I did A months ago and have completely forgotten how to do this, can anyone help?

Answer:

i believe it is 57

Step-by-step explanation:

since complimentary angles add up to 90 and angle 1 is 33 if you were to subtract 33 from 90 you would get 57

In linear equations, 18.816 is the cost of 2 2/5 pounds of salmon.

What are instances of linear equations?

grocery store sells salmon = $7.84 per pound

the cost of 2 2/5 pounds of salmon = \(2\frac{2}{5}\)  × 7.84

the cost of 2 2/5 pounds of salmon =  12/5  * 7.84

the cost of 2 2/5 pounds of salmon =   12 * 1.568

the cost of 2 2/5 pounds of salmon =   18.816

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Answer:

The answer to x is 107

Step-by-step explanation:

If the driver and truck weigh 4500 and the bridge is can hold 6000 lbs. than there is room for 1500 more lbs. multiply 14 by 100 and get 1400, than  multiply 14 by 7 and get 98. Add those to to get 1498. So the answer is x=107

Answer:

See below

Step-by-step explanation:

3 (x^2 + 3x) = 4

3 ( x + 3/2)^2   = 4 + 27/4  

The importance and advantage of using graph representation when organizing your data are that it makes data presentable, summarizing, better way of comparison of data.

An organized diagram or pictorial representation of the relationship between values or data is referred to as a graph. it is a a diagram that depicts a variable's variation in comparison to that of one or more other variables, such as a series of points, lines, line segments, curves, or areas.

The following are the three advantages of graphs:

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The best interpretation of these data is that there is a direct relationship between number of hours studied and the score on the test.

The correlation coefficient r measures the strength and direction of a linear relationship between two variables. In this case, the positive value of r = .59 indicates a direct (or positive) relationship between number of hours studied and the score on the test. This means that as the number of hours studied increases, the score on the test tends to increase as well.

Therefore, we can conclude that more study leads to a higher score on the test.

Option 1 and 2 are correct interpretations, while options 3 and 4 are incorrect. Option 3 implies a negative correlation coefficient, while option 4 implies an inverse relationship between the variables, which is not the case here.

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C. When there is no outlier, the mean is the appropriate measure of center.

When there are no outliers in a dataset, the mean is a good measure of center because it takes into account the values of all the data points. The median is also a good measure of center, but it may not be the best choice if there are extreme values or outliers in the dataset, as it can be influenced by those values. However, when there are no outliers, both the mean and the median are appropriate measures of center.

Option A is not true because the mean is not skewed in one direction when there is no outlier. Skewness refers to the shape of the distribution, and it can be affected by outliers, but not by the absence of outliers.

Option B is not true because the median is not skewed in one direction when there is no outlier. Skewness refers to the shape of the distribution, and the median is not affected by the shape of the distribution, but by the position of the values.

Option D is not true because the median can be used as the measure of center even when there is no outlier. It is a robust measure of center that is not influenced by extreme values.

The statement that is not always true is (b) every linearly independent set of vectors in \(R^n\) consists of at most n vectors.

(a) If u, v, and w are linearly independent vectors in a vector space, then u v, v w, and w are also linearly independent vectors in the vector space. This statement is true.

(b) Every linearly independent set of vectors in R^n consists of at most n vectors. This statement is not always true. For example, the set of vectors {(1, 0, 0), (0, 1, 0), (0, 0, 1), (1, 1, 1)} is linearly independent but consists of 4 vectors, which is greater than n=3.

(c) Every spanning set of R^n contains a basis of R^n. This statement is true.

(d) If the nullity of a matrix A is zero, then the linear system Ax=0 has only the trivial solution. This statement is true.

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Answer:

-243

Step-by-step explanation:

Answer:

\(h(x)=\frac{1}{5}x\)

Step-by-step explanation:

\(6x+y=4x+11y\\\\6x-4x=11y-y\\\\2x=10y\\\\y=\frac{2x}{10}\\\\y=\frac{1}{5}x\)

so h(x) is

\(h(x)=\frac{1}{5}x\)

Therefore , the solution of the given problem of inequality comes out to be the solutions x = -6 or x = -10 would be acceptable.

