how to solve 2(q+4)+16how to solve 7j+2=12+5jhow to solve 12z=60-3z

Answer:

She has 12 oranges left

Step-by-step explanation:

convert 3/5 to a decimal

3÷5=0.6

then multiply that by 20

0.6*20=12

Answer:

A) 37+42=79(1.07)=84.53

B) you would take off the discount and that equals 59.25 then you would apply taxes 63.40

C)9.48 and 7.11

Step-by-step explanation:

Answer:

a) $84.53

37+42=79

79(0.07)=5.53

79+5.53=84.53

b) $56.50

You have to multiply the cost of both shoes by 0.25 to get the amount of money that Isaac gets discounted. Then you subtract that amount from the cost of the shoes to get the new price. Then you multiply the new price by 0.07 to get how much he will be taxed. Finally, you add the tax to the total.

c) Before the coupon is applied: $10.08

After the coupon is applied: $9.48

84(0.12)=10.08

79(0.12)=9.48

Step-by-step explanation:

Answer:

392

Step-by-step explanation:

Answer:

area of parllelogram=base×height=(4+8)×7=12×7=

84m²

Answer:

second one

Step-by-step explanation:

just multiply by -9 and see which one fits in

Answer:

{1, -9, 81, -729, …}

Step-by-step explanation:

Geometric sequence is basically multiplying the previous number by the constant. So it is 1 x -9 = -9, -9 x -9 = 81, -81 x -9 = -729, and so on.

The approximate area of the mulch around the merry-go-round is 126.228 feet².

Diameter of the merry go round = 10.4 feet

Radius is half of the diameter.

Radius of the merry go round = 10.4/2 = 5.2 feet

Before the piece can be installed, a solid circular pad of mulch must be put down which extends 3 feet beyond the edge of the merry-go-round.

Radius of the merry go round with mulch = 5.2 + 3 = 8.2 feet

Total area of the merry go round with the mulch is,

Area = π (8.2)² = 67.24π feet²

Area of the merry go round = π (5.2)² = 27.04π feet²

Area of the mulch = 67.24π feet² - 27.04π feet² = 40.2π = 126.228 feet²

Hence the required area is 126.228 feet².

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Answer:

(7x^2 -1)(x - 2).

Step-by-step explanation:

7x^3 - 14x^2 - x + 2

We can factor this by grouping - that is factoring the first 2 terms and the last 2:

= 7x^2(x - 2)  - 1(x - 2)      <-- the x - 2 is common to both parts so we have:

(7x^2 -1)(x - 2).

Answers:

a = 2

b = -1

c = 3

===========================================================

Work Shown:

(numerator)/(denominator) = quotient + (remainder)/(denominator

(2x^3-5x^2+4x-8)/(ax^2+bx+c) = x-2 + (bx-a)/(ax^2+bx+c)

2x^3-5x^2+4x-8 = (x-2)(ax^2+bx+c) + (bx-a)

2x^3-5x^2+4x-8 = x(ax^2+bx+c)-2(ax^2+bx+c) + (bx-a)

2x^3-5x^2+4x-8 = ax^3+bx^2+cx-2ax^2-2bx-2c + bx-a

2x^3-5x^2+4x-8 = ax^3+(bx^2+2ax^2) + (-2bx+cx+bx) + (-a-2c)

2x^3-5x^2+4x-8 = ax^3+(b+2a)x^2 + (-b+c)x + (-a-2c)

The x^3 term of the left hand side (LHS) is 2x^3, while the x^3 term of the right hand side (RHS) is ax^3. This must mean a = 2.

