Answer:
l think that it can take two months.pliz can you mark me the brainest.
Step-by-step explanation:
It's Laura Rays Amira Ashley. ♥️
Given the triangle information below solve for the x value and the measure in degrees of angle a
What is the value of (x)
Answer:
x=1
Step-by-step explanation:
anything times 1 is itself
Answer:
x=1
Step-by-step explanation:
Please write the exponential function. Show work
Answer:
y=10·4^x
Step-by-step explanation:
i need help on this translation stuff
The translated shape would have the vertices of :
U' = (3, 5)S' = (0, 1)T' = (0, 4)How to translate ?Geometry employs translation to move a figure from a certain location to another while retaining its shape, size, and orientation. All points on the initial object are shifted equidistant in a unified direction. A vector showcases the magnitude and course of the movement.
The vectors of the original shape are:
U ( - 2 , 0 )
S ( -5 , - 4 )
T ( - 5, - 1 )
The translated vectors would be:
U' ( - 2 + 5, 0 + 5) = (3, 5)
S' ( -5 + 5, -4 + 5) = (0, 1)
T' ( -5 + 5, -1 + 5 ) = (0, 4)
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( 7x 100) +(5 x 1) +( 8 x 1/10)+( 1x 1/100) why is it not equivalent to 75.81
Step-by-step explanation:
It is NOT equal to 75.81. The correct answer is 705.81
This is because you first multiply each parenthesis then add them together.
So, it would be: 700 + 5 + 0.8 + 0.01= 705.81 not 75.81.
PLSS HEPPPP-P BRAINLIESTTT
Answer:
d awnser
Step-by-step explanation:
when player a played football, he weighed 228 pounds. how many standard deviations above or below the mean was he?
The mean weight of the team was found to be 222.47 pounds. The standard deviation was 28.32 pounds. 3 standard deviations below the mean were 136.83 pounds. Player A was approximately 0.20 standard deviations above the mean.
(i) Mean:
mean = (sum of all weights) / (number of weights) = (177 + 203 + 211 + 211 + 232 + 205 + 185 + 185 + 178 + 210 + 206 + 212 + 184 + 174 + 185 + 242 + 188 + 212 + 215 + 247 + 241 + 223 + 220 + 260 + 245 + 259 + 278 + 270 + 280 + 295 + 275 + 285 + 290 + 272 + 273 + 280 + 285 + 286 + 200 + 215 + 185 + 230 + 250 + 241 + 190 + 260 + 250 + 302 + 265 + 290 + 276 + 228) / (55) = 222.47
So, the mean weight of the team members of Football Team A was approximately 222.47 pounds.
(ii) Standard deviation:
We need to calculate the deviation from the mean for each weight and then find the square of the deviations. We can then find the sum of the squared deviations, divide by the number of weights minus 1, and then find the square root of the result.
Deviation from the mean:
177 - 222.47 = -45.47,
203 - 222.47 = -19.47,
211 - 222.47 = -11.47, and so on till,
228 - 222.47 = 5.53
Squared deviation:
(-45.47)^2 = 2070.5489,
(-19.47)^2 = 379.3409,
(-11.47)^2 = 131.4409, and so on till,
(5.53)^2 = 30.6409.
Sum of squared deviations:
sum = 2070.5489 + 379.3409 + 131.4409 + ... + 30.6409
sum = 30589.6409
standard deviation = square root of [(sum of squares of deviations from the mean) / (number of observations - 1)]
standard deviation = square root of [(30589.6409) / (55 - 1)]
standard deviation = 28.32
So, the standard deviation of the weights of the team members of Football Team A was approximately 28.32 pounds.
(iii) 3 standard deviations below the mean:
3 standard deviations below the mean = mean - (3 * standard deviation) = 222.47 - (3 * 28.32) = 136.83
So, a weight that is 3 standard deviations below the mean is approximately 136.83 pounds.
(iv) Player A's weight in terms of standard deviations:
Player A's weight = 228 pounds
Player A's deviation from the mean = 228 - 222.47 = 5.53
Player A's weight in terms of standard deviations = 5.53 / 28.32 = 0.20
So, Player A was approximately 0.20 standard deviations above the mean.
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Complete question: Following are the published weights (in pounds) of all of the team members of Football Team A from a previous year. 177; 203; 211; 211; 232; 205; 185; 185; 178; 210; 206; 212; 184; 174; 185; 242; 188; 212; 215; 247; 241; 223; 220; 260; 245; 259; 278; 270; 280; 295; 275; 285; 290; 272; 273; 280; 285; 286; 200; 215; 185; 230; 250; 241; 190; 260; 250; 302; 265; 290; 276; 228; 265 Assume the population was Football Team A. Find the following. (Round your answers to two decimal places.) (i) the population mean (ii) the population standard deviation (iii) the weight that is 3 standard deviations below the mean (iv) When Player A played football, he weighed 228 pounds. How many standard deviations above or below the mean was he?
