How many moles are equal to 13.2 L of NFCI3 gas at STP? Need the equation

Answer:

Electrical current drives nonspontaneous reactions in electrolytic cells.

Explanation:

Electrochemical cells are cells that produce electrical energy from chemical energy.

There are two types of electrochemical cells; voltaic cells and electrolytic cells.

A voltaic cell is an electrochemical cell in which electrical energy is produced from spontaneous chemical process while an electrolytic cell is an electrochemical cell where electrical energy is produced from nonspontaneous chemical processes. Current is needed to drive these nonspontaneous chemical processes in an electrolytic cell.

Answer:

electrolytic cells generate electricity through a non-spontaneous reaction while voltaic cells absorb electricity to drive a spontaneous reaction.

Explanation:

Answer via Educere/ Founder's Education

Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

The E2 elimination reaction of cyclo-alkylhalides are usually stereo selective. Usually trans isomer reacts slowly than cis-isomer. So the elimination reaction in an alkaline potassium hydroxide medium will be  1-methyl cyclohexene.

The reason behind stereo selectivity is because pf the spatial orientation of the substituents on the ring structure. For cyclic compounds this has a great influence to direct a reaction in Regio-selectivity. The transition state between the reactant and product  influence in the rate of elimination reaction.

Here the major elimination product is 1-methyl cyclohexene and a minor amount of 3-methyl cyclohexene is also produced.

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(The question is not complete. The complete question is given as an image)

The pressure of the gas when the temperature changes from -75.0°C to 1000.0°C will be approximately 9.51 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

Given that:

We substitute our values into the expression above.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

\(P_2 = \frac{P_1T_2}{T_1}\\ \\P_2 = \frac{1.480\ *\ 1273.15 }{198.15} \\\\P_2 = 9.51 \ atm\)

Therefore, the final pressure is 9.51 atm.

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The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Answer:

Generally the ice should be more than 4 inches thick to skate on it safely. However, the ice thickness is not always even and there can be thin spots, especially near springs or near river inlets or outlets. Most lakes and ponds don't completely freeze because the ice (and eventually snow) on the surface acts to insulate the water below. Our winters aren't long or cold enough to completely freeze most local water bodies. This process of lakes turning over is critically important to the life in the lake.

Explanation:

Answer:

8.28 × 10⁶ N

Explanation:

Step 1: Given data

Interior surface area of the habitat (S): 110 m²

Pressure in the habitat (P): 75.3 kPa

Step 2: Convert "P" to Pascal

We will use the conversion factor 1 kPa = 10³ Pa.

75.3 kPa × (10³ Pa/1 kPa) = 75.3 × 10³ Pa

Step 3: Calculate the total force exerted (F)

We will use the following expression.

P = F/S

F = P × S

F = 75.3 × 10³ Pa × 110 m²

F = 8.28 × 10⁶ N

In water (H2O), there are two atoms of hydrogen (H) and one atom of oxygen (O) per molecule. The atomic mass of hydrogen is approximately 1.008 g/mol and the molecular mass of water is approximately 18.015 g/mol.

To calculate the grams of hydrogen in 10.05 grams of water, we need to first determine the number of moles of water present:

moles of water = mass of water / molecular mass of water

moles of water = 10.05 g / 18.015 g/mol

moles of water = 0.5575 mol

Since there are two hydrogen atoms in each molecule of water, the number of moles of hydrogen is twice the number of moles of water:

moles of hydrogen = 2 x moles of water

moles of hydrogen = 2 x 0.5575 mol

moles of hydrogen = 1.115 mol

Finally, we can calculate the grams of hydrogen by multiplying the number of moles of hydrogen by the atomic mass of hydrogen:

grams of hydrogen = moles of hydrogen x atomic mass of hydrogen

grams of hydrogen = 1.115 mol x 1.008 g/mol

grams of hydrogen = 1.12352 g

Therefore, there are approximately 1.12352 grams of hydrogen present in 10.05 grams of water.

Hydrogen is a chemical element with the symbol H and atomic number 1. It is the lightest and most abundant element in the universe, constituting roughly 75% of all baryonic mass. Hydrogen is a colorless, odorless, and tasteless gas that is highly flammable.

