I don't understand this QUESTION​

The net force on particle q3 is -3.49 x 10^-3 N.

The net force on particle q3 can be calculated by considering the electric forces between q3 and each of the other particles, and then adding them vectorially. The electric force between two charged particles can be calculated using Coulomb's law:

\(F = k * |q1 * q2| / r^2\)

where k is Coulomb's constant (8.9875 x 10^9 N * m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.

First, let's calculate the electric force between q3 and q2:

\(F12 = k * |-84.2 uC * 90.6 uC| / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 uC^2) / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 x 10^-6 C^2) / (0.432 m)^2\\= 3.05 x 10^-3 N\)

Next, let's calculate the electric force between q3 and q1:

\(F13 = k * |-84.2 uC * -75.8 uC| / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 uC^2) / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 x 10^-6 C^2) / (0.876 m)^2\\= -6.54 x 10^-3 N\)

Finally, the net force on particle q3 is given by the vector sum of the individual forces:

Fnet = \(F12 + F13 = 3.05 x 10^-3 N - 6.54 x 10^-3 N = -3.49 x 10^-3 N\)

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In the absence of air resistance, the launch angle of the projectile results in the longest range is found to be 45°.

The launch angle may be defined as the vertical angle at which the ball leaves a player's bat after being struck. Average Launch Angle (aLA) is calculated by dividing the sum of all Launch Angles by all Batted Ball Events.

The angle between an input ray and the fiber axis. If the end face of the fiber is perpendicular to the fiber axis, the launch angle is equal to the angle of incidence. The angle of a projectile's initial velocity is definitely calculated when measured from the horizontal direction. These angles are typically 90° or less.

Therefore, in the absence of air resistance, the launch angle of the projectile results in the longest range is found to be 45°.

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Yes, it contains two leading zeroes.

A leading zero are zeroes before the non-zero digits.

There are 2 zeroes before the non-zero digits.

Best of Luck!

The percent composition by mass of nitrogen in NH\(_{4}\)Oh (gram-formula mass = 35 grams/mole) is equal to 40% N.

Meaning of Nitrogen: Nitrogen (N), a nonmetallic element belonging to Periodic Table Group 15. It is a colorless, flavorless, and odorless gas that makes up the majority of the atmosphere on Earth and is a component of all living things.

You must divide the element's atomic mass (AM), which is 14 for nitrogen, by the total compound's molar mass (MM), then multiply the result by 100 to determine the percent composition of an atom by mass. The following is the formula for calculating percent composition.

\(=\frac{14}{35} *100\)

\(=\frac{1400}{35}\)

\(= 40\)

Therefore the percent composition by mass of nitrogen in NH₄OH is

40% N

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Answer:

i think its bulb 2

Explanation:

Answer:q

Explanation:

The marked part x is inside the circle hence, the direction will be same in all points. Therefore, the correct label is x includes a magnitude.

There are two types of physical quantities namely, scalar and vector quantities. Scalar quantities or variables are those which are having magnitude only and not depends upon the direction.

Temperature, volume, refractive index, energy  etc. are scalar quantities. Vector quantities are those having both magnitude and direction. Force, acceleration, velocity, work done etc. are vector quantities which depends on the direction.

The marked area x is a point inside a circle. Therefore its path of motion or change is circular and thus does not affects its magnitude. Thus it have no directional change and has a magnitude.

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Answer:

56.916  kg m/s

Explanation:

Convert g to kg        15.3 g =   .153 kg

.153 kg  *  372 m/s   = 56.916 kg*m/s

Objects move relative to background such that it is covered and  uncovered  - start walking, the changes that occur in the surfaces, contours and textures provide information for perception.

Signals from the ocular, vestibular, and proprioceptive systems, among others, are used to perceive motion. One sensory system's knowledge is not reliable on its own.

The current illusion demonstrates how motion signals present throughout the scene affect how an object's perceived location is perceived. Evidently, the predominate motion signals across significant portions of visual space affect how any specific object's motion and location are perceived.

The visual system uses the shifting retinal image to deduce the trajectory and 3D structure of the moving object. The visual system infers the motion and structure of an object when the viewer is still and the object is moving.

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Answer:

Explanation:

constant speed is where the speed is the same throughout and instantaneous speed is speed given at any moment and average speed is a total distance traveled divided by the amount of time it took to travel it.

Answer:

Average speed is a measurement of velocity over a period of time.

