How many moles can be found in 3.2526443x1023 atoms in Bismuth?

Answer:

When the silver-colored penny is heated, the outside zinc atoms and inside copper atoms move around because of the heat excitement. This makes the outer layer of zinc mix with the copper below, which becomes an alloy called yellow brass

Explanation:

hydrated cucl2 have blue-green colour

The mass of 2.80 moles of H2O is approximately 50.441 grams.

Molar mass is the mass of one mole of a substance and is expressed in units of grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in a molecule, and it is expressed in the same units as atomic mass, which is atomic mass units (amu).

The molar mass of water (H2O) is 18.01528 g/mol (2 hydrogen atoms with atomic mass 1.008 and 1 oxygen atom with atomic mass 15.999).

To find the mass of 2.80 moles of H2O, we can use the following formula:

mass = number of moles x molar mass

Plugging in the values, we get:

mass = 2.80 mol x 18.01528 g/mol

mass = 50.441 g

Therefore, the mass of 2.80 moles of H2O is approximately 50.441 grams.

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Answer:

See below

Explanation:

To convert from Celcius to Kelvin, you add 273.15.

To convert from Kelvin to Celcius, you subtract 273.15

109.85     383

80            353.15

49.85       323

10             283.15

-10            263.15

-30.15       243

The conclusion about the rates of the rotting reaction from the table would be that the reaction occurs more quickly when the concentration of salt is higher—option B.

The rate of reaction, or reaction rate, is the time it takes for a reaction to occur. In other words, it is the time it takes for the reactants of a reaction to become products.

In this case, the reactant is the rope and the product is the rotten product of the rope. From the table, it took 10 years for the rope to decay in a lake. On the other hand, it took the same rope just 4 years to decay in an ocean.

The difference between the two water bodies is the presence of salt. The lake has almost zero salt while the conentration of salt in the ocean water is high.

Thus, the conclusion about the rate of rotting reaction would be that the reaction is hastened by the presence of salt in the ocean water.

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Dew forms on the grass in the early morning due to the process of condensation.

During the day, the sun heats up the ground and the air around it. When the sun sets, the ground and the air begin to cool down. As the air cools, its ability to hold moisture decreases. When the temperature drops below the dew point, which is the temperature at which the air is saturated and cannot hold any more moisture, the excess moisture in the air condenses into liquid water droplets. These droplets then collect on cool surfaces, such as grass, forming dew.

The grass is a good surface for dew to form on because it is usually cooler than the surrounding air due to transpiration, the process by which water evaporates from the leaves and stems of plants. This causes the grass to cool down faster than the air around it, making it more likely for dew to form on its surface.

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Any three base sequence found on the mRNA that codes for a specific amino acid is called a codon.

The three base of the sequences that are found in the mRNA , the one after another code for the specific amino acid. So, the three bases are together is known as the codons and it based on the codon sequence of the mRNA polypeptides will be produced.

The polypeptides will be formed after the translation and it based on the codons in the mRNA the peptide will be produced.  The coons are the specific for the single amino acid that will makes the codons universal.

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To calculate the volume of the reactor and space-time for a reversible gas phase reaction, A+2B, conducted at 540 °F and 3 atm with a feed rate of 75 lb mol/h and 40% A, and an equilibrium conversion of 75%, we need to consider the specific reaction rate and the concentration equilibrium constant.

The space-time for a reactor is defined as the volume of the reactor divided by the feed rate. To calculate the volume of the reactor, we first determine the molar flow rate of component A, which is 75 lb mol/h * 0.40 = 30 lb mol/h. Then, we divide the molar flow rate of A by the specific reaction rate to obtain the volume: Volume = 30 lb mol/h / (1.6 s * 3600 s/h) = 5.2083 ft³.

To calculate the space-time, we divide the volume by the feed rate: Space-time = 5.2083 ft³ / 75 lb mol/h = 0.0694 ft³/lb mol/h.

Therefore, the volume of the reactor is 5.2083 ft³ and the space-time is 0.0694 ft³/lb mol/h.

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Based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

To determine the relative contribution of C3 and C4 plants to the soil organic matter in Kenya based on their stable carbon isotopic composition, we can use the concept of isotopic discrimination.

C3 and C4 plants have different photosynthetic pathways, and they exhibit distinct carbon isotope signatures. C3 plants typically have a more negative δ13C value (around -30 permil to -22 permil), while C4 plants have a less negative δ13C value (around -16 permil to -9 permil).

In this case, the soil organic matter in Kenya has a δ13C value of -18 permil, while the air δ13C value is -7 permil. The difference between these values (-18 permil - (-7 permil)) gives us the isotopic discrimination between the atmosphere and the soil organic matter.

