The balanced equations are;
2Na + Cl2 ---> 2NaCl2Na + 2H2O → 2NaOH + H22Mg + O2 ---> 2MgO2KClO3 ---> 2KCl + 3O22Al + 3CuO → Al2O3 + 3CuCaCO3 ---->CaO + CO22Na2S2O3 + I2 → Na2S4O6 + 2 NaI6Mg + P4 → 2Mg3P2Balance reaction equationsIf we want to balance reaction equations, the key is that we have to ensure that the number of each of the atoms on the reactant side is the same as the number of atoms of the same element on the products side.
Having said this, we can now look at each of the equations that have been balanced above and see that the criterion stated above was fulfilled in each one.
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A snowboarder on a slope starts from rest and reaches a speed of 3.9 m/s after 6.3 s.
(a) The average acceleration of this snowboarder is 0.62 m/s².
(b) The distance travelled by the snowboarder is 12.27.
What is the average acceleration of this snowboarder?The average acceleration of this snowboarder is calculated as follows;
v = u + at
where;
v is the final velocityu is the initial velocitya is the average accelerationt is timev = 0 + at
a = v / t
t = ( 3.9 ) / ( 6.3 )
t = 0.62 m/s²
The distance travelled by the snowboarder is calculated as follows
v² = u² + 2as
where;
v is the final velocity of the snowboarder =3.9 m/su is the initial velocity of the snowboarder = 0a is the average acceleration of the snowboarder s is the distance travelled by the snowboarderv² = 0 + 2as
s = v² / 2a
s = ( 3.9² ) / ( 2 x 0.62)
s = 12.27 m
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How much Hydrogen (H) atoms are in this 5NH4Cl?
Answer:
5
Explanation:
The compound formed from the elements calcium and chlorine is known as
Answer:
calcium chloride
Explanation:
an inorganic compound,a salt with the chemical formula CaCl2
During the Egg Drop lab sim you manipulated several variables like height, egg mass and impact surface. Which varible combination would produce the biggest force of impact on the egg?
Large time of impact and small speed at impact
Small time of impact and small speed at impact
Large time of impact and large speed at impact
Small time of impact and large speed at impact
Varible combination that would produce the biggest force of impact on the egg (E). Small time of impact and large speed at impact.
IntroductionHi ! This problem is the application of the impulse to the change in momentum. Impulse is the total force applied in a certain time interval. Impulses can cause a change of momentum, because momentum itself is a mass that is affected by the velocity of an object. We know that velocity is a vector quantity easy to change its direction. The relationship between impulse and change in momentum is formulated by :
\( \sf{I = \Delta p} \)
\( \sf{F \cdot \Delta t = (m \cdot v') - (m \cdot v)} \)
\( \boxed{\sf{\bold{F \cdot \Delta t = m (v' -v)}}} \)
With the following condition :
I = impulse that given (N.s)\( \sf{\Delta p} \) = change of momentum (kg.m/s)F = force that given (N)m = mass of the object (kg)v = initial velocity (m/s)v' = final velocity (m/s)\( \sf{\Delta t} \) = interval of the time (s)ExplanationIn this case, to produce a great force, then here, we refine the formula again to:
\( \sf{F \cdot \Delta t = m (v' -v)} \)
\( \boxed{\sf{F = \frac{m (v' -v)}{\Delta t}}} \)
Remember, when the result is a comparison, then the numerator part will be proportional to the force. The number that is the denominator will have an inversely proportional value. For this reason, if you want a great force, then:
Increase the mass of the egg or choose a heavier egg, this is because the mass will be proportional to the force.Increase the change of velocity, this occurs because the change in velocity of the egg is also proportional to the force.Reduce the time interval (you can throw it at close range), this happens because the value of time is inversely proportional to the value of the force.ConclusionVarible combination that would produce the biggest force of impact on the egg (E). Small time of impact and large speed at impact.
Use the universal law of gravitation to solve the following problemsTwo cars of mass 3000kg are 2m apart. What is the force between them?The force of gravity between a planet and its moon is 371N. If the planet has a mass of 4*10^22kg and the moon has a mass of 5*10^5kg, what is the distance between their centers?The force of gravity between Tim and John is 1.85*10^-9N. If they are 18m apart and Tim has a mass of 120kg. What is johns mass?
