So, we need to know amount of aluminum hydroxide is in the solution in order to respond to your inquiry.
To calculate the amount of calcium hydroxide required to precipitate aluminum hydroxide, we need to know the amount of aluminum hydroxide present in the solution. The balanced chemical equation for the precipitation reaction is:
Aluminum hydroxide: what is it?
A naturally occurring mineral called aluminum hydroxide is used as an antacid to alleviate acid reflux, upset stomach, and heartburn. In addition, it is employed to lower phosphate levels in patients with specific kidney conditions1. Amphoteric means that aluminum hydroxide possesses both basic and acidic properties. It serves as a raw material for the production of other aluminum compounds, including sodium aluminate, activated aluminum, aluminum nitrate, polyaluminum chloride, aluminum chloride, and calcined alumina's.
2Al³+(aq) + 6OH-(aq) + 3Ca²+(aq) + 6OH-(aq) → 2Al(OH)³(s) + 3Ca²+(aq)
From this equation, we can see that 2 moles of Al(OH)³ are produced for every 3 moles of Ca(OH)² added. Therefore, we can use stoichiometry to calculate the amount of Ca(OH)² needed to produce a certain amount of Al(OH)³.
For example, if we have 1 mole of Al3+ ions in solution,
we would need (1 mole Al(OH)³ / 2 moles Al3+) x (3 moles Ca(OH)² / 6 moles OH-) x (74.09 g Ca(OH)² / 1 mole Ca(OH)²)
= 12.35 g Ca(OH)²
So, we need to know how much aluminum hydroxide is in the solution in order to respond to your inquiry.
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Give one hazard of using sodium hydroxide and state how to reduce the risks from this hazard.
Answer:
Sodium hydroxide is very corrosive. It can cause irritation to the eyes, skin, and mucous membrane; an allergic reaction; eye and skin burns; and temporary loss of hair. Workers may be harmed from exposure to sodium hydroxide.
Explanation:
How to reduce:
Inhalation: Move victim to fresh air.
Skin Contact: Avoid direct contact
Eye Contact: Avoid direct contact
Ingestion: Have victim rinse mouth with water.
For the equation below, write the oxidation half-reaction and the reduction half-reaction. 2Na + Cl2 -----> 2NaCl
Answer:
Oxidation half-reaction : Na(s) → Na⁺ + 1 e-
Reduction half-reaction: Cl₂ + 2 e- → 2 Cl⁻
Explanation:
Oxidation half-reaction: solid sodium (Na(s)) has an oxidation number of 0. It loses 1 electron and forms the cation Na⁺. So, the half-reaction is the following:
Na(s) → Na⁺ + 1 e-
Reduction half-reaction: chlorine gas (Cl₂) has an oxidation number of 0. Each atom of Cl gains 1 electron to form two Cl⁻ ions, according to the following half-reaction:
Cl₂ + 2 e- → 2 Cl⁻
The total oxidation-reduction reaction is obtained by adding the oxidation half-reaction multiplied by 2 (to balance the electrons) and the reduction half-reaction, as follows:
2 x (Na(s) → Na⁺ + 1 e-)
Cl₂ + 2 e- → 2 Cl⁻
--------------------------------
2Na(s) + Cl₂ → 2NaCl
Lana drew the diagram below to model asexual reproduction. Based on Lana's diagram, which statement explains the results of asexual reproduction? A. The offspring are not genetically identical to the parent, because each offspring receives only half of the chromosomes from a single parent. B. The offspring are not genetically identical to the parents, because two parents each contribute half of their chromosomes to each offspring. C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes. D. The offspring are genetically identical to the parents, because two parents each contribute a complete copy of their chromosomes to each offspring.
Based on Lana's diagram, the correct statement that explains the results of asexual reproduction is C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes.
What happens in asexual reproduction?In the diagram, the parent cell divides into two identical daughter cells, each of which contains a complete copy of the parent cell's genetic material.
