How many grams are in 0.500 liters of SBr6?

Please show work if possible or say how to do it

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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The first half-reaction is the oxidation of Cr2O7^2– to Cr^3+ and the second half-reaction is the reduction of I^– to IO3^–. When combined, the overall reaction is Cr2O7^2– + I^– → Cr^3+ + IO3^–.

The electrolytic cell consists of two electrodes, one anode and one cathode, both of which are immersed in an electrolyte solution. At the anode, the Cr2O7^2– ions are oxidized to Cr^3+ ions, releasing electrons into the external circuit.

At the cathode, the I^– ions are reduced to IO3^– ions, and the electrons from the external circuit are used to drive the reaction. The electrolyte solution must contain both Cr2O7^2– and I^– ions in order to facilitate the transfer of electrons between the electrodes.

The overall reaction is driven by the potential difference between the anode and the cathode, which is created by the flow of electrons through the external circuit.

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answer

Explanation:

Carbon with 4 single bonds is sp3. If it has a double bond it is sp2. If there is a triple bond it is sp hybridization

Type #1 Flame symbols are among the WHMIS emblems.

Type 2: Symbols with a flame above a circle.

Exploding bomb symbols are of type 3.

Compressed gas symbols are of type 4.

Corrosion symbols are type #5.

Skull and water the water symbols are type #6.

Exclamation mark symbols are type #7.

Health hazard symbols are type #8.

Because workplaces require a defined technique to detect hazardous items, WHMIS labels are crucial.

The national ’s hazard standard for Canada is the Health And Safety At work System (WHMIS). Hazard categorization, cautionary container labeling, the distribution of safety data sheets, and worker information and training programs are the system's main components.

The U.S. Ohs Hazard Identification Standard and WHMIS are quite similar.

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The vapor pressure of methanol at 40°C is 0.234 atm.

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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Answer:

\(1.53~moles~CH_2Cl_2\).

Explanation:

We can start with the reaction, if we know the formula for each compound:

-) Methane: \(CH_4\)

-) Carbon tetrachloride: \(CCl_4\)

-) Dichloromethane: \(CH_2Cl_2\)

With this in mind, we can write the reaction:

\(CH_4~+~CCl_4~->~CH_2Cl_2\)

Now, we can balance the reaction:

\(CH_4~+~CCl_4~->~2CH_2Cl_2\)

After this, we have 2 carbon atoms on each side, 4 hydrogen atom on each side, and 4 chlorine atoms on each side.

If we want to know how many moles of \(CH_2Cl_2\) would be produced with .766 moles of \(CH_4\), we have to check the balanced reaction and use the molar ratio. In this case, the molar ratio is 1 mol \(CH_4\) will produce 2 moles of \(CH_2Cl_2\) (1:2). So:

\(0.766~moles~CH_4\frac{2~moles~CH_2Cl_2}{1~mol~CH_4}=1.53~moles~CH_2Cl_2\)

We wil have \(1.53~moles~CH_2Cl_2\).

I hope it helps!

The concept half life is used here to determine the mass of 'A' remaining after 0.731 min. The rate constant of a reaction is defined as the rate of the reaction when the molar concentration of each of the reactants is unity. The mass of A remaining is 5.163 g.

The half life period of a reaction is defined as the time in which the concentration of a reactant is reduced to half of its initial concentration. The expression for half life period of a first order reaction is:

\(t _{1} /_{2} = 0.693 / k\)

k - rate constant

k = 0.693 / 0.0459 = 15.098 s

Divide by 60 to convert half life into minutes.

15.098 s = 0.251 minutes

The number of half lives that have past is:

0.731 min / 0.251 min = 2.912 ≈ 3

Initial mass / number of half lives = 15.49 / 3 = 5.163 g

Thus the mass of A remaining after 0.731 min is 5.163 g.

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Our current understanding of the atom is based on Dalton's early 19th-century idea of atomism, which was developed through meteorological investigations. John Dalton is well recognised for developing the atomism hypothesis.

When British chemist John Dalton realised that compounds usually had whole number ratios of atoms, he provided the first modern proof for the existence of atoms. Because of this, it's H2O rather than H20. A novel state of matter has been demonstrated by scientists: an electron circles a nucleus at a considerable distance while being bonded to several other atoms inside the orbit. The Bose-Einstein condensate's electron (blue) orbits the nucleus (red), and the orbit encompasses a large number of other atoms (green). Chemistry's fundamental building component is an atom. It is the lowest fraction of substance into which electrically charged particles cannot be released.

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31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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The limiting reactant is Al and 4.48 g of the product is obtained

The concept of a limiting reactant is important because the amount of product that can be formed is determined by the amount of limiting reactant available, even if there is excess of the other reactants. The reactant that is not completely consumed in the reaction is called the excess reactant.

