How Many Grams Of Water Are Produced By Reacting 15.8 g H2, With Excess Oxygen? 2H2 + O2 --> 2H20
A. 141 G
B. 15.8 G
C. 17.8 G
D. 282 G
Answers
By using stoichiometry and considering the molar ratios from the balanced chemical equation, we find that reacting 15.8 g of H2 with excess oxygen will produce 141 g of water. 141 g.option A.
In the balanced chemical equation 2H2 + O2 → 2H2O, it is stated that two moles of hydrogen gas (H2) react with one mole of oxygen gas (O2) to produce two moles of water (H2O). Since the molar mass of water is approximately 18 g/mol, we can calculate the amount of water produced by converting the mass of hydrogen gas to moles and then using the mole ratio from the balanced equation.
To find the moles of hydrogen gas, we divide the given mass (15.8 g) by the molar mass of hydrogen (2 g/mol), which gives us 7.9 moles of H2. According to the balanced equation, each mole of H2 produces two moles of H2O. Therefore, 7.9 moles of H2 will produce 2 * 7.9 = 15.8 moles of H2O.
Finally, we convert the moles of water to grams by multiplying the moles (15.8) by the molar mass of water (18 g/mol), which gives us 284.4 g. However, we need to remember that the given reaction has excess oxygen, meaning all the hydrogen will react. Therefore, the limiting reactant is not hydrogen but oxygen.
Consequently, the amount of water produced will be based on the number of moles of oxygen. Since there is excess oxygen, we can assume that the moles of oxygen consumed are equal to the moles of hydrogen reacted. Therefore, the correct answer is 15.8 moles * 18 g/mol = 141 g.option A.
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Related Questions
A proposed explanation that is based on observations and that can be tested (but hasn't been tested yet) is known as a(n)
Answers
Answer: I think its a hypothesis.
A particular brand of gasoline has a density of 0.733 g/mL at 25 oC. How many grams of this gasoline would fill a 10.7 gal tank (1 US gal
Answers
For a certain brand of gasoline, which has a density of 0.733 g/mL at 25 oC, 41848 grammes would fill a 10.7 gal tank. Mass in relation to volume is referred to as density.
Although the Latin letter D can also be used, the symbol for density is most frequently written as (the lower case Greek letter rho). Any combination of gases can be considered a gas gas solution. As a result of their great distance from one another, gas molecules typically only interact very little. All gases can therefore be thought of as being soluble in one another.
15x 3785.41 ml = 56781.15 ml. Consequently, the mass is calculated as 0.737g/ml x 56781.15 ml = 41848 grammes.
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How many different elements are involved in the reaction shown below?
2Fe + 6HC2H3O2 → 2Fe(C2H3O2)3 + 3H2
Answers
There are four. Fe, H, C, and O
The formula for propane is c3h8 what would you need to know to answer how much energy is required to combust propane vs gasoline
Answers
For propane combustion, the balanced equation is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
This equation shows that one molecule of propane (C₃H₈) reacts with five molecules of oxygen (O₂) to produce three molecules of carbon dioxide (CO₂) and four molecules of water (H₂O).
For gasoline, the composition can vary, and the exact balanced equation would depend on the specific hydrocarbon components present in the gasoline.
Once you have the balanced equations, you would also need to know the standard enthalpy of formation (ΔH°f) values for the reactants and products involved in the combustion reactions. These values represent the change in enthalpy (energy) during the formation of one mole of a substance from its constituent elements, at standard conditions.
With the balanced equations and the ΔH°f values, you can apply the principles of thermochemistry and use the Hess's Law to calculate the energy released during the combustion reactions of propane and gasoline. The difference in energy released would indicate the difference in energy required to combust propane vs gasoline.
HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71 Ha : Not all proportions are equal. HD: Not all proportions are equal. Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71 HD: Not all proportions are equal. Ha:pSun =pMon =pTue =pWed =pThu =rhoFri =pSat =71 HD:pSun =pMon =pTue =pWod =pThu =pFri =pSat =71 Ha : All proportions are equal. Find the value of the test statistic. (Round your answer to three d: Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject H0−. We conclude that the proportion of traffic Reject HD. We conclude that the proportion of traffic acciden Reject HD. We conclude that the proportion of traffic acciden Do not reject H0−We conclude that the proportion of traffic Compute the percentaqe of traffic accidents occurring on each day What day has the highest percentage of traffic accidents? Sunday Monday Tuesday Wednesday Thursday Friday Saturday Based on 2017 sales, the six top-selling compact showed the following number of vehicles sold. Use a goodness of fit test to determine if the sample data indicate that the market shares for compact cars in the city are different than the market shares suggested by nationwide 2017 sales. Use a 0.05 level of significance. State the null and alternative hypothesis. Ha : The market shares for the compact cars in the city are different for at least one of the nationwide market shares listed. o: The market shares for the compact cars in the city do not differ from market shares nationwide. : The market shares for the compact cars in the city are different from at least one of the nationwide market shares listed. Ha : The market shares for the compact cars in the city are not different from any of the natione Ha : The market shares for the compact cars in the city do not differ from market shares nationwide. "the test statistic.(Round your answer to two decimal places.) d the rho-value. (Round your answer to four decimal places.) Reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We conclude that market shares for the compact cars in the city differ from the nationwide market shares. Do not reject H0. We cannot conclude that market shares for the compact cars in the city differ from the nationwide market shares.
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The p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
Firstly, let us conduct a Chi-square test of independence of categorical variables based on the information given above. We have three different cases of hypothesis testing that we have to solve one by one.
Case 1: HD:pSun =rhoMan =pTue =pWed =pThu =pFri =pSat =71
Ha : Not all proportions are equal.
Test Statistic
For this hypothesis, we need to compute the test statistic that is given as:
\($$\chi^2=\sum_{i=1}^{k}\frac{(O_i-E_i)^2}{E_i}$$\) where k is the number of groups/categories. Since we have 7 days of the week, \(k = 7. $O_i$ and $E_i$\) are the observed and expected frequencies respectively.
Here, we have equal proportions of 71 for each day of the week.
Therefore, the expected frequencies are also equal to 71.
\($$E_i = 71, i=1,2,3,4,5,6,7.$$\)
We also have to use the given information to compute the observed frequencies,
\($O_i$.$$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126$$\)
Therefore, the test statistic can be computed as \($$\chi^2=\frac{(90-71)^2}{71} + \frac{(99-71)^2}{71} + \frac{(122-71)^2}{71} + \frac{(123-71)^2}{71} + \frac{(130-71)^2}{71} + \frac{(160-71)^2}{71} + \frac{(126-71)^2}{71}$$$$\chi^2=180.14\)
Now we have to find the p-value of this test. Since the number of degrees of freedom is k - 1 = 7 - 1 = 6, the p-value can be found using the chi-square distribution table with 6 degrees of freedom at the 0.05 significance level. The p-value is 0.000014. ConclusionSince the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
The total number of accidents is \($$90+99+122+123+130+160+126=850$$\)
The percentage of accidents occurring on each day of the week can be found as follows:
\($$Sunday: $$\frac{90}{850}\times 100 = 10.59\%$$Monday: $$\frac{99}{850}\times 100 = 11.65\%$$Tuesday: $$\frac{122}{850}\times 100 = 14.35\%$$Wednesday: $$\frac{123}{850}\times 100 = 14.47\%$$Thursday: $$\frac{130}{850}\times 100 = 15.29\%$$Friday: $$\frac{160}{850}\times 100 = 18.82\%$$Saturday: $$\frac{126}{850}\times 100 = 14.82\%$$\)
From the above percentages, we can see that Friday has the highest percentage of traffic accidents.
Case 2:
HD: Not all proportions are equal.
Ha:pSun =pMon =pTue =rhoWed =pThu =rhoFri =rhoSat =71
Test Statistic
\($$E_1 = 78.57, E_2 = 86.57, E_3 = 106.86, E_4 = 107.43, E_5 = 113.57, E_6 = 139.43, E_7 = 109.14$$\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic can be computed as:
\($$\chi^2=\frac{(90-78.57)^2}{78.57} + \frac{(99-86.57)^2}{86.57} + \frac{(122-106.86)^2}{106.86}+ \frac{(123-107.43)^2}{107.43} + \frac{(130-113.57)^2}{113.57} + \frac{(160-139.43)^2}{139.43} + \frac{(126-109.14)^2}{109.14} $$$$ \implies \chi^2=34.98$$\)
The p-value is 0.000001.
Conclusion- Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that not all proportions are equal.
Case 3:
All proportions are equal.
