Answers
Answer:
40J
Explanation:
Given parameters:
Mass of box = 10kg
distance moved = 2m
Force applied = 20N
Unknown:
Work done in pushing the box = ?
Solution:
The work done in moving a body is a function of the force applied to move it through a particular distance.
Work done = Force x distance
So;
Work done = 20 x 2 = 40J
Related Questions
Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?
Answers
We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.
The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.
The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.
The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.
The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.
The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.
The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.
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what do you mean by power of a bulb is 550 watt
Answers
Answer:
P=IV is the formula you can use for electricity.
Explanation:
P - Power, I - Current, V - Voltage
What you are asking in your question can be broken down a system that has the power can move /work 550 joules per second. Taken from an electricity point of view, a 550W light bulb can drive a current of 550 amperes with a potential difference of 1 Volt
Where is the electric field between a charged balloon and a charged piece of paper 0.04 m away?
A. The electric field is in the region around the balloon and paper where there are outside charges that affect them.
B. The electric field is in the 0.04 m distance between the balloon and paper and not anywhere else around either the paper or the balloon.
C. The electric field is all around the balloon and paper including between them, where, depending on their charge, there would be a force of either attraction or repulsion.
D. The electric field is in the region in which the forces come in contact.
Answers
The electric field is all around the balloon and paper including between them, where, depending on their charge, there would be a force of either attraction or repulsion.
What is electric field?An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
Thus, for the charged balloon and a charged piece of paper 0.04 m away, we can conclude that, the electric field is all around the balloon and paper including between them, where, depending on their charge, there would be a force of either attraction or repulsion.
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BRAINLIEST IF ITS CORRECT HEPL
Answers
Answer: C.
Explanation: They describe the direction of the magnetic force on a north monopole at any given position.
How much (in decimal dollars) does it cost to run a 1,500 W hair dryer for 43 minutes each day for a month (30 days) at a cost of 19¢ per kWh?___________$
Answers
Answer:
$612.75
Explanation:
First, convert 43 minutes into hours
\(43\text{ min}\times\frac{1\text{ hour}}{60\text{ min}}=0.716\text{ hours}\)Then, the total number of hours in the month is
\(0.716\text{ hours }\times30\text{ days = 21.5 hours}\)Then, 1,500 W is equivalent to 1.5 kW, so the total kWh is equal to
\(1.5kW\times21.5\text{ hours = 32.25 kWh}\)Now, we can calculate the cost as follows
\(33.25\text{ kWh}\times\frac{19\text{ \$}}{1\text{ kWh}}=612.75\text{ }\)Therefore, the answer is $612.75
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
FILL IN THE BLANK many missionary expeditions were stopped by what are locally known as______, winds that bring quick temperature drops of up to 40 degrees in a matter of minutes.
Answers
Many missionary expeditions were stopped by what are locally known as Chinook, winds that bring quick temperature drops of up to 40 degrees in a matter of minutes.
Descending air on the leeward side of mountains can cause Chinook winds, which raise the temperature and eat snow. Residents on the eastern sides of large mountain ranges in Canada and the United States may benefit from these reprieves in mid-winter.
Chinook winds can cause the temperature to increase 40 degrees Fahrenheit in a matter of minutes. The warm air then rapidly melts or sublimates the snow.
Organisms living in regions prone to Chinook winds have to withstand extreme temperature changes and often dry conditions. People may like Chinook winds since they give a reprieve from the frigid days of winter.
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please please please i need heeelp
Answers
9514 1404 393
Answer:
A and B started at the same time
Explanation:
Speed is the slope of the position vs. time curve. Here, both curves have positive slope (positive speed) at t=0, so both A and B started at the same time.
In Bolt’s fastest 100 meter, he accelerated from the starting block to a speed of 27.8 mi/hr in 9.58 s. What was his acceleration?
O 9.58 mi/hr/s
O 3.60 mi/hr/s
O 2.90 mi/hr/s
O 2780 mi/hr/s
Answers
Answer: 2.90mi/hr/s
Explanation:
Acceleration = Final Velocity - Initial over time
Acceleration = 27.8mi/hr over 9.58s.
Answer is 2.90mi/hr/s
Hope I Helped!
2. If you are driving at a constant velocity of 5 m/s what is your
acceleration?
