How would life be different without penicillin

The general form of a neutralization reaction is HF + FrOH → FrF + H₂O

We refer to this as a neutralisation reaction. Only this reaction, which produces NaCl and water as products, is a neutralisation reaction since it involves HCl and NaOH. The resulting response is listed below: NaCl(aq) + H₂O = HCl(aq) + NaOH(aq) (l)

The interaction of H⁺ ions and OH⁻ ions produces water in a neutralisation reaction, which occurs when an acid and a base combine to make water and a salt. The neutralisation of a strong acid and strong base yields a pH of 7.

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The reaction that will result in a decrease in entropy is:

Entropy is a measure of the degree of randomness of a substance.

An increase in entropy means an increase in disorderliness whereas a decrease in entropy means an increase in orderliness.

A change of state from gas to liquid or gas to solid or liquid to solid means a decrease in entropy value.

Also, a decrease in the moles of a gas after a reaction means a decrease in entropy.

Therefore, the reaction that will result in a decrease in entropy is:

N₂(g) + 3H₂(g) → 2NH3(g).

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Answer: D)

Explanation:

Na is the symbol for sodium.

As per the given details, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

Based on the provided information, we can match the metals to the methods used to extract them as follows:

Sodium - Extracted by electrolysis of a molten ionic compound.

Magnesium - Extracted from its oxide by reduction with carbon.

Carbon - Not a metal, so it doesn't apply in this context.

Metal E - Extracted from its oxide by reduction with hydrogen.

Iron - Removed from earth as metal itself.

Hydrogen - Not a metal, so it doesn't apply in this context.

Copper - Not a metal D or E, so it doesn't apply in this context.

Matching the metals to the extraction methods:

Sodium - extracted by electrolysis of a molten ionic compound.

Magnesium - extracted from its oxide by reduction with carbon.

Metal D - extracted from its oxide by reduction with hydrogen.

Metal E - removed from earth as metal itself.

Iron - removed from earth as metal itself.

Therefore, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

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Answer: 4.88 g/mol. and helium

Explanation:

To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:

P = pressure = 2.000 atm

V = volume = 50.00 L

n = number of moles

R = gas constant = 0.08206 L·atm/K·mol

T = temperature = 273.15 K

First, we need to find the number of moles of the gas:

PV = nRT

n = PV/RT

n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)

n = 1.844 mol

Now, we can find the molar mass of the gas by dividing its mass by the number of moles:

molar mass = mass/number of moles

mass = 9.00 g

molar mass = 9.00 g/1.844 mol

molar mass = 4.88 g/mol

Therefore, the molar mass of the gas is 4.88 g/mol.

To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

1.55 × 10²⁵ atoms of H  

Explanation:

3.21mol C₃H₈ × 8mol H × (6.022×10²³)

Answer:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Explanation:

Kinetic Energy is directly related to temperature; the higher the temperature the higher the kinetic energy. Kinetic energy is also equal to 12m⋅v2, so if we want a high velocity we want high temp and low mass. So let's list out approximate masses:

m(H2)≈2

m(NO2)≈46

m(Ne)≈20

So we have NO2 at 339 K, the lowest temperature out of the mix, and the highest mass out of the mix, so this is moving the slowest.

In contrast, we have H2 at 425 K, the highest temperature out of the mix, and the lowest mass out of the mix, so this is moving the fastest.

Now we have Ne and H2 at 371 K, since they are at the same temperature they have the same kinetic energy. But H2 is lighter than Ne so it must be faster. To quantify this mathematically, let's assume (this is wrong but just as an assumption for an example) KE at 371 K is 100:

100=12⋅m⋅v2

200=m⋅v2

√200m=v

So H2 is about v=10 and Ne is about v=√10≈3

So the order to recap is:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Hope that makes it clearer!

Answer: ≈ 13620g³m

Explanation:

A = m d

1Lb = 454g

1000g = 1kg

m = 120Lb × 454/1Lb ×1kg/1000g ≈ 1362Lb/25g kg

m = 10.0 mg / kg

A = m d

(1362kg) ( 10.0 mg/kg)

≈ 13620g³m

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Answer:

The watch is 40.9 years old.

