Hypothesis: In this section, please include the if/then statements you developed during your lab activity.These statements reflect your predicted outcomes for the experiment. You must use 1 metal and 2 non-metals for each combination. Note: There are only 14 possible combinations for this practice activity. If I use __________, _________________, and ________________, then I can make ___ new compounds in five minutes.

Answer:

53.491 g/mol

Explanation:

Create the chemical compound and find each individual element's molar mass. Lastly, add them up.

Answer:

0.8g.

Explanation:

So, in this question we are to calculate for the actual yield of the product, Say C.

Thus, the equation for Determining the percentage yield is given as;

Percentage yield = actual yield/ theoretical yield × 100 ---------------------(1).

Therefore, from equation one above we can calculate the value for the percentage yield for product C.

A + B ==========================> C.

From the given value we have that, before the reaction there are 1.0 g of A and 7.0 g of B, after the reaction; we have 0 gram of A and 5.2 gram of B. That means that A is the limiting reactant. Thus, A Determines the reaction.

Hence, the mass of product C = 1 g = 0.1 × 10^1 grams.

Therefore, using the reaction (1) above;

Percentage yield = actual yield/ theoretical yield × 100.

80 =( actual yield / 0.1 × 10^1 grams ) × 100.

80 × 0.1 × 10^1 grams = 100 × actual yield.

Actual yield = 0.8 g.

Taking into account the reaction stoichiometry and the definition of limiting reactant, HBr is the limiting reagent.

In first place, the balanced reaction is:

2 Al + 6 HBr → 2 AlBr₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 54 grams of Al reacts with 485.4 grams of HBr, 73.22 grams of Al reacts with how much mass of HBr?

mass of HBr= (73.22 grams of Al×485.4 grams of HBr)÷54 grams of Al

mass of HBr= 658.166 grams

But 658.166 grams of HBr are not available, 54.96 grams are available. Since you have less mass than you need to react with 73.22 grams of Al, HBr will be the limiting reagent.

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Answer:66 grams of Carbon Dioxide.

Explanation:

The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams.

C 3 H 8 + 5 O 2 = =3 C O 2 + 4 H 2 O

This is the balance equation for the burning of propane in Oxygen.

From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3

Convert 22 grams of propane to moles by dividing by the molar mass of propane.

3 x 12 = 36 grams

1 x 8 = + 8 grams

total = 44 grams/ mole.

22

44

= .5 moles of propane.

Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide.

Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide

1 x 12 = 12 grams

2 x 16 = +32 grams

total = 44 grams /mole.

1.5 moles x 44 grams/mole = 66 grams.

hope that helps :)

Answer:

they are not lustrous

hope it helps

Answer/Explanation:

No compounds must be made up of two or more elements. otherwise it wouldn't be a compound. There must be some type of combination or it isn't a compound.

the reason that pressure measured in mm of mercury decreases exponentially is because the air pressure itself decreases exponentially with altitude, and the height of the mercury column in the tube is directly proportional to the air pressure.

Pressure is often measured using a unit called millimeters of mercury (mmHg), which is based on the height of a column of mercury in a tube. This type of pressure measurement is called a mercury barometer.

When air pressure pushes down on the surface of a pool of mercury, it causes the mercury to rise up a tube until the pressure of the mercury in the tube exactly balances the air pressure pushing down on the surface of the mercury pool. The height of the mercury column in the tube is a measure of the air pressure.

The reason that the height of the mercury column decreases exponentially as you go up in altitude is because air pressure decreases exponentially with altitude. This is because the weight of the air above a particular altitude decreases with altitude, and therefore the air pressure at that altitude also decreases.

As the air pressure decreases with altitude, the mercury column in the tube has to decrease in height in order to balance the reduced pressure. This decrease in height is not linear, but instead it follows an exponential curve because the pressure change with altitude is exponential.

So in summary, the reason that pressure measured in mm of mercury decreases exponentially is because the air pressure itself decreases exponentially with altitude, and the height of the mercury column in the tube is directly proportional to the air pressure.

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steps that are followed in taking a stratified random sample are

i. Take a sample of size n/k from each strata, where n is the sample size and k is the number of strata

iv. Take a systematic sample from the population as a whole. Take random samples from each strata.

Stratified random sampling is a sampling method that divides the population into smaller groups called layers. Groups or hierarchies are organized based on the common characteristics or attributes of the members in the group. The process of dividing the population into groups is called hierarchization.

Stratified Random Sample Example:

Suppose a research team wants to determine a GPA for a college student in the United States. The research team is having a hard time collecting data from all 21 million college students. We decided to use 4,000 students to extract a random sample of the population.

