Answers
Given:
The distance covered by the plane, d_A=1170 miles
The distance covered by the car, d_C=260 miles
To find:
The speed of the car.
Explanation:
Let us assume that the speed of the jet and the car is S_A and S_C respectively.
Then from the question,
\(S_A=S_C+325\text{ }\to\text{ \lparen i\rparen}\)Let us assume the time of ride in the jet and the car is t_A and t_C respectively.
Then from the question,
\(t_A=t_C-1\text{ }\to\text{ \lparen ii\rparen}\)The speed of the jet is given by the equation,
\(\begin{gathered} S_A=\frac{d_A}{t_A} \\ \implies d_A=S_At_A\text{ }\to\text{ \lparen iii\rparen} \end{gathered}\)On substituting the equations (i) and (ii) in equation (iii),
\(d_A=(S_C+325)(t_C-1)\text{ }\to\text{ \lparen iv\rparen}\)The speed of the car is given by,
\(\begin{gathered} S_C=\frac{d_C}{t_C} \\ \implies t_C=\frac{d_C}{S_C}\text{ }\to\text{ \lparen v\rparen} \end{gathered}\)On substituting the equation (v) in equation (iv),
\(\begin{gathered} d_A=(S_C+325)(\frac{d_{C}}{S_{C}}-1) \\ \implies d_AS_C=(S_C+325)(d_C-S_C) \end{gathered}\)On substituting the known values in the above equation,
\(\begin{gathered} 1170S_C=(S_C+325)(260-S_C) \\ \implies1170S_C=-S_C^2-65S_C+84500 \\ \implies S_C^2+1235S_C-84500=0 \end{gathered}\)On solving the above equation,
\(\begin{gathered} S_C=65\text{ mph or} \\ S_C=-1300\text{ mph} \end{gathered}\)As the car is moving forward, S_C=65 mph
Final answer:
The speed of the car is 65 mph.
Related Questions
A red 8-kg ball that is going 3-m/s collides with a 2-kg blue ball that is at rest. The blue
ball then goes 6-m/s. What is the red ball's speed?
Answers
Answer:
Explanation:
Given:
m₁ = 8 kg
V₁ = 3 m/s
m₂ = 2kg
V₂ = 0
V₂' = 6 m/s
__________
V₁' - ?
m₁V₁ + m₂V₂ = m₁V₁' + m₂V₂'
8·3 + 2·0 = 8·V₁' + 2·6
24 = 8·V₁' + 12
24 - 12 = 8·V₁'
12 = 8·V₁'
V₁' = 12 / 8 = 1.5 m/s
Two objects (m1 = 5.30 kg and m2 = 3.50 kg) are connected by a light string passing over a light, frictionless pulley as in the figure below. The 5.30-kg object is released from rest at a point h = 4.00 m above the table. Answer parts a-c.
Answers
The speed of the 5.30-kg object when it has fallen 2.50 m is 3.03 m/s.
In the scenario, the two objects (m1 = 5.30 kg and m2 = 3.50 kg) are connected by a light string passing over a light, frictionless pulley. When the 5.30-kg object is released from rest at a point
h = 4.00 m
above the table, we have to find the tension, acceleration, and speed of the 5.30-kg object. The following are the answers to parts a, b, and c of the given question.a. What is the tension in the string?The tension in the string is equal to the weight of the objects. Therefore, we can calculate the tension in the string as:
$$T = (m_1 + m_2)g$$
Substitute the values to get:Tension
T = (5.30 kg + 3.50 kg) × 9.8 m/s² = 82.6 NAns
The tension in the string is 82.6 N.b. What is the acceleration of the 5.30-kg object?We can calculate the acceleration using the formula:
$$a = \frac{m_1 - m_2}{m_1 + m_2}g$$
Substitute the values to get:Acceleration
a = (5.30 kg - 3.50 kg) / (5.30 kg + 3.50 kg) × 9.8 m/s² = 1.84 m/s²Ans:
The acceleration of the 5.30-kg object is 1.84 m/s².c.
What is the speed of the 5.30-kg object when it has fallen 2.50 m?We can use the formula to calculate the final velocity of an object with constant acceleration. The formula is
v² = u² + 2aswhere:v = final velocityu = initial velocity = 0as = acceleration × distance = 1.84 m/s² × 2.50 m = 4.6 m/s²Substitute the values to get:
v² = 0² + 2 × 1.84 m/s² × 2.50 mv² = 9.2 m²/s²v = √9.2 m²/s² = 3.03 m/sAns:
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find the power of a lift that transfers 450 J of energy in 15 seconds.
