How many diseases are genetic?

Answer: The mesocyclone

Explanation: The unsaturated air, if moved upward, will be cooler than the surrounding air and it will sink. ... This convective action (that is, the circulation of air as a result of heat transfer) produces the huge clouds commonly associated with thunderstorms and tornadoes.

Hopes this help um pls mark me as brainliest

The signal that has a continuous change in amplitude and frequency is known as an analog signal. This type of signal is characterized by its ability to represent a range of values using a continuous waveform, as opposed to a digital signal which represents values discretely.

The amplitude of an analog signal refers to the height of the waveform at a given point in time, while the frequency refers to the number of cycles per second. In an analog signal, both the amplitude and frequency can change continuously, resulting in a signal that is constantly varying in both amplitude and frequency.
Examples of analog signals include sound waves, radio waves, and electrical signals. These signals are used in a wide variety of applications, from music and communication to industrial automation and medical imaging.
Overall, the continuous change in amplitude and frequency of analog signals allows for more precise and nuanced representation of data, making them an important tool in many fields.

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Ratio of distances of image and object respectively = ratios of heights of image and objects respectively

This implies

(1.7/600) = (x/1) ........ ( X is largeness of letter on retina)

x= 0.002833333 cm

What is retina?

The retina is the innermost, light-sensitive layer of eye tissue in most vertebrates and some mollusks. The optics of the eye create a focused two-dimensional image of the visual world on the retina. The retina processes that image within the retina, sending nerve impulses along the optic nerve to the visual cortex to produce vision. The retina functions in many ways similar to the film and image sensors in cameras.

The neural retina consists of several layers of neurons connected by synapses and supported by an outer layer of pigment epithelial cells. The main light-sensitive cells in the retina are photoreceptor cells, of which there are two types: rods and cones. Rods work primarily in low light and provide monochromatic vision. Cones function in bright environments, use different opsins to perceive color, and are responsible for sharp vision used for tasks such as reading. A third type of photosensitive cell, the photosensitive ganglion cell, is important in entrainment of circadian rhythms and reflex responses such as the pupillary light reflex.

Therefore, x= 0.002833333 cm

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If we pass light through two narrow slits. then a double-slit interference pattern will form.

When light is passed through two narrow slits, an interference pattern will be formed on a distant screen. This is known as the double-slit interference pattern.

The interference pattern is formed because the light passing through each slit interferes with the light passing through the other slit. The light waves can either reinforce or cancel each other out, depending on the phase relationship between them.

On the screen, there will be alternating bright and dark fringes, with the brightest fringes corresponding to constructive interference, where the waves are in phase, and the darkest fringes corresponding to destructive interference, where the waves are out of phase.

The pattern will have a series of bright bands, called interference maxima, where the bright fringes occur, separated by dark bands, called interference minima, where the dark fringes occur. The position of the maxima and minima will depend on the wavelength of the light, the distance between the slits, and the distance between the slits and the screen.

This interference pattern is a classic example of the wave nature of light, and it played an important role in the development of quantum mechanics.

Hence, when we pass the light through two narrow slits a double-split interference is formed.

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The approximately time that takes to stop the stunt driver once she hit the cushion is: 0.4 s

To solve this exercise, the formulas and procedures to be applied are:

Where:

Information about the problem:

Applying the force formula and isolating the acceleration, we get:

F = m * a

a = F/m

a = -2500 N /50kg

a = -2500 kg * m/s² / 50 kg

a = -50 m/s²

Applying the time formula we get:

t = (vf – vi) / a

t = (0 m/s – 20 m/s) / 50 m/s²

t = (– 20 m/s) / -50 m/s²

t = 0.4 s

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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Answer:

Condensation

Explanation:

Answer:

Condensation! Hope this helps!!!

Explanation:

Answer:

Explanation: The density of gas differentiates all the varieties of gas present in the atmosphere.

HYDROGEN- it is a lighter gas having a lesser density.

For example, a hydrogen balloon displaces the air around it thus making it rise.

CARBON DIOXIDE: It is a denser gas as it makes the balloon heavier than the air pressure around it thus making it sink.

I hope the explanation was helpful. :)

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

Answer:

The average velocity from 5 to 6 seconds is -27 m/s

Answer:

16.44 N

Explanation:

From the diagram attached,

we make use of cosine rule to calculate the resultant force

R² = P²+Q²-2PQcosα............................. Equation 1

Where R = resultant force

Given: P = 7 Newton, Q = 10 Newton, α = (180-30) = 150°

Substitute these values into equation 1

R² = 7²+10²-(2×7×10×cos150°)

R² = 49+100-140cos150°

R² = 149-140cos150°

R² = 149-140(-0.8660)

R² = 149+121.24

R² = 270.24

R = √(270.24)

R = 16.44 N

The correct option is C, When a conductor mounted on an insulating stand is charged and left for some time, the conductor eventually loses all its charges. This is because the charges on the conductor are neutralized by opposite charges from the surrounding air.

