How many grams of cu would have to react to produce 89. 5 grams of ag.

One method that may be used to replace traditional damming is the use of sub-surface dams to prevent the environmental consequences of dams while still harnessing the flowing water.

Therefore, we can confirm that the building of a sub-surface dam would result in less water being lost to evaporation, as well as the ecosystem benefits of not completely stopping the flow of water the way a traditional dam does.

To learn more about dams visit:

https://brainly.com/question/6592407?referrer=searchResults

Answer:

33,666

Explanation:

is the dictionary definition of a word.

is the feeling or idea associated with a word.

The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

Learn more about chemical equations,here:

https://brainly.com/question/19626681

#SPJ1

Answer:

hope this helps

Explanation:

it has to do with crystallization in the wax. When solid, the long alkyl chains align and crystallize, and these crystallites scatter light which leads to higher opacity. When heated, the crystallites melt, and the resulting amorphous liquid no longer scatters light.

Answer: A volume of .5650 what? And what unit will be considered?

The molecular formula of the unknown compound is C2H2O2.

To determine the molecular formula of the unknown compound, we need to calculate the empirical formula first and then find the multiple of its subscripts to obtain the molecular formula.

Given:

Percentage of carbon = 40.0%

Percentage of hydrogen = 6.7%

Percentage of oxygen = 53.3%

Molecular mass = 60.0 g/mol

Step 1: Convert the percentages to grams.

Assuming we have 100 grams of the compound:

Mass of carbon = 40.0 g

Mass of hydrogen = 6.7 g

Mass of oxygen = 53.3 g

Step 2: Convert the masses to moles using the molar masses of the elements.

Molar mass of carbon = 12.01 g/mol

Molar mass of hydrogen = 1.008 g/mol

Molar mass of oxygen = 16.00 g/mol

Number of moles of carbon = Mass of carbon / Molar mass of carbon

= 40.0 g / 12.01 g/mol

= 3.332 mol

Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen

= 6.7 g / 1.008 g/mol

= 6.648 mol

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen

= 53.3 g / 16.00 g/mol

= 3.331 mol

Step 3: Determine the empirical formula by dividing the moles by the smallest value.

Dividing the moles of carbon, hydrogen, and oxygen by 3.331 gives approximately 1 for each element.

So, the empirical formula of the compound is CHO.

Step 4: Determine the multiple of the subscripts to obtain the molecular formula.

To find the multiple, we divide the molecular mass by the empirical formula mass.

Molecular mass = 60.0 g/mol

Empirical formula mass = (12.01 g/mol) + (1.008 g/mol) + (16.00 g/mol) = 29.018 g/mol

Multiple = Molecular mass / Empirical formula mass

= 60.0 g/mol / 29.018 g/mol

= 2.07

Rounding to the nearest whole number, we get 2.

Therefore, the molecular formula of the unknown compound is C2H2O2.

learn more about molecular here

https://brainly.com/question/30640129

#SPJ11

Answer: I believe the answer is surface tension :)

The rate of dissolution can be increased by increasing the surface area, increasing the temperature, and agitating the solution.

There are several factors that can affect the rate of dissolution, which is the process of a solute dissolving in a solvent. One of the ways to increase the rate of dissolution is by increasing the surface area of the solute. When the solute is broken down into smaller particles or crushed into a fine powder, it exposes more surface area to the solvent, allowing for a faster interaction and dissolution.

Another factor that affects the rate of dissolution is the temperature. Generally, as the temperature increases, the rate of dissolution also increases. This is because higher temperatures provide more energy to the molecules, increasing their kinetic energy and promoting faster molecular motion. This enhanced motion leads to more collisions between the solute and solvent particles, facilitating the dissolution process.

Agitating the solution, such as stirring or shaking it, can also increase the rate of dissolution. By agitating the solution, it helps in maintaining a uniform distribution of the solute particles and prevents the formation of stagnant regions around the solute. This promotes the contact between the solute and solvent, enabling a faster dissolution process.

While increasing the size, freezing the solvent, and solidifying the solute may have some impact on the dissolution process, they do not directly increase the rate of dissolution. Increasing the size of the solute without increasing the surface area would actually decrease the rate of dissolution. Freezing the solvent and solidifying the solute may slow down or inhibit the dissolution process altogether, as lower temperatures reduce the kinetic energy and mobility of the solute and solvent particles.

