how to put 1/2 and 3/4 as a pair of fractions with a common denominator

Answer:

Simply by using a protractor.

Step-by-step explanation:

Place the center of the protractor on the origin of the angle. The distance between the two lines is the angle in degrees. Read it on the protractor. You can also do basic arithmetics if other angles are given. For instance 180 degrees- 30 degrees = 150 degrees.

Hope it helped pls mark as brainliest.

Change the amount of teachers to be 10.

The expected value is the long-term average outcome of a random variable. It is calculated by multiplying each possible outcome by its probability and summing them up. In simpler terms, it represents the average value we expect to get over many trials.

The expected value is a concept in probability and statistics that represents the long-term average outcome of a random variable. It is also known as the mean or average. To calculate the expected value, we multiply each possible outcome by its probability and sum them up.

For example, let's say we have a fair six-sided die. The possible outcomes are numbers 1 to 6, each with a probability of 1/6. To find the expected value, we multiply each outcome by its probability:

Summing up these values gives us:

1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6 = 21/6 = 3.5

Therefore, the expected value of rolling a fair six-sided die is 3.5. This means that if we roll the die many times, the average outcome will be close to 3.5.

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Answer:

WHeres the questionnn???????

Step-by-step explanation:

Answer:

(C) 2 and 50

Step-by-step explanation:

Answer:Objective: Solve systems of equations with three variables using addition/elimination.

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve u

Step-by-step explanation:

sorry my answer was wrong

The solution of the system of equations f(x) = 2^x + 1 and g(x) = 3^x is x = 1

From the question, we have the following parameters that can be used in our computation:

f(x) = 2^x + 1

g(x) = 3^x

The above expression is a system of exponential equations

We are required to solve by graph

That implies that we graph the equations in the system on the same plane and write out ordered pairs from the point of intersection of the equations in the system

Next, we plot the graph

See attachment for the graph of the equations

The ordered pairs of the intersection point is (1, 3)

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The area of the sandbox whose base is 3.5 meter and height is 2.4 meter is 4.2 m².

Given:

Base = 3.5 m

Height = 2.4 m

First, the area of the sandbox formula:

Area = 1/2 x base x height.

Next,  substitute b = 3.5 meters and h = 2.4 meters.

Area = 1/2 * (3.5) * (2.4).

Now, simplify by multiplying 1/2, 2.4, and 3.5.

Area = 1/2 x 2.4 x 3.5

Area = 4.2 square meters.

Thus, The area of the sandbox is 4.2 m².

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The question attached here seems to be incomplete, the complete question is:

Lokota wants to build a sandbox for his little brother. Determine the amount of sand he needs by finding the area of the sandbox. Use the drop-down menus to complete the statements.

First, write the formula: A = 1/2 bh
Next, use parentheses when you substitute __ for b and __ for h.

Now, simplify by ___ 1/2, 2.4, and 3.5.

The area of the sandbox is ___ m²

Answer:

14

Step-by-step explanation:

An inscribed angle is formed by two chords of a circle that intersect at a vertex located on the circle.

The angle itself is formed by the two sides of the angle, which are the line segments connecting the vertex to the endpoints of the chords. The property that makes inscribed angles interesting is that the measure of an inscribed angle is half the measure of the intercepted arc on the circle.

This relationship holds true for any inscribed angle in a circle, making it a useful concept in geometry for solving problems involving angles, arcs, and circles.

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The equation which represents total pay P and the number of copies sold N is P = 2300 + 90N and the total pay for 22 copies sells will be $4280.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Total pay = base salary + additional

Total pay = base salary + number of copies × per copy price

P = 2300 + N × 90

P = 2300 + 90N

Now for 22 copies

P = 2300 + 90(22) = $4280

Hence, the equation which represents total pay P and the number of copies sold N is P = 2300 + 90N and the total pay for 22 copies sells will be $4280.

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Based on the given information, Jolene's behavior is suggestive of obsessive-compulsive disorder (OCD).

Obsessive-compulsive disorder(OCD) is a mental health condition characterized by the presence of obsessions and/or compulsions. Obsessions are intrusive and unwanted thoughts, images, or urges that cause distress and anxiety.

In Jolene's case, her obsession revolves around the fear of miscounting the cracks in the sidewalk. Compulsions, on the other hand, are repetitive behaviors or mental acts performed in response to obsessions, with the goal of reducing anxiety or preventing a feared outcome.

Jolene's compulsion is the urge to return home to recount the cracks, driven by her fear of having miscounted them.

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Answer:

The answer to your question is 07 cups

Step-by-step explanation:

1 ounce to cups = 0.125

56oz x 0.125 = 7

I hope this helps and have a wonderful day!

a) Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

b) The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

(a) To show that E is compact, we need to show that any open cover of E has a finite subcover. Let {U_i} be an open cover of E. Since E is closed in F, its complement F\E is open in F. Thus, {U_i} and F\ E together form an open cover of F. Since F is compact, there exists a finite subcover {U_i1, U_i2, ..., U_in, F\ E}. Since E is closed, its complement F\ E is contained in F, so the intersection of {U_i1, U_i2, ..., U_in} with E is still a finite subcover of E. Thus, E is compact.

