how to simplify 1.1(x+2)

Answer:

$755

Step-by-step explanation:

You can use the formula c = 60m + 35 for this. c is the cost and m is the number of months. Since a year is 12 months, 60m = 60*12 = 720. Then add the one time fee of $35. 720 + 35 = 755.

The simplest way to perform a division is long division and synthetic division.

What is division?

Division in mathematics is the process of dividing an amount into equal parts. For instance, we may split a group of 20 people into four groups of 5, five groups of 4, and so on.

There are two methods to perform division:

Long division: The mathematical procedure for splitting big numbers into more manageable groups or sections is known as long division. A difficulty can be solved by breaking it down into manageable parts. Dividends, divisors, quotients, and remainders all exist in long divisions.

Synthetic division: In algebra, synthetic division is a technique for manually dividing polynomials according to Euclid, requiring less writing and calculation than long division. Although the approach can be applied to division by any polynomial, it is often taught for division by linear monic polynomials.

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To prove that in a collection of 51 integers there is a subset of 11 where the difference of two of them is a multiple of 5, we can use the Pigeonhole Principle.

Consider the residues of the integers modulo 5, which can take values from 0 to 4. Let's assume that none of the 51 integers has a difference that is a multiple of 5. In other words, no pair of integers in the collection has a difference that leaves a residue of 0 when divided by 5.

Now, we can divide the 51 integers into five subsets based on their residues modulo 5. Each subset will contain the integers with the corresponding residues 0, 1, 2, 3, or 4.

Since we have 51 integers and only five possible residues, by the Pigeonhole Principle, at least one of the subsets must contain at least 51 / 5 = 10 + 1 = 11 integers. Let's assume, without loss of generality, that the subset with residue 0 contains 11 or more integers.

Within this subset, any pair of integers will have a difference that leaves a residue of 0 when divided by 5. Hence, we have found a subset of 11 integers where the difference of two of them is a multiple of 5.

Therefore, we have proved that in a collection of 51 integers, there is always a subset of 11 where the difference of two of them is a multiple of 5.

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A program system that reads two polynomials as linked lists, adds them together, and prints the result as a polynomial stored in a third linked list.

The program system described in the question aims to perform addition on two polynomials represented as linked lists. Each node in the linked list contains the coefficient and exponent of a term in the polynomial.

The program reads two polynomials from the user, stores them as linked lists, and then adds the corresponding terms together. The result is stored in a third linked list, representing the sum of the two polynomials.

To implement this, the program will prompt the user to enter the terms of each polynomial. It will then create linked lists by constructing nodes for each term with the coefficient and exponent.

The program will traverse both linked lists simultaneously, adding the

coefficients of terms with the same exponent and creating new nodes for the resulting terms. The process continues until both linked lists have been traversed completely.

Finally, the program will print the resulting polynomial by traversing the third linked list and displaying each term with its coefficient and exponent. The output will represent the sum of the two input polynomials.

This program system allows for the efficient manipulation of polynomials using linked lists, providing a flexible and dynamic approach to polynomial addition.

By representing polynomials as linked lists, the program can handle polynomials of varying degrees and perform addition accurately. It offers a convenient way to manipulate and perform operations on polynomials in a computational environment.

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Answer:

8 cups

Step-by-step explanation:

So say the canister hold x when it's full. Half is 0.5x

he used 1 + 0.75 = 1.75

Subtract that from 0.5x and get an equation:

0.5x - 1.75 = 2.25

0.5x = 4

x = 8

To stretch a spring 1 ft. from its natural length, a 15 ft-lb work is needed. To stretch a spring 6 in. from its natural length, the required work is 3.75 ft-lb

The work done on a spring is given by the formula:

W = 1/2 . kx²

Where:

k = spring constant

x = spring displacement

From the formula, we know that the work is directly proportional to the square of displacement, or mathematically:

                W ∝ x²

Therefore,

W₁ : W₂ = x₁² : x₂²

Data from the problem

W₁ = 15 ft-lb

x₁ = 1 ft

x₂ = 6 in. = 0.5 ft

Hence,

15 : W₂ = 1² : 0.5²

W₂ = 0.25 x 15 = 3.75 ft-lb

Hence, the required work to stretch the spring 6 in beyond its natural length is 3.75 ft-lb