The reaction equation is;

Fe2O3 + 2AI → Al2O3 + 2 Fe

We know that;

Number of moles of Fe2O3  = 8.00g /160 g/mol

= 0.05 moles

Number of moles of Al =  2.16g/27 g/mol

= 0.08 moles

If 1 mole of Fe2O3  reacts with 2 moles of Al

0.05 moles of Fe2O3  reacts with 0.05 moles * 2/1

= 0.1 mole

Hence Al is the limiting reactant

Now we have that;

2 mole of Al produces 2 moles of Fe

Thus we would have that;

Mass of Fe produced = 0.08 moles * 56 g/mol

= 4.48 g

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Answer:

It is important for us to be able to make hydrogen from seawater instead of pure water for several reasons:

   Abundance: Seawater is abundant and widely available, making it a more sustainable and renewable source of hydrogen compared to pure water, which is often in limited supply.

   Cost-effective: Seawater is a low-cost source of hydrogen, as it does not require the use of fresh water, which can be scarce and expensive in many regions.

   Energy efficient: Seawater contains dissolved salts and minerals, which can be used as catalysts to speed up the water splitting process and make it more energy efficient.

   Environmental impact: Using seawater as a source of hydrogen instead of pure water reduces the amount of freshwater that is used, conserving this precious resource and minimizing the environmental impact of water extraction and transportation.

   Versatility: Seawater can be used as feedstock for various hydrogen production methods such as electrolysis, thermolysis, photocatalysis, and biotechnology.

In summary, being able to make hydrogen from seawater is crucial to address the growing energy demand while also preserving fresh water resources, and also to make hydrogen production more sustainable and cost-effective.

Explanation:

hope this helps

The answers for following multiple question are given below.

(a)The equilibrium pressure of NH3 gas would remain unaffected. KP = (PNH3)(PH2S). Thus the amount of solid NH4HS present usually does not affect the equilibrium of the reaction.

(b) Generally, the equilibrium pressure of NH3 gas would decrease. In order for the pressure equilibrium to be constant, KP, to remain constant, the equilibrium pressure of NH3 must decrease when the pressure of H2S is increased. KP = (PNH3)(PH2S). (The complete explanation is based on the LeChatelier’s principle is also acceptable.)

(c) The mass of NH4HS increases because a decrease in volume causes the pressure of each gas to increase. To maintain the value of the pressure equilibrium constant, Kp, the pressure of each of the gases must decrease. The decrease in pressure is realized by the formation of more solid NH4HS. Kp = (PNH3)(PH2S). (A complete explanation based on LeChatelier’s principle is also acceptable.)

(d) Basically, the mass of NH4HS decreases because the endothermic reaction absorbs heat and goes nearer to completion (to the right) as the temperature increases.

Generally, for any chemical reaction, the equilibrium constant can be defined as the ratio between the amount of reactant and the amount of product which is used to determine chemical behaviour. At equilibrium, for any reaction, Rate of the forward reaction = Rate of the backward reaction.

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Answer:

190.2 grams

Explanation:

each arrow points to the amount it weighs, just add it all up

Answer:

190g

Explanation:

Using the scale, you can see that both arrows are over 100 and 90. You simply add these integers together to get your answer. 100 + 90 = 190. But don't forgot your units! If you don't add the g, the answer may be considered wrong. Good luck!

Answer:

the answer is all of them, so the letter choice a><

Explanation:

Given elements:

Cl, Ne, Ge, Ca and Se

Chemistry -> The periodic table -> Periodic Trends: Ionization Energy

The ionization energy refers to the amount of energy needed to remove an electron from the valence shell of an atom.

Ionization energy increases as we go across a period and increases as we go up a group. This tred happens due to atomic radius, atomic number, electronegativy, among other properties.

Let's separate the period and group of each atom so we can predict the order of ionization energy.

Cl: Period 3 Group 17

Ne: Period 2 Group 18

Ge: Period 4 Group 14

Ca: Period 4 Group 2

Se: Period 4 Group 16

From the trend, we know that the atom that is higher and to the far right in the periodic table will have the greatest ionization energy. So, Ne that is in the 2nd period and 18th group will have the highest ionization energy.

Followed by Cl, since it is clores to Ne than the rest.

Then among the elements in the 4th period, we just have to analyse by their group. Se is farther to the right than Ge that is farther to the right than Ca.

In conclusion, the order by increasing ionization energy will be:

Final answer:

Ca < Ge < Se < Cl < Ne

The enthalpy diagram for the formation of C₆H₁₂O₆ is shown in the image attached.

We know that the Hess law is the law that can be used to show the principle of the constant heat summation. The implication of this law is that the total heat that is involved in a number of the process would involves the summation of all the heats of the processes that we have.

In this case, we have the compound that has been formed in this case as  C₆H₁₂O₆. We can see that there were about three process that went on in the formation of the compound and we need to find the enthalpy of formation of the compound which is the summation of the enthalpies of of all the processes involved.