This type of reproduction, where a single parent produces offspring that are genetically identical to itself, is called asexual reproduction. It is the process by which many unicellular organisms, such as bacteria and some protists, reproduce.
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CAN SOMEONE PLEASE HELP ME WITH THIS?!!!!
Answer:
1. A. 9 eggs
2. B. 5:3
3. C. Exactly 44 g
4. C. Mass and atoms only
5. D. 6.81 g of PH₃
6. C. 88.4%
7. B. O₂
8. D. 30.8 g CO₂
9. B.
10. B.
11. C. 99 g
12. D. mole ratio
13. C. Theoretical
14. A. 6.0 mol H₂O
15. D. 39.7 g CH₃OH
16. A. 650 g HgO
17. D. 8.8 mol H₂
18. B. 82.6%
Explanation:
1. The number of eggs it takes to make 1 cake = 3 eggs
The number of eggs it takes to make 3 × 1 = 3 cake = 3 × 3 = 9 eggs
Therefore, the correct option is;
A. 9 eggs
2. The given reaction is presented as follows;
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
In the above reaction, we have;
Moles of , O₂, reacted = 5 moles
Moles of , CO₂, produced = 3 moles
The ratio of the of O₂ reacted to moles of CO₂ produced = 5 moles:3 moles
∴ The ratio of the of O₂ reacted to moles of CO₂ produced = 5:3
The correct option is;
B. 5:3
3. The reaction is presented as follows;
O₂ (g) + C(s) → CO₂ (g)
From the reaction, 1 mole (12 g) of carbon produces 1 mole of CO₂
The molar mass of CO₂ = The mass of 1 mole of CO₂ = 44.01 g/mol
Given that the reaction is completed, the mass of CO₂ produced = The mass of 1 mole of CO₂ ≈ 44 g
The correct option is;
C. Exactly 44 g
4. The given reaction is presented as follows;
N₂ + 3 F₂ → 2NF₃
The initial number of atom = 2 + 6 = 8
The final number of atom = 2 × 4 = 8
∴ The initial number of atom = The final number of atom
Therefore, the number of atoms is conserved;
The mass of the reactants ≈ 28 g/mol + 3 × 37.996806 g/mol ≈ 141.993612 g/mol ≈ 142 g/mol
The mass of the product ≈ 2 × 71 g.mol = 142 g/mol
∴ The mass is conserved
Moles of reactants = 1 + 3 = 4
Moles of products = 2
∴ The number of moles is not conserved
The correct option is
C. Mass and atoms only
5. The molar mass of P₄ = 123.895048 g/mol
One mole of P₄ (123.895048 g) produces four moles (4 × 34.00) of PH₃
6.20 g of P₄. will produce (4 × 34.00)/(123.895048) × 6.20 g ≈ 6.80576 g ≈ 6.81 g
The correct option is D. 6.81 g of PH₃
6. The percentage yield = ((The actual yield)/(The ideal yield)) × 100
The actual yield of silver = 38.1 g
The ideal yield of silver = 43.1 g
∴ The percentage yield = ((38.1 g)/(43.1 g)) × 100 = 88.3990719258% ≈ 88.4%
The percentage yield = 88.4%
The correct option is C. 88.4%
7. The given chemical equation is presented as follows;
CS₂ (g) + 3 O₂ (g) → CO₂ (g) + 2 SO₂ (g)
The number of moles in 192 g of O₂ = 192 g/(32 g/mol) = 6 moles
Given that 3 moles of O₂ reacts with 1 mole of CS₂ to produce 1 mole of CO₂ and 2 moles SO₂, therefore 2 × 3 = 6 moles of O₂ will reacts with 2 × 1 = 2 moles of CS₂ to produce 2 moles of CO₂ and 4 moles SO₂
∴ The limiting reactant is;
B. O₂
8. The given chemical equation is presented as follows;
2 C₈H₁₈ (g) + 25 O₂ (g) → 16 CO₂ (g) + 18 H₂O (l)
The number of moles in 10 g of C₈H₁₈, n₁ = (10 g)/(114.26 g/mol)
The number of moles of CO₂ produced, n₂ = (10 g)/(114.26 g/mol) × 16/2 ≈ 0.7 moles
The mass of CO₂ produced, m ≈ 44.01 × n₂ ≈ 44.01 g/mol × 0.7 moles ≈ 30.807 grams ≈ 30.8 grams
The theoretical yield of CO₂ from completely burning 10.0 g of C₈H₁₈ ≈ 30.8 grams of CO₂
The correct option is D. 30.8 g CO₂
9. The correct option is B. The limiting reactants determine the maximum amount of product that can be formed
10. Option B, which has 3 atoms of each element combining to form a product with 1 atom of one element and 2 atoms of the other element
The correct option is B.
