How many milliliters of 3. 0m naoh are required to react with 4. 0ml of 16m hno3?.

Answers

Answer 1

12.0 milliliters of 3.0 M NaOH is required to react with 4.0 mL of 16.0 M HNO3.

The given reaction is HNO₃ + NaOH → NaNO₃ + H₂O. Here, we need to find the volume of NaOH required to react with HNO₃. We can use the formula of the molarity equation: Number of moles = Molarity × Volume. We need to find the number of moles of HNO₃ in 4 mL of 16 M HNO₃. Number of moles of HNO₃ = Molarity × Volume= 16 mol/L × 4 mL/1000 mL/L= 0.064 moles.

Now, we need to use the balanced chemical equation to find the number of moles of NaOH required to react with HNO₃. HNO₃ + NaOH → NaNO₃ + H2O. 1 mole of HNO₃ reacts with 1 mole of NaOH0.064 moles of HNO₃ reacts with x moles of NaOH x = 0.064 moles. So, the number of moles of NaOH required is 0.064 moles. Now, we can use the molarity equation to find the volume of NaOH required. Volume = Number of moles/Molarity= 0.064 moles/3.0 mol/L= 0.02133 L or 21.33 mL.

Therefore, the volume of 3.0 M NaOH required to react with 4.0 mL of 16.0 M HNO₃ is 12.0 mL.

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Related Questions

acid-catalyzed hydrolysis of diethyl acetamidobenzylmalonate delivers the desired (±)-phenylalanine hydrochloride product and the following byproduct(s)

Answers

The byprοducts in this reactiοn are acetic acid (οptiοn A) and ethanοl (οptiοn C).

What is acid-catalysed?  

In acid catalysis and base catalysis, a chemical reactiοn is catalyzed by an acid οr a base. By Brønsted–Lοwry acid–base theοry, the acid is the prοtοn (hydrοgen iοn, H+) dοnοr and the base is the prοtοn acceptοr. Typical reactiοns catalyzed by prοtοn transfer are esterificatiοns and aldοl reactiοns.

The acid-catalysed hydrοlysis οf diethyl acetamidοbenzylmalοnate can lead tο variοus by prοducts depending οn the reactiοn cοnditiοns and specific chemical pathways. Hοwever, withοut mοre detailed infοrmatiοn οr a specific reactiοn mechanism, it is difficult tο prοvide a cοmprehensive list οf the by prοducts that may fοrm.

Based οn the infοrmatiοn prοvided, the acid-catalysed hydrοlysis οf diethyl acetamidοbenzylmalοnate delivers the desired (+)-phenylalanine hydrοchlοride prοduct and the fοllοwing byprοduct(s):

E. Bοth A and C: Acetic acid and ethanοl.

The hydrοlysis οf diethyl acetamidοbenzylmalοnate invοlves the cleavage οf ester bοnds, resulting in the fοrmatiοn οf acetic acid as a byprοduct. Additiοnally, since diethyl acetamidοbenzylmalοnate is an ester, hydrοlysis οf the ester bοnds can alsο prοduce ethanοl as anοther byprοduct.

Therefοre, the byprοducts in this reactiοn are acetic acid (οptiοn A) and ethanοl (οptiοn C).

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Complete Question :

acid-catalyzed hydrolysis of diethyl acetamidobenzylmalonate delivers the desired ()-phenylalanine hydrochloride

An ecosystem is all the populations of organisms that live together and
A.
the food that they take in as energy.
B.
the organisms that generate energy from sunlight.
C.
the microorganisms that depend on them.
D.
the physical factors with which they interact.

Plllzzzzz help :(

Answers

Answer:

D i belive

Explanation:

15. How many neutrons are in the nucleus of an atom hat has an atomic mass of 36 and an atomic number of 18?​

Answers

the answer is 11 i believe

3. An atom
OF
elemente A has mass number 39 and 19 protons
Write the electron arrangement of the atom


Answers

Answer:

Explanation:

Potassium (K) atom has 19 electrons. The full electron configuration of Potassium (K) is 1s22s22p63s23p64s1

Principal energy level

Quantum number: n

1

2

3

4

5

6

Sublevels

availableQuantum number: l

1s

2s 2p

3s 3p 3d

4s 4p 4d 4f

5s 5p 5d 5f 5g

6s 6p 6d 6f 6g 6h

How can you distinguish A from B?
In this lab, you will
do experiments to identify types
of changes. Using the question format you learned
(shown above), write
you
an investigative question that
can answer by doing these experiments.

