How many moles in 13 grams of C 2 H6 ? show work

Number of Silver atoms : N = 7.8 x 10²² atoms

Given

mass of bracelet : 13.94 g

Required

Number of atoms

Solution

Assuming the bracelet consists entirely of silver

mol of silver :

= mass : molar mass

= 13.94 g : 107,8682 g/mol

= 0.129

Number of atoms :

N = n x No(No = Avogadro's number)

N = 0.129 x 6.02 x 10²³

N = 7.8 x 10²² atoms

A Bronsted-Lowry acid is defined by its ability to donate a proton. A Bronsted-Lowry acid is a substance that can donate protons (hydrogen ions) to other substances during a chemical reaction.

In a chemical reaction, a Bronsted-Lowry acid is any species that loses a proton and a Bronsted-Lowry base is any species that accepts a proton.The Bronsted-Lowry definition of acids and bases defines an acid as a substance that donates hydrogen ions (H+) and a base as a substance that accepts hydrogen ions (H+). The Bronsted-Lowry acid-base theory is the most widely used definition of acids and bases, and it defines an acid as a substance that donates a proton and a base as a substance that accepts a proton.In summary, the ability of a Bronsted-Lowry acid is to donate a proton or hydrogen ion during a chemical reaction to another substance or base.

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The result of 554.3x10^117 - 5044x10^116 in standard form is  -4988.57 x10^116

The term standard form refers to a way in which mathematical notation is made much easier. It is always a number multiplied by 10 raised to a given power.

As such, the problem 554.3x10^117 - 5044x10^116 can be written as; 55.43x10^116 - 5044x10^116 = -4988.57 x10^116

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Workplace labels are not required to include borders or particular language, but they do need the following details: Product identification data for the product's secure handling.

Labels are a suitable set of written, printed, or graphic informative components about a hazardous chemical some of which are attached to, printed on, or fastened to the adjacent container of something like a hazardous chemical but rather to the outside packaging, as defined by the HCS.

In order to give the customer the ability to make an educated decision regarding the potential for energy savings—and consequently, cost savings—of the relevant marketed product, the Bureau the Energy Efficiency launched this same Standards & Branding programme for appliances and appliances in 2006.

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Answer:

There are 122.1982401 moles of  H2O in \(7.36*10^{25}\)  molecules of H2O

Explanation:

We know,

\(6.023*10^{23}\)  molecules of H2O contains 1 mole H2O

            1      molecules of H2O contains \(\frac{1}{6.023*10^{23}}\)  mole H2O

∴ \(7.36*10^{25}\) molecules of H2O contains \(\frac{1}{6.023*10^{23}}*(7.36*10^{25})\) moles of H2O

                                                               = 122.1982401 moles of  H2O

∴ There are 122.1982401 moles of  H2O in \(7.36*10^{25}\)  molecules of H2O

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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The total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

Given Potential for two inert gas (Xe) atoms at separation R :

U=λe^(-R/rho)-R^6/a^6

a) To calculate the potential energy of the two atoms at equilibrium separation R_0,

we have to put dU/dR = 0λ e^(-R_0/rho) = (6R_0^6)/(a^6)λ e^(-R_0/rho) = (6(12rho)^6)/(a^6)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12)

The potential energy can be expressed as, U=λe^(-R_0/rho) = ((6(12rho)^6)/(a^6)) * e^(12) * e^(-12rho/rho)= ((6*12^6)/a^6) * e^(-11rho)

b) Given R_0 = 12rho, λ = (6(12rho)^6)/(a^6) * e^(12)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Potential energy U = λe^(-R_0/rho) = (6 * 12^6)/(a^6) * e^(-11rho)c)

The total interaction energy in units of eV/ atom assuming λ = 4156 eV and R_0/rho = 12

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Total energy (U) = (N/2)U = (N/2)λe^(-R_0/rho) = (N/2)(6 * 12^6)/(a^6) * e^(-11rho) = 150N eV/atom.

Therefore, the total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

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The chemical equation is H₂SO₄ → 2H⁺ + SO₄⁻². It gives H⁺ ions in aqueous solution so it is an arrhenius acid.

According to the arrhenius theory acid and base are divided according to their ability to provide H⁺ and OH⁻ ions.

If it dissolve substance in an aqueous solution and it gives H⁺ ions then it means that it is an arrhenius acid.

While dissolve a substance in an aqueous solution and give it gives OH⁻ ions then it means that it is in arrhenius base.

When we dissolve H₂SO₄ in water it dissociates into ions.

The chemical equation for the dissociation is,

H₂SO₄ → 2H⁺ + SO₄⁻²

As we can see that sulphuric acid is providing 2H⁺ ions in the aqueous solution then it means that it is an arrhenius acid.

