Hydrogen sulfide (H2S) is an odorous gas that can be stripped from solution in a process similar to that described for ammonia. The reaction is the following: H'S ⇆ H) + HS, Ka1 = 0.86 x 10-7 (a) Sketch the a-diagram for H2S. Include the (i) axes titles, (ii) the location of pKa1, and (iii) the curves and formulae for a0 and a1. (b) Find the fraction of hydrogen sulfide in the H2S form at (i) pH 5.5 and (ii) pH 7.5. (c) For both pH’s, what is the % of total hydrogen sulfide removed from water in an air stripping tower that has reach equilibrium conditions. Assume the H2S partial pressure in air is 0.0002 atm, the initial total hydrogen sulfide concentration in the water (i.e., [H2S]t,0 (aq)) is 20 ppm, and the Henry’s Law constant (KH) for H2S is 0.1 M atm-1 . (d) Which pH would you use to operate your H2S stripping system?

Answer: aragon is in group 0

2. It’s a non metal

3. Group number

Explanation:

Answer:

that the polar bear will come out again in 2 years

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

Substitute the values into the formula.

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

The units of Kelvin cancel, so we are left with the units of mL.

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

The volume of the balloon at 250 K is approximately 416.7 milliliters.

The balanced equation is: 4 Fe(s) + 3 O₂(g) → 2 Fe₂O₃(s)

This equation represents the reaction between iron and oxygen to produce iron(III) oxide in the stoichiometric ratio.

The balanced equation for the reaction between iron (Fe) and oxygen (O₂) to form iron(III) oxide (Fe₂O₃) is:

4 Fe(s) + 3 O₂(g) → 2 Fe₂O₃(s)

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Starting with the iron (Fe) atoms, we have 4 Fe atoms on the left side but only 2 Fe atoms on the right side. To balance this, we place a coefficient of 2 in front of Fe₂O₃ on the right side:

4 Fe(s) + 3 O₂(g) → 2 Fe₂O₃(s)

Now, let's look at the oxygen (O) atoms. On the left side, we have 3 O₂ molecules, which means we have a total of 6 oxygen atoms. On the right side, we have 3 O atoms in Fe₂O₃. To balance the oxygen atoms, we need to have a total of 6 O atoms on the right side. We can achieve this by multiplying O₂ by 2:

4 Fe(s) + 6 O₂(g) → 2 Fe₂O₃(s)

Now, the equation is balanced with 4 Fe atoms, 6 O atoms, and 6 O₂molecules on both sides.

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The technique for brainstorming new ideas by asking a lot of questions is called starbursting. Option a.

This technique involves generating a lot of questions related to a particular topic and then answering each question with a set of new questions. By doing this, it helps to identify different aspects of the problem and to come up with new ideas that may not have been considered before.

This method encourages critical thinking and helps to explore different possibilities and perspectives. It is a useful tool for problem-solving, innovation, and decision-making. In summary, starbursting is a powerful technique that helps to unlock creativity and generate fresh ideas. Answer option a.

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Answer:

That is true

Explanation:

The group determines the valence electrons in the outer shell , the period determines the number of energy levels.

Theoretical yield of copper is 7.22 g when 4.25g of iron in the chemical reaction.

2Fe(s) + 3Cu2(aq.) ---->  2Fe3(aq.)  + 3Cu (s)

Molar mass of Iron (Fe) is 56g/mole.

Molar mass of copper (cu) is 63.5g/mole.

2 mole ( 2 * 56g/mole) Iron produces = 3 mole ( 3 * 63.5g/mole ) copper

Theoretical yield is the maximum amount of product that could be formed from the given amounts of reactants. The actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory. The theoretical yield is the amount of product that would be formed from a reaction if it was 100% efficient.

There are 4. 25 g of Iron .so,

4.25 g Iron produces = (3 * 63.5g / 2 * 56 g ) * 4.25 g copper

                                     = 7.22 g copper

Theoretical yield of copper is 7.22g.

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Answer:

Moving water helps plant's and islands form and grow. Which shapes earth.

Answer:

answer: B

Explanation:

becaucse it is B

A bond between a nonmetal and a nonmetal is called a covalent bond. The correct answer is option C.

Covalent bonding occurs when two nonmetal atoms share one or more pairs of electrons in order to achieve a stable electron configuration.