01:48:05
Factor x3 – 7x2 – 5x + 35 by grouping. What is the resulting expression?
(x2 – 7)(x – 5)
(x2 – 7)(x + 5)
(x2 – 5)(x – 7)
(x2 + 5)(x – 7)
Answer:
Step-by-step explanation:
x^2(x - 7) - 5(x - 7)
(x^2 - 5)(x - 7)
Answer:
It’s C on ed 2021
The amounts of nicotine in a certain brand of cigarette are normally distributed with a meank of 0.946 g and standard deviation of 0.289 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine In what range would you expect to find the middle 68% of amounts of nicotine in these cigarettes (assuming the mean has not changed)? Between and If you were to draw samples of size 41 from this population, in what range find the middle 68% of most average amounts of nicotine in' would you expect to the cigarettes in the sample? Between and Enter your answers rounded to 3 decimal places_
We would expect to find the middle 68% of the average amounts of nicotine in a sample of size 41 to be between approximately 0.901 g and 0.991 g by using properties of the normal distribution.
To find the range in which you would expect to find the middle 68% of amounts of nicotine in these cigarettes, we can use the properties of the normal distribution.
Given:
Mean (μ) = 0.946 g
Standard deviation (σ) = 0.289 g
For a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. Therefore, we can expect the middle 68% of amounts of nicotine to fall within the range:
μ ± σ
Substituting the given values:
0.946 ± 0.289
To calculate the range, we have:
Lower bound = 0.946 - 0.289 ≈ 0.657 g
Upper bound = 0.946 + 0.289 ≈ 1.235 g
Therefore, we can expect to find the middle 68% of amounts of nicotine in these cigarettes to be between approximately 0.657 g and 1.235 g.
Now, if we were to draw samples of size 41 from this population, the standard deviation of the sample mean (also known as the standard error) can be calculated as:
Standard error (SE) = σ / √n
where σ is the population standard deviation and n is the sample size.
Substituting the given values:
SE = 0.289 / √41 ≈ 0.045 g
To find the range in which we would expect to find the middle 68% of the sample means, we multiply the standard error by 1 to capture approximately 68% of the data, giving us:
Lower bound = μ - SE ≈ 0.946 - 0.045 ≈ 0.901 g
Upper bound = μ + SE ≈ 0.946 + 0.045 ≈ 0.991 g
Therefore, we would expect to find the middle 68% of the average amounts of nicotine in a sample of size 41 to be between approximately 0.901 g and 0.991 g.
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Please help :) Please help :)
Answer:
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Terra argues that is not a function because two different inputs produce the same output, as shown in the table.
Is Terra correct in claiming that is not a function?
Input Output
-1 2
0 0
1 2
Terra is
correct/incorrect
. In order for a relationship to be a function, each input value must result in
only one input/ multiple outputs
. In this equation, each input value does result in only one output value. It is
allowed/not allowed
for more than one input to have the same out. This does not mean that the relationship is not a function.
Terra is correct. In order for a relationship to be a function, each input value must result in only one input.
What is a function?A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a connection between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is often represented as y = f. (x).
We know that for a function each input value must result in a unique output value. Terra claims this statement, and hence she is correct.
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what is the value of the 4 in the number 546210?
give your anwer in words
Answer:
1000
Step-by-step explanation:
Answer:
10000 or 40000 pls mark this answer as brain list
someone, please help me out with these two problems, it's trig.
Answer:
2nd problem
The sum of the angles of the triangle is 180°.
B= 90°
What is the simplify of 1 2/3 6/5
Step-by-step explanation:
you can look it up
I need help simplifying this problem
Answer: Use math x way it is very helpful for problems like these. The answer is attached.
Step-by-step explanation:
Write an equation of the line that passes through the point (-6, -5) with slope 6.
A. y +5= -6(x+6)
B.y+6= -6(x+5)
C. y+6=6(x+5)
D.y+5= 6(x+6)
Answer:
Option (D) is the correct option.
Step-by-step explanation:
Let the equation of a line which passes through (x', y') and slope 'm' is,
y - y' = m(x - x')
If this line passes through a point (-6, -5) and slope 'm' = 6
Equation of the line will be,
y -(-5) = 6[x - (-6)]
y + 5 = 6(x + 6)
Therefore, equation the line will be y + 5 = 6(x + 6).
Option (D) will be the answer.
can i have some help pls
The ratio of boys to girls in a class is 3:5. There are 40 students in the class. How many more girls than boys are there?
