(3 m/s)^{2} + 9.81 m/s^{2}*58 m = 0.574 kJ/Kg \)

Hence, the total mechanical energy of the river is 0.574 kJ/kg.

2. The power generation potential on the river is:

\( P = m(t)E_{m} = \rho*V(t)*E_{m} = 1000 kg/m^{3}*550 m^{3}/s*0.574 kJ/kg = 315.7 MW \)

Therefore, the power generation potential of the entire river is 315.7 MW.

I hope it helps you!

Question 13 of 25
Which of the following best describes the function of an electric motor?
29
о A. Converts stored potential energy into mechanical energy
B. Converts mechanical energy into electrical energy
о C. Converts electric energy into mechanical energy
D. Converts the voltage of an alternating current source
SUB

Answers

An electric motor converts electric energy into mechanical energy. So, the right option is C.

In contrast to an electric generator, an electric motor transforms electrical energy into mechanical energy.

They function according to electromagnetism's principles, which demonstrate that a magnetic field's electric current exerts a force.

In the magnetic field, this force produces a torque that spins a loop of wire, causing the motor to function.

Fans, power tools, appliances, electric vehicles, and hybrid vehicles are just a few examples of the many uses for electric motors.

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how many cubic feet are in 6,117 ounces

Answers

6.388 or 6.388468 cubic feet..

not sure

7 , 1 , 5 , 3 , multiple choice quiz is on apex

7 , 1 , 5 , 3 , multiple choice quiz is on apex

Answers

From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.

What is a histogram?

A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.

Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.

Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2

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A corpse is discovered in a room that has its temperature held steady at 25oC. The CSI ocers ar- rive at 2pm and the temperature of the body is 33oC. at 3pm the body's temperature is 31oC. Assuming Newton's law of cooling and that the temperature of the living person was 37oC, what was the approximate time of death

Answers

Answer: Around 0:35 Pm or 12:35 Am

Explanation:

The equation that describes the cooling of objects can be written as:

T(t) = Ta + (Ti - Ta)*e^(k*t)

Where Ta is the ambient temperature, here Ta = 25°C.

Ti is the initial temperature of the body, we have Ti = 37°C.

t is the time.

k is a constant.

So our equation is:

T(t) = 25°C +12°C*e^(k*t)

at 2pm, the temperature was 33°C

at 3pm, the temperature was 31°C.

we want to find the hour where we have our t = 0, suppose this hour is X.

then we can write our times as:

2pm ---> 2 - X

3pm ----> 3 - X

and our equations are:

33°C = 25°C + 12°C*e^(k2 - k*X)

31° = 25°C + 12°C*e^(k3 - k*X)

So we have two equations and two variables, let's solve the system.

first, simplify it a bit, for the first eq:

33 - 25 = 12*e^(k2 - k*X)

8/12 = e^(k2 - k*X)

ln(8/12) = k*2 - k*X

for the second equation we have:

31 - 25 = 12*e^(k3 - k*X)

6/12 = e^(k3 - k*X)

ln(6/12) = k*3 - k*X

So our equations are:

1) ln(2/3) = 2*k - X*k

2) ln(1/2) = 3*k - X*k

First, let's isolate one of the variables in one of the equations. let's isolate k in the first equation.

ln(2/3)/(2-X) = k

now we can replace it in the second equation:

ln(1/2) = 3*ln(2/3)/(2 - X) - X*ln(2/3)/(2-X)

now let's solve it for X, i will take a = ln(1/2) and b = ln(2/3) so it is easier to read.

a = 3*b/(2 - X) - X*b/(2 - X)

a*(2 - X) = 3*b - X*b

2a - aX = 3b - Xb

X(a - b) = 2a - 3b

X = (2*ln(1/2) - 3*ln(2/3))/(ln(1/2) - ln(2/3)) = 0.590

now, knowing that one hour has 60 minutes, then this is:

0.59*60m = 35 minutes

So the hour of death is 0:35 Pm or 12:35 Am

8. A 2 kg flower pot weighing 20 N falls from a window ledge.
How large must air resistance be in order that the pot fall
with an acceleration of 8 m/s2?

Answers

The magnitude of the force of air resistance opposing the downward motion of the pot is 4 N.

The given parameters;

mass of the flower pot, m = 2 kgweight of the flower pot, W = 20 N

Apply Newton's second law of motion to determine the force of the air resistance acting upward to oppose the motion of the pot falling downwards.

This air resistance force decreases the magnitude of the downward force because it limits the downward motion of the pot as it falls from the window.Let the air resistance = F

From Newton's second law of motion;

\(\Sigma F = ma\\\\W - F = ma\\\\a = \frac{W - F}{m} \\\\8 = \frac{20 - F}{2} \\\\20 - F = 16\\\\F = 20 - 16\\\\F = 4 \ N\)

Thus, the magnitude of the force of air resistance opposing the downward motion of the pot is 4 N.