Answers
Answer: P=30W
Explanation:
formula is p=w/t
p = power
w = work
t = elapsed time
input variables, solve then simplify.
The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.
Power is defined as the rate of doing work, i.e. the amount of work done per unit time.
Mathematically, it can be represented as follows:
Power = Work done / time taken
Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:
Power = Work done / time taken= 450 J / 15 s= 30 W
Therefore, the power of the lift is 30 watts.
To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.
Here, we are given that the lift transfers 450 J of energy in 15 seconds.
We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.
In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.
Hence, we can conclude that the power of the lift is 30 watts.
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) The graph in the figure shows the position of a particle as a function of time as it travels along the x-axis.
What is the average velocity of the particle between t = 2.0 s and t = 4.0 s?
Answers
The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
What is average velocity?Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.
The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
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Very far from earth (at R- oo), a spacecraft has run out of fuel and its kinetic energy is zero. If only the gravitational force of the earth were to act on it (ie., neglect the forces from the sun and other solar system objects), the spacecraft would eventually crash into the earth The mass of the earth is Me and its radius is Re. Neglect air resistance throughout this problem, since the spacecraft is primarily moving through the near vacuum of space
Find the speed s of the spacecraft when it crashes into the earth Express the speed in terms of M, Re, and the universal gravitational constant G.
Answers
Answer:
Speed of the spacecraft right before the collision: \(\displaystyle \sqrt{\frac{2\, G\cdot M_\text{e}}{R\text{e}}}\).
Assumption: the earth is exactly spherical with a uniform density.
Explanation:
This question could be solved using the conservation of energy.
The mechanical energy of this spacecraft is the sum of:
the kinetic energy of this spacecraft, andthe (gravitational) potential energy of this spacecraft.Let \(m\) denote the mass of this spacecraft. At a distance of \(R\) from the center of the earth (with mass \(M_\text{e}\)), the gravitational potential energy (\(\mathrm{GPE}\)) of this spacecraft would be:
\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R}\).
Initially, \(R\) (the denominator of this fraction) is infinitely large. Therefore, the initial value of \(\mathrm{GPE}\) will be infinitely close to zero.
On the other hand, the question states that the initial kinetic energy (\(\rm KE\)) of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.
Right before the collision, the spacecraft would be very close to the surface of the earth. The distance \(R\) between the spacecraft and the center of the earth would be approximately equal to \(R_\text{e}\), the radius of the earth.
The \(\mathrm{GPE}\) of the spacecraft at that moment would be:
\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\).
Subtract this value from zero to find the loss in the \(\rm GPE\) of this spacecraft:
\(\begin{aligned}\text{GPE change} &= \text{Initial GPE} - \text{Final GPE} \\ &= 0 - \left(-\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\right) = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \end{aligned}\)
Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the \(\rm GPE\) of this spacecraft would be equal to the size of the gain in its \(\rm KE\).
Therefore, right before collision, the \(\rm KE\) of this spacecraft would be:
\(\begin{aligned}& \text{Initial KE} + \text{KE change} \\ &= \text{Initial KE} + (-\text{GPE change}) \\ &= 0 + \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \\ &= \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\end{aligned}\).
On the other hand, let \(v\) denote the speed of this spacecraft. The following equation that relates \(v\!\) and \(m\) to \(\rm KE\):
\(\displaystyle \text{KE} = \frac{1}{2}\, m \cdot v^2\).
Rearrange this equation to find an equation for \(v\):
\(\displaystyle v = \sqrt{\frac{2\, \text{KE}}{m}}\).
It is already found that right before the collision, \(\displaystyle \text{KE} = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\). Make use of this equation to find \(v\) at that moment:
\(\begin{aligned}v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{\frac{2\, G\cdot M_\text{e} \cdot m}{R_\text{e}\cdot m}} = \sqrt{\frac{2\, G\cdot M_\text{e}}{R_\text{e}}}\end{aligned}\).
identical spheres are dropped from a height of 100 m above the surfaces of Planet X and Planet Y. The speed of the spheres as a function of time is recorded for each planet in the graph
above. Which planet exerts the greater force of gravity on the sphere, and what evidence supports this conclusion?
A Planet X because its line has the greater area under it.
Planet X, because its line has the greater slope
Planet Y. because it falls for the smaller amount of time
Planet Y because the object's final speed is greater
Answers
Answer:
B. Planet X, because its line has the greater slope.
Explanation:
In a speed graph, acceleration is slope. A greater slope means a greater acceleration. According to Newton's 2nd law (F=mg), a greater acceleration means a greater force.
