Answer:
5 ten thousands
Step-by-step explanation:
Ten thousands: 10,000
So...
50,000/10,000=5
5 ten thousands
If the moon is setting at 6 a.m., the phase of the moon must be: a. first quarter b. third quarter c. new d. full e. waning crescent
The phase of the moon that is most likely setting at 6 a.m. is the waning crescent.
If the moon is setting at 6 a.m., we can determine its phase based on its position in relation to the Sun and Earth.
Considering the options provided:
a. First quarter: The first quarter moon is typically visible around sunset, not at 6 a.m. So, this option can be ruled out.
b. Third quarter: The third quarter moon is typically visible around sunrise, not at 6 a.m. So, this option can be ruled out.
c. New: The new moon is not visible in the sky as it is positioned between the Earth and the Sun. Therefore, it is not the phase of the moon that is setting at 6 a.m.
d. Full: The full moon is typically visible at night when it is opposite the Sun in the sky. So, this option can be ruled out.
e. Waning crescent: The waning crescent phase occurs after the third quarter moon and appears in the morning sky before sunrise. Given that the moon is setting at 6 a.m., the most likely phase is the waning crescent.
Therefore, the phase of the moon that is most likely setting at 6 a.m. is the waning crescent.
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How do I determine whether a graph is a function?
Here's a more detailed explanation: To determine if a graph is a function, you can use the vertical line test. The vertical line test states that if you can draw a vertical line that intersects the graph in more than one place, then the graph is not a function.
Determining whether a graph represents a function is an important concept in mathematics, especially in algebra and calculus. A function is a set of ordered pairs where each input is associated with exactly one output.
So, if you take a ruler or a straight edge and place it vertically on the graph, and it intersects the graph in two or more points, then the graph is not a function. This is because if two points in the graph have the same x-value, they must have different y-values, since functions can only have one output for each input.
On the other hand, if you place a vertical line anywhere on the graph and it intersects the graph in only one point, then the graph is a function.
It's also important to remember that a function must also pass the horizontal line test, which means that no horizontal line can intersect the graph in more than one place.
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Your answer is
Dante will run at least 33 miles this week. So far, he has run 15 miles. What are the possible numbers of additional miles he will run?
Use t for the number of additional miles he will run.
Write your answer as an inequality solved for t.
The number of possible additional miles that he needs to run will be 18.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
Dante will run at least 33 miles this week. So far, he has run 15 miles.
Then the number of possible additional miles that he needs to run.
Let t be the number of additional miles he will run. Then the inequality is given as,
15 + y ≤ 33
y ≤ 33 - 15
y ≤ 18
The number of possible additional miles that he needs to run will be 18.
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Find the measure of one interior angle for the following polygon
Answer:
i had the same question myself
Step-by-step explanation:
I need help also
PLEASE HELP! this is due today! Brainlist for right answer!
Answer:
2550.5
Step-by-step explanation:
We have a circle and are asked to find the area.
We know the diameter already, but the formula to find area requires a raidus, which is unknown to us yet.
To find radius, all you need to do is follow \(\frac{d}{2}\). D being diameter.
D = 57.
\(\frac{57}{2}= 28.5\)
The radius is 28.5, now do the formula of area.
\(A = \pi *r^2\)
\(A = \pi *28.5^2\)
\(28.5^2\)
\(812.25\)
\(A=\pi *812.25\)
\(A=3.14 * 812.25\)
\(A = 2550.465\)
Now we need to round to the nearest tenths, since 6 is the knowledge that we round up, round up.
\(2550.5\)
for the cost function c(q) = 100 2q 3q2, the average fixed cost of producing 2 units of output is multiple choice 100. 50. 3. 2.
The given cost function is c(q) = 100 + 2q + 3q^2. We need to find the average fixed cost of producing 2 units of output. An average fixed cost is calculated by dividing the total fixed cost by the quantity produced.
The fixed cost of producing any quantity is c(0) because it is the cost of fixed inputs that do not vary with the level of output.
