How many milliliters of 12.0 M hydrochloric acid contain 3.646 g of HCl (36.46 g/mol)?
Group of answer choices

Density is calculated using the following equation:

where m is the mass and v is the volume.

p = 299.8 g/74.2mL

p = 4.040431267 g/mL

The number of significant figures in this amount of density is 10 if you do not round off.

.

When molecules collide, there is generally a delay before an explosion occurs, if an explosion occurs at all. This is because an explosion requires a chemical reaction to take place, which involves the breaking of chemical bonds and the formation of new bonds. These reactions require a certain amount of energy, which is called the activation energy.

The collision of molecules can provide energy to the system, but it is not always enough to overcome the activation energy needed for a chemical reaction to occur. If the energy of the collision is less than the activation energy, no reaction will occur and there will be no explosion. If the energy of the collision is equal to or greater than the activation energy, a chemical reaction may occur and an explosion may result.

The time delay between the collision of molecules and an explosion occurring depends on the nature of the molecules and the conditions under which the collision occurs. Some chemical reactions are very fast and can occur almost instantly, while others may take longer to reach the activation energy and proceed to completion.

It's worth noting that not all collisions between molecules result in an explosion. In many cases, the collision may simply transfer energy from one molecule to another without leading to a chemical reaction.

The net ionic equation for this gas evolution reaction is H+(aq) + SO32-(aq) SO2(g) + H2O, while the balanced molecular equation is 2HBr(aq) + K2SO3(aq) SO2(g) + 2H2O(l) + 2KBr(aq) (l).

The reaction's chemical formula is K2CO3(aq)+2HBr(aq)2KBr(aq)+CO2(g)+H2O. (l) Strong electrolytes in the process, K2CO3, HBr, and KBr totally dissociate in water to generate their corresponding ions.

A salt (the KBr) and water will be created when the HBr and KOH interact. While balancing this equation, make careful to count both hydrogen atoms on the reactants side.

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Long-range order is best found in crystalline solids. Crystalline solids are characterized by a highly ordered arrangement of atoms or molecules in a repeating pattern called a crystal lattice. Option 2)

Long-range order is best found in crystalline solids. Crystalline solids are characterized by a highly ordered arrangement of atoms or molecules in a repeating pattern called a crystal lattice. The arrangement of the particles in a crystalline solid extends over long distances, resulting in a well-defined and repetitive structure.

In contrast, amorphous solids lack long-range order. They do not possess a well-defined crystal lattice or a regular arrangement of particles. The atoms or molecules in amorphous solids are arranged in a more random and disordered manner, leading to a lack of long-range order.

Thermal plasmas and nonthermal plasmas, on the other hand, are states of matter where the atoms or molecules are highly ionized, resulting in the formation of charged particles or ions. While plasmas can exhibit certain levels of order, they do not possess the same level of long-range order as crystalline solids.

Therefore, crystalline solids are the primary location where long-range order is typically found. Option 2)

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Note Complete Question

Which of the following best identifies where long-range order would be found?

1) in amorphous solids

2) in crystalline solids

3) in thermal plasmas

4) in nonthermal plasmas

OPTION B. Long-range order is most commonly found in crystalline solids, where atoms or molecules are arranged in a well-defined, consistent pattern. Amorphous solids and plasmas do not showcase this characteristic.

Long-range order pertains to the organization and regularity of constituents over large scale distances. It's a term often associated with the structure of crystalline solids. This is due to the fact that their atoms or molecules are arranged in a well-defined and repeated pattern extending in all three spatial dimensions over the length of the solid. On the contrary, an amorphous solid does not have a long-range order, instead, its structure is only ordered on a short range. Plasmas, both thermal or nonthermal, are an ionized gas and do not exhibit long-range order, primarily due to their high level of kinetic energy and lack of fixed positions for particles.

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Correct option is c) One atom is now positively charged, and the other is negatively charged. This is due to nature of ionic bond.

An ionic bond is formed when one or more electrons are transferred from one atom to another, resulting in the formation of two oppositely charged ions. In an ionic bond, the electron(s) transferred from one atom are accepted by the other atom, leading to the formation of cations and anions.

The atom that loses an electron becomes a positively charged ion (cation), and the atom that gains an electron becomes a negatively charged ion (anion). The opposite charges of the ions attract each other and form an ionic bond between the two atoms.

Ionic bonds usually occur between atoms of different elements with a significant difference in electronegativity. Ionic compounds generally have high melting and boiling points, are solid at room temperature, and are usually soluble in water.

In contrast to an ionic bond, a covalent bond is formed when atoms share electrons, as in the case of molecular compounds. In a covalent bond, atoms do not become charged. Instead, they share electrons in a way that allows them to complete their valence shells.

