Hydrazine (N_2H_4) decomposes to produce N_2 and NH_3. How many molecules of NH_3 will be formed if 60 molecules of N_2H_4 decompose into N_2 and NH_3

Answer:

4.1g of Cr will make (317/104) x 4.1 = 12.5g of CrCl3

Answer:

Explanation:

The pressure required can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the required pressure

\(P_2 = \frac{P_1V_1}{V_2} \\\)

From the question we have

\(P_2 = \frac{6 \times 1200}{200} = \frac{7200}{200} = \frac{72}{2} \\ \)

We have the final answer as

Hope this helps you

Answer: lol

Explanation: ok 11 plus 1 is 12

Four electrons are required to reduce cytochrome c.

Cytochrome c is a small, heme-containing protein that plays an important role in the process of cellular respiration. In cellular respiration, electrons are transferred from molecules of fuel, such as glucose, to oxygen, with the help of cytochrome c and other proteins.

Cytochrome c acts as an electron carrier, transferring electrons from one protein to another in a series of redox (reduction-oxidation) reactions. In each redox reaction, electrons are removed from one molecule (the oxidized form) and added to another molecule (the reduced form). In the case of cytochrome c, it must be reduced four times, meaning that it must accept four electrons in total.

Each electron that is added to cytochrome c changes the oxidation state of the iron atom in its heme group, reducing it from the oxidized form (Fe3+) to the reduced form (Fe2+). This process allows cytochrome c to transfer electrons from one protein to another, until they eventually reach oxygen and are used to form water.

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Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.

Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.

The time can be represented as follows:

t= 2.303\∧ log A0/A

∧= 0.693/t 1/2

The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.

The given parameters are as follows:

t1/2=12.3

A0=5.5

A=0.688

t= 2.303/(0.693/12.3) log (5.5/0.688)

t=36.9

t=37 years

Thus, wine was produced 37 years ago (1984 as usual year 15,2021)

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The single replacement reaction in this question is: Zn + 2HCl → ZnCl2 + H2.

A single replacement reaction is the type of reaction in which one element in a reaction is replaced by another element.

According to this question, the reaction given below is an example of single replacement reaction:

This is because hydrogen in HCl is replaced by Zinc element to form zinc chloride.

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The top 10 periodic table elements that most students are excited to learn about are listed below. Carbon. Nitrogen is the atomic code for carbon, or C.

A crucial component of a whole. an ordinary substance whose cannot be divided into smaller components or transformed into another substance is referred to as in chemistry. Atoms, which are made up of protons, neutrons, and electrons, are the building blocks of an element.

Chemical substances that cannot be converted into other chemicals are referred to as elements. Chemical elements are distinguishable from one another by the number of of protons in their atoms' nucleus, which is the fundamental particle that makes up a chemical element.

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The correct answer is simple molecular structure.

What is a molecule?

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Explanation:

a)  Using the provided information about the density  of gold, the sample size, thickness, and the following  equations and comersion factors, find the area of   the gold leaf:

\(V=l \cdot w \cdot h=A \cdot h\\m=\rho \cdot V\)

Gold \(_{\rho}=19.32 \mathrm{g} / \mathrm{cm}^{3}\)

\(1 \mu=10^{-6} \mathrm{m}\)

First, find the volume of the sample and then find the area of the sample.

\(V=\frac{m}{\rho}=\frac{27.6 \mathrm{g}}{19.32 \mathrm{g} / \mathrm{cm}^{3}} \cdot\left(\frac{0.01 \mathrm{m}}{1 \mathrm{cm}}\right)^{3}\) \(=\frac{1.429 \times 10^{-6} \mathrm{m}^{3}}\)

\(V=A \cdot h \rightarrow A=\frac{V}{h}=\frac{1.429 \times 10^{-6} \mathrm{m}^{3}}{10^{-6} \mathrm{m}} \approx 1.429 \mathrm{m}^{2}\)

b.  Using the provided information from part \(a\) ), the radius of the cylinder, and the following equation for the volume of a cylinder, find the length of the fiber :

\(V=\pi r^{2} h \rightarrow h=\frac{V}{\pi r^{2}}\)

\(h=\frac{1.429 \times 10^{-6} \mathrm{m}^{3}}{\pi \cdot\left(2.5 \times 10^{-6} \mathrm{m}\right)^{2}} \approx 72778 \mathrm{m}\)

A single crystal of solute was added to a solution, and many additional crystals settled to the bottom (crystals came out of solution). the original solution was supersaturated solution.

A supersaturated solution contains more dissolve solute than the saturated solution. supersaturated solution is unstable and will readily crystallizes when added a seed crystal or when the solution is disturbed.  A solution that contain maximum amount of the dissolved solute than saturated solution .

Thus, A single crystal of solute was added to a solution, and many additional crystals settled to the bottom (crystals came out of solution). the original solution was supersaturated solution.