A conductor is a material that allows the flow of electric charge. Specifically, a conductor is a material in which some or all of the electrons in its atoms are free to move, allowing for the transfer of electric charge through the material. Metals, such as copper and aluminum, are good conductors because they have many free electrons that can move easily through the material when a voltage is applied. Other materials, such as carbon and some semiconductors, can also conduct electricity under certain conditions.

The ability of a material to conduct electricity is measured by its electrical conductivity, which is a property that describes how easily an electric charge can flow through the material. Conductors are essential components in many electrical devices and systems, including wires, circuits, and electronic components. The properties of conductors are important in understanding the behavior of electricity and the design of electrical systems.

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Complete Question:

When a conductor mounted on an insulating stand is charged and left for some time, the conductor eventually loses all its charges. This is because the

A. electric charges evaporate from the surface of the conductor

B. charges are connected to the earth

C. charges on the conductor are neutralized by opposite charges from the surrounding air

D. charges ionize the surrounding air

Answer:

Rust occurs when iron or its alloys, such as steel, corrode. The surface of a piece of iron will corrode first in the presence of oxygen and water.The process of rusting is a combustion reaction, similar to fire. Left in contact with oxygen, iron will react with the oxygen to form rust.

Hope this helps!!

Answer:

iron is oxidation reaction

Explanation:

it occurs when iron reacts with water and oxygen to form hydrated iron(iii) oxide

a. The faintest galaxies look redder because their stars are younger.

This prediction of the standard Big Bang theory has not been successfully verified by observations.

Option a is not a prediction of the standard Big Bang theory that has been successfully verified by observations. It refers to the idea that the faintest galaxies appear redder because their stars are younger.

However, the color of a galaxy is determined by several factors, including the age of its stars, the presence of dust, and the effects of cosmic expansion. While the age of stars in a galaxy can influence its color, it is not the sole determining factor.

Observations have shown that the color of galaxies can vary due to different reasons, and it is not solely linked to the age of their stars.

The successful verifications of the standard Big Bang theory include predictions such as the cosmic microwave background radiation, the abundance of light elements (helium, lithium, and beryllium), and the expansion of the universe.

Therefore, (a) Younger stars in faint galaxies cause them to appear redder in color.

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The magnitude of the force on the wire is 1.9 × 10⁻⁴ N. The direction of the current is 50° south of the west. 1.9×10 N⁻⁴, out of the Earth's surface is the correct option.

Length of the horizontal wire, L = 3.0 m

Current flowing through the wire, I = 6.0 A

Earth's magnetic field, B = 0.14 × 10⁻⁴ T

Angle made by the current direction with due west = 50° south of westForce on a current-carrying wire due to the Earth's magnetic field is given by the formula:

F = BILsinθ, where

L is the length of the wire, I is the current flowing through it, B is the magnetic field strength at that location and θ is the angle between the current direction and the magnetic field direction

Magnitude of the force on the wire is

F = BILsinθF = (0.14 × 10⁻⁴ T) × (6.0 A) × (3.0 m) × sin 50°F = 1.9 × 10⁻⁴ N

Earth's magnetic field is due north, the direction of the force on the wire is out of the Earth's surface. Therefore, the correct option is 1.9×10 N⁻⁴, out of the Earth's surface.

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We can presume that an ambulance with its siren activated is rushing to get somewhere and, depending on the driving circumstances, is likely travelling between 30 and 150 km/h. The vehicle's speed can be determined using the Doppler effect equation. Let va represent the ambulance's maximum speed. The frequency, f'=(vvv a)f=560Hz, is audible as it gets closer.

Because the source is travelling in the direction of the observer, a negative sign appears. The ambulance is described as moving away by the opposite sign with source velocity magnitude. The Doppler shifted frequency as it recedes is f')=(vv+v0)f=480Hz.

The speed of the source can be calculated as va=v(f'f')f'+f'=(343ms)(560Hz480Hz)560Hz+480Hz=26.4ms by solving the second of these equations for f and substituting into the other.

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Answer:

4

Explanation:

because when u have 5 then take 1 away u have 4

Answer:

Volt divided by ampere

Explanation:

V = IR

V/I = R

The unit of resistance from ohms law is volt / ampere. Thus, option A is correct.

Ohm's law states that the applied voltage is directly proportional to the current flow in the conductor. It is written as V ∝ I. It remains constant at room temperature.

V is defined as  potential difference or voltage. The SI unit of voltage is volt(V). I is defined as the current flowing in the circuit. The SI unit of current is ampere (A).