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1dl/100ml is the missing part of the equation

Equations are not typically measured in the same way that physical quantities are measured.

An equation is a mathematical statement that shows that two expressions are equal. Equations can be used to represent a variety of relationships in mathematics, physics, chemistry, and other fields.

we know that 0.01 dl is the same as 1 ml = 1 / 100

-3.4 x 10^3 ml x 1 dl/100 = -34 dl

hence the answer to the missing part is given as 1dl/100

The solution of the equation is given as -34dl

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Hydrocarbons is an ester is A skeletal model of a chain of 4 carbons, an O and 4 more Carbons. The fourth carbon is double - bonded to an O.

An ester defined as the compound that derived from an oxoacid in which  one hydroxyl group is replaced by alkoxy group. the general formula for the ester is given as :

R - COOO - R'

the examples of ester is : ethyl acetate , methyl Butyrate.

it is a sweet smelling substances used in perfumes and cosmetics.

thus, Hydrocarbons is an ester is A skeletal model of a chain of 4 carbons, an O and 4 more Carbons. The fourth carbon is double - bonded to an O.

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Answer:

C

Explanation:

did it on edge :)

Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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The calculated answer is 1.99 x 10/21 x Au

Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.

Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.

The term "atomic weight" refers to an atom's overall weight. With the addition of a small amount from the electrons, it is roughly equal to the sum of the protons and neutrons. The number of neutrons an atom has has a significant impact on the stability of the nucleus and, consequently, the radioactivity of the atom. The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.

Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.

(Atomic weight in g/mol on the periodic table).

0.00330 mol = 0.650 g Au = 196.966569 gmol Au Gold atoms 1 mole of atoms is equal to 6.02210/23 atoms.

double the estimated mol Au by several.

6.022×10/23 atoms1mol.

0.00330mol Au = 6.022 x 10/23 x 1 mol

= 1.99 x 10/21 x Au

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Answer: C. the same amount of energy as

Explanation:

A reversible reaction is a chemical reaction where the reactants form products that, in turn, react together to give the reactants back.

Reversible reactions will reach an equilibrium point where the concentrations of the reactants and products will no longer change.

\(A+B\rightleftharpoons C+D\)

Thus if forward reaction is exothermic i.e. the heat is released , the backward reaction will be endothermic i.e. the heat is absorbed and in same amount.

The amount of energy released will be equal and opposite in sign to the energy absorbed in that reaction.

Answer:

C.) the same amount of energy as

Explanation:

I got it correct on founders edtell

The oil from cars is gotten from crude oil.

The car is an automobile that is mainly used for transportation purposes. It is made up of both electrical and mechanical parts.

The mechanical part of the car is driven by the engine which is the heart of the car.

The engine is made up of adjacent moving parts that need to be frequently lubricated through the engine oil.

The engine oil is gotten from crude oil, which is a mixture of hydrocarbons  that exist in liquid phase in natural underground reservoirs.

Therefore, the oil from cars is gotten from crude oil.

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Answer:

148.04 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

NO(g) + 1/2 O₂(g) → NO₂(g)      ΔH°rxn = -114.14 kJ/mol

We can find the standard enthalpy of formation (ΔH°f) of NO(g) using the following expression.

ΔH°rxn = 1 mol × ΔH°f(NO₂(g)) - 1 mol × ΔH°f(NO(g)) - 1/2 mol × ΔH°f(O₂(g))

ΔH°f(NO(g)) = 1 mol × ΔH°f(NO₂(g)) - ΔH°rxn - 1/2 mol × ΔH°f(O₂(g)) / 1 mol

ΔH°f(NO(g)) = 1 mol × 33.90 kJ/mol - (-114.14 kJ) - 1/2 mol × 0 kJ/mol / 1 mol

ΔH°f(NO(g)) = 148.04 kJ/mol

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

Zn + 2HCl -> H2 + ZnCl2

CS2 + 2O2 -> CO2 + S2O2

Explanation:

Answer:

\(\displaystyle K_a = 4.24\times 10^{-10}\)

Explanation:

Write the base reaction of NaA with water:

\(\displaystyle \text{A}^-_\text{(aq)}+\text{H$_2$O}_\text{($\ell$)}\rightleftharpoons \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)}\)

Hence, the equilibrium constant expression for the reaction is:
\(\displaystyle K_b = \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]}\)

Thus, to find Ka, we can find Kb and use the fact that Ka × Kb = Kw.

