How many significant figures are in 100.3

Answer:

Explanation:

solidos disueltos totales TDS

okAnswer:

Explanation:

yep

The characteristic of elemental bromine reacting vigorously with elemental sodium metal to form a white solid represents a chemical property.

Chemical characteristics define how substances react or change chemically. A white solid forms when elemental bromine and sodium metal combine, suggesting a chemical transition.

However, a substance's physical attributes can be detected or quantified without changing its chemical composition. Colour, density, melting, and boiling points are physical qualities.

It is a chemical property of elemental bromine to react with sodium metal and generate a new compound.

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21.3 days will be taken to consume 1000kg glucose.

Fermentation is an alcoholic process where 1 molecule of glucose is converted to 2 molecules of CO2 and 2 molecule of ethanol/ethyl alcohol.

Fermentation takes place in absence of oxygen, which means in anaerobic conditions.

It takes place in presence of enzyme zymase.

The formula for alcoholic fermentation,

C6H12O6 -> 2C2H5OH + 2CO2

From the data given,  we know

5 hr. = 8 kg alcohol.

Days to consume = 1000 kg glucose.

Mol ethanol:

5000/46 = 108.7 moles.

1/2 X 108.7 = 54.35

hence, 54.35 moles are produced in 5 hours.

moles of 1000kg of glucose:

10⁶g/180g/mol = 5555.5 moles.

so for 5555.5 moles the days we need is

5555.5/54.35 X 5 hours

= 511.085h

= 21.3 days.

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Answer:

\(m_{undissolved}=27g\)

Explanation:

Hello,

In this case, we first define the solubility as the maximum amount of a solute that is completely dissolved in an specific amount of solvent and it is temperature-dependent. Thus for potassium iodide, its solubility at 30°C is 153 g per 100 cm3 of water, therefore, with the given amount, the undissolved amount results:

\(m_{undissolved}=180g-153g=27g\)

Best regards.

The answers include the following:

Tendons are connective fibrous tissues that attaches muscle to bone and they have a bright white color together with a strong and smooth appearance which can be observed when studied.

Tendons are very important as they help in ensuring that the movement of parts of the body are easy due to its holding some structures such as ligaments in place. It is present in all bone joints due to its numerous functions in the musculoskeletal system of organisms.

The tendon is very flexible and binds the muscles in the body to other structures which is why it is referred to as a connective tissue and the above answers are the most appropriate.

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The possible causes of bedding in sedimentary rocks can include:

ii. Change in climate

iv. Discrete events

v. Change in sea level

vi. Change in sediment supply

vii. Change in currents

Layering in sedimentary rocks, as well as occasionally in metamorphic rocks, is known as bedding. Bedding can happen when a fresh layer of sediment is deposited on top of an older layer of sediment or when exposed sedimentary rock receives a new layer of sediments.

Since the bigger, older grains lie towards the base of the bed, bedding may be used to identify the oldest and youngest rocks in a sedimentary succession. One of the geologist's most crucial tools for understanding Earth's history is understanding the origin, make-up, and interpretation of bedding variation.

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Answer:

true

Explanation:

hope this helps

Plants can be defined as multicellular organisms that has the ability to manufacture or produce their own food.

The multicellular organisms are those organisms that are made up of various cells which work together to maintain the functionality of the living organism.

The plant can be described as a multicellular organism as it contains cells such as:

The plants are also has the ability to manufacture their own food due to the presence of the green pigment called the chloroplast.

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The enthalpy of the reaction as written is approximately 239,306 J/mol.

To calculate the enthalpy of the reaction, we need to use the heat released (2330 J) and the amount of sodium reacted (0.224 g) to determine the heat released per mole of sodium reacted.

The molar mass of sodium (Na) is 22.99 g/mol.

First, we need to calculate the number of moles of sodium reacted:

Number of moles of Na = Mass of Na / Molar mass of Na

Number of moles of Na = 0.224 g / 22.99 g/mol ≈ 0.00974 mol

Next, we can calculate the enthalpy change (ΔH) per mole of sodium reacted:

ΔH = Heat released / Number of moles of Na

ΔH = 2330 J / 0.00974 mol ≈ 239306 J/mol

Enthalpy (H) is a thermodynamic property that represents the total heat content of a system at constant pressure. It includes the internal energy of the system plus the product of pressure and volume. Enthalpy is often used to describe heat changes in chemical reactions, where the difference in enthalpy between the reactants and products determines whether a reaction is exothermic (releases heat) or endothermic (absorbs heat). Enthalpy is typically measured in joules (J) or kilojoules (kJ).

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If a mixture of 0.0333 g of hydrogen and 0.0165 mol of oxygen in a closed container is sparked to initiate a reaction. 0.2976 grams of water will be formed.

If the hydrogen reacted has a mass of 0.0333 g. then

Molar mass = m / n

2.016 g/mol = 0.0333 g / n

n = 0.01651785714 mol \(H_{2}\)

According to the actual reaction to make water:

\(2H_{2} +O_{2} = 2H_{2}O\)

To produce two molecules of water (\(H_{2}O\)), two molecules of diatomic hydrogen (\(H_{2}\)) must be combined with one molecule of diatomic oxygen (\(O_{2}\)) and energy will be released in the process. And to complete the process, one from the reactant side must be in equilibrium with the other or in excess.

