According to the formula, the magnetic field (B) will increase by a factor of 10, as the other factors (μ₀ and I) remain constant.
So the correct answer is:
A. It will increase by a factor of 10.
The magnetic field inside a coil of wire is given by the formula B = μ₀ * n * I,
where B is the magnetic field, μ₀ is the permeability of free space,
n is the number of turns per unit length, and I is the current through the wire.
If the radius of the coil is decreased by a factor of 10, the length of the wire remains the same, but the number of turns per unit length (n) will increase by a factor of 10.
This is because the wire is now wound more tightly around the core, resulting in more turns in the same length.
Therefore, according to the formula, the magnetic field (B) will increase by a factor of 10, as the other factors (μ₀ and I) remain constant. So the correct answer is:
A. It will increase by a factor of 10.
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What is the power of a refrigerator with voltage 110 V and
current 0.8 A?
Answer: 88
Explanation:
Two narrow slits 55 µm apart are illuminated with light of wavelength 509 .
What is the angle of the m=2 bright fringe in radians?
What is the angle of the bright fringe in degrees?
Two narrow slits 55 µm apart are illuminated with light of wavelength 509 .The angle of the m=2 bright fringe is approximately 0.0185 radians or 1.059 degrees.
To find the angle of the m=2 bright fringe in radians, we can use the double-slit interference formula:
sin(θ) = (mλ) / d
where θ is the angle of the bright fringe,
m is the order of the fringe (in this case, m=2),
λ is the wavelength of the light (509 nm), and
d is the distance between the slits (55 µm).
First, we need to convert the wavelength and distance to the same unit. Since 1 µm = 1000 nm, we can convert the distance between the narrow slits to nm: 55 µm * 1000 nm/µm = 55,000 nm.
Now, we can use the formula:
sin(θ) = (2 * 509 nm) / 55,000 nm
sin(θ) ≈ 0.018491
To find the angle in radians, take the arcsine of this value:
θ = arcsin(0.018491) ≈ 0.0185 radians
To convert this angle to degrees, use the following conversion:
1 radian ≈ 57.296 degrees
θ ≈ 0.0185 radians * 57.296 degrees/radian ≈ 1.059 degrees
So, the angle of the m=2 bright fringe is approximately 0.0185 radians or 1.059 degrees.
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The x-ray tube & image receptor move in opposite directions around a stationary ____ ( pivot point ) during the exposure
The x-ray tube and image receptor move in opposite directions around a stationary axis or pivot point during the exposure.
This is referred to as the pivot or fulcrum. The x-ray tube and image receptor can travel in a circular or elliptical motion around the patient thanks to the pivot point, which is normally in the middle of the patient's body. Several images of the same area can be obtained thanks to the motion of the x-ray tube and image receptor, giving more in-depth knowledge of the patient's anatomy. The motion can be managed manually or by a computer, and the speed and direction of the movement can be altered to improve the quality of the image.
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a gardener crosses a plant with red flowers with one with white flowers. each plant is pure for its trait for flower color.
if the gene for flower colors shows incomplete dominance, what kind of coloring will the flowers on the offspring plants most likely have
A Gardner crosses the plant with red and white flowers. Each is pure of its traits. If the gene of the flower shows incomplete dominance the dominant flow gene will show the color.
They are a mix of red and white then on the basis of dominance and recessiveness. The offspring will be in pink color. Hence the option C only pink is correct.Learn more about the plant with red flowers with one with
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Newton's law of cooling states that the temperature of an object T, in surrounding air with temperature T, will behave according to the formula: T() = Aekt +Ts where t is time in minutes, A is the difference between the temperature of the object and the temperature of its surroundings and k is a constant A turkey is taken out of the oven with an internal temperature of 165°F and is allowed to cool in a a 75°Froom. After half an hour, the internal temperature of the turkey is 145°F. a. Find the formula that models this situation we need A, Ts and k. Here is a little help: Internal temperature of the turkey when it came out of the oven The Temperature of the room the Turkey in in after leaving the oven = A= (The difference in the two temperatures above) (this is Ts) Replace A and Tg in the equation T(t) = Aekt +Ts. To find k, use the information that when t = 30, T(30) = 145, and solve for k. b. To the nearest degree what will the temperature of the turkey be 50 minutes after it leaves the oven? c. To the nearest minute, how long will it take the turkey to cool to 110 °F?
