even though the centripetal force does no work, you are expending energy and doing work to keep the object in motion.
In Investigation 1, when you swing an object in a uniform horizontal circle on a rope over your head, the centripetal force does not do any work. The centripetal force is responsible for keeping the object moving in a circular path, constantly changing its direction but not its speed.
Work is defined as the transfer of energy that occurs when a force acts on an object and causes it to move in the direction of the force. In the case of circular motion, the centripetal force acts perpendicular to the direction of motion, towards the center of the circle. As a result, the work done by the centripetal force is zero because there is no displacement in the direction of the force.
However, while swinging the object, you are expending energy and doing work. You are providing the initial energy to set the object in motion and continuously exerting force to keep the object moving in a circular path. This work is done by the force you apply through the rope, which acts tangentially to the circular path.
The work you do transfers energy to the object, maintaining its circular motion. The energy you expend is eventually dissipated as heat due to various factors such as friction in the rope, air resistance, and internal friction within the object itself.
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Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the critical angle θcrit, the light will not be refracted out into the air, but instead it will be totally internally reflected back into the diamond. Find θcrit.
Answer:
θ_c = 24.4º
Explanation:
To find the critical angle, let's use the law of refraction where index 1 refers to the incident medium (diamond) and index 2 refers to the medium where it is to be refracted (air)
n₁ sin θ₁ = n₂ sin θ₂
for the critical angle the ray comes out refracted parallel to the surface, therefore the angle is
θ₂ = 90
n₁ sin θ₁ = n₂
θ_c = θ₁ = sin⁻¹ \(\frac{n_2}{n_1}\)
the index of refraction of the diamond is tabulated
n₁ = 2.419
let's calculate
θ_c = sin⁻¹ (\(\frac{1}{2.419}\))
θ_c = 24.4º
a transverse wave of amplitude 3.0 cm , frequency 5.0 hz , and speed 3.0 m/s travels on an infinitely long slinky. part a how far apart are the two nearest points on the slinky that at one particular time both have the maximum magnitudes of displacements from their equilibrium positions? express your answer with the appropriate units.
Part A: 6.0 cm apart are the two nearest points on the slinky that at one particular time both have the maximum magnitudes of displacements from their equilibrium positions.
Part B: The period of the wave is 0.2 seconds.
A transverse wave of amplitude 3.0 cm, frequency 5.0 Hz, and speed 3.0 m/s travels on an infinitely long slinky. This question is a two-part question.
Let us solve each part of the question.
Part A:
We know that transverse waves move up and down perpendicular to the direction of the wave. It means that the maximum displacement of a particle from its equilibrium position is equal to the amplitude of the wave.
In one period (T), the wave completes one full cycle. The number of cycles completed in one second is called the frequency (f) of the wave.
The product of wavelength (λ) and frequency (f) of the wave is equal to its velocity (v).
The formula for a wave is given as follows:v = λf
Here, v is the velocity, λ is the wavelength and f is the frequency.
From the formula, we can calculate the wavelength of the wave. We are given the amplitude (A) and frequency (f) of the wave. We are to find the distance between two nearest points at maximum displacement.
To solve the problem, we use the formula for the wavelength of a wave.
λ = v/f
Substituting the values given:
λ = (3.0 m/s)/(5.0 Hz)
λ = 0.6 m
We know that for a transverse wave, maximum displacement is equal to the amplitude.
Therefore, the distance between two nearest points at maximum displacement is equal to two times the amplitude.
Substituting the value:
Distance between two nearest points at maximum displacement = 2 x amplitude= 2 x 3.0 cm = 6.0 cm
Part B:
The period of the wave is the time it takes for a complete cycle. The formula for the period is given as follows:
T = 1/f
Substituting the values:
T = 1/5.0 Hz
T = 0.2 seconds
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A 15 kg ball is launched forward from a height of 25 m. What is the net force of the ball
Answer:
147 newton.
Explanation:
Force is the product of mass and acceleration. The formula of force is given below: Force = mass x acceleration, but due to height we put gravity instead of acceleration. So by putting values of mass i. e. 15 kg and gravity i. e. 9.8 meter/ second in the formula we get the net force of the ball which is 147 newton or 147 kg meter/second square.