δ13C discrimination = δ13C organic matter - δ13C atmosphere

δ13C discrimination = -18 permil - (-7 permil)

δ13C discrimination = -11 permil

Since the δ13C discrimination is negative, it suggests that C3 plants have a dominant contribution to the soil organic matter. C4 plants, with their less negative δ13C values, are less likely to contribute significantly to the organic matter in this case.

Therefore, based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

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Answer:

The given equation shows the decomposition of hydrated sodium sulfate to form anhydrous sodium sulfate:

$Na_2SO_{4 \cdot x} \rightarrow Na_2SO_4 + xH_2O$

From the given data, we know that 10.10 g of hydrated sodium sulfate decomposes to form 4.40 g of anhydrous sodium sulfate. Let's first calculate the number of moles of anhydrous sodium sulfate formed:

$Moles\ of\ Na_2SO_4\ =\ \frac{4.40\ g}{142.04\ g/mol} = 0.0310\ mol$

Since one mole of hydrated sodium sulfate produces one mole of anhydrous sodium sulfate, the number of moles of hydrated sodium sulfate present in 10.10 g can be calculated as:

$Moles\ of\ Na_2SO_{4 \cdot x}\ =\ 0.0310\ mol$

The formula mass of the hydrated sodium sulfate can be calculated by adding the molar masses of all its constituent atoms:

$Formula\ mass\ of\ Na_2SO_{4 \cdot x}\ =\ 2\times23.00\ g/mol\ +\ 32.06\ g/mol\ +\ x\times18.02\ g/mol = 142.04\ g/mol$

Solving for x, we get:

$x = \frac{142.04\ g/mol - 46.00\ g/mol - 32.06\ g/mol}{18.02\ g/mol} = 4$

Therefore, the formula of the hydrated sodium sulfate is $Na_2SO_{4 \cdot 4H_2O}$ and its formula mass is 322.20 g/mol.

Answer:

Problem: What is the effect of the amount of fish feed on the mass of goldfish?

Hypothesis: I think that feeding the goldfish four times a day will greatest increase in the mass of the goldfish.

Explanation:

The problem tends to ask question to which the research is conducted. It open ways for ideas towards a particular topic.

While the hypothesis is a tentative or assumed stand on a subject. It is further tested through an experiment or survey and if after many trials it gives same results and the obtained results is concordant with the hypothesis, the hypothesis will then become accepted and a theory or law is formed thereafter.

The emitted fluorescent light has longer wavelength and lower energy because it lost some energy to the solvent molecules and some fraction of energy is dissipated as heat.

A material that has absorbed light or other electromagnetic radiation will emit light when it undergoes fluorescence. It has a luminescent quality. Most of the time, the emitted light has a lower photon energy than the absorbed radiation because it has a longer wavelength.

Fluorescence can be seen when the emitted light is in the visible spectrum while the absorbed radiation is in the ultraviolet (UV) region of the electromagnetic spectrum, which is invisible to the human eye.

The fluorescent photons have lower energy. The non-radiative  vibrational transitions taking place in between causes dissipation of energy as heat and some energy is transferred to the solvent molecules.

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To determine the volume of N2(g) produced by the complete decomposition of 1 mole of nitroglycerin (C3H5N3O9), we need to consider the balanced chemical equation for the decomposition reaction.

The balanced equation for the decomposition of nitroglycerin is as follows:

4 C3H5N3O9(s) → 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g) From the balanced equation, we can see that for every 4 moles of nitroglycerin, 6 moles of N2(g) are produced. Since we are considering the decomposition of 1 mole of nitroglycerin, we can use this ratio to determine the moles of N2(g) produced, which is 6/4 = 1.5 moles of N2(g). Now, at STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1.5 moles of N2(g) would occupy approximately 33.6 liters

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Answer:

the large object moving quickly because the more the mas the more kenetic energy

The answer is:

Because they have 1 more or less electron in there last orbit, so they are very active to form compounds which make them stable.

Hope this will help you❤️

The empirical formula of the solvent is CH4.

Relative number of atoms

Of H= 25/1 = 25

Of C= 75/12 = 6.25

What is a solvent?

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The reaction between tin (IV) oxide and carbon produces tin and carbon monoxide, obeying the law of conservation of mass with equal moles and mass on both sides.

In the given reaction, SnO₂ (s) + 2C (s) → Sn (l) + 2CO (g), tin (IV) oxide (SnO₂) reacts with carbon (C) to produce tin (Sn) and carbon monoxide (CO).