Generally, ohm's law equals to V = IR. R represents resistance of a material which oppose the current flow in the conductor. The unit of resistance is ohm(Ω).

When the potential difference(V) is constant, Resistance is inversely proportional to current. Current increases with decrease of resistance and current decreases with increase of resistance.

To find  equivalent unit of resistance, the ohm's law is :

V = IR

R = V / I

  = volt / ampere.

Hence, the unit of resistance from ohm's law is volt / ampere. The SI unit of resistance is ohm(Ω). Thus, option A is correct.

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The influence in an influence diagram is visually depicted by an arrow. The arrow represents the direction and strength of the influence between the variables or factors included in the diagram. The longer the arrow, the stronger the influence, while the shorter the arrow, the weaker the influence.

It is important to note that the influence diagram itself is not a quantitative tool, but rather a qualitative one that helps to visualize and organize the relationships between the variables or factors. Therefore, the height of the influence diagram, a straight line, or a circular symbol do not represent the influence in an influence diagram. It is important to properly understand and use the visual elements of an influence diagram to effectively analyze and communicate complex systems or problems.

In an influence diagram, the influence between variables is visually depicted by an arrow. These arrows represent the relationships between different elements in the diagram, helping to convey the cause and effect or dependencies among them.

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Answer:

Explanation:

Given:

L = 10 m

t = 60 s

________

V -?

Velocity:

V = L / t = 10 / 60 ≈ 0,17 m/s   ot  17 cm/s

Answer:

i believe it would be 40 divided by 1,532 but i may be wrong! i haven't done this in a while

Explanation:

In gradation, the higher the angle of the comb, the greater the amount of work. The correct option is a).

In gradation, the angle of the comb refers to the degree of incline or slope of its teeth. The higher the angle of the comb, the greater the amount of space between the teeth of the comb. This increased space allows for a greater amount of work to be done while combing, as it allows for more hair to be lifted and separated.

Therefore, the correct answer is (a) work. The angle of the comb is an important factor in determining the amount of work that can be done while combing, as it determines the amount of space available for the hair to be lifted and separated.

Additionally, a higher angle of the comb can also result in longer and more gradual transitions between the lengths of hair, which can help to create a more natural and blended look. Transparency, on the other hand, is not affected by the angle of the comb, and therefore option (d) is not correct.

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In gradation, the higher the angle of the comb, the greater the amount of length, specifically arc length. This impacts the path lengths of waves passing through a diffraction grating, intensifying their diffraction.

In the context of gradation, the higher the angle of the comb, the greater the amount of length, in terms of the arc length. The arc length is inversely proportional to the angle of rotation, meaning as the angle of rotation increases, so does the arc length.

In addition, this principle aligns with the properties of a diffraction grating, often used in Physics to study wave interactions. The slits in a diffraction grating are narrower, with space them that changes based on their angle. As the angle increases, the distance between the slits increases too, affecting the path length of the waves passing through them, and thus, intensifying the diffraction impacts.

For instance, this is represented in Figure 27.18 showing the intensity of light passing through a double slit and a diffraction grating for monochromatic light. Here, the maxima become narrower and the regions between darker as the number of slits increases, a result of increased lengths due to gradation angle.

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If the wall doesn't move, its mean that the work he did is 0 J.

Hello my friend ! Here, I will help you. Alright, before it, I will to introduce to you about work (physics). In the world of physics, work is the amount of force exerted to cause an object to move a certain distance from its starting point. The amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

\( \boxed{\sf{\bold{W = F \times s}}} \)

With the following condition :

How about a stationary object like a wall pushed by Mr. Avalos ? Yes it is 0 J. Let's prove it!

Give :

Asked : W = work = ... J

Proven :

\( \sf{W = F \times s} \)

\( \sf{W = 150 \times 0} \)

\( \boxed{\sf{W = 0 \: J}} \) (Q.E.D)

Answer:C

Explanation:

Inner core, outer core, mantle, crust

Answer:

c

Explanation:

Answer:

When one object exerts a force on another object, the second object exerts the same size force on the first object

Explanation:

The minimum speed at which a car can negotiate this banked curve, even in the complete absence of friction, is approximately 18.8 m/s.

The speed at which a car can negotiate a banked curve with a given radius and banking angle, even in the complete absence of friction, is called the "no-slip" or "minimum" speed.

here,

The gravitational force acting on the car is balanced by the normal force provided by the banked surface, and the car moves in a circular path with no slipping or skidding.

The minimum speed for a car to negotiate a banked curve can be found using the following equation:

v = √(r * g * tan(θ))

In this case, the radius of the curve is 75.0 m, and the banking angle is 15.0 degrees or 0.262 radians. Plugging these values into the equation, we get:

v = √(75.0 * 9.8 * tan(0.262))

v ≈ 18.8 m/s

Therefore, the minimum speed at which a car can negotiate this banked curve, even in the complete absence of friction, is approximately 18.8 m/s.