This type of bond is characterized by the sharing of electrons between the atoms, rather than the transfer of electrons as in ionic bonding.

An example of a covalent bond between two nonmetals: The bond between two oxygen atoms in an \(\rm O_2\) molecule. In this molecule, the two oxygen atoms share two pairs of electrons to form a stable covalent bond.

Therefore, option C. Covalent bond is a bond between a nonmetal and a nonmetal.

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The given statement, production associates are not allowed to view the process safety management documents. They are only for supervisors and upper management is true.

Since they provide advice on how to manage the risks and hazards connected to certain operations or processes, these documents are often written with supervisors and top management in mind. This is done to make sure the management team has the knowledge it needs to decide on process safety in an informed manner and to make sure the right safety measures are in place to safeguard employees and the neighbourhood.

It is crucial to remember that a person's unique job responsibilities and the level of access required to carry out those duties should determine who has access to PSM documents. If it's necessary for them to carry out their duties, some production associates might have access to particular PSM documents.

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Answer:

C

Explanation:

Boyle's law states that "the volume of a given mass of gas is inversely proportional to its pressure at constant temperature."

Inverse proportionality means that as one quantity is increasing, the other quantity is decreasing and vice versa.

Hence, as the pressure was increased, the volume decreases accordingly in obedience to Boyle's law.

Answer:

What is TRUE about the missing volume is option C.

C. The volume will decrease due to inverse relationship of V & P

Explanation:

The given parameters of the gas are;

The initial pressure of the gas, P₁ = 2 atm

The initial volume of the gas, V₁ = 1.5 L

The final pressure of the gas, P₂ = 2 atm

Boyle's law states that, at constant temperature, the volume, 'V', of a given mass is inversely proportional to its pressure, 'P';

Mathematically, Boyle's law can be expressed as follows;

P ∝ 1/V

From which we have;

P·V = Constant

∴ P₁·V₁ = P₂·V₂

For the given gas, we get;

2 atm × 1.5 L = 6 atm × V₂

∴ V₂ = 2 atm × 1.5 L/(6 atm) = 0.5 L

Therefore, the volume decreases from 1.5 L to 0.5 L.

The oxidation number of the zinc in the ZnCl₂  is the +2.

The oxidation number, is also called as the oxidation state, the total number of the electrons that an atom either will gains or will loses in order to form the chemical bond with the another atom.

The oxidation number of the chlorine = -1

The oxidation number of the Zn is as follows :

Zn + 2( -1 ) = 0

Zn - 2 = 0

Zn = + 2.

The Oxidation number of an atom can be  defined as the charge that the atom appears will have on forming the ionic bonds with the other heteroatoms.

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Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)

From the question we have

actual number = 0.95 g/mL

error = 0.95 - 0.56 = 0.39

We have

\(p(\%) = \frac{0.39}{0.95} \times 100 \\ = 41.0526315...\)

We have the final answer as

Hope this helps you

b. state , hess's law can be used to solve for reaction enthalpy changes because enthalpy is a state function.

Hess's Law states that the change in enthalpy (heat content) of a chemical reaction is independent of the route by which the reaction occurs. This means that the total enthalpy change for a reaction can be calculated by summing the enthalpy changes for a series of intermediate steps that lead to the final reaction. This allows for the prediction of the heat of reaction for a reaction without the need for direct measurement.

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Answer:

a)

Hmax=v2sin⁡2452g+hH_{max}=\frac{v^2\sin^2{45}}{2g}+hHmax​=2gv2sin245​+h

Hmax=2+62sin⁡2452(9.81)=2.92 mH_{max}=2+\frac{6^2\sin^2{45}}{2(9.81)}=2.92\ mHmax​=2+2(9.81)62sin245​=2.92 m

It is less than the height of the basket of 3.05 m. So, this is a miss.

b)

d=R=v2sin⁡(2⋅45)g=v2gd=R=\frac{v^2\sin{(2\cdot45)}}{g}=\frac{v^2}{g}d=R=gv2sin(2⋅45)​=gv2​

4.21=v29.814.21=\frac{v^2}{9.81}4.21=9.81v2​

v=6.43msv=6.43\frac{m}{s}v=6.43sm​

The substance that possesses the larger standard entropy is 1 mol of As4(g) at 300 ∘C, 0.01 atm. As4 has a larger size and more complex structure than P4.