Planet X exerts the greater force of gravity on the sphere, because its line has the greater slope. Hence option B is correct.
What is Gravitational Force ?Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F ∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
if a planet has greater gravitational force(force of gravity), then body falls with greater speed as compare to other planet which is having less force of gravity. we can see in case of planet X there is greater speed as compare to plane Y in short time. Hence option B is correct.
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Which of these could be considered models? Check all that apply.
a drawing of Earth's rock layers
a digital measuring tool
a computer design of a space shuttle
a 3-D representation of a volcano
a rover on the surface of Mars
Answers
Answer: drawing of Earth's rock layers
computer design of a space shuttle
3-D representation of a volcano
Explanation:
A scientific model can be defined as the physical, conceptual, and mathematical representation of the facts, processes and events. This helps in demonstration, education, and prediction of patterns of the world based on various aspects of the scientific study.
The drawing of the earth rock layers will help in understanding the generation of rocks.
The computer designed shuttle will help in understanding its function and working in the space.
The 3-D representation of volcano will help in understanding the formation and effect of volcano in the surrounding.
Answer:
1
3
4
Explanation:
1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
Answers
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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What are some of the forces affecting rock climbers?
Answers
Answer:
Gravitational force
Explanation:
Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.
Answer:
Gravity, low oxygen, and rock slides.
Explanation:
Some rock climbers train for years but are hardly prepared for some situations.
A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 118 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 33.4°. How wide is the river?
Answers
Answer:
68.5 meters
Explanation:
To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.
Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).
sin(33.4°) = opposite/hypotenuse
sin(33.4°) = w/x
w = x * sin(33.4°)
w = 118 m * sin(33.4°)
w = 68.5 m
Therefore, the width of the river is approximately 68.5 meters.
What do you picture in your mind when you read this simile?
Bolt runs as fast as lighting.
Bolt runs very fast.
Bolt runs in a straight line.
Bolt runs in a wavy manner.
Bolt's each step produces thunder.
Answers
When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."
This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.
While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.
Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.
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How much work is done by 15 kW engine during 3.5 min? Explain the answer if you can plz
Answers
Answer:
W = 3.15 · 10⁶ J
Explanation:
We know that power is calculated using the formula:
P = W/twhere P = power (W), W = work (J), and t = time (s)We can derive a formula for work using this formula by multiplying t to both sides of the equation.
W = PtLet's convert 15 kW to W.
15 kW → 15,000 WLet's convert 3.5 min to s.
3.5 min → 210 sSubstitute these values into the formula for work and solve for W.
W = Pt W = (15,000 W) · (210 s) W = 3,150,000 J W = 3.15 · 10⁶ JThis is the amount of work done by a 15 kW engine in 3.5 minutes.
How does the Law of Conservation of Matter apply to you when you eat food? Why do you not continuously gain exactly the amount of mass you consume with each meal? Help meh explain this!
Answers
Explanation:
You cannot gain exact amount of mass you consume because some of the food particles will trap in the mouth or teeth
And some food will not digest ex fiber
And some food particles will stay in the plate
When one eats food, some of the food is excreted in solid form or in its liquid form; As such, it is impossible to gain exactly the amount of mass consumed.
The law of conservation of mass states that matter can neither be created nor destroyed by chemical reactions or physical transformations.
On this basis; it is impossible to gain exactly the amount of mass one consumes with each meal because some of the food consumed are given off and are therefore responsible for the deficit in mass gain.
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Imagine you have three flashlights. One has a blue light, one has a green light and
one is red. If you were to shine each of those lights in the same spot, what color do
you think you would see? Explain.
Answers
Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
What is the visible spectrum?
At one end of the electromagnetic wave line, which has the group of the visible spectrum. This has been referred to as the visible light of the spectrum. The visible light with the shortest of the wavelength has the blue light and the one with the longest has the red light.
The primary colors of the light has been the spectrum are red, blue, and green. The combination of these colors will form other as well as the colors which has been referred to as the secondary colors. The combination of the beam of the red light and the beam of green light will form yellow color.
Therefore, Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
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The liquid and gaseous state of hydrogen are in thermal equilibrium at 20.3 K. Even though it is on the point of condensation, model the gas as ideal and determine the most probable speed of the molecules (in m/s). What If? At what temperature (in K) would an atom of xenon in a canister of xenon gas have the same most probable speed as the hydrogen in thermal equilibrium at 20.3 K?