To learn more about dissolution refer:

https://brainly.com/question/16818744

#SPJ11

Answer:NH4, because nitrogen needs four electrons, and each hydrogen needs one electron.

Explanation:

The results illustrate the law of multiple proportions since the oxygen atoms in A and B are in simple multiple ratios.

The formula of the oxides is SO₃ and SO₂ respectively.

Mass of sulfur in A = 3.50 g

Moles of sulfur in A = 3.50/32

Moles of sulfur in A = 0.11 moles

Mass of oxygen in A = 6.05 g

Moles of oxygen in A = 6.05/16

Moles of oxygen in A = 0.38

The mole ratio of sulfur to oxygen = 0.11 : 0.38

The mole ratio of sulfur to oxygen = 1 : 3

The formula of oxide = SO₃

Mass of sulfur in B = 2.80 g

Moles of sulfur in B = 2.80/32

Moles of sulfur in B = 0.088 moles

Mass of oxygen in B = 2.80 g

Moles of oxygen in B = 2.80/16

Moles of oxygen in B = 0.175

The mole ratio of sulfur to oxygen = 0.088 : 0.175

The mole ratio of sulfur to oxygen = 1 : 2

The formula of oxide = SO₂

The oxygen atoms in A and B are in simple multiple ratio.

Learn more about the law of multiple proportions at: https://brainly.com/question/2624012

#SPJ1

The idea is to foretell the formation of a carbonyl compound by the reaction between alcohol and too much pyridinium chlorochromate. An oxidizing agent called pyridinium chlorochromate converts the alcohol group into the 1carbonyl group.

The carbonyl molecule that results from the reaction will depend on the reactant's OH group. Pyridinium chlorochromate [PCC] converts primary OH to aldehydes, whereas it converts secondary OH to ketones, and oxidation of tertiary OH has little effect. Alcohols and pyridinium chlorochromate [PCC] react to create a carbonyl molecule.

From primary alcohols to aldehydes and from secondary alcohols to ketones, pyridinium chlorochromate oxidizes alcohols one step up the oxidation ladder. pyridinium chlorochromate will not oxidize aldehydes to carboxylic acids, in contrast to chromic acid. Comparable to Pyridine (the Collins reagent) and CrO3 will both oxidize primary alcohols to aldehydes. Here are two instances of pyridinium chlorochromate being used.

To learn more about pyridinium chlorochromate please visit -
https://brainly.com/question/14019316
#SPJ4

The pH of the 4.06 mg/L Ba(OH)₂ solution is approximately 12.68.

To calculate the pH of a barium hydroxide (Ba(OH)₂) solution, we need to consider the hydrolysis of the compound. However, Ba(OH)₂ is a strong base and will dissociate completely in water. Therefore, we do not need to consider the hydrolysis reaction.

Barium hydroxide dissociates into barium ions (Ba²⁺) and hydroxide ions (OH⁻) in a 1:2 molar ratio.

Given the concentration of the Ba(OH)₂ solution as 4.06 mg/L, we need to convert this to molarity (mol/L) before proceeding with the pH calculation.

First, let's calculate the molar mass of Ba(OH)₂:

Ba = 137.33 g/mol

O = 16.00 g/mol

H = 1.01 g/mol

Molar mass of Ba(OH)₂ = (137.33 g/mol) + 2[(1.01 g/mol) + (16.00 g/mol)] = 171.34 g/mol

Next, let's convert the concentration from mg/L to mol/L:

Concentration (mol/L) = (4.06 mg/L) / (171.34 g/mol) = 0.0237 mol/L

Since Ba(OH)₂ dissociates into two hydroxide ions (OH-) per formula unit, the concentration of hydroxide ions in the solution is twice the concentration of Ba(OH)₂:

Concentration of OH- (mol/L) = 2 * 0.0237 mol/L = 0.0474 mol/L

To calculate the pOH, we take the negative logarithm (base 10) of the hydroxide ion concentration:

pOH = -log10(0.0474) ≈ 1.32

Finally, we can determine the pH using the equation:

pH = 14 - pOH

pH = 14 - 1.32 ≈ 12.68

Learn more about pH at https://brainly.com/question/172153

#SPJ11

The main difference in the degree of electron delocalization between a 4-dimethylamino-4'nitrostilbene and a 4-dimethylamino-3'-nitrostilbene is their resonance structure.