Answers
acceleration= 0m/s^2
A coaxial cable consists of an inner cylindrical conductor of radius 3 cm on the axis ofan outer hollow cylindrical conductor of inner radius 7 cm and outer radius of 10 cm.The inner conductor carries current 4.5 A in one direction, and the outer conductor carries current 8 A in the opposite direction. What is the value of the magnetic field atfollowing distances from the axis of the cable:
Answers
Answer:
Hello your question lacks some information and that is the distance
At r = 0.150 m (outside the cable) note : (μ 0 = 4π × 10-7 T · m/A)
answer: 4.7 * 10^-6 T
Explanation:
R1 = 0.03 m
R2 = 0.07 m
R3 = 0.1 m
Inner conductor carries current = 4.5A in one direction
outer conductor carries current = 8A in opposite direction
Determine the value of magnetic field at r = 0.150 m
net current = 8 - 4.5 = 3.5 A
∴ β ( value of magnetic field )
= ( 4π * 10^-7 * 3.5 ) / ( 2π * 0.150 )
= 4.4*10^-6 / 0.94
= 4.7 * 10^-6 T
If a 500-mL glass beaker is filled to the brim with methanol at a temperature of 5.00ºC, how much will overflow when its temperature reaches 22.0ºC?
(Suppose the coefficient of volume expansion for methanol is 1200x10^(-6) 1/ºCRequired to answer. Single choice.
(1 Point)
Answers
Answer:
10.2 mL.
Explanation:
From the question given above, the following data were obtained:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Rise in volume (ΔV) =?
Next, we shall determine the volume (V₂) of the methanol at 22 °C. This can be obtained as follow:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Volume 2 (V₂) at temperature θ₂ =?
γ = V₂ – V₁ / V₁ (θ₂ – θ₁)
1200×10¯⁶ = V₂ – 500 / 500 (22 – 5)
1200×10¯⁶ = V₂ – 500 / 500 × 17
1200×10¯⁶ = V₂ – 500 / 8500
Cross multiply
V₂ – 500 = 1200×10¯⁶ × 8500
V₂ – 500 = 10.2
Collect like terms
V₂ = 10.2 + 500
V₂ = 510.2 mL
Thus, the volume of the methanol at 22 °C is 510.2 mL
Finally, we shall determine the rise in volume of methanol as illustrated below:
Original Volume (V₁) at temperature θ₁ = 500 mL
Volume (V₂) at temperature θ₂ = 510.2 mL
Rise in volume (ΔV) =?
ΔV = V₂ – V₁
ΔV = 510.2 – 500
ΔV = 10.2 mL
Thus, 10.2 mL of the methanol will overflow when the temperature reaches 22 °C.
A proton high above the equator approaches the
Earth moving straight downward with a speed of
365 m/s.
Find the acceleration of the proton, given that the magnetic field at its altitude is 4.10*10^-5 T.
Answers
We can see from the calculations that the acceleration of the proton is 1.43 * 10^7 ms-2.
What is acceleration?Acceleration is the rate of change of velocity with time. We know that the magnetic force is obtained by;
F = qvB
q= 1.6 * 10^-19 C
v = 365 m/s
B = 4.10*10^-5 T
F = 1.6 * 10^-19 C * 365 m/s * 4.10*10^-5 T
F = 2.39 * 10^-20 N
Recall that the mass of the proton is 1.67 × 10−27 kg hence
a = F/m = 2.39 * 10^-20 N/1.67 × 10−27 kg = 1.43 * 10^7 ms-2
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The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of Q is located at one of the corners of the square. What is the potential (relative to infinity) at the center when each of the other corners is also contains a point charge of Q
Answers
Answer:
12.0 V
Explanation:
Data :
Potential difference due to a single charge (+Q), E = 3.0 V
The Electric potential for the system of charges is given as:
\(E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]\)
for single charge, E = 3.0 V = \(\frac{1}{4\pi \epsilon_o}[\frac{Q}{r}]\) ->eq(1)
And for 4 charges:
\(E=\frac{1}{4\pi \epsilon_o}[4\frac{Q}{r}]\) -eq(2)
from eq(1) and (2) we have
E = 4 × 3.0 V = 12 V
a free-falling object has a speed of 30 m/s at one instant. exactly 2 seconds later its speed will be
Answers
The velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
Explain the term acceleration due to gravity?Gravitational acceleration is the rate at which the speed of a body falling freely increases. Gravitational acceleration is measured in SI units of m/s², m/s², m/s².A body is considered to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.For the given question-
The freely falling body has the speed at an instant as u = 30 m/s.
