How many solutions does this equation have?

13 + 6h = –11 + 6h

Answer:

X = {O,B,A,N,D}

Y = {B,U,L,A,C,N}

Step-by-step explanation:

Given

Words: OBANDO and BULACAN,

Such that X and represent either of those words respectively.

Next, is to remove all repetition and assign X and Y to the words as thus:

X = {O,B,A,N,D}

Y = {B,U,L,A,C,N}

Answer: D

Step-by-step explanation: D shows the initial value as 2 and the rate of change as three which is what the problem says

Answer:

Choice D

Step-by-step explanation:

It would be D because it directly graphs what is being asked is shown in the graph. It is also d because I got it right on quizizz. It shows that the initial value is 2 and the rate of change is 3, so therefore the answer is D.

1. (a)  Using a z-table, we can find the probability corresponding to this z-score, which is 0.758. Therefore, the probability that a student's mark is less than 52 is 0.758. (b) To find the number of students whose marks are between 45 and 55, we need to calculate the z-scores for 45 and 55 . The z-score for 45 is (45 - 45) / 10 = 0, and the z-score for 55 is (55 - 45) / 10 = 1.  (c)  The probability corresponding to this z-score is 0.3085. Therefore, the percentage of students whose marks exceed 40 is 1 - 0.3085 = 0.6915, or 69.15%. 2. (a)  So, the probability that a student only has regular study time is 750/1000 - 550/1000 = 200/1000 = 0.2. (b) The probability that a student either has a regular study time or uses reference books is 750/1000 + 550/1000 - 550/1000 = 750/1000 = 0.75. (c) The probability that a student neither studies regularly nor uses reference books is 1 - 0.75 = 0.25.

Therefore, the probability that a student's mark is between 45 and 55 is 0.8413 - 0.3413 = 0.5. Since there are 220 students in the college, the number of students whose marks are between 45 and 55 is 0.5 * 220 = 110.

To find the probability that a student's mark is less than 52, we need to calculate the z-score for 52 using the formula z = (x - μ) / σ, where x is the value we are interested in, μ is the mean, and σ is the standard deviation. So, z = (52 - 45) / 10 = 0.7.

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The curve joining the points P1, P2, P3, and so on is called the involute of a circle.

To construct the locus of the free end of the coir for unwinding through an angle of 360 degrees, as well as the normal and tangent at any point on the curve.

Here are the steps for construction:

1. Draw a line PQ that is tangent to the circle and is equal to the circumference of the circle. This line represents the coir being unwound.

2. Divide both the circle and the tangent line into the same number of equal parts. Label these divisions on the circle as 1, 2, 3, and so on. Similarly, label the divisions on the tangent line as 1', 2', 3', and so on.

3. Draw tangents at points 1, 2, 3, and so on on the circle. Mark the points where these tangents intersect the tangent line as P1, P2, P3, and so on.

The distance from each point Pi to the corresponding point i' on the tangent line should be the same as the distance from the center of the circle to the point i on the circle.

4. The curve joining the points P1, P2, P3, and so on is called the involute of a circle. This curve represents the locus of the free end of the coir as it unwinds.

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The process involves creating an initial circle that represents the drum, then using this to draw a horizontal line that's the same length as your first circle's circumference. Divide both into segments and draw lines (tangents) from one set of segments to the other. Points along these lines represent an unwound thread and create the involute when joined up. Tangents and normals can also be drawn onto this curve.

This question pertains to the mathematical concept of a curve locus, specifically the spiral curve produced by unwinding a coir from a drum. To draw this spiral curve (or 'involute'), start by sketching a circle representing the drum (with diameter 30mm). Next, calculate the circumference of this circle and draw a horizontal line of equivalent length. Then, divide this line and the circumference of your circle into the same number of equal sections. For each section in your circle, draw a line from the point of division to an equivalent point on your horizontal line. These lines are your tangents. Mark points on these lines which correspond to the distances covered by the unwound thread. Finally, join these points to create the involute of the circle.

For the part about drawing a normal and a tangent at any point on the curve: Pick a point on the curve. Remember that the tangent at a point on an involute is perpendicular to the line from the point to the centre of the original circle. A normal at any point on a curve is simply a line drawn perpendicular to the tangent at that point.