Answers

In order to distinguish A from B in a change in which A forms B, the chemical and physical properties of A and B are compared.

What are chemical and physical changes?

Chemical changes are changes that involve changes in the structure and arrangement of the atoms of the substances. In chemical changes, new substances are formed. Hence, chemical changes are not easily reversible changes.

Physical changes are changes that do not involve changes in the structure and arrangement of the atoms of the substances. In physical changes, no new substances are formed. Hence, physical changes are easily reversible changes.

In conclusion, chemical changes involve changes in the chemical properties of the substances undergoing the changes whereas physical changes involve changes in the physical properties of the substances.

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The overlapping of food chains results in a
the last ?
braided chain
food web
webbed chain
woven chain

Answers

The overlapping of food chains results in the last is food web

if the pco2 in the plasma increases, what effect will this have on plasma ph?

Answers

When the partial pressure of carbon dioxide (pCO2) in the plasma increases, this leads to a decrease in plasma pH, resulting in a more acidic environment. The relationship between pCO2 and pH is described by the Henderson-Hasselbalch equation, which helps predict the acid-base balance in the body.

An increase in pCO2 levels indicates that more CO2 is being produced or less is being eliminated. As CO2 dissolves in the plasma, it forms carbonic acid (H2CO3), which subsequently dissociates into hydrogen ions (H+) and bicarbonate ions (HCO3-). The increase in H+ ions is what causes the decrease in pH, signifying a more acidic environment.
This change in pH can disrupt the body's normal homeostasis and is commonly referred to as respiratory acidosis. The body's response to this imbalance involves various buffering systems, such as the bicarbonate buffer system, to help restore pH to a normal range.
In conclusion, an increase in plasma pCO2 levels leads to a decrease in plasma pH, creating a more acidic environment. This can disrupt the body's normal functioning and prompt compensatory mechanisms to restore the acid-base balance.

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1. Which is conduction?
A. energy transfer from a reaction system to its surroundings
B. energy transfer as electromagnetic waves
C. energy transfer by currents of moving liquid or gas
D. energy transfer by direct contact
2. What is a chemical reaction system?
A. the reactants and products in a reaction
B. a diagram used to show energy changes in a reaction
C. everything outside the reaction
D. a container in which chemical reactions take place
3. In photosynthesis within one plant, other plants would be considered the _____
A. products.
B. system.
C. reactants.
D. surroundings.
4. The products of a particular reaction have more energy than the reactants. Which type of reaction has occurred?
A. convection
B. exothermic
C. radiation
D. endothermic
5. Which type of reaction is occurring during a fireworks show? How do you know?
A. It is an endothermic reaction. Fireworks are bright, indicating a release of light energy.
B. It is an exothermic reaction. Fireworks are bright, indicating a release of light energy.
C. It is an exothermic reaction. Heat must be added to light the fuses of the fireworks.
D. It is an endothermic reaction. Heat must be added to light the fuses of the fireworks.
PLZ HELP

Answers

Answer:

1. D

2. A

3. This question doesn't make sense

4. D

5. B or C

Explanation:

Answer: Which is conduction?


energy transfer by direct contact

What is a chemical reaction system?


the reactants and products in a reactionIn photosynthesis within one plant, other plants would be considered the ___


surrounding


The products of a particular reaction have more energy than the reactants. Which type of reaction has occurred?

endothermic


Which type of reaction is occurring during a fireworks show? How do you know?


It is an exothermic reaction. Fireworks are bright, indicating a release of light energy.

Explanation: just did the quick check got 100%

3-methyl-1-butanol (also called isoamyl alcohol or isopentyl alcohol) was mixed with an excess of acetic acid (ethanoic acid is its systematic name) and a trace of sulfuric acid (which serves as a catalyst). This reaction is an equilibrium reaction, so it is expected that not all the starting materials will be consumed. The equilibrium should lie quite far to the right due to the excess of acetic acid used, but not completely.
After an appropriate length of time, isolation of the desired product from the reaction mixture was begun by adding a volume of 5% aqueous sodium bicarbonate (NaHCO3 has an effective pKa of 7) roughly equal to the volume of the reaction mixture. Bubbling occurred and a mixture consisting of two layers resulted—a basic aqueous layer and an organic layer.
The layers were separated, and the aqueous layer was removed.
The addition of aqueous sodium bicarbonate to the layer of organic materials and separation of the layers was repeated twice. Each time the predominantly aqueous layers were removed, they were combined in the same collection flask.
The organic layer that remained after the three bicarbonate extractions were dried and then subjected to distillation to obtain a pure sample of 3-methylbutyl ethanoate (isoamyl acetate).
List all the chemical species likely to be present at the end of the reaction but before adding aqueous NaHCO3. Note that the H2SO4 was not consumed (since it is a catalyst).