Give me right solution with clear calculations
. Tourists arrive at the Manila Zoo at a rate of 250 vehicles per hour. But before entering the zoo, the vehicles must get a brochure and pay the entrance fee at the single entrance booth. If the vehicles can be serviced at a rate of 400 vehicles per hour, determine the percentage of time that the operator of the single entrance booth will be free.
Note: Round off your answers to the nearest thousandths. Only include the numeric value of vour answer without the unit (i.e. 0.123).
The percentage of time the operator of the single entrance booth will be free is approximately 38.462%.
To determine the percentage of time that the operator of the single entrance booth will be free, we need to calculate the service rate and the arrival rate. The service rate is given as 400 vehicles per hour, and the arrival rate is 250 vehicles per hour. The percentage of time the operator will be free can be calculated using the formula:
Free time percentage = (Service rate - Arrival rate) / Service rate * 100
Substituting the given values into the formula:
Free time percentage = (400 - 250) / 400 * 100
= 150 / 400 * 100
= 0.375 * 100
= 37.5%
Rounding off the answer to the nearest thousandths, the percentage of time the operator of the single entrance booth will be free is approximately 38.462%.
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Why does time seem to flow only in one direction?
Answer:
Time seem to flow only in one direction because if it started to go in backward direction that would break the second law of thermodynamics. We do not find time to be moving in any direction because time is not an object that can move nor is it a force that can move any object.
g speakers a and b are vibrating in phase. they are directly facing each other, and are 1.32 m apart, and are each playing a 700 hz tone. On the line between the speakers there are points where minimum sound intensity occurs
When two speakers are vibrating in phase, it means that they are both moving in the same direction at the same time,
creating a stronger and more focused sound. However, when they are directly facing each other, they can also create interference patterns that result in areas of minimum sound intensity.
These areas are called "nodes" and they occur when the sound waves from each speaker cancel each other out. In this specific scenario, the speakers A and B are 1.32 meters apart and each playing a 700 Hz tone.
The distance between the speakers and the frequency of the tone determine the spacing between the nodes. The distance between each node is equal to half the wavelength of the sound wave.
Assuming the speed of sound is approximately 343 m/s, the wavelength of a 700 Hz tone would be around 0.49 meters.
Therefore, the distance between each node would be approximately 0.245 meters (half the wavelength). Since the speakers are facing each other directly, the nodes would occur along the line between them.
The first node would be located at the midpoint between the speakers (0.66 meters from each speaker), and the next node would be located 0.245 meters away from the first node on either side.
If there are points along this line where minimum sound intensity occurs more than once, it means that there are multiple nodes present in that area.
This can create a unique listening experience, as certain frequencies may be louder or quieter depending on where you are standing.
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A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
Tech A says that an overdrive gear ratio means the input gear turns faster than the output gear. Tech B says that overdrive ratios provide less torque output than underdrive ratios. Who is correct?
Answer:
Technician B only is correct
Explanation:
The gear ratio is the ratio of the output speed to the input speed such that an overdrive gear ratio of more than 1:1, having more speed per speed of engine rotation RPM
Overdrive ratios conditions is one where the vehicle wheels and speed is faster at a given engine rotation, such that there is fuel efficiency is increased as the engine rotation is low for a given speed and distance of travel.
Two joggers run at a constant velocity of 7.5 m/s to the east. At t=0s one jogger is 15 m east of the origin, the other is 15 m west of the origin. How would their position-time graphs look different?
The position-time graphs of the two joggers will look like a rectangle at the given time period.
What is position time graph?A position time graph is a type of graph in which the position x of a particle is plotted on the y-axis and the time t on the x-axis.
The position time graph of the two jogger can be sketched as follows;
| | |
| | |
| | |
|-----------------------------------------|----------------------------------------|
15 m(west) 15 m(east)
The position of both joggers will be same after the given time but their direction will be different.
Thus, the position-time graphs of the two joggers will look like a rectangle at the given time period.
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How did harlow shapley conclude that the sun was not in the center of the milky way galaxy?
We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.
What is the work of Harlow Shapley?Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.
There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.
Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.
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which takes more work, accelerating a car from 10 to 20 m/s or from 20 to 30 m/s? explain why.
The work required is greater for accelerating the car from 20 to 30 m/s than from 10 to 20 m/s.
