how should water be added to a concrete mix

Because it encourages (d) the reuse of previously written code, inheritance is a useful feature of a language.

Classes can inherit behavior and properties from their parent classes thanks to the powerful programming idea of inheritance. It has the potential to simplify software development, reduce redundant code, and improve code readability when used correctly. Notwithstanding, when utilized inaccurately, legacy can prompt code that is challenging to comprehend, keep up with, and adjust.

Sadly, programming frequently abuses inheritance. developers relying on it as a panacea without taking into account its potential drawbacks. Over time, this can lead to code that is cumbersome or rigid, making it difficult to work with. As a result, developers need to know when and how to use inheritance correctly. in order to write code that is simple to use, easy to maintain, and efficient.

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Answer:

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

Explanation:

Given the data in the question;

Vs = 10∠30°V   { peak value }

V"s\(_{rms\) = 10/√2 ∠30° V

resonance freq w₀ = 10³ rad/s

Average Power at resonance Power\(_{avg\)  = 2.5 W

Q = 5

values of R, L, and C = ?

We know that;

Power\(_{avg\) = |V"s\(_{rms\)|² / R

{ resonance circuit is purely resistive }

we substitute

2.5 = (10/√2)² × 1/R

2.5 = 50 × 1/R

R = 50 / 2.5

R = 20Ω

We also know that;

Q = w₀L / R

we substitute

5 = ( 10³ × L ) / 20

5 × 20 = 10³ × L

100 = 10³ × L

L = 100 / 10³

L = 0.1 H

Also;

w₀ = 1 / √LC

square both side

w₀² = 1 / LC

w₀²LC = 1

C = 1 / w₀²L

we substitute

C = 1 / [ (10³)² × 0.1 ]

C = 1 / [ 1000000 × 0.1 ]

C = 1 / [ 100000 ]

C = 0.00001 ≈ 1 × 10⁻⁵ F

Therefore;

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

Solution :

It is given that :

Thermal coefficient = 0.0045/K

Ambient temperature, \($T_a = 25 - 40^\circ$\)

air velocity, v = 0-5 m/s

Solar radiation, \($G= 400-100 \ W/m^2$\)

\($P=50 \ W$\)

Model calculations :

Cell temperature (\($T_c$\))

\($T_c = T_a + \left(\frac{0.25}{5.7+3.8 \ v_w}\right) G$\)

where \($ v_w - v_a = $\) wind speed / air speed

∴ \($T_c = 2 \pi + \left(\frac{0.25}{5.7+3.8 \times 1}\right) \times 400$\)

   \($T_c = 35.526 ^\circ$\)

\($\Delta T = T_c -25$\)

      = 35.526 - 25

      = 10.526 K

Thermal coefficient = 0.0045 x 10.526

                                = 0.04737

Pv power = \($(1 -C_T) \times P \times \frac{G}{1000}$\)

                \($=(1 -0.04737) \times 50 \times \frac{400}{1000}$\)

                = 17.0526 W

To make z the subject in the expression 7 = ax + b / (zx + d), we rearrange the equation as z = (b - 7d + adx) / (7x - ax).

To make z the subject of the given expression, we can rearrange the equation as follows:

7 = ax + b / (zx + d)

First, we'll isolate the term containing z by subtracting ax from both sides:

7 - ax = b / (zx + d)

Next, we'll multiply both sides by (zx + d) to eliminate the denominator:

(7 - ax)(zx + d) = b

Expanding the brackets:

7zx + 7d - axz - adx = b

Rearranging the terms:

7zx - axz = b - 7d + adx

Finally, factoring out z:

z(7x - ax) = b - 7d + adx

Dividing both sides by (7x - ax):

z = (b - 7d + adx) / (7x - ax)

Therefore, z is the subject of the equation.

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a. Signal conditioning circuits are crucial in ensuring accurate and reliable measurements by preparing the sensor output signal for further processing. Amplification, filtering, linearization, and conversion are four key processes performed by these circuits.

b. The three essential elements of a Date Acquisition System are sensors, Signal Conditioning, and data converter.

a. Signal conditioning circuits perform several processes to enhance the sensor output signal. Four of these processes are:

1. Amplification: Amplification is used to increase the amplitude of the sensor output signal. This is necessary when the sensor generates a weak signal that needs to be strengthened for further processing. Amplifiers such as operational amplifiers (op-amps) are commonly used in signal conditioning circuits to achieve this.

2. Filtering: Filtering is employed to remove unwanted noise and interference from the sensor output signal. This process ensures that the signal contains only the relevant information, improving the accuracy and reliability of the measurements. Different types of filters, such as low-pass, high-pass, band-pass, and notch filters, can be used based on the specific requirements of the measurement system.

