From the stoichiometry of the reaction, the mass of K2O produced is 0.58 g/
What is a chemical reaction?A chemical reaction is one in which two or more substances are able to combine to lead to the formation of something new.
In this case, the reaction equation is; 4K + 02 -----> 2K20.
Number of moles of K = 0.50g/39 g/mol = 0.013 moles
Number of moles of O2 = 0.10g/32 g/mol = 0.0031 moles
If 4 moles of K reacts with 2 moles of O2
0.013 moles moles of K reacts with 0.013 moles * 2 moles/ 4 moles
= 0.0065 moles
Hence, O2 is the limiting reactant
1 mole of O2 yields 2 moles of K2O
0.0031 moles of O2 yields 0.0031 moles * 2 moles/ 1 mole
= 0.0062 moles
Mass of K2O = 0.0062 moles * 94.2 g/mol
= 0.58 g
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Match each element to the number of electrons in its valence shell.
Match Term Definition
Carbon (C) A) Four
Hydrogen (H) B) Two
Magnesium (Mg) C) Six
Oxygen (O) D) One
Answer:
C: 4
H: 1
Mg: 2
O : 6
Explanation:
You can quickly find out the number of valence electrons by looking at where the element is on the periodic table and referring to the table that is attached.
how can freeze-fracture be used to determine the orientation of a protein in a membrane?
Freeze-fracture is a technique used to determine the orientation of proteins in a membrane. It involves freezing a sample, fracturing it, and examining the resulting membrane surfaces.
1. By using specific labeling techniques and electron microscopy, freeze-fracture can reveal the distribution and arrangement of proteins within the lipid bilayer.
2. Freeze-fracture begins by rapidly freezing a biological sample, preserving its structure. The frozen sample is then fractured, typically along the lipid bilayer, resulting in two complementary fracture faces: the fracture face (P-face), which corresponds to the protoplasmic (cytoplasmic) side of the membrane, and the complementary fracture face (E-face), which corresponds to the exoplasmic (extracellular) side of the membrane. These faces can be coated with heavy metals, such as platinum, to enhance their visibility under an electron microscope.
3. To determine the orientation of a protein within the membrane, specific labeling techniques can be employed. Antibodies or other protein-specific probes can be used to label the protein of interest with gold particles or other electron-dense markers. These markers selectively bind to the protein and can be visualized using electron microscopy. By examining the distribution and density of the markers on the P-face and E-face, it is possible to infer the orientation of the protein in the membrane.
4. If a protein is evenly distributed on both faces, it suggests that the protein spans the membrane, with portions exposed on both sides. If the protein is predominantly observed on one face, it indicates that it may be oriented asymmetrically in the membrane. By comparing the labeling patterns of various proteins, researchers can gain insights into their orientation and arrangement within the lipid bilayer.
5. In conclusion, freeze-fracture combined with specific labeling techniques and electron microscopy provides a valuable tool for determining the orientation of proteins in a membrane. This approach allows researchers to study the distribution and arrangement of proteins within the lipid bilayer, providing insights into their functional roles in cellular processes.
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Sodium will do an ionic bond with
Answer:
Chorine
Explanation:
It's a classic, sodium chloride, table salt, which is an ionic bond.
PLS GIVE BRAINLIEST
Answer this question without using numbers from the book (or anywhere else!)
ΔS for the following reaction is positive. True or false?
HCl(aq) + NaOH(aq) => NaCl(aq) + H2O(l)
True. The reaction of HCl(aq) and NaOH(aq) to form NaCl(aq) and H2O(l) is an example of a reaction that is classified as exothermic, meaning that it releases heat.
This release of heat is due to the breaking of bonds in the reactants, which requires energy, and the formation of new bonds in the products, which releases energy.
The entropy of the system is increased by the release of heat and the additional movement of particles, since the products are in a more disorganized state than the reactants. Therefore, the entropy change (ΔS) for the reaction is positive.
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Question 4 "That oil sands executive is greedy and heartless and therefore can't be trusted when she claims to want to improve her company's environmental record."
O False dilemma
O Ad hominem attack
O Straw man
O Appeal to authority
Question 5 "There is no proof that humans are causing climate change so it must natural causes
O False dilemma
O Appeal to ignorance
Strawman
O Appeal to authority
That oil sands executive is greedy and heartless and therefore can't be trusted when she claims is Ad hominem attack. So, Option B is correct.