Algebra, which lacking a symbol for this difference, can represent it using a pair or group of numbers. Equity usually comes after equilibrium. Inequality is bred by the persistent gap of standards. Equality and disparity are not the same thing. As was my least preferred symbol, notwithstanding knowing that the pieces are often not connected or close to one another. (). No matter how small the variations, they all affect value.

Here,

Finding values of x that cause the left side of the inequality to be bigger than the right side is necessary to make the inequality -2x > 10 true. Divide both sides by -2 and invert the inequality sign to achieve this:

=> -2x > 10

=> x < -5

The inequality is therefore true for any value of x that is less than -5. For instance, the solutions x = -6 or x = -10 would be acceptable.

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Answer:

A=87.5

Step-by-step explanation:

Hope im right and this helps you

Answer:

what lesson..

Step-by-step explanation:

Kami will have $1,413.60 in the account after 4 years.

(1) Depositing $550 at 3% interest for one year generated a $16.50 profit for Abe.

(2) Jessi returned a $1,500 loan with a quarterly 3% rate and paid $1,511.25 in total.

(3) After keeping a deposit worth $418 at 2% for a year, Heath made an $8.36 profit. In 5.5 years, his account balance grew to $463.98.

(4) By depositing $825.50 at 4%, Pablo saw a $33.02 profit within a year.

(5) Kami put down $1,140 earning a $68.40 annual yield thanks to the 6% interest rate. Four years later, her account balance reached $1,413.60.

Interest = 1,140 * 0.06 * 4 = $273.60

Now, add the interest to the principal:

Total Amount = Principal + Interest = 1,140 + 273.60 = $1,413.60

Kami will have $1,413.60 in the account after 4 years.

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3x = 18

Divide both sides by 3 and simplify

x=6

Answer:

Step-by-step explanation:

assuming  that you need to find the value of x

3x = 18

-divide both sides by 3

3x/3 = 18/3

-use the facts that 3/3 =1 and 18/3 = 3*6/3 = 6

x = 6

The standard form equation for the hyperbola with center at the origin, vertices at (0, 3) and (0, -3), and foci at (0, 6) and (0, -6) is x²/9 - y²/36 = 1.

To find the standard form equation for a hyperbola with center at the origin, we need to use the following formula: ((x-h)²/a²) - ((y-k)²/b²) = 1

where (h,k) is the center of the hyperbola, a is the distance from the center to the vertices, and b is the distance from the center to the foci.

In this case, the center is at (0,0), a = 3, and b = 6.

Plugging these values into the formula, we get: ((x-0)²/3²) - ((y-0)²/6²) = 1 Simplifying this equation, we get: x²/9 - y²/36 = 1

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The events of removing balls from the bag can be analyzed as follows:

Disjoint events: Disjoint events, also known as mutually exclusive events, are events that cannot occur at the same time. In this scenario, if one ball is removed from the bag, it cannot be selected again. Therefore, the events of removing the first and second balls are disjoint since the first ball's removal makes it impossible for it to be selected again.

Independent events: Independent events are events where the outcome of one event does not affect the outcome of another event. In this case, since the first ball is not returned to the bag, the probabilities of selecting the second ball are affected by the removal of the first ball. Therefore, the events of removing the first and second balls are not independent.

Based on the above analysis:

- The events of removing the first and second balls are disjoint.

- The events of removing the first and second balls are not independent.

So, the events are disjoint, but not independent.

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Check the picture below.

\(\tan(56^o )=\cfrac{\stackrel{opposite}{10}}{\underset{adjacent}{w}}\implies w=\cfrac{10}{\tan(56^o )} \\\\[-0.35em] ~\dotfill\\\\ \tan(34^o )=\cfrac{\stackrel{opposite}{10}}{\underset{adjacent}{w+x}}\implies w+x=\cfrac{10}{\tan(34^o )} \implies x=\cfrac{10}{\tan(34^o )}-w \\\\\\ x=\cfrac{10}{\tan(34^o )}-\cfrac{10}{\tan(56^o )}\implies x\approx 8.1\)

Make sure your calculator is in Degree mode.