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Answer:

12 inches

Step-by-step explanation:

Raj tested his new flashlight by shinning it on his bedroom wall the beam of the light can be described by the equation (x^2-2x) + (y^2-4y) - 31=0. how many inches wide is the beam of light on the wall

Solution

Given:

(x^2-2x) + (y^2-4y) - 31=0

By completing the square

(x^2-2x) + (y^2-4y) - 31=0

(x^2-2x+1-1) + (y^2-4y+4-4)-31=0

(x-1)^2 -1 + (y-2)^2 - 4 - 31=0

(x-1)^2 + (y-2)^2 - 1 - 4 - 31=0

(x-1)^2 + (y-2)^2 - 36=0

(x-1)^2 + (y-2)^2=36

Writing the equation in the form: (x-h)^2+(y-k)^2=r^2

(x-1)^2+(y-2)^2=6^2

From the above, r=6

Where,

r=radius

how wide is the diameter ?

radius=6

Diameter= 2 × radius

=2×6

=12 inches

Answer:

12

Step-by-step explanation:

to graph it just scan the equation on photo math!!

There are 24 different ways to arrange the cards in the boxes.

How to arrange the card in the box?

Because there are four boxes and four cards, there are four ways to arrange the first card, three ways to arrange the second card (because one box is already occupied), two ways to arrange the third card, and one method to arrange the fourth card. As a result, the total number of possible ways to arrange the cards in the boxes is:

4 x 3 x 2 x 1 = 24

So there are 24 different ways to arrange the cards in the boxes.

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a) The slope of tangent is 12.

b) The equation of the tangent is given by : y = 12x - 7.

a)The given parabola is y = 6x².

Differentiating with respect to x, we have;

dy/dx = 12x.

The slope of the tangent at point (1, 5) is

dy/dx = 12x = 12(1) = 12.

So, the slope of the tangent is 12.

b)We have the slope of the tangent as 12 and the point (1, 5).

The equation of the tangent is given by

y - y₁ = m(x - x₁).

Substituting y₁ = 5, x₁ = 1, and m = 12, we have;

y - 5 = 12(x - 1).

Expanding the equation, we get;

y = 12x - 7.

f(a)To find f(a), we are given f(x) = 4x² - 3x + 2.

Substituting x = a, we get;

f(a) = 4a² - 3a + 2.

Substituting a = -10, we get;

f(-10) = 4(-10)² - 3(-10) + 2

= 40

2.Estimate the average rate of cell phone growth

(i) from 1998 to 2002:

The change in the number of phone subscribers is 233 - 109 = 124 million.

The change in the number of years is 2002 - 1998 = 4 years.

So, the average rate of cell phone growth from 1998 to 2002 is;

124/4 = 31 million phones/year.

(ii) from 2000 to 2002:

The change in the number of phone subscribers is 233 - 141 = 92 million.

The change in the number of years is 2002 - 2000 = 2 years.

So, the average rate of cell phone growth from 2000 to 2002 is;

92/2 = 46 million phones/year.

(iii) from 1998 to 2000:

The change in the number of phone subscribers is 141 - 109 = 32 million.

The change in the number of years is 2000 - 1998 = 2 years.So, the average rate of cell phone growth from 1998 to 2000 is;

32/2 = 16 million phones/year.

(b) Estimate the instantaneous rate of growth in 2000:

We are given the change in the number of phone subscribers from 1998 to 2000 as 32 million and from 2000 to 2002 as 92 million.

The change in the number of years is 2 years.

Therefore, the average rate of cell phone growth in 2000 is;

(32 + 92)/2 = 62 million phones/year.

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Answer: a) 46 minutes
               b) 10:47

The basic knowledge for this is that 60 minutes = 1 hour

a) Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes

Here you go! Total 46 minutes from Mosley to Bamford.

b) From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.

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The language paradigm that is based on the mathematical concept of a function is the functional programming paradigm.

In functional programming functions are treated as first-class citizens means that they can be passed as arguments to other functions returned as values from functions and assigned to variables.

This is similar to mathematical functions are used in algebra and calculus.

Functional programming emphasizes on the use of pure functions are functions that produce output only based on their input and do not have any side effects.

This helps in writing code that is easier to reason about and test.

