HURRY PLS What is the ratio of cookies with a bite out of them to cookies without a bite taken? *

Answer:

DC = 99

Step-by-step explanation:

BD perpendicular AC

AD/BD = BD/DC

=> DC =DB^2/AD

         =33^2/11=99

{calculate}

The amount Sandra will have in the account after 12 years is b. $140,181.30 if she deposits $3,000 at the end of each semiannual period

We can determine the amount she will have in the account after 12 years by using the formula for future value as follows;

FV = P(1+i)×{ (1+i)^n - 1 } / i

Here;

FV = future value of the money after n periods

P = deposit per period

i = interest rate per period

n = the number of periods

Substituting the values in this equation to find the amount after 12 years as follows;

FV = 3000(1+0.05)×( (1+0.05)^24 - 1 ) / 0.05

FV = 3000(1+0.05)×( (1+0.05)^23 ) / 0.05

FV = 140,181.296 = 140,181.30

Hence the amount after 12 years is calculated to be $140,181.30

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Answer:

The answer is 1/5

Step-by-step explanation:

The answer is 1/5

There is a .90 probability that the project will be completed before approximately day 118.

The given information can be solved by using the formula of z-score as follows:

Z = (X - μ)/σ

Where: Z = z-score

X = the time for project completion

μ = the mean time for the critical path

σ = standard deviation for the critical path

σ² = variance of the critical pathσ = √64

σ = 8

Given that the mean time for the critical path is μ = 108 days and σ = 8 days,

Therefore, the z-score of the completion of the project before 108 days is given by:

Z = (X - μ)/σ0.90

 = P(Z < z)

 = P(Z < (X - 108)/8)P(Z < (X - 108)/8)

 = 0.90

Using a z-table or calculator, we find the z-value to be 1.28.

Then,1.28 = (X - 108)/8

Multiplying both sides by 8, we get:10.24 = X - 108

Adding 108 to both sides, we get: X = 118.24

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A total of 250 packets of  4g cremora will make 1kg cremora box.

A function is a elation between a dependent and independent variable.

Given are 4g cremora sachets.

We can write the total number of cremora sachets that will make 1kg cremora box as -

{n} = 1000/4

{n} = 250

Therefore, a total of 250 packets of  4g cremora will make 1kg cremora box.

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Answer:

(B) rhombus

I think its B

Answer:

2m/s² ; - 2m/s²

25m ; 50m ; 25m

6.67 m/s²

Step-by-step explanation:

The acceleration and deceleration :

Both rates are the Same from the graph ;

According to scenario described, acceleration = 2m/s²

Deceleration occurred in equal time interval = - 2m/s

Distance covered during each stage:

Stage 1 : area of triangle

0.5 * base * height

0.5 * 5 * 10 =25 m

Stage 2: area of rectangle :

Length * breadth = 5 * 10 = 50 m

Stage 3 : area of triangle

0.5 * base * height

0.5 * 5 * 10 =25 m

Average Velocity :

Total distance / time = (25 + 50 + 25) / 15 = 100/ 15 = 6. 67 m/s

Answer:

its C

Step-by-step explanation:

I just took the test

Answer:

point c

Step-by-step explanation:

gimme points and i will give explain

Step-by-step explanation:

vertex             vertical angles

The equation for the line of best fit is given by:

y = mx + b

In which m is the slope

They are given by:

Sum of x:

Sum of all values of x.

Sum of y:

Sum of squares of x:

Sum of xy:

Slope:

14 students, so n = 14.

Then

The line of best fit is y = 0.38x + 2.36. This means that for a parents that smokes x cigarettes a day, the child is expect to miss 0.38x + 2.36 days of school during the quarter.

Graphic

The mean number of new subscribers per month during that year is 242000.

A mean simply means the average of the numbers given.

The number of cable television subscribers increased from about 1 151 000 in 2002 to about 1 393 000 in 2003.

The mean number of new subscribers will be:

= Change in numbers / Number of years

= (1393000 - 1151000) / 1

= 242000 / 1

= 242000

Therefore, the mean is 242000.