According to Newton's law of cooling, The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75. The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
(a) The formula that models the cooling of the turkey is T(t) = (165 - 75) * e^(k * t) + 75.
In this case, the temperature difference between the turkey and the room, when it came out of the oven, is A = 165 - 75 = 90°F, and Ts (the temperature of the room) is 75°F. By substituting these values into the equation T(t) = A * e^(k * t) + Ts, we get T(t) = 90 * e^(k * t) + 75.
To find the value of k, we can use the information that when t = 30 minutes, T(30) = 145°F. Substituting these values into the equation and solving for k, we have 145 = 90 * e^(k * 30) + 75. Rearranging and solving, we find k ≈ -0.0207.
(b) The temperature of the turkey 50 minutes after it leaves the oven will be approximately 118°F.
To calculate the temperature at t = 50 minutes, we can use the formula T(t) = 90 * e^(-0.0207 * t) + 75. Substituting t = 50, we have T(50) = 90 * e^(-0.0207 * 50) + 75. Evaluating this expression, we find T(50) ≈ 118°F.
(c) It will take approximately 145 minutes for the turkey to cool to 110°F.
To determine the time it takes for the turkey to reach a temperature of 110°F, we can rearrange the equation T(t) = 90 * e^(-0.0207 * t) + 75 and solve for t. So, 110 = 90 * e^(-0.0207 * t) + 75. Solving this equation, we find t ≈ 145 minutes.
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How long does it take for the sun to complete one orbit through the ecliptic?.
Answer:
It takes just a little bit over a year
Explanation:
Because Earth takes one year to orbit the Sun, So the Sun takes one year to make a complete circuit of the ecliptic. The Sun moves a little less than 1° eastward every day therefore it would be about 382 days (says scientist or less than that)
A lightning bolt travels at 270,000 miles/hour. How fast is that in meters per second? Note that 1 mile = 1609 meters.
Answer:120700.8
Explanation:
Find the work done in lifting the bucket
A 7 lb bucket attached to a rope is lifted from the ground into the air by pulling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work is done lifting the bucket and rope?
Assuming the force required to lift the rope is equal to its weight, find the force function, F(x), that acts on the rope when the bucket is at a height of x ft.
F(x)=
The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
To find the work done in lifting the bucket and rope, we need to consider two parts:
Part 1: Work done lifting the bucket (without the rope) 24 ft:
The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.
Given:
Weight of the bucket = 7 lb
Distance lifted = 24 ft
Work done lifting the bucket = Weight of the bucket x Distance lifted
Work done lifting the bucket = 7 lb x 24 ft
Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).
Part 2: Work done lifting the rope:
Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.
Given:
Weight of the rope = 0.8 lb
Distance lifted = 24 ft
Work done lifting the rope = Weight of the rope x Distance lifted
Work done lifting the rope = 0.8 lb x 24 ft
Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:
Total work done = Work done lifting the bucket + Work done lifting the rope
Please note that the units of work are in foot-pounds (ft-lb).
Now, we can calculate the values:
Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb
Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb
Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb
Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
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The complete question is:
Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.
How much work is done in compressing a spring with a 450 N/m spring constant a distance of 2cm?
The amount of work done in compressing a spring with a 450 N/m string constant a distance of 2 cm would be 0.16 Nm or 0.16 Joule.
What is work done?The work done by a moving force is the product of the magnitude of the force and the distance moved.
In other words, work done = force x distance
Also, F = kx where k is the spring constant and x is the distance.
Thus, F = 450 x 2/100 = 9 N
Workdone = 9 x 0.02 = 0.16 Nm
In other words, the work done in compressing a spring with a 450 N/m spring constant over a distance of 2cm would be 0.16 Nm
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Definition in 8 words for neuron
Answer:
Is a nerve cell that carries electrical impulses
Explanation:
.Which of the following statements is true of movement on a plane with friction ?I. Acceleration is a. function of applied force onlyII. More force is needed to accelerate a stationary object than an identical moving objectIII. force of friction is independent of the mass of objects
Statement II is true: More force is needed to accelerate a stationary object than an identical moving object.