Explanation:

To know how many years old is the watch we need to use the following equation:

\( I_{(t)} = I_{0}e^{-\lambda t} \)   (1)

Where:

\(I_{(t)}\): is the brightness in a time t = (1/10)I₀

\(I_{0}\): is the initial brightness

λ: is the decay constant of tritium

The decay constant is given by:

\( \lambda = \frac{ln(2)}{t_{1/2}} \)   (2)

Where:

\(t_{1/2}\): is the half-life of tritium = 12.3 years

By entering equation (2) into (1)  we have:

\( I_{(t)} = I_{0}e^{-\lambda t} = I_{0}e^{-\frac{ln(2)}{t_{1/2}}t} \)

\( \frac{I_{(t)}}{I_{0}} = e^{-\frac{ln(2)}{t_{1/2}}t} \)

By solving the above equation for "t" we have:

\( ln(\frac{I_{(t)}}{I_{0}}) = -\frac{ln(2)}{t_{1/2}}t \)

\( t = -\frac{ln(\frac{I_{(t)}}{I_{0}})}{\frac{ln(2)}{t_{1/2}}} = -\frac{ln(\frac{1}{10})}{\frac{ln(2)}{12.3}} = 40.9 y \)

Therefore, the watch is 40.9 years old.

I hope it helps you!

Answer:

The percentage of IF₅ (by mole) in the final product mixture will be 50%. This is determined by the stoichiometry of the reaction, the given molar mass of the reactants, and the ideal gas law.

Explanation:

Answer: True because if you leave it outside and it rains on the bike it will cause rust. Keep it in the garage or something. :) I have a bike btw.

Explanation:

The best way to prevent rusting is to store your bike safely away when it isn't being used and apply a rust-proofing lubricant to protect it when you are riding it – enjoying those wet and wild rides guilt-free!

so true

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Answer:

- \(M=0.38M\)

- \(\\ \% m=3.67\%\)

Explanation:

Hello,

In this case, since the molar mass of potassium nitrate is 101.1 g/mol, we can compute the molarity as follows:

\(M=\frac{75.1g*\frac{1mol}{101.1g} }{1.95L} \\\\M=0.38M\)

Moreover, as the mass percent is computed as:

\(\% m=\frac{m_{KNO_3}}{m_{solution}} *100\%\)

Thus, by using the given density of the solution, we obtain:

\(\% m=\frac{75.1g}{1.95L*\frac{1000mL}{1L}*\frac{1.05g}{1mL} } *100\%\\\\ \% m=3.67\%\)

Regards.

Answer:

Due to an electron-pair acceptor and donor.

Explanations:

Lewis acid can be defined as an electron-pair acceptor. An example is Hydrogen ion(H+). This is because it is a proton and it distributes positive charge which means that it accepts electrons(negative charge).

Lewis base can be defined as an electron-pair donor. This is because it donates electrons to be accepted by the proton. An example is ammonia(NH3).

The number of atoms of any element in the given chemical formula is the number that is written on the foot of the symbol of that element. Therefore, chlorine has the strongest attraction for electrons in a chemical bond.

Atom is the smallest particle of any matter. Atom combines to form element and element combine to form molecule or compound.

Atom consists of electron, proton and neutron. The total mass of atom is inside the nucleus. Inside the nucleus proton and neutron is there. So calculate mass of an atom, total mass of all protons is added to the total mass of neutron. Electrons revolve around the nucleus.

Electronegative element have greatest strongest attraction for electrons due to high effective nuclear charge. Among the given molecules, chlorine is the most electronegative element. Chlorine has the strongest attraction for electrons in a chemical bond.

Therefore, chlorine has the strongest attraction for electrons in a chemical bond.

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Answer:

B me get points

Explanation:

:(

Answer:

most likely A not sure

because coal let's off smoke that has carbon minoxidil and carbon gets into the oxygen o2

Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

V  = π × 182.25 cm × 32.4 cm

V = 18550.79 cm³  

V = 18.551 L

given that; maximum safe pressure P = 3.10 MPa = 30.5946 atm

vessel contains 0.218kg or 218 gram of carbon monoxide gas

molar mass of carbon monoxide gas is 28.010 g/mol

so

moles of carbon monoxide gas n = 218 gram /  28.010 g/mol = 7.7829 mol

we know that;

PV = nRT

solve for T

T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

T = ( 889.317387 - 273.15 ) °C

T = 616.167 ≈ 616 °C  { 3 significant digits }

Therefore, the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Answer:

Diseases of Poultry
a. ESCHERICHIA COLI INFECTIONS.
b. SALMONELLOSES.
c. PARATYPHOID INFECTIONS.
d. FOWL CHOLERA.
e. RIEMERELLA ANATIPESTIFER INFECTIONS.MYCOPLASMA.
f. NECROTIC ENTERITIS.
g. CHOLANGIOHEPATITIS IN BROILER CHICKENS.