The x^2 term of the LHS is -5x^2. The x^2 term of the RHS is (b+2a)x^2

Plugging in a = 2 leads to (b+2a)x^2 turning into (b+4)x^2. Equating the two x^2 coefficients has us get b+4 = -5 solve to b = -1

Now focus on the x terms. The LHS has 4x and the RHS has (-2b+c)x. Plug in b = -1 to get (-b+c)x turn into (c+1)x. Set this equal to 4x and you should find that c = 3

-----------------

In summary, we have:

a = 2

b = -1

c = 3

Note how the last term on the RHS is -a-2c = -2-2(3) = -8 which matches with the last term on the LHS. This helps confirm we have the correct values for a,b,c. Further confirmation would involve polynomial long division.

Answer:

a = 2; b = -1; and c = 3

Step-by-step explanation:

If the quotient of \(2x^3-5x^2+4x-8\)  divided by \(ax^2+bx+c\), gives   \(x-2\)  , with a remainder of \(bx-a\), then the product ( \(ax^2+bx+c\),  ) * ( \(x-2\) ) plus  \(bx-a\)  should equal: \(2x^3-5x^2+4x-8\)

And we can investigate the values of a, b, and c via operating the product and afterwards identifying like terms as shown below:

\((x-2) * (ax^2+bx + c)+bx-a= ax^3 +bx^2+cx-2ax^2-2bx-2c+bx-a=\\=ax^3+(b-2a)x^2+(c-2b+b)x-2c-a=2x^3-5x^2+4x-8\)

And therefore, making the coefficients of like terms equal, we get:

\(a = 2\\b-2a=-5;\,\,and\,\, b=-1\\c-b=4;\,\,and\,c=3\\-2c-a=-6-2=-8\)

Answer:

y = x + 6

Step-by-step explanation:

slope = (10 - 6) / (4 - 0) = 1

pass through (0, 6)

Equation is

y - 6 = 1 * (x - 0)

y = x + 6

OR

x - y + 6 = 0

Given the expression

It can be equivalent to the following

a) By adding the like terms, i.e

b) By adding two like terms and factorizing the common factor, i.e

Hence, the answers are A and D

can you show me a picture then maybe i can help you

The strategy that will help to eliminate the variable and solve the equation easily is (D) multiply the second equation by 3 and add it to the first equation.

So, to cancel the variable that will make the equation easy to solve:
Let,

So, calculate as follows:

This addition of the (2) equation to the (1) equation will give the answer:

Hence, variable x has been canceled.

Therefore, the strategy that will help to eliminate the variable and solve the equation easily is (D) multiply the second equation by 3 and add it to the first equation.

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The length of the longest leg in the right triangle is 5 units

Let x be the length of the shortest leg. Then the other leg has length x + 1, and the hypotenuse has length x + 2.

By the Pythagorean Theorem, we have:

x^2 + (x + 1)^2 = (x + 2)^2

Set x = 3

So, we have

3^2 + (3 + 1)^2 = (3 + 2)^2

Evaluate

25 = 25

The above equation is trie

So, we have

Longest = x + 2

Longest = 3 + 2

Evaluate

Longest = 5

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Answer:

q=9

Step-by-step explanation:

5q+1+44=90

5q+45=90

5q=45

q=9

The possible real zeros for the function will be:

Positive: 4 or 2

Negative: 1

The Descartes rule of sign is technique which helps us  to find no. of real positive/negative and imaginary zeros a function has.

To apply the rule:

1. Arrange the function in the decreasing value of exponents of variables.

2. The no. of positive real zeros of f(x) will be either equal to the number of sign change or less than the number of sign changes by an even number.

3. For real negative real zeros it will be the same but we will check the sign change of f(-x).

now let's look at the function.

f(x) = 6\(x^{7}\) -3\(x^{4}\) + 6\(x^{3}\) + 9\(x^{2}\) - 7x + 4

The sign change here is 4 times so the value of +ve zeros of f(x) will be either 4 or 2.

similarly  let's take f(-x) for negative zeros.

f(x) = 6\((-x)^{7}\) -3\((-x)^{4}\) + 6\((-x)^{3}\) + 9\((-x)^{2}\) - 7(-x) + 4

Here sign change is 1 which cannot be decreased by an even no. so it is the only value.

