How much work must be done to stop a 925-kg car
traveling at 95 km/h?

The stress within the column is 175,000 Pa and the strain is 2.92 x \(10^{-6\) when cross-sectional area is 1.4 \(m^2\) and mass of 25,000 kg.

a) To find the stress within the column, we use the formula stress = force/area. The force acting on the column is the weight of the mass it supports, which is 25,000 kg multiplied by the acceleration due to gravity (9.8 \(m/s^2\)), giving a force of 245,000 N. The area of the column is given as 1.4 \(m^2\). Thus, the stress within the column is:
stress = force/area = 245,000 N/1.4 \(m^2\) = 175,000 Pa
b) To find the strain, we use the formula strain = change in length/original length. The change in length can be found using Hooke's law, which states that the strain is directly proportional to the stress within the elastic limit. For marble, the elastic limit is quite high, so we can assume that the strain is directly proportional to the stress. The proportionality constant is known as the modulus of elasticity or Young's modulus. For marble, the Young's modulus is about 60 GPa (60 x \(10^9\) Pa). Thus, the strain within the column is:
strain = stress/Young's modulus = 175,000 Pa/60 x \(10^9\) Pa = 2.92 x \(10^{-6\) (or 0.000292%)
Therefore, the stress within the column is 175,000 Pa and the strain is 2.92 x \(10^{-6\).

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Answer:

a large beach ball

Explanation:

The buoyant force is the upward force exerted by a fluid, such as magma, on an object immersed in it.

When volatile-rich magma rises, the gases present in the magma expand due to decreasing pressure, and this leads to the formation of gas bubbles. As the gas bubbles are less dense than the surrounding magma, they exert an additional upward force, which makes the magma even more buoyant. This process of gas bubble formation and buoyancy enhancement can create an explosive eruption if the magma rises quickly and reaches the surface. The explosive nature of the eruption depends on the type and amount of gas present in the magma, the viscosity of the magma, and the depth of the magma chamber. In summary, the volatile-rich magma's gas bubbles provide an additional buoyant force, which accelerates the upward movement of magma, making it more aggressive.

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Viscosity, the resistance to flow, is determined by the strength of the intermolecular attractions. Substances with strong intermolecular forces are more viscous than are substances with weak intermolecular forces. Temperature also affects the viscosity of a given liquid. As temperature increases, the corresponding increase in kinetic energy overcomes some of the intermolecular attractions. This decreases the overall viscosity of the liquid and allows the liquid to flow more freely.

Surface tension is the tendency of liquids to minimize their surface area. Molecules at the surface of the liquid have no liquid molecules above them with which to interact, so they experience a downward pull. This downward pull causes all liquids to minimize their surface area. Cohesion is the attraction of atoms and molecules to like particles. Adhesion, the attraction to different particles, is also possible, provided the other particle can form intermolecular forces. Cohesion and adhesion help to explain capillarity, the ability of a liquid to flow against gravity up a narrow tube.

Viscosity refers to a fluid’s resistance to flow. A high-viscosity fluid will be thicker and flow less freely than a low-viscosity fluid. Intermolecular forces in a liquid can also impact its viscosity. Stronger intermolecular forces result in a higher viscosity. Temperature affects viscosity because it influences kinetic energy, which can overcome some of the intermolecular attractions in a liquid, leading to a lower viscosity.

Surface tension is the tendency of a liquid to minimize its surface area. The molecules at the surface of a liquid experience a downward pull since they have no other liquid molecules above them with which to interact. The cohesive forces between liquid molecules give rise to surface tension. Cohesion is the attraction of atoms and molecules to like particles, while adhesion is the attraction to different particles. Capillarity is the ability of a liquid to flow against gravity up a narrow tube, and it occurs due to both cohesion and adhesion.

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Answer:

first one down second one up

Explanation:

Answer:a no net force

Explanation: google lol

The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.

In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.

No atoms gain or lose electrons in this process.

In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.

This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.

A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.

These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.

It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.

Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.

Therefore, statement B, which suggests that each atom gains one electron, is false.

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Answer:

F = m a

it means as m increase force increase also and acceleration is constant

the best example of this case is free fall regardless of the mass of something the free fall acceleration is constant - 9.81 m/s^2, because as mass increase gravitational force increase also

Answer:

hlw I'm jess bregoli

your answer is here (◕ᴗ◕✿)

mass is the amount of matter..Gravity affects weight, it does not affect mass.

Masses always remain the same.

Explanation:

hope it may help you

The total voltage drop for the entire circuit is calculated as 45.00 V.

Amount of voltage loss that happens through all or part of circuit due to impedance is called as voltage drop.

When resistors are connected in series, the total resistance is the sum of individual resistances, i.e., R = R1 + R2.

For 5.00 Ω resistor, the voltage drop is V1 = IR1 = (3.00 A)(5.00 Ω) = 15.00 V.

For 10.0 Ω resistor, the voltage drop is V2 = IR2 = (3.00 A)(10.0 Ω) = 30.00 V.

Total voltage drop for the entire circuit is the sum of the voltage drops across each resistor:

V = V1 + V2 = 15.00 V + 30.00 V = 45.00 V.

Therefore, the total voltage drop for the entire circuit is 45.00 V.

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The greatest height reached by the ball is given by A(z) and the horizontal distance to the thrower's feet at this point is denoted as D.

The height from which the ball was thrown is represented as H. The horizontal distance to the thrower when the ball hits the ground is denoted as Dg.

The greatest height reached by the ball is A(z), and the horizontal distance to the thrower's feet at this point is D. The ball was thrown from a height of H.

The horizontal distance to the thrower when the ball hits the ground is Dg.

To find the greatest height reached by the ball, we need to analyze the function A(z). The horizontal distance D to the thrower's feet at this point can be determined by considering the horizontal component of the ball's motion.

To calculate the height from which the ball was thrown, we can use the initial condition or other given information.

Finally, to determine the horizontal distance Dg when the ball hits the ground, we need to analyze the ball's trajectory and identify the point at which its height becomes zero.

These calculations involve analyzing the ball's motion in both the horizontal and vertical dimensions, incorporating factors such as initial velocity, angle of projection, and gravitational acceleration.

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Answer:

The sun and other stars consist of plasma. Plasma is also found naturally in lightning and the northern and southern lights. Human-made plasma is found in fluorescent lights, plasma TV screens, and plasma spheres

Explanation:

hope this helps if so mark me brainliest <3

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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The total energy stored in the spring at the new stretched length is 2.25 Joules.

The potential energy stored in a spring is given by the formula:

U = (1/2) k x²

where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position. Initially, the spring was stretched by 5.0 cm, so its displacement from the equilibrium position is x = 0.05 m + 0.05 m = 0.10 m.

The force applied to stretch the spring is given by Hooke's law, F = kx, where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position. The force applied to stretch the spring by an additional 5.0 cm is,

F = kx = (200 N/m)(0.05 m) = 10 N

The total displacement of the spring is now x = 0.10 m + 0.05 m = 0.15 m. The total potential energy stored in the spring is:

U = (1/2) k x² = (1/2)(200 N/m)(0.15 m)² = 2.25 J

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Answer:

26897.3 m

Explanation:

1 km = 1000 m

1 cm = 0.01 m

so the calculation will be

25873 m + 1024 m + 0.03 m= 26897.3 m

The sum of the given expression (25.873 kilometers ) + (1024 meters ) + (3.0 centimeters)  would be 26897.0 meters.

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

As given in the problem we have to Calculate the following sum and express the answer in meters, by Following the rules for significant figures,

(25.873 kilometers ) + (1024 meters ) + (3.0 centimeters)

1 kilometers = 1000 meters

1 meter =100 centimeters

(25.873 ×1000×100) + (1024×100 ) + (3.0 centimeters)

                = 26897.03 centimeters

Thus ,the sum of the given expression (25.873 kilometers ) + (1024 meters ) + (3.0 centimeters)  would be 26897.0 meters.