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a car travelling at 18 km/hr accelerates uniformly at 2m per seconds square. calculate its velocity in km/hr in 5 seconds ​

Answers

1 km = 1000 m

1 hr = 3600 s

So, 18 km/hr = (18 * 1000) / (3600) m/s = 5 m/s

And 2 m/s^2 = 2 m/s^2

Now, we can use the formula for final velocity (v) when an object starts with an initial velocity (u) and accelerates at a constant rate (a) for a given time (t):

v = u + at

Plugging in the values, we get:

v = 5 + (2 * 5) m/s v = 15 m/s

To convert this back to km/hr, we use the inverse conversions: v = (15 * 3600) / (1000) km/hr v = 54 km/hr

Therefore, the car’s velocity in km/hr after 5 seconds is 54 km/hr.

PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Magnetic flux of earth is maximum at

Answers

When it’s equal to zero.

ITS ACTUALLY ASTRONOMY

What is the name for a star that has two shells of hydrogen and helium undergoing fusion?

A. asymptotic giant branch star

B.Supergiant

C. hypergiant

D. supernova


*please help thx*

Answers

Answer:

A. Asymptotic giant branch star

Explanation:

Hope this helped.

Answer:

asymptotic giant branch star

Explanation:

Plato/Edmentum

ITS ACTUALLY ASTRONOMYWhat is the name for a star that has two shells of hydrogen and helium undergoing

what are Newton's 3 laws

Answers

Answer:

Newton 3 laws

Explanation:

1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.

Answer- In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Hope this helps:)

PLEASE HELP
The spine is part of which system?
A. Circulatory System
B. Central Nervous System
C. Endocrine System

Answers

Answer:

Explanation:

B. Central Nervous System

The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.

Answers

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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Two blocks with masses 2.00 kg and 4.00 kg are placed side-by-side on a frictionless horizontal surface. A horizontal force with a magnitude of 5.20 N is applied to the 2.00-kg block perpendicular to its surface. What is the magnitude of the force on the 4.00-kg block?
a. 2.60
b. 3.11
c. 3.47
d. 3.89

Answers

The magnitude of the force on the 4.00-kg block is 3.47 N.

The given parameters:

Mass of first block, m1 = 2 kgMass of second block, m2 = 4 kgHorizontal force, F = 5.2 N

Acceleration of both blocks;The acceleration of both blocks is calculated by applying Newton's second law of motion.

\(a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2\)

The magnitude of the force on the 4.00-kg block is calculated as follows;

F = ma

F = 4 x 0.867

F = 3.47 N

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The density of diamond is 3.51 g/cm^3, and the density of platinum is 21.43 g/cm^3. If equal masses of diamond and platinum are transferred to equal volumes of water in separate graduated cylinders, which graduated cylinder would have the greatest volume change? Explain or show with a sample calculation.

Answers

The graduated cylinder with the greatest volume change is the one containing the diamond, as it displaced more water than the cylinder containing the platinum.

To determine which graduated cylinder would have the greatest volume change, we need to calculate the volume of water displaced by each object. The volume of water displaced is equal to the volume of the object, as water is displaced to make room for the object.

The graduated cylinder with the greatest volume change will have the larger volume of water displaced.

The formula for calculating the volume of an object is:

Volume = Mass / Density

Let's assume we have 1 gram of diamond and 1 gram of platinum. Using the given densities, we can calculate the volumes of the objects as follows:

Volume of diamond = 1 g / 3.51 g/cm^3 = 0.284 cm³

Volume of platinum = 1 g / 21.43 g/cm^3 = 0.047 cm³

Then, in separate graduated cylinders, we transfer equal masses of diamond and platinum to equal volumes of water. As previously stated, the volume of water displaced by each object is equal to the volume of the object. As a result, for each graduated cylinder, the volume change equals the volume of water displaced by the object. Using the previously calculated volumes, we get:

Volume change for diamond = 0.284 cm³

Volume change for platinum = 0.047 cm³

Therefore, the graduated cylinder with the greatest volume change is the one containing the diamond, as it displaced more water than the cylinder containing the platinum.

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If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?

Answers

Answer:

V=u+at

=4+4*2.5

=14m/s

Explanation:

Initial velocity =4m/s

acceleration =4m/(second) squared

time =2.5 seconds

v=u+at

v=4+4*2.5

v=14m/s

five physical properties of metals

Answers

Metals are malleable and ductile.
Metals are good conductors of heat and electricity.
Metals are lustrous (shiny) and can be polished.
Metals are solids at room temperature (except mercury, which is liquid).
Metals are tough and strong.
hope this helps!

Students want to investigate the inverse relationship between the pressure and temperature of an ideal gas as predicted by the ideal gas law. Their plan is to use a gas filled cylinder with a movable piston on one end and a heater inside that can be turned on and off. The students will the measure the pressure and temperature of the gas. Which of the following refinements to this procedure will allow the students to observe the predicted relationship between pressure and temperature? Select two answers
A. Start with enough gas to have a pressure near atmospheric pressure, and repeat the experiment, removing gas from the cylinder each time.
B. Fix the piston in place so the volume of the pas remains constant.
C. Ensure the piston and cylinder walls are insulated to the gas can reach equilibrium for each set of measurements
D. Conduct the investigation under conditions of very high pressure to ensure ideal gas behavior

Answers

Answer:

Option B, Fix the piston in place so the volume of the pas remains constant

Explanation:

As we know

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)

The effect on variable due to another variable can be studied by keeping the third variable constant.

Hence, in order the study the variation of temperature with pressure or vice versa, the volume needs to fixed at a certain value.

Hence, option B is correct

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