How much effort will be required on the small piston having cross section area zam to lift a lead of 4000N on a large piton having cross sectional area 1m². also calculate pressure exerted on the small piston.​

Answer:

Vận tốc pháp tuyến tỉ lệ với vận tốc góc nhân với bán kính r. T T T là chu kỳ, ω là vận tốc góc và f là tần số. Chu kì tỉ lệ nghịch với vận tốc góc nhân với hệ số 2 π 2 \ pi 2π và tỉ lệ nghịch với tần số.

Answer:

0.238 m/min

Explanation:

The volume of water in the trough V =Ah' where A = area of cross-section = area of isosceles trapezoid = 1/2(a + b)h where a = length of bottom of isosceles trapezoid = 40 cm = 0.4 m, b =  length of top of isosceles trapezoid = 100 cm = 1 m and h = height of isosceles trapezoid = 60 cm = 0.6 m. So,

A = 1/2(a + b)h = 1/2(0.4 m + 1 m)0.6 m = (1.4 m)0.3 m = 0.42 m² and h' = height of water level in trough = H - h" where H = length of trough = 10 m and h" = depth of water level in trough = 10 cm = 0.1 m

So, V = Ah'

V = A(H - h") = A(10 - h")

Now, the rate of change of volume of the trough with respect to time dV/dt = d[A(10 - h")]/dt

dV/dt = -Adh"/dt

dh"/dt = -dV/dt/A

Since dV/dt = 0.1 m³/min, substituting the other variables into the equation, we have

dh"/dt = -dV/dt/A

dh"/dt = -0.1 m³/min/0.42 m²

dh"/dt = -0.238 m/min

This is the rate at which the depth is decreasing

Since the height h' = 10 - h"

dh'/dt = d(10 - h")/dt

= -dh"/dt

= -(-0.238 m/min)

= 0.238 m/min

So the water level is increasing at a rate of 0.238 m/min

Answer:

At constant velocity, his weight equals the force of friction. In other words, there is no net force. If however, he loosens his grip and decreases the friction force, he will accelerate downward.

Explanation:

(a) Velocity with which the mug leaves the counter is approximately 5.02 m/s.

(b) The direction of velocity of mug just before it hits the floor is downwards, since mug is falling under influence of gravity.

Velocity is a quantity that designates how fast and also in what direction a certain point is moving.

(a) As we know, PE = m g h

\(\mathrm{PE = mgh }\)

\(\mathrm{= (m)(9.81 m/s^2)(1.36 m) }\)

= 13.4mJ

\(\mathrm{KE =\frac{1}{2} mv^2}\)

PE = KE

\(\mathrm{mgh = \frac{1}{2}mv^2}\)

\(\mathrm{v = \sqrt{2gh}}\)

\(\mathrm{v = \sqrt{2 \times 9.81 \times 1.36 m}}\)

v = 5.02 m/s

Therefore, the velocity with which the mug leaves the counter is approximately 5.02 m/s.

(b) The direction of the velocity of mug just before it hits the floor is downwards, since mug is falling under the influence of gravity. Velocity vector has a vertical component that points downwards and horizontal component that is parallel to counter.

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Given data

*The given mass is m = 48 g = 48 × 10^-3 kg

*The given initial temperature of the ice is T = -14 °C

*The given temperature of the steam is t = 118 °C

*The specific heat of ice is c = 2090 J/kg °C

*The specific heat of water is s = 4186 J/kg °C

*The specific heat of the stream is 2010 J/kg ° C

*The heat of vaporization is 2.26 x 10^6 J/kg

*The heat of fusion is 3.33 x 10^5 J/kg

The formula for the energy is required to change a 48 g ice cube from ice at -14 °C to

steam at 118 °C is given as

Substitute the values in the above expression as

From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.

An 800-pound man evenly distributes his weight between two bathroom scales while standing still on them. There is a 400N reading on each scale.

A person can measure and monitor their body weight using bathroom scales. Today, several models may offer other data points including body fat percentage & hydration levels.

It measures how strongly gravity pulls on a body. Weight has the same SI unit as just a force since it is a force, namely the Newton (N). Each bathroom scale will register half of the weight when you stand on them with one foot on each one and your weight evenly divided.

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Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.

Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.

To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.

The work done by the air can be calculated using the equation:

Work = Force * Distance * cos(θ)

Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.

In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:

Work = Force * Distance * 0

Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.

However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.

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The velocity of ball after it bounces back elastically toward you is given as : 18.02 m/s.

For the stated question:

The rubber ball will rebound at the same speed plus two times overall speed of the rhino if you suppose that now the rhino is infinitely greater massive than rubber ball (the rhino is also pushing off the earth, so momentum conservation also doesn't follow - it won't slow down).