Answer:

n=3

Step-by-step explanation:

Triangle area: height*length*(1/2)

Rectangle area: width*length

Let's say x is the length, then our equation would be:

mx(1/2)=nx

we also know m is 6, so

6x(1/2)=nx

now we can solve for n

6x(1/2)=nx

3x=nx

3=n

n=3

Answer:

1.  Y = -1/4x + 1

3. Y = 2/5x + 1

5. Y = 4/5x + 5

7. Y = -x + 5

9. Y = -5/2x - 16

Step-by-step explanation:

Find the slope using the formula

Use the slope and one of the points to find the y-intercept

Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.

The expected value is 6.0.

The expected value (or mean) of a probability distribution can be obtained by the formulaµ = E(X) = ∑ xᵢP(xᵢ). The given probability distribution has a mean of 7, a median of 6, a standard deviation of 3, and a variance of 9. Therefore, we can get the expected value using the formulaµ = E(X) = ∑ xᵢP(xᵢ).

Mean = 7Median = 6Standard deviation = 3Variance = 9The formula for variance is:Variance = (Standard deviation)²9 = (3)²Variance = 9The formula for variance can be modified as:

Variance = E(X²) - [E(X)]²Variance + [E(X)]² = E(X²)Substituting the values,9 + 7² = E(X²)E(X²) = 58To find expected value (or mean), the formula is:µ = E(X) = ∑ xᵢP(xᵢ)The median is the value that separates the upper 50% of the distribution from the lower 50%.

The mean is a measure of the central tendency of the distribution. So, the probability distribution is skewed to the right. There are many possible ways to construct a probability distribution with the given mean, median, variance, and standard deviation.

One example of such a probability distribution is shown below:x: 0 1 5 6 9P(x): 0.05 0.1 0.4 0.3 0.15Using the formula µ = E(X) = ∑ xᵢP(xᵢ), the expected value isµ = 0(0.05) + 1(0.1) + 5(0.4) + 6(0.3) + 9(0.15)µ = 0.5 + 2 + 1.8 + 1.35 + 1.35µ = 6.0Thus, the expected value is 6.0.

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The total number of visitors to the zoo that day=3980.

Given:

cost of each ticket for an adult=$25

cost of each ticket for an adult=$10

Total ticket sales one day=$47,750.

⇒$25+$10=47,750

⇒25+10=47,750-----(1)

Also,

c=6a+270

6a-c=-270------(2)

multiplying eq(2) with 10 we get:

60a-10c=-2700----(3)

Adding eq(1) and eq(3) we get

25a+10c=47,750

60a-10c=-2700

--------------------------

85a=45050

--------------------

To calculate a value just divide 45050 by 85 we get

a=45050/85

a=530

Now to get the value of c substitutes a value.

c=60(530)+270

c=3450

Number of Adult visitors=530

Number of children visitors=3450

Total Number of visitors=3980.

Therefore, the total number of visitors to the zoo that day=3980.

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Answer:

A 6.09

Step-by-step explanation:

Answer:

5.625

Step-by-step explanation:

Answer:

$8.75

Step by Step Explanation:

10.00 - 1.25= $8.75

Answer:

Approximately $14.20

Step-by-step explanation:

Let the cost of the groceries be represented by c, then;

cost price + VAT = c + (5% of c)

To get the value of the cost, c, that would make him spend as close to $15. Since the tax is 5% of the cost price, then the cost price would be close to $15.

Let c = $14.20, then;

So that,

c + (5% of c) = 14.20 + (5% of 14.20)

                    = 14.20 + 0.71

                    = $14.91

Thus, the greatest total cost of groceries Darla can spend in order to spend as close to $15 as possible is approximately $14.20.

Answer:

They are 6 sunsets

Step-by-step explanation:

the sets are

(abc),(abd),(ade),(acd),(ace),(ade)

The expression cos⁡(−x)+tan⁡(−x)sin⁡(−x) simplifies to cos⁡(x)+tan⁡(x)sin⁡(x).

To find the minterms using Karnaugh maps (K-maps), we need to create the K-maps for each Boolean expression and identify the cells corresponding to the minterms.

a) For the expression wyz + w'x' + wxz':

We have three variables: w, x, and yz. We create a 2x4 K-map with w and x as the inputs for the rows and yz as the input for the columns:

\begin{array}{|c|c|c|c|c|}

\hline

\text{w\textbackslash x,yz} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & & & \\

\hline

\end{array}

Next, we analyze the given expression wyz + w'x' + wxz' and identify the minterms:

- For wyz, we have the minterm 111.