Answers
Answer:
a) the most probable speed of the molecules is 409.2 m/s
b) required temperature of xenon is 1322 K
Explanation:
Given the data in the question;
a)
Maximum probable speed of hydrogen molecule (H₂)
\(V_{H_2\) = √( 2RT / \(M_{H_2\) )
where R = 8.314 m³.Pa.K⁻¹.mol⁻¹ and given that T = 20.3 K
molar mass of H₂; \(M_{H_2\) = 2.01588 g/mol
we substitute
\(V_{H_2\) = √( (2 × 8.314 × 20.3 ) / 2.01588 × 10⁻³ )
\(V_{H_2\) = √( 337.5484 / 2.01588 × 10⁻³ )
\(V_{H_2\) = 409.2 m/s
Therefore, the most probable speed of the molecules is 409.2 m/s
b)
Temperature of xenon = ?
Temperature of hydrogen = 20.3 K
we know that;
T = (Vxe² × Mxe) / 2R
molar mass of xenon; Mxe = 131.292 g/mol
so we substitute
T = ( (409.2)² × 131.292 × 10⁻³) / 2( 8.314 )
T = 21984.14167 / 16.628
T = 1322 K
Therefore, required temperature of xenon is 1322 K
A basketball player jumps straight up for a ball. To do this he lowers his body 0.330m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940m above the floor
Answers
a) Velocity of basketball player when he leaves the floor is 6.64 m/s ; b) Acceleration while basketball player is straightening his legs is 73.8 m/s² ; c) Basketball player exerts a force of 8118 N on the floor to jump up for the ball.
What is meant by velocity and acceleration?Acceleration is the rate of change of velocity, while velocity is the rate of change of displacement.
(a) m g h = (1/2)mv²
m is player's mass, g is acceleration due to gravity, h is initial height, v is velocity when the player leaves the floor.
(110 kg)(9.81 m/s²)(0.300 m) = (1/2)(110 kg)(v²) + (110 kg)(9.81 m/s²)(0.900 m)
v = 6.64 m/s
So, velocity of basketball player when he leaves the floor is 6.64 m/s.
(b) v² = u² + 2as
u is initial velocity (zero in this case), a is acceleration, s is distance traveled, and v is the final velocity (6.64 m/s in this case).
(6.64 m/s)² = 2a(0.300 m)
a = 73.8 m/s²
Therefore, acceleration while the basketball player is straightening his legs is 73.8 m/s²
(c) F = ma
F : force, m is the player's mass, and a is the acceleration.
F = (110 kg)(73.8 m/s²)
F = 8118 N
Therefore, basketball player exerts a force of 8118 N on the floor to jump up for the ball.
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Note: The question given on the portal is incomplete. Here is the complete question.
Question: A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.900 m above the floor. (a) Calculate his velocity when he leaves the floor. (b) Calculate his acceleration while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.300 m. (c) Calculate the force he exerts on the floor to do this, given that his mass is 110 kg.
Question 1
2 pts
Explain what causes a solution to be a strong acid.
Answers
Answer:
Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.
A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.
Answers
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
1. Lucky Larry was in a car crash. He hit a brick wall going 40 mph. But his airbag
inflated and saved him because
A. it reduced the time of the collision.
B. it reduced his initial velocity.
C. it reduced his change in momentum.
D.it reduced his average
force.
Answers
Answer:
The answer is D (It reduced his average
force.)
1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
Answers
2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.
.An electron of charge 1.6 x 10-19is situated in a uniform electric filed strength of 120 vm-1 Calculate the force acting on it
Answers
The force acting on the electron is 1.92 x 10^-17 N.
The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.
We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.
The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.
Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.
F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.
Therefore, the force acting on the electron is 1.92 x 10^-17 N.
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An object weighs 3 lb. at 10 earth radii from its center. What is the object's weight on the earth's surface?
______ lb.
300
30
3
3,000
Answers
Answer:
3
Explanation:
how might countries go about changing their CO2 emissions? What, if anything should be done about these countries C02 emissions?
Answers
2. Encourage citizens to use public transport
3. Better waste management systems (instead of burning waste, recycle etc.)
that’s all i could think of :)
On the graph of voltage versus current, how do the resistors compare?
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The diagram shows squares 1, 2, and 3 constructed on the
sides of a right triangle.
3
2
Which statement about the squares must be true?