The equation for the elastic collision;

v1'  = (m - M)/(m+M) * v1 + (2M)/(m+M) * v2

But, M>>m

v1' = -v1 - 2v2

v1 - velocity of rhino : 4.60 m/s.

v2 - velocity of the rubber ball :  6.71 m/s.

speed of the ball after collision:

v1' = -v1 - 2v2

v1' = - 4.60 - 2*6.71

v1' = -18.02 (in the direction in which ball is being thrown).

Thus, the velocity of the ball after it bounces back elastically toward you is given as : 18.02 m/s.

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The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

answer here is 5 hope I'm right

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

Current through them, voltage across them.

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

\( V = IR\)

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

A resistor can be defined as an electronic component that opposes the free flow of current from one point to another in an electrical circuit.

In a series circuit of two resistors, the resistors have the same current through them; in a parallel circuit of two resistors, the resistors have the same voltage across them.

The number of each period in the modern  periodic table represents the number of energy shell of outer electron of the material in that period.

The chemical elements are arranged in rows and columns on what is known as the periodic table, or periodic table of the (chemical) elements. It is frequently used in physics, chemistry, and other sciences and is frequently regarded as a symbol of chemistry.

It is a visual representation of the periodic law, which claims that the atomic numbers of chemical elements have a roughly periodic relationship with their attributes. The table is divided into four blocks that are about rectangular in shape.

The table's columns are referred to as groups and its rows are known as periods. The periodic table's elements in the same group have comparable chemical properties.

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Answer:

"However, there is no actual force applied."

"The passenger is merely continuing in a straight direction."

Explanation:

Am AP Phys student

To calculate the liquid pressure at points A, B, and C in the given diagram, we need to consider the height and density of the liquid.

Let's assume that the liquid in the container is water, which has a density of approximately 1000 kg/m³.

Given:

- Height of column AB = 60 cm = 0.6 m

- Height of column BC = 30 cm = 0.3 m

To calculate the pressure at each point, we can use the formula:

Pressure = density * gravity * height

where:

- Density = 1000 kg/m³ (density of water)

- Gravity = 9.8 m/s² (acceleration due to gravity)

Calculating the pressures:

At point A:

Pressure_A = density * gravity * height_AB

         = 1000 kg/m³ * 9.8 m/s² * 0.6 m

         = 5880 Pascal (Pa)

At point B:

Pressure_B = density * gravity * (height_AB + height_BC)

         = 1000 kg/m³ * 9.8 m/s² * (0.6 m + 0.3 m)

         = 8820 Pascal (Pa)

At point C:

Pressure_C = density * gravity * height_BC

         = 1000 kg/m³ * 9.8 m/s² * 0.3 m

         = 2940 Pascal (Pa)

Therefore, the liquid pressures at points A, B, and C are as follows:

- Pressure at point A = 5880 Pa

- Pressure at point B = 8820 Pa

- Pressure at point C = 2940 Pa

Answer:

24m

Explanation:

you can use the formula

s=ut+1/2at²

s=0+1/2(3)(4)²

=1/2(3)(8)

=24m

I hope this helps

Answer:

it is A  or 20x80 cm

Explanation: DID IT ON APEX

WOO

Answer:

The heat needed to raise the temperature of 1 gallon of water from 68°F to 40°C is approximately 28,265 Joules.

Explanation:

The truck's cargo weighs 2400 N. The department has a mechanical advantage of 4.

Combining hard and soft abilities in areas like arithmetic, computing, design, and interaction make up the talents required for mechanical engineering. Because they operate in a variety of fields, such as the manufacturing, science, and automotive manufacturing, engineers in the mechanical technology profession have one of the broadest scopes.

Longitudinal, transversal, as well as pressure waves are the three different forms of physical phenomena. They differ based on how the medium's atomic constituents behave when the stage's energy goes through. Wind farms that are powered by steam, water, winds, gas, or hydrocarbons are a few examples of this. Other sources of energy are frequently produced through machinery.

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The insect  appears 3cm away from the image shown.

The refractive index is the ratio of the speed of light in a vacuum to the speed of light in a given medium. However, when light passes through a medium with a different refractive index than the surrounding medium, it appears to change direction at the boundary between the two media. This phenomenon is called refraction.

Refractive index = Real depth/ Apparent Depth

3/2 = 9/A

A = 18/3

A = 6 cm

Displacement = 9 cm - 6 cm = 3cm

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The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.

This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.

Potential energy = mgh,

Where

Kinetic energy = (1/2)mv^2,

Where

Equating these two expressions and solving for v, we get:

mgh = (1/2)mv^2

v^2 = 2gh

v = sqrt(2gh)

Plugging in the given values, we get:

v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s

Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.