3. Linearization: Some sensors exhibit non-linear behavior, meaning their output is not directly proportional to the input. In such cases, linearization techniques are applied in signal conditioning circuits to convert the non-linear sensor output into a linear relationship with the input. This enables easier interpretation and analysis of the measurement data.

4. Conversion: Signal conditioning circuits may also include analog-to-digital converters (ADCs) to convert the analog sensor output signal into digital form. This digital representation allows for easier processing, storage, and transmission of the data within the measurement system and to external devices.

b. The three essential elements of a Data Acquisition System (DAS) are:

1. Sensors/Transducers: Sensors or transducers are the primary components of a DAS that capture physical phenomena and convert them into electrical signals. These sensors can measure various parameters such as temperature, pressure, humidity, flow rate, and many others. They act as the interface between the physical world and the digital system, providing the necessary input data for measurement and analysis.

2. Signal Conditioning: Signal conditioning is a crucial step in a DAS that involves processing and modifying the raw electrical signals obtained from the sensors. This process includes amplification, filtering, linearization, and conversion, as discussed in the previous answer. Signal conditioning circuits enhance the quality of the signals, removing noise and ensuring compatibility with the next stages of the system.

3. Data Converter: The data converter is responsible for converting the analog signals from the signal conditioning stage into a digital format that can be processed and stored by a computer or other digital devices. Analog-to-digital converters (ADCs) are commonly used to perform this conversion. The digital data allows for easy manipulation, analysis, and storage, facilitating further processing and interpretation.

These three elements work together in a Data Acquisition System to capture, condition, and convert physical data into a digital format for analysis and interpretation. Sensors capture the physical phenomena, signal conditioning circuits enhance the signals, and data converters convert the signals into a digital format. This enables the acquisition, storage, and analysis of data in various applications such as scientific research, industrial monitoring, and environmental sensing.

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The velocity at d is given as 0.518

r / sin 30 = 0.4 / sin 45

r = 0.546 m

From here we have to find the value of vB =

wAB * AM = 1 m / s

angular velocity of BC

= Vb / r = 1.83

Vd - = WBC / r

= 0.518

velocity at C = 0.368

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The flap is used to lift the aircraft in the air as it provides them with balance.

The flaps' main function is to produce additional pull during decreased airspeed, therefore allowing the aircraft to fly at much low rpm with a reduced chance of crashing.

The flap is used to lift the aircraft in the air as it provides them with balance.

They are used for dragging the aircraft as it provides them with a certain amount of height with increases and lowers it.

The takeoff speed is slowed so relatedly to the flap as the change in the structure for the dynamic effect of the airspeed.

Flap reduces the takeoff distance as a smaller speed is being created, which reduces the feed with the coefficient of lift.

The class have a chamber it provides some hollow stairs through which they can store the good and services also it is sometimes used for oil storage.

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2.1) The support reactions are calculated now: \(A_{x} = 10\,kN\), \(A_{y} = -10\,kN\), \(B_{y} = 30\,kN\).

2.2) The member CD is on tensile load and the member BC is on compressive load. \(F_{BC} \approx 28.284\,kN\), \(F_{CD} = 20\,kN\)

The dynamic situation of a mechanical system whose geometry cannot be neglected is described by Newton's laws and D'Alembert's principle. A planar system in equilibrium is described by the following formulae:

\(\sum F_{x} = 0\)     (1)

\(\sum F_{y} = 0\)     (2)

\(\sum M = 0\)     (3)

2.1) The support reactions can be found by assuming that the truss is a rigid solid:

\(\sum F_{x} = A_{x} - F = 0\)    (4)

\(A_{x} = F\)

\(A_{x} = 10\,kN\)

\(\sum M_{A} = F\cdot r_{BD} - G \cdot (r_{AB}+r_{CD}) + B_{y}\cdot r_{AB} = 0\)     (5)

\(B_{y} = \frac{G\cdot (r_{AB}+r_{CD})-F\cdot r_{BD}}{r_{AB}}\)

\(B_{y} =\frac{(20\,kN)\cdot (8\,m)-(10\,kN)\cdot (4\,m)}{4 \,m}\)

\(B_{y} = 30\,kN\)

\(\sum F_{y} = A_{y} + B_{y} - G = 0\)     (6)

\(A_{y} = G - B_{y}\)

\(A_{y} = 20\,kN - 30\,kN\)

\(A_{y} = -10\,kN\)

Note - The negative sign means that the real direction of the component is antiparallel to the assumed one.