11. By the conservation of mass, we have;
The mass of the reactants = The mass of the products
Let 'x' represent the mass of zinc in the products of the reaction
Therefore, we have;
61 g of calcium + 207 g of zinc chloride = 169 g of calcium chloride + x g of Zinc
∴ x g = 61 g + 207 g - 169 g = 99 g
The mass of zinc in the products of the reaction, x g = 99 g
The correct option is;
C. 99 g
12. The quantity that must be used to convert from one chemical substance to another is the mole ratio
The correct option is D. mole ratio
13. The maximum mass of the product that could form in a reaction is called the theoretical yield, which is option C.
The correct option is C. Theoretical
14. 1 mole of O₂ produces 2 moles of water (H₂O), therefore;
3 × 1 = 3.0 moles of O₂ will produce 3 × 2 = 6 moles of H₂O
The correct option is
A. 6.0 mol H₂O
15. 2 mole × 2.02 g/mol = 4.04 g of H₂ (g) produces 32.05 g CH₃OH (l)
∴ 5 g of H₂ (g) will produce 32.05 g × 5/4.04 ≈ 39.6658416 g ≈ 39.7 g of CH₃OH
The correct option is;
D. 39.7 g CH₃OH
16. 2 (2 × 216.59 g = 433.18 g) moles of HgO produces 1 mole of O₂
1.5 mole of O₂ will be produced by 1.5 × 2 = 3 moles (3 × 216.59 g = 649.77 g ≈ 650 g) of HgO
The correct option is A 650 g HgO
17. 3 moles of H₂ produces 2 moles of NH₃
The number of moles of NH₃ in 100 g of NH₃, n = 100 g/(17.04 g/mol) = 5.868544 moles
The number of moles of H₂ that will produce 5.868544 moles of NH₃ = 3/2 × 5.868544 moles = 8.802816 moles ≈ 8.8 moles
Therefore, the correct option is;
D. 8.8 mol H₂
18. The theoretical yield of PbO = (223.2/331.2) × 9.90 g = 6.67173913 g
The percentage yield = (5.51 g)/(6.67173913 g) × 100 ≈ 82.6%
The correct option is option B 82.6%.
When the following compound is treated with a mixture of nitric and sulfuric acid at 50°C, nitration occurs to afford a compound with two nitro groups. Draw the structure of this product: HNO H2SOA
The given aromatic reactant reacts with sulfuric and nitric acid to form the para-nitro-substituted product. This reaction is referred to as aromatic nitration.
Nitration reaction is a type of reaction where the hydrogen atom (in the organic compound) will be replaced with the nitro groups (NO₂). In aromatic nitration, the combination of sulfuric (H₂SO₄) and nitric acid (HNO₃) will help to produce this nitro group (NO₂). This is a powerful electrophile.
In the given compound, the benzene ring is substituted with an ether moiety (-OAr) and butyl group. Since the ether moiety is in ortho-para orientation within the two rings, the ortho position is blocked by the butyl group, so the nitration will take place in the para position of both the benzene ring and results in the product as mentioned in the diagram.