Given,
Mass of the cars, m₁=m₂=3000 kg
The distance between the cars, r=2m
From the universal law of gravitation,
\(F=\frac{Gm_1m_2}{r^2}\)Where G is the gravitational constant. The value of G is 6.67×10⁻¹¹ N·m²/kg²
On substituting the known values in the above equation,
\(F=\frac{6.67\times10^{-11}\times3000\times3000}{2^2}=1.05\times10^{-4}\text{ N}\)Therefore the force between the cars is 1.05×10⁻⁴ N
Directions: Determine if the following scenarios are describing an object’s speed, velocity, or acceleration
Pls check my answers
I WILL GIVE BRAINLIEST
In which situation is the maximum possible work done? A. when the angle between the force and displacement is 0° B. when the angle between the force and displacement is 180° C. when the angle between the force and displacement is 45° D. when the angle between the force and displacement is 90°s the work done by the force on the box? A. 6.0 × 101 joules B. -6.0 × 101 joules C. 5.9 × 102 joules D. -5.9 × 102 joules
Answer:
C
Explanation:
Answer:
c
Explanation:
In contrast to data in a database, data in a data warehouse is described as subject oriented, which means that it inswered out of Select one: a. categorizes based on time b. manages data transactions question c. captures aggregated data d. focuses on a specific area
In contrast to data in a database, data in a data warehouse is described as subject-oriented, which means that it focuses on a specific area.
What is data warehouse?A data warehouse is a sizable, consolidated collection of data created with business intelligence and analytics tasks in mind. A data warehouse is tailored for querying and analysis, in contrast to a regular database, which is often built to serve transactional processing.A data warehouse's subject orientation is one of its most important characteristics. In other words, the information in the warehouse is arranged according to a certain subject or theme, such sales, consumer behaviour, or financial performance. Data analysts and business users can more readily access and analyse data pertaining to a particular area of interest by arranging the data in this fashion, as opposed to having to sift through vast amounts of unrelated data.To know more about data warehouse, check out :
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What's the speed of a sound wave through water at 25 Celsius?
A. 1,000 m/s
B. 1,500 m/s
C. 1,250 m/s
D. 750 m/s
Answer:
B) 1500m/s
Explanation:
Ans is 1500m/s
Your friend's Frisbee has become stuck 19 m above the ground in a tree. You want to dislodge the Frisbee by throwing a rock at it. The Frisbee is stuck pretty tight, so you figure the rock needs to be traveling at least 4.1 m/s when it hits the Frisbee.
If you release the rock 1.8 m above the ground, with what minimum speed must you throw it?
Answer:
18.36 m/s
Explanation:
We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:
1/2mv^2=mgh
m=mass
g=gravity
h=height
v=velocity
We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.
19m-1.8m=17.2m
Now we can plug in our variables to solve for velocity.
First we negate mass since its on both sides and cancels out leaving us with.
1/2v^2=gh
Plug in.
1/2v^2=(9.8)(17.2)
1/2v^2=168.56
v^2=337.12
v=18.36m/s
Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
Please help true or false
Answer:
the answer is true.......
A certain car can accelerate from 0 to 60 mph in 7.9 s. What is the car's average acceleration in mph/s?
Answer:
a = 7.6\ mph/s
Explanation:
Motion With Constant Acceleration
It's a type of motion in which the velocity of an object changes uniformly in time.
The equation that describes the change of velocities is:
\(v_f=v_o+at\)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
Solving the equation [for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
The car accelerates from vo=0 to vf=60 mph in t=7.9 s, thus the acceleration is:
\(\displaystyle a=\frac{60 \ mph-0}{7.9}\)
a = 7.6\ mph/s
The most commonly used conductor in the laboratory is?
Answer:
A battery
Explanation:
A battery is the biggest conductor. I think.
A box with a mass of 0.5 slugs lies on an inclined plane making an angle of 30o with the horizontal. If the coefficient of kinetic friction between the box and the plane is 0.4, what is the magnitude of the force that must be applied parallel to the incline to keep the box moving down the incline at a constant speed
Answer: 10.98 N
Explanation:
Given
mass of box is \(m=0.5\ slugs\approx 7.3\ kg\)
The coefficient of kinetic friction is \(\mu= 0.4\)
It is given that on the application of force box started moving with constant speed i.e. there is no net external force
\(\Rightarrow F+mg\sin 30^{\circ}=\mu mg\cos 30^{\circ}\\\Rightarrow F=mg(\mu \cos 30^{\circ}-\sin 30^{\circ})\\\Rightarrow F=7.3\times 9.8(0.866\times0 .4-0.5)=-10.98\ N\\\)
The negative sign indicates direction of force is opposite i.e. it must be applied upwards
(ii) Given instead that G=0 and the forces are in equilibrium, find the values of F and alpha
If G = 0 and the forces are in equilibrium, then the net force on the object must be 0. This means that the sum of the forces must be 0. The values of F and α are 8N and -19.47° .
What is force ?Force is a physical quantity that describes the interaction between two or more objects. It is a vector quantity, meaning it has both magnitude and direction. Forces can cause an object to accelerate, decelerate, change direction, or remain in its current state of motion. Some examples of forces include gravity, friction, and electromagnetic forces. Force is one of the most fundamental concepts in physics and is the basis of many physical phenomena. It is essential to understand forces in order to understand how the universe works.