Answers

At the end of the reaction before adding aqueous \(NaHCO_3\), the following chemical species are likely to be present:

3-methyl-1-butanol (isoamyl alcohol or isopentyl alcohol).Acetic acid (ethanoic acid).3-methylbutyl ethanoate (isoamyl acetate).Water.Sulfuric acid (catalyst).

A Lewis structure, also known as a Lewis dot diagram, is a way to represent the chemical bonding in a molecule. It uses dots (also called electron dots or Lewis dots) to show the valence electrons on an atom, and lines to show the bonds between atoms. The goal of drawing a Lewis structure is to use the valence electrons of the atoms in a molecule to form the most stable arrangement of atoms, that is to say, to achieve the octet rule where each atom has 8 valence electrons in its outermost shell.

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How is velocity defined?
O speed
O speed in a particular direction
O direction
O changing direction

Answers

Answer:

B Speed in a particular direction

You made a 0.03000 M solution of H2SO4. What volume (mL) of 0.02500 M NaOH is required to titrate a 25.00 mL sample to the phenolphthalein endpoint

Answers

Amount of 0.02500 M NaOH required to titrate a 25.00 mL sample to the phenolphthalein endpoint is 60 mL.

Given :

Concentration of H2SO4 = 0.03000 M

Concentration of NaOH = 0.02500 M

Volume of H2SO4 = 25.00 mL

To find : Volume of NaOH required to titrate H2SO4

Step 1: Write a balanced chemical equation of the reaction

NaOH + H2SO4 → Na2SO4 + 2H2O

Step 2: Write the equation for the reaction taking place in the titration

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 3: Calculate the moles of H2SO4

Moles of H2SO4 = Molarity x Volume in Liters

Moles of H2SO4 = 0.03000 M x 25.00 mL / 1000 mL/L

Moles of H2SO4 = 0.0007500 mol

Step 4: Calculate the volume of NaOH required to react with H2SO4

The balanced equation shows that 1 mole of H2SO4 reacts with 2 moles of NaOH. Since the volume of NaOH is to be found in milliliters, convert the number of moles of H2SO4 into moles of NaOH.

Number of moles of NaOH = 2 x Moles of H2SO4

Number of moles of NaOH = 2 x 0.0007500 mol

Number of moles of NaOH = 0.001500 mol

Now, find the volume of NaOH from the moles and concentration of NaOH.

Volume of NaOH = Moles of NaOH / Molarity of NaOH in L

Molarity of NaOH = 0.02500 M

Volume of NaOH = 0.001500 mol / 0.02500 M

Volume of NaOH = 60 mL

Therefore, 60 mL of 0.02500 M NaOH is required to titrate a 25.00 mL sample of 0.03000 M H2SO4 to the phenolphthalein endpoint.

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Which factor will INCREASE the rate of solvation of a solid in a liquid?

A. decreasing the surface area of the solute

B. decreasing the temperature

C. allowing the mixture to sit undisturbed

D. increasing the temperature

(It’s D)

Answers

Answer:

the answer is D =decreasing the temperature ️️️

The isolation of p-aminobenzoic acid is the trickiest step due to the formation of an amino compound. Why don't we do the esterification step prior to the deprotection step?

Answers

Doing the esterification step prior to the deprotection step in the isolation of p-aminobenzoic acid is not preferred because it would result in the formation of an ester instead of the desired amino compound.

In the process of isolating p-aminobenzoic acid, the deprotection step is crucial for converting the protected form of the compound into its free form. The protected form usually involves temporarily blocking or protecting certain functional groups to prevent unwanted reactions during synthesis.

If the esterification step is performed before deprotection, it would result in the formation of an ester compound rather than the desired amino compound. Esterification involves the reaction between an alcohol and an acid, resulting in the formation of an ester and water. This reaction would occur between the protected p-aminobenzoic acid, which contains a carboxylic acid group, and the alcohol used for esterification.

To obtain p-aminobenzoic acid, it is necessary to remove the protecting group before performing any reactions that involve the carboxylic acid group. This is typically achieved through a deprotection step, which selectively removes the protecting group while leaving the desired functional groups intact.