2.2) If the entire system is at equilibrium, then every part of the system must be also at equilibrium. The joint is considered a particle and thus the D'Alembert's principle is not necessary. The member CD is on tensile load and the member BC is on compressive load.

\(\sum F_{x} = F_{BC} \cdot \cos 45^{\circ} - F_{CD} = 0\)     (7)

\(\sum F_{y} = -G + F_{BC}\cdot \sin 45^{\circ} = 0\)     (8)

By (8):

\(F_{BC} = \frac{G}{\sin 45^{\circ}}\)

\(F_{BC} \approx 28.284\,kN\)

By (7):

\(F_{CD} = F_{BC}\cdot \cos 45^{\circ}\)

\(F_{CD} = 20\,kN\)

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Yes, the order of the letters in the string does affect the result of a simple string hash function that sums the ASCII values of the letters.

In a simple string hash function that sums the ASCII values of the letters, the algorithm calculates the hash value by iterating over each character in the string, converting it to its ASCII value, and adding it to a running sum.

The order in which the characters appear in the string directly influences the resulting sum.

For example, consider two strings "abc" and "cba." In the "abc" string, the ASCII values of 'a,' 'b,' and 'c' are summed in that order, resulting in a specific hash value.

On the other hand, in the "cba" string, the ASCII values of 'c,' 'b,' and 'a' are summed in reverse order, resulting in a different hash value.

Thus, even though the two strings contain the same characters, the different order of the letters leads to distinct hash values.

This demonstrates that the order of the letters in the string affects the result of the simple string hash function that sums the ASCII values.

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Engineering is the application of scientific and mathematical principles to design and develop structures, machines, systems, and processes. Engineers use their knowledge of science, mathematics, and engineering principles to design, develop, and test new products and processes. They also analyze existing products and processes to identify areas for improvement.

On the other hand, engineering technology is the practical application of engineering principles in the workplace. Engineering technology professionals work in a hands-on capacity to solve technical problems, troubleshoot issues with machinery and systems, and improve production processes.

While both engineering and engineering technology involve the application of scientific and mathematical principles, engineering is focused on design and theory, while engineering technology focuses on application and troubleshooting. Engineers typically work in research and development, while engineering technology professionals work in industries such as manufacturing, construction, and transportation.

Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Answer:

Phuong works on a research project and creates a report for her boss.

Answer:

B. Bart types information into a computer database.

C. Phuong works on a research project and creates a report for her boss.

D. Anton answers phone calls and greets guests who visit a company.

Answer:

a) 4 hectómetros cuadrados equivalen a 400 decámetros cuadrados.

b) 21345 centímetros cuadrados equivalen a 2,135 metros cuadrados.

c) 0,592 kilómetros cuadrados equivalen a 592000 metros cuadrados.

d) 0,102 metros cuadrados equivalen a 1020 centímetros cuadrados.  

e) 23911 kilómetros cuadrados equivalen 2391100 hectómetros cuadrados.

Explanation:

a) 4 hectómetros cuadrados a decámetros cuadrados:

Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un hectómetro cuadrado equivale a 100 decámetros cuadradps. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:

\(x = 4\,Hm^{2}\times\frac{100\,Dm^{2}}{1\,Hm^{2}}\)

\(x = 400\,Dm^{2}\)

4 hectómetros cuadrados equivalen a 400 decámetros cuadrados.

b) 21345 centímetros cuadrados a metros cuadrados:

Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un metro cuadrado equivale a 10000 centímetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:

\(x = 21345\,cm^{2}\times \frac{1\,m^{2}}{10000\,cm^{2}}\)

\(x = 2,135\,m^{2}\)

21345 centímetros cuadrados equivalen a 2,135 metros cuadrados.

c) 0,592 kilómetros cuadrados a metros cuadrados:

Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un kilómetro cuadrado equivale a 1000000 metros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:

\(x = 0,592\,km^{2}\times \frac{1000000\,m^{2}}{1\,km^{2}}\)

\(x = 592000\,m^{2}\)

0,592 kilómetros cuadrados equivalen a 592000 metros cuadrados.

d) 0,102 metros cuadrados a centímetros cuadrados:

Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un metro cuadrado equivale a 10000 centímetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:

\(x = 0,102\,m^{2}\times \frac{10000\,cm^{2}}{1\,m^{2}}\)

\(x = 1020\,cm^{2}\)

0,102 metros cuadrados equivalen a 1020 centímetros cuadrados.

e) 23911 kilómetros cuadrados a hectómetros cuadrados:

Según las unidades de área y sus escalas utilizadas por el Sistema Internacional de Pesos y Medidas, un kilómetro cuadrado equivale a 100 hectómetros cuadrados. Entonces, obtenemos el dato equivalente por la siguiente regla de tres simple:

\(x = 23911\,km^{2}\times \frac{100\,Hm^{2}}{1\,km^{2}}\)

\(x = 2391100\,Hm^{2}\)

23911 kilómetros cuadrados equivalen 2391100 hectómetros cuadrados.