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Equation of path of projectile is y=x(1-x)
The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.
To better understand projectile motion, we must first examine the horizontal and vertical components of motion. The horizontal component of motion is constant, indicating that there is no acceleration in that direction. The vertical component, on the other hand, has acceleration because of gravity. The parabolic trajectory is the result of these two components of motion.As the projectile is launched, it travels a certain distance horizontally before beginning to descend as a result of gravity's influence, resulting in a parabolic path.The general formula for the trajectory of a projectile in two dimensions is given by:y = xtanθ - (gx²) / 2(v₀cosθ)²Where:y is the vertical distance covered by the projectilex is the horizontal distance covered by the projectileθ is the angle of projectiong is the acceleration due to gravityv₀ is the initial velocity of the projectile In the case of the given equation, y = x(1 - x), the path of the projectile will be a parabolic trajectory with a vertex at x = 0.5 and y = 0.25. The equation represents the projectile's vertical distance, y, as a function of its horizontal distance, x. It is crucial to note that the projectile's initial velocity and angle of projection are not considered in this equation.For such more question on acceleration
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what could be the possible answer to the question ?
thankyou ~
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
The value of F₀ so that string 1 remains vertical is approximately 0.377·M·gHow can the equilibrium of forces be used to find the value of F₀?Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
\(T_1 = \mathbf{\dfrac{M \cdot g}{2}}\)
Which gives;
\(M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}\)
\(T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}\)
F₀ = T₂·sin(37°)
Which gives;
\(F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2} \approx \mathbf{0.377 \cdot M \cdot g}\)
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define ohms laws and prism
Answer:
the ohms law says
Explanation:
ohm found that current, voltage, and resistance in a circuit are always related in the same day.
ohms obersivations
ohms found that if the factors that affect resistance are held constant, the resistance of most conductors does not depend on the voltage across them charging the voltage in a circuit changes the current but does not change the resistance regardless of the applied voltage. the ohms law resistance in a circuit is equal to voltage divided by current
resistance =current or voltage =current × resistance
Why does passing a current through a wire create a magnet?
a. The protons create an electrical charge.
b. The electrons create an electrical charge
C. The protons create a magnetic charge.
d. The electrons create a magnetic field.
Please select the best answer from the choices provided
Ο Α
OB
C
OD
Passing a current through a wire create a magnet because the electrons create a magnetic field.
Is it possible for a wire's current to generate a magnetic field?
Flemming's Right Hand Rule states that while a current flows, it generates a magnetic field all around it. The magnetic field produced by the wire's electric current will repel both poles of the magnet by bending away from the wire since it is changing directions around the wire. Magnetic fields are produced when moving electric charges (electrons in a circuit) move, and vice versa (electricity).
A wire heats up when a current flows through it because some of the electrical energy is transformed into heat energy due to resistance the wire encounters. This is referred to as the electric current's heating impact.
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A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is the end of the ramp from the ground? m
Answer:
The end of the ramp is 38.416 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)
If the maximum horizontal distance is known, we can solve the above equation for h:
\(\displaystyle h=\frac {d^2g}{2v^2}\)
The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:
\(\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}\)
\(\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}\)
h= 38.416 m
The end of the ramp is 38.416 m high
Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system
Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of
tan(θ) = 15.80 → θ ≈ 86.38°
The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of
∑ F = P - (M + m) g sin(θ) = (M + m) a
(see the attached free body diagram)
where
P = magnitude of the push
g = 9.80 m/s²
a = 2.53 m/s²
and M and m are the given masses.
Then the system requires a push of
P = (M + m) (a + g sin(θ))
P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
P ≈ 233 N
If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is
∑ F = T - M g sin(θ) = M a
where
T = tension in the rope
Then
T = M (a + g sin(θ))
T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
T ≈ 175 N
The letter 'J' represent
a. Wavelength
b. Crest
c. Trough
d. Amplitude
of the wave (3.2.1)
Explanation:
J is amplitude
I is wavelength
K is trough
L is crest
M is midline
Which statement is true for objects in dynamic equilibrium?
A.
Objects have zero acceleration.
B.
Objects have non-zero positive acceleration.
C.
Objects have non-zero negative acceleration.
D.
Objects can have positive as well as negative acceleration.
E.
Objects have forces which are not balanced in at least one direction.
Answer:d
Explanation:
I think I've done this
Answer:
A objects have zero acceleration
Explanation:
I did this on Plato and it was right
A bowling ball hits a single stationary pin at 59.1 m/s. The bowling ball and pin have masses of 41.7kg, and 4.17 kg, respectively. After the collision the bowling ball is moving at 48.35m/s. What is the velocity of the pin after the collision?
Two vehicles get into a head on collision. Consider the collision perfectly inelastic. Vehicle 1 has a mass of 51.3kg and a velocity of 50.1m/s. Vehicle 2 has a mass of 100kg and a velocity of 47.2m/ s. What is the velocity of the cars after they collide?