Therefore the positive and negative zeros of the function will be 2 or 4 and 1 respectively.

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Answer:

see below

Step-by-step explanation:

f(0) = 6/(2*0-3) = -2

f(-3) = 6/(2*-3 -3) =-2/3

Answer: One solution

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

they intersect at 1 point

\(x7 - 2 \: or \: x \leqslant - 3\)

Answer:

Step-by-step explanation:

-lukelaws

did i help?

Answer:

linear

Step-by-step explanation:

A linear equation is in y = mx + b form.

~theLocoCoco

Answer:

linear

Step-by-step explanation:

The surface area of the rectangular prism in this problem is given as follows:

A. 426 m².

The surface area of a rectangular prism of height h, width w and length l is given by:

S = 2(hw + lw + lh).

This means that the area of each rectangular face of the prism is calculated, and then the surface area is given by the sum of all these areas. -> net method.

The dimensions for this problem are given as follows:

5 m, 12 m and 9 m.

Hence the surface area of the prism is given as follows:

S = 2(5 x 12 + 5 x 9 + 12 x 9)

S = 426 m².

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Answer:

x = 15/2

Step-by-step explanation:

The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

To solve this problem, we can use the concept of radioactive decay and the decay factor. Here's how we can calculate the required volume to correct the dose:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = Initial activity * Decay factor

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = Initial activity - 20 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = Remaining activity * Decay factor

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = Desired activity at 9:30 / Remaining activity at 9:30 * Volume at 9:30

Calculate the remaining volume at 9:30:

Remaining volume = Volume at 8 am - Volume withdrawn - Volume accidentally discharged

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume

Let's perform the calculations step by step:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = 180 mCi * 0.841 = 151.38 mCi

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = 180 mCi - 20 mCi = 160 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = 160 mCi * 0.841 = 134.56 mCi

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = (Desired activity at 9:30 / Remaining activity at 9:30) * Volume at 9:30

Volume at 9:30 = Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Volume needed = (20 mCi / 134.56 mCi) * 15 ml = 2.236 ml

Calculate the remaining volume at 9:30:

Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume = 2.236 ml - 15 ml = -12.764 ml

Since the calculated volume to be added is negative, it means that no additional volume is required. The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

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Answer:

7 1/2

Step-by-step explanation:

Convert 7 1/2 to a decimal then multiply it by 1.6 to get 12.00 then add 48 to get 60.

P.S i got it right

Answer:

Recall the following identities

cos2α+sin2α=1

cot2β+1=csc2β

Hence,

cot2(2x)+cos2(2x)+sin2(2x)=cot2(2x)+(cos2(2x)+sin2(2x))=1cot2(2x)+1=csc2(2x)

Answer:

69°

Step-by-step explanation:

To obtain the value of w, we must first obtain the value y as shown in the attached photo.

The value of y can be obtained as follow:

y + (w + 37) = 180 (sum of angle on a straight line)

y + w + 37 = 180

Make y the subject by rearranging

y = 180 – 37 – w

y = 143 – w

Finally, we shall determine the value of w as follow:

w + (w – 32) + y = 180 (sum of angles in a triangle)

y = 143 – w

w + (w – 32) + (143 – w) = 180

w + w – 32 + 143 – w = 180

Rearrange

w + w – w – 32 + 143 = 180

w + 111 = 180

Collect like terms

w = 180 – 111

w = 69°

Therefore, the value of w is 69°

Answer:

x = -30

Step-by-step explanation:

-24 = 6 + x

we'll subtract 6 to get x alone:

-24 - 6 = x

-30 = x

____________

then to check, we plug it back in

-24 = 6 + (-30)

-24 = -24 true! so -30 is right :)

Answer:

-30

Step-by-step explanation:

You can backtrack to find x:

-24-6=-36

-30+6=-24