Explanation:

Answer:

◎Bacterial diseases

◎Mycoplasmosis (CRD, Air sac, Sinusitis)

◎Fowl Cholera

◎Necrotic Enteritis

◎Ulcerative Enteritis (Quail disease)

◎Pullorum Disease

◎Fowl

◎Botulism

◎Infectious Coryza

◎Omphalitis

◎Erysipelas

◎Parasitic diseases (internal)

◎Parasitic diseases (external)

◎Infectious Bronchitis

◎Viral diseases

◎Newcastle Disease

◎Quail Bronchitis

◎Lymphoid Leukosis

◎Marek's Disease (Visceral Leukosis)

◎Infectious Bursal Disease (Gumboro)

Explanation:

:)

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

where,

\(P_1\) = initial pressure of gas = 751 mm Hg

\(P_2\) = final pressure of gas = 495 mm Hg

\(V_1\) = initial volume of gas = 340 L

\(V_2\) = final volume of gas = ?

\(T_1\) = initial temperature of gas = \(30^oC=273+30=303K\)

\(T_2\) = final temperature of gas = \(-27^oC=273-27=246K\)

Now put all the given values in the above equation, we get:

\(\frac{751\times 340}{303}=\frac{495\times V_2}{246}\)

\(V_2=419L\)

Thus the volume of the balloon at this altitude is 419 L

\(\frac{1}{6}L\) or 166.667 ml of water must be evaporated in order to make this solution 3M.

When the problem states "250ml of 1M Ca(OH)₂", it means that you have 250ml of a solution that contains 1 mole of solute (Ca(OH)₂) for each liter of the solution.

In order to make a 1M solution be a 3M solution, we'll have to remove some of the solvent liquid, in order to make it more concentrated.

The original molarity is: M= Moles of solute (n) / Liters of solution (v).

Since the problem states that the original molarity is 1M, we have 1 mole of solute per liter of solution in the original solution. Therefore, initial molarity is: \(M=\frac{1mol}{1liters}=\frac{0.250mol}{0.250L}\)

250ml= 0.250 L.

As you may see, in order to make the molarity fraction equal 3M, we'll have to multiply the numerator by 3 or divide the denominator by the same number:

\(M=\frac{0.250mol}{0.250L/3}=\frac{0.250mol}{\frac{1}{12} L}\)

The amount of solution evaporated is given by the difference between the denominator of the molarity of the original expression and the new expression:

\((0.250-\frac{1}{12})\\ \\(\frac{3}{12}-\frac{1}{12})L\\ \\\frac{2}{12} L\\ \\\frac{1}{6} L\)

\(\frac{1}{6}L\) or 166.667 ml of water must be evaporated in order to make this solution 3M. The ending product will have the following molarity:

\(M=\frac{0.250moles}{\frac{1}{12} L} =3M\).

Answer:

pp

Explanation:

Explanation:

goodluck to your test!

The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, 35071.6 °C is the  final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points or thermometric substances.

The most popular scales were the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

Δ T = T(initial) - T(final)

T(final)= m × c × q - T(initial)

T(final)= 79.9 x 4.184 x 105 - 30.0

T(final)= 35071.6 °C

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1. The volume occupied by 8.8 g of H₂O vapor is 11.0 L

2. The mass of the oxygen (O₂) in the cylinder is 9.28 grams

1. How to determine the volume

The volume occuppied by the water, H₂O vapour can be obtained as follow:

1 mole of H₂O = 22.4 L

Therefore,

0.49 mole of H₂O = (0.49 mole × 22.4 L) / 1 mole

0.49 mole of H₂O = 11.0 L

Thus, the volume of H₂O is 11.0 L

2. How to determine the mass

We know that:

22.4 L = 1 mole of O₂

Therefore,

6.5 L = (6.5 L × 1 mole) / 22.4 L

6.5 L = 0.29 mole of O₂

Thus, we can obtain the mass as follow:

Mass = mole × molar mass

Mass of O₂ = 0.29 × 32

Mass of O₂ = 9.28 grams

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Answer:

0.0

Explanation:

Answer:

no stranger danger!

Explanation:

nice profile pic tho

Answer:

Explanation:

The number of atoms that remains after 3 half-lives given that it was originally 300000 atoms is 37500 atoms

Data obtained from the question

Original amount (N₀) = 300000 atoms

Number of half-lives (n) = 3

Amount remaining (N) =?

How to determine the amount remaining

The amount remaining after 3 half-lives can be obtained as illustrated below:

N = N₀ / 2ⁿ

N = 300000 / 2³

N = 300000 / 8

N = 37500 atoms

C, B, A, D, E  is the  sequence of events, in order from oldest to youngest.

The principle of superposition states that the youngest sedimentary rock units are at the top and the oldest ones are at the bottom. This indicates that layer C is the oldest, followed by layers B and A.

The Hadean Eon of Earth's geological history is when the oldest dated rocks on the planet were created as an amalgam of minerals that have not since been destroyed by erosion or melting. These rocks are more than 4 billion years old.

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Answer:

A)Mass

Explanation:

Mass measure the amount of matter

By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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