Constant speed refers to your velocity at any point in time or period

Answer: (a) The velocity of the ball at its highest point is 10.12 m/s

              (b) The height that the ball goes is 1.13 m.

Mass of ball, m = 0.48 kg

Initial velocity, u = 8.8 m/s

Initial angle, θ = 36°

Using the principle of conservation of energy, the final velocity at the highest point can be found. The potential energy of the ball is converted into kinetic energy at its highest point, where the ball will stop momentarily. Then, we know that the total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴

mgh + 1/2mu² = mgh(max) where h(max) is the maximum height the ball attains. At this point, the kinetic energy will be zero. Therefore,0.5mv² + mgh = mgh(max). Since the kinetic energy of the ball at the top is zero, the total energy at the top of the projectile’s trajectory is the potential energy at the start of the trajectory, which is mgh.∴ v = √(2gh).

This is the velocity at the maximum height.

(a) Speed at its highest point:

Initial velocity of ball, u = 8.8 m/s

Angle made with horizontal, θ = 36°

The vertical component of velocity, v_y = usinθv_y = 8.8 sin 36°v_y = 5.0 m/s

Now using the formula, v = √(u² + v_y²)v = √(8.8² + 5.0²)v = √(77.44 + 25)v = √102.44v = 10.12 m/s

Therefore, the velocity of the ball at its highest point is 10.12 m/s

(b) How high does it go: lets calculate the potential energy at the initial position. Potential energy, Ep = mgh

Ep = 0.48 * 9.8 * 0Ep = 0 J. The total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴ mgh + 1/2mu² = mgh(max). Substituting the values,0.48*9.8*h(max) + 0.5*0.48*8.8² = 0.48*9.8*0hmax = (0.5*0.48*8.8²)/(0.48*9.8)h(max) = 1.13 m.

Therefore, the height that the ball goes is 1.13 m.

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Answer: it is located over Ellesmere Island, Canada

Explanation

it is now drifting away from North America and toward Siberia.

Answer:ellesmere island, Canada

The normal force exerted on the rider when passing point D is option D, 1.2Fg.

The weight of the person is Fg. The centripetal force is mv²/r, where m = mass of the person, v = velocity of the person, and r = radius of the wheel.

The velocity of the person is equal to the velocity of the wheel, which is constant. The radius of the wheel is also constant.

Therefore, the centripetal force is always equal to mv²/r.

At point D, the velocity of the person = √2gR, where g = acceleration due to gravity.

Therefore, the centripetal force at point D is equal to mv²/r = m(2gR)/r = 2mg.

The total force on the person at point D = normal force + the centripetal force. The normal force = weight of the person + the centripetal force.

Therefore, the normal force at point D is equal to Fg + 2mg = 1.2Fg.

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Complete question:

An amusement park ride consists of a large vertical wheel of radius R that rotates counterclockwise on a horizontal axis through its center, as shown above. The cars on the wheel move at a constant speed v. Points A and D represent the position of a car at the highest and lowest point of the ride, respectively. A person of weight F, sits upright on a seat in one of the cars. As the seat passes point A, the seat exerts a normal force with magnitude 0.8F_{g} on the person. While passing point A, the person releases a small rock of mass m, which falls to the ground without hitting anything.

9. What is the normal force exerted on the rider when passing point D?

(A) 0.2F_{g}

(B) 0.8F_{g}

(C) 1F_{g}

(D) 1.2F_{q}

A spectrometer (c) is used by astronomers to separate light into its individual colours.

A spectrometer is a tool used in science to examine the characteristics of light. It functions by dividing light into its many wavelengths or colours, enabling astronomers to examine the spectra of celestial objects' emissions and absorptions. Spectrometers can be made to work in the visible, ultraviolet, and infrared wavelength ranges, among others. A slit to let light through, a dispersion component such a prism or diffraction grating, and a detector to assess the intensity of the various wavelengths are the standard components of such devices.

Astronomers can create a spectrum—a graph depicting the intensity of light at each wavelength—by passing light through a spectrometer. This spectrum offers important details regarding the makeup, temperature, and motion of celestial objects. Astronomers can identify elements that are present, ascertain their abundances, and investigate a variety of physical processes taking place in celestial objects by carefully examining the distinct patterns and features in the spectrum.

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Answer:

Material medium

compressions and rarefactions

Explanation:

A sound wave is an example of a mechanical wave. All mechanical waves require a material medium for propagation. The medium for the propagation of sound is air. This is the reason why, if you cover your mouth, it will be difficult for another person to hear whatever you are saying.