If the number of moles of 0.0333 g of \(H_{2}\) is 0.0165, then it only needs 0.00826 mol of \(O_{2}\) to form 0.0165 mol of water. (oxygen is in excess)

\(n_{H_{2} } : n_{O_{2} } :n_{H_{2}O } =\) 2 : 1 : 2

= 0.0165 : 0.00826 : 0.0165

If the water produced is 0.0165 mol, then its mass is:

Molar mass = m / n

18.01528 g/mol = m / 0.01651785714 mol

m = 0.2975738214 g

m = 0.2976 g

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Answer:Sexual reproduction produces offspring with novel combinations of genes

Explanation:

yes

CH3CH2OCH2CH3 is best classified as a Brønsted-Lowry base and a Lewis base. This is because the oxygen atom is electron-rich, and thus can donate electrons to form a bond.

This makes the molecule an acceptor of hydrogen ions (H+), which classifies it as a Brønsted-Lowry base. In addition, the oxygen atom is also electron-rich, which makes it a Lewis base, meaning it can donate electrons to form a bond.

Brønsted-Lowry acids are molecules that can donate a hydrogen ion (H+), and Brønsted-Lowry bases are molecules that can accept a hydrogen ion (H+). Lewis acids are molecules that can accept electrons to form a bond, and Lewis bases are molecules that can donate electrons to form a bond.

CH3CH2OCH2CH3 can act as both a Brønsted-Lowry base and a Lewis base, since it can both accept a hydrogen ion (H+) and donate electrons to form a bond.

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Answer:

The periodic table

The periodic table is a tabular array of the chemical elements organized by atomic number, from the element with the lowest atomic number, hydrogen, to the element with the highest atomic number, oganesson. The atomic number of an element is the number of protons in the nucleus of an atom of that element.

Explanation:

False. It can be helpful to perform multiple titrations of the unknown acid in order to obtain a more precise and accurate average value for the concentration of the acid.

In the experiment of titrating an unknown acid with a standardized base, doing more than one fine titration of the unknown acid can be helpful. The purpose of titration is to determine the exact amount of a substance in a sample.

The first titration can provide an approximate value, but it may not be precise enough. By performing multiple titrations, it is possible to calculate the average volume of the titrant needed to reach the endpoint, which can lead to a more accurate result.

Additionally, if the results of the titrations are not consistent with each other, it may indicate that something went wrong in the procedure or that the sample is not uniform. In this case, repeating the titration can help to identify and correct any errors.

Therefore, performing more than one fine titration of the unknown acid can be helpful in ensuring accuracy and identifying potential errors in the experimental procedure.

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Answer:

More than 30

Explanation:

There are more than More than 30 STDs

Answer:

Obtain the relative numbers of atoms of each element in the compound by dividing the number of moles of each element in the 100 g sample by the number of moles of the element present in the smallest amount.

Answer:

Obtain the relative numbers of atoms of each element in the compound by dividing the number of moles of each element in the 100 g sample by the number of moles of the element present in the smallest amount.

Answer:

2. Chemical tests to distinguish between unlabelled samples of the following solutions and their expected observations are:

a) Sodium sulfate and calcium nitrate: Add dilute hydrochloric acid to the unknown solution. Calcium nitrate will produce a white precipitate while sodium sulfate will not produce any precipitate.

b) Sodium sulfate and sodium nitrate: Add silver nitrate solution to the unknown solution. Sodium nitrate will produce a white precipitate of silver chloride while sodium sulfate will not react.

c) Strontium nitrate and strontium hydroxide: Add dilute hydrochloric acid to the unknown solution. Strontium hydroxide will produce a white precipitate while strontium nitrate will not produce any precipitate.

d) Barium chloride and lithium chloride: Add a few drops of dilute sulfuric acid to the unknown solution, followed by a few drops of a solution of potassium dichromate. Barium chloride will produce a green color while lithium chloride will not show any color.

3. Compound A giving a lilac flame test color and producing a white precipitate when added to a solution of barium chloride indicates the presence of potassium ion (K+). Therefore, compound A is most likely potassium chloride (KCl).

Answer:

An Atom

Explanation:

This is the smallest unit which still has the properties of an element.

The balanced redox reaction can be separated into two half-reactions: the oxidation half-reaction and the reduction half-reaction. Oxidation half-reaction: 2Cl^- → Cl2 + 2e^-, Reduction half-reaction: Cl2 + 2e^- → 2CuCl

In the oxidation half-reaction, chloride ions (Cl^-) are oxidized to form chlorine gas (Cl2) and release two electrons (2e^-). This represents the loss of electrons, which is characteristic of an oxidation process. In the reduction half-reaction, chlorine gas (Cl2) gains two electrons (2e^-) to form copper chloride (CuCl). This represents the gain of electrons, which is typical of a reduction process. When combined, the two half-reactions form the overall balanced redox reaction: 2Cl^- + Cl2 → 2CuCl.