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Answer:

-43

Step-by-step explanation:

-1-7(6)

-1-42

-43

Answer:

Exponente positivo

Potencias de 10

Escribe estos números en forma ordinaria:

           7'3·103;  4'724·108; 8'24·105

Notación científica. Orden de magnitud. Comparaciones

Expresa en notación científica las siguientes cantidades e indica su orden de magnitud.

235'74; 1985; 12 billones; 320 millones; 37.800.000.000; 220.000.

La desaparición de los dinosaurios ocurrió hace 65 millones de años, aproximadamente 108 años. Por ello hemos situado la D debajo de la potencia correspondiente:

El nacimiento del Universo (U) ocurrió hace 15 mil millones de años . Sitúa U en la casilla que le corresponde. Haz lo mismo con:

El califato cordobés de Abderramán (A): aproximadamente 800 años.

El control, del fuego (F): hace 600.000 años.

Aparición del hombre de Cromagnon (C): 30.000 años.

El nacimiento de la Tierra: (T): 4.5 mil millones de años.

El primer paso del hombre en la Luna (L): hace una veintena de años.

El primer paso del hombre en la Tierra (H): tres millones de años

La invención de la imprenta por Gutenberg (G): hace 550 años.

La nebulosa "Triangulum" está a 1'4·1022  metros de la Tierra. Escribe esta distancia en forma ordinaria.

Step-by-step explanation:

Answer:

Step-by-step explanation:

9+k=10

k=1

Step-by-step explanation:

Hey there!

Simply work with it.

As it is a Right angled triangle, taking angle 40° as a reference angle. Then,

Length of board = hypotenuse = 15 feet.

To find: height of ladder = perpendicular.

Now,

Taking sin ratio,

\( \sin = \frac{p}{h} \)

\(sin \: 40 = \frac{p}{15} \)

or, as in per the given sin value is 0.6428

so,

\(0.6428 = \frac{p}{15} \)

or, 15 × 0.6428 = p

or, p = height of ladder = 9.642.

Therefore, p = height of ladder = 10 feet. { rounding off we get 10 feet as answer}.

Hope it helps...

Answer:

Part 1) The fractions in the list are not equal to the decimal number indicated

Part 2) The fractions 401/99 and 802/198 are equal to the decimal number indicated.

Part 1)

we have the decimal number

4.05 -----> is a terminating decimal ( t's a decimal with a finite number of digits)

Convert to fraction number

Multiply and divide by 100

Simplify

Divide by 5 both numerator and denominator

therefore

The fractions in the list are not equal to the decimal number indicated.

Part 2) we have

4.050505... ------> is a repeating decimal (is a decimal that has a digit, or a block of digits, that repeat without ever ending)

Let

x=4.050505...

we have that

Multiply by 2 both numerator and denominator

therefore

The fractions 401/99 and 802/198 are equal to the decimal number indicated.

Step-by-step explanation:

The solution is: the value of x  is x = √2+√2+√2+..... = 2.

We have to find the value of x = √2+√2+√2+.....

First take squares on both sides, then,

⇒ x² = 2 + √2+√2+√2+.....

As the terms inside the square roots are non terminating, we can substitute x =√2+√2+√2+.....  into the above equation.

i.e.,  x² = 2 + x

⇒ x² - x -2 = 0

This is a quadratic equation which can be solved using factorization.

⇒  x²+(-2+1)x +(-2.1) = 0

⇒ (x-2)(x+1) = 0

So x = 2 or -1

But here the value of √2 is positive and square root of sum of positive numbers will always be positive.

So we can conclude that

x = √2+√2+√2+..... = 2

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complete question:

Devise a plan to find the value of x .

x= √2 + √2+ √2+.

To construct a box plot from the given data, which represents the diameters of cans in an assembly line, we need to determine the five-number summary and plot the corresponding box and whisker plot.

The five-number summary consists of the minimum value, the first quartile (Q1), the median (Q2), the third quartile (Q3), and the maximum value.