Substituting q = 0 in the given cost function, we get,c(0) = 100 + 2(0) + 3(0)^2c(0) = 100Therefore, the fixed cost of producing any quantity is $100.
The average fixed cost of producing 2 units of output is obtained by dividing the fixed cost by the quantity produced, which is,$100/2 = $50Therefore, the average fixed cost of producing 2 units of output is $50, i.e., option (B).
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Find the range of the given function y = 3x + 2 for the domain 4 and -4.
Answer:
Range: (-10 , 14)
Step-by-step explanation:
Given information:
Equation: y = 3x +2Domain: (-4 , 4)Range: (x , y)?
Plug in domain of x = -4 and x = 4 into equation to find range.
f(-4) = 3 * -4 + 2 = -10
f(4) = 12 + 2 = 14
Range: (-10 , 14)
The table below represents a quadratic function. Use the data in the table to
determine the domain and range of the function.
x
-1
0
1
4
y
5
3
5
35
The domain is all real numbers and the Range is y ≥ 3.The correct answer is option A.
To determine the domain and range of the quadratic function based on the given table, let's analyze the values.
Domain represents the set of possible input values (x-values) for the function.
Range represents the set of possible output values (y-values) for the function.
From the given data:
x = -1, 0, 1, 4
y = 5, 3, 3, 5, 35
Looking at the x-values, we can see that the function has values for all real numbers. Therefore, the domain of the function is "all real numbers."
Now, let's consider the y-values. The minimum value of y is 3, and there are no y-values less than 3.
Additionally, the maximum value of y is 35. Based on this information, we can conclude that the range of the function is "y ≥ 3" since all y-values are greater than or equal to 3.
Therefore, the correct answer is:A. Domain: all real numbers
Range: y ≥ 3
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The probable question may be:
The table below represents a quadratic function. Use the data in the table to determine the domain and range of the function.
x= -1,0,1,4
y= 5,3,3,5,35
A. Domain: all real numbers Range: y ≥3
B. Domain: all real numbers
Range: x≥0
c. Domain: all real numbers
Range: y ≥0
D. Domain: all real numbers
Range: y ≤3
How many solutions does this equation have?
8n = 10 + 10n
Answer:
1
Step-by-step explanation:
-10n+8n=10
-2n=10
n=-5
So, one solution
Which inequality correctly compares 2/5, 1/8 ,5/7
Answer:
The correct answer is -3.9> -4.5
Step-by-step explanation:
a spring has a natural length of 26 cm. if a 20-n force is required to keep it stretched to a length of 32 cm, how much work w is required to stretch it from 26 cm to 29 cm? (round your answer to two decimal places.) w
We need to determine the change in length and use Hooke's Law. which states that the force required to stretch or compress a spring is directly proportional to the change in length.
Given that the natural length of the spring is 26 cm and the force required to stretch it to 32 cm is 20 N, we can calculate the spring constant (k) using Hooke's Law. Hooke's Law states that F = kx, where F is the force applied, k is the spring constant, and x is the change in length. Rearranging the formula, we get k = F/x. In this case, the change in length is 32 cm - 26 cm = 6 cm, and the force applied is 20 N. Thus, the spring constant is k = 20 N / 6 cm = 3.33 N/cm.
To find the work required to stretch the spring from 26 cm to 29 cm, we need to calculate the force applied for this change in length. The change in length is 29 cm - 26 cm = 3 cm. Using Hooke's Law, the force required is F = kx = 3.33 N/cm * 3 cm = 9.99 N. Finally, we can calculate the work using the formula W = F * d, where W is the work, F is the force, and d is the distance moved. In this case, the distance moved is 3 cm. Therefore, the work required is W = 9.99 N * 3 cm = 29.97 N·cm.
Rounding to two decimal places, the work required to stretch the spring from 26 cm to 29 cm is approximately 29.97 N·cm.
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Given that f(x)= 11x, g(x)= x^2-6x+3, and h(x)= -x+4, find the function (g*h)(x)
*= Multiplication
Please show work thank you
Answer:
Step-by-step explanation:
What is the solution y 2 3x 3 x =- 2?