Sound is also a longitudinal wave. Longitudinal waves are described in terms of compressions and rarefactions. Compressions refer to areas where air molecules crowd together while rarefactions refer to areas where the air molecules spread out.

Answer:

The sea level will be 5m higher in 1667 y (years)

Explanation:

From the question, the rate at which the ocean's level is currently rising is about 3mm per year.

First, we will convert mm (millimeter) to m (meter)

1 mm = 0.001 m

Then,

3 mm = 3 × 0.001 m

= 0.003m

That is, the rate at which the ocean's level is currently rising is about 0.003m per year.

Now, to determine how long it will take for the ocean's level be 5 m higher than now at the given rate,

If the ocean rises 0.003 m in 1 year, then

the ocean will rise 5 m in x years

x = (5 m × 1 year) / 0.003 m

x = 5 / 0.003

x = 1666.67 years

x ≅ 1667 years

Hence, the sea level will be 5m higher in 1667 y (years)

A wave pulse travels along the horizontal string. As the pulse enacts a point on the string. The point moves vertically up and then back down again. The speeds could not be uniquely corresponded, because there is no fixed relationship between them.

A simple type of wave called a pulse is produced. The pulse pushes down the string and so everyplace the pulse goes that part of the string attains kinetic and elastic energy. In general, a wave is characterized as a disruption in a medium that transports both energy and momentum. Wave interference is the consequence of the interactions of multiple waves. Wave interference usually provokes wave beats. A wave pulse is a quick, non periodic, wave created by a single input of energy instead than a continuous or recounted input of energy.

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The mountain stream is 30 km long and experiences an elevation drop of 1300 meters, resulting in a gradient of 43.33 meters per kilometer. The water flows downhill from its starting point to join the main river.

The given information includes its length, starting elevation, and ending elevation. Here are a few additional details we can derive from the given information:

1. Elevation change: The stream starts at an elevation of 2000 meters above sea level and ends at 700 meters above sea level. Therefore, the stream experiences an elevation drop of 2000 - 700 = 1300 meters over its 30 km length.

2. Gradient: The gradient of the stream refers to the rate at which the stream's elevation changes over a given distance. In this case, the stream's gradient can be calculated by dividing the elevation change (1300 meters) by the length of the stream (30 km): 1300 meters / 30 km = 43.33 meters per kilometer.

3. Flow direction: The stream flows from its starting point, which is at a higher elevation, towards its endpoint where it joins the main river. The flow of water is typically downhill, following the force of gravity.

These details provide a basic understanding of the mountain stream's characteristics in terms of elevation, length, elevation change, gradient, and flow direction.

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If the distance between two objects is 4.00 m and the distance is tripled, then the new distance will be 12.00 m.

To find out the new distance, you need to multiply the original distance by the factor by which it is tripled, which is 3.In other words, if the distance between two objects is "d", and it is tripled, then the new distance is 3d.

Using this formula, if the original distance is 4.00 m, then the new distance will be 3 x 4.00 m = 12.00 m.

The new distance is three times the original distance.

Therefore, the new distance between the two objects will be 12.00 meters if the original distance was 4.00 meters and it was tripled.

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All of the options listed are important safety measures that should be present in a laboratory, but an eyewash station is the one that has no substitute when it comes to lab safety.

An eyewash station is a crucial safety device that is used to rinse the eyes when they come into contact with chemicals or other hazardous substances. It provides a steady stream of water that can quickly flush out any contaminants that may be present in the eye, preventing further damage or injury. While spill containment kits, fire extinguishers, and laboratory showers are also essential safety measures, they do have substitutes. For example, in the case of a spill, absorbent materials can be used in place of a spill containment kit. However, when it comes to the safety of your eyes, there is simply no substitute for an eyewash station. It is a critical safety device that should always be present in any laboratory environment to protect the health and safety of laboratory workers.

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Among the list of essential safety equipment in a lab, an eyewash station could be considered irreplaceable. It's designed to reduce the potential harm caused by eyes being exposed to dangerous substances, requiring immediate and prolonged washing.

In terms of lab safety, there are important elements that have no substitution. A spill containment kit, fire extinguisher, and a laboratory shower can be very important. However, considering the fact that an eyewash station can be critical in reducing the impact of an accident involving the eyes - as illustrated by the figure highlighting the severe consequences of working without eye protection - it could be argued that an eyewash station has no substitution when it comes to safety in a lab environment.

