How many orbitals in an atom can have each of the following designations:
(a) 1s;

Answer:

1.3 atm

Explanation:

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P1 x V1) / (T1) = (P2 x V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature of the gas.

We are given:

P1 is what we want to find

V1 = 839 mL

T1 = 45 degrees Celsius = 318 K

V2 = 1032 mL

T2 = 58 degrees Celsius = 331 K

P2 = 1.9 atm

Plugging these values into the formula, we get:

(P1 x 839 mL) / (318 K) = (1.9 atm x 1032 mL) / (331 K)

Simplifying and solving for P1, we get:

P1 = (1.9 atm x 1032 mL x 318 K) / (839 mL x 331 K)

P1 = 1.3 atm (rounded to one decimal place)

Therefore, the original pressure of the oxygen sample was 1.3 atm.

Answer:

o and o

Explanation:

please mark as brainlist answer

The element that probably forms a compound with hydrogen that has a chemical formula most and least similar to the chemical formula of the compound formed by hydrogen and selenium is sulfur.

Sulfur is in the same group as selenium, which means they have similar chemical properties. Therefore, sulfur would most likely form a compound with hydrogen that has a chemical formula similar to hydrogen selenide (H₂Se), the compound formed by hydrogen and selenium. On the other hand, chlorine and fluorine are both highly reactive nonmetals that would not likely form compounds with hydrogen in a similar way to selenium.

Potassium is a highly reactive metal and would not likely form a compound with hydrogen in a similar way to selenium either.

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Answer: 269.3 kPa

Explanation:

Since the volume does not change, the formula: P/T = P/T can be used.

However, all temperatures must first be converted into kelvin, which can be done like this: 225 Celsius + 273 = 498 K; and 25 Celsius + 273 = 298 K.

Now, plug into the formula: 450 / 498 = P / 298 → Cross multiply and divide to get:

P = 269.3 kPa :)

Answer:

Refractive index

Heat capacity

Density

Explanation:

Properties that are used to identify materials are called intensive properties. These intensive properties are characteristic of the material and does not depend on the amount of material present.

Thus, if i want to identify whether the three bars are made of the same metal, i can look out for the following properties;

Refractive index

Heat capacity

Density

These properties are intensive properties thus they can be used to identify an unknown substance.

find the answer in the attached image. please mark as brainliest if it is helpful.

Liquids and solids exhibit practically no change of solubility with changes in pressure.

As expected, gases increase in solubility with increasing pressure. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the surface of the solution.

In chemistry, solubility is the ability of one substance (solute) to form a solution with another substance (solvent). Insolubility is the opposite property, the inability of a solute to form such a solution.

The solubility of a substance in a particular solvent is usually measured as the concentration of the solute in the saturated solution beyond which the solute cannot dissolve.  At this point, the two substances are said to be in solubility equilibrium. For some solutes and solvents, there may be no such restriction, in which case the two substances are said to be "miscible in all proportions" (or simply "miscible") [2 ].

Solutes can be solids, liquids, or gases, while solvents are usually solids or liquids. Both can be pure substances or solutions. Gases are always miscible in all proportions except in very extreme circumstances, and a solid or liquid can only be "dissolved" in a gas by first going to the gaseous state.

Solubility is primarily dependent on solute and solvent composition (including pH and the presence of other solutes), temperature, and pressure. This dependence can often be explained by interactions between two particles of matter (atoms, molecules, or ions) and thermodynamic concepts such as enthalpy and entropy.

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Answer: there are 118 elements

Explanation:

Answer:

asexual cell

Explanation:there are mainly 2 types sexual and asexual i would say asexual because they grow without another parent and don't have a nucleus.

Answer:

k,39

Explanation:

Is the answer

Answer:

differential

Explanation:

According to openstax.org, "Gram-staining is a differential staining technique that uses a primary stain and a secondary counterstain to distinguish between gram-positive and gram-negative bacteria."

Answer:

Speed

Explanation:

Motion can be represented by a distance-time graph, which plots distance on the y-axis and time on the x-axis. The slope of a distance-time graph represents speed. The steeper the slope is, the faster the speed.