The effort is greater when the car is accelerated from 20 to 30 m/s than from 10 to 20 m/s due to the change in kinetic energy. This is due to the fact that an object's kinetic energy grows as a function of velocity, hence as velocity rises, so does the amount of work needed to produce a given increase in kinetic energy.
The kinetic energy of an object determines how much labour is necessary to accelerate it from one velocity to another.
The equation: gives the kinetic energy of an item
K = (1/2)mv^2
where
m is the mass of the object
v is its velocity.
We have to find the at which velocity a car required more work to accelerate a car from 10 to 20 m/s or from 20 to 30 m/s we can find it by comparison,
To determine the change in kinetic energy, we may compute the car's kinetic energy at each velocity and then subtract the beginning kinetic energy from the final kinetic energy.
Let's take mass of that the car is 1000 kg.
Case1: accelerating the car from 10 m/s to 20 m/s:
Initial kinetic energy \(= (1/2)mv^2\)
Initial kinetic energy \(= (1/2)(1000 kg)(10 m/s)^2\)
Initial kinetic energy \(= 50,000 J\)
Final kinetic energy \(= (1/2)mv^2\)
Final kinetic energy \(= (1/2)(1000 kg)(20 m/s)^2\)
Final kinetic energy \(= 200,000 J\)
Change in kinetic energy = 200,000 - 50,000
Change in kinetic energy = 150,000 J
Case2: accelerating the car from 20 m/s to 30 m/s:
Initial kinetic energy \(= (1/2)mv^2\)
Initial kinetic energy \(= (1/2)(1000 kg)(20 m/s)^2\)
Initial kinetic energy \(= 200,000 J\)
Final kinetic energy \(= (1/2)mv^2\)
Final kinetic energy \(= (1/2)(1000 kg)(30 m/s)^2\)
Final kinetic energy \(= 450,000 J\)
Change in kinetic energy = 450,000 - 200,000
Change in kinetic energy = 250,000 J
We can see that accelerating the automobile from 10 to 20 m/s results in less effort than accelerating it from 20 to 30 m/s due to the change in kinetic energy.
The automobile must thus put in more effort to accelerate from a greater velocity than from a lower one.
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The camshaft turns at what speed in relation to the crankshaft?
how does increasing and decreasing the temperature affect the kinetic energy of molecules?
Answer:
Amontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas
What is something that you do not like, you can't explain it but, but u know u just don't like it. For me, i don't like closed doors. It makes me feel trapped
Answer:
religion
Explanation:
when I get asked this... what is your religion... I try to explain so the best explanation I can give is
believing in one god is like saying bread can't get wet
What do velocity, acceleration, force, and displacement, have in common?
Velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common
What is a vector quantity?This is a which have both magnitude and direction. Example include:
VelocityDisplacement ForceAccelerationMomentWeightWhat is a scalar quantity?This is a quantity which has magnitude but no direction. Example include:
WorkEnergySpeedMassTimeDistanceFrom the above, we can see that velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common
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A 2-kg mass is attached to a spring whose constant is 18 N/m, and it arrives at the position
of balance. From
t = 0, an external force equal to
f(t)=2sin2t.
Find the resulting equation of motion.
The resulting equation of motion for the system is given by m × x''(t) + k × x(t) = f(t), which is 2 × x''(t) + 18 * x(t) = 2 * sin(2t).
What is equation of motion?
The equations of motion are a set of mathematical relationships that describe the motion of objects under the influence of forces. There are different sets of equations of motion, depending on the specific scenario and the type of motion being considered (linear motion, projectile motion, circular motion, etc.). The equations of motion for linear motion, also known as the equations of uniformly accelerated motion.
To find the equation of motion for the system, we start with Newton's second law of motion, which states that the sum of forces acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the object is the 2-kg mass attached to the spring.
The force exerted by the spring is proportional to the displacement of the mass from its equilibrium position, and it can be expressed as F_spring = -k× x(t), where k is the spring constant and x(t) is the displacement of the mass at time t.
In addition to the force exerted by the spring, there is an external force f(t) = 2 ×sin(2t) acting on the mass.
Applying Newton's second law, we have the equation of motion: m ×x''(t) + k ×x(t) = f(t).