In 4-dimethylamino-4'-nitrostilbene, the electron-donating dimethylamino group and electron-withdrawing nitro group are located on opposite ends of the stilbene molecule, both para to the central double bond. This allows for greater resonance stabilization and extended electron delocalization across the entire molecule.

In contrast, in 4-dimethylamino-3'-nitrostilbene, the nitro group is meta to the central double bond. This arrangement disrupts the resonance stabilization, resulting in reduced electron delocalization.

So, the main difference is that the 4-dimethylamino-4'-nitrostilbene has greater electron delocalization due to its para positioning, while the 4-dimethylamino-3'-nitrostilbene has reduced electron delocalization due to its meta positioning.

To know more about electron delocalization:

https://brainly.com/question/28039656

#SPJ11

Using dimensional analysis with the labels of atoms or molecules, we found that there are 4.94 * 10²⁴ atoms of P, 7.41 * 10²⁴ atoms of Si, and 5.60 * 10²³ atoms of Mn in the given moles.

Here's a step-by-step explanation for each problem:
1.) 8.21 mol of P:
Step 1: Identify the conversion factor. In this case, we will use the Avogadro's number, which is 6.022 * 10²³ atoms/mol.
Step 2: Apply dimensional analysis using the given moles of P and the conversion factor.
(8.21 mol P) * ( 6.022 * 10²³ atoms/mol) = 4.94 * 10²⁴ atoms of P.
2.) 12.3 mol of Si:
Step 1: Identify the conversion factor. In this case, we will use the Avogadro's number, which is  6.022 * 10²³atoms/mol.
Step 2: Apply dimensional analysis using the given moles of Si and the conversion factor.
(12.3 mol Si) * ( 6.022 * 10²³ atoms/mol) = 7.41 * 10²⁴ atoms of Si.
3.) 0.93 mol of Mn:
Step 1: Identify the conversion factor. In this case, we will use the Avogadro's number, which is  6.022 * 10²³ atoms/mol.
Step 2: Apply dimensional analysis using the given moles of Mn and the conversion factor.
(0.93 mol Mn) * ( 6.022 * 10²³ atoms/mol) = 5.60 * 10²³ atoms of Mn.

learn more about Avogadro's number Refer: https://brainly.com/question/28812626

#SPJ11

If the presence of molecule a decreases the reaction rate and increasing substrate concentration does not overcome the inhibition, it is likely a noncompetitive or uncompetitive inhibitor.

To determine the type of inhibitor molecule a is, we need to first analyze the steady-state kinetic data. If the presence of molecule a decreases the rate of the enzyme-catalyzed reaction, it is likely an inhibitor.
Next, we need to look at the effect of increasing concentrations of substrate on the reaction rate in the presence and absence of molecule a. If molecule a is a competitive inhibitor, increasing substrate concentration can overcome the inhibition because the inhibitor and substrate are competing for the same active site on the enzyme. Therefore, the reaction rate will increase with increasing substrate concentration in the presence of molecule a.
On the other hand, if molecule a is a noncompetitive or uncompetitive inhibitor, increasing substrate concentration will not overcome the inhibition because the inhibitor binds to a different site on the enzyme than the substrate. Therefore, the reaction rate will not increase with increasing substrate concentration in the presence of molecule a.
Overall, if the presence of molecule a decreases the reaction rate and increasing substrate concentration does not overcome the inhibition, it is likely a noncompetitive or uncompetitive inhibitor. However, if increasing substrate concentration does overcome the inhibition, it is likely a competitive inhibitor.

For more such questions on reaction rate , Visit:

https://brainly.com/question/24795637

#SPJ11

As a substance moves across line X from left to right on the Methanol phase diagram, it undergoes a change in state from solid to liquid.

The above change in state is due to an increase in temperature and pressure, which causes the intermolecular forces between the Methanol molecules to weaken, allowing them to move more freely and transition from a solid state to a liquid state. Therefore, the intermolecular forces between the molecules are decreasing as the substance moves across line X.

On the other hand, as a substance changes across line Z from the right to the left, it undergoes a change in state from gas to liquid. This change in state is due to a decrease in temperature and pressure, which causes the intermolecular forces between the Methanol molecules to strengthen, resulting in the gas molecules losing energy and transitioning to a liquid state. Therefore, the intermolecular forces between the molecules are increasing as the substance moves across line Z.