Test Statistic
The expected frequency for each group is
\(E = \frac{850}{7} = 121.43\)
We already know the observed frequencies,
\($$O_1 = 90, O_2 = 99, O_3 = 122, O_4 = 123, O_5 = 130, O_6 = 160, O_7 = 126.$$\)
The test statistic is,
\($$\chi^2=\frac{(90-121.43)^2}{121.43} + \frac{(99-121.43)^2}{121.43} + \frac{(122-121.43)^2}{121.43} + \frac{(123-121.43)^2}{121.43} + \frac{(130-121.43)^2}{121.43} + \frac{(160-121.43)^2}{121.43} + \frac{(126-121.43)^2}{121.43}} \\\implies \chi^2=9.17$$\)
The p-value is 0.1664.
Since the p-value is greater than the significance level of 0.05, we do not reject the null hypothesis and conclude that all proportions are equal.
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Need help answering these questions. Please show all work. Thank you so much.
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Answer:
i dont know
Explanation:
GIVING BRAINLIEST TO WHOEVER ANSWERS THIS!!
What is the density of rod D, in g/cm3 ? Mass is 15 grams and volume is 14 cm3.
A: 2.5 g/cm3
B: 1.4 g/cm3
C: 1.1 g/cm3
D: 0.94 g/cm3
Answers
Answer:
The answer is option CExplanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\ \)
From the question we have
\(density = \frac{15}{14} \\ =1.0714285 ...\)
We have the final answer as
1.1 g/cm³Hope this helps you
Calculate the equilibrium constant for the reaction, at 25°CCu(s) + 2Ag+ (aq) → Cu+2 (aq) + 2Ag (s)at 25oC, Eocell = 0.47 V, R = 8.134 JK−1 F = 96500 C is
Answers
The equilibrium constant for the reaction is 8.5* 10^15.
What does chemical equilibrium mean?Chemical equilibrium is characterized as an active condition in which the concentration of each reactant remains constant. While they might not be equal, they are not altering. A double arrow in a chemical process denotes an equilibrium state. Products are on the right while reactants are to the left.
What are equilibrium and an example?The Latin term libra, which meaning weight or balance, is the origin of the word equilibrium. Several instances of equilibrium include: a book that is open and at rest. a vehicle that is going steadily. a chemical process where both the forward and backward rates of reaction are equal.
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Adiabatic process is a process in which _ is constant (a) temperature (b)volume (c)pressure (d) heat
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Answer: Adiabatic process is a process in which heat is constant
Explanation:
The processes in which temperature remains constant is called isothermal process.
The process in which Volume remains constant is called isochoric process.
The process in which pressure remains constant is called isobaric process.
The process in which no heat is gained or lost by the system, Hence heat remains constant is called as adiabatic process.
Thus option d) heat is correct
ng.
3. Connect to Technology How do probes,
including landers and rovers, improve our
ability to make observations of other planets?
s
Answers
18. which of the following description of color is correct? a. [cu(nh3)4]2 (aq), deep blue b. [ag(nh3)2] (aq), deep blue c. agcl (s) black precipitate d. agi (s), white precipitate
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w 17. Which of the following is the atomic number of a halogen? A. O 10 B. 136 C. 17 D. 13
Answers
Answer:
C. 17
Explanation:
The question above is related to the "Periodic Table of Elements." The Halogen group is located on the right side of the table. It consists of six elements: Fluorine, Chlorine, Bromine, Iodine, Astatine and Tennessine.
The "atomic number" of an element refers to the number of protons that can be found in the element's nucleus. Among the halogens, "Chlorine" is the only one with an atomic number of 17. Halogens do not have an atomic number of 10, 136 and 13.
Which is a positive effect of using chemistry?
O The synthesis of drugs to disease may increase adverse reactions in others.
O The use of herbicides to increase resistance in tolerant plants.
O Fertilizer runoff from farms into natural waters will purify water systems.
O Energy can be generated without burning fossil fuels.
Answers
The positive effect of using chemistry is the generation of energy without fossil fuels.
Chemistry is the branch of science that deals with the study of the nature, properties and composition of matter as well as the changes that matter undergoes. Chemistry has really contributed positively to the advancement of the society.
Lately, there has been a lot of emphasis on alternative sources of energy apart from fossil fuels. One such options is the use of hydrogen fuels. Chemistry has been at the forefront of this research.
Hence, one positive effect of using chemistry is that energy can be generated without burning fossil fuels.
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Answer:
its D.