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Answer:

A:Itasca

A:ItascaB:Hubbard

A:ItascaB:HubbardC:Douglas

A:ItascaB:HubbardC:DouglasD:Grand Marais

E:Two harbors

F:Duluth

Answer:

Duluth, Twin Harbors and Grand Marais because they are on the coast of the lake.

Explanation:

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

Ultraviolet

Explanation:

It doesn't use much energy and so it creates ultraviolet light.

Answer:

yea they look good. From what I can tell everything is correct.

Explanation:

1) List the known and unknown quantities.

Sample: gas.

Volume: 500 mL.

Pressure: 740 mmHg

Temperature: 25 ºC.

Vapor pressure at 25 ºC: 24 mmHg.

2) Pressure of the gas.

The pressure of the gas is 716 mmHg

3) Moles of gas

3.1- List the known quantities.

Volume: 500 mL.

Temperature: 25 ºC.

Pressure: 716 mmHg.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

3.2- Set the equation.

3.3- Convert the units of the volume, the temperature, and the pressure.

Volume.

1 L = 1000 mL

Temperature.

Pressure

1 atm = 760 mmHg

3.4- Plug in the know quantities in the ideal gas equation.

3.5- Solve for n (moles).

Divide both sides by (0.082057 L * atm * K^(-1) * mol^(-1)) * (298.15 K)

4) Dry volume at STP

STP conditions are

Temperature: 273 K

Pressure: 1 atm.

At STP conditions 1 mol of a gas occuppies 22.4 L. We can use this as a conversion factor.

1 mol gas = 22.4 L

The volume of the dry gas at STP is 0.432 L.

.

Answer:

1) List the known and unknown quantities.

Sample: gas.

Volume: 500 mL.

Pressure: 740 mmHg

Temperature: 25 ºC.

Vapor pressure at 25 ºC: 24 mmHg.

2) Pressure of the gas.

The pressure of the gas is 716 mmHg

3) Moles of gas

3.1- List the known quantities.

Volume: 500 mL.

Temperature: 25 ºC.

Pressure: 716 mmHg.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

3.2- Set the equation.

3.3- Convert the units of the volume, the temperature, and the pressure.

Volume.

1 L = 1000 mL

Temperature.

Pressure

1 atm = 760 mmHg

3.4- Plug in the know quantities in the ideal gas equation.

3.5- Solve for n (moles).

Divide both sides by (0.082057 L * atm * K^(-1) * mol^(-1)) * (298.15 K)

4) Dry volume at STP

STP conditions are

Temperature: 273 K

Pressure: 1 atm.

At STP conditions 1 mol of a gas occuppies 22.4 L. We can use this as a conversion factor.

1 mol gas = 22.4 L

The volume of the dry gas at STP is 0.432 L.

Explanation:

Answer:

1.237g/L = density at 14°C

1.167g/L = density at 31°C

Explanation:

Density is the ratio between mass and volume of a determined substance

From ideal gas law:

PV = nRT:

Where P is pressure, V volume, n moles, R constant gas law, and T absolute temperature

P/RT = n/V

You can obtain moles / L. now:

moles / L × (molar mass of the gas (g/mol)

g/L

You can obtain the density of the gas in g/L

763torr are:

763torr × (1atm / 760torr) = 1.004 atm

14°C and 31.0°C in absolute temperature are:

14°C + 273.15 = 287.15K

31°C + 273.15 = 304.15K

Replacing, density at 14°C:

1.004atm / (0.082atmL/molK×287.15K) × 29g/mol = density

1.237g/L = density at 14°C

And at 31.0°C:

1.004atm / (0.082atmL/molK×304.15K) × 29g/mol = density

1.167g/L = density at 31°C

Answer:

Cu2 + 2Mg-> 2Cu+ Mg2

Explanation:

Balance the equation and make sure both the reactant and the products are the same

Hope it will be helpful

\(Cu^{+2} + 2Mg\)  -> \(2Cu + Mg^+2\)  is the correct half-reactions.

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total oxidation numbers is the same for both the reactants and the products.

\(Cu^{+2} + 2Mg\)  -> \(2Cu + Mg^+2\) is the correct half-reactions.

Magnesium is oxidized because its oxidation state increased from 0 to +2 while Cu is reduced because its oxidation state decreased from +2 to 0.

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The amount of the heat needed to boil the 49.6 g of hexane (C₆H₁₄), the beginning from the temperature of 43.4 °C is 19.49 kJ.

The Molar mass of hexane, C₆H₁₄ = 86.18 g/mol.