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Let's simplify the expression step by step: Expand the squared term:

(x - 3y)² = (x - 3y)(x - 3y) = x² - 6xy + 9y²

Expand the second term:

3(x + y)(x − 4y) = 3(x² - 4xy + xy - 4y²) = 3(x² - 3xy - 4y²)

Expand the third term:

x(3x + 4y + 3) = 3x² + 4xy + 3x

Now, let's combine all the expanded terms:

(x - 3y)² + 3(x + y)(x − 4y) + x(3x + 4y + 3)

= x² - 6xy + 9y² + 3(x² - 3xy - 4y²) + 3x² + 4xy + 3x

Combining like terms:

= x² + 3x² + 3x² - 6xy - 3xy + 4xy + 9y² - 4y² + 3x

= 7x² - 5xy + 5y² + 3x

The simplified form of the expression is 7x² - 5xy + 5y² + 3x.

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Answer:347

Step-by-step explanation:=

347 ⇔ 347 R 0

8328 divided by 24

=

347 with a remainder of 0

Answer:

3

Step-by-step explanation:

81/(-9)/(-3)=3

The number 3 is prime number.

Three segments a, b, and c using net sales as the basis for allocation is = $475,000.

Based on the given conditions,

Three segments are a , b , c

The segment a of trump enterprises have net sales = $300,000

The segment b of trump enterprises have net sales = $150,000

The segment c of trump enterprises have net sales = $50,000

a net sales + b net sales + c net sales = $300,000 + $150,000 + $50,000

= $500,000

If the unit is eliminated, then the a net sales and b net sales will be gone, but the c net sales will be allocated to other business units.

So instead of losing $500,000,

A decision is made to allocate the pool = $25,000

The company's net sales as the basis for allocation by $500,000 - $25,000 = $475,000

Therefore,

Three segments a, b, and c using net sales as the basis for allocation is =

$475,000.

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Lets denote:

x  --- Angle 1

y  --- Angle 2

Two angles are supplementary:

x + y = 180

The difference of their measures is 172

x - y = 172

Them we have the system:

x + y = 180

x - y = 172

-------------- Add both equations:

2x = 352

x = 352/2

x = 176

The partial fraction decomposition is:

Y(s) = 4/(s + 1)

1. Take the Laplace transform of both sides of the differential equation.

2. Solve for the Laplace transform of the unknown function.

3. Find the inverse Laplace transform to obtain the solution in the time domain.

Step 1: Taking the Laplace transform of both sides

Applying the Laplace transform to the differential equation, we have:

L[y'] + L[y] = L[t - 1]

Using the linearity property of the Laplace transform, we get:

sY(s) - y(0) + Y(s) = 1/s^2 - 1/s

where Y(s) represents the Laplace transform of y(t), and y(0) is the initial condition y(0) = 3.

Step 2: Solve for the Laplace transform of the unknown function

Combining like terms and isolating Y(s), we have:

Y(s)(s + 1) = 1/s^2 - 1/s + y(0)

Y(s)(s + 1) = (1 - s + s^2)/s^2 + 3

Now, let's simplify the right side of the equation:

Y(s)(s + 1) = (1 - s + s^2 + 3s^2)/s^2

Y(s)(s + 1) = (4s^2 - s + 1)/s^2

Dividing both sides by (s + 1), we get:

Y(s) = (4s^2 - s + 1)/(s^2(s + 1)

Step 3: Find the inverse Laplace transform

To simplify the expression further, we need to decompose the right side using partial fractions. Let's find the partial fraction decomposition:

Y(s) = (4s^2 - s + 1)/(s^2(s + 1)

To find the partial fractions, we write Y(s) as:

Y(s) = A/s + B/s^2 + C/(s + 1)

Multiplying through by s^2(s + 1), we have:

4s^2 - s + 1 = A(s^2 + s) + B(s + 1) + Cs^2

Expanding and equating coefficients, we get the following system of equations:

4s^2 - s + 1 = As^3 + As^2 + Bs^2 + B + Cs^2

4s^2 - s + 1 = As^3 + (A + B + C)s^2 + B + 1

Equating coefficients for each power of s:

s^3 coefficient: A = 0 (since the left side has no s^3 term)

s^2 coefficient: A + B + C = 4

s coefficient: 0 = -1

s^0 coefficient: B + 1 = 1

From the second and fourth equations, we find B = 0 and C = 4. Plugging these values back into the equation for A + B + C = 4, we find A = 0.