4- The argument in question 4 is an example of an ad hominem attack. This is due to the argument's focus on the character of the oil sands executuive rather than the actual problem, which is how to improve the company's environmental record.
The argument holds that the executive cannot be believed when she says she wants to improve the company's environmental record because she is avaricious and callous. This is an error in logic, though, as the executive's character may not necessarily be related to the company's environmental policies.
5- The argument in question 5 is an example of an appeal to ignorance. This is because the argument states that there is no proof that humans are causing climate change, so it must be natural causes. Just because there is no conclusive proof that humans are causing climate change, it does not mean that they are not.
The argument assumes that just because there is no evidence to the contrary, the argument must be true. This is a logical fallacy.
So, Option B is correct.
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pick repel,or attract. were its circled
KINDLY PARAPHRASE THE FOLLOWING PARAGRAPHS:
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Growth in Distribution Spaces
An essential part of the e-commerce business is its supply chain. Figuring out the logistics for packaging and shipping goods to customers includes warehousing, and that’s where commercial real estate comes into play. As e-commerce has grown, we have seen significant growth in the leasing and sale of distribution centers and warehouse spaces.
E-commerce giants look for spaces near large cities like Houston while still having enough space for large buildings. There is a lot of potential and growth in the Houston suburbs such as Katy, Brookshire & Waller. We are seeing more distribution centers popping up in these areas.
Smaller Retail Spaces
As retail has shifted to online, we have seen businesses struggling to keep physical spaces open over the past few years. While e-commerce is booming, some brick-and-mortar spaces are having to close or downsize.
There are certain markets, like groceries, that will always require a physical location, but there is a trend for smaller retail spaces across the market. Smaller spaces mean less inventory in-store, and this consequently encourages a combination of online and in-store shopping. Hybrid shopping especially increased in popularity during the Covid-19 lockdown.
Merging online shopping with curbside or in-store pick-up offered that element of convenience and a safe way to shop during the pandemic, and even as restrictions ease, people will still seek the ease of this approach. However, even though convenience is what mainly drives e-commerce, we don’t expect to see in-store experiences disappear altogether.
Increased Technology in Retail
Since many prefer shopping online, working to translate the benefits of technology to physical spaces has been important in keeping up with trends. Integrating technology into retail spaces will be essential for future leasing and selling opportunities in the market. Implementing tools such as apps can create unique and convenient shopping experiences and can help businesses gather data that is essential for tracking traffic and learning more about the customer.
These tools can also help drive customers to the retail location with special offers or in-store pickup options. Large lifestyle shopping centers have shown to be among the most proactive in blending technology with consumer experiences.
Overall, e-commerce has a major impact on the commercial real estate business, from the industrial real estate benefit from its growth to seeing space buying and leasing becoming a smaller part of retail operations. In 2020 alone, e-commerce accounted for 14 percent of all sales, but it is inevitable that e-commerce will continue to grow as it has for the last decade. Commercial real estate is a reflection of society and its habits and we will continue to see it mirrored as changes in technology and retail emerge.
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The impact of e-commerce on commercial real estate is significant. E-commerce sales have grown steadily, accounting for a considerable portion of overall sales.
The growth of e-commerce has fueled the demand for distribution spaces, specifically distribution centers and warehouses, which play a crucial role in the supply chain and logistics of packaging and shipping goods to customers. These spaces are sought after by e-commerce giants, who prefer locations near large cities while still providing ample room for large buildings. Suburban areas, such as Katy, Brookshire, and Waller near Houston, are experiencing significant growth in the establishment of distribution centers.
On the other hand, the rise of online shopping has posed challenges for brick-and-mortar retailers. Many physical retail spaces have struggled to remain open or have had to downsize. As a result, there is a trend towards smaller retail spaces, which require less inventory in-store. This trend encourages a combination of online and in-store shopping, known as hybrid shopping. The Covid-19 pandemic further accelerated this trend as consumers sought the convenience and safety of online shopping with options like curbside or in-store pick-up. Even as restrictions ease, this approach is expected to remain popular.
To adapt to the changing retail landscape, integrating technology into physical retail spaces has become crucial. Technology tools, such as mobile apps, can enhance the shopping experience, offer special promotions, and provide valuable data on customer behavior. Retailers, especially large lifestyle shopping centers, have been proactive in blending technology with consumer experiences to stay relevant and attract customers.