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As a result, the picture behind the mirror is virtual, upright, and enlarged.

You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.

The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.

Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.

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When a subject has changed and developed over time., it is referred to as evolution. Here we have discussed the evolution of Calculus.

Development of Calculus:

Calculus is a sophisticated area of mathematics that deals mostly with rates of change and issues like calculating areas or volumes within curved surfaces or lines. Calculus was first developed by Newton. Calculus was independently created by German mathematician Gottfried Wilhelm Leibniz, a contemporary of Isaac Newton. Calculus was created by Newton before Leibniz substantially pursued mathematics, as is now widely accepted. The first time calculus became well known, though, was in Leibniz's work from 1684. Today, calculus is the prerequisite for everyone interested in studying physics, chemistry, biology, economics, or finance.

Both planetary motion and the theory of gravitation were studied by Newton. He suggested that the gravitational pull of the Sun is the main reason why planetary orbits are typically elliptical. Newton was questioned about orbital dynamics in 1684 by the British astronomer Edmond Halley. A tract titled De Motu ("On Motion"), which Newton later started to enhance and develop, contained the information he gathered for Halley.

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a) Time period is given by 0.751 b) Displacement is  0.0751 nm c) The wavelength of the electromagnetic radio waves emitted is  225.56 m

T = 1/f

T = 1/(1330*10^3 Hz)

T = 751.88 ns

Time period T = 0.751 us

b) displacement is given by:

x = velocity * Time

x = 100*10^-6 m/sec*0.751*10^-6 sec

x = 0.0751 nm

c) lambda = c/f

lambda = 3*10^8/(1330*10^3 Hz)

lambda = 225.56 m

Displacement, commonly known as length or distance and denoted by the letters d or s, is a one-dimensional variable that represents the separation between two defined points. In the International System of Units (SI), the meter is the common unit of displacement (m). Transferring unfavorable emotions from one thing or person to another is referred to as displacement and is a defensive tactic. To "take out" their rage on a family member, for instance, a person can yell at them if they are upset with their job. Replace, supersede, and supplant are some frequent alternatives to the word "displace."

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This is an exercise in kinetic energy, which is a form of energy associated with the movement of an object and its speed. It is important in many areas of physics, from classical mechanics to modern physics. This form of energy can be transformed into other forms of energy, such as thermal energy, sound energy or electrical energy. The formula for calculating kinetic energy is KE = m * v^2/2, where m is the mass of the object and v is its speed.

Kinetic energy is a fundamental concept in classical mechanics. It is used to analyze the movement of objects and calculate the amount of work required to stop them. When an object is in motion, it has kinetic energy, which is equal to half its mass times its speed squared. If the object collides with another object, some of its kinetic energy is transferred to the second object in the form of work or heat.

Kinetic energy is also important in modern physics. In Einstein's theory of special relativity, the mass of a moving object increases with its speed, which means that its kinetic energy also increases. In fact, the kinetic energy of a moving object is a form of energy that is included in Einstein's famous equation E=mc^2, where E is the energy, m is the mass of the object, and c is the speed of light. . This equation shows how the mass of an object and its energy are related.

Kinetic energy is also important in quantum physics. In quantum mechanics, particles have a property called momentum, which is a measure of their motion. Momentum and kinetic energy are related, and experiments in quantum physics often measure the momentum and kinetic energy of particles.

It tells us that the diver has a mass of 150 kg, and that he jumps from a diving board into the water at a speed of 40 m/s.

We know that the formula for kinetic energy is:

KE = m * v^2/2. We should not do the formula clearance, because we are going to calculate the kinetic energy.

We already know our data from the formula, now we substitute and solve, then

KE = (m × v²)/2

KE = (150 kg × (40 m/s)²)/2

KE = (150 kg × 1600 m²/s²)/2

KE = 120000 J

When the diver enters the water, the kinetic energy is 120,000 J.

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Answer:

The kinetic energy of the diver entering the water is 120,000 Joules.

Explanation:

The kinetic energy (KE) of an object is given by:

\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * m * v^2\)

where:

Plugging in the given values, we get:

\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * (40\: m/s)^2\)

\(\sf\qquad\dashrightarrow KE = \dfrac{1}{2} * 150\: kg * 1600\: m^2/s^2\)

\(\sf\qquad\dashrightarrow KE = \boxed{\bold{\:\:120,000\: J\:\:}}\)

Therefore, the kinetic energy of the diver entering the water is 120,000 Joules.

Answer:

B. The force of gravity that acts on the kitten

Explanation:

Answer:

A, C, E

Explanation:

I put this and got it right.