In terms of particles, one mole of SnO₂ reacts with two moles of carbon to produce one mole of tin and two moles of carbon monoxide. The mass of the reactants equals the mass of the products, as demonstrated by the balanced chemical equation.

This illustrates the law of conservation of mass, which states that mass is neither created nor destroyed during a chemical reaction, maintaining a constant mass before and after the reaction.

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Answer:

Helium will heat up the fastest

Explanation:

Answer:

0.02 m

Explanation:

∆U = q + w

w = ∆U - q = (1380 - 2040) J = -660 J

w = -p∆V = -pA∆h

∆h = -w/(pA)

p = 1 bar × (100000 Pa/1 bar) = 100000 Pa

∆h = -(-660 J)/(100000 Pa×0.33 m²) = 0.02 m

A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2. The distance through which the piston moves is 0.02 m.

Among other related systems, pistons are found in reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders. It is the moving part that is enclosed in a cylinder and sealed off from the gas by piston rings.

The piston, which is a part of combustion engines, transforms the energy released during combustion into a mechanical action and sends it, via the piston pin and connecting rod, to the crankshaft as a torsional force. The piston in the cylinder goes up and down when the engine is running.

The equation given by

∆ U = q + w

w = ∆ U - q

= ( 1380 - 2040 )

J = -660 J

w = -p∆V

= -pA∆h

∆h = -w / (pA)

p = 1 bar × ( 100000 Pa / 1 bar )

= 100000 Pa

∆h = - ( -660 J) / ( 100000 Pa × 0.33 m² )

= 0.02 m

Thus, The distance through which the piston moves is 0.02 m.

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Answer:

Answer: When you add an electron to zinc, it needs some extra energy. This is because zinc atoms naturally don't like having an extra electron. The extra electron and the electrons already present in zinc repel each other due to their negative charges. So, you have to give some energy to the zinc atom to overcome this repulsion and make it accept the additional electron. Basically, energy input is required to make zinc accept an extra electron because the electron doesn't fit easily and needs some force to be added.

Explanation: hope this helps

To form 1.4 mol of ammonia, you need 0.7 mol of nitrogen.

Ammonia is formed by combining nitrogenand hydrogenin a 1:3 ratio, as shown in the balanced chemical equation:

N₂ + 3H₂ → 2NH₃

To determine the amount of nitrogen needed to form 1.4 mol of ammonia, follow these steps:

1. Identify the stoichiometry of the reaction: 1 mol N2 reacts with 3 mol H2 to produce 2 mol NH3.
2. Divide the desired amount of ammonia (1.4 mol) by the stoichiometric coefficient of ammonia (2 mol): 1.4 mol / 2 mol = 0.7.
3. Multiply the result (0.7) by the stoichiometric coefficient of nitrogen (1 mol): 0.7 x 1 mol = 0.7 mol.

Therefore, you need 0.7 mol of nitrogen to form 1.4 mol of ammonia.

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Answer:

C) protons and neutrons

Explanation:

im pretty sure it is c

Answer:

3.38  Tablespoons

10.14 Teaspoons

0.21 U.S. Cups

0.18 Imperial Cups

0.20 Metric Cups

50.00 Milliliters

Explanation:

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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Answer:B

Explanation:

The compound that would be the second from the left according to the list is H₂0. Option B

We know that a compound can be said to be formed when there is a combination of two or more atoms. The combination of the atoms can be able to show us that there is a compound that if formed.

In this case, the task that we have is to be able to arrange the compounds in the order of the intermolecular interactions that are able to exist in the compound as it has to do with how the compound would be able to exist.

By looking at the table, we can see that the order in which the compounds are going to appear would depend on the magnitude of the electronegativity difference that we can be able to observe between the atoms in the compound.

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And at the end we will calculate enthalpy by expressing it from the following equation:ΔmixH=ΔmixG+TΔmixS=−3.43⋅103J+(298K)(11.5JK−1)=−3.43⋅103J+3.43⋅103J=0J/mol Δmix​H​=Δmix​G+TΔmix S=−3.43⋅103J+(298K)(11.5JK−1)=−3.43⋅103J+3.43⋅103J=0J/mol​

ΔG is Gibbs free energy change. For an ideal solution. ΔHmix=0. ΔG<0 i.e., negative. ΔG=ΔH−TΔS.

The molar enthalpy HA+ B of a mixture of A + B can be obtained by combining the molar excess enthalpy H E with the molar enthalpies H A and HB of its pure components: HA + B = XA HA + XB HB + H E, (1) where x denotes mole fraction.

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