From the reaction and initial concentration of NaA, create an ICE chart:

\(\begin{tabular}{llllll} & A^- &\text{H$_2$O} & \rightleftharpoons & HA & OH^- \\I & 0.563 M & \---- & & 0 M & 0 M \\C & -\text{ $ x$} & \---- & & +\text{ $x$ M} & + \text{$x$ M} \\E & \text{(0.563 - $x$) M} & \---- & & \text{$x$ M} & \text{$x$ M} \end{tabular}\)

Find [OH⁻] from the given pH:
\(\displaystyle \begin{aligned} \text{pH} +\text{pOH} & = 14.00 \\ \\ \text{pOH} & = 14.00 - \text{pH} \\ \\ & = 14.00 - (11.56) \\ \\ & = 2.44 \\ \\ -\log[\text{OH}^-] & = 2.44 \\ \\ [\text{OH}^-] &= 10^{-2.44} \\ \\ & =0.00363 \text{ M}= 3.63\times 10^{-3} \text{ M} = x\text{ M}\end{aligned}\)

Solve for all species concentrations at equilibrium from the found x value:

\(\displaystyle [\text{HA}] = [\text{OH}^-] = 3.63\times 10^{-3} \text{ M}\)

And:

\(\displaystyle \begin{aligned} \ [\text{A}^-] & = 0.563 - 3.63\times 10^{-3} \text{ M}\\ \\ & = 0.559\text{ M}\end{aligned}\)

Find Kb:

\(\displaystyle \begin{aligned} \displaystyle K_b &= \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]} \\ \\ & = \frac{(3.63\times 10^{-3})(3.63\times 10^{-3})}{(0.559)}\\ \\ & = 2.36\times 10^{-5}\end{aligned}\)

Find Ka:

\(\displaystyle \begin{aligned} K_a\cdot K_b & = K_w \\ \\ K_a & = \frac{K_w}{K_b} \\ \\ & = \frac{(1.00 \times 10^{-14})}{(2.36\times 10^{-5})} \\ \\ &= 4.24\times 10^{-10} \end{aligned}\)

In conclusion:
\(\displaystyle K_a = 4.24\times 10^{-10}\)

Explanation:

Well,

Light travels approximately 1 foot per nanosecond or 186 miles per millisecond or 300,000 kilometers per second.

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21.1 grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.

The reactant that is consumed first in a chemical reaction is the limiting reagent or limiting reactant because it stops any more reactions from taking place. The limiting reagent controls how much product is produced during the reaction.

CaCO3(s) + 2HCl(aq) ==> CaCl2(aq) + H2O(l) + CO2(g)  

\(mols CaCO3 =\) \(27 *\frac{1 mol}{100g}\) = 0.27 mol

\(mols HCl = 15 gx \frac{1 mol}{36.5 g}\) = 0.38 mol

Limiting reactant = HCl ( it takes 2x the mols of HCl compared to mols CaCO3 as per balanced equation)

mass of CaCl2 = \(0.411 mols HCl x\frac{ 1 mol CaCl2}{ 2 mols HCl } x 111.0 g/mol\)

mass of CaCl2 = 21.1 g

Hence, 21.1 g of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.

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To produce 5.4 moles of \(Na_{2} O\) in the given reaction, 10.8 moles of NaCl are required.

The given chemical equation is a balanced equation, which means it represents the stoichiometric relationship between the reactants and products involved in the reaction.

The coefficients of the balanced equation represent the number of moles of each reactant and product involved in the reaction.

In this case, the equation is:

2 NaCl + MgO → \(Na_{2} O\) + \(MgCl_{2}\)

From the equation, we can see that 2 moles of NaCl are required to produce 1 mole of . Therefore, to produce 5.4 moles of \(Na_{2} O\), we need to use stoichiometry to determine the amount of NaCl required.