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The complete question is -
When the following compound is treated with a mixture of nitric and sulfuric acid at 50°C, nitration occurs to afford a compound with two nitro groups. Draw the structure of this product:
when sodium chloride dissolves in water, how do the water molecules orient around the ions? question 6 options: a) the oxygen atoms point toward the sodium ions, and the hydrogen atoms point toward the chloride ions. b) the hydrogen atoms point toward both the sodium and the chloride ions. c) the oxygen atoms point toward both the sodium ions and the chloride ions. d) the hydrogen atoms point toward the sodium ions, and the oxygen atoms point toward the chloride ions. e) water molecules are randomly oriented around the ions.
When sodium chloride dissolves in water, water molecules orient around the ions in such a way that the hydrogen atoms point toward the chloride ions. The correct option is b.
When sodium chloride (NaCl) dissolves in water, it separates into \(Na^+\) and \(Cl^-\) ions. As a result, water molecules surround the ions, shielding them from one another. Water molecules are orientated around the ions in such a way that their hydrogen atoms (δ+) are directed toward the chloride ions ( \(Cl^-\)) and their oxygen atoms (δ-) are directed toward the sodium ions (\(Na^+\)).
A water molecule has two positively charged hydrogen atoms and one negatively charged oxygen atom that form a V-shaped geometry, with the oxygen atom at the vertex. The H-O-H bond angle is 104.5 degrees. As a result, when\(Na^+\) and \(Cl^-\) ions are present in water, they are surrounded by water molecules, with their hydrogen atoms pointed toward the \(Cl^-\) and their oxygen atoms pointed toward the \(Na^+\) .
In summary, when sodium chloride dissolves in water, the water molecules orient around the ions in such a way that the hydrogen atoms point toward the chloride ions. The correct option is b.
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The bonding within the molecules or compounds directly affects its solubility. The_______ bonds within hexane, CH14. prevent the compound from being dissolved by a solvent like water , H₂O.A) shared ionicB) polar covalentC) nonpolar covalentD)Electrostatic metallic
Water is a polar substance. Polar solvents dissolve polar substances. Now, the bond between carbon and hydrogen is a covalent bond, because the electronegativity difference between these two elements is less than 1.7.
Therefore, the low solubility of hexane is due to the fact that hexane is nonpolar with covalent bonds.
Answer: C) Nonpolar covalent
in exothermic reaction heat energy is ________________ during reaction.
Energy is released
exo-outside
thermic-heat
A good example of an exothermic reaction is combustion where heat is released
A block of wood is measured to be 3.25 cm on each side the density of this particular word is 0.9 45g/7cm3 what is the mass of the sample will the sample float in the water
Mass of the block of wood = 3.25 cm
Density of the block of wood = 0.945 g/ cm³
The selenate ion, SeO32-, is classified as which of the following?a. polyatomic cationb. monoatomic cationc. polyatomic aniond. monoatomic anione. none of the above
The selenate ion, SeO₃²⁻, is classified as a. polyatomic anion. Polyatomic ions are composed of two or more atoms covalently bonded together and carry a charge.
In the case of the selenate ion, it consists of one selenium (Se) atom and three oxygen (O) atoms bonded together, with an overall charge of -2. A cation refers to a positively charged ion, whereas an anion refers to a negatively charged ion. Since the selenate ion carries a negative charge, it is an anion.
Furthermore, it is not monoatomic because it consists of more than one atom. Thus, the correct classification for the SeO₃²⁻ ion is a polyatomic anion (option c).
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Atoms of an element, X, have the electronic configuration shown below.
The compound most likely formed with magnesium, Mg, is:
(A) MgX
(B) Mg2X
(C) MgX2
(D) Mg3X2
The compound most likely formed with magnesium, Mg, is MgX . The correct option is (A) MgX.
The electronic configuration of the element, X is 2,8,7. Since X is located in group 7 of the periodic table, it has 7 electrons in its valence shell. In order to obtain a stable configuration, the atom can either gain one electron to fill the 3rd energy level completely or lose seven electrons to completely empty the 2nd energy level, which is easier. The resulting ion, X-, would have a stable electronic configuration of 2,8. Hence, the compound most likely formed with magnesium, Mg, is MgX .The correct option is (A) MgX.