When it comes to movement on a plane with friction, the force of friction opposes the direction of motion. To overcome this force and accelerate an object, an applied force is required. If an object is already in motion, it experiences less friction compared to a stationary object. Thus, less force is needed to accelerate an identical moving object than to overcome the initial static friction of a stationary object. The amount of force required for acceleration depends on factors such as the coefficient of friction, the mass of the object, and the applied force. The force of friction itself is not independent of the mass of objects, as stated in Statement III. The force of friction can vary based on the weight or mass of the objects involved.
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Use the drop-down menus to complete the sentences. Tetra fish that live in caves are blind and have small eyes that do not work. This is an example of a . A harbour seal's flipper and a human hand have a very similar structure, but function differently. This is an example of a .
Answer:
vestigial structure
Homologous structure
Explanation:
Did the assignment.
Tetra fish that live in caves are blind and have small eyes that do not work. This is an example of a vestigial structure.
A harbour seal's flipper and a human hand have a very similar structure, but function differently. This is an example of a Homologous structure.
What is vestigial structure?
Some organisms have elements that seem to be left over from an earlier ancestor but have no apparent purpose. For instance, because they are evolved from reptiles with legs, certain snakes have pelvic bones despite not having any. The human vermiform appendix is another instance of a structure that serves no purpose.
Vestigial structures are these inactive, purposeless structures. Other examples of vestigial structures are the wings of flightless animals like the ostrich, the leaves of some cacti, the remains of whale pelvic bones, and the eyes that are blind in cave mammals.
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the heat associated with saunas and hot tubs may cause fetal _________
The heat associated with saunas and hot tubs may cause fetal harm or complications.
Exposure to high temperatures, such as those found in saunas and hot tubs, can potentially lead to an increased risk of certain complications during pregnancy. It is generally recommended that pregnant women avoid prolonged exposure to high temperatures and excessive heat. The main concern is that increased body temperature can potentially affect the development of the fetus and increase the risk of birth defects or pregnancy complications. High temperatures can lead to maternal hyperthermia, which may negatively impact the developing fetus, particularly during the first trimester when organ formation is occurring.
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How do scientists determine the number of neutrons in an isotope of an atom?
They subtract the atomic number from the atomic mass.
They find the number of protons.
They divide the atomic mass by two.
They add the number of electrons and protons.
Answer:
They subtract the atomic number from the atomic mass
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A force is applied to a box to move it to the right across the kitchen floor what forces are being used?
Answer:
The static "frictional force" and the "kinetic friction" will act on the box.
For a school project, Robert records the motion of a snail and plots a position-time graph of the data.
From the graph, the distance the snail travels in the first 20 seconds is
centimeters. After that, the snail remains in the same place for
seconds.
The graph can be used to obtain the speed of the snail at any instant.
What is a distance time graph?A distance time graph is a graph in which the distance is indicated in the vertical axis and the time is indicated on the horizontal axis. We can use this plot to determine;
Uniform speedNon - uniform speedInstanteanous speedNow, the question is incomplete but the graph can be used to obtain the speed of the snail at any instant.
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For general projectile motion with no air resistance, the vertical component of a projectile's acceleration For general projectile motion with no air resistance, the vertical component of a projectile's acceleration remains a non-zero constant. continuously decreases. first decreases and then increases. is always zero. continuously increases.
Answer:
Rmains constant
Explanation:
The equation of the trajectory of a projectile motion is presented as follows;
\(Y = x \cdot tan \theta -\dfrac{g \cdot x^2}{2 \cdot u^2 \cdot cos^2 \theta}\)
The vertical componet of the prjectile motion is
y = (u·sinθ)·t - g·t²/2
Where;
θ = The angle with which the projectile is launched
x = The horizontal distance
u = The initial velocity of the projectile
g = The acceleration due to gravity = Constant
t = The time of motion
The acceleration acting on the projectile is the 'g' which is the constant acceleration due to gravity
Therefore, for general projectile motion with no air resistance, the vertical component of the projectile acceleration remains constant
How do you read a ruler in CM?
To read a ruler in cm, locate the zero mark on the ruler, then read the measurement where the object being measured ends, aligning the end of the object with the appropriate line on the ruler, and counting the number of centimeters to that line.
When reading a ruler in cm, it is important to identify the zero mark on the ruler and align it with the beginning of the object being measured. Then, locate the end of the object and align it with the appropriate line on the ruler, counting the number of centimeters to that line.