1) The velocity of the pin after the collision is 107.4 m/s.
2) The velocity of the two cars as the collision is inelastic is 48.2 m/s.
What is the velocity after collision?We know that by the principle of the conservation of linear momentum, the momentum before Collison is equal to the total momentum after collision. Now we have to use this principle in the both questions that we have here.
1) Given that;
Total momentum before collision = Total momentum after collision
(41.7 * 59.1) + (4.17 * 0) = (41.7 * 48.35) + ( 4.17 * v)
We then have;
2464 + 0 = 2016 + 4.17v
2464 - 2016 = 4.17v
v = 2464 - 2016 /4.17
v = 107.4 m/s
2) Given that;
Total momentum before collision = Total momentum after collision
(51.3 * 50.1) + (100 * 47.2) = (100 + 51.3)v
2570 + 4720 = 151.3v
v = 2570 + 4720/151.3
v = 48.2 m/s
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An ice skater with a mass of 80 kg pushes off against a second skater with a mass of 32 kg. Both skaters are initially at rest. (a) What is the total momentum of the system after they push off? (b) If the larger skater moves off with a speed of 3 m/s, what is the corresponding speed of the smaller skater
A. The total momentum of the system after they push off is zero.
B. m1v1=m2v2
v2=m1v1/m2
v2=80*3.0/32
v2=7.5 m/s
in fact
m1v1=80*3= 240 kgm/s
m2v2= 32*7.5= 240 kgm/s.
A penny board is a type of skateboard characterized by a short, narrow deck made of plastic. If you're on the short side, consider choosing a smaller deck. Smaller decks are easier to operate and control, lighter, and more portable. If you are taller, you should choose a larger deck.
The larger deck gives more stability and power when skating. A big part of being a skater girl is looking like that which means wearing skate-branded shoes and clothes. Other skaters tend to wear these clothes cut to allow the skater's movement. Good skatesHer brands include Vans DC Nike especially basketball lines and Etnies I have.
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If a spaceship traveling 1000 miles per hour enters an area free of gravitational forces, its engine must run at some maximum level in order to maintain the ships velocity.
Question is whether the statement made is true or false.
Answer:
False
Explanation:
The statement is false.
Thus is because even though we are told that the spaceship is running at 1000 miles per hour and an enters an area free of gravitational forces, there is no rule or law that says the engine must run at some maximum level to maintain the velocity.
So, that's why it is false as there is no proof of the statement from every law of physics.
The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
of the force F.
\(\boxed{\sf \tau=rFsin\theta}\)
Put values
\(\\ \rm\hookrightarrow 40=2Fsin40\)
\(\\ \rm\hookrightarrow Fsin40=20\)
\(\\ \rm\hookrightarrow 0.64F=20\)
\(\\ \rm\hookrightarrow F=31.25N\)
The moment of force is 40 Nm here. The displacement is 2.5 m and the angle of inclination is 45°. The force about the pivot is then 28.2 N.
What is moment of force?Moment of force is the product of the force and distance from a fixed axis. Moment of force can be calculated for both balanced and unbalanced forces.
The expression for moment of force relating the distance d and force f with an angle of inclination θ is written as below:
moment of force = f d sin θ
Given that moment of force = 40 Nm
distance from the fixed axis from the figure = 2 m
angle of inclination = 45 °
40 Nm = 2 f sin 45.
20 = f sin 45
f = 20 N / sin 45
= 28.2 N
Therefore, the force about the pivot is 28.2 N.
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A(n) 28.3 g bullet is shot into a(n) 5004 g wooden block standing on a frictionless surface. The block, with the bullet in it, acquires a speed of 1.7 m/s. Calculate the speed of the bullet before striking the block. Answer in units of m/s
Answer:
the speed of the bullet before striking the block is 302.3 m/s.
Explanation:
Given;
mass of the bullet, m₁ = 28.3 g = 0.0283 kg
mass of the wooden block, m₂ = 5004 g = 5.004 kg
initial velocity of the block, u₂ = 0
final velocity of the bullet-wood system, v = 1.7 m/s
let the initial velocity of the bullet before striking the block = u₁
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
0.0283u₁ + 5.004 x 0 = 1.7(0.0283 + 5.004)
0.0283u₁ = 8.5549
u₁ = 8.5549 / 0.0283
u₁ = 302.3 m/s
Therefore, the speed of the bullet before striking the block is 302.3 m/s.
Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the brakes than a sober driver's car? Assume that both are initially traveling at 50.0 mi/h and their cars have the same acceleration while slowing down, and that the sober driver takes 0.33 s to hit the brakes in a crisis, while the drunk driver takes 1.0 s to do so. (5280 ft = 1 mi)
Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
ΔS = 49.13 ft