Answer:

Bluetooth is a slow wireless technology used to connect devices within a radius of about 30 feet. While Bluetooth technology is amazing, there are lots of bugs involved with Bluetooth devices, and there is still lots to be discovered in this area of tech.

D be the minimum required diameter of the shaft. A solid steel shaft turns freely in bearings at points A and E. Therefore, the shaft must be in equilibrium condition. Thus, we have:ΣT = 0, where ΣT is the sum of all the torques. Torque T2 at C is clockwise. Torque T1 at B is counter clock wise.Torque T3 at D is clockwise.

Therefore\(,ΣT = -T1 + T2 - T3 = 0⇒ -200 + 325 - 125 = 0⇒ 0 = 0\)The shaft is in equilibrium condition. our assumption is valid.
The length of BC is LBC = 20 in.

Therefore, using the above relation, we have:

\(τ/r = T/JL⇒ τ/r = 200/(πd⁴/32 × 20) [since J = πd⁴/32]⇒ τ = 32 × 200d⁴/(π × 20)⇒ τ = 320d⁴/π\)

Using the value of ta, we get:

\(τ ≤ ta⇒ 320d⁴/π ≤ 56×103⇒ d⁴ ≤ (56×103 × π)/320⇒ d ≤ (56×103 × π/320)1/4d ≤ 1.632\)

The torque acting on CD is T3 = 125 lb-ft.

The length of CD is LCD = 15 in.

\(τ/r = T/JL⇒ τ/r = 125/(πd⁴/32 × 15)\) [since \(J = πd⁴/32\)]⇒ \(τ = 32 × 125d⁴/(π × 15)⇒ τ = 800d⁴/π\)

Using the value of ta, we get:τ ≤ \(ta⇒ 800d⁴/π ≤ 56×103⇒ d⁴ ≤ (56×103 × π)/800\)⇒ \(d ≤ (56×103 × π/800)1/4d ≤ 1.328\)

\(θ = TL/JG\)⇒ \(θ = (T1 × LBC + T2 × LCD) × 1/G × J\)⇒ \(θ = (200 × 20 + 325 × 15) × 1/(11600 × 103) × πd⁴/32\)⇒ \(θ = 174.42d⁴× 10⁻⁷ radians\)

We know that the angle of twist (θ) is related to the angle of twist per unit length (ϕ), the length of the segment of the shaft under consideration (L) and the angle of twist (θ) by the following relation:ϕ = θ/L

we have:\(ϕ = θ/LCD⇒ ϕ = 174.42d⁴× 10⁻⁷/15⇒ ϕ = 1.163d⁴× 10⁻⁶ radians/in\)

Therefore, the angle of twist between gears B and D is\(1.163d⁴× 10⁻⁶\) radians/in or\(69.8d⁴× 10⁻⁶\) degrees/in.

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For surfaces that are perpendicular to one direction, the stress magnitude is greatest, and for surfaces that are parallel to that direction, the stress magnitude is zero.

Stress is the applied force or system of forces that tends to deform a body from the viewpoint of loading. Stress is the internal distribution of forces within a body that balance and respond to the loads given to it from the viewpoint of what is happening inside a material. Stress is a measurement of how a substance reacts to external influences. It is merely a ratio of the material's cross sectional area to the external forces. Stress (S = R/A, where S is the stress) is the ratio of force to area.

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Answer:

Development of creative and develop ideas

Explanation:

First task as an entrepreneur is to be creative and develop ideas. The person must design the product based on which he will develop the business strategy.

The remaining activities such as marketing, fund raising, recruitment etc. comes at a later stage.

Answer:

I don't know

Explanation:

sorry I am answering this for points

please follow and mark as brainliest for me I will also do same

Answer:

Adapting this case to a work environment, especifically an industry, there should be a security and health brigade in charge of response against emergencies within the organization. Said brigade has the duty of giving direction to all people that could be hurt in any way by a negative event caused by the emergency These directions are given orally in the case of emergencies. Also, emergency services personnel, such as police, firefighters, and paramedics, are certified professionals who have the responsibility of protecting people against harm, and this includes giving guidance during emergencies.