Explanation: Magnesium is located in group 2 of the periodic table and has two valence electrons in its outermost shell. It loses these two electrons to form Mg2+ ions with stable electronic configurations of 2,8. On the other hand, element X gains an electron to form X- ions with stable electronic configurations of 2,8.The combination of Mg2+ and X- ions results in the formation of the compound MgX with a neutral charge.
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f.
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What is octet? Why is it inactive?
Answer:
Join here if u r a girl owu-bqfx-fvq
Using the same sample of gas (P = 475 torr , T = 21 °C ), we wish to change the pressure
to 4750 torr with no accompanying change in volume or amount of gas. What temperature T2 in
Celsius, is needed to reach this pressure?
Answer:
210°C
Explanation:
using the equation
P1/T1=P2/T2
475/21=4750/T2
T2= (21×4750)/475
T= 210°C
How many atoms are in 4.3 moles of lithium?
help me please i love you so much yes
Answer: When this occurs, the particles bind with the chemicals and form larger particles, the clear water on top will pass through filters of varying compositions (sand.
Explanation: I hoped that helped.
Explain the relationship between primary, secondary, tertiary consumers, and decomposers
Answer:
The organisms that consume the primary producers are herbivores: the primary consumers. Secondary consumers are usually carnivores that eat the primary consumers. Tertiary consumers are carnivores that eat other carnivores.
Hazardous gas released from a factory’s smokestack is an example of __________ externality. a. local b. positive c. resource d. negative
Answer: D. negative
Explanation:
How many molecules are in 5.50 grams of AgNO3?
a 6.14 x 1022 molecules
b 0.032 molecules
c 3.22 x 1022 molecules
d 1.93 x 1022 molecules
e 8.67 x 1021 molecules
Answer:
1.95*10²² molecules are in 5.50 grams of AgNO₃
Explanation:
Being the molar mass of the elements:
Ag: 107.87 g/moleN: 14 g/moleO: 16 g/molethen the molar mass of the compound is:
AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole
Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?
\(moles=\frac{5.50 grams*1 mole}{169.87 grams}\)
moles= 0.0324
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?
\(molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}\)
molecules=1.95*10²²
1.95*10²² molecules are in 5.50 grams of AgNO₃
2) The purpose of the following multi-part problem is to help you think about air pollution and its impacts on a community from an engineering design and regulatory perspective. You are an engineer tasked with thinking about whether or not to convert the Intermountain Power Plant in Delta Utah from coal to oil or natural gas. The costs of the upgrades will be $500 million. Power Power Emission Factors (g/GJ) Plant Provided NOx SO₂ со PM₁0 CO₂ Type (GW) Natural Gas 1 93.3 0.68 14.5 0.1 56,100 Coal 1 292 765 89.1 1,203 94,600 Oil 1 195 1,350 15.7 16 77,400 a. Assuming that the plant operates for one year at full capacity, calculate the total emissions (in tons) for each of the five pollutants per year. Hint: this is nothing more than a unit conversion problem. b. Explain the environmental and human health impacts of each pollutant. c. What emissions control technologies would you use to reduce emissions of each pollutant? d. Which of the following temperature profiles represents a worst-case scenario for a nearby community? A best-case scenario? Why? Environmental Inversion Dry adiabatic Environmental Temperature C Temperature C Elevation, km Environmental lapse rate Inversion Dry adiabatic lapse rate Temperature, "C -Environmental lapse rate Figure 1 Figure 2 e. What percent savings in terms of tons of CO₂ will there be per year with the conversion to oil and natural gas? f. US Cap and Trade regulations require power plant operators to pay for their emissions above a certain cap. The cap for this plant is 100,000 metric tons per year. Assuming a price of $0.02 per metric ton, how much would the power plant save each year as a result of the conversion oil and natural gas assuming that there were no air pollution controls installed. 3) Greenhouse Gas Simulation (Adapted from PhET from the University of Colorado Boulder). For this problem, please follow the directions below and answer the embedded questions.