Acceleration due to gravity g = 9.8 m/s².
After time t = 2 sec, the final velocity v m/s.
Using equation of motion,
v = u + gt
v = 30 + 9.8 x 2
v = 49.6 m/s.
Thus, the velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
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What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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will there be a mega tsunami like in the movie tidal wave from 2009?
Answers
What precise meaning do you attach to the statement r = (24.0 ± 0.3) mm, where r is the radius of a tube.
Answers
The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.
In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.
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*
Check all of the things that can affect power
Time
Work
Distance
Force
Answers
Answer:
fhddmvxmvydlyghclhchc
A 2kg block on a horizontal table is pulled to the right by a constant force of 16N the acceleration of the block is 3m/s^ 2 Determined the coefficient of kinetic friction between the block and the table top
Answers
The coefficient of kinetic friction between the block and the table top is 0.204.
Kinetic friction calculation.
To determine the coefficient of kinetic friction, we can use the equation for the net force acting on the block:
F_net = ma
where F_net is the net force, m is the mass of the block, and a is the acceleration of the block. The net force is the difference between the applied force and the force of friction:
F_net = F_applied - F_friction
where F_applied is the applied force, and F_friction is the force of friction.
Since the block is moving with constant velocity, the force of friction is equal in magnitude but opposite in direction to the applied force:
F_friction = μ_k * N
where μ_k is the coefficient of kinetic friction, and N is the normal force (equal to the weight of the block, N = mg).
Substituting the expressions for F_net and F_friction into the first equation and solving for the coefficient of kinetic friction, we get:
F_applied - μ_k * N = ma
μ_k = (F_applied - ma) / N
Substituting the given values, we get:
μ_k = (16 N - 2 kg * 3 m/s^2) / (2 kg * 9.8 m/s^2)
μ_k = 0.204
Therefore, the coefficient of kinetic friction between the block and the table top is 0.204.
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Which phrase describes an irregular galaxy O has a round shape O does not have a specific shape O has arms that extend from the center O is larger than other types of galaxies
Answers
Answer:
I think it does not have a specific shape
Explanation:
Irregular galaxies have no definite shape, which means that the second option is correct. They are definitely not round.
The "spiral galaxy" is the type of galaxy that has arms that extend from the center. These arms look "spiral," which influenced its name.
They are actually smaller than the other types of galaxies. This makes them prone to collisions.
The phrase that describes the irregular galaxy is that it does not have a specific shape. The correct option is B.
What is irregular galaxy?A galaxy with an undefined shape is an irregular galaxy with a large number of young stars and a large amount of gas and dust that is typically found near larger galaxies.
An irregular galaxy is a catch-all term for any galaxy that does not neatly fit into one of the Hubble classification schemes.
They have no discernible shape or structure and could have formed as a result of collisions, close encounters with other galaxies, or violent internal activity.
They lack beautiful spiral arms, but they do have dark patches of gas and dust. Some irregular galaxies appear to be the result of two galaxies colliding.
Thus, the correct option is B.
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what is angular frequency
Answers
Which formula describes
acceleration?
O m/s
O m²
O m/s²
O s/m
Answers
Answer:
the answer is the formula of acceleration is m/s²
You're at the hardware store buying a lightbulb for your living room lamp, which you typicallyuse for about 4 hours per day (7 pm - 11 pm). You're considering three options:Type. Power Rating. Efficiency Cost per bulb. LifetimeIncandescent 60 W. 3%. $1.00. 1.5 yearsCompactFluorescent. 13W. 14%. $1.50. 7.5 years(CFL) 13 WLED 10 W. 18%. $2.00 15 years(a) Energy consumed: What's the annual energy usage (in kWh) for each bulb option? (3pt)(b) Energy cost: If electricity costs 12 cents/kWh, what is the annual operating cost foreach lightbulb? (3 pt)(c) Payback time: Compared to the incandescent, what are the payback times of the CFLbulb and LED bulb? Give you answer in operating hours and years to two decimalplaces. (8 pts)(d) Return on investment: Over the life of a LED bulb, what's the Return onInvestment (ROI) compared to if you were running the lamp on incandescent bulbs thewhole time? Give your answer as a percentage ROI. (8 pt)
Answers
The return on investment of using an LED bulb instead of incandescent over the life of the LED bulb is 745.75%.