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What functional group does the molecule below have?

*two leg spider looking molecule*

What functional group does the molecule below have?*two leg spider looking molecule*

Answers

Answer:

ether

Explanation:

Ether, any of a class of organic compounds characterized by an oxygen atom bonded to two alkyl or aryl groups. I attached an image as well.

What functional group does the molecule below have?*two leg spider looking molecule*

Answer:

D. Ether

Explanation:

Ethers look like R---O---R. Thus, this molecule has the ether functional group. :)

The speed limit on a certain highway is 72 km/h. what is the speed in cm/s?

Answers

Answer:

7.2e+6 cm (7200000cm)

Explanation:

Hope this is the answer your looking for ;)

How would the concentration of silver ions compare in a 1.0 x 10-16 L saturated solution to a 1.5 x 10-16 L saturated solution?

Answers

The second one is more concentrated as they both times with the same thing but the second one (1.5) is bigger

what is a mixture of elements and compounds

what is a mixture of elements and compounds

Answers

The substance in the image above would be classified as a mixture of elements (option E).

What is a compound and mixture?

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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when iron-rich materials cool below their __________ temperature, they may preserve the orientation of the magnetic field

Answers

When iron-rich materials cool below their Curie temperature, they may preserve the orientation of the magnetic field.

The Curie temperature is the temperature at which a ferromagnetic material loses its magnetic properties. When a ferromagnetic material is heated to its Curie temperature, the thermal energy causes the magnetic moments of the atoms in the material to become disordered, which causes the material to lose its magnetic field. When the material cools below its Curie temperature, the magnetic moments of the atoms become ordered again, but the orientation of the magnetic field may not be preserved. However, in iron-rich materials, if the cooling process is slow enough, the orientation of the magnetic field can be preserved, creating a record of the Earth's magnetic field at the time the material cooled. This property has been used to study the Earth's magnetic field history by analyzing the magnetic properties of rocks and sediments.

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Conclusions

1. Compare the densities of the pre-1982 and post-1982 pennies. Using

the table to the right, state which metal is most likely used in the core

of post-1982 pennies. Explain your choice.

Metal

magnesium

aluminum

zinc

copper

silver

lead

Density

(g/cm³)

1. 74

2. 70

7. 00

8. 92

10. 50

11. 35

Answers

The pre-1982 pennies are made of an alloy of 95% copper and 5% zinc, while the post-1982 pennies have a copper-plated zinc core and are 97.5% zinc and 2.5% copper.

The densities of these metals differ, with copper being denser than zinc. The density of the pre-1982 penny is 8.94 g/cm³, while the post-1982 penny has a density of 6.87 g/cm³. This means that the metal used in the core of post-1982 pennies is most likely zinc, as its density matches that of the penny. Copper is too dense to be used in the core without significantly increasing the weight and cost of the coin. Zinc is a more cost-effective choice, and the copper plating on the outside of the penny gives it the appearance and conductivity of copper.

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Calculate the number of moles of oxygen in the copper oxide. the molar mass of oxygen is 16.00 g/mol.

Answers

To calculate the number of moles of oxygen in copper oxide, we need to know the molar mass of oxygen and the amount of copper oxide present.

Given that the molar mass of oxygen is 16.00 g/mol, we can use this information to determine the number of moles of oxygen.

First, we need to determine the molar mass of copper oxide. Copper oxide consists of one copper atom (Cu) and one oxygen atom (O). The atomic mass of copper is 63.55 g/mol.

The molar mass of copper oxide can be calculated as follows:

Molar mass of copper oxide = (atomic mass of copper) + (atomic mass of oxygen)
                         = 63.55 g/mol + 16.00 g/mol
                         = 79.55 g/mol

Next, we need to know the amount of copper oxide present. Let's assume we have 100 grams of copper oxide.

To calculate the number of moles of oxygen, we can use the formula:

Number of moles = Mass of substance / Molar mass

Mass of oxygen = Mass of copper oxide - Mass of copper
             = 100 g - (63.55 g/mol * 1 mol)
             = 36.45 g

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen
                        = 36.45 g / 16.00 g/mol
                        ≈ 2.28 mol

The number of moles of oxygen in 100 grams of copper oxide is approximately 2.28 moles.

To calculate the number of moles of oxygen in copper oxide, we need to know the molar mass of oxygen and the mass of copper oxide. By using the formula for moles and the given information, we can determine that there are approximately 2.28 moles of oxygen in 100 grams of copper oxide.