The solution of the equation y = (2/3)x + 3 is 5/3
The given equation is
y = (2/3)x + 3
The slope of the line is the change in y coordinates with respect to the change in x coordinates.
This is the linear equation in the the slope intercept form
y = mx + b
Where m is the slope of the line
b is the y intercept
y is the y coordinates
x is the x coordinates
The value of x = -2
Substitute the value of x in the equation
y = (2/3) × -2 + 3
Do the arithmetic operations
= -4/3 + 3
Add the numbers
= 5/3
Therefore, the solution is 5/3
I have solved the question in general, as the given question is incomplete
The complete question is:
What is the solution of the equation y = (2/3)x + 3x, when x = -2?
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Can anyone solve this question ?? I have to find the value of unknown sizes
Answer:
Step-by-step explanation:
50 plus 50 is 100 we know that the number left that is 80 that is so a 40 and x 40 as well
Which two ratios represent quantities that are proportional?
Answer:
A is correct (33/18 and 66/26)
Step-by-step explanation:
Both fractions equal 6/5 when fully simplified. All you have to do is divide 18 by 15 and divide 24 by 20. Both of them will equal 1.2.
The correct answer is an option (B)
What is ratio?"It is the comparison of two quantities of the same kind."
What is proportion?"When two ratios are equal then they are said to be in proportion."
For given question,
We need to find two ratios that represent quantities that are proportional.
A.
\(\frac{33}{18}\) and \(\frac{66}{26} = \frac{33}{13}\)
This pair of ratios does not represent quantities that are proportional.
C.
\(\frac{4}{6}=\frac{2}{3}\)
and
\(\frac{9}{12}=\frac{3}{4}\)
So, this pair of ratios does not represent quantities that are proportional.
D.
\(\frac{9}{14}\) and \(\frac{45}{56}\)
This pair of ratios does not represent quantities that are proportional.
B.
\(\frac{18}{15}=\frac{6}{5}\)
and
\(\frac{24}{20} =\frac{6}{5}\)
So, this pair of ratios represents the quantities that are proportional.
The correct answer is an option (B)
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\frac{\sqrt{p}}{2p+\sqrt{p}}=\frac{2\sqrt{p}-q}{3p+q}\ show\ q\ =\ \frac{p\ +\ 2\sqrt{p}}{2\ +2\sqrt{p}}
The value of the given expression: will be \(q = (p + 2\sqrt{p}) / (2 + 2\sqrt{p}).\)
We can start by cross-multiplying the two sides of the equation:
2p + \(\sqrt{p}\) = 2\(\sqrt{p}\) - q
3p + q = (2\(\sqrt{p}\) - q) * (2p +\(\sqrt{p}\)) / (2\(\sqrt{p}\) - q)
Expanding the right-hand side, we get:
3p + q = (2p^2 + 2p\(\sqrt{p}\) - q\(\sqrt{p}\)) / (2\(\sqrt{p}\) - q)
Now, we can multiply both sides by (2\(\sqrt{p}\) - q) to isolate q on one side:
(2\(\sqrt{p}\) - q)(3p + q) = \(2p^2\) + 2p\(\sqrt{p}\)
Expanding the left-hand side, we get:
6p\(\sqrt{p}\) - 2q^2 + 3pq = 2p^2 + 2p\(\sqrt{p}\)
Isolating q^2 on one side:
q^2 - 3pq + 6p\(\sqrt{p}\) - 2p^2 - 2p\(\sqrt{p}\) = 0
Expanding and simplifying the left-hand side, we get:
q^2 - 3pq - 4p\(\sqrt{p}\) + 4p^2 = 0
Now, we can use the quadratic formula to solve for q:
\(q = (3p \Pm \sqrt{(9p^2 + 16p{\sqrt{p}} - 16p^2))} / 2\)
Since q is positive, we take the positive root:
\(q = (3p + \sqrt{(9p^2 + 16p\sqrt{p} - 16p^2))} / 2\)
Expanding and simplifying the square root, we get:
\(q = (3p + \sqrt{(16p))} / 2\)
And finally, substituting \(p = \sqrt{p}^2\), we get:
\(q = (3 + 2\sqrt{p}) / 2\)
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In the figure below, o ll m. Find the values of y and z
Answer: y = 117 and z = 32
Step-by-step explanation:
y: 180 - 63 = 117
z: 180 - 117 (also known as y) = 63 which is the top corner right next to the equation for z, so you do it again. 180 - 63 = 117
then you do 117 + 43 = 160, then 160 divided by 5 = 32
which means that 5(32) - 43 = 117, 5 x 32 = 160 - 43 = 117.