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How did the data from the class barometer compare to the air pressure shown in the weather report?
How did the data from the class barometer compare to the air pressure shown in the weather report?
The comparison between the class barometer data and the air pressure shown in the weather report serves as a means to evaluate the accuracy and effectiveness of the barometer's measurements.
The comparison between the data from the class barometer and the air pressure shown in the weather report revealed a correlation between the two measurements. The class barometer readings were likely taken at the same time as the weather report's air pressure measurement to ensure accurate comparison.
If the class barometer readings closely matched the air pressure indicated in the weather report, it would suggest that the barometer was functioning correctly and providing reliable measurements. This would indicate that the class barometer could be used as a reliable tool for monitoring air pressure changes.
However, if there were significant discrepancies between the class barometer readings and the air pressure reported in the weather report, it could indicate a calibration issue with the barometer or potential inaccuracies in its measurements. In such a case, it would be necessary to investigate the reasons behind the discrepancies and determine the reliability of the class barometer for future use. It helps to determine the barometer's reliability as a tool for monitoring air pressure changes in the local environment.
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How many grams of NH3
form when 22.3 L
of H2(g)
(measured at STP) reacts with N2
to form NH3
according to this reaction?
N2(g)+3H2(g)→2NH3(g)
Answer:
11.2823 grams of NH3 are produced
Explanation:
No. of moles for H2 = 22.3/22.4 = 0.9955 moles
By calculating number of moles produced of NH3, by using ratios:
N2 + 3H2 → 2NH3
1 : 3 : 2
? : 0.9955: ?
part value = 0.9955/3 = 0.33183
No. of moles for NH3 = 2 * 0.33183 = 0.6637 moles
mass of produced NH3 (Molar mass = 17 g/mol) = 0.6637*17 = 11.2823 grams
What is a Titration?
Titration is a laboratory technique used to determine the concentration of a solution by adding a solution of known concentration to it until a reaction occurs.
The point at which the reaction is complete is called the equivalence point, and it can be identified using an indicator or by monitoring the pH of the solution. The amount of the known solution required to reach the equivalence point is used to calculate the concentration of the unknown solution.
Titration is commonly used in chemistry to analyze the properties of acids and bases, as well as in pharmaceuticals, food science, and environmental testing.
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A quantity of monatomic ideal gas expands adiabatically from a volume of 2.0 liters to 6.0 liters. if the initial pressure is p0, what is the final pressure?
Answer:
1/3p0
Explanation:
The combined gas law:
P1V1/T1 = P2V2/T2, where P, V and T are Pressure, Volume, and Temperature. Temperature must always be in Kelvin. The subscriopts 1 and 2 are for initial (1) and final (2) conditions.
In this case, temperature is constant (adiabatically). V1 = 2.0L and V2 = 6.0L. I'll assume P1 = p0.
Rearrange the combined gas law to solve for final pressure, P2:
P1V1/T1 = P2V2/T2
P2 = P1*(V1/V2)*(T2/T1) [Note how I've arranged the volume and temoperature terms - as ratios. This helps us understand what the impact of raising or lowering one on the variables will do to the system].
No enter the data:
P2 = P1*(V1/V2)*(T2/T1): [Since T2 = T1, the (T2/T1) terms cancels to 1.]
P2 = p0*(2.0L/6.0L)*(1)
P2 = (1/3)p0
The final pressure is 1/3 the initial pressure.
2. What range of numbers would you expect on the pH scale for an acid? (1 mark)
Answer:
A pH less than 7 is acidic
how many unique proton signals are seen in the h1 nmr spectrum of ethanol after shaking with d2o? number of unique proton signals:
After shaking with D₂O, the spectrum of ethanol shows two proton signals. The OH signals will no longer exist.
Three peaks may be seen in the ethanol 1H-NMR spectra. The following are the chemical shifts (Image 1).
The spectrum of ethanol after shaking with D₂O shows only two peaks. After shaking with D₂O, the peak that corresponds to OH disappears at this point. The following are the chemical shifts (Image 2).
At around 3.57 ppm, a water peak forms while the -OH resonance totally vanishes. This happens as a result of leftover H₂O and HOD in the D₂O bottle and traded out hydroxy protons (-OH), which now produce more H₂O.
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What is the name of MnO? Explain how you determined the bond type and the steps you used to determine the naming convention for the compound.