- For w'x', we have the minterm 010.

- For wxz', we have the minterm 110.

Placing these minterms in the corresponding cells of the K-map, we get:

\begin{array}{|c|c|c|c|c|}

\hline

\text{w\textbackslash x,yz} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & \textbf{1} & & \textbf{1} \\

\hline

\end{array}

Therefore, the minterms for the expression wyz + w'x' + wxz' are 111, 010, and 110.

b) For the expression A'B + A'CD + B'CD + BC'D':

We have four variables: A, B, C, and D. We create a 4x4 K-map with AB as the inputs for the rows and CD as the inputs for the columns:

\begin{array}{|c|c|c|c|c|}

\hline

\text{A\textbackslash B,CD} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & & & \\

\hline

\end{array}

Next, we analyze the given expression A'B + A'CD + B'CD + BC'D' and identify the minterms:

- For A'B, we have the minterm 10xx.

- For A'CD, we have the minterm 1x1x.

- For B'CD, we have the minterm x11x.

- For BC'D', we have the minterm x1x0.

Placing these minterms in the corresponding cells of the K-map, we get:

\begin{array}{|c|c|c|c|c|}

\hline

\text{A\textbackslash B,CD} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \textbf{1} \\

\hline

1 & \textbf{1} & \textbf{1} & \textbf{1} & \\

\hline

\end{array}

Therefore, the minterms for the expression A'B + A'CD + B'CD + BC'D' are 1000, 1011, 1111, and 0110.

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Answer:

start fraction, 5, dot, x, start superscript, 3, end superscript, divided by, x, start superscript, 2, end superscript, end fraction

for

x=2x=2

x=2

x, equals, 2

The given expression 5, start superscript, 12, end superscript, dot, 5, start superscript, 8, end superscript equivalent to the 5 start superscript 97 end superscript.

We have given that

\(5^{12}\cdot5^{85}\)

We have to find the equivalent expression

Here we use the exponent rule:

\(a^b\cdot a^c=a^{b+c}\\\)

here base is the same of both the number

If base are same then we can add the exponent

Therefore,In a given expression base is 5 therefore the

\(5^{12}\cdot5^{85}=5^{12+25}\\5^{12}\cdot5^{85}=5^{97}\)

Therefore the given expression \(5^{12}\cdot5^{85}\)equivalent to the \(5^{97}\).

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the expected value during a 1-month period is E(X) = λ / 12.

To solve the given problems, we'll use the Poisson distribution with λ = 9, where λ represents the average number of tornadoes observed in Kansas during a 1-year period.

a) Compute P(6 ≤ x ≤ 9):

To calculate this probability, we need to find the cumulative probability from 6 to 9 using the Poisson distribution.

P(6 ≤ x ≤ 9) = P(x = 6) + P(x = 7) + P(x = 8) + P(x = 9)

Using the Poisson probability formula:

P(x; λ) = (e²(-λ) × λ²x) / x!

P(x = 6) = (e²(-9) × 9²6) / 6!

P(x = 7) = (e²(-9) × 9²7) / 7!

P(x = 8) = (e²(-9) × 9²8) / 8!

P(x = 9) = (e²(-9) × 9²9) / 9!

Calculate each probability and sum them up to find P(6 ≤ x ≤ 9).

b) Compute P(6 < x < 9):

To calculate this probability, we need to find the cumulative probability from 7 to 8 using the Poisson distribution.

P(6 < x < 9) = P(x = 7) + P(x = 8)

Using the Poisson probability formula, calculate each probability and sum them up to find P(6 < x < 9).

c) Expected value during a 1-year period:

The expected value of a Poisson distribution is equal to its parameter λ.

Therefore, the expected value during a 1-year period is E(X) = λ = 9.

d) Expected value during a 1-month period:

To calculate the expected value during a 1-month period, we need to consider that the rate λ is given for a 1-year period. We can convert it to a 1-month period by dividing it by 12 (assuming an average of 12 months in a year).

Therefore, the expected value during a 1-month period is E(X) = λ / 12.

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