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Answer:

B. 4.76 atm

Explanation:

\(P_1\) = Initial pressure = 3.8 atm

\(T_1\) = Initial temperature = \(25+273.15\ \text{K}\)

\(P_2\) = Final pressure

\(T_2\) = Final temperature = \(100+273.15\ \text{K}\)

From Gay Lussac's law we have

\(\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=P_1\dfrac{T_2}{T_1}\\\Rightarrow P_2=3.8\times\dfrac{100+273.15}{25+273.15}\\\Rightarrow P_2=4.76\ \text{atm}\)

The pressure inside the can would be \(4.76\ \text{atm}\).

Answer:

50.63 cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, V1 = 45.0 cm³, V2 = ?, T1 = 280 K, T2 = 315 K

Using; V1/T1 = V2/T2

45/280 = V2/315

Cross multiply

45 × 315 = 280 × V2

14175 = 280V2

V2 = 14175 ÷ 280

V2 = 50.625

V2 = 50.63 cm³

Answer:

Genetics is the scientific study of inherited variation. Human genetics, then, is the scientific study of inherited human variation.

Why study human genetics? One reason is simply an interest in better understanding ourselves. As a branch of genetics, human genetics concerns itself with what most of us consider to be the most interesting species on earth

\(\\ \tt\hookrightarrow C_{15}H_{32}+23O_2\longrightarrow 15CO_2+16H_2O\)

\(\\ \tt\hookrightarrow CO_2+CaO=CaCO_3\)

1) The balanced equation for the combustion of C15H32 (pentadecane) is:

C15H32 + 23O2 → 15CO2 + 16H2O

2) To test for the presence of carbon dioxide (CO2) in the products of the combustion of C15H32, one simple way is to bubble the gas through limewater (aqueous calcium hydroxide solution). When carbon dioxide is passed through limewater, it reacts with the calcium hydroxide to form a white precipitate of calcium carbonate according to the following chemical equation:

Ca(OH)2 + CO2 → CaCO3 + H2O

The formation of a white precipitate indicates the presence of carbon dioxide in the gas. Another way to test for the presence of carbon dioxide is to use a pH indicator, such as universal indicator or litmus paper. When carbon dioxide dissolves in water, it forms a weak acid called carbonic acid. This can be detected by observing a change in the color of the pH indicator. Carbon dioxide will turn universal indicator yellow or litmus paper red, indicating an acidic solution.

Apprοximately 0.02 mοles οf the precipitate (BaSO₄) will be fοrmed.

Tο determine the number οf mοles οf the precipitate (BaSO₄) fοrmed in the reactiοn between BaCl₂ and Na₂SO₄, we need tο cοmpare the reactants' mοles and use the stοichiοmetry οf the balanced equatiοn.

The balanced equatiοn fοr the reactiοn is:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

Frοm the equatiοn, we can see that 1 mοle οf BaCl₂ reacts with 1 mοle οf Na₂SO₄ tο prοduce 1 mοle οf BaSO₄.

First, we need tο calculate the number οf mοles οf BaCl₂ and Na₂SO₄ present in the reactiοn mixture using their respective mοlar masses.

The mοlar mass οf BaCl₂ is calculated as:

Mοlar mass οf BaCl₂ = (1 * 137.33 g/mοl) + (2 * 35.45 g/mοl) = 208.23 g/mοl

The mοlar mass οf Na₂SO₄ is calculated as:

Mοlar mass οf Na₂SO₄ = (2 * 22.99 g/mοl) + 32.06 g/mοl + (4 * 16.00 g/mοl) = 142.04 g/mοl

Nοw, let's calculate the number οf mοles fοr each reactant:

Mοles οf BaCl₂ = mass οf BaCl₂ / mοlar mass οf BaCl₂

= 4.16 g / 208.23 g/mοl

≈ 0.02 mοl

Mοles οf Na₂SO₄ = mass οf Na₂SO₄ / mοlar mass οf Na₂SO₄

= 3.30 g / 142.04 g/mοl

≈ 0.023 mοl

Based οn the stοichiοmetry οf the balanced equatiοn, 1 mοle οf BaCl₂ reacts with 1 mοle οf Na₂SO₄ tο prοduce 1 mοle οf BaSO₄.

Since the reactiοn is stοichiοmetric, the limiting reactant is the οne with fewer mοles, which in this case is BaCl₂ (0.02 mοl).