(b) Let K1, K2, ..., Kn be a finite collection of compact subsets of S. Let {U_i} be an open cover of their union K= K1∪ K2 ∪ ... ∪ Kn. Then each Ki is contained in K, so {U_i} is also an open cover of each Ki. Since each Ki is compact, there exists a finite subcover {U_i1, U_i2, ..., U_ik_i} of {U_i} for each Ki. Thus, we have a finite collection of sets {U_i1, U_i2, ..., U_ik_1}, {U_i1, U_i2, ..., U_ik_2}, ..., {U_i1, U_i2, ..., U_ik_n} that covers K1, K2, ..., Kn respectively. The union of all these finite subcovers is a finite subcover of {U_i} that covers K, showing that K is compact.

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Answer:

the answer is 208.6

Step-by-step explanation: I don't have any work to show

As x gets closer to infinity, the ratio f'(x) / g'(x) approaches zero. We can deduce that ex xn for any integer n > 0 since the ratio is getting close to being zero.

To show that ex ≫ xn for any integer n > 0, we can examine the ratio of their derivatives. Let's find the derivative of dn/dx^n.

For any positive integer n, dn/dx^n represents the nth derivative of the function d(x^n)/dx^n. We can find this derivative using the power rule repeatedly.

The power rule states that if we have a function f(x) = x^n, where n is a constant, then its derivative f'(x) is given by:

f'(x) = n * x^(n-1)

Using the power rule repeatedly, we can find the nth derivative of x^n:

(d^n)/(dx^n)(x^n) = n * (n-1) * (n-2) * ... * 2 * 1 * x^(n-n)  = n!

Now let's compare the ratio of the derivatives:

f(x) = ex

g(x) = xn

f'(x) = d(ex)/dx = ex

g'(x) = d(xn)/dx = nx^(n-1)

Taking the ratio

f'(x) / g'(x) = ex / (nx^(n-1))

We want to show that this ratio approaches infinity as x approaches infinity.

Taking the limit as x approaches infinity:

lim(x->∞) (ex / (nx^(n-1)))

We can rewrite this limit by dividing the numerator and denominator by x^(n-1):

lim(x->∞) (e / n) * (x / x^(n-1))

lim(x->∞) (e / n) * (1 / x^(n-2))

As x approaches infinity, the term (1 / x^(n-2)) approaches 0 since the exponent is positive.

Therefore, the limit becomes:

lim(x->∞) (e / n) * 0 = 0

This means that the ratio f'(x) / g'(x) approaches 0 as x approaches infinity.

Since the ratio approaches 0, we can conclude that ex ≫ xn for any integer n > 0.

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The attached graph describes the relationship between the amount of money raised and the number of students who attend the dance

The parameters that will help us to determine the graph are

Decorations for the dance cost $80,

The club is charging $10 per student that attends

This forms a linear equation:

y = mx + b

y = 10x - 80

Plotting the graph:

That is the full solution of the equation

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The probability that both Event A (the first die is 4 or less) and Event B (the second die is even) will occur is 1/3.

To find the probability that both Event A and Event B will occur, we need to calculate the individual probabilities of each event and then multiply them together.

Event A: The first die is 4 or less.

There are 6 possible outcomes for the first die (numbers 1 to 6), and out of those, 4 outcomes (numbers 1, 2, 3, and 4) satisfy the condition. Therefore, the probability of Event A is 4/6, which simplifies to 2/3.

Event B: The second die is even.

For a fair six-sided die, there are 3 even numbers (2, 4, and 6) out of a total of 6 possible outcomes. Therefore, the probability of Event B is 3/6, which simplifies to 1/2.

To find the probability that both events will occur, we multiply the probabilities of Event A and Event B:

Probability of both events occurring = Probability of Event A * Probability of Event B

P = (2/3) * (1/2)

P = 2/6

P = 1/3

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The correct option a. They are easier to buy and sell than other forms of investment, describes the relatively liquid.

A type of debt fund known as "liquid funds" mostly invests in higher financing instruments with 91-day maturities.

Thus,

Liquid assets are those that are challenging to buy, sell, or convert into cash.

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The speed of the plane in still air is 304.76 mph and the speed of the wind is 38.09 mph.

The speed formula can be defined as the rate at which an object covers some distance. Speed can be measured as the distance travelled by a body in a given period of time. The SI unit of speed is m/s.

Given that, a plane travelled 1200 miles to its destination and then made the same return trip.

Let x be the speed of the plane and y be the speed of the wind, both in miles per hour.

On its way to the destination, the plane takes 3.5 hours to travel 1200 miles. So the speed of the plane along with the tailwind is

1200/3.5

= 342.85 mph

Then, x+y =342.85 -------(I)

While flying back, it takes 4.5 hours to cover the same distance. So the speed of the plane against the headwind is

1200/4.5

= 266.67

So, x-y = 266.67-------(II)

Add equation (I) and (II), we get

2x=342.85+266.67

2x=609.52

x=304.76 mph

Substitute x=304.76 in equation (I), we get

y=38.09 mph

Therefore, the speed of the plane in still air is 304.76 mph and the speed of the wind is 38.09 mph.