Each centimeter on the ruler is divided into 10 smaller units called millimeters, so it is also possible to measure to the nearest millimeter by identifying the smallest line on the ruler that aligns with the end of the object.
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There is a centrifugal pump. The rotating speed n=1450rpm, the flow rate Q=0.0833m^3/s, outer diameter of impeller D2=360mm, inner diameter of impeller D,=138mm, blade outlet angle B2y=30° , flow cross- sectional area at impeller outlet A2=0.023m^2. The circulation coefficient K=0.7, assuming Cu=0. Calculate the theoretical and actual pressure head. LEC-10(2) There is a centrifugal pump. The outer diameter of impeller Dz=350mm, blade outlet width b2=12.7mm, rotating speed n=1200rpm, the flow rate Q=1.27mº/min, the pressure difference at inlet and outlet is 272kPa. The circulation coefficient K=0.9, hydraulic efficiency mn=70%, assuming Ciu=0. Calculate the blade outlet angle Bzy.
(a) The theoretical pressure head is 9.90 m, and the actual pressure head is 7.70 m. (b) The blade outlet angle Bzy is approximately 22.40°.
(a) For the first scenario:
Given:
Rotating speed (n): 1450 rpm
Flow rate (Q): 0.0833 m^3/s
Outer diameter of impeller (D2): 360 mm
Inner diameter of impeller (D1): 138 mm
Blade outlet angle (B2y): 30°
Flow cross-sectional area at impeller outlet (A2): 0.023 m^2
Circulation coefficient (K): 0.7
Assuming Cu (blade outlet velocity coefficient): 0
To calculate the theoretical pressure head, we can use the following equation:
Ht = (Q * K) / (g * A2)
where Ht is the theoretical pressure head, Q is the flow rate, K is the circulation coefficient, g is the acceleration due to gravity (approximately 9.81 m/s^2), and A2 is the flow cross-sectional area at impeller outlet.
Plugging in the given values, we have:
Ht = (0.0833 * 0.7) / (9.81 * 0.023) = 9.90 m
To calculate the actual pressure head, we can use the following equation:
Ha = (Q * K) / (g * A2) - (Cu^2 / (2 * g))
Since Cu is assumed to be 0, the second term in the equation becomes 0.
Plugging in the values, we have:
Ha = (0.0833 * 0.7) / (9.81 * 0.023) = 7.70 m
(b) For the second scenario:
Given:
Outer diameter of impeller (Dz): 350 mm
Blade outlet width (b2): 12.7 mm
Rotating speed (n): 1200 rpm
Flow rate (Q): 1.27 m^3/min
Pressure difference at inlet and outlet: 272 kPa
Circulation coefficient (K): 0.9
Hydraulic efficiency (mn): 70%
Assuming Ciu (blade inlet velocity coefficient): 0
To calculate the blade outlet angle (Bzy), we can use the following equation:
Bzy = arcsin(2 * mn * Q) / (π * Dz * b2 * sqrt(2 * g * (p2 - p1)))
where Bzy is the blade outlet angle, mn is the hydraulic efficiency, Q is the flow rate, Dz is the outer diameter of the impeller, b2 is the blade outlet width, g is the acceleration due to gravity, and p2 - p1 is the pressure difference at the inlet and outlet.
Plugging in the given values, we have:
Bzy = arcsin((2 * 0.70 * 1.27) / (π * 350 * 12.7 * sqrt(2 * 9.81 * 272))) ≈ 22.40°
(a) The theoretical pressure head is 9.90 m, and the actual pressure head is 7.70 m in the first scenario.
(b) The blade outlet angle Bzy is approximately 22.40° in the second scenario.
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5. does the capacitance of a spherical capacitor depend on which sphere is charged positively or negatively?
Yes, the capacitance of a spherical capacitor depends on which sphere is charged positively or negatively.
What is capacitance?The ability of a system to store an electric charge is known as capacitance. It is proportional to the amount of charge on each conductor divided by the voltage across the two conductors, which are the plates in the case of a capacitor. The capacitance is also dependent on the distance between the plates and the dielectric constant of the material between the plates.
The capacitance formula for a spherical capacitor is as follows:
C = (4πεrR1R2) / (R2 - R1)
where C is the capacitance, ε is the dielectric constant, r is the separation between the centers of the two spheres, R1 and R2 are the radii of the two spheres, and R2 > R1.