The boiling point of the hexane = 341.85 K

The Specific heat of hexane = 2.26 kJ/kg K

The Enthalpy of vaporization = 28.85 kJ/mol

The Mass of hexane = 49.6 g = 0.0496 kg

The moles of hexane = mass / molar mass

                                    = 49.6 / 86.18

                                     = 0.577 mol

The amount of heat is as :

q1 = m c ΔT

q1 = 0.0496 × 2.26 ( 341.85 - 316.4 )

q1 = 2.85 kJ

q2 = n ΔH

ΔH = heat of vaporization.

q2 = 0.577 ×  28.85

q2 = 16.64 kJ

The total amount of the heat is needed is as :

q = q1 + q2

q = 2.85 kJ + 16.64 kJ

q = 19.49 kJ

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Explanation:  C) the air temp. at the top is lower

Answer:

Tea also contains two substances related to caffeine: theobromine and theophylline

Answer:

an aqueous solution of HNO3

✔ pH = 2.5

an aqueous solution of NaCl

✔ pH = 7

an aqueous solution of NaOH

✔ pH = 13

Explanation:

The answer is that the  pH will be <7 , =7 , >7 for the respective solutions.

pH is an expression of hydrogen ion concentration in water.

pH is the negative logarithm of hydrogen ion (H+) concentration (mol/L) in an aqueous solution:

pH = -log₁₀(H+)

The term is used to indicate basicity or acidity of a solution on a scale of 0 to 14, with pH 7 being neutral.

As the concentration of H⁺ ions in solution increases, acidity increases and pH gets lower, below 7

When pH is above 7, the solution is basic.

For the above solutions mentioned

1. An aqueous solution of HNO3

This will be an acidic solution so

pH < 7

2. An aqueous solution of NaCl

As NaCl is a salt therefore , it will be a neutral solution

pH=7

3. An aqueous solution of NaOH

This will be an alkaline solution

pH>7

Therefore the  pH will be <7 , =7 , >7 for the respective solutions.

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Answer:

will you help us with that one please

The masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

A buffer solution is defined as an acid or a base aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa whose pH changes very little when a small amount of a strong acid or base is added to it.

For above given information, the dimethylamine (CH₃)₂NH and dimethylammonium chloride (CH₃)₂NH * HCl are mixed to prepare a buffer solution

The concentration of the components is given as 0.5M , Volume = 5L

No. of moles = CV = 0.5 * 5 =2.5 moles

2.5 moles of dimethylamine = mass/ Molecular weight

Molecular weight of dimethylamine = 45 gm

Therefore the mass of dimethylamine required = 45 * 2.5 = 112.5gm

4 moles of dimethylammonium chloride = 362 gm

Therefore the mass of dimethylammonium chloride required = 362*2.5 = 905 gm

Thus, the masses of dimethylamine and dimethylammonium chloride we need to prepare 8. 00 l of pH = 12. 00 buffer is 905 gm.

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Answer:

Explanation:

How to add a great answer

ADD YOUR ANSWER

Question

Consider a 180. g sample of water. The specific heat of water is 1.00 cal(g · °C) or 4.18 J/(g: °0).

(a) How much energy, in calories, is released as the water is cooled from 55.0°C to 12.0°C? (Enter your

answer in scientific notation.)

Taking into account the Charles's law, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

Charles's law shows the relationship between the volume and temperature of a gas sample at constant pressure.

This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

\(\frac{V}{T}= k\)

Considering an initial state 1 and an initial state 2:

\(\frac{V1}{T1}= \frac{V2}{T2}\)

In  this case, you know:

Replacing in Charles's Law:

\(\frac{0.0141 m^{3} }{284.5 K}=\frac{V2}{368 K}\)

Solving:

\(\frac{0.0141 m^{3} }{284.5 K}x368 K=V2\)

0.0182 m³= V2

Finally, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

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Answer:

A bed

Explanation:

Four legs up, four legs down, soft in the middle, and hard all round.

Explanation:

The number of moles of a substance is represented by the following formula:

n=NNA

where, n

is the number of moles of the substance, N

is the total number of molecules present in a substance, andNA

is the Avogadro constant.

The given compound is N2O5

So one mole of N2O5

contains 6.023×1023

numbers of molecules. Thus the 0.400

moles of N2O5

contains a number of molecules => 0.400moles×6.023×10^23

.

=> 2.41×10^23 molecules.

there are 2.41 thats the anwser

An example of heterogeneous equilibrium is:

Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.

Considering the given equations:

The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.

This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.

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Answer:

e. 1.4.

Explanation:

Hello,

In this case, for a second-order reaction, the integrated rate law is:

\(\frac{1}{[A]} =kt+\frac{1}{[A]_0}\)

In such a way, for the given data, we compute the initial concentration as shown below in molar units (M):

\(\frac{1}{[A]_0} =\frac{1}{[A]}-kt=\frac{1}{0.65M} -\frac{0.025}{M*s}*33s \\\\\frac{1}{[A]_0} =\frac{0.713}{M}\)

\([A]_0=\frac{1M}{0.713} =1.4M\)

Therefore, answer is e. 1.4 M.