Therefore, the partial fraction decomposition is:

Y(s) = 4/(s + 1)

Now, we can find the inverse Laplace transform. Using a table of Laplace transforms, we find that:

L^(-1){Y(s)} = L^(-1){4/(s + 1)} = 4e^(-t)

Hence, the solution to the initial-value problem is:

y(t) = 4e^(-t)

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The congruent figures are given as follows:

Congruent figures are figures whose outer side lengths have the same measures. They may have different orientations, but the outer side lengths have to be the same.

Hence the congruent figures in this problem are given as follows:

They have different orientations(rotated), but same side lengths.

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Answer:

674

Step-by-step explanation:

Answer:

woah woah woah woah calm down there buddy its 674 :)

Answer:

45c−20c2

Step-by-step explanation:

have great day

The Hairdresser used 6.72 ounces of shampoo , she washed her hair.

The shampoo the hairdresser used, we need to calculate 2/5 of the total amount of shampoo in the new bottle.

The total amount of shampoo in the new bottle is obtained by adding the amounts from the three bottles: 4.8 ounces + 5.4 ounces + 6.6 ounces.

Adding these values, we get:

4.8 ounces + 5.4 ounces + 6.6 ounces = 16.8 ounces

So, the new bottle contains a total of 16.8 ounces of shampoo.

To calculate 2/5 of the total amount of shampoo, we multiply 16.8 ounces by 2/5:

(16.8 ounces) * (2/5) = 33.6/5 ounces = 6.72 ounces

Therefore, the hairdresser used 6.72 ounces of shampoo when she washed her hair.

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Answer:

A scale is a way to resize drawings or figures to make them fit into a particular size.

Step-by-step explanation:

In 2D drawing or diagrams, a  scale factor greater than 1 enlarges the object, while a scale factor between 0 and 1 shrinks the objects, also using a scale factor of 1 changes nothing or leaves the drawing the way it is.

Furthermore, scales are represented in ratio form 1:2, telling us that say 1cm in the virtual environment or paper represents 2km in reality

Step-by-step explanation:

Area=b×h

= (x+5)×(x+6)

=x^2+6x+5x+30

=x^2+11x+30

If u simplify u will get (x+5)(x+6) as answer.

Keep smiling and hope u are satisfied with my answer.Have a good day :)

hey friend your answer is

I hope it will helpful for you

mark as brainest answer

thank you

the answers is 1,3,and 4

Answer: 155.04

Step-by-step explanation:

1) Find the amount of hours Fred runs 1 mile

- divide 6.25 by 6.25 and 114 by 6.25 (18.24)

2) Multiple back up to 8.5

- 1 by 8.5 (miles) and 18.24 by 8.5 (time)

For 155.04 hours, Fred runs 8.5 miles.

Hope this helps:)
[7th Grader]

The TQ is a chord, PR is a secant line and WU is a tangent line.

Circle is a two dimensional figure which consist of set of all the points which are at equal distance from a point which is fixed called the center of the circle.

A chord of a circle is the line segment joining two points on the circle.

Line segments TQ and QV are chords.

TV is also a chord, which is the diameter.

A secant line is a line which intersects the circle at two different points.

Line PR is a secant line which intersects the circle at T and Q.

A tangent line is a line which intersects the circle at exactly one point.

Line WU is a tangent line which intersects the circle at V.

Hence the chords in the given figure are TQ and QV, secant line is PR and tangent line is WU.

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Step-by-step explanation:

Put the logs on the same side.

\( log_{2}(7y - 1) - log_{2}(y - 1) = 3\)

Using log rules, whenever you separate two logs using subtraction and they have the same base, we can write them as one log where they are a rational function

\( log_{2}( \frac{7y - 1}{y - 1} ) = 3\)

Let both of these expression be the power of a exponent with base 2.

\(2 {}^{ log_{2}( \frac{7y - 1}{y - 1} ) } = 2 {}^{3} \)

The base 2 and log base 2 cancel out

\( \frac{7y - 1}{y - 1} = 8\)

When y =1, we will get undefined so y cannot be 1

However, multiply both sides by y-1

\(7y - 1 = 8(y - 1)\)

\(7y - 1 = 8y - 8\)

\(7 = y\)