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To clean powder fouling, corrosion, and dirt from outside parts of the lower receiver and extension assembly, one should use the best quality cleaning materials and methods.

Powder fouling, corrosion, and dirt can accumulate on the outside parts of the lower receiver and extension assembly, making it hard to maintain the rifle. It is essential to clean the weapon regularly to maintain its efficiency and longevity.

The following cleaning materials are required for the cleaning process:

Cleaning solvent

Cleaning brush

Microfiber cloth

Lubricant

The best solvent to use when cleaning the rifle is a powder solvent. This is because it is specifically designed to remove fouling from firearms. It is also essential to use a cleaning brush made of brass, nylon, or synthetic material to avoid damaging the parts of the lower receiver and extension assembly.

Brass brushes are best for removing fouling, while nylon and synthetic brushes are gentle on the metal parts and help prevent corrosion. Avoid using a steel brush when cleaning the rifle since it may scratch or damage the surface of the metal.Lubricant is also essential in maintaining the rifle. It helps keep the moving parts smooth and minimizes friction between metal parts.

A high-quality lubricant should be used, and the excess should be wiped off with a microfiber cloth. To clean the weapon, apply the cleaning solvent onto the brush and scrub the outside parts of the lower receiver and extension assembly, then wipe it off with a microfiber cloth. Ensure the surface of the metal parts is dry before applying lubricant. Apply lubricant to moving parts of the weapon.

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(C) The reaction order is zero. The activation energy is the same for both the forward and reverse reactions.

For a reaction where the activation energy is the same for both the forward and reverse reactions, it implies that the rate constants for the forward and reverse reactions are equal. The rate constant (k) is related to the reaction order (n) by the equation: k = A * [reactants]^n, where A is the pre-exponential factor and [reactants] represents the concentrations of the reactants.

If the rate constants are equal, then the reaction order (n) must be zero. This is because any value of n other than zero would result in different rate constants for the forward and reverse reactions, given that the concentrations of the reactants would be different.

Therefore, the statement (C) The reaction order is zero must be true for a reaction where the activation energy is the same for both the forward and reverse reactions.

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Answer:

YELLOW

Explanation:

Answer: Gravity i think

The volume (V₂) of the container at the new altitude is 0.717 Hg. It can be calculated by operating the ideal gas law.

Given information,

V₁ = 250 mL = 0.25L

P₁ = 30.07 Hg

P₂ = 9.96 Hg

T₂ = 3.7 °C

The equation of the ideal gas law is:

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

The initial and final temperatures in Kelvin:

T₁ = 273.15 + 3.7 = 276.85 K

T₂ = 273.15 - 9.96 °C = 263.19 K

Now,

(30.07  * 0.25) / (276.85 ) = (9.96  * V₂) / (263.19 )

V₂ = (30.07  * 0.25  * 263.19 ) / (9.96  * 276.85)

V₂ = 0.717 Hg

Therefore, the volume at the new altitude is 0.717 Hg.

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Answer:

78.04g of 0.448 moles must be added

Explanation:

Using H-H equation we can find the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

Where pH is the pH of the buffer = 7.2

pKa = 7.1

[A⁻] = [K₂HPO₄]

[HA] = [KH₂PO₄]

Replacing:

7.2 = 7.1 + log [K₂HPO₄] / [KH₂PO₄]

0.1 = log [K₂HPO₄] / [KH₂PO₄]

1.2589 = [K₂HPO₄] / [KH₂PO₄] (1)

And as the  concentration of the buffer is:

1M = [K₂HPO₄] + [KH₂PO₄] (2)

Replacing (2) in (1):

1.2589 = 1M - [KH₂PO₄] / [KH₂PO₄]

1.2589 [KH₂PO₄] = 1M - [KH₂PO₄]

2.2589 [KH₂PO₄] = 1M

[KH₂PO₄] = 0.44M

And [K₂HPO₄] = 0.56M

In 800mL = 0.8L:

0.8L * (0.56mol / L) = 0.448 moles K₂HPO₄. The mass is -Molar mass K₂HPO₄: 174.2g/mol-:

0.448 moles * (174.2g / mol) =

Answer:I love to travel however I do erode aluminum so we won't be taking off on undertakings in planes at any point in the near future

Explanation:

Answer:

its D

Explanation:

Took the test

The specie whose concentration is plotted is D. The rate of reaction is how quickly or slowly hat a reaction proceeds.

The term rate of reaction refers to how quickly or slowly hat a reaction proceeds. A reaction rate plot involves the concentration of the species plotted against time.

Now we can see from the plot that concentration is increasing with time. Since the concentration of products increases with time, then the specie whose concentration is plotted is D.