Functional programming languages such as Haskell Lisp and OCaml are based on this paradigm and provide built-in support for functions as first-class citizens.

Object-oriented programming (OOP) is based on the concept of objects encapsulate data and behavior.

Imperative programming is based on a sequence of statements that change the state of the program declarative programming focuses on what the program should achieve rather than how to achieve it.

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Given expression:

\(\sf \rightarrow \dfrac{7}{p}=\dfrac{8}{9}\)

cross multiply

\(\sf \rightarrow7(9) = 8(p)\)

multiply variables

\(\sf \rightarrow 63 = 8p\)

exchange sides

\(\sf \rightarrow 8p = 63\)

divide both sides by 8

\(\sf \rightarrow \dfrac{8p}{8} = \dfrac{63}{8}\)

in improper fraction

\(\sf \rightarrow p = \dfrac{63}{8}\)

in mixed fraction

\(\sf \rightarrow p = 7\dfrac{7}{8}\)

in decimals

\(\sf \rightarrow p =7.875\)

Answer:

\(p = 7 \frac{7}{8} \\ \)

Step-by-step explanation:

\( \frac{7}{p} = \frac{8}{9} \\ \)

Use cross multiplication.

\(7 \times 9 = 8 \times p \\ 63 = 8p\)

Divide both sides by 8.

\( \frac{63}{8} = \frac{8p}{8} \\ \\ \frac{63}{8} = p \: \: \: \)

Now we can write the as a mixed number.

\(7 \frac{7}{8} = p\)

Life in the neighborhood depicted in the film "Los Olvidados" is characterized by challenging economic and social conditions.

The neighborhood in "Los Olvidados" is portrayed as a poverty-stricken area where the residents struggle to make ends meet. The film explores the lives of marginalized individuals most particularly young boys, who are caught in a cycle of poverty, violence, and neglect.

The economic conditions in the neighborhood are harsh, with limited opportunities for employment and a lack of access to basic necessities. As a result, the residents are often forced into criminal activities to survive leading to a high level of violence and crime within the community.

Moreover, the social conditions exacerbate the challenges faced by the neighborhood. There is a sense of abandonment and neglect from the government and wider society with little support or resources available to address the issues faced by the residents.

Full question:

Describes life in the neighborhood that takes place in the film Los Olvidados by Luis Buñuel, taking into account their economic and social conditions through the different activities carried out by the neighborhoods.

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Answer:

It's the 2nd one : -30\(a^{5}\)b + 12\(a^{4} b^{3}\) + 16\(a^{3} b^{2}\) - 4\(a^{2} b^{4}\) - 2a\(b^{3}\)

Twice a number (2x) increased by 4 is at least 10 more than the number (x) 2x + 4 ≥ x + 102x - x ≥ 10 - 42x ≥ 6x ≥ 3, Thus, the solution is x ≥ 3

Problem Twice a number increased by 4 is at least 10 more than the number

Solution: Let's define a variable x.

Let the number be x

According to the problem statement,

Twice a number (2x) increased by 4 is at least 10 more than the number (x) 2x + 4 ≥ x + 102x - x ≥ 10 - 42x ≥ 6x ≥ 3

Thus, the solution is x ≥ 3

Let's check whether our solution is correct or not.

Taking x = 3 in the inequality 2x + 4 ≥ x + 102(3) + 4 ≥ (3) + 104 + 6 ≥ 106 ≥ 10

Yes, the inequality holds true.

Therefore, our solution is correct.

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Answer:

7  13/24 miles

Step-by-step explanation:

First reduce 11/6 into 1 5/6

Then add them all together to get 7  13/24

Answer:

The total would be 6 7/8 miles.

Step-by-step explanation:

Hope this helps :)

Using the variable x to represent the unknown number and knowing that 75% is equivalent to the decimal number 0.75, we can write the following inequation:

Then, solving the inequation for x, we have:

Solving the equation with the values of x to get y we get the table

x                      1                      2                      3                      4

y                     22                   40                   58                    76

Here we are given to draw a table for solutions for the equation

y = 18x + 4

The values of x are given to be x = 1, 2, 3 and 4,

For this problem, we need to solve the given equation by replacing x with the given values instead. This will give us a definite value for y. Then we will make a table with these values.