Therefοre, the number οf mοles οf BaSO₄ precipitate fοrmed will be equal tο the number οf mοles οf BaCl₂ used:

Number οf mοles οf BaSO₄ = 0.02 mοl

Sο, apprοximately 0.02 mοles οf the precipitate (BaSO₄) will be fοrmed.

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Answer:

70

Explanation:

The atomic number stands for the number of protons.

mass number stands for number of neutrons and protons.

30 neutrons + 40 protons = mass number of 70

Hope this helps!

Answer:

b. positively

Explanation:

For numbers less than 0.1 such as 0.06, the zeros to the right of the decimal point but before the first nonzero digit show the decimal place of the first digit.

The number of significant figures in a measurement often show the degree of accuracy of the measurement. We ascertain the number of significant figures from the first non - zero digit in the figure.

Given the figure 0.06, there is only one significant figure present. The zeros to the right of the decimal point but before the first nonzero digit show the decimal place of the first digit.

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Answer:

C. C5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O (l), ΔH = –3,536.1 kJ/mol

Explanation:

This equation represents the combustion of C5H12 (pentane) in the presence of oxygen to produce carbon dioxide (CO2) and water (H2O), with a heat change (ΔH) of -3,536.1 kJ/mol.

Therefore, the water is heated as a result of heat transfer.

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Answer:

0.985

Explanation:

moles= mass/Mr

Mr is the molecular mass

Cu=63.5

F2=38

Mr=63.5+38=101.5

moles=100/101.5=0.985

round answer if needed

Answer:

Ghawar field   location-Saudi Arabia

Burgan Field   location-Kuwait

Ahvaz field      location-Iran

Upper Zakum Oil Field   Location-Abu Dhabi UAE

Explanation:

I learned this yesterday :D

Answer:

6.3 atm

General Formulas and Concepts:

Atomic Structure

Ideal Gas Law

Ideal Gas Law Formula: PV = nRT

Explanation:

Step 1: Define

Identify variables

[Given] n = 3.2 mol O₂

[Given] V = 12.3 L

[Given] T = 294 K

[Solve] P

Step 2: Solve for P

Step 3: Check

Follow sig figs and round. We are given 2 sig figs as our lowest.

6.27965 atm ≈ 6.3 atm

Answer:

molecular so number 3. ...

Answer:

A. The mass of reactants is the same as the mass of products

0.279 g He

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

4.20 × 10²² molecules He

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of He - 4.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.278997 g He ≈ 0.279 g He

The increasing order of reactivity of the given compounds in nucleophilic addition reactions is: Butanone < Propanone < Propanal < Ethanal

The reactivity of a carbonyl compound in nucleophilic addition reactions depends on the electron density at the carbonyl carbon. The more electron density at the carbonyl carbon, the less reactive it is towards nucleophilic attack.

In the given compounds, the electron density at the carbonyl carbon decreases with increasing number of alkyl groups. This is because alkyl groups are electron-releasing groups and they donate electrons to the carbonyl carbon.

The more alkyl groups there are, the more electrons are donated to the carbonyl carbon, and the less reactive it is towards nucleophilic attack.

Therefore, butanone, which has the fewest alkyl groups, is the most reactive towards nucleophilic attack. Propanone, which has one alkyl group, is less reactive than butanone.

Propanal, which has two alkyl groups, is less reactive than propanone. And ethanal, which has three alkyl groups, is the least reactive towards nucleophilic attack.

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Ions are formed when atoms lose or gai electron in order to fulfill the octet rule

The dot structure that can be shown to be incorrect is the dot structure that has been shown by option A

The Lewis structure is based on the concept that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration similar to that of a noble gas. In the Lewis structure, the valence electrons of the atoms are represented as dots around the symbol of the atom.

We can see that in the dot structure that is in option A the both atoms are coming from the hydrogen atoms and shoud not be differently marked.

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The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction, only rearranged. Therefore, the total mass of the reactants must equal the total mass of the products.

Starting with 0 g of calcium (Ca) and 1.9 g of fluorine (F2), we can calculate the total mass of the reactants:

Total mass of reactants = Mass of Ca + Mass of F2

Total mass of reactants = 0 g + 1.9 g

Total mass of reactants = 1.9 g

According to the problem statement, the reaction forms 3.9 g of calcium fluoride (CaF2). Therefore, the total mass of the products is:

Total mass of products = Mass of CaF2

Total mass of products = 3.9 g

Since the total mass of the reactants must equal the total mass of the products, we can set these two expressions equal to each other:

Total mass of reactants = Total mass of products

1.9 g = 3.9 g

This is a contradiction, as it is impossible for the mass of the reactants to be less than the mass of the products. Therefore, there must be an error in the problem statement or the given values.

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