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Answer:

Center  = (1,2)  radius = 2

Step-by-step explanation:

I used Demos to graph the circle.

Then I added two line to find the center of the circle

The radius is 2

The length of each piece of wood is 0.725 feet.

We are given that the Length= 3.5feet

Now,

This is a word problem that can be solved by using algebra and arithmetic.

Part A: Let x be the length of each of the four pieces of wood he cut. Then, according to the problem, we have:

4x + 0.6 = 3.5

This is the equation that could be used to determine the length of each piece of wood.

Part B: We know the equation from part A is correct because it represents the total length of the wood before and after cutting. The left side of the equation is the sum of the lengths of the four pieces of wood and the leftover piece of wood. The right side of the equation is the original length of the wood. Since cutting does not change the total length of the wood, these two sides must be equal.

Part C: To solve the equation from part A, we need to isolate x by using inverse operations. We get:

4x + 0.6 = 3.5 4x = 3.5 - 0.6 (subtract 0.6 from both sides) 4x = 2.9 x = 2.9/4 (divide both sides by 4) x = 0.725

Therefore, by the algebra the answer will be 0.725 feet.

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The function f is defined as a mathematical rule that relates an input value x to an output value, which is determined by the equation f(x) = sqrt(25-x^2). In this case, the function takes an input value x and returns the square root of the difference between 25 and x squared. This function is defined for all values of x between -5 and 5, as any value outside of this range would result in a negative number under the square root function, which is not defined in real numbers.


The function f is defined by the equation f(x) = sqrt(25 - x^2). To work with this function, follow these steps:

1. Identify the input variable x, which is within the parentheses f(x).
2. Substitute the value of x into the equation, replacing the x in (25 - x^2).
3. Calculate the result of the expression inside the square root, (25 - x^2).
4. Finally, take the square root of the calculated result to find the output value f(x).

Remember that this function has a domain restriction, as the value inside the square root must be greater than or equal to zero. Therefore, the domain of the function f is -5 ≤ x ≤ 5.

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(a)54 (b)Thus, \(\(\left|2A\right|=48\)\) (c) both matrices A and B are nonsingular, or invertible, or non-singular.

Let \(A\) and \(B\) be square matrices of order 3 such that \(\left|A\right|=6\) and \(\left|B\right|=9\). We have to find: (a) Find \(\left|AB\right|\)(b) Find \(\left|2A\right|\).(c) Are A and B singular or nonsingular? Explain.

(a) We know that\(\(\left|AB\right|=\left|A\right|\cdot\left|B\right|\)\).So, we have\(\(\left|AB\right|=6\cdot9=54\)\)

(b) We know that if a matrix \(A\) is multiplied by a scalar \(k\), then its determinant becomes \(k^n\) times its original determinant. So,\\([\left|2A\right|=2^n\cdot\left|A\right|=2^3\cdot6=48\]\). Thus, \(\(\left|2A\right|=48\)\)

(c) If the determinant of a matrix is 0, the matrix is said to be singular. If the determinant is nonzero, the matrix is nonsingular. So, from the given information we know that\(\(\left|A\right|\neq0\) and \(\left|B\right|\neq0\)\).

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The sample mean for the freshmen reading comprehension test is \(\bar{x}\) = 10.22.

To determine if this sample is significantly different from the population mean μ = 12, a one-sample t-test can be conducted with a significance level of α = .05.

Using the given sample scores, the t-value can be calculated as t = (\(\bar{x}\) - μ) / (s / √n), where s is the sample standard deviation and n is the sample size.

For the given sample, the calculated t-value is t ≈ -1.86.

The critical t-value can be found from the t-distribution table or using statistical software, considering the degrees of freedom (df = n - 1). For α = .05 and df = 8, the critical t-value is approximately t_crit = -2.31 (one-tailed test).

Since the calculated t-value (-1.86) is greater than the critical t-value (-2.31), we fail to reject the null hypothesis. There is not enough evidence to conclude that the sample mean is significantly different from the population mean.

Regarding effect size, Cohen's d is an appropriate measure. It can be calculated as d = (\(\bar{x}\) - μ) / s, where s is the pooled standard deviation. Cohen's d measures the standardized difference between the means. In this case, the calculated Cohen's d is approximately -0.73, indicating a small effect size.

Therefore, the average score for the freshmen reading comprehension test is 10.22.

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Complete question below:

A sample of freshmen takes a reading comprehension test and their scores are summarized below. If the mean for the general population on this test is μ = 12, can you conclude that this sample is significantly different from the population. Test with α = .05. Include an effect size measure you find appropriate and explain why you chose what you calculated - you determine the tail and why.

Sample Scores: 16, 8, 8, 6, 9, 11, 13, 9, 10

Answer:

After 2 1/3 hours.

Step-by-step explanation:

For this you have to calculate how much hours is 1/3 of 7 hours. The word 'of' implies a multiplication function.

1/3 * 7 = 7/3 = 2 1/3

Answer:

Step-by-step explanation:

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

=  - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

=  6z

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

=  √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

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