Substituting the given values, m = 2 kg and k = 18 N/m, we obtain 2 ×x''(t) + 18 × x(t) = 2 ×sin(2t).
Therefore, the resulting equation of motion for the system is 2 × x''(t) + 18 × x(t) = 2 × sin(2t).
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Find a unit vector in the direction of the vector [−56/105]. A unit vector in the direction of the given vector is [. (Type integers or simplified fractions.)
The unit vector in the direction of the given vector is [-1, 1/2].
A unit vector in the direction of the given vector [−56/105], we need to normalize the vector by dividing each component by its magnitude.
The magnitude of the vector [−56/105] can be calculated as:
|[-56/105]| = \(\sqrt {((-56/105)^2)\) = \(\sqrt {(3136/11025)\) =\(\sqrt {(56^2 / 105^2\)) = 56/105
Normalize the vector, we divide each component by the magnitude:
[-56/105] / (56/105) = [-56/105] * (105/56) = [-1, 1/2]
a unit vector, we divide each component of the vector by its magnitude.
Dividing [-56/105] by (56/105) yields [-56/105] * (105/56) = [-1, 1/2].
A unit vector in the direction of the given vector is [-1, 1/2]. This means that the vector [-1, 1/2] has the same direction as the original vector [-56/105], but its length or magnitude is equal to 1.
Unit vectors are useful as they represent only the direction of a vector, allowing for easy comparison and calculation without concerns for the vector's scale or magnitude.
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are same side exterior angles congruent or supplementary?
The same-side exterior angles are not congruent, they are supplementary. The same side exterior angles are formed and they have a sum of 180 degrees.
What is meant by congruence?Congruent refers to having the same precise size and shape. Even if we flip, turn, or rotate the forms, their shape and size need to remain constant. If it is possible to superimpose one geometric figure onto the other such that they correspond throughout, then the two are said to be congruent, or to be in the relation of congruence.
In general relativity, a congruence (more precisely, a congruence of curves) is the collection of integral curves of a (never vanishing) vector field in a four-dimensional Lorentzian manifold that is used to physically represent spacetime.
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____________is a cross section of two infinite lines of charge that extend out of the page. Both have linear charge density l. Find an expression for the electric field strength E at height y above the midpoint between the lines.
To find the expression for the electric field strength E at height y above the midpoint between two infinite lines of charge with linear charge density λ, we can use the principle of superposition.
Consider a small section of length dl on one of the lines of charge. The electric field dE produced by this section at point P (midpoint) is given by Coulomb's law:
dE = (k * λ * dl) / (2πε₀r)
where k is Coulomb's constant, ε₀ is the permittivity of free space, and r is the distance from the section dl to point P.
Since the lines of charge are infinite, the electric field contributions from all the sections add up. We integrate this expression over the length of the line of charge:
E = ∫ (k * λ * dl) / (2πε₀r)
Now, we need to express r in terms of y and dl. As the two lines of charge are symmetrically placed with respect to the midpoint,
we have r = √(y² + (dl/2)²).
Substituting this into the integral expression, we have:
E = ∫ (k * λ * dl) / (2πε₀√(y² + (dl/2)²))
Integrating over the length of the line of charge will give the final expression for the electric field strength E at height y above the midpoint between the lines.
Please note that the specific form of the integral will depend on the geometry of the charge distribution, such as the separation between the lines of charge and their orientation.
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Excited sodium atoms emit light in the infrared at 589 nm. What is the energy of a single photon with this wavelength?a. 5.09×10^14Jb. 1.12×10^−27Jc. 3.37×10^−19Jd. 3.37×10^−28Je. 1.30×10^−19J
The energy of a single photon with a wavelength of 589 nm is 3.37 x 10⁻¹⁹ J.
Here correct option is E.
The energy of a photon with a given wavelength can be calculated using the formula: E = hc/λ
where E is the energy of the photon, h is Planck's constant (6.626 x 10⁻³⁴ J·s), c is the speed of light (2.998 x 10⁸ m/s), and λ is the wavelength of the light.
Substituting the given values into the formula, we get:
E = (6.626 x 10⁻³⁴ J·s)(2.998 x 10⁸ m/s)/(589 x 10⁻⁹ m)
E = 3.37 x 10⁻¹⁹ J
Therefore, the energy of a single photon with a wavelength of 589 nm is 3.37 x 10⁻¹⁹ J.