Because the image that contains ∠KCL is not indicated, see attached one that adequately describes an adjacent angle.

W/hen two angles exist on the same vertex, and on the same side, they are said to be adjacent to one another.

Thus from the attached image, the adjacent angles are ∠ABD and ∠CBD

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The minimum standard reduction potential of the cathode is -0.64V. The cathode has no maximum standard reduction potential.

O₂(g) + 4 H⁺(aq) + 4 e⁻ ⇒ 2 H₂O(l)

The difference between the cathode's reduction potential (E°red, cat) and the anode's reduction potential (E°red, an) is known as the standard cell potential (E°).

E° = E°red, cat - E°red, an

If E°red, an = -0.64 V and E° = 0.90V,

E°red, cat = E° + E°red, an = 0.90V --0.64V = 0.26V

The cathode's standard reduction potential is -0.64V at the very least. The cathode has no maximum standard reduction potential.

The O2/H2O cathode, with a reduction potential of E°red = -0.64V, is a potential cathode. The cathode would experience the following reduction:

O₂(g) + 4 H⁺(aq) + 4 e⁻ ⇒ 2 H₂O(l)

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The business application that uses passive (no power source) electronic tags and labels to identify objects wirelessly over short distances (up to 20 feet) is radio-frequency identification (RFID).

RFID (radio-frequency identification) is a system that employs passive (no power source) electronic tags and labels to identify objects wirelessly over short distances (up to 20 feet).

The tags contain data that is transmitted by a reader that is also called a radio-frequency identification interrogator or transceiver.

An RFID tag is placed on the object to be identified, and when it comes into range of the reader, the reader sends a signal that activates the tag.

After that, the tag responds by transmitting the data encoded in its memory.

This data can include identification, status, location, and other information related to the object.

A conclusion may be that the radio-frequency identification (RFID) is an advanced technology that has been developed to improve the accuracy and efficiency of data collection and management.

It can be used in a variety of business applications, such as inventory management, supply chain management, and asset tracking.

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Answer:

  Put a 10.0-ohm resistor in the circuit. Measure the current in the circuit. Replace the 10.0-ohm resistor with a 20.0-ohm resistor. Measure the new current. Continue replacing the resistor with a different resistor of known resistance. Measure the current for each resistor. Record all data.

Explanation:

The only design that has resistance varying with everything else remaining the same is the first design. That would be what you'd want to do if you're exploring the effect of resistance on current.

Answer:

La temperatura Kelvin que corresponde a 0 ºB es 493.15 Kelvin.

Explanation:

Sabemos que el punto de congelación del agua es 273.15 Kelvin y, según el enunciado, -60 ºB. Asimismo, el punto de ebullición de esta sustancia es 373.15 Kelvin y, según el enunciado, -10 ºB. Asumiendo una relación lineal, podemos determinar la temperatura en escala Kelvin equivalente a 0 ºB mediante la siguiente extrapolación:

\(T = 373.15\,K+\left[\frac{373.15\,K-273.15\,K}{-10\,^{\circ}B-(-60\,^{\circ}B)}\right]\cdot [0\,^{\circ}B-(-60\,^{\circ}B)]\)

\(T = 493.15\,K\)

La temperatura Kelvin que corresponde a 0 ºB es 493.15 Kelvin.

1. We cannot solve nonlinear programming problems by simplex.The simplex method is utilized for linear programming problems only. The LP problems have linear constraints and a linear objective function. The nonlinear programming problems cannot be solved by the simplex method.

We have to use the other methods for these kinds of issues.2. In any integer basic feasible solution of the transportation problem, the number of positive variables is equal to half the number of functional constraints. It is feasible to use a solution that is restricted to whole numbers for transportation problems. We've got a few formulas that can help us figure out the answers.3. A discrete dynamic programming problem can be represented by a tree. To solve a dynamic programming problem, we typically use a graph structure known as a decision tree. The nodes of a decision tree represent decision points, and the arcs represent the choices available at each decision point.4. A tree is a special case of a graph. Trees are a special kind of graph, so it makes sense that they're also used to represent decision trees. Trees are graphs with nodes linked together in a particular manner. There is a parent-child relationship between the nodes of a tree, which means that each node has only one parent and zero or more children. Trees have no cycles, which means that there is no way to traverse the tree from a node to itself without first traversing a node that is not a descendant.

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Answer:

The ACT Science test explained below begins on page 40 of the guide. Please note that the 2020-2021 guide features the same practice test

Explanation:

Answer:

I don't understand the question

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