Explanation:
metallic pan is provided with a wooden plastic handle give reason
Answers
The metallic pan iis most likely going to be used on a stove.
The stove is heating something, and the conductive metallic pan will, well, conduct that heat throughout the entire body of the pan. Doing this will spread the heat to the handle, burning your hands.
Both wood and plastic are insulators, and they do not conduct heat or electricity. They will insulate your hands and protect them from the heat.
a funnel containin a relatively wide nozzle (opening). used to deliver solids without making a mess. essential in precise preparation of solid-liquid solutions.
Answers
A funnel with a wide nozzle is essential in precise preparation of solid-liquid solutions.
A funnel with a wide nozzle is crucial in the accurate and mess-free delivery of solids when preparing solid-liquid solutions. The wide opening of the nozzle allows for easy pouring of solid materials into the funnel without the risk of spills or splashing. This is particularly important when working with substances that require precise measurements or specific concentrations.
The wide nozzle ensures that the solids can be poured into the funnel without clogging or creating blockages. It allows for a smooth and controlled flow, ensuring that the solid particles are evenly distributed throughout the liquid. This is especially critical in applications such as scientific experiments, laboratory procedures, or industrial processes where the accuracy of the solution's composition is paramount.
By using a funnel with a wide nozzle, the risk of contamination or inaccurate measurements is minimized. The wider opening provides ample space for the solid particles to pass through without causing disruptions or inconsistent mixing. Additionally, it simplifies the cleaning process after use, as any remaining solids can be easily rinsed out without leaving residue or causing blockages.
In summary, a funnel with a wide nozzle is an essential tool for delivering solids without making a mess, especially when preparing solid-liquid solutions. Its design allows for precise and controlled pouring, ensuring accurate measurements and uniform mixing of the substances.
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PLEASE HELP ASAP
During convection heat is transferred through fluids. Which statement is true about fluids?
Only gasses are fluids
Only liquids are fluids
Only solids are fluids
Both liquids and gasses are fluids
Answers
John has a solution. It turns yellow when he adds red cabbage juice. Predict what colour the solution would turn if he added hibiscus- flower juice. Explain your answer.
Answers
As the solution turns yellow when re cabbage juice indicator is added it implies that its base solution so the color of the solution when hibiscus flower juice added is dark grey to green.
when hibiscus indicator added Anywhere from dark pink to pale pink usually indicates an acid, while dark gray to green colors usually indicate a base.
Dark blue should be the color of red cabbage indicator. The cabbage indicator's color will shift to red or pink if the solution is an acid, and to green or yellow if the solution is a base. In the event that the test solution is neutral, it will stay purple or blue
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A toy car that is 0.12 m long is used to model the actions of an actual size car that is 6 m long which ratio shows the relationship between the sizes of the model and the actual car ?
Answers
Answer:
The correct answer is - 1:50.
Explanation:
Given:
Model toy car = 0.12 m
Actual size of car = 6 m
The ratio of model and actual car size = ?
Solution:
We know that 1 m = 100 cm
then, Model toy car - 0.12*100 = 12 cm
and size of the actual car - 6*100 - 600 cm
Then the ratio of model and actual car size = model car size/ actual car size
= 12/600
= 1/50
Thus, the correct answer is - 1:50.
according to epa values, are the chloride concentrations in surrounding large watersheds to lake michigan a concern? what about surrounding small watersheds?
Answers
However, generally speaking, chloride concentrations in surrounding watersheds can be a concern for aquatic life and the ecosystem.
What is concentration?Concentration refers to the amount of a substance present in a given volume or mass of another substance. It can be expressed in different units, such as mass per volume (e.g., mg/L), moles per volume (e.g., mM), or percentage (%). Concentration is often used to describe solutions, but it can also be used for gases and solids.
Here,
High chloride levels can impact water quality, harm aquatic organisms, and affect the overall health of a watershed. The EPA has established water quality standards for chloride in surface waters to protect aquatic life and human health. The specific concentrations that are considered a concern can vary depending on the location and other factors. It is important to regularly monitor chloride levels in watersheds and take action if they are found to be above safe levels.
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WILL GIVE BRAINLIEST AND 20 POINTS How many grams are in 2.36 L of neon gas
Answers
Answer:
2.088464 grams.
Explanation:
The density of neon is 0.9002 g/L. Multiplying this value by the number of liters gives how many grams of neon it contains.