The standard entropy of a substance is a measure of the disorder or randomness of its particles. The higher the entropy, the more disordered the particles are. In this case, we are comparing the standard entropies of P4(g) and As4(g) at the same temperature and pressure.

Standard entropy is a measure of the randomness or disorder of a substance. Generally, larger, more complex molecules have higher standard entropy values than smaller, simpler molecules. As4 is larger and heavier than P4 due to the higher atomic weight of arsenic compared to phosphorus.
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The molarity of the HCl solution is approximately 0.390 M.

To find the molarity of the HCl solution, you can use the formula:

Molarity of acid(M2) x Volume of acid(V2) = Molarity of base(M1) x Volume of base(V1)

Molarity of acid(M2) = (Molarity of base(M1) x Volume of base(V1)) / Volume of acid(V2)

Therefore,

M1V1 = M2V2
where M1 and V1 are the molarity and volume of NaOH, and M2 and V2 are the molarity and volume of HCl.

Given:
M1 = 0.212 M (NaOH)
V1 = 25.0 mL (NaOH)
V2 = 13.6 mL (HCl)

You need to find M2 (molarity of HCl).

Step 1: Rearrange the formula to solve for M2:
M2 = (M1V1) / V2

Step 2: Plug in the given values:
M2 = (0.212 M * 25.0 mL) / 13.6 mL

Step 3: Calculate the result:
M2 ≈ 0.390 M

So, the molarity of the HCl solution is approximately 0.390 M.

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The question requires us to calculate the mass necessary to prepare a lead(II) nitrate (Pb(NO3)2) solution, given the volume of the solution and its molar concentration.

The following information was provided by the question:

salt used = Pb(NO3)2

volume of solution = V = 750.0 mL = 0.7500 L

molar concentration of solution = C = 0.20 mol/L

To solve this problem, we'll use two important definitions and their equations: the molar concentration and number of moles.

The molar concentration (C, given in mol/l) is defined as the number of moles of a compound (n, given in moles) divided by the volume of the solution (V, given in liters):

On the other hand, the number of moles of a substance (n, given in moles) can be calculated by dividing the mass of this substance (m, given in grams) by its molar mass (M, given in g/mol):

If we replace n as given by the second equation in the first equation, we'll have:

And, rearranging this last equation, we find an expression to calculate the mass of a substance from the molar concentration of a solution, its volume and the molar mass of the substance:

(where m is the mass, in g, C is the molar concentration, in mol/L, M is the molar mass, in g/mol, and V is the volume, in L).

Since the question provided the values for C and V, we'll only need the molar mass of Pb(NO3)2.

The atomic masses of Pb, N and O are 207.2 u, 14.01 u and 15.99 u, respectively. Thus, the molar mass of Pb(NO3)2 can be calculated as:

molar mass Pb(NO3)2 = (1 * 207.2) + (2 * 14.01) + (6 * 15.99) = 331.2 g/mol

Next, we apply the values of to the equation to calculate the mass of Pb(NO3)2:

Therefore, the mass of Pb(NO3)2 required to prepare 750.0 mL of a 0.20 M solution is 49.68 g.

Answer:

Hydrogen (H) “burning” initiates the fusion energy source of stars and leads to the formation of helium (He).

FUSION Reaction

Explanation:

mark me brainliest please.

Answer:

VSEPR molecular shapes are the substances from the laboratory operation that have more than one central atom.

Explanation:

Molecular shapes from VSEPR

Explanation:

The reason is VSEPR theory, it considers electrons, involved in bond formation as the key part. The pairs of electrons around a central atom, they may be in  sigma bonds, pi bonds, or lone pairs, are always in proximity with the positive nucleus and  as far as possible from each other. Therefore, only the lone pairs on the central atom are taken into consideration when predicting molecular shape.

H2O2 , C2O4,  CH3OH, CH3NH2

substances from the lab activity have more than one central atom

The number of moles of H₂O is  0.36 mol.

The number of moles of LiClO₄ is  0.0521  mol.

Mole is an important standard unit used for the measurement of large quantities of atoms, molecules, or other particles. One mole is equal to 6.022×10²³ units.