The enthalpy cycles are;

6 C(s) + 6 O₂(g) ⇒ 6 CO₂(g) ΔHc = 6*(-395) = - 2,370 kJ/mol

6 H₂(g) + 3 O₂(g) ⇒ 6 H₂O(l) ΔHc = 6*(-269.4) = -1,616. kJ/mol

6 CO₂(g) + 6 H₂O(l) ⇒ 6 O₂(g) + C₆H₁₂O₆(s) ΔHc = -1*(-2900) = 2900 kJ/mol

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Answer: The pressure exerted by the \(CO_2\) gas, in atm is 1.092

Explanation:

According to the ideal gas equation:'

\(PV=nRT\)

P = Pressure of the gas = ?

V= Volume of the gas  

T= Temperature of the gas = \(22.165^0C=(273+22.165)K=295.165K\)  (0°C = 273 K)

n= moles of gas =  \(\frac{\text {given mass}}{\text {Molar mass}}\)

R= Value of gas constant = 0.0821 Latm/K mol

\(P=\frac{mRT}{MV}\)       as \(Density=\frac{mass}{Volume}\)

\(P=\frac{dRT}{M}\)    where d is density

\(P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm\)

Thus  pressure exerted by the \(CO_2\) gas, in atm is 1.092

Answer:

1.4 g/cm3

Explanation:

Density = Mass/Volume

Mass = 21g

Volume = 15cm3

Density = 21/15 = 1.4

Answer:

all living things need water. no water, no life.

The mass (in grams) of KNO₃ needed to prepare 554.49 mL of 4.85 M KNO₃ solution is 271.69 grams

First, we shall determine the mole of KNO₃. Details below:

Molarity = Mole / Volume

Cross multiply

Mole = molarity × volume

Mole of KNO₃ = 4.85 × 0.55449

Mole of KNO₃ = 2.69 moles

Finally, we shall determine the mass of KNO₃ needed. Details below:

Mass = Mole × molar mass

Mass of KNO₃ = 2.69 × 101

Mass of KNO₃ = 271.69 grams

Therefore, the mass of KNO₃ needed to prepare the solution is 271.69 grams

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This is a stoichiometry problem, where we have an initial amount of reactant and we need to find out how much of the product will we end up with, in order to do that we need to:

1. Set up the properly balanced equation, which the question already provided us

2 Mg + O2 -> 2 MgO

2. See how many moles of reactant there are in the given amount of grams, 5.85 grams, and the molar mass of the reactant is 32g/mol

32g = 1 mol

5.85g = x moles

x = 0.183 moles of O2 in 5.85 grams

3. Check the molar ratio between the two compounds, for O2 and MgO the molar ratio is 1:2, 1 mol of O2 for every 2 moles of MgO, therefore:

1 O2 = 2 MgO

0.183 O2 = x MgO

x = 2 * 0.183

x = 0.366 moles of MgO

4. Calculate how many grams will be equal to the number of moles that we found out, 0.366 moles and the molar mass of MgO, 40.30g/mol

40.30g = 1 mol

x grams = 0.366 moles

x = 0.366 * 40.30

x = 14.75 grams of MgO are produced from 5.85 grams of O2

The mass of the solid aluminum that forms are 192.73 grams

To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.

The balanced chemical equation is:

3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al

The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.

To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:

Mass = Volume × Density

Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g

Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:

Moles of magnesium = Mass of magnesium / Molar mass of magnesium

= 260.7 g / 24.31 g/mol

= 10.72 mol

According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:

Moles of aluminum = (2/3) × Moles of magnesium

= (2/3) × 10.72 mol

= 7.15 mol

Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):

Mass of aluminum = Moles of aluminum × Molar mass of aluminum

= 7.15 mol × 26.98 g/mol

= 192.73 g

Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.

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If you're attempting to synthesize 2 benzyl pentanoic acid from acetoacetic ester, keep in mind that you can do so fairly quickly by following these simplified instructions:

From its pungent free scent to its solid state at temperatures ranging from 118 120°C, acetoacetic ester (better known as ethyl acetoacetate) offers significant value for those working within organic synthesis.

As one of many potent ketones utilized by researchers around the globe its unique properties make it ideal for building complex molecules essential for modern medicine and more.

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Answer:

K2CO3 is potassium carbonate, a compound made up of: 2 atoms of Potassium. 1 atom of Carbon. 3 atoms of Oxygen.

Explanation:

Answer: pure water is homogeneous and pure substance.

Explanation: However, when a homogeneous substance consists of two or more different types of molecules uniformly intermingled with one another, then it’s called a homogeneous mixture. A mixture’s composition can vary, but a pure substance does not.

Answer:

True

Explanation:

since the gases and minerals dissolved in water are in the same state as water and they do not form separate layers