0.9002(2.32) = 2.088464
How did Henry Ford affect diversity in Detroit?
Diversity increased because Ford hired immigrants from many different countries. Diversity increased because Ford hired immigrants from Canada and Mexico only. Diversity decreased because Ford practiced discriminatory hiring practices and immigrants looked for work elsewhere.
Diversity decreased because Ford primarily used machines and hired fewer workers.
Answers
Answer:
A) "Diversity increased because Ford hired immigrants from many different countries." I believe this is the answer.
Explanation:
Answer:
A
Explanation:
a chemical reaction is performed in a flask that is connected to a piston. the gas produced in the reaction pushes the piston upward against a constant external pressure of 1.5 atm so that the volume of gas changes from 0.95 l to 2.5 l. what is the value of work (in joules) along with the correct sign?
Answers
the value of work done is -235.73 J. The negative sign indicates that the work done is against the external pressure.
The chemical reaction produces gas that pushes the piston upward against an external pressure of 1.5 atm so that the volume of the gas changes from 0.95 L to 2.5 L. The work (in joules) can be calculated as follows:
W = -PΔV
where,
W = work done
P = external pressure
ΔV = change in volume
We are given the following values:
P = 1.5 atm
ΔV = 2.5 L - 0.95 L = 1.55 L
Substituting the given values in the formula for work done,
W = -PΔV = -(1.5 atm) (1.55 L) = -2.325 atm L
Converting the units of pressure and volume to SI units,
W = -2.325 atm L × 101.3 J L⁻¹ atm⁻¹ × (1 m³ / 1000 L) = -235.73 J
Thus, the value of work done is -235.73 J. The negative sign indicates that the work done is against the external pressure.
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The efeect of concentration and temperature on the rate of reaction can be explored using the reaction between magnesuim ribbon and dilute sulphuric acid. Mg(s) +H2SO4(aq)—mgso4(aq)+h2(g)
Answers
The effect of concentration on the rate of reaction between magnesium ribbon and dilute sulphuric acid can be observed by changing the concentration of the acid while keeping the temperature constant.
As the concentration of the acid increases, the rate of reaction will also increase. This is because there are more acid particles present in the solution, which means there is a greater chance of successful collisions between the acid particles and the magnesium ribbon.
Similarly, the effect of temperature on the rate of reaction can be observed by changing the temperature while keeping the concentration of the acid constant. As the temperature increases, the rate of reaction will also increase. This is because the particles have more energy at higher temperatures, which means they will move faster and collide more frequently, leading to a faster reaction rate.
Overall, both concentration and temperature have an impact on the rate of reaction between magnesium ribbon and dilute sulphuric acid. By increasing the concentration or temperature, the rate of reaction will increase as well.
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Which statement describes the conditions in which diamonds form?
A.they form deep underground, in certain areas that are under a great deal of pressure.
B.they form as water evaporates on the shores of very salty bodys of water.
C.They form as water evaporates on the shore of any body of water.
D.they form deep underground, in most regions of earth.
Answers
Answer:
b for sure
Explanation:
Si se sabe que el bronce se forma con 60% de cobre y 40% de estaño¿cual sera la masa de cobre contenida en 200 gramos de bronce
Answers
Answer:
Mass of copper in 200 g bronze is 120 g.
Explanation:
If it is known that bronze is formed with 60% copper and 40% tin, what will be the mass of copper contained in 200 grams of bronze?
Percentage of copper in bronze = 60 %
Percentage of tin in bronze = 40 %
Mass of bronze = 200 grams
Mass of copper in bronze = 60 % of 200 g
= 0.6 x 200 = 120 grams
Mass of copper in 200 g bronze is 120 g.
Then if I have 210.1 g barium chloride with 45g potassium...how many grams of potassium chloride will I produce?
Do the stoich
I need help please is for today ):
Answers
Answer:
85.8 g
Explanation:
The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...
210.1/208.233 ≈ 1.009 mol
The molar mass of K is about 39.089 g/mol, so 45 g is about ...
45/39.089 ≈ 1.1509 mol
The balanced equation seems to be ...
BaCl₂ + 2K ↔ 2KCl + Ba
This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.
The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.
The reaction produces 85.8 g of KCl.