The number of moles of a substance is calculated by:

Moles =\(\frac{mass}{molar \;mass}\)

To find the number of moles of H₂O:

Mass of H₂O in the sample = 6.579 g

The molecular weight of H₂O = 18.02g

Moles = \(\frac{mass}{molar \;mass}\)

Moles = \(\frac{6.579 g}{18.02g}\)

Moles = 0.36

To find the number of moles of \(ZnSO_4\):

Mass of \(ZnSO_4\) in the sample = 8.421 g

The molecular weight of \(ZnSO_4\)= 161.47 g/mol

Moles =\(\frac{mass}{molar \;mass}\)

Moles = \(\frac{8.421 g}{161.47 g/mol}\)

Moles = 0.0521 moles

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Answer:

A

Explanation:

Be certain that the data collected will fully support the hypothesis

Answer: D. Determine whether it is possible to gather the necessary data.

The effect of assuming that the solution volume is the same as the solvent volume on the calculated solution density is that the calculated solution density will be lower than the actual density.

This is because the addition of the solute, in this case, sugar, increases the overall volume of the solution compared to the volume of the solvent alone.

When the student measured the mass of the solution accurately, they would have obtained the correct value for the total mass of the solution. However, if the volume of the solution is underestimated, the calculated density would be lower than the actual density, as the density is the mass of the solution divided by its volume.

To obtain an accurate density value, it is important to measure both the mass and volume of the solution, accounting for the volume contribution of the solute.

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To determine the two half-reactions that will produce the largest voltage under standard conditions, we must consider the standard reduction potentials for each half-reaction.

The half-reaction with the more positive reduction potential will be the reduction half-reaction, while the half-reaction with the more negative reduction potential will be the oxidation half-reaction. This is because the reduction half-reaction is where the electrons are gained, while the oxidation half-reaction is where the electrons are lost.

Under standard conditions, the standard reduction potential for the reduction half-reaction must be higher than the standard reduction potential for the oxidation half-reaction. This creates a larger potential difference between the two half-reactions, resulting in a larger overall voltage.

In general, the half-reaction with a metal as the reactant tends to have a more negative reduction potential, while the half-reaction with a non-metal tends to have a more positive reduction potential.

Therefore, to answer the question, we must compare the standard reduction potentials for various half-reactions and select the two that have the largest potential difference. This will result in the largest voltage under standard conditions.

Overall, the selection of the two half-reactions will depend on the specific conditions of the galvanic cell, such as the type of electrodes and electrolytes used. It is important to consider the conditions carefully when selecting the appropriate half-reactions for a given galvanic cell.

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The Kb for NH3 is 1.79×10−5.

In aqueous solutions, ammonium hydroxide (NH4OH) partially dissociates to form ammonium (NH4+) and hydroxide (OH-) ions.

The equilibrium constant for this dissociation is known as the Kb value for the reaction NH3 + H2O ⇌ NH4+ + OH-. The Ka and Kb values are related through the autoionization of water (Kw = Ka * Kb).

To find the Kb value for NH3, we can use the given Ka value for NH4+ (5.6×10−10) and the known value of Kw at 25°C (1.0×10−14). By rearranging the equation, Kb = Kw / Ka, we can calculate the Kb value as 1.79×10−5.

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Step 1 - Finding the molar mass of glycine

The molar mass of glycine can be found by multiplying the molar mass of each element by the number of times it appears in the formula and then summing it all up.

For glycine, we find the molar mass of 75.07 g/mol.

Step 2 - Interpreting the meaning of molar mass

The molar mass gives us the total mass of one mole of that substance. Let's take water as an example: its molar mass is 18 g/mol, which means one mole of water would weight 18 g, two moles 36 g and so on.

For glycine, therefore, one mole weights 75.05 g.

Step 3 - Finding the number of moles

To find the number of moles, we can use a very simple formula relating mass (m), molar mass (M) and number of moles (n):

Therefore, there are 1.77*10^(-2) moles in 1.332 g of glycine.

Answer:

than, (less than or exactly one mole

The edge-length  of unit cell in a  body-centered cubic structure is given by the formula a=4r /√3 and is found out to be 312.138 pm.

Unit cell is defined as the smallest repeating unit of crystal which when repeated leads to the generation of a crystal.They have 6 lattice parameters  and seven crystal structures.Accordingly, the number of atoms in unit cells is different.

In case of BCC unit cell, edge length is calculated by the formula,a=4r /√3 , substitution of values gives, a=4×135/1.73=312.138 pm.

Thus, the edge length of  body-centered cubic unit cell is 312.138 pm.

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