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There are 0.125 moles of oxygen in 10 grams of copper oxide.

To calculate the number of moles of oxygen in the copper oxide, we need to know the mass of copper oxide and its chemical formula. Assuming the formula of copper oxide is CuO, we can use the molar mass of oxygen (16.00 g/mol) to calculate the number of moles.

1. Determine the mass of copper oxide.
2. Calculate the molar mass of copper oxide using the atomic masses of copper and oxygen.
3. Divide the mass of copper oxide by its molar mass to obtain the number of moles.

Let's say we have 10 grams of copper oxide.
1. The mass of copper oxide is 10 grams.
2. The molar mass of copper oxide (CuO) is the sum of the atomic masses of copper (Cu) and oxygen (O). The atomic mass of copper is 63.55 g/mol, and the atomic mass of oxygen is 16.00 g/mol. So the molar mass of copper oxide is 63.55 g/mol + 16.00 g/mol = 79.55 g/mol.
3. Divide the mass of copper oxide (10 grams) by its molar mass (79.55 g/mol) to get the number of moles of copper oxide.

So, the number of moles of copper oxide is 10 grams / 79.55 g/mol = 0.125 moles.

Therefore, there are 0.125 moles of oxygen in 10 grams of copper oxide.

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I come in many different colors and I get bigger when I’m full. I will float away if you don’t tie me down and I will make a loud sound if I break. What am I?

i'm b.o.r.e.d

Answers

Answer:

Balloon

Explanation:

It comes in different colors, it expands when it's "full". It floats away if it is not tied down and will make a loud noise if it pops (breaks).

How did Wegener work out what Pangea looked like?

Answers

Answer:

ok so basicalkly he lloked at how the subdiction zone formed and where previus conintal drift occured

Explanation:

Question 11
Which formula represents a hydrocarbon?


C₂H6
C₂H5OH
C₂H5Cl
C₂H6O

Answers

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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difference between fluids and nonfluids

Answers

Answer:

All liquids are fluids but not all fluids are liquids. Fluids basically describe anything that can flow as a result of a difference in pressure between two points. Liquids on the other hand are a subset of fluids. Liquids are the incompressible fluids. These are the fluids who's density does not change sharply with pressure.

Gases are also fluids, they form the compressible fluids. They do flow as a result of difference in pressure between two points but at the same time they can be compressed or expanded. Their density fluctuates with pressure.

Hence fluids consist of 2 mutually exclusive groups of compressible and incompressible fluids. Liquids are the incompressible fluids and hence form a subset of the more general term fluid.

when gathering glassware and equipment for an experiment, you should

Answers

When gathering glassware and equipment for an experiment, you should

Read all directions carefully to know what equipment is necessary.Examine all glassware to check for chips or cracks. Clean any glassware that looks dirty.

To avoid accidents and injuries, follow all lab safety standards when using and handling glassware. Before use, every glassware should be examined for fractures and contaminants. Items that are cracked should be discarded, and tainted glassware should be cleaned. Before doing any experiment, you should assess the dangers associated with the job, including what the worst possible outcomes are, how to deal with them, and what sensible procedures, protective facilities, and equipment are required to reduce the chance of exposure to the hazards.

A beaker should never be carried by its side. Carrying glassware should always be done with two hands (position one hand under the glass for support). An appropriate glove should be worn when there is a risk of breakage (e.g., inserting a glass rod), chemical contamination, or a temperature hazard.

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PLEASE HELP! explain how magma produces different types of volcanoes.

Answers

The form of the volcano is determined by the rate and severity of eruptions, as well as the composition of the magma. Some volcanic eruptions are explosive, while others flow slowly. Eruptions might occur through a primary opening at the volcano's summit or through vents that arise on the volcano's slopes.

Magma is shaped via way of means of the partial melting of mantle rocks. As the rocks travel upward (or have water added to them), they begin to melt slightly. These little blobs of melt migrate upward and merge into bigger volumes that continue to travel higher.

They might congregate in a magma chamber or come straight up. Gas molecules in the magma come out of the solution and form bubbles as they rise, and the bubbles expand as they ascend. When the pressure from these bubbles becomes greater than the pressure from the surrounding solid rock, the surrounding rock cracks, enabling the magma to reach the surface.

Volcanoes may be located on both land and the ocean floor. When volcanoes erupt on the ocean floor, the expelled lava cools and solidifies, forming underwater mountains and mountain ranges. When volcanoes on the ocean floor grow large enough to rise above the water's surface, they form islands.