hope this helps
Nikita determines that female freshmen text their parents more often than male students. Does this result express statistical significance, effect size, or practical significance?
This is an example of _____ significance because....
Therefore, in response to the given query, we can state that However, expressions since no data or analysis is offered, it does not mention the statistical significance or impact size of this difference.
what is expression ?In numbers, you can multiply, split, add, or take away. The following is how a phrase is made together: Numeric number, expression, and arithmetic operator The elements of a mathematical expression are integers, factors, and functions. It is feasible to use contrasting words and terms. Any mathematical declaration containing variables, integers, and a mathematical action between them is known as an expression, also known as an algebraic expression. As an example, the expression 4m + 5 is composed of the expressions 4m and 5, as well as the variable m from the provided equation, which are all separated by the mathematical symbol +.
This result has practical importance because it has applications in the real world. In particular, it implies that freshmen male and female may communicate differently, which may have an effect on their total academic and personal experiences. However, since no data or analysis is offered, it does not mention the statistical significance or impact size of this difference.
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Use the substitution formula to evaluate the integral. 2r 3 co² x sin x dx 7/3 O O 129 1024 776 774
The evaluated integral is -2r^3 * (cos^3(x)/3) + C.
To evaluate the integral ∫2r^3 cos^2(x) sin(x) dx, we can use the substitution method. Let's make the substitution u = cos(x), then du = -sin(x) dx.
Substituting these values into the integral, we have:
∫2r^3 cos^2(x) sin(x) dx = ∫2r^3 u^2 (-du)
Now, we can simplify the integral:
∫2r^3 u^2 (-du) = -2r^3 ∫u^2 du
Integrating u^2 with respect to u, we get:
-2r^3 ∫u^2 du = -2r^3 * (u^3/3) + C
Finally, substituting u = cos(x) back into the equation, we have:
-2r^3 * (cos^3(x)/3) + C
Therefore, the evaluated integral is -2r^3 * (cos^3(x)/3) + C.
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Point P is a point on a circle with center point O. Point P is also a point on PQ←→, which is tangent to circle O.
Which of the following describes the relationship between radius OP and tangent PQ←→?
A.) OP and PQ←→ are sometimes perpendicular
B.) OP and PQ←→ are always perpendicular
C.) OP and PQ←→ are never perpendicular.
D.) The relationship is dependent on the placement of point P on the circle.
The radius of the circle and tangent of the circle are perpendicular to each other. Then the correct option is B.
What is a circle?It is the centre of an equidistant point drawn from the centre. The radius of a circle is the distance between the centre and the circumference.
Point P is a point on a circle with a center point O. Point P is also a point that lies on line PQ, which is tangent to circle O.
Then the relationship between radius OP and tangent PQ will be
We know that the radius of the circle and tangent of the circle are perpendicular to each other.
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Find each angle measure
Answer:
1=125
2=55
3=55
4=125
5=125
6=55
7=55
8=125
Step-by-step explanation:
Find the value of x
.