It's used in the event that a harmful or corrosive substance comes into contact with the eyes. Safety guidelines suggest that once a person's eyes are potentially exposed to such substances, they should be washed immediately with water for at least 15-20 minutes.

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Answer:

(i) The volume of the cylindrical beaker is given by:

V = A x h = (25 cm^2) x (10 cm) = 250 cm^3

The mass of the oil in the beaker is given by:

m_oil = density x volume = (0.8 g/cm^3) x (250 cm^3) = 200 g

The total mass of the beaker and oil is therefore:

m_total = m_beaker + m_oil = 50 kg + 0.2 kg = 50.2 kg

(ii) The volume of the aluminum is given by:

V_aluminum = m_aluminum / density = 66 g / (2.2 g/cm^3) = 30 cm^3

When the aluminum is lowered into the beaker, it displaces an equal volume of oil. Therefore, the volume of oil that overflows is 30 cm^3.

(iii) The final mass of the beaker and its contents is the sum of the mass of the beaker, the mass of the oil remaining in the beaker, and the mass of the aluminum:

m_final = m_beaker + m_oil + m_aluminum = 50 kg + 0.17 kg + 0.066 kg = 50.24 kg

To calculate the mass of the remaining oil, we need to subtract the volume of aluminum from the volume of the beaker and multiply by the density of the oil:

V_remaining_oil = (A x h) - V_aluminum = (25 cm^2 x 10 cm) - 30 cm^3 = 220 cm^3

m_remaining_oil = density x V_remaining_oil = 0.8 g/cm^3 x 220 cm^3 = 176 g

Therefore, the final mass of the beaker and its contents after the overflow liquid has been wiped off is 50.24 kg, and there is 176 g of oil remaining in the beaker

A 392 N wheel falls off a moving vehicle and rolls along a highway without slipping. It is revolving at 50 rad/s near the base of a slope. The wheel's radius is 0.6 meters, and its moment of inertia with respect to its axis of rotation is 0.8MR2. As the wheel rolls up the hill to come to a standstill h above the hill's base, friction exerts 3000 J of effort on it.  The hill is approximately 26.79 meters tall.

Finding the wheel's initial kinetic energy is the first step.

Since it is rolling without slipping, the kinetic energy is given by the sum of the translational and rotational kinetic energies:

K1 = (1/2)\(mv^2\) + (1/2)Iω\(^2\)

where m is the mass of the wheel, v is its linear velocity, I is its moment of inertia about its rotation axis, and ω is its angular velocity.

We can use the fact that the wheel is rotating at 50 rad/s at the bottom of the hill to find ω. The linear velocity of the wheel can be found from its angular velocity using the formula v = ωr, where r is the radius of the wheel. Thus:

v = ωr = 50 rad/s * 0.6 m = 30 m/s

The mass of the wheel can be found from its weight using the formula:

F = ma

where F is the weight of the wheel (392 N), and a is its acceleration. Since the wheel is not accelerating vertically, we have:

F = mg

where g is the acceleration due to gravity. Solving for m, we get:

m = F/g = 392 N/9.81 \(m/s^2\) = 40 kg

The moment of inertia of the wheel about its rotation axis is given as 0.8MR^2, where M is the mass of the wheel and R is its radius. Thus:

I = \(0.8MR^2\)= 0.8 * 40 kg *\((0.6 m)^2\) = 11.52 kg \(m^2\)

Substituting the values we have found into the expression for K1, we get:

K1 = \((1/2)mv^2\) + (1/2)Iω\(^2\)

= \((1/2)(40 kg)(30 m/s)^2 + (1/2)(11.52 kg m^2)(50 rad/s)^2\)

= 13500 J

The work done by friction is given as 3000 J. Since the wheel comes to a stop at the end of the hill, all of the initial kinetic energy is converted into potential energy:

K1 - Wf = mgh

where h is the height of the hill. When we substitute the values we discovered, we obtain:

13500 J - 3000 J = (40 kg)gh

Solving for h, we get:

h = (10500 J)/(40 kg * 9.81 \(m/s^2\)) = 26.79 m

Therefore, the height of the hill is approximately 26.79 meters.

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The angular speed of the snowball as it reaches the end of the inclined section of the roof can be calculated using the principle of conservation of energy.

The conservation of energy states that the total mechanical energy of a system remains constant if no external forces are acting on it. In this case, as the snowball moves down the inclined section of the roof, the only force acting on it is gravity.