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\(\\ \tt\hookrightarrow C_{15}H_{32}+23O_2\longrightarrow 15CO_2+16H_2O\)

\(\\ \tt\hookrightarrow CO_2+CaO=CaCO_3\)

1) The balanced equation for the combustion of C15H32 (pentadecane) is:

C15H32 + 23O2 → 15CO2 + 16H2O

2) To test for the presence of carbon dioxide (CO2) in the products of the combustion of C15H32, one simple way is to bubble the gas through limewater (aqueous calcium hydroxide solution). When carbon dioxide is passed through limewater, it reacts with the calcium hydroxide to form a white precipitate of calcium carbonate according to the following chemical equation:

Ca(OH)2 + CO2 → CaCO3 + H2O

The formation of a white precipitate indicates the presence of carbon dioxide in the gas. Another way to test for the presence of carbon dioxide is to use a pH indicator, such as universal indicator or litmus paper. When carbon dioxide dissolves in water, it forms a weak acid called carbonic acid. This can be detected by observing a change in the color of the pH indicator. Carbon dioxide will turn universal indicator yellow or litmus paper red, indicating an acidic solution.

Answer:

10.875 miles

So 87 minutes

.125 miles per minute

So just multiply int his case

87*.125

You’d get 10.875

Chemical chemical X. The silicon is available. This information is not given here. Therefore, we shall use the atomic number as the amount of protons. So, the solution is 17.

A proton, a quasiparticle, is found in the nucleus of every atom.. The particle has an electrical charge that is positive and opposite to the electron's. A single proton would weigh just 1.673? 10-27 kilos if it were isolated, which is only a little bit less than a neutron.

A subatomic particle with a negative charge is an electron. A proton is an unit of matter with the a positive charge. Protons are bound together in an atom's nucleus by the potent nuclear energy. The neutron is a type of subatomic particle sans charge (they are neutral).

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Answer:

mid-ocean ridge.

Explanation:

Answer:

See explanation

Explanation:

A salt is made up of homogeneous particles while sand is made up of heterogeneous particles. Salt is a crystalline substance while sand is a coarse substance.

If salt and sand are mixed with water, salt forms a solution with water, hence, salt cannot be caught on filter paper. However, sand does not form any chemical specie with water hence it is caught on the filter paper as a solid.

Answer:

\(\boxed {\boxed {\sf 4 \ g/cm^3}}\)

Explanation:

We are asked to find the density of a brick. Density is a substance's mass per unit volume. The formula for calculating density is as follows.

\(\rho= \frac{m}{v}\)

The mass of the brick is 100 grams and the volume is 25 cubic centimeters.

Substitute the values into the formula.

\(\rho= \frac{ 100 \ g}{25 \ cm^3}\)

Divide.

\(\rho=4 \ g/cm^3\)

The density of the brick is 4 grams per cubic centimeter.

Explanation:

\(v = vdm \times n\)

Vdm=22.4dm.

mole(n)=4 mol

therefore the total volume

\(v = 22.4 \times 4 \\ v = 89.6dm\)

Answer:

cell wall > skeletal system (maybe)

cell membrane > skin (maybe)

nucleus > brain

mitochondria > digestive system

Explanation:

The cations found in higher concentration in the intracellular fluid (ICF) are potassium (K⁺) and magnesium (Mg²⁺). To provide an explanation step by step, the following can be noted:

1. The ICF is the fluid inside cells, which is separated from the extracellular fluid (ECF) by the cell membrane.
2. The ICF contains many ions, including cations (positively charged ions) such as K⁺ and Mg²⁺.
3. These cations are involved in many cellular processes, such as maintaining cell membrane potential and regulating enzymatic activity.
4. K⁺ is the most abundant cation in the ICF, with a concentration of about 140 mM.
5. Mg²⁺ is also found in higher concentration in the ICF compared to the ECF, with a concentration of about 1 mM in the ICF and 0.5 mM in the ECF.
6. The concentration of these cations in the ICF is carefully regulated by ion channels and transporters in the cell membrane to maintain proper cellular function.

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Answer:

Explanation:

Hope that helps if not lmk have a wonderful day!

Answer:

A Homogeneous mixture is one that consists of a single type of element, for example - Oxygen, as it consists two oxygen atoms to make one oxygen molecule. Hope my answer helps :)

The balanced chemical equation is:

0.5C7H16 + O2 → 0.5CO2 + H2O

For balancing the chemical equation C7H16 + O2 → CO2 + H2O, we can use linear algebraic techniques. We need to determine the coefficients that balance the number of atoms on both sides of the equation.

Let's denote the coefficients for C7H16, O2, CO2, and H2O as a, b, c, and d, respectively.

The balanced chemical equation can be written as:

aC7H16 + bO2 → cCO2 + dH2O

To balance the carbon (C) atoms, we have:

7a = c (Equation 1)

To balance the hydrogen (H) atoms, we have:

16a = 2d (Equation 2)

To balance the oxygen (O) atoms, we have:

2b = 2c + d (Equation 3)

We have three equations (Equations 1, 2, and 3) and four unknowns (a, b, c, d). To solve this system of equations, we can write it in matrix form and find the solution using linear algebraic techniques.