Answer:
Magnesiumoxide
Explanation:
I don't know
PLEASE HELP ME 40 POINTS RIGHT ANSWERS ONLY :)
Answer:
Hi
Please mark brainliest ❣️
Thanks
Explanation:
Correct answer is D
Energy A
Look at this
Energy required to break bonds that is intermolecular forces
Which of the following compounds would contain an electrostatic attraction as bonds between ions?
Answer:
Fe2O3
Explanation:
H2 gas is added to the system at
equilibrium below. How does the
system adjust to reestablish
equilibrium?
51.8kJ + H_{2}(g) +l 2 (g)
The reaction shifts to the left reactants and the concentration of HI increases
The reaction shifts to the right products and the concentrations of H2 and I2 increase
The reaction shifts to the left reactants and the concentration of H2 and I2 increase
The reaction shifts to the right products and the concentration of HI increases
When the concentration of hydrogen gas is increased, the reaction will shift toward the products right and increase the concentration of HI, to consume the increased concentration of H₂.
What is chemical equilibrium ?Chemical equilibrium is the state at which the rate of forward reaction and backward reaction takes place in the same rate. According to Le-chatlier principle, When any imbalance occurs by some factors to the equilibrium, the system itself balances the disorder and re-establish a new equilibrium state.
An increase in the concentration of reactants will shift the reaction to the forward direction. Similarly, if the product concentration is increased, then the reaction shifts to backward direction to produce reactants.
Here, H₂ is the reactant and increasing its concentration makes the reaction shifts to the direction which consumes H₂. Hence, the reaction will shift toward the products right increasing the concentration of HI.
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11) A sample of gas has a volume of 823.7 mL and a pressure of 351.8 torr. What volume (in mL) will the gas occupy at 752.9 torr if the temperature of the gas doesn't change? Keep the answer with one decimal place
Answer:
384.9 mL.
Explanation:
What is given?
Volume 1 (V1) = 823.7 mL.
Pressure 1 (P1) = 351.8 torr.
Pressure 2 (P2) = 752.9 torr.
What do we need? Volume 2 (V2).
Step-by-step solution:
This is a Boyle's Law problem. Boyle's law states that the volume of a given mass of gas varies inversely with the pressure when the temperature is kept constant. An inverse relationship is described in this way. As one variable increases in value, the other variable decreases.
The formula of the law is:
\(P_1V_1=P_2V_2.\)Where P is pressure and V is volume. We want to find volume 2, 'V2'. So let's solve for 'V2' and replace the given data that we have in the new formula:
\(V_2=\frac{P_1V_1}{P_2}=\frac{351.8\text{ torr}\cdot823.7\text{ mL}}{752.9\text{ torr}}=384.882\text{ mL}\approx384.9\text{ mL.}\)The new volumewill be 3384.9 mL You can note as the pressure is increasing, the volume is decreasing.
Calculate the solubility parameter of polyamide 11. Determine which of the solvents: benzyl alcohol, methanol or ethyl methyl ketone will be the best solvent for polyamide 11.
The solubility parameter of polyamide 11 is approximately [value] (units).Among the solvents benzyl alcohol, methanol, and ethyl methyl ketone, the best solvent for polyamide 11 is [solvent name].
The solubility parameter is a measure of the cohesive energy density of a substance and is used to determine the compatibility between a polymer and a solvent. It represents the overall energy required to disperse the intermolecular forces within a substance.
To calculate the solubility parameter of polyamide 11, we need to know the values of the solubility parameters for the individual components of the polymer, such as the molar volume and cohesive energy density. Unfortunately, the solubility parameter values for specific polymers are not readily available in general literature.
To determine the best solvent for polyamide 11, we compare the solubility parameter values of the solvents with that of polyamide 11. The solvent with a solubility parameter closest to that of polyamide 11 is considered the best solvent.
Without specific solubility parameter values for polyamide 11 and the solvents benzyl alcohol, methanol, and ethyl methyl ketone, it is not possible to provide a direct calculation or comparison. The solubility parameter is an important factor in solvent selection for polymers, as it indicates the compatibility and likelihood of dissolution. However, without the necessary data, a definitive conclusion cannot be drawn regarding which solvent would be the best for polyamide 11. To determine the best solvent, it is recommended to consult literature or experimental data that provides solubility information for polyamide 11 in various solvents.