The first value of x is 1. Putting this value we get

y = (18 X 1) + 4

or, y = 18 + 4

or, y = 22

The next value of x is 2. Putting this value we get

y = (18 X 2) + 4

or, y = 36 + 4

or, y = 40

The next value of x is 3. Putting this value we get

y = (18 X 3) + 4

or, y = 54 + 4

or, y = 58

The next value of x is 4. Putting this value we get

y = (18 X 4) + 4

or, y = 72 + 4

or, y = 76

Hence we get the table,

x                      1                      2                      3                      4

y                     22                   40                   58                    76

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Answer:

Reflection over the y-axis.

Step-by-step explanation:

All the x values will change sign so its over the yaxis

Answer:

a. The graph will be reflected over the y-axis

Step-by-step explanation:

When a function is reflected over the y-axis, the x-coordinates are divded by -1, and then the new points will become reflections of the y-axis. Because x was changed to -x in this problem, we know that the graph was relfected across the y-axis.

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The diameter of the peach increased by approximately how many times after James watered it?The diameter of the peach was initially 98 mm.

After watering it with a magical solution, it grew to 188,869 mm. To find out how many times larger the diameter of the peach became after James watered it, divide the final diameter by the initial diameter. Then, round the answer to the nearest whole number.So,Long Answer:The diameter of the peach initially was 98 mm.Diameter of the peach after watering it with a magical solution is 188,869 mm.

To determine how many times larger the diameter of the peach became after James watered it, divide the final diameter by the initial diameter.Let's divide the final diameter by the initial diameter.

188,869/98=1929.88775510204

After dividing, we get

1929.88775510204. Therefore, the diameter of the peach increased by approximately 1930 times (rounding to the nearest whole number) after James watered it.

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The simplex method is a widely used algorithm for solving linear programming problems, which involve optimizing a linear objective function subject to linear constraints. False.

However, the simplex method does not explicitly require the variables to be nonnegative in order to find a solution.

The simplex method starts with an initial feasible solution and iteratively improves it by moving along the edges of the feasible region, ultimately reaching the optimal solution. During the iterations, the variables can take any real values, including negative values.

That being said, some variations of the simplex method, such as the dual simplex method, have been developed specifically to handle problems with nonnegativity constraints. These variations can be used when variables are required to be nonnegative.

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Answer:

8.8 grams

...................

The required 88 Decigrams equals 8.8 grams.

Given that,
To determine 88 Decigrams equals 8.8.

All over the world, most things are in use as of common quantity, so people all over the world agree that they have to follow a common system of measurement and that the common system of measurement is called standard measurement.

Fraction is defined as the number of compositions that constitutes the Whole.

here,
10 decigram = 1 gram
88 decigram = 8.8 gram

Thus, the required 88 Decigrams equals 8.8 grams.

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Answer & Step-by-step explanation:

To find if they have a constant of proportionality of 12, use the following:

\(\frac{y}{x}=12\)

Divide y by the x value (x,y), and if the remaining equation is true, then that table has a constant of proportionality of 12.*

:Done

*Make sure you check all the values in a table. Sometimes only the first values will have k=12, while the others don't.

**The constant of proportionality is represented by k.

Answer:

A for Khan Academy :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: To fill the whole bucket, it will take 64 seconds so the remaining time is 40 seconds

Step-by-step explanation: As we are given 3/8 th part of the bucket is filled in 24 seconds. So by simply applying the unitary method we can say -

3/8 th part -----> 24 seconds

To fill the whole bucket multiply both sides by 8/3 in order to make the 1 unit of the bucket on the L.H.S, we get

1 bucket ----> 64 seconds.

The remaining times as it already passes 24 seconds and 3/8 th part of the bucket is filled, 64-24 seconds i.e 40 seconds is remaining in which bucket is full.

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The pairwise comparisons that need to be made for this anova result will be b.3

In order to determine the number of pairwise comparisons needed for a one-way between-subjects ANOVA with three groups, we can use the formula:

N = (k * (k-1)) / 2

Where N represents the number of pairwise comparisons and k represents the number of groups. In this case, k = 3.

Plugging in the values:

N = (3 * (3-1)) / 2

N = (3 * 2) / 2

N = 6 / 2

N = 3

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