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:

ultraviolet B

Explanation:

\(\\ \sf\bull\longmapsto Wd=Force(Displacement)\)

\(\\ \sf\bull\longmapsto Work=10(0.3)\)

\(\\ \sf\bull\longmapsto Work=3J\)

Answer:

\({ \tt{work \: done = force \times distance}}\)

• force → 10 N

• distance → 30 cm = 0.3 m

\({ \tt{ work \: done = (10 \times 0.3)}} \\ \\ { \boxed{ \tt{work \: done = 3 \: joules}}}\)

Answer:

a1 = (V2 - V1) / 1 s = 3.75 m/s^2

a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2

v = a (t2 - t1)

B) after    1 sec    v = 3.75 m / sec^2 * 1 sec = 3.75 m/s

    after   2 sec     v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s

C)  The velocity increases proportionaly to the time

D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)

A much larger factor is due to air resisance of the air on the falling object

The specific heat of a substance of a container affect the quantity of substances that can be accommodated in the container at a given temperature.

The specific heat capacity of a substance is the quantity of heat required to raise the temperature of a unit mass of the substance.

Mathematically, the formula relating specific heat capacity and heat capacity of a substance is given as;

Q = m x  c  x Δθ

where;

From the formula above we can make mass " m " the subject of the formula;

m = ( Q ) / (  c  x Δθ )

As the specific heat of a substance increases, the smaller the mass of the substance that can be held in a container at equal heat gain and temperature and vice versa.

Thus, the specific heat of a substance affects the performance of a container as it depends the mass or volume of the substance that can be held in a container at a constant heat capacity and temperature.

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An exchange of energy between system and environment is called an energy transfer.

Energy can be transferred in two ways: heat and work. Heat is the transfer of energy that occurs when there is a temperature difference between the system and its surroundings. Work is the transfer of energy that occurs when a force is applied to a system and causes it to move.

The total energy of a system and its surroundings is constant. This is known as the first law of thermodynamics.

Here are some examples of energy transfer:

Energy transfer is essential for life. All living organisms need to exchange energy with their environment in order to survive.

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Answer:

300 miles

Explanation:

3*60 + 5*24 = 300

Answer: On this scale,Alpha centauri would be 1.48×10∧6

metres or about 890 miles away.

Explanation: If the sun were scaled to a 1 foot radius  , then alpha centauri would be about 10,000 miles away.

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy (\(K\)), in joules, is entirely translational, whose formula is:

\(K = \frac{1}{2}\cdot m\cdot v^{2}\) (1)

Where:

\(m\) - Mass, in kilograms.

\(v\) - Speed, in meters per second.

If we know that \(m = 0.5\,kg\) and \(v = 35\,\frac{m}{s}\), then the kinetic energy of the baseball thrown by the player is:

\(K = \frac{1}{2}\cdot m \cdot v^{2}\)

\(K = 306.25\,J\)

The kinetic energy of the baseball is 306.25 joules.

A 175-g object is attached to a spring that has a force constant of 72.5 N/m. The object is pulled 8.25 cm to the right of equilibrium and released from rest to slide on a horizontal, friction less table.when the object's velocity is one-third of the maximum speed, its location (displacement from equilibrium) is approximately 12.1 cm to the right.

a) To calculate the maximum speed of the object, we can use the principle of conservation of mechanical energy. At the maximum speed, all the potential energy stored in the spring is converted into kinetic energy.

The potential energy stored in the spring can be calculated using the formula:

Potential energy = (1/2) × k × x²

where k is the force constant of the spring and x is the displacement from the equilibrium position.

Given that the object is pulled 8.25 cm to the right of equilibrium, we can convert it to meters: x = 8.25 cm = 0.0825 m.