Answer:
85.8 gThe grams of potassium chloride that will produce.The enthalpy change for the following reaction is 66. 4 kJ. Using bond energies, estimate the N=O bond energy in NO2(g). N2(g) + 2O2(g) + 2NO2(g) 66. 4 kJ/mol 93. 8 kJ/mol -32. 5 kJ/mol / -132 kJ/mol
Answers
The bond energy of N=O in NO2(g) is +282.8 kJ/mol, based on the convention that breaking bonds is a positive value.
Total bond energy in reactants = (1 × N ≡ N bond energy) + (2 × O = O bond energy) + (2 × N–O bond energy)
Total bond energy in reactants = (1 × 941 kJ/mol) + (2 × 498 kJ/mol) + (2 × N–O bond energy)
Total bond energy in reactants = 1878 kJ/mol + 2N–O bond energy
Calculate the bond energy of the bonds formed in the products.
The only bond formed in the products is the N–O bond.
N–O bond energy = 623 kJ/mol
Therefore, the total bond energy in the products is:
Total bond energy in products = 2 × N–O bond energy
Total bond energy in products = 2 × 623 kJ/mol
Total bond energy in products = 1246 kJ/mol
Using these bond energies, estimate the N=O bond energy.
Bond energy = (total energy of reactants) - (total energy of products)
∆Hrxn = ∑Bonds broken - ∑Bonds formed
66.4 kJ/mol = (1878 kJ/mol + 2N–O bond energy) - (1246 kJ/mol)
66.4 kJ/mol = 1878 kJ/mol + 2N–O bond energy - 1246 kJ/mol
66.4 kJ/mol = 632 kJ/mol + 2N–O bond energy
66.4 kJ/mol - 632 kJ/mol = 2N–O bond energy
-565.6 kJ/mol = 2N–O bond energy
The bond energy of N=O in NO₂(g) is 282.8 kJ/mol, which is half of 565.6 kJ/mol.
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Define positive or reinforcing feedback
Answers
Answer: right answerq
Explanation: Positive feedback occurs to increase the change or output
a solution containing a mixture of metal cations was treated with dilute hcl and no precipitate formed. next, h2s was bubbled through the acidic solution. a precipitate formed and was filtered off. then, the ph was raised to about 8 and h2s was again bubbled through the solution. a precipitate again formed and was filtered off. finally, the solution was treated with a sodium carbonate solution, which resulted in no precipitation. classify the metal ions based on whether they were definitely present, definitely absent, or whether it is possible they were present in the original mixture.
Answers
Answer:
Based on the observations described, we can classify the metal ions as follows:
Definitely present: The metal ions that formed precipitates with H2S under acidic conditions are definitely present. These metal ions include:
Pb2+ (lead)
Hg2+ (mercury)
Cu2+ (copper)
Bi3+ (bismuth)
Cd2+ (cadmium)
Definitely absent: The metal ions that did not form precipitates with H2S under both acidic and basic conditions are definitely absent. These metal ions include:
Na+ (sodium)
K+ (potassium)
Mg2+ (magnesium)
Ca2+ (calcium)
Al3+ (aluminum)
Fe3+ (iron III)
Possible presence: The metal ions that did not form precipitates with H2S under acidic conditions but formed precipitates under basic conditions are possibly present. These metal ions include:
Zn2+ (zinc)
Mn2+ (manganese)
Ni2+ (nickel)
Co2+ (cobalt)
However, we cannot definitively conclude that these metal ions were present in the original mixture, as their precipitation under basic conditions may have been due to other factors such as the formation of complex ions or the pH dependence of their solubility. Further tests would be needed to confirm their presence.
Explanation:
The metal cations most likely present in the original mixture were iron (Fe2+), lead (Pb2+), and zinc (Zn2+).
The iron ions would definitely have been present since they reacted with both the dilute HCl and the H2S to form a precipitate both times. Lead and zinc ions were also likely present since they too reacted with H2S, forming a precipitate in the second trial.
The metal cations that were definitely not present in the original mixture were copper (Cu2+), silver (Ag+), and cadmium (Cd2+). Copper and silver do not react with H2S and therefore no precipitate was formed.
Cadmium does react with H2S, but did not form a precipitate in the second trial when the pH was raised to 8, likely because it was not present in the original solution.
It is possible that nickel (Ni2+) and chromium (Cr3+) were present in the original mixture since they do not react with either HCl or H2S. However, since they did not react with the sodium carbonate to form a precipitate, it is impossible to definitively conclude their presence.
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As the wavelength of an electromagnetic wave gets longer, the frequency ____________________.
Answers
Or
Decreases