To construct the box plot, we start by arranging the data in ascending order: 5.1, 5.2, 5.2, 5.2, 5.3, 5.5, 5.5, 5.5, and 5.6. The minimum value is 5.1, and the maximum value is 5.6. The median is the middle value, which in this case is 5.3.

To find the first quartile (Q1) and the third quartile (Q3), we divide the data into two halves. Q1 is the median of the lower half, which consists of 5.1, 5.2, 5.2, and 5.2. Q3 is the median of the upper half, which consists of 5.5, 5.5, 5.5, and 5.6. The box plot will show the minimum value, Q1, Q2 (median), Q3, and the maximum value, giving us a visual representation of the distribution and variability of the data.

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The answer of the above question is 1 point.

When you successfully score a basket from the free-throw line, you are awarded 1 point in a basketball game.

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you get one point when you successfully make a free throw from the free-throw line in basketball.

A free throw is awarded to a team when an opposing player commits a foul, and it is an opportunity for the fouled team to score without any defensive pressure. The free throw line is located 15 feet from the basket, and the shooter must shoot the ball within 10 seconds while staying behind the line until the ball leaves their hand. In

when a player successfully makes a free throw from the free-throw line, they earn one point for their team.
When you throw from the free-throw line, you are awarded 1 point per successful shot.

In basketball, a free-throw is attempted from the free-throw line, which is located 15 feet (4.57 meters) away from the backboard. Free-throws are typically awarded due to fouls committed by the opposing team or other specific situations. Each successful free-throw made scores 1 point for the shooting team.

In conclusion, throwing from the free-throw line can earn you 1 point per successful shot in a basketball game.

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The correct statement regarding the variation of the two measures is given as follows:

C. Yes, they vary directly. When one quantity increases, the other quantity also increases.

For this problem, we have that when the number of correct answers on the test increases, the score also does, hence the two quantities vary directly, and option c is the correct option for this problem.

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The null hypothesis is always the statement that we are trying to reject and the alternative hypothesis is the statement that we want to support.

In the video game satisfaction rating case, the manufacturer of the XYZ-Box wishes to use the random sample of 62 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42.

Now, we need to set up the null hypothesis H0 and the alternative hypothesis Ha if we want to attempt to provide evidence supporting the claim that μ exceeds 42.

Null Hypothesis: H0: μ ≤ 42 (the mean composite satisfaction rating for the XYZ-Box is less than or equal to 42)Alternative Hypothesis:

Ha: μ > 42 (the mean composite satisfaction rating for the XYZ-Box exceeds 42)

Note that the null hypothesis is always the statement that we are trying to reject and the alternative hypothesis is the statement that we want to support.

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Answer:

the bottom right graph represents a single function.

Step-by-step explanation:

Answer:

$240

Step-by-step explanation:

I = prt

I = (2,400) (0.04) (2.5)  

note: I changed 4% to a decimal and 30 months to 2.5 years

I = 96 (2.5)

I = 240   <-- The interest

------------------------------------------------------------------------------------------------------------

The simple interest accumulated on a principal of $ 2,400.00  at a rate of 4% per year for 2.5 years (30 months) is $240.00.

---------------------------------------------------------------------------------------------------------

* Last time I did interest was in 6th grade and I don't remember much. So I am very sorry if my answer is wrong *

The correct number line showing the solution to the inequality is the one with an open circle at 16 and the shaded region to the left.

To find the solution to the inequality x/4 + 1 < 5, we need to solve it step by step and represent the solution on a number line.

First, let's isolate the variable x by subtracting 1 from both sides of the inequality:

x/4 < 5 - 1

x/4 < 4

To eliminate the fraction, we can multiply both sides of the inequality by 4:

4 * (x/4) < 4 * 4

x < 16

Now, we have the solution x < 16.

To represent this solution on a number line, we need to mark the number line with the values and include an open circle at 16 to indicate that it is not included in the solution. Then, we shade the area to the left of 16 since the inequality is less than.

Here is the representation on a number line:

```

--------------------------------------------------------------

               16

```

The shaded part of the number line represents the solution to the inequality x/4 + 1 < 5, which is x < 16.

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Evaluating the integral-  \(\int_0^1 (u+2)(u-3) du\) we get the simplified answer = -37/6.