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In the Millikan oil droplet experiment, the oil is sprayed from an atomizer into a chamber. The droplets are allowed to pass through the hole into the chamber so that their fall can be observed. The top and bottom of the chamber consist of electrically charged plates. The upper plate is positively charged, and the lower plate is negatively charged. X rays are introduced into the chamber so that when they strike the oil droplets, the droplets will acquire one or more negative charges. The electric field (voltage) is applied to the metal plates.
Watch the animation and identify the effects of an electric field on the motion of a negatively charged oil droplet. Consider the gravitational force as Fg and the electric force as Fe. All the other forces acting on the oil droplet can be ignored as their effect on the motion of the oil droplet is negligible.
A/ In the absence of an electric field, the oil droplet falls freely due to the gravitational force.
B/ If Fe is increased until it is equal to Fg, the negatively charged oil droplet will remain stationary.
C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.
D/ In the presence of an electric field, the negatively charged oil droplet moves freely toward the negatively charged plate.
** I chose B, but that was the wrong answer

Answers

C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.

In the Millikan oil droplet experiment, the negatively charged oil droplets are subjected to an electric field created by the charged plates. The electric force (Fe) acts on the oil droplet in a direction opposite to the gravitational force (Fg). When Fe is greater than Fg, the electric force overcomes the gravitational force, causing the negatively charged oil droplet to experience an upward force. As a result, the oil droplet moves freely upward toward the negatively charged plate.

Option B is incorrect because if Fe is equal to Fg, the forces balance each other, resulting in a stationary droplet. However, the question states that Fe is increased until it is greater than Fg, implying that the droplet is no longer stationary but moves in response to the electric force.

Therefore, option C is the correct answer, as it describes the effect of an electric field on the motion of a negatively charged oil droplet in the Millikan oil droplet experiment.

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A reaction that had two compounds as reactants and two compounds as products is most likely a

Answers

double-replacement reaction

if the bod of a municipal wastewater at the end of 7 days is 60.0 ml/l and the ultimate bod is 85.0 mg/l, what is the rate constant? assume the temperature is 20c

Answers

The rate constant is approximately -0.585 day^-1 at a temperature of 20°C.

To calculate the rate constant, we can use the following formula:

k = (ln(BOD1/BOD2)) / (t2 - t1)

where BOD1 is the initial BOD (which is assumed to be 0), BOD2 is the final BOD after 7 days (60.0 ml/l), t1 is the time at the start of the test (also assumed to be 0), t2 is the time at the end of the test (7 days), and ln represents the natural logarithm.

First, we need to convert the ultimate BOD from mg/l to ml/l by dividing by the density of water (1 g/ml).

Ultimate BOD = 85.0 mg/l / 1000 mg/g / 1 g/ml = 0.085 ml/l

Now we can plug in the values and solve for k:

k = (ln(0/60.0)) / (7 - 0) = (-4.094) / 7

k = -0.585 day^-1

So the rate constant is approximately -0.585 day^-1 at a temperature of 20°C.

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Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen react with 70. 0 g of nitrogen, hydrogen is considered the limiting reactant because 7. 5 mol of hydrogen would be needed to consume the available nitrogen. 7. 5 mol of nitrogen would be needed to consume the available hydrogen. Hydrogen would produce 7. 5 mol more ammonia than nitrogen. Nitrogen would produce 7. 5 mol more ammonia than hydrogen.

Answers

In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

The reaction is the following:

3H₂(g) + N₂(g) → 2NH₃(g)   (1)

To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

\( n = \frac{m}{M} \)

Where:    

m: is the mass

M: is the molar mass

For hydrogen we have:

\( n_{H_{2}} = \frac{m}{M} = \frac{7.00 g}{2.016 g/mol} = 3.47 \:moles \)

And for nitrogen:

\( n_{N_{2}} = \frac{m}{M} = \frac{70.0 g}{28.013 g/mol} = 2.50 \:moles \)

We can see in reaction (1) that 3 moles of hydrogen react with 1 mol of nitrogen, so the number of hydrogen moles needed to react nitrogen is:

\( n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles \)

Since we have 3.47 moles of hydrogen and we need 7.50 moles to react with all the mass of nitrogen, the limiting reactant is hydrogen.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that 3 moles of hydrogen produces 2 moles of ammonia, so:

\( n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles \)

Hence, hydrogen would produce 2.31 moles of ammonia.

Therefore, hydrogen is the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

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Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen
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