Answer:
3x+5x=40
=8x=40
=x=5
then no.of boys= 3×5 = 15
and no. of girls= 5×5=25
girls more than boys= 25-15=10
mark me brainliest
pls it takes too much time to solve this
Answer:
There will be 10 more girls than boys in the class.
Step-by-step explanation:
5x+3x=40
8x = 40
8x/8 = 40/8
x = 5
5*2 = 10
Which expression is equivalent to (4 x cubed) (2 x) superscript negative 4?
Answer:
section covers somplifying algebraic expressions
Step-by-step explanation:
(4\(x^{3}\))(2\(x^{-4}\)) = \(\frac{4x^{3} }{2x^{4} }\) = 2/x⇒Answer:
A) 1/4x
Step-by-step explanation:
Cause I took the test and got it right
3/5 feet long by 2/3 feet wide
What is the area?
Answer:
2/5
Step-by-step explanation:
To find Area you have times do length times Width so you would be doing 3/5 times 2/3 which would give you 2/5.
Question Content Area
Net Present Value
A project has estimated annual net cash flows of $15,000 for ten
years and is estimated to cost $47,500. Assume a minimum acceptable
rate of return of 20%. Use
The required rate of return (or minimum acceptable rate of return) is 20 percent. If the net cash flows are $15,000 per year for ten years, the total cash flow is $150,000. The project's cost is $47,500. We can now apply the net present value formula to determine whether or not the project is feasible.
Net Present Value (NPV) = Cash flow / (1 + r)^n - Cost Where, r is the discount rate, n is the number of years, and Cost is the initial outlay.
Net Present Value = 150000 / (1 + 0.20)^10 - 47500
Net Present Value = $67,482.22
Since the NPV is positive, the project is feasible. When calculating net present value, it's important to remember that a positive NPV implies that the project is expected to generate a return that exceeds the cost of capital, whereas a negative NPV indicates that the project is expected to generate a return that is less than the cost of capital, and as a result, it should be avoided.
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Express 2.099×104 in normal notation
The number 2.099×\(10^4\) can be expressed in normal notation as 20,990.
To express the number 2.099×\(10^4\) in normal notation, we need to move the decimal point to the right by the exponent value of 10^4, which is 4. By doing so, we obtain the value of 20,990.
Here's the step-by-step calculation:
Start with the given number: 2.099×\(10^4\).
To move the decimal point to the right, we increase the value by a factor of 10 for each position we move.
Since the exponent is 4, we move the decimal point four positions to the right.
After moving the decimal point, we have the value 20,990.
Thus, the number 2.099×\(10^4\) is expressed in normal notation as 20,990.
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the appropriate chi-square test will be performed to test the claim. what is the contribution of the monday absences to the calculation of the chi-square test statistic?
The contribution of the Monday absences to the calculation of the chi-square test statistic would depend on the size of the observed and expected frequencies in that cell relative to the other cells in the table.
Without more information about the specific claim being tested and the data being analyzed, it is difficult to provide a precise answer. However, in general, if the claim being tested involves a comparison of the frequency of absences on Mondays to the frequency of absences on other days of the week, then the number of Monday absences would likely be one of the variables included in the calculation of the chi-square test statistic.
The chi-square test is a statistical test that is used to determine if there is a significant association between two categorical variables. In order to perform the test, the observed frequencies of each category of each variable are compared to the expected frequencies, which are calculated based on the assumption of independence between the variables. The difference between the observed and expected frequencies is then squared, divided by the expected frequency, and summed across all categories of both variables to obtain the chi-square test statistic.
If the claim being tested involves a comparison of the frequency of absences on Mondays to the frequency of absences on other days of the week, then the number of Monday absences would likely be one of the categories of one of the variables included in the calculation of the chi-square test statistic. For example, if the data were organized into a contingency table with one variable representing the day of the week and the other variable representing the frequency of absences on that day, then the number of Monday absences would be one of the cells in the table. The contribution of the Monday absences to the calculation of the chi-square test statistic would depend on the size of the observed and expected frequencies in that cell relative to the other cells in the table.
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In ΔABC, the measure of ∠C=90°, the measure of ∠A=57°, and CA = 2.6 feet. Find the length of BC to the nearest tenth of a foot.
Step-by-step explanation:
The answer for length of BC is 4.0 feet.
caculate the account balance if you invest 15000 for 15 years at 1.5% interest compounded quarterly
The account balance after 15 years with an initial investment of $15,000, compounded quarterly at an interest rate of 1.5%, is $18,899.82.