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Express the dosage using the ratio format you prefer. (Use mg for milligrams and mL for an injectable solution that contains 250mg in each 0.6 mL 3. [-/3 Points] CURRENMEDMATH11 12.3.002. EP. Consider the following. A 40mg in 2.5 mL solution will be used to prepare a 26mg dosage. Calculate the dosage using ratio and proportion. Express your final answer in mL to the
40mg
mL
=
X mL
26mg
40x
X
=
=
mL
[-/1 Points] CURRENMEDMATH11 12.3.004. Calculate the dosage (in milliliters). Express your answer to the nearest tenth. Assess y A 36mg per 2 mL strength solution is used to prepare 22mg. mL
The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.
The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.
To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.
40mg in 2.5 mL solution will be used to prepare a 26mg dosage.
Let X represent the mL of the solution needed to prepare the 26mg dosage.
We can set up the proportion as follows:
40mg/2.5mL = 26mg/X mL
Cross-multiplying and solving for X, we have:
40mg * X mL = 2.5mL * 26mg
40X = 65
X = 65/40
X ≈ 1.625 mL
For the second question:
36mg per 2 mL strength solution is used to prepare 22mg.
Let Y represent the mL of the solution needed to prepare the 22mg dosage.
We can set up the proportion as follows:
36mg/2mL = 22mg/Y mL
Cross-multiplying and solving for Y, we have:
36mg * Y mL = 2mL * 22mg
36Y = 44
Y = 44/36
Y ≈ 1.222 mL
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Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %
Using this formula, we can calculate the confidence interval once we have the sample data, without the sample data, it is not possible to provide an accurate confidence interval estimate.
To construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system, we would need the sample data, specifically the number of cell phone users and the number of users who developed cancer. Without the sample data, it is not possible to provide an accurate confidence interval estimate.
However, if we assume that we have the necessary sample data, we can proceed with the calculation. The formula for calculating a confidence interval for a proportion is:
Confidence interval
\(=�^±�×�^(1−�^)�Confidence interval= p^ ±z× np^ (1− p^ ) where:�^p^\)
is the sample proportion (number of users with cancer divided by the total number of cell phone users).
\(�\)
z is the z-score corresponding to the desired confidence level (90% confidence level corresponds to a z-score of approximately 1.645).
\(�\)
n is the sample size (total number of cell phone users).
Using this formula, we can calculate the confidence interval once we have the sample data.
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when exposed to an etchant, the atoms at the grain boundary dissolve at a greater rate than those within grains. this is because the atoms at the boundary i. have a higher state of energy ii. have no free electron iii. have a higher density iv. are packed more efficiently
when exposed to an etchant, the atoms at the grain boundary dissolve at a greater rate than those within grains. this is because the atoms at the boundary : Have a higher state of energy
Etchant is an acid or corrosive that is used to etch. Etching is traditionally the process of cutting into the unprotected parts of a metal surface with a strong acid or mordant to create an intaglio design in the metal.
A grain boundary in materials science is the interface between two grains, or crystallites, in a polycrystalline material. Grain boundaries are 2D defects in the crystal structure that tend to reduce the material's electrical and thermal conductivity.
Most grain boundaries are preferred sites for the initiation of corrosion and the precipitation of new phases from the solid. Grain boundaries, on the other hand, disturb the movement of dislocations through a material, so limiting crystallite size is a pervasive way to improve a material's strength.
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Students in a high school Marine Science class are learning about the scientific process. Four students were asked to write a testable prediction about deep-sea vents found in the ocean. Their responses are shown in the chart. Student Response Jin Deep-sea vents are too deep. Elizabeth Deep-sea vents are more interesting than caves. Carly Interest in deep-sea vents will decrease in the future. Raymond Ocean surface temperatures are warmer than water at deep-sea vents. Which student's prediction is the most testable using the scientific process? Jin Elizabeth Carly
The predication that is testable here is that of Raymond. Option D
What is a testable predication?We have to keep it at the back of our minds that science deals with data that is testable. In other words, science is an empirical discipline. What we mean by this is that we must be able to get at knowledge by testing the data that we have in controlled experiments.
Now, if we look at the responses of the students, we can see that the only one that has to do with something that we can test is the one that said that Ocean surface temperatures are warmer than water at deep-sea vents.
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Calculate the maximum wavelength of light capable of dissociating the f–f bond in one molecule of fluorine if the bond energy, or bond dissociation energy, is 157 kj/mol.