The augmented matrix for the system of equations is:

[ 7 0 -1 0 | 0 ]

[ 0 0 0 -2 | 0 ]

[ 0 -2 2 -1 | 0 ]

By performing row operations to row-reduce the augmented matrix, we can obtain the solution:

[ 1 0 -0.5 0 ]

[ 0 1 -1 -0.5 ]

[ 0 0 0 0 ]

The solution to the system of equations is:

a = 0.5

b = 1

c = 0.5

d = 1

Putting the values of a,b,c, and d we get the balanced chemical equation as:

0.5C7H16 + O2 → 0.5CO2 + H2O

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Answer:

The boiling point of NaBr is higher than that of Na2S

Explanation:

Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point

Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.

Hence, the boiling point of NaBr is higher than that of Na2S

19.4 mol Kr

Chemistry

Stoichiometry

Gas Laws

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

435 L Kr at STP

Step 2: Identify Conversions

[STP]   22.4 L = 1 mol

Step 3: Convert

\(435 \ L \ Kr(\frac{1 \ mol \ Kr}{22.4 \ L \ Kr} )\) = 19.4196 mol Kr

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

19.4196 mol Kr ≈ 19.4 mol Kr

Answer:4

To calculate the volume of the reactor and space-time for a reversible gas phase reaction, A+2B, conducted at 540 °F and 3 atm with a feed rate of 75 lb mol/h and 40% A, and an equilibrium conversion of 75%, we need to consider the specific reaction rate and the concentration equilibrium constant.

The space-time for a reactor is defined as the volume of the reactor divided by the feed rate. To calculate the volume of the reactor, we first determine the molar flow rate of component A, which is 75 lb mol/h * 0.40 = 30 lb mol/h. Then, we divide the molar flow rate of A by the specific reaction rate to obtain the volume: Volume = 30 lb mol/h / (1.6 s * 3600 s/h) = 5.2083 ft³.

To calculate the space-time, we divide the volume by the feed rate: Space-time = 5.2083 ft³ / 75 lb mol/h = 0.0694 ft³/lb mol/h.

Therefore, the volume of the reactor is 5.2083 ft³ and the space-time is 0.0694 ft³/lb mol/h.

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Answer:

It provides the electrons that "make" electricity and it contains the electrons that are involved in molecular bond formation.

The chemical formula of aluminum chloride is AlCl₃ and the  chemical formula of aluminum oxide is Al₂O₃.

The chemical formula of aluminum chloride is written as;

Al³⁺  + Cl⁻   → AlCl₃

The chemical formula of aluminum oxide is written as;

Al³⁺  + O²⁻   → Al₂O₃

Thus, the chemical formula of aluminum chloride is AlCl₃ and the  chemical formula of aluminum oxide is Al₂O₃.

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Answer:

gg mate

Explanation:

Nitroglycerin transdermal patches can be used in the management of angina and can deliver therapeutic dosages for up to 24 hours. These patches contain nitroglycerin and are applied to the skin to provide continuous delivery of nitroglycerin.

Nitroglycerin is a vasodilator that dilates blood vessels and helps improve blood flow. Nitroglycerin can help reduce the frequency and severity of angina attacks by dilating the arteries in the heart, which increases blood flow to the heart and reduces the workload of the heart.Due to the skin's characteristics, the nitroglycerin transdermal patch slowly releases nitroglycerin into the bloodstream over an extended period of time. The duration of the action of a nitroglycerin transdermal patch is usually 24 hours, and the drug is absorbed through the skin.The medication's therapeutic effect lasts for around 14 hours on average, with the remaining ten hours serving as a drug-free period. After removal of the nitroglycerin patch, the effect of the medication begins to wear off within hours, typically four to six hours.Because of its long duration of action, nitroglycerin transdermal patches are particularly beneficial for individuals who have angina symptoms that occur regularly and can cause discomfort throughout the day.

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The value of x in the x% nickel alloy is 15%.

To find the worth of x, we can set up a situation in light of how much nickel in the amalgams:

(0.35 * 2) + (x * 6) = 0.20 * (2 + 6)

To start with, we ascertain how much nickel contributed by the 35% nickel combination, which is 0.35 * 2 grams = 0.7 grams. The x% nickel compound contributes x grams of nickel when joined with 6 grams.

The aggregate sum of nickel in the subsequent 20% nickel compound is 0.20 * (2 + 6) = 1.6 grams.

Presently we can address the condition:

0.7 + 6x = 1.6

Taking away 0.7 from the two sides:

6x = 1.6 - 0.7

6x = 0.9

Partitioning the two sides by 6:

x = 0.9/6

x = 0.15

Hence, the worth of x is 0.15, or 15%.

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