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To synthesize 2-methylpentan-3-one efficiently, following process has to be followed:

Start with the synthesis of 2-methylpentan-3-ol, which can be prepared via a Grignard reaction. Firstly, prepare 2-methylpentan-3-ol by reacting ethyl magnesium bromide with 3-methylbutanal.

Afterward, hydrolysis of this Grignard reagent using HCl or dilute sulfuric acid provides the alcohol.2-methylpentan-3-ol.

( Grignard reaction -The Grignard reaction is an organometallic chemical reaction in which carbon alkyl, allyl, vinyl, or aryl magnesium halides (Grignard reagent) are added to the carbonyl groups of either an aldehyde or ketone. This reaction is important for the formation of carbon–carbon bonds.)

Now,the oxidation of 2-methylpentan-3-ol is carried out using oxidizing agents like PCC (pyridinium chlorochromate), PDC (pyridinium dichromate), or Jones reagent to synthesize 2-methylpentan-3-one.Oxidation of 2-methylpentan-3-ol to synthesize 2-methylpentan-3-one can be represented as follows: PCC or PDC or Jones Reagent2-methylpentan-3-one.

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Answer:

heat and large amount of surface area

Explanation:

the heat and surface area allows the iron in the wool to combine with oxygen. by doing this it increases the mass of the steel wool

The mass of steel wool increases after burning because it reacts with oxygen in the air, leading to the formation of iron oxide.

After burning, steel wool's bulk grows due to the oxidation process. Iron oxide, also referred to as rust, is created when steel wool burns when it comes into contact with oxygen from the air.

The steel's iron reacts chemically with the oxygen to create iron oxide, which is heavier than the original iron. As a result of going through the oxidation process and becoming iron oxide, steel wool gains bulk.

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Answer:

sorry if this is wrong but B

Explanation:

ITS C

Oxygen, APT, and Glucose

Without knowledge of the IR spectrum or any information about the molecules A, B, C, and D, it is not possible to definitively match any molecule with the given spectrum.

To determine which molecule is consistent with the given IR spectrum, more specific information about the spectrum or the molecules is needed. Without additional details, it is challenging to make a conclusive determination.

IR spectra provide information about the vibrational modes of molecules and can be used to identify functional groups present.To analyze the spectra, one needs to compare the peaks observed in the spectrum with characteristic absorption bands associated with different functional groups. Each molecule will have a unique combination of peaks depending on its structure and functional groups.

However, if you provide more specific details or the IR spectrum itself, I can assist you in identifying the molecule consistent with the spectrum.

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The question is asking us to determine which of the given molecules (A, B, C, or D) is consistent with the given IR spectrum.

To do this, we need to analyze the IR spectrum and compare it to the characteristic peaks or absorption bands of the molecules. Unfortunately, the IR spectrum is not provided in the question, so we are unable to determine which molecule is consistent with it.

Without the IR spectrum, we cannot accurately identify the molecule that matches its characteristic peaks or absorption bands. It is important to have the specific details of the IR spectrum to make an accurate determination.

Therefore, the answer to the question cannot be determined without the IR spectrum.

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Answer:

it is D. Reactant

Explanation:

Answer:

D

Explanation:

A chemical reaction is a process in which one or more substances, also called reactants.

Answer:

Explanation:

First of all, let's differentiate between a physical and a chemical change.

A physical change has the following properties

- no new substance is formed

- change is easily reversible

- it mostly involves physical properties (like size)

- examples include burning of candle wax and freezing of water to become ice

A chemical change has the following properties

-new substances are formed

- change is not easily reversible

- it involves both physical and chemical properties (like surface area and reactivity)

- examples include burning of wood and rusting of iron

From the above, it is clear that burning of a log of wood is a chemical change because the wood is burnt in open air (by a chemical process known as combustion) and converted to coal and then ashes. The produced ash cannot be reversed back to wood. The energy change that occurs here (in the combustion) is from chemical energy to heat energy. Which is unrelated to the energy changes that occurs in a swinging/moving pendulum, which is the conversion of potential energy (energy at rest) to kinetic energy (energy in motion). The energy changes in a moving pendulum is not a physical change, which is where the classmate got it wrong.

Hence, she (the classmate) is right about the energy changes been unrelated but she is wrong in her explanation of the process/energy changes involved.

If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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The slowest step in a reaction mechanism is known as the rate-determining step. The rate-determining step limits the overall rate and therefore determines the rate law for the overall reaction.

Overall reaction equation:

2NO (g) + O2(g) ---------> 2NO2(g)

Overall rate= k1 [NO]^2

Overall reaction equation:

2NO (g) + O2(g) ---------> 2NO2(g)

The overall reaction equation is obtained by adding the two equations. This now gives the actual overall equations when intermediates must have been cancelled out.

Since k1<<k2 which me as that the first step is much slower than the second step, then the first step is the rate determining step, being the slowest step in the non elementary reaction sequence.

Therefore overall rate;

Overall rate= k1 [NO]^2

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