Answer:
x = 9
Step-by-step explanation:
5x + 27 = 45 + 3x
Subtract 3x from both sides
2x + 27 = 45
Subtract 27 from both sides
2x = 18
Divie both sides by 2
x = 9
subtract 6 from 13, them multiply by 2
Answer:
14
Step-by-step explanation:
13-6= 7(2)
7 times 2= 14
So basically 13-6= 7, and anything in parenthesis will multiply, so "7(2)" equals 7x2. If you're multiplying a number by 2, the easiest way if you don't know it, is to add it by itself, so 7+7=7x2 which also equals 14.
hope this helps
The solution of the given equation form would be 14
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
Given that subtract 6 from 13, them multiply by 2
13-6= 7(2)
7 x 2= 14
Thus anything in parenthesis will multiply, we get;
"7(2)" = 7x2.
If you're multiplying a number by 2,
Thus, it is equals 14.
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a croissant shop has plain croissants, cherry croissants, chocolate croissants, almond crois- sants, apple croissants, and broccoli croissants. assume each type of croissant has infinite supply. how many ways are there to choose a) three dozen croissants. b) two dozen croissants with no more than two broccoli croissants. c) two dozen croissants with at least five chocolate croissants and at least three almond croissants. solution: a) we apply stars ’n bars, with stars
a)There are 749,398 ways to choose three dozen croissants.
b)There are 1,013 ways to choose two dozen croissants with no more than two broccoli croissants.
c) There are 4,186 ways to choose two dozen croissants with at least five chocolate croissants and at least three almond croissants.
To solve the given problems, we can use combinations and counting techniques. Let's break down each problem:
a) To choose three dozen croissants, we need to select a total of 36 croissants from the available types. Since each type has an infinite supply, we can select any number of croissants from each type.
This is equivalent to distributing 36 identical objects (croissants) into 6 distinct groups (types of croissants). We can use the stars and bars technique to solve this.
Using the stars and bars formula, the number of ways to distribute 36 croissants among 6 types is:
C(36 + 6 - 1, 6 - 1) = C(41, 5) = 749,398
Therefore, there are 749,398 ways to choose three dozen croissants.
b) To choose two dozen croissants with no more than two broccoli croissants, we can consider different cases:
- 0 broccoli croissants: Choose 24 croissants from the remaining 5 types (excluding broccoli).
- 1 broccoli croissant: Choose 23 croissants from the remaining 5 types.
- 2 broccoli croissants: Choose 22 croissants from the remaining 5 types.
The total number of ways to choose two dozen croissants with no more than two broccoli croissants is the sum of these cases:
C(24, 5) + C(23, 5) + C(22, 5) = 425 + 336 + 252 = 1,013
Therefore, there are 1,013 ways to choose two dozen croissants with no more than two broccoli croissants.
c) To choose two dozen croissants with at least five chocolate croissants and at least three almond croissants, we can again consider different cases:
- 5 chocolate croissants and 3 almond croissants: Choose 16 croissants from the remaining 4 types (excluding chocolate and almond).
- 6 chocolate croissants and 3 almond croissants: Choose 15 croissants from the remaining 4 types.
- 7 chocolate croissants and 3 almond croissants: Choose 14 croissants from the remaining 4 types.
The total number of ways to choose two dozen croissants with the given conditions is the sum of these cases:
C(16, 4) + C(15, 4) + C(14, 4) = 1820 + 1365 + 1001 = 4,186
Therefore, there are 4,186 ways to choose two dozen croissants with at least five chocolate croissants and at least three almond croissants.
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if x=5, y=-3, and z=-7 z=-7, evaluate 3x^2-9y/yz
Naturalists find that the populations of some kinds of predatory animals vary periodically. Assume that the population of foxes in a certain forest varies sinusoidally with time. Records started being kept at time t=0 years. A maximum number, 800 foxes, occurred when t=0.7 years. The next minimum number, 200 foxes, occurred when t=2.9 years. The maximum, 800 foxes, occurred again at t=5.1 years.
a. Sketch the graph of the sinusoidal curve based on the data above.
b. Fit an equation of the form: P(t)=asin(bt-c)+d or P(t)=acos(bt-c)+d to the fox population.
c. Use your model to predict the population at 7 years.
d. What is the first year in which there are 600 foxes (counting from year 0).