Let's evaluate the integral as follows -

\(\int_0^1 (u+2)(u-3) du\)

now lets multiply the expression and we will get,  

\(= \int_0^1 u^2-u-6 d u\)

Distributing the integrals to each expression.

\(= \int_0^1 u^2 d u+\int_0^1-u d u+\int_0^1-6 d u\)

By the Power Rule, the integral of \($u^2$\) with respect to u is  \($\frac{1}{3} u^3$\).

\(= \left.\frac{1}{3} u^3\right]_0^1+\int_0^1-u d u+\int_0^1-6 d u\)

Since -1 is constant w.r.t u, move -1 out of the integral of the second term.

\(= \left.\frac{1}{3} u^3\right]_0^1 -\int_0^1u d u+\int_0^1-6 d u\)

By using the power rule, the integral of \($u^2$\) w.r.t to u is \($\frac{1}{2} u^2$\)

\(= \left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{1}{2} u^2\right]_0^1\right)+\int_0^1-6 d u\)

Let's Combine \($\frac{1}{2}$\) and \($u^2$\).

\(= $$\left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{u^2}{2}\right]_0^1\right)+\int_0^1-6 d u$$\)

Now, apply the constant rule,

\(= $$\left.\left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{u^2}{2}\right]_0^1\right)+-6 u\right]_0^1$$\)

Substituting the limits and simplifying we get,

= -37/6

Hence, the simplified answer for the given integral \(\int_0^1 (u+2)(u-3) du\) is -37/6.

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The complete question is-

Evaluate the integral-  \(\int_0^1 (u+2)(u-3) du\).

Answer:

Step-by-step explanation:

Step one:

given data

actual reading= 350°F

thermometer reading 2% of the actual reading

Step two:

Required:

The thermometer reading

let us find 2% of 350°F

2/100*350°

=0.02*350

=7°F

Hence the thermometer reading is 7°F greater than  350°F

The thermometer reading is 350+7=357°F

Both functions decrease at (-1, 2)

The complete question is added as an attachment

The polynomial function f(x) is represented by the graph.

From the graph, the polynomial function decreases at (-2, 2)

The absolute function is given as;

f(x) = =5|x + 1| + 10

The vertex of the above function is

Vertex = (-1, 10)

Because a is negative (a= -5), the vertex is a maximum.

This means that the function decreases at (-1, ∞)

So, we have

(-2, 2) and (-1, ∞)

Combine both intervals

(-1, 2)

This means that both functions decrease at (-1, 2)

See attachment 2 for the number line that represents the interval where both functions are decreasing

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Minimal sedation is characterized by c) less than 50% N2O in the first stage of the continuum.

Minimal sedation is defined as a state in which the patient is able to respond normally to verbal commands, breathe on their own and maintain stable blood pressure and heart rate. It is achieved by administering a small dose of a sedative or anxiolytic medication.

Minimal sedation is a light form of sedation that allows the patient to remain conscious and responsive throughout the procedure, and it helps the patient to relax and reduce anxiety.

It is considered a safer option than deeper forms of sedation as the patient remains able to breathe on their own, which reduces the risk of complications. This level of sedation is often used in procedures such as dental work, minor skin procedures, and diagnostic tests.

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Let r be a partial order on set S, and let t be a subset of S. If a and a' are both elements of t, where a is the greatest element and a' is a maximal element, then it can be proven that a = a'.

To prove that a = a', we consider the definitions of greatest and maximal elements. The greatest element in a set is an element that is greater than or equal to all other elements in that set. A maximal element, on the other hand, is an element that is not smaller than any other element in the set, but there may exist other elements that are incomparable to it.

Given that a is the greatest element in t and a' is a maximal element in t, we can conclude that a' is not smaller than any other element in t. Since a is the greatest element, it is greater than or equal to all elements in t, including a'. Therefore, a is not smaller than a'.

Now, to prove that a' is not greater than a, suppose by contradiction that a' is greater than a. Since a' is not smaller than any other element in t, this would imply that a is smaller than a'. However, since a is the greatest element in t, it cannot be smaller than any other element, including a'. This contradicts our assumption that a' is greater than a.