(a) Energy consumed:Incandescent bulb: 60W x 4 hours/day x 365 days/year = 87.6 kWh/year
CFL: 13W x 4 hours/day x 365 days/year = 18.98 kWh/year
LED: 10W x 4 hours/day x 365 days/year = 14.6 kWh/year
(b) Energy cost:Incandescent bulb: 87.6 kWh/year x $0.12/kWh = $10.51/year
CFL: 18.98 kWh/year x $0.12/kWh = $2.28/year
LED: 14.6 kWh/year x $0.12/kWh = $1.75/year
(c) Payback time:
CFL vs. Incandescent: CFL costs $0.50 more but saves $8.23/year in energy costs. Payback time = $0.50 / $8.23/year = 0.061 years or 22.29 operating hours
LED vs. Incandescent: LED costs $1.00 more but saves $8.76/year in energy costs. Payback time = $1.00 / $8.76/year = 0.114 years or 41.59 operating hours
(d) Return on investment:
ROI = (Savings - Investment) / Investment x 100%
Over 15 years, the incandescent bulb would cost $157.65 to operate ($10.51/year x 15 years). The LED bulb would cost $26.25 to operate ($1.75/year x 15 years) and would have an investment of $2.00.
ROI = ($157.65 - $26.25 - $2.00) / $2.00 x 100% = 745.75%
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What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.250 kg attached to a spring of force constant 9.75 N/m
Answers
Answer:
the length of the simple pendulum is 0.25 m.
Explanation:
Given;
mass of the air-track glider, m = 0.25 kg
spring constant, k = 9.75 N/m
let the length of the simple pendulum = L
let the frequency of the air-track glider which is equal to frequency of simple pendulum = F
The oscillation frequency of air-track glider is calculated as;
\(F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz\)
The frequency of the simple pendulum is given as;
\(F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m\)
Thus, the length of the simple pendulum is 0.25 m.
if one food calorie which equals 1000 "chemistry" calories equals 4184 J, then how far could you go on one cookie containing 50 calories ?
Answers
On one cookie containing 50 calories, you could potentially go approximately 298 meters
How to calculate the valueGiven that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:
50 food calories * 4184 J/calorie = 209,200 joules
Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).
Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)
Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)
Distance ≈ 298 meters
Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters
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A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what
depth it sinks when placed in a tank of water (assume the sides are sufficiently high,
so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.
Answers
Answer:
60
Explanation:
A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what
depth it sinks when placed in a tank of water (assume the sides are sufficiently high,
so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.
Show what you know : Mining
Answers
a. waste rock or overburden - cookie crumbles left over because they have no value.
b. valuable mineral ore - chocolate chips.
c. mining equipment to dig and move earth materials - toothpicks and paper clips.
d. mining reclamation - restoring the mining site by attempting to place all of the leftover cookie crumbles in the circle.
What is mining reclamation?Mining reclamation is the process of restoring land that has been mined for natural resources, such as coal, oil, gas, minerals, or metals, to its pre-mining condition or a suitable alternative condition. The goal of mining reclamation is to ensure that the land can be used for future beneficial purposes, such as agriculture, forestry, wildlife habitat, recreational activities, or development.
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Venus and Earth may be regarded as behaving as black bodies. The mean temperature at the surface of Venus is about 600 K and at the surface of Earth is about 300 K. Which of the following is the best estimate for the ratio \frac{\text{power radiated per unit area on Earth}}{\text{power radiated per unit area onVenus}} power radiated per unit area onVenus power radiated per unit area on Earth
Answers
The best estimate for the ratio of Power radiated per unit Area on Earth and Power radiated per unit Area on Venus is 1/16. The correct option is D.
What is power radiated?Power radiated is directly proportional to the fourth power of Temperature at the surface and also to the cross-section area.
P = σ A T⁴
For 600 K at Venus, σ A T⁴ = σ A (600)⁴
For 300 K at Earth , σ A T⁴ = σ A (300)⁴
Comparing, we get
[σ A (300)⁴/ σ A (600)⁴ ] = 1/16
Thus, the the best estimate for the ratio is 1/16. The correct option is D.
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On half of the moon appears to be lit (Light is on the RIGHT side of the moon)
this is science btw!!
Answers
Answer:
Moon appears lit on the right half of the Moon during the First Quarter. The Moon appears lit on the left side during the Third Quarter because the Moon is on the other side of Earth. Again, if you think of the baseball analogy, and you’re standing at home plate, the first base or First Quarter is on your right side.
Explanation:
i hope is help