Answer:
Step-by-step explanation:
a. Based on the given data, we can sketch the graph of the sinusoidal curve. At t=0.7 years, there is a maximum of 800 foxes. At t=2.9 years, there is a minimum of 200 foxes. At t=5.1 years, there is another maximum of 800 foxes. The graph will have a repeating pattern of peaks and valleys. The x-axis represents time in years, and the y-axis represents the population of foxes.
b. To fit an equation to the fox population, we can use the form P(t)=asin(bt-c)+d or P(t)=acos(bt-c)+d. Let's use the first form. Given the data, we have three key points: (0.7, 800), (2.9, 200), and (5.1, 800). We can use these points to determine the values of a, b, c, and d in the equation. The amplitude a represents half the difference between the maximum and minimum values, which is (800-200)/2 = 300. The period is the time it takes to complete one cycle, which is 5.1 - 0.7 = 4.4 years. Therefore, b = 2π/4.4. The phase shift c can be calculated using one of the maximum points as c = bt - arcsin((P(t) - d)/a). Using the maximum point (0.7, 800), we can solve for c. Finally, d is the vertical shift, which is the average of the maximum and minimum values, (800 + 200)/2 = 500. Substituting these values into the equation, we can obtain the equation for the fox population.
c. To predict the population at 7 years using the model, we substitute t=7 into the equation obtained in part b and solve for P(t).
d. To find the first year in which there are 600 foxes, we set the equation obtained in part b equal to 600 and solve for t.
Note: Without the specific values of a, b, c, and d obtained from the calculations, it is not possible to provide the exact equation, population prediction, or the year with 600 foxes in this response.
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: uspected number of defects for a 1,000-unit production run in the following situations. places and for the number of defects to the nearest whole number. Probability of a defect: Number of defects: of a defect to four decimal places and for the number of defects to the nearest whole number. Probability of a defect: Number of defects: c) What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean? Reducing the process standard deviation causes a in the number of defects.
A) Suspected number of defects in 1,000 unit production run where probability of a defect is 0.01: We are given, Probability of a defect= 0.01Number of units= 1,000 units
Thus, Expected number of defects= Probability of a defect * Number of units Expected number of defects= 0.01 * 1,000 Expected number of defects= 10 defects∴ Suspected number of defects in 1,000 unit production run where probability of a defect is 0.01 is 10.B) Suspected number of defects in 1,000 unit production run where probability of a defect is 0.005: We are given, Probability of a defect= 0.005Number of units= 1,000 units
Thus, Expected number of defects= Probability of a defect * Number of units Expected number of defects= 0.005 * 1,000Expected number of defects= 5 defects∴ Suspected number of defects in 1,000 unit production run where probability of a defect is 0.005 is 5.C) Advantage of reducing process variation: When the process variation is reduced, the standard deviation of the process decreases. This leads to a tighter control of the process that will result in a decrease in the number of defects being produced. Thus, the advantage of reducing process variation is that it results in a decrease in the number of defects being produced.
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How to find the surface area of a rectangular prism
Answer:
A=2(wl+hl+hw)
Step-by-step explanation:
To find the surface area of a rectangular prism, measure the length, width, and height of the prism. Find the area of the top and bottom faces by multiplying the length and width of the prism. Then, calculate the area of the left and right faces by multiplying the width and height.
Pleaseeee helpppppppp
Answer:
B
Step-by-step explanation:
don't take my word for it
which equations would you use the subtraction property of equality to solve? check all that apply. 5 y
answer 5y - 12 = 8.
In order to use the subtraction property of equality to solve equations, the subtraction of the same quantity should be done on both sides of the equation.
Here are the equations in which you can use the subtraction property of equality to solve:7x + 2 = 25-2y = 10-4r = 28-1/3p = 15+9z = -27
The only equation from the options given in the question is 5y - 12 = 8. So, we can use the subtraction property of equality to solve this equation as follows:5y - 12 = 8Add 12 to both sides5y - 12 + 12 = 8 + 125y = 20Divide both sides by 55y/5 = 20/5y = 4 Therefore, the equation in which we can use the subtraction property of equality to solve is 5y - 12 = 8.
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