Hence, we have shown that a is not smaller than a' and a' is not greater than a, which implies that a = a'. Therefore, if a is the greatest element and a' is a maximal element in t, then a = a'.

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Yes, you can be confident that your portfolio will not lose more than 30% in value over the next year.

the reason is

For this question, the portfolio has an average return of 12.5% ​​with a standard deviation of 19.5%. It is estimated that next year will be a 30% loss. Confidence intervals are 95%.

Range = Average return ± 2 x Standard deviation Low aid = 12.5% - (2 x19.5%) =12.5% -39% = -26.5%

High end = 12.5% +(2 x19.5%) =12.5%+39% = 51.5%

Thus, the low end is 26.5%

Returns range from -26.5% to 51.5% with 95% confidence intervals

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Answer:

Salma = 33 text messages

Ali = 72 text messages

Jose = 24 text messages

Step-by-step explanation:

Let "s" be the number of text messages Salma sent.

Let "a" be the number of text messages Ali sent.

Let "j" be the number of text messages Jose sent.

From the given information and defined variables, create a system of equations:

\(\begin{cases}s + a + j = 129\\a = 3j\\s=j+9\end{cases}\)

Substitute the second and third equations into the first equation to create an equation with only the variable j:

\(s+a+j=129\)

\(j+9+3j+j=129\)

Solve for j:

     \(5j+9=129\)

\(5j+9-9=129-9\)

           \(5j=120\)

     \(5j \div 5=120 \div 5\)

             \(j=24\)

Therefore, Jose sent 24 text messages.

Substitute the found value of j into the second and third equations to find the values of a and s:

\(a=3(24)=72\)

\(s=24+9=33\)

Therefore, Ali sent 72 text messages and Salma sent 33 text messages.

Therefore, in conclusion:

\(\\ \sf\longmapsto \dfrac{BM}{AM}=\dfrac{BN}{CN}\)

\(\\ \sf\longmapsto \dfrac{12}{x}=\dfrac{6}{2}\)

\(\\ \sf\longmapsto 6x=24\)

\(\\ \sf\longmapsto x=4\)

_______

\( \: \)

\( \sf{ \frac{12}{x} = \frac{6}{2}} \)

\( \sf{6x = 12 \times 2}\)

\( \sf{6x = 24}\)

\( \sf{x = \frac{24}{6}} \)

\( \sf{x = \bold{4}}\)

Soo :

Ab = 12 + 4 = 16 (C.)

Answer:

x=34

Step-by-step explanation:

so since the two lines are parallel, those two angles are corresponding. In other words, equal.

(x+27)=(2x-7)

subtract x from both sides: 27=x-7

add 7 to both sides: 34=x

Answer:

(x+27)=(2x-7)

Step-by-step explanation:

They are equal to each other

Answer:

24 Square Feet.

Step-by-step explanation:

Answer: The probability that less than 4 of the 7 adults need correction for their eyesight is approximately 0.1637.

Step-by-step explanation:

This problem can be solved using the binomial distribution, which models the probability of a certain number of successes in a fixed number of independent trials, each with the same probability of success.

Let X be the number of adults among the 7 randomly selected who need correction for their eyesight. Then X follows a binomial distribution with parameters n = 7 (the number of trials) and p = 0.7 (the probability of success in each trial).

We want to obtain  the probability that less than 4 of the 7 adults need correction for their eyesight. This can be written as:

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

To calculate each of these individual probabilities, we can use the formula for the binomial probability mass function:

P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k successes from n trials.

Using this formula, we can calculate each of the probabilities:

P(X = 0) = (7 choose 0) * 0.7^0 * 0.3^7 = 0.0002

P(X = 1) = (7 choose 1) * 0.7^1 * 0.3^6 = 0.0032

P(X = 2) = (7 choose 2) * 0.7^2 * 0.3^5 = 0.0292

P(X = 3) = (7 choose 3) * 0.7^3 * 0.3^4 = 0.1311

Summing these probabilities, we get:

P(X < 4) = 0.0002 + 0.0032 + 0.0292 + 0.1311 = 0.1637

Therefore, the probability that less than 4 of the 7 adults need correction for their eyesight is approximately 0.1637.

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