Regards.

The initial concentration of the reaction is 1.4 M.

Using the formula;

1/[A] = kt + 1/[A]o

Where;

[A] = concentration at time t =  0.65 M

t = time = 33 s

k = rate constant = 0.025 M-1s-1

[A]o = initial concentration = 0.025 M-1s-1

Hence;

1/ 0.65 = (0.025 × 33) +  1/[A]o

1/[A]o = (0.65)^-1 -  (0.025 × 33)

1/[A]o = 1.54 - 0.83

[A]o = 1.4 M

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Answer:

B

Explanation:

Do diện tích tiếp xúc ở dạng bột cao hơn dạng tinh thể

The shorthand or noble gas electron configuration for tellurium (Te) is [Kr]5s²4d¹⁰5p⁴.

The electron configuration of Te describes the arrangement of its electrons in different energy levels and orbitals. The electron configuration notation is a shorthand method for writing the distribution of electrons among different shells and subshells.

Te has an atomic number of 52, meaning that it has 52 electrons distributed among its different shells and subshells. The first two electrons of Te occupy the 1s subshell, the next two electrons occupy the 2s subshell, and the next six electrons occupy the 2p subshell.

The following ten electrons occupy the 3d subshell, and the next two electrons occupy the 4s subshell. After that, ten electrons occupy the 4d subshell. The remaining six electrons are found in the 5p subshell.

The noble gas electron configuration for Te is [Kr]. This means that Te's outermost shell is similar in electron configuration to that of Kr, which is a noble gas. The noble gas electron configuration for Te indicates that its outermost shell contains six valence electrons (5s²5p⁴), which can participate in chemical reactions.

The full configuration including the noble gas indicates that the outermost electrons for Te are in the p subshell, which is useful for predicting reactivity.

In summary, the noble gas electron configuration for tellurium is [Kr]5s²4d¹⁰5p⁴. This notation helps to describe the electron arrangement of Te in a concise manner and indicates that the outermost shell of Te is similar to that of Kr, which is a noble gas.

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Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Holonium and Gadolinium has the highest number of neutrons in the nucleus.

Looking at the atoms listed;

Then,

Number of neutrons = Mass number - number of protons

157 - 66 = 91 neutrons

162 - 67 = 95 neutrons

149 - 60 = 89 neutrons

148 - 63 = 85 neutrons

159 - 64 = 95 neutrons

Hence, Holonium and Gadolinium has the highest number of neutrons in the nucleus.

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The volume of hydrogen gas produced in the reaction of 73 grams of zinc and 73 grams of hydrochloric acid (under normal conditions) is approximately 22.4 liters.

To calculate the volume of hydrogen gas produced in the reaction of zinc and hydrochloric acid, we need to use the principles of stoichiometry and the ideal gas law.

First, let's write the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):

Zn + 2HCl →\(ZnCl_2\)+ H2

From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. To determine the number of moles of zinc and hydrochloric acid, we need to convert the given masses into moles.

The molar mass of zinc (Zn) is approximately 65.38 g/mol, so 73 grams of zinc is equal to:

73 g Zn * (1 mol Zn / 65.38 g Zn) ≈ 1.116 mol Zn

Similarly, the molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol, so 73 grams of HCl is equal to:

73 g HCl * (1 mol HCl / 36.46 g HCl) ≈ 2.002 mol HCl

According to the balanced equation, the reaction produces one mole of hydrogen gas for every two moles of hydrochloric acid. Therefore, since we have 2.002 moles of HCl, we expect to produce half that amount, or approximately 1.001 moles of hydrogen gas.

To calculate the volume of hydrogen gas, we can use the ideal gas law, which states:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. In this case, we assume the reaction is conducted under normal conditions, which means a pressure of 1 atmosphere and a temperature of 273.15 Kelvin.

Rearranging the equation to solve for V, we have:

V = nRT / P

Substituting the values, we get:

V = (1.001 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K) / (1 atm) ≈ 22.4 L

Therefore, the volume of hydrogen gas produced in the reaction is approximately 22.4 liters.

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Barrier islands are not permanent because the wind and the waves are constantly redistributing the sand.

Barrier islands are particularly flat or lumpy sand regions that are formed parallel to the mainland shore by wave and tide action. They typically appear in groups called chains, which can range in size from a few to more than a dozen islands.

They are called "barriers" because they act as a physical barrier, protecting the mainland from the effects of strong waves, storm surges, and flooding. Barrier islands are formed by a variety of processes, including longshore drift, sediment deposition, and sea level changes.

Barrier islands typically consist of sandy beaches on their seaward side and marshes, lagoons, or dunes on their landward side.

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