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What is the change of GPE for a 8.0 kg object which is lowered from an initial height of 10 m above the floor to a final height of 4.0 m above the floor?
The change in gravitational potential energy, GPE for the 8 Kg object which is lowered from a height of 10 m to 4 m is -470.4 J
How do I determine the change in potential energy of the object?We'll begin by obtaining the initial potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₁) = 10 mAcceleration due to gravity (g) = 9.8 m/s² Initial potential energy (PE₁) = ?PE₁ = mgh₁
PE = 8 × 9.8 × 10
PE = 784 J
Next, we shall determine the final potential energy. Details below:
Mass of object (m) = 8 KgInitial height (h₂) = 4 mAcceleration due to gravity (g) = 9.8 m/s² Final potential energy (PE₂) = ?PE₂ = mgh₂
PE = 8 × 9.8 × 4
PE = 313.6 J
Finally, we shall determine the change in the potential energy. This is shown below:
Initial potential energy (PE₁) = 784 JFinal potential energy (PE₂) = 313.6 JChange in potential energy (ΔPE) =?ΔPE = PE₂ - PE₁
ΔPE = 784 - 313.6
ΔPE = -470.4 J
Thus, the change in potential energy is -470.4 J
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in most non concealed observation it is best to use _____ disclosure.
In most non-concealed observations, it is best to use overt disclosure.
Overt disclosure refers to openly informing the individuals being observed that they are being watched or studied. This approach is considered ethical and respectful as it allows individuals to provide informed consent and participate willingly in the observation process.
There are several reasons why overt disclosure is preferred in non-concealed observations:
1. Ethical considerations: Overt disclosure respects the rights and autonomy of individuals. It allows them to be aware that they are being observed and gives them the opportunity to give their consent or choose not to participate. Respecting the privacy and dignity of individuals is crucial in research or observational studies.
2. Transparency: Overt disclosure promotes transparency and openness in the research process. It establishes a clear and honest relationship between the observer and the observed. By openly communicating the purpose of the observation, individuals can have a better understanding of the study's objectives and make informed decisions about their involvement.
3. Validity and natural behavior: Overt disclosure can minimize the potential for observer effects and alter the behavior of individuals being observed. When people are aware that they are being watched, they may modify their behavior consciously or subconsciously. By openly disclosing the observation, individuals may feel more comfortable and behave more naturally, leading to more accurate and valid data collection.
4. Trust and cooperation: Overt disclosure helps build trust between the observer and the observed. When individuals are aware that they are being observed and their consent is sought, it fosters a sense of trust and cooperation. This can lead to better participation, more honest responses, and a more positive research environment.
It's important to note that there may be situations where covert or concealed observation is necessary, such as when studying certain sensitive or illegal behaviors where overt disclosure could compromise the validity of the observation. However, in most non-concealed observational contexts, overt disclosure is considered the best practice for ethical and valid data collection. Researchers and observers should always adhere to ethical guidelines and seek institutional review and approval when conducting observations involving human subjects.
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the eye changing light waves into impulses and the ear changing sound waves into impulses are examples of:
The eye changing light waves into impulse and the ear changing sound waves into impulses are examples of transduction.
Transduction is the method of translation of arriving signal into a command transfer to the brain by a sensory receptor. It starts when stimulus changes the membrane potential of a receptor cell, which converts the signal energy in a stimulus and then into an electrical signal. Receptors are categorized into two main categories: exteroceptors, and interoceptors. Exteroceptors receive external sensory stimuli, and interoceptors receive internal sensory stimuli.
in visual system, cone and rods are the sensory cells that convert the physical light energy signal into electrical signal. In auditory system, hair cells transduced the sound vibrations into electrical signal and transfer them to the brain.
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Do you think aksionov is able to get justice in the end? Why?
Measurements of one Paramecium cell performing the barium dance show that it is moving to the left at 100 μm/s before adding barium; five seconds after adding the barium, it is moving to the right at 200 μm/s. The average acceleration of the cell is:
Measurements of one Paramecium cell performing the barium dance show that it is moving to the left at 100 μm/s before adding barium, the average acceleration of the cell is 20 μm/s².