Hope this helps!:)

Answer:

The reverse reaction is occurring at a faster rate than the forward reaction.

Explanation:

When the reaction:

aA + bB ⇔ cC + dD

has not reached the balance, it is possible to calculate:

\(Qc=\frac{[C]^{c}*[D]^{d} }{[A]^{a}*[B]^{b} }\)

where Q is called the reaction quotient, and the concentrations expressed in it are not the equilibrium concentrations, but other concentrations given at a time of the reaction.

Comparing Qc with Kc allows to find out the status and evolution of the system:

In the case of the reaction:

N₂ (g) + O₂ (g) ⇄ 2 NO (g)

\(Qc=\frac{[NO]^{2} }{[N_{2} ]*[O_{2} ] }\)

Being:

and replacing:

\(Qc=\frac{0.10^{2} }{0.80*0.050 }\)

you get:

Qc= 0.25

Being Kc=0.10, Qc>Kc.  Then the system is not in equilibrium and will evolve to the left to increase the concentration of reagents. So, the reverse reaction is occurring at a faster rate than the forward reaction.

Using stoichiometry and the molar mass, we find that one would need approximately 2218.32 milligrams of MgSO₄·7H₂O (Epsom salt) to make 30 mL of 0.3 M MgSO₄ solution.

The molar mass of MgSO₄·7H₂O is calculated as follows:

Therefore, the molar mass of MgSO₄·7H₂O is :

30 mL of 0.3 M MgSO₄ solution is prepared by finding the amount of MgSO₄·7H₂O required in milligrams:

Converting grams to milligrams, multiplying by 1000:

Therefore, to make 30 mL of 0.3 M MgSO₄ solution, you would need approximately 2218.32 milligrams of MgSO₄·7H₂O.

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Complete question :

On the first day of your new job as a chemist, you are given a bottle of magnesium sulfate and asked to make 30 mL of 0.3 M MgSO4. The formula on the bottle is MgSO4∗7H2O (also known as Epsom salt). Calculate the amount of salt you need (in milligrams).

Answer:

A. Food

Explanation:

Water alone does not give energy, Carbon Dioxide cannot be consumed healthily, and photosynthesis is for plants.

Using a micropipette, pipette 12 µL of the stock solution into the second labeled tube.5. Add 18 µL of nuclease-free water to the second labeled tube to bring the total volume up to 30 µL. This will give a final concentration of 250 ng/µL.

RNA or Ribonucleic acid is the genetic material that helps to transfer genetic information from DNA to protein synthesis. It is essential in decoding and regulation of genes. RNA isolation is the process of extracting RNA molecules from biological samples.The given formula C1V1

= C2V2 states that the concentration (C1) and volume (V1) of the initial solution is equal to the concentration (C2) and volume (V2) of the final solution. This means that the amount of solute (in this case, RNA) before and after dilution is the same. The formula can be used to calculate the volume of the stock solution required to prepare a dilution of a specific concentration.1. Label two new 1.5 mL microfuge tube with your name and RNA sample. Close the lids on them.2. Using a micropipette, pipette 30 µL of your RNA sample into one of the labeled tubes.3. Using the formula C1V1

= C2V2, we can calculate the volume of stock solution required to prepare the dilution.C1

= initial concentration

= unknown V1

= initial volume

= 30 µL (the volume we pipetted)C2

= final concentration

= 250 ng/µLV2

= final volume

= unknown (what we need to find)We can rearrange the formula to solve for V2:V2

= C1V1/C2V2

= (C1V1)/C2V2

= (100 ng/µL × 30 µL) ÷ 250 ng/µLV2

= 12 µL4.

Using a micropipette, pipette 12 µL of the stock solution into the second labeled tube.5. Add 18 µL of nuclease-free water to the second labeled tube to bring the total volume up to 30 µL. This will give a final concentration of 250 ng/µL.

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Answer:

How would you confirm that a colourless liquid given to you is pure water? A very easy solution is to take a sample of the colourless liquid and put it on the stove if it starts boiling exactly at 100 ºC then it is pure water. Any other colourless liquid such as vinegar always has a different boiling point.

The concentration of the HCl solution is 0.148 M.