In summary, as a substance moves across line X from left to right, the intermolecular forces between the molecules are decreasing, while as a substance moves across line Z from right to left, the intermolecular forces between the molecules are increasing.

Read more about intermolecular forces here:

https://brainly.com/question/2193457

#SPJ1

See full question below



ANALYZING DATA

Analyze Phase Diagrams

A phase diagram shows, at any given temperature and pressure, the state of a certain substance, and the conditions where different states can be in equilibrium. The triple point, shown at where the three lines X, Y, and Z meet, is the temperature and pressure where solid, liquid, and gas can coexist. The critical point shows the minimum temperature and pressure where a substance can exist as both a liquid and gas. It is the point where it becomes a supercritical fluid. Supercritical fluids are used for industrial processes, including an alternative way to dye fabrics.

Methanol Phase Diagram

Pressure (atm)

80

Laqurd

Solid X

Y

1

Z

Gas

65

240

-97.65

-97.45

Temperature (°C)

sep interpret data explain what is happening to the intermolecular forces as a substance moves across line x from the left to the right. how does this compare to the molecular behavior as a substance changes across line z from the right to the left?

Answer:

True or T

Explanation:

Is the correct answer please make me brainliest

Answer:

merits of mendeleev periodic table are:

demerits of mendeleev periodic table

hope these points helped you

need more points then comment it .

Answer:

157 grams magnesium chloride

Explanation:

1.  We must first find the molar mass (g/mole) of magnesium chloride.  The molecular formula is MgCl2.

Add the elemental atromic weights for one molecule of the material:

1 Mg = 24.3

2 Cl = 2*(35.45) = 70.9

Total = 95.2 grams/mole

We can use this as a conversion factor by multiplying it times the moles we are asked to convert:  (1.65 moles MgCl2)*(95.2 grams/mole MgCl2).

The moles cancel, leaving us with 157 grams of magnesium chloride.

Answer:

Formic acid H. COOH

Acetic acid CH3.COOH

Propionic acid CH3 . CH1 . COOH

Butyric acid CH3 . CH1 . CH1 . COOH

Explanation:

Atmospheric sulfur compounds, C. originate primarily from natural sources.

In a compound, the atoms of the elements are held together by chemical bonds, which can be either ionic or covalent. Compounds have a fixed ratio of elements, and their properties can be different from the properties of the individual elements that make them up.

Atmospheric sulfur compounds, such as sulfur dioxide (SO₂) and hydrogen sulfide (H₂S), can originate from both natural and anthropogenic (human) sources.

However, natural sources, such as volcanic eruptions, geothermal activity, and biological processes, are significant contributors to atmospheric sulfur compounds.

These compounds can undergo various reactions in the atmosphere, leading to the formation of sulfuric acid (H₂SO₄) and other sulfur-containing aerosols, which can contribute to acid precipitation.

Additionally, atmospheric sulfur compounds can exist in both gaseous and particulate forms, depending on their concentration, temperature, and other environmental factors.

To know more about compounds, click here:

https://brainly.com/question/14117795

#SPJ4

Answer:

Einstein also in 1905 mathematically proved the existence of atoms, and thus helped revolutionize all the sciences through the use of statistics and probability. Atomic theory says that any liquid is made up of molecules (invisible in 1905)

Explanation:

Answer:

The discoveries of Albert Einstein led to development in the understanding of the atom through the study of quantum mechanics and the electron cloud. In this model, there is still a nucleus with protons and neutrons. But unlike the Bohr model, the electrons exist in a cloud outside the nucleus, much like the fruit around the pit of a peach.

Explanation:

A very reactive metal is image D

A reactive metal is a metal that readily reacts with other substances in its environment, particularly with non-metals such as oxygen, chlorine, sulfur, and nitrogen. The reactivity of a metal depends on the ease with which it can lose electrons to form positive ions.  These metals are often used in chemical reactions because of their reactivity

The metal that has been shown in the image that is attached in option D is sodium which is known to loose electron easily hence it is a reactive metal.

Learn more about reactive metal:https://brainly.com/question/20570629

#SPJ1

Sodium (Na) and chlorine (Cl) are the largest dissolved components in ocean water due to the abundance of sodium and chloride ions in the Earth's crust and the continuous input of these elements into the oceans through various processes. Sodium is one of the most common elements in the Earth's crust, and chlorine is widely distributed in rocks, minerals, and salts.