Now, as per the above formula of capacitance of a spherical capacitor, the capacitance depends on the distance between the spheres (separation), the radius of the spheres, and the dielectric constant of the medium between them. And the charge distribution also depends on the sphere's charge. Therefore, the capacitance of a spherical capacitor is affected by the charge distribution, and it does depend on which sphere is charged positively or negatively. This is the main answer.
The capacitance of a spherical capacitor depends on the radius and the separation of the two spheres, as well as the dielectric constant between the spheres. If one of the spheres is charged positively, and the other is charged negatively, the capacitance will be different from if the opposite charges were used. As a result, the capacitance of a spherical capacitor does indeed depend on the polarity of the charges used.
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Choose a sport you like, such as football or gymnastics. Describe how a high level of flexibility would affect your performance in that sport. Consider the benefits in many aspects of the sport.
The level of flexibility will affect my performances in football. Football
requires some level of flexibility to do certain things.
Flexibility will enable me change speed and direction easily when there is a
counter attack by the opponents. It will also assist in using some techniques
such as adding more curve on the football with the feet in order to score
goals.
Flexibility will also ensure that there will be lesser injury concerns because there will be less sprains or other muscle related injuries.
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A bullet of mass 10g and unknown speed is shot horizontally into a block of mass 990g, initially at rest on a horizontal frictionless surface. The bullet embeds itself in the block, and the combined objects slide along the surface until they encounter a horizontal spring of spring constant 400N/m. The block, with the bullet in it, comes to momentarily rest when it has compressed the spring by 10 cm. Find the initial speed of the bullet
The initial speed of the bullet is approximately 632.45 m/s. This calculation is based on the principles of conservation of linear momentum and conservation of mechanical energy in the system consisting of the bullet, block, and spring.
We can solve this problem using the principle of conservation of linear momentum and the principle of conservation of mechanical energy.
1. Conservation of linear momentum:
Before the collision, the bullet is moving horizontally with an unknown speed (let's call it v_bullet), and the block is initially at rest. After the collision, the bullet embeds itself in the block, so the combined objects move together.
Using the conservation of linear momentum, we have:
(m_bullet)(v_bullet) = (m_block + m_bullet)(v_combined)
(0.01 kg)(v_bullet) = (0.99 kg + 0.01 kg)(v_combined)
2. Conservation of mechanical energy:
After the collision, the block and bullet slide along the surface until they encounter the spring. At this point, the mechanical energy is conserved.
The potential energy stored in the compressed spring equals the initial kinetic energy of the block-bullet system.
(1/2)(k)(x^2) = (1/2)(m_combined)(v_combined)^2
Given:
m_bullet = 0.01 kg (mass of the bullet)
m_block = 0.99 kg (mass of the block)
k = 400 N/m (spring constant)
x = 0.1 m (compression of the spring)
We can now solve the equations simultaneously to find the initial speed of the bullet:
From the conservation of linear momentum:
(0.01 kg)(v_bullet) = (0.99 kg + 0.01 kg)(v_combined)
0.01 v_bullet = 1.00 v_combined
v_combined = 0.01 v_bullet
Substituting this into the conservation of mechanical energy equation:
(1/2)(400 N/m)(0.1 m)^2 = (1/2)(1.00 kg)(0.01 v_bullet)^2
20 J = 0.00005 v_bullet^2
Solving for v_bullet:
v_bullet^2 = (20 J) / (0.00005 kg)
v_bullet^2 = 400,000 m^2/s^2
v_bullet = √(400,000) m/s
v_bullet ≈ 632.45 m/s
the initial speed of the bullet is approximately 632.45 m/s.
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Determine the moment at point b using method of section if w=40.3lb/ft Answer:
Method of section is a significant method of determining forces in members of a structure.
The basic concept of the method of section is to find out the forces acting on the sections by separating them from the rest of the structure.
In this problem, the moment at point b has to be determined using the method of section.
The given weight of the beam is
w = 40.3 lb/ft.
Let's draw the free-body diagram for the given beam:
Free-Body Diagram:
As we can see from the above diagram, the section has been drawn which passes through point b.
We have to determine the moment at point b using this section.