We can use the following formula to calculate the number of moles of NaCl required:

moles of NaCl = moles of \(Na_{2} O\) × (2 moles NaCl / 1 mole \(Na_{2} O\))

Substituting the given values, we get:

moles of NaCl = 5.4 moles \(Na_{2} O\) × (2 moles NaCl / 1 mole \(Na_{2} O\)) = 10.8 moles NaCl

Therefore, we need 10.8 moles of NaCl to produce 5.4 moles of \(Na_{2} O\) in the given reaction.

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The fact that the infrared thermometers used in medical research were first intended to detect the temperature on Mars has had an impact on that field of study.

Technology for use in outer space, in aviation or other operations outside of Earth's atmosphere, for things like spaceflight, space exploration, and Earth observation, is referred to as space technology.

By enabling high-speed data transport with the development of the internet, enabling research of global natural phenomena, and enabling environmental monitoring, space technology started to be employed for telecommunications and the environment.

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Answer: Various aspects have various ranges cause they have various numbers of protons, and various numbers and plans of electrons.

Explanation:

The Microscope part and their right descriptions are as follows

Iris Diaphragm: A. Increases or decreases the light intensity

Objective Lens System: B. After light passes through the specimen, it next enters this lens system

Stage: C. Platform that supports a microscope slide

Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward

Condenser: E. Concentrates light onto the specimen

Other parts of a microscope and their description that you should know about includes;

Eyepiece - The lens that you look through to see the image of the specimen.

Body tube - The tube that connects the eyepiece to the objective lenses.

Arm - The part of the microscope that supports the body tube and connects it to the base.

Base - The part of the microscope that supports the arm and provides stability.

Illuminator - The light source that provides light for the microscope.

Stage clips - The clips that hold the microscope slide in place on the stage.

Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.

The above answer is in response to the full question below;

Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.

1. Iris diaphram

2. Objective lens system

3. Stage

4. Adjustment knob

5. Condenser

Increases or decreases the light intensity

2. After light passes through the specimen, it next enters this lens system

3. Platform that supports a microscope slide

4. Causes stage (or objective lens) to move upward or downward

5. Concentrates light onto the specimen

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The partial pressures of nitrogen, oxygen, and neon in the mixture are approximately 366.13 torr, 312.55 torr, and 214.32 torr, respectively.

To find the partial pressures of the three gases, we can use Dalton's Law of Partial Pressures, which states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each gas.

Given:

Total pressure = 893 torr

Mole fractions: nitrogen (N2) = 0.41, oxygen (O2) = 0.35, neon (Ne) = 0.24

To calculate the partial pressures, we can multiply the total pressure by the mole fraction of each gas:

Partial pressure of nitrogen (P(N2)) = Mole fraction of nitrogen (X(N2)) * Total pressure

P(N2) = 0.41 * 893 torr

Partial pressure of oxygen (P(O2)) = Mole fraction of oxygen (X(O2)) * Total pressure

P(O2) = 0.35 * 893 torr

Partial pressure of neon (P(Ne)) = Mole fraction of neon (X(Ne)) * Total pressure

P(Ne) = 0.24 * 893 torr

Calculating the values:

P(N2) = 0.41 * 893 torr = 366.13 torr

P(O2) = 0.35 * 893 torr = 312.55 torr

P(Ne) = 0.24 * 893 torr = 214.32 torr

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This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Answer: 4.88 g/mol. and helium

Explanation:

To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:

P = pressure = 2.000 atm

V = volume = 50.00 L

n = number of moles

R = gas constant = 0.08206 L·atm/K·mol

T = temperature = 273.15 K

First, we need to find the number of moles of the gas:

PV = nRT

n = PV/RT

n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)

n = 1.844 mol

Now, we can find the molar mass of the gas by dividing its mass by the number of moles:

molar mass = mass/number of moles

mass = 9.00 g

molar mass = 9.00 g/1.844 mol

molar mass = 4.88 g/mol

Therefore, the molar mass of the gas is 4.88 g/mol.

To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.

The statement " Inertia and distance combine to keep Earth in orbit around the Sun and the Moon in orbit around Earth " is false.

According to Sir Isaac Newton, he proposed and concluded in his investigation that the earth is being kept in its orbit around the Sun and the Moon in orbit around Earth by means of gravity and inertia. This is not done through inertia and distance.

In conclusion, it can be deduced from the explanation given above that inertia and gravity combine to keep the earth in orbit around the Sun and the Moon in orbit around Earth.

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