Assuming a price of $0.02 per metric ton, the power plant will save $2,000 per year as a result of the conversion to oil and natural gas, assuming that there were no air pollution controls installed.
a) Total emissions of pollutants per year from the Intermountain Power Plant in Delta Utah will be as follows:Natural Gas Type: Pollutants Emissions NOx : 62,610 tonsSO2 : 1,461 tonsCO : 6,090 tonsCO2 : 3.49 million tonsPM10 : 100 tons Coal Type: Pollutants Emissions NOx : 194,580 tonsSO2 : 508,410 tonsCO : 13,230 tonsCO2 : 8.15 million tonsPM10 : 12,005 tons Oil Type: Pollutants Emissions NOx : 130,680 tonsSO2 : 905,460 tonsCO : 10,530 tonsCO2 : 6.10 million tonsPM10 : 58 tons b)The environmental and human health impacts of each pollutant are:
1. NOx: It leads to the formation of photochemical smog and acid rain which has a negative impact on the environment. It is also harmful to human health and causes respiratory problems. 2. SO2: It causes acid rain, reduces visibility, and harms the environment. It is also harmful to human health and causes respiratory problems.3. CO: It is harmful to human health and can cause headaches, nausea, and can even lead to death in large amounts.4. CO2: It is a greenhouse gas and contributes to global warming.5. PM10: It causes respiratory problems and can cause lung cancer in extreme cases.c) The emissions control technologies that can be used to reduce emissions of each pollutant are:1. NOx: Selective Catalytic Reduction (SCR) and Exhaust Gas Recirculation (EGR) are used to reduce NOx emissions.2. SO2: Flue Gas Desulphurization (FGD) technology can be used to remove SO2 from the flue gases.3. CO: Combustion control techniques can be used to reduce CO emissions.
4. CO2: Carbon Capture and Storage (CCS) technology can be used to capture CO2 and store it in geological formations.5. PM10: Fabric filters, electrostatic precipitators, and scrubbers can be used to control PM10 emissions.d)The worst-case temperature profile for a nearby community is represented by Figure 1, i.e., an inversion temperature profile. Inversion traps pollutants and prevents them from escaping into the atmosphere, leading to an increase in pollution levels.
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can someone please explain to me the difference between oxidation and reduction? Please I need help.
Answer:
Oxidation occurs when a reactant loses electrons during the reaction. Reduction occurs when a reactant gains electrons during the reaction.
Buffers tend to prevent dramatic changes in the ph when __________ are added to a solution.
Buffers tend to prevent dramatic changes in the pH when proton donors or proton acceptors are added to a solution.
A weak acid and its conjugate base, or a weak base and its conjugate acid, make up a buffer. The amount of acid or base that may be added to a buffer before the pH changes is known as the buffer capacity.
Blood bicarbonate, which keeps the body's internal pH stable, is an illustration of a buffer solution. Any proton acceptor is a base, while any proton donor is an acid. Amphiprotic refers to a material that can function as a proton acceptor or donor. The most prevalent amphiprotic material is probably water.
Therefore, buffers tend to prevent dramatic changes in the pH when proton donors or proton acceptors are added to a solution.
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explain how and where each of these molecules may enter the process of cellular respiration:
Starch, glycogen, proteins, and fats are all macromolecules that can be broken down and used as a source of energy for cellular respiration.
Each of these molecules enters the process of cellular respiration at different stages and through different pathways.
Starch: Starch is a complex carbohydrate made up of many glucose molecules linked together. In order to enter the process of cellular respiration, starch must first be broken down into glucose molecules. This occurs through the process of hydrolysis, in which water molecules are used to break the bonds between the glucose molecules. Once the glucose molecules have been released, they can enter glycolysis, the first stage of cellular respiration.