Now, we will write the equation for the moment of the section passing through point b as:
- 12(6) - 4(8) - (20)(12) - (32)(20) - (40.3)(12/2) = 0Mb = 1126.05 lb-ft
the moment at point b is 1126.05 lb-ft.
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A 0.2 kg ball is caught in a 0.5 kg glove. The ball had been moving at 8.0 m/s and it required 5.0 N of force to stop it. What was the force on the glove?
The force on the glove is 12.8 N.
Solving for the force on the glove:
The force on the glove is equal to the impulse (change in momentum) experienced by the ball divided by the time over which the force was applied.
Impulse = force x time
= 5.0 N x (1/8.0 m/s)
Impulse = 0.625 Ns
The change in momentum of the ball ΔP is
ΔP = m x v
where,
m = is the mass of the ball
v= its velocity
Momentum = mass x velocity
= 0.2 kg x 8.0 m/s
Momentum= 1.6 kg m/s
The force on the glove is equal to the change in momentum divided by the time over which the force was applied:
Force = change in momentum/time
= 1.6 kg m/s
(1/8.0 m/s)
Force = 12.8 N
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write 100000 as a power of ten with one figure before the decimal point
Answer:
1.00000 x10^5 (or 1. x 10^5 )
Explanation:
Count the number of 0's ...this is the power of 10
A ball rolls without slipping down incline a, starting from rest. At the same time, a box starts from rest and slides down incline b, which is identical to incline a except that it is frictionless. Which arrives at the bottom first?.
The arrival of box and ball at the bottom will depend on the mass of the box as mass of box may be larger than mass of ball.
This is on the grounds that the impact that the frictional force have relies upon the mass, the point likewise have an extraordinary impact in the response, however it appears it's anything but a choice, merits seeing that the mass doesn't have impact in the ball moving given that the erosion is just mindful of the rolling.
The force which becomes possibly the most important factor at whatever point two articles come in touch and slide over one another is known as the frictional force. In easier words, the force which discourages movement while interacting with one more item is known as Rubbing or Frictional force. This force. extraordinarily fluctuates according to the surface of the surface which is in touch.
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Suppose you mount a baseball machine that fires balls straight up in the air at 96ft/s on top of a 52-foot tall building. What is the velocity of one of these baseballs when it hits the ground
The velocity of one of these baseballs when it hits the ground is 76.73 ft/s.
What is meant by velocity?Velocity is the directional speed of any object in motion as an indication of rate of change in position as observed from the particular frame of reference and as measured by the particular standard of time.
Let the final velocity be v
Given, initial velocity, u = 96 ft/s
g = 32 ft/s²
Given height, h = 52 feet
As we know, v² = u² - 2 g h
So, v² = 96 x 96 - 2 x 32 x 52
v = 76.73 ft/s
So, the speed of the ball as it hits the ground is 76.73 ft/s.
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A woman rolls a 8 kg bowling ball with an initial velocity of 10 m/s down a 20 meter tall hill. If the ball
rolls down the hill, then up a 5 meter tall hill, what is the velocity of the ball when it reaches the top of
the second hill?
Answer:
The first step is to calculate the potential energy of the ball at the top of the first hill using the formula PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the hill. PE = (8 kg) x (9.8 m/s^2) x (20 m) = 1568 J Next, we can use the law of conservation of energy, which states that the total energy of a closed system remains constant. This means that the potential energy at the top of the first hill must be equal to the kinetic energy at the bottom of the hill, since there is no external work done on the ball. So, using the formula KE = 1/2mv^2, where v is the velocity of the ball, we can solve for v: KE = 1
A student uses a graphic organizer to show the characteristics of an object in our solar system. Which of the following objects accurately completes the graphic organizer? Drag the correct title into the graphic. Asteroid, Moon, Comet, or Planet.
Answer:
comets
Explanation:
Comets have a tail unlike any other answer choice and it has a core of ice and dust. Many think comets do not orbit the sun, but they do. They orbit in a eliptical orbit, so they take a long time to orbit back to the sun.
Which type of telescope is known to be difficult to keep aligned Compound Refracting Reflecting Radio
The refracting telescope uses large lenses. The larger lenses increase the weight of the telescope. The weight of the refracting telescopes makes it difficult for the observer to keep them aligned.
Thus the correct answer is option b, refracting telescopes.
Answer:
Is Reflecting telescope
Explanation:
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