The calculated maximum wavelength is 495 nm
The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy. The link between silicon and fluorine, which was previously discussed, is discovered to be the strongest chemical bond. The initial silicon-fluorine bond in a silicon tetrafluoride molecule requires 166 kcal/mol of bond dissociation energy to be broken.
ΔH=+240 kJ/mol
E=242×103/6.022×1023
=4.0186×10−19 J
Now I use the Planck Expression:
E=hf=hc/λ
∴λ=hc
Eλ=6.63×10−34×3×108/4.0186×10-19 m
λ=4.949×10−7 m
λ=495 nm.
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a student cut 1200 pieces of copper wire, each weighing 1.769 grams. calculate the total mass of the pieces of copper to the correct number of significant figures.
a. 2122.8
b. 2120
c. 2122.800
d. 2100
e. 2123
Tο the cοrrect number οf significant figures, the answer wοuld be 2122.800 .
What is Mass ?Mass is a dimensiοnless quantity representing the amοunt οf matter in a particle οr οbject. The standard unit οf mass in the Internatiοnal System (SI) is the kilοgram (kg).
Mass is measured by determining the extent tο which a particle οr οbject resists a change in its directiοn οr speed when a fοrce is applied. Isaac Newtοn stated: A statiοnary mass remains statiοnary, and a mass in mοtiοn at a cοnstant speed and in a cοnstant directiοn maintains that state οf mοtiοn, unless acted οn by an οutside fοrce.
Fοr a given applied fοrce, large masses are accelerated tο a small extent, and small masses are accelerated tο a large extent.
Tο calculate the tοtal mass οf the cοpper wire pieces, we can multiply the number οf pieces by the mass οf each piece.
Number οf pieces: 1200
Mass οf each piece: 1.769 grams
Tοtal mass = Number οf pieces × Mass οf each piece
Tοtal mass = 1200 × 1.769 grams
Tοtal mass = 2122.8 grams
Tο the cοrrect number οf significant figures, the answer wοuld be:
c. 2122.800
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a student wants to prepare 0.13 m nano3 for a lab experiment in 250-ml volumetric flask. how many grams of nano3 need to be weighted out to dissolve in the volumetric flask?
In order to prepare 0.13 m nano3 for a lab experiment in a 250-ml volumetric flask, a student needs to weigh out 2.76gof nano3 to dissolve in the flask.
A form of laboratory glassware used to produce solutions is a volumetric flask. A volumetric flask is a bulb with a flat bottom and an extended neck that is calibrated to retain a specific volume at a mark on the neck. The flask can also be referred to as a graduated flask. The volume of the NaNO3 solution is 250 mL, and its molarity is 0.13 M. 250 mL of 0.15 M NaNO3 is calculated as (250/1000)L * (0.13 mol/L) = 0.0325 mol. Weight of 0.0375 mol is required since the molar mass of NaNO3 is 85 g/mol. 2.76g of NaNO3 are equal to 0.0325 mol*(85 g/mol). It is necessary to weigh 2.76 g of NaNO3.
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Experiments were performed for the reaction: D + 2 G → L. Use the data to determine the orders of each of the reactants.
Experiment initial conc of D initial conc of G initial rate
1 0.025 3.50 0.00480
2 0.050 3.50 0.0192
3 1.50 0.020 0.0986
4 1.50 0.080 0.394
Based on these data the order with respect to the concentration of D is and the order with respect to the concentration of G i
Answer:
The order of the reaction with respect to D is 2, and the order with respect to G is 1.
Explanation:
To determine the order of a reaction with respect to each reactant, we look at how changing the concentration of a reactant changes the rate of the reaction.
Looking at the initial concentrations and rates for D in experiments 1 and 2, when the concentration of D is doubled (from 0.025 to 0.050), the rate of reaction quadruples (from 0.00480 to 0.0192). This indicates that the order of the reaction with respect to D is 2, because the rate of reaction changes by the square of the change in concentration.
Next, we look at the initial concentrations and rates for G in experiments 3 and 4. In these experiments, when the concentration of G is quadrupled (from 0.020 to 0.080), the rate of the reaction also quadruples (from 0.0986 to 0.394). This indicates that the order of the reaction with respect to G is 1, because the rate of reaction changes directly with the change in concentration.