Over millions of years, weathering of rocks, volcanic activity, and erosion release these elements into rivers and ultimately into the oceans. The combination of sodium and chlorine ions results in the formation of sodium chloride, which is commonly known as table salt and contributes to the salinity of seawater.

The most abundant dissolved gas in ocean water is carbon dioxide (CO2). Carbon dioxide dissolves in the surface waters of the ocean through gas exchange with the atmosphere. It plays a crucial role in regulating the pH of seawater and is an essential component of the carbon cycle. Carbon dioxide is involved in various biological and chemical processes in the ocean, including photosynthesis by marine plants and the formation of calcium carbonate shells by marine organisms. Additionally, the increase in atmospheric carbon dioxide due to human activities has led to ocean acidification, which is a significant concern for marine ecosystems.

To know more about Sodium (Na) and chlorine (Cl), click here, https://brainly.com/question/5319005

#SPJ11

Due to the fact that they combine to form the ionic compound sodium chloride (NaCl), also known as salt, sodium (Na) and chlorine (Cl) are the two most abundant dissolved elements in ocean water.

Thus, Salts are among the many dissolved compounds that water from rivers and streams transports into the ocean.

In particular, sodium and chloride ions have accumulated in the ocean throughout time, leading to the high concentration of these elements in seawater. Magnesium, calcium, potassium, and sulphate ions are among the other dissolved substances in ocean water.

Oxygen  is the dissolved gas that is most prevalent in ocean water.

Thus, Due to the fact that they combine to form the ionic compound sodium chloride (NaCl), also known as salt, sodium (Na) and chlorine (Cl) are the two most abundant dissolved elements in ocean water.

Learn more about Ocean, refer to the link:

https://brainly.com/question/12738467

#SPJ4

The monomers combine with each other via covalent bonds to form larger molecules known as polymers. In doing so, monomers release water molecules as byproducts.

The pH of kalkwasser can be determined using the concentration of the solution. In this case, the concentration of the solution is given as 0.0225 M Ca(OH)2  the pH of the kalkwasser solution with a concentration.

To find the pH, we need to consider the dissociation of Ca(OH)2 in water. Ca(OH)2 dissociates into one Ca2+ ion and two OH- ions. The OH- ions make the solution basic, so we need to calculate the pOH and then convert it to pH.

First, let's determine the concentration of OH- ions in the solution. Since Ca(OH)2 dissociates into two OH- ions, the concentration of OH- ions will be twice the concentration of Ca(OH)2. Therefore, the concentration of OH- ions is 2 * 0.0225 M = 0.045 M.

To know more about kalkwasser visit :-

https://brainly.com/question/33007630

#SPJ11

The balanced equations are as follows:

1.) 2K(s) + 2Al³⁺(aq) → 2Al(s) + 2K⁺(aq)

2.) 6Cr(s) + 14H+(aq) + 6Co²⁺(aq) → 6Cr³⁺(aq) + 6Co(s) + 7H₂O(l)

3.) 8IO₃⁻(aq) + N₂H₄(g) + 10H⁺(aq) → 5I⁻(aq) + N₂(g) + 12H₂O(l)

1.) In this redox reaction, potassium (K) is oxidized to potassium ions (K⁺) while aluminum ions (Al³⁺) are reduced to aluminum (Al). The balanced equation is obtained by ensuring that the number of electrons lost in oxidation (K) is equal to the number of electrons gained in reduction (Al).

2.) This reaction involves the oxidation of chromium (Cr) to chromium ions (Cr³⁺) and the reduction of cobalt ions (Co²⁺) to cobalt (Co). To balance the equation, it is necessary to balance the atoms and the charges, making sure that the number of electrons lost in oxidation (Cr) is equal to the number of electrons gained in reduction (Co).

3.) In this reaction, iodate ions (IO³⁻) are reduced to iodide ions (I⁻) while nitrogen hydrazine (N₂H₄) is oxidized to nitrogen gas (N₂). Balancing the equation involves ensuring that the number of electrons lost in oxidation (N₂H₄) is equal to the number of electrons gained in reduction (IO₃⁻).

Phases are indicated in parentheses, where (s) represents solid, (aq) represents aqueous, (g) represents gas, and (l) represents liquid.

To learn more about redox reactions, here

https://brainly.com/question/28300253

#SPJ4