Glycogen: Like starch, glycogen is a complex carbohydrate made up of many glucose molecules linked together. Glycogen is stored in the liver and muscle tissue and can be broken down into glucose molecules when needed. The process of breaking down glycogen into glucose molecules is called glycogenolysis. Once the glucose molecules have been released, they can enter glycolysis and continue through the rest of cellular respiration.
Proteins: Proteins are made up of amino acids and can also be used as a source of energy for cellular respiration. Before proteins can enter the process of cellular respiration, they must first be broken down into their constituent amino acids. This process is called proteolysis and can occur in the digestive system or within cells themselves. Once the amino acids have been released, they can be converted into pyruvate, acetyl-CoA, or other molecules that can enter the various stages of cellular respiration.
Fats: Fats are a rich source of energy and can be broken down into smaller molecules called fatty acids and glycerol. The breakdown of fats into fatty acids and glycerol is called lipolysis and occurs in the cytoplasm of cells. The fatty acids can be converted into acetyl-CoA, which can then enter the citric acid cycle, the second stage of cellular respiration. The glycerol can be converted into a molecule called glyceraldehyde 3-phosphate, which can enter glycolysis.
All of these molecules can enter the process of cellular respiration, but they must first be broken down into smaller molecules that can enter the various stages of cellular respiration. Starch and glycogen must be broken down into glucose, proteins into amino acids, and fats into fatty acids and glycerol before they can be used as a source of energy in cellular respiration.
Question - Explain how and where each of these molecules may enter the process of cellular respiration: Starch Glycogen Proteins Fats
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Describe Pasteur’s results and how they helped disprove spontaneous generation.
Answer:
Pasteur-Disproved spontaneous generation using S-necked flasks that were open to the air but did not let microorganisms in. Broth boiled in the flasks did not become contaminated. ... The organisms could have come from the air and settled into the broth.
Explanation:
2. Suppose that the identification labels fell off three of the Beral pipets in the set used in this experiment. You realize that the pipets with the missing labels hold NH,CI, HCI, and NaCl solutions. Describe an experi- ment you could perform, using these three solutions and any two of the indicators used in this experiment, not including the Universal Indicator, that would allow you to correctly relabel the pipets. If the data from your experiment would be inconclusive, state the pH range for which you would need an indicator to make certain of the identifications.
To correctly relabel the pipets, we need to determine the identity of each solution based on its properties. We can use two indicators, bromothymol blue and phenolphthalein, to perform the following experiments:
Add a few drops of bromothymol blue to each solution. NH4Cl solution will turn yellow, NaCl solution will remain unchanged, and HCl solution will turn blue. Based on this, we can label the pipet with the yellow solution as NH4Cl, the unchanged solution as NaCl, and the blue solution as HCl.
Add a few drops of phenolphthalein to each solution. NaCl solution will remain colorless, NH4Cl solution will turn pink, and HCl solution will remain colorless. Based on this, we can label the pipet with the pink solution as NH4Cl, the colorless solution as NaCl, and the colorless solution as HCl.
If the data from these experiments are inconclusive, we would need an indicator that can distinguish between acidic and basic solutions. In this case, we can use methyl red as an indicator. NH4Cl solution will turn red, NaCl solution will remain unchanged, and HCl solution will remain colorless. Based on this, we can label the pipet with the red solution as NH4Cl, the unchanged solution as NaCl, and the colorless solution as HCl.
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Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct about the ΔG° at 25 °C?
A)+4,360 J
B)−6,942 J
C)−4,360 J
D)+6,942 J
Answer:
B)−6,942 J /mol
Explanation:
At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:
ΔG = ΔH - TΔS
Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.
Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):
ΔG = ΔH - TΔS
ΔG = 25450J/mol - 298K×108.7J/molK
ΔG = -6942.6J/mol
Right solution is:
B)−6,942 J /molthe vapor pressure of a certain liquid increases by a factor of 3 when the temperature is increased from 22.4 c to 30.7 c. what is the heat of vaporization of the liquid in kj/mole?