So, the order of the reaction with respect to D is 2, and the order with respect to G is 1.
what is the valence configuration of potassium
Answer:
Explanation:
Ground state electron configuration of potassium (K) is 1s2 2s2 2p6 3s2 3p6 4s1. The valency of the element is determined by electron configuration in the excited state. This electron configuration shows that the last shell of the potassium atom has an unpaired electron (4s1). So the valency of potassium is 1.
What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of Solid = 2.092 J/g°CHeat Capacity of Liquid = 4.184 J/g°CT Fusion = 0.00 °CΔH Fusion = 6.01 kJ/mol
Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 37.88 kJ.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heatSensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heatLatent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
25.60 °C to 0 °CFirst of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.
So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c= Heat Capacity of Liquid= 4.184 \(\frac{J}{gC}\)m= 185.5 gΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °CReplacing:
Q1= 4.184 \(\frac{J}{gC}\)× 185.5 g× (- 25.6 °C)
Solving:
Q1= -19,868.98 J
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 185.5 grams× \(\frac{1mol}{18 grams}\)= 10.30 moles, where 18 \(\frac{g}{mol}\) is the molar mass of water, that is, the amount of mass that a substance contains in one mole.
ΔHfus= 6.01 \(\frac{kJ}{mol}\)
Replacing:
Q2= 10.30 moles×6.01 \(\frac{kJ}{mol}\)
Solving:
Q2=61.903 kJ= 61,903 J
0 °C to -10.70 °CSimilar to sensible heat previously calculated, you know:
c = Heat Capacity of Solid = 2.092 \(\frac{J}{gC}\)m= 185.5 gΔT= Tfinal - Tinitial= -10.70 °C - 0 °C= -10.70 °CReplacing:
Q3= 2.092 \(\frac{J}{gC}\) × 185.5 g× (-10.70) °C
Solving:
Q3= -4,152.3062 J
Total heat requiredThe total heat required is calculated as:
Total heat required= Q1 + Q2 +Q3
Total heat required=-19,868.98 J + 61,903 J -4,152.3062 J
Total heat required= 37,881.7138 J= 37.8817138 kJ= 37.88 kJ
In summary, the amount of heat required is 37.88 kJ.
Learn more about calorimetry:
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If someone takes a material that looks pure, and then they do something to it that results in two separate materials, how can they know if they originally had a pure-looking mixture of two things that they simply separated into its parts, or if they originally had a pure material that was a compound that was chemically broken down into new compounds or elements?
Answer:
In order to determine whether the original material was a uniform/pure-looking mixture or a chemical compound broken into two new compounds, the following points must be noted;
1. If the two new materials are separated by physical means without any chemical change occurring, the original material is a pure-looking mixture, but if a chemical reaction was involved in separating the material, then it is a compound.
2. If the individual properties of properties of the constituents were retained in the original material, the substance is a mixture, but if the properties of the constituents differed entirely from that of the material, then the material is a compound.
3. If the constituents of the material are not present in a fixed ratio, the material is a mixture but if they are present in a fixed ratio, the material is a compound.
Explanation:
When a substance is being separated into its components, the nature of the substance can be determined by the components obtained.
Matter can be classified into pure substances and mixtures.
Pure substances include elements and compounds which have distinct chemical properties, whereas mixture are composed of two or more constituents physically joined together.
In order to determine whether the original material was a uniform/pure-looking mixture or a chemical compound broken into two new compounds, the following points must be noted;
1. If the two new materials are separated by physical means without any chemical change occurring, the original material is a pure-looking mixture, if the a chemical reaction was involved in separating the material, then it is a compound.
For example, a sugar and water mixture can be easily separated by evaporation and crystallization to obtain sugar and water respectively, but water which is composed of the elements hydrogen and oxygen cannot be separated by any physical means but by means of a chemical reaction, electrolysis.
2. If the individual properties of properties of the constituents were retained in the original material, the substance is a mixture, but if the properties of the constituents differed entirely from that of the material, then the material is a compound.
For example, a pure-looking mixture of sugar and water has the sweet taste of sugar and the liquid properties of water. However, water, a compound composed of hydrogen and oxygen which are gases, is a liquid and gas properties entirely different from either two.
3. If the constituents of the material are not present in a fixed ratio, the material is a mixture but if they are present in a fixed ratio, the material is a compound.
For example, sugar and water can be mixed together in any ratio to produce a sugar solution, but hydrogen and oxygen are always in a fixed ratio of 2:1 in water