A. (Perimeter of 1) + (Perimeter of 2) = (Area of 3)
B. (Area of 1) + (Area of 2) = (Area of 3)
C. (Perimeter of 1) + (Perimeter of 2) = (Perimeter of 3)
D. (Area of 1) + (Area of 2) = (Perimeter of 3)
SUBMIT
Answers
The statement that must be true is: (Area of 1) + (Area of 2) = (Area of 3). This statement accurately reflects the relationship between the areas of the squares in the given diagram.
The correct answer is option B.
To determine which statement about the squares must be true, let's analyze the given diagram and the properties of squares.
In the diagram, square 1 is constructed on one side of the right triangle, square 2 is constructed on another side of the right triangle, and square 3 is constructed on the hypotenuse of the right triangle.
Statement A: (Perimeter of 1) + (Perimeter of 2) = (Area of 3)
This statement relates to the perimeters of squares 1 and 2 being equal to the area of square 3. However, this is not necessarily true. The perimeters of squares 1 and 2 are related to the lengths of their sides, while the area of square 3 is related to the length of its side. The perimeters and areas are different measures, so this statement is not necessarily true.
Statement B: (Area of 1) + (Area of 2) = (Area of 3)
This statement compares the areas of squares 1 and 2 to the area of square 3. Since squares have all sides equal in length, the areas of squares 1 and 2 are equal to the area of square 3. Therefore, this statement must be true
Statement C: (Perimeter of 1) + (Perimeter of 2) = (Perimeter of 3)
This statement relates to the perimeters of squares 1 and 2 being equal to the perimeter of square 3. However, since the squares have different side lengths, their perimeters are different. Therefore, this statement is not necessarily true.
Statement D: (Area of 1) + (Area of 2) = (Perimeter of 3)
This statement compares the areas of squares 1 and 2 to the perimeter of square 3. As mentioned earlier, the areas of squares 1 and 2 are equal to the area of square 3, which means they are not necessarily equal to the perimeter of square 3. Hence, this statement is not necessarily true.
Therefore, the correct statement is option B.
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Can you make predictions about what will happen in a crash when
you know the object's momentuo?
LAB SCIENCE
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A vector has components (6,2). What will be the new components if the vector is multiplied by a scalar value of 5?
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Answer:
The specified vector can be written in the form
A = 6 i + 2 j
5 A = 30 i + 10 j
with components (30, 10)
HELP: A block of mass 3 kg slides along a horizontal surface that has negligible friction except for one section, as shown above. The block arrives at the rough section with a speed of 5 m/s and leaves it 0.5 s later with a speed of 3 m/s.
Question
What is the magnitude of the average frictional force exerted on the block by the rough section of the surface?
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The average frictional force exerted on the block by the rough section of the surface D 4N.
What is frictional ?Frictional force is the force exerted between two objects when they are in contact and one object is moving relative to the other. It is caused by the microscopic irregularities on the surface of the objects, which cause them to stick together and resist relative motion. Frictional forces are always present, and can be beneficial in some cases, but can also cause wear and other forms of damage if too great. Frictional forces can be reduced by applying a lubricant, such as oil or grease, which reduces the surface area of contact and allows the objects to move more easily.
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Select the correct answer. What is the electron configuration of an element with atomic number 15? A. B. O C. O D. OE. 15² 25² 2p6 1s² 2s² 2p 3s² 3p5 1s² 25² 2p 3s² 3p³ 1s² 25² 2p 3s² 1s² 2s² 2p 3p³ 3s² 3p¹
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The electron configuration of an element with atomic number 15 is 3s² 3p⁵.
What is electronic configuration?The electron configuration of an element with atomic number 15 (which corresponds to the element phosphorus) can be determined by following the Aufbau principle and the Pauli exclusion principle. The Aufbau principle states that electrons occupy the lowest energy levels available, while the Pauli exclusion principle states that each orbital can hold at most two electrons with opposite spins.
What is energy level of phosphorus?Starting with the first energy level, we fill in the electrons for each subsequent energy level until we reach the 15 electrons of phosphorus: 1s² 2s² 2p⁶ 3s² 3p⁵
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I want you to think about each of these scenarios, what do you think will happen after? I just want you to think about it, and write a little about what is going to happen.
2. A truck is moving at 20 mph. Your car is standing still at a light and the truck crashes into you before the driver has a chance to step on the brakes.
3. You are driving your car at 20 mph. A bicycle right ahead of you suddenly stops and you crash into it before you have a chance to step on the brakes.
4. A bicycle is moving at 20 mph. Your car is stopped for a light and the bicycle crashes into you.