Initially, the snowball has gravitational potential energy due to its height on the roof. As it moves down the inclined section, this potential energy is converted into kinetic energy. The rotational kinetic energy of the snowball is given by the equation: KE_rotational = (1/2) * I *ω², where I is the moment of inertia and ω is the angular speed.

Since the snowball is rolling without slipping, we can relate the linear speed v and the angular speed ω by the equation: v = r * ω, where r is the radius of the snowball.

As the snowball reaches the end of the inclined section, all of its initial potential energy has been converted into kinetic energy. Therefore, we can equate the initial potential energy to the final rotational kinetic energy:

m * g * h = (1/2) * I *ω²

We can substitute the moment of inertia for a solid sphere, I = (2/5) * m * \(r^2\), and rearrange the equation to solve for ω:

ω = sqrt((10 * g * h) / (7 * r))

This gives us the angular speed of the snowball as it reaches the end of the inclined section of the roof.

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The solid forms of ice last longer because there is more weight with less surface area. This statement is false.

Factors like temperature, shape, size, humidity and impurities are some of the factor decides the time for which the ice survives. Even though larger ice particles may have more surface area than solid forms of ice, this does not always imply that they will persist longer.

In reality, due to the insulating effect of the ice itself, larger ice formations, like glaciers, can melt more quickly. In the end, a complex combination of physical, chemical, and environmental elements determines how long ice will last.

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Answer:

1.84 m

Explanation:

ME = KE + PE = 1/2mv² + mgh

600 J = 1/2(30 kg)(2 m/s)² + (30 kg)(9.8 m/s²)h

Solve for h:

600 J = 60 J + (294 kg·m/s²)h

h = 540J/294kg·m/s² = 1.84 m

Part A: The fundamental frequency of a pipe is given by the equation f1 = v/2L, where v is the speed of sound and L is the length of the pipe. Rearranging the equation, we get L = v/2f1. Given that the frequency of the standing wave shown in figure 1 is 225 Hz, we can calculate the fundamental frequency as follows:
f1 = 225 Hz/3 = 75 Hz
Part B: Using the equation above and the speed of sound in air at room temperature (v = 343 m/s), we can calculate the length of the pipe:
L = v/2f1 = 343 m/s / (2 x 75 Hz) = 2.29 m
Therefore, the length of the pipe is 2.29 meters.

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The length of the pipe to be L = (1/2)(3.04m) = 1.52 meters.

Part A: The frequency of the standing wave shown in Figure 1 is 225 Hz, which is the second harmonic frequency. Therefore, the fundamental frequency can be calculated by dividing 225 Hz by 2, which results in a fundamental frequency of 112.5 Hz.

Part B: The length of the pipe can be determined using the formula L = (n/2)λ, where L is the length of the pipe, n is the harmonic number, and λ is the wavelength of the sound wave. Since the fundamental frequency is 112.5 Hz, the wavelength can be calculated using the formula λ = c/f, where c is the speed of sound (approximately 343 m/s) and f is the frequency (112.5 Hz). This results in a wavelength of approximately 3.04 meters. Plugging in n=1, we find the length of the pipe to be L = (1/2)(3.04m) = 1.52 meters.

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Answer:

kinetic and I think sound energy

Answer:

kinetic energy

Explanation:

An apple falling to the ground has both potential energy and kinetic energy. As the apple falls, its potential energy is converted into kinetic energy, which is the energy an object has due to its motion. The apple gains kinetic energy as it falls and its velocity increases, and at the moment it reaches the ground, all of its potential energy has been converted into kinetic energy.


ALLEN

1) Determine the mass of the expelled CO2, 2) Calculate the acceleration of the CO2 using Newton's second law, and 3) Multiply the mass by the acceleration to obtain the force exerted by the CO2 on the system.

Newton's second law states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. To apply this principle to predict the force exerted by expelled CO2 on a system, the following steps can be followed:

Determine the mass of the expelled CO2: This can be achieved by measuring the mass of the CO2 or using known properties such as the molar mass of CO2 and the quantity of CO2 expelled.

Calculate the acceleration of the CO2: The acceleration can be determined by considering the forces acting on the CO2. In this case, the main force acting on the CO2 would be the expulsion force. Other factors such as air resistance can be taken into account if necessary.

Multiply the mass by the acceleration: Once the mass and acceleration are determined, multiply them together to obtain the force exerted by the CO2 on the system. The unit of force is typically Newtons (N).

By following this method and applying Newton's second law, it is possible to predict the force exerted by the expelled CO2 on the system. It is important to ensure accurate measurements and consider all relevant forces to obtain a reliable prediction.

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