The Clausius-Clapeyron equation, which links a substance's vapour pressure to its temperature. Therefore, the liquid's heat of vaporisation is roughly 45.56 kJ/mol.
The Clausius-Clapeyron equation, which connects the change in vapour pressure to the change in temperature and the heat of vaporisation, can be used to address this issue: Hvap/R(1/T1 - 1/T2) is equal to ln(P2/P1). When the temperature rises from 22.4°C (295.55 K) to 30.7°C, the liquid's vapour pressure increases by a factor of three (303.85 K). P2/P1 = 3 T1 = 295.55 K T2 = 303.85 K is the result.
The Clausius-Clapeyron equation can be solved for by substituting these values and getting the answer: ln(3) = Hvap/R(1/295.55 - 1/303.85).
ΔHvap = -R(1/295.55 - 1/303.85)
ln(3)
Applying the gas constant R = 8.314 J/(mol K), the following equation is obtained: Hvap = -8.314 J/(mol K) (1/295.55 K - 1/303.85 K) ln (3)
Hvap equals -40.71 J/mol.
We divide this amount by 1000 to get kJ/mol:
ΔHvap = -0.0407kJ/mol
As a result, the liquid's heat of vaporisation is 0.0407 kJ/mol.
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1. How does nephron separate urine from blood ?
2. What properties of metals help to make them the following ? [ Mention two points for each ]
i. Utensils to cook in it
ii. Conducting wire
iii. Body of aeroplane
- Plagiarised / Random answers will be reported !
Answer: Hope This Helps
Explanation:
1: The nephrons contain a filter called the glomerulus. The fluid that is filtered from the blood then travels down through a tubule. The tubule adjusts the level of wastes that will leave the body in the urine.
(I dont know the second part so hope this half answer helps a little bit. Sorry.)
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✍ 1. ➺ Nephrons have filters known as glomerulus (they are a cluster of very thin-walled blood capillaries). Glomerulus filters our blood & then removes any unwanted waste materials. Now, this filtrate which is removed out from the blood gets collected & filtered again in the Bowman's Capsule & tubules from where nephrons remove glucose, amino acids & a major amount of water. The urine forming in each kidney now enters a long tube (ureter) where urine passes & gets stored in the urinary bladder. Urine gets passed out of the body through the urethra.
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✐ 2. i) Property of metals ⎆ Good conduction of heat.
ii) Property of metals ⎆ Good conduction of electricity & ductility.
iii) Property of metals ⎆ Malleability & ductility.
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Which of the following examples best represents heat?
1. A sample of platinum is 76°C.
2. A piece of plastic contains 57 J of energy.
3. A piece of wood burns at 350°C.
4. A toy car generates 45 J of kinetic energy.
Answer:
What I think it is it's.. 3?
Jimmy claims that the Earth’s rotation takes longer than the Earth’s revolution. Do you agree or disagree?
Answer:
I disagree, because earth rotation on its axis causes day and night, on the other hand the its revolution on the orbit around the sun causes seasons. One Rotation would means one day has completed, and one revolution would mean that one year has completed. Therefore, it's obvious that Earth's revolution takes longer than the rotation.
I hope that helps...
two absorption peaks located near 255 nm are separated by 0.03 nm. what minimum resolution must a grating have in order to separate these wavelengths?
The minimum resolution to separate these wavelengths is 250nm as they are located near 255n and 0.03nm.
Resolution also known as optical resolution or chiral resolution, or chiral activity refers to the activeness of the compound. It is the process in which two racemic mixtures are separated into its components.
Wavelength is known as the distance between two repeated waves of light. Wavelength is denoted by the symbol lambda (λ). It gives us the idea of the speed or pace of a particular light.
In the given condition, two absorption peaks - absorption spectroscopy is the absorption spectrum between which the light releases protons. Therefore, the wavelength to separate these two absorption peaks is 250nm in minimum.
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