Formula for compound interestTo calculate the account balance after 15 years with an initial investment of $15,000, compounded quarterly at an interest rate of 1.5%, we can use the formula for compound interest:
A = P(1 + r/n)ⁿᵇ
where:
A = final amount (account balance)
P = principal amount (initial investment)
r = annual interest rate (as a decimal)
n = number of times the interest is compounded per year
b = time (in years)
Plugging in the given values, we get:
A = 15000(1 + 0.015/4)⁴×¹⁵
A = 15000(1 + 0.00375)⁶⁰
A = 15000(1.00375)⁶⁰
A = 15000(1.260655)
A = $18,899.82
Therefore, the account balance after 15 years with an initial investment of $15,000, compounded quarterly at an interest rate of 1.5%, is approximately $18,899.82.
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Really need help and ALL CAPS NO SPACES
Step-by-step explanation:
1. \(x+6 + 3x + 2 + 2x + 4\)
Combine Like Terms:
Answer: \(6x+12\)
G
2. \(6x + 4 + 7x + 1 + 5x + 7\)
Combine Like Terms:
Answer: \(18x+12\)
B
3. \(4x-3 + 3x + 5x - 6\)
Combine Like Terms:
Answer: \(12x-9\)
I
4. \(6x - 8 + 3x + 7 + 5x - 3\)
Combine Like Terms:
Answer: \(14x-4\)
H
Your code is, GBIH
Find the elementary matrix E₁ such that E₁A = B where 9 10 1 20 1 11 A 8 -19 -1 and B = 8 -19 20 1 11 9 10 1 (D = E₁ =
Therefore, the elementary matrix E₁, or D, is: D = [0 0 1
0 1 0
1 0 0]
To find the elementary matrix E₁ such that E₁A = B, we need to perform elementary row operations on matrix A to obtain matrix B.
Let's denote the elementary matrix E₁ as D.
Starting with matrix A:
A = [9 10 1
20 1 11
8 -19 -1]
And matrix B:
B = [8 -19 20
1 11 9
10 1 1]
To obtain B from A, we need to perform row operations on A. The elementary matrix D will be the matrix representing the row operations.
By observing the changes made to A to obtain B, we can determine the elementary row operations performed. In this case, it appears that the row operations are:
Row 1 of A is swapped with Row 3 of A.
Row 2 of A is swapped with Row 3 of A.
Let's construct the elementary matrix D based on these row operations.
D = [0 0 1
0 1 0
1 0 0]
To verify that E₁A = B, we can perform the matrix multiplication:
E₁A = DA
D * A = [0 0 1 * 9 10 1 = 8 -19 20
0 1 0 20 1 11 1 11 9
1 0 0 8 -19 -1 10 1 1]
As we can see, the result of E₁A matches matrix B.
Therefore, the elementary matrix E₁, or D, is:
D = [0 0 1
0 1 0
1 0 0]
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determine the volume of this cube. height = 7 cm length = 14 cm width = 7 cm a. a. 432 cm³. b. b. 682 cm³. c. c. 2744 cm³. d. d. 343 cm³.
This is closest to option d) 343 cm³, The volume of the cube is 343 cm³. which is the correct answer.
The volume of a cube is given by the formula \(V = s^3,\) where s is the length of any side of the cube. In this case, the height, length, and width are all equal to 7 cm. Thus, the length of any side of the cube is also 7 cm.
Substituting s = 7 cm into the formula for the volume of a cube, we get:
V = s^3 = 7^3 = 343 cm³
Therefore, the volume of the cube is 343 cm³. This is closest to option d) 343 cm³, which is the correct answer.
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How do confidence intervals tell you whether your results are statistically significant?.
It can be inferred that there is a statistically significant result if the confidence interval excludes the value of zero effect.
Confidence Interval;
In statistics, confidence is another word for probability. For instance, if you create a confidence interval with a 95% confidence level, you can be sure that 95 times out of 100 the estimate will fall between the upper and lower values indicated by the confidence interval.
Therefore,
The confidence level is 95% if your significance level is 0.05. The hypothesis test is statistically significant if the P value is lower than your significance (alpha) level. The findings are statistically significant if the confidence interval excludes the null hypothesis value. 0
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A package of 12 confetti eggs cost $2.88 At this rate what is the cost of ONE confetti egg
Answer:
$0.24
Step-by-step explanation:
just divide the $2.88 by the 12 to get the unit rate.
The length of a rectangular screen is 15 cm. Its area is 180 sq. cm. Find its width.
\(\\ \rm\hookrightarrow LB=Area\)
\(\\ \rm\hookrightarrow 15x=180\)
\(\\ \rm\hookrightarrow x=180/15\)
\(\\ \rm\hookrightarrow x=12cm\)
Let the width be x
Area = Length × Breadth
180 = 15× x
180=15x
180÷15=15x÷15
12=x or x=12
The width is 12 cm...~