The concentration of a solution is typically measured in moles per liter (M). We can calculate the concentration of HCl in the given solution as follows:

Concentration (M) = moles of solute/volume of solution (in liters)

We are given that the solution contains 0.0074 moles of HCl in 0.05 liters of solution. Plugging these values into the equation above, we get:

Concentration (M) = 0.0074 mol / 0.05 L

Concentration (M) = 0.148 M

The concentration of the HCl solution is 0.148 M.

A mole is a measurement used to quantify a substance's quantity. A material is said to have one mole if there are the same number of its constituent parts (such as atoms, molecules, or ions) in it as there are 12 grams of carbon-12.

Because they help us connect a substance's bulk to the number of particles it contains, moles are crucial in the study of chemistry. The mass in grams of one mole of a material, for instance, is known as its molar mass.

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Answer:

Try everything

1. How many moles of nitrogen gas are in 1.54x10^26 molecules? How many atoms?

2. How many molecules of water are in 3.45 moles of water?

3. How many atoms of C are in 2.00 moles of Cv6Hv12Ov6? (v means the number is below)

Explanation:

When two MOS transistors, M1 and M2, are connected in series with the same width but different channel lengths, the overall behavior can be analyzed using the long-channel model

The long-channel model assumes that the channel length of a MOS transistor is significantly larger than the technology scaling limits, thereby neglecting the short-channel effects. In this case, M1 and M2 have the same width but different channel lengths, denoted as L1 and L2, respectively.

In the long-channel model, the key factor determining the behavior of a MOS transistor is its channel length. A longer channel length results in higher resistance and reduced current flow. Therefore, the transistor with the longer channel length (M2) will exhibit higher resistance compared to the transistor with the shorter channel length (M1).

When two transistors are connected in series, the overall behavior is dominated by the transistor with the higher resistance. In this scenario, since M2 has the longer channel length, it will have a higher resistance compared to M1.

Consequently, the overall behavior of M1 and M2 connected in series will be influenced primarily by the characteristics of M2 due to its higher resistance.

Therefore, using the long-channel model, we can conclude that the behavior of M1 and M2 connected in series will be primarily determined by the transistor with the longer channel length, M2, due to its higher resistance.

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Given :

An atom Iodine.

To Find :

How many electrons will an iodine atom donate or accept, based on its number of valence electrons :

A.donate seven electrons

B.accept one electron

C.donate one electron

D.accept seven electrons

Solution :

We know, valence electron in Iodine is 7 electrons.

So, it is easy for iodine to accept 1 electron rather than giving all 7 electrons to another element.

Therefore, Iodine will accept one electron ( Option B.).

Hence, this is the required solution.

Answer:

11.958129200057586 molecules

Explanation:

The power radiated by the radiator changes by a factor of 14.1573 when the temperature is increased from 27°C to 54°C.

The formula that relates the power radiated by an object with the fourth power of the temperature is known as the Stefan-Boltzmann Law. It is stated as follows: P = σA(T⁴), where P is the power radiated, σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴), A is the surface area of the radiator, and T is the temperature in Kelvin.

We must first convert the temperature to Kelvin:

TK = T°C + 273.15

TK1 = 27°C + 273.15 = 300.15 K

TK2 = 54°C + 273.15 = 327.15 K

The factor by which the power radiated changes is the ratio of the power at the new temperature to the power at the original temperature. The equation is as follows:

P2/P1 = (T2/T1)⁴

Substituting the given values:

P2/P1 = (327.15/300.15)⁴

P2/P1 = 1.8856⁴

P2/P1 = 14.1573

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Since the breakdown of hydrogen peroxide can cause a reduction in concentration and potency over time, it is a good idea to check the concentration of hydrogen peroxide that has been exposed to air and light.

The chemical student employed titration with potassium permanganate to measure the quantity of hydrogen peroxide.

Using this technique, the volume of potassium permanganate solution needed to completely react with the hydrogen peroxide sample is measured after adding a known quantity of a standard potassium permanganate solution to the hydrogen peroxide sample until the reaction is complete.