The formula for average acceleration can be used to get the cell's average acceleration:
\(\[ \text{Average Acceleration} = \dfrac{\text{Change in Velocity}}{\text{Time Interval}} \]\)
Given values:
Initial velocity (\(\(v_i\)\)) = 100 μm/s (to the left)
Final velocity (\(\(v_f\)\)) = 200 μm/s (to the right)
Time interval (t) = 5 seconds
The change in velocity is the difference between the final velocity and the initial velocity:
\(\[ \text{Change in Velocity} = v_f - v_i \]\)
Substitute the values:
\(\[ \text{Change in Velocity} = 200 - 100 \\\\= 100\)
Now, plug this into the formula for average acceleration:
\(\[ \text{Average Acceleration} = \dfrac{\text{Change in Velocity}}{\text{Time Interval}}\\\\ = \dfrac{100 }{5 }\)
= 20 μm/s².
Therefore, the average acceleration of the cell is 20 μm/s².
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Which of the following planets or moons has an atmosphere consisting mainly of Hydrogen and Helium with some methane?
A) Venus
B) Saturn
C) Titan
D) Uranus
Saturn is the following planet or moon, and its atmosphere is primarily made of hydrogen with a small amount of methane.
The correct answer is B
What makes Saturn the best planet?The planet Saturn is incredibly large and its rings make it incredibly gorgeous. Amazing moons as Titan reside there as well. The Solar System's Saturn is arguably the most popular and stunning planet. Compared to the rings of other planets, Saturn's are much larger and easier to see.
Where could we possibly live?Then, only a year ago, researchers found a second Earth-like planet around Proxima Centauri, one of our nearest nearby stars. The best option we now have for maintaining human life is this planet.
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A quartz crystal vibrates with a frequency of 56,621 hz. what is the period of the crystal's motion? course hero
The period of an oscillating motion is the time it takes to complete one full cycle. To find the period of the quartz crystal's motion, we can use the formula:
Period = 1 / Frequency
Given that the frequency of the quartz crystal is 56,621 Hz, we can plug this value into the formula to calculate the period:
Period = 1 / 56,621 Hz
By dividing 1 by the frequency, we can determine that the period of the crystal's motion is approximately 0.00001767 seconds.
The period of the quartz crystal's motion is approximately 0.00001767 seconds.
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Who ever gets it right I will give Brainly and 20 points.
Answer:
?
Explanation:
amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. ... Waves are generated by vibrating sources, their amplitude being proportional to the amplitude of the source.
Period refers to the time that it takes to do something. ... The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
.Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time. ... An object with no movement at all has a zero speed.
wavelength, distance between corresponding points of two consecutive waves.
frequency refers to the number of waves that pass a fixed point in unit time. It also describes the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.
When light passes through a narrow slit and undergoes diffraction, what happens to the angular extent of the flaring if we narrow the slit?
- increases
- decreases
- remains
If the slit is narrowed the angular extent of the flaring decreases.
When light passes through a narrow slit, it undergoes diffraction, which causes the light to spread out in a flaring pattern. The angular extent of this flaring refers to the width of the pattern in degrees. As the width of the slit is narrowed, the angular extent of the flaring decreases. This phenomenon can be explained by the principle of diffraction. When light passes through a narrow slit, it diffracts or bends around the edges of the slit.
The amount of diffraction is dependent on the width of the slit, with narrower slits causing greater diffraction. When the width of the slit is increased, the diffraction pattern becomes wider, resulting in a larger angular extent of the flaring. Conversely, when the width of the slit is decreased, the diffraction pattern becomes narrower, resulting in a smaller angular extent of the flaring.
This relationship between slit width and angular extent of flaring is important in various applications such as microscopy and spectroscopy. In microscopy, narrowing the slit can increase the resolution of the image by reducing the amount of diffraction. In spectroscopy, the width of the diffraction pattern can be used to determine the size of the slit and the wavelength of light being diffracted.
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Jose has two bar magnets. He pushes the ends of the two magnets together and then lets it go. The magnets move quickly apart. Which of the following statements best explains why this happens
A.The north poles of the two magnets are facing each other.
B.One magnet is a north pole & one magnet is a south pole.
C.The ends of the magnets repel each other but the centers attract. D.One magnet is storing energy & one magnet is releasing energy.
Answer:
A. like poles repel or push apart