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Answer:

Answer:122 g/ mol

Answer:122 g/ molExplanation:

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compound

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses46+28+48 = 122g/mol

The molecular weight of \(\rm Na_2SiO_3\) (sodium silicate) is approximately 122.07 g/mol.

To calculate the molecular weight of \(\rm Na_2SiO_3\) (sodium silicate), we need to add the atomic weights of each individual element in the compound.

The atomic weights are as follows:

- Sodium (Na) = 22.99 g/mol

- Silicon (Si) = 28.09 g/mol

- Oxygen (O) = 16.00 g/mol

Now, multiply the atomic weights by the number of atoms in the compound:

- Sodium (Na) = 2 atoms * 22.99 g/mol = 45.98 g/mol

- Silicon (Si) = 1 atom * 28.09 g/mol = 28.09 g/mol

- Oxygen (O) = 3 atoms * 16.00 g/mol = 48.00 g/mol

Finally, add up all the atomic weights:

\(\rm \[Molecular \, weight \, of \, Na2SiO3 = 45.98 g/mol + 28.09 g/mol + 48.00 g/mol \\= 122.07 g/mol\]\)

So, the molecular weight of \(\rm Na_2SiO_3\) (sodium silicate) is approximately 122.07 g/mol.

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If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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In 0.75 moles of caffeine, there are a total of 6 carbon atoms, 7.5 hydrogen atoms, 3 nitrogen atoms, and 1.5 oxygen atoms.

To determine the total number of atoms in 0.75 moles of caffeine, we need to consider the molecular formula of caffeine, which is C8H10N4O2. The molecular formula provides the ratios of each element present in the compound. By multiplying the number of atoms in each element by the corresponding coefficient in the molecular formula, we can calculate the total number of atoms. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms in each molecule of caffeine. Multiplying these values by 0.75 moles will give us the total number of atoms in 0.75 moles of caffeine.

The molecular formula of caffeine, C8H10N4O2, provides the number of atoms for each element present in one molecule of caffeine. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To calculate the total number of atoms in 0.75 moles of caffeine, we need to multiply the number of atoms for each element by the coefficient in the molecular formula, and then multiply that by the number of moles (0.75 moles).

For carbon (C): 8 atoms x 0.75 moles = 6 atoms (since there are 8 carbon atoms in one molecule of caffeine).

For hydrogen (H): 10 atoms x 0.75 moles = 7.5 atoms (since there are 10 hydrogen atoms in one molecule of caffeine).

For nitrogen (N): 4 atoms x 0.75 moles = 3 atoms (since there are 4 nitrogen atoms in one molecule of caffeine).

For oxygen (O): 2 atoms x 0.75 moles = 1.5 atoms (since there are 2 oxygen atoms in one molecule of caffeine).

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The primary ester example presented is ethyl acetate, which has a fruity descriptor and is commonly found in Riesling wines.

The primary ester example that was presented is ethyl acetate. Ethyl acetate is an ester formed by the condensation of acetic acid and ethanol. It is commonly used as a flavoring compound due to its fruity aroma and taste.

When it comes to wine, ethyl acetate is one of the most common esters found in both red and white wines. It contributes to the fruity and floral aromas often associated with wines. In particular, it is commonly found in Riesling wines, a white wine varietal known for its aromatic profile.

The fruity descriptor refers to the characteristic scent and flavor of ethyl acetate, reminiscent of fruits such as apples, pears, and bananas. This fruity note adds complexity and enhances the overall sensory experience of the wine.

It's important to note that the presence and concentration of ethyl acetate in wines can vary depending on factors such as grape variety, fermentation conditions, and aging process.

However, it is generally recognized as an ester that contributes to the aromatic profile and flavor profile of wines.

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The fossil is approximately 17,100 years old.

The age of a fossil can be estimated by using the half-life of carbon-14. The half-life of carbon-14 is approximately 5,700 years, which means that after this time, half of the carbon-14 in a sample will have decayed into nitrogen-14.

If a fossil contains 1 part carbon-14 to 7 parts nitrogen-14, this means that the carbon-14 has decayed to one-eighth (1/8) of its original amount. Since we know the half-life of carbon-14, we can use this information to estimate the age of the fossil.

If we assume that the fossil originally contained only carbon-14, then the number of half-lives that have passed can be calculated as follows:

1/2n = 1/8

where n is the number of half-lives that have passed.

Simplifying this equation, we get:

2n = 8

n = 3

Therefore, the fossil has undergone 3 half-lives of carbon-14 decay. Since the half-life of carbon-14 is approximately 5,700 years, we can estimate the age of the fossil by multiplying the half-life by the number of half-lives:

age = 5,700 years/half-life * 3 half-lives

age = 17,100 years.

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Answer: atomic mass

Explanation:

Mass Number. The mass number (A) of an atom is the total number of protons and neutrons in its nucleus. The mass of the atom is a unit called the atomic mass unit (amu).

Answer:

I think Ne electron configuration

Answer:

D 2-7-2

Explanation:

I got it wrong and then they showed me the right answer