Hydrogen peroxide and potassium permanganate react in the following way: 5 H2O2 + 2 KMnO4 + 3 H2SO4 5 O2 + 2 MnSO4 + K2SO4 + 8 H2O

The amount of hydrogen peroxide in the sample may be determined from the volume and concentration of the potassium permanganate solution used in the titration because the reaction uses 5 moles of hydrogen peroxide for every 2 moles of potassium permanganate.

The chemical student should carry out the following procedures to examine the hydrogen peroxide samples in dark and light vials that have been exposed to air for 10, 20, and 30 hours:

1. Make a standard potassium permanganate solution with a known concentration.

2. Pour a known volume of each test sample of hydrogen peroxide into a flask.

3. To serve as a catalyst for the reaction, add a tiny quantity of diluted sulfuric acid to the hydrogen peroxide sample.

4. Continue titrating the hydrogen peroxide sample with the potassium permanganate standard solution until the reaction is finished, which is shown by a lingering pink hue of the potassium permanganate solution.

5. To confirm the correctness of the results, repeat the titration using the same sample.

6. Using the volume and concentration of the potassium permanganate solution used in the titration, determine the concentration of hydrogen peroxide in the sample.

The chemical student can find out if the exposure to air and light has changed the concentration of hydrogen peroxide over time by analysing the concentration of hydrogen peroxide in the light and dark vials after 10, 20, and 30 hours.

The findings may be calculated by comparing them to the original concentration of 3% by weight.

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Answer:

Periodic trends are specific patterns that are present in the periodic table that illustrate different aspects of a certain element, including its size and its electronic properties

Explanation:

hope you understand

To see the number of atoms of an element in a given molecule we need to multiply stoichiometry to the number that is written on the foot of the element that is stoichiometry. The correct option is option A.

Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit. Atoms can make many different molecules, just like letters can make many different words.

In the nucleus, proton and neutron are present. Electron has -1 charge while proton has +1 charge. Neutron is neutral that is it has no charge. So overall the charge of nucleus is due to only proton, not by neutron.

Therefore, the correct option is option A that is Atoms can make many different molecules, just like letters can make many different words.

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Since a pure liquid freezes at a constant temperature, a flat, horizontal zone is anticipated on the cooling curve. if the liquid is allowed to cool until it is completely frozen.

The temperature will then continue to drop as the solid cools, eventually reaching the bath's temperature.

When a liquid is cooled in a constant-temperature bath, a cooling curve for the liquid illustrates graphically how the temperature changes over time. To preserve temperature uniformity, the liquid is enclosed in a test tube and continually swirled. Two elements dominate in determining the pace of cooling. The temperature differential between the liquid and the bath is the first. As the liquid temperature approaches the bath temperature as a result of this factor, the cooling curve gradually becomes less steep (has a lower negative slope), finally approaching zero, and producing a horizontal line at the bath temperature.

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Answer: 3.002 ==> C

Explanation:

3.00183 =

3.00183 =3.002 => since 8 is closer to 10 than to 0, add 1 to the 1 in 3.00183

3.002 ==> C

The nuclei with a=200 and a=60 differ in terms of their stability, the number of protons, and their size. As we all know, a nucleus is composed of protons and neutrons. The protons and neutrons together determine the nucleus' size, stability, and other characteristics.

So, the difference between a nucleus with a=200 and a nucleus with a=60 are as follows. It can be said that a nucleus with a=200 is more stable than a nucleus with a=60 because the nuclear forces present in the larger nucleus are stronger than those present in the smaller nucleus. The electromagnetic forces present in the protons are more effective in the smaller nucleus. As a result, the smaller nucleus tends to break apart easily. Due to this reason, the half-life of the nucleus with a=60 is less than that of the nucleus with a=200.

The half life of the nucleus with a=200 is very long, and it is extremely difficult to break it down. Nucleus with a=200 has more protons than nucleus with a=60. The number of protons in the nucleus determines the number of electrons that orbit it. The larger nucleus has more protons and thus attracts more electrons, resulting in a larger size. On the other hand, a smaller nucleus attracts fewer electrons, resulting in a smaller size. So, a nucleus with a=200 has a larger size than a nucleus with a=60.

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