The potential energy stored in the spring is:

Potential energy = (1/2) × (72.5 N/m) × (0.0825 m)²

Next, we equate the potential energy to the kinetic energy at the maximum speed:

Potential energy = Kinetic energy

(1/2)× (72.5 N/m) × (0.0825 m)² = (1/2) × m × v²

We need to convert the mass from grams to kilograms: m = 175 g = 0.175 kg.

Simplifying the equation and solving for v (velocity):

(72.5 N/m) × (0.0825 m)² = 0.5 × 0.175 kg × v²

v² = (72.5 N/m) × (0.0825 m)² / 0.175 kg

v² ≈ 6.0857

v ≈ √6.0857 ≈ 2.47 m/s

Therefore, the maximum speed of the object is approximately 2.47 m/s.

b) To find the locations of the object when its velocity is one-third of the maximum speed, we need to determine the corresponding displacement from the equilibrium position.

Using the equation of motion for simple harmonic motion, we can relate the displacement (x) and velocity (v) as follows:

v = ω × x

where ω is the angular frequency of the system.

The angular frequency can be calculated using the formula:

ω = √(k/m)

Substituting the given values:

ω = √(72.5 N/m / 0.175 kg)

ω ≈ √414.2857 ≈ 20.354 rad/s

Now, we can find the displacement (x) when the velocity is one-third of the maximum speed by rearranging the equation:

x = v / ω

x = (2.47 m/s) / 20.354 rad/s

x ≈ 0.121 m

Converting the displacement to centimeters:

x ≈ 0.121 m × 100 cm/m ≈ 12.1 cm

Therefore, when the object's velocity is one-third of the maximum speed, its location (displacement from equilibrium) is approximately 12.1 cm to the right.

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The correct expression for the rotational inertia of the spherically shaped object is \(\(\text{c) } 3.6m^5\)\).

In the given scenario, the students determine that the radius of the object is given by \(\(r = km^2\) with \(k = 3\, \text{m/kg}^2\)\). To calculate the rotational inertia of the object, we need to use the formula for rotational inertia of a spherical object, which is given by \(\(I = \frac{2}{5}mr^2\)\), where m is the mass of the object and r is the radius.

Substituting the given expression for r in terms of m, we have \(\(I = \frac{2}{5}m(km^2)^2\)\). Simplifying this equation, we get \(\(I = \frac{2}{5}mk^2m^4\)\).

Substituting the value of \(\(k = 3\, \text{m/kg}^2\)\), we have \(\(I = \frac{2}{5}(3\, \text{m/kg}^2)^2m^5\)\), which further simplifies to \(\(I = \frac{2}{5} \times 9 \, \text{m}^2/\text{kg}^2 \times m^5\)\).

Finally, multiplying the constants, we get \(\(I = 3.6 \, \text{m}^2/\text{kg}^2 \times m^5\)\), which corresponds to option c) \(3.6 \(m^5\)\).

Therefore, the correct expression for the rotational inertia of the object is \(3.6 \(m^5\)\).

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Answer:

\(velocity = \frac{distance}{time} \\ velocity = \frac{10}{12.20} \\ velocity = \frac{50}{61} \\ multiply \: by \: 3.6u \: can \: convert \: to \: km \: per \: hour \\ velocity = \frac{50}{61} \times 3.6 \\ v = \frac{180}{61} \\ v = 2.95 \frac{km}{h} \\ thank \: you\)

The fuel in a pressure carburetor is pressurized to avoid vaporization. As a result, a float is required to regulate the vapor vent content. If the vapor vent float in a pressure carburetor loses its buoyancy, it will prevent the carburetor from functioning properly.

Buoyancy refers to the upward force that an object experiences when it is placed in a fluid. The vapor vent float is in charge of regulating the vapor vent in the carburetor. If the vapor vent float loses its buoyancy, the vapor vent will not be correctly regulated, which will cause the carburetor to malfunction.

The fuel in the carburetor will then be unable to regulate its pressure and become excessively volatile, resulting in poor engine performance. A mechanic should inspect and change the vapor vent float if there is any indication that it is no longer working correctly.

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