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Heat waves are defined by the difference in temperature compared to the normal temperature typical of a region.

A heatwave happens when a location has extremely high maximum and minimum temperatures over the course of three days. This is taken into account in light of the area's climate and previous weather patterns.

An protracted period of unusually warm weather that frequently lasts longer than two days is known as a heat wave. Heat waves can occur both with and without a lot of humidity. They can spread out across a large region, placing many people in danger of extreme heat.

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The relationship between iron and nitrogen will depend on where they fall in the periodic table.

Iron (Fe) and Nitrogen (N) are two different elements that have distinct properties:

Chemical properties: Iron is a metal that is highly reactive and is commonly found in the Earth's crust. Nitrogen is a non-metal that is relatively unreactive and makes up the majority of the Earth's atmosphere.

Physical properties: Iron is a dense, silvery-gray metal that is hard and brittle. Nitrogen is a colorless, odorless, tasteless gas that is lighter than air.

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Answer:

I thinks its c

Explanation:

I hope this helps :)

We need to calculate the circumference of the semi-circle. Additionally, to determine how much more fencing would be needed for a rectangle that encloses the same semi-circle.

The area of a semi-circle is half the area of a full circle, so to find the radius of the semi-circle, we can use the formula A = (πr²)/2, where A is the area. Rearranging the formula, we get r² = (2A)/π. Given an area of 2.5 km², we can substitute the value and solve for the radius.

Once we have the radius, we can calculate the circumference of the semi-circle using the formula C = 2πr. This will give us the amount of fencing (in feet) needed to enclose the semi-circle.

To find the perimeter of the rectangle that encloses the semi-circle, we need to determine the lengths of the rectangle's sides. The length of the rectangle is equal to the diameter of the semi-circle, which is twice the radius. The width of the rectangle is the same as the radius.

The perimeter of the rectangle is given by P = 2(length + width). By substituting the values, we can calculate the perimeter of the rectangle.

To determine how much more fencing would be needed for the rectangle compared to the semi-circle, we subtract the circumference of the semi-circle from the perimeter of the rectangle.

Therefore, by comparing the two values, we can find the additional amount of fencing (in feet) needed for the rectangle that encloses the same semi-circle.

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Answer:

a. 0.41 m

b. 5.72 m/s

c. i. For part (a), I chose the hand as the reference level since the penny was thrown from the hand and the height of the penny at the hand is zero and also, it is easier to calculate from a zero reference level.

ii. For part (b), I chose the ground as the reference level since the height of the penny above the ground is positive and the height of the penny when the penny hits the ground is zero and also, it is easier to calculate from a zero reference level.

d. 5.72 m/s

Explanation:

a. Use energy to find how high the penny goes above your hand before stopping.

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy at the hand, E equals the total mechanical energy when the penny stops in the air, E'.

E = E'

U + K = U' + K' where U = initial potential energy at hand level = mgh where h = height at hand level = 0, K = initial kinetic energy at hand level = 1/2mv² where v = speed at hand level = 2.85 m/s, U' = final potential energy at stopping level = mgh' where h' = height at stopping level, K = final kinetic energy at stopping level = 1/2mv'² where v = speed at stopping level = 0 m/s (since the penny momentarily stops)

So, U + K = U' + K'

mgh + 1/2mv² = mgh' + 1/2mv'²

substituting the values of the variables into the equation, we have

mg(0) + 1/2m(2.85 m/s)² = mgh' + 1/2m(0 m/s)²

0 + 1/2m(8.1225 m²/s²) = mgh' + 0

m(4.06125 m²/s²) = mgh'

h' = 4.06125 m²/s² ÷ g

h' = 4.06125 m²/s² ÷ 9.8 m/s²

h' = 0.41 m

(b) The penny then falls to the floor, 1.26 m below your hand. Use energy to find its speed just before it hits the floor.  

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy when the penny stops in the air, E'  equals the total mechanical energy on the ground, E"

E' = E"

U' + K' = U" + K" where U' = initial potential energy at stopping level = mgh" where h' = height at stopping level = height of penny above hand, h' + height of hand above ground = 0.41 m + 1.26 m = 1.67 m, K = initial kinetic energy at stopping level = 1/2mv'² where v = speed at stopping level = 0 m/s (since the penny momentarily stops), U = final potential energy at ground level = mgh₁ where h₁ = height at ground level = 0, K = final kinetic energy at ground level = 1/2mv"² where v" = speed at ground level,

So, U' + K' = U' + K'

mgh" + 1/2mv'² = mgh₁ + 1/2mv"²

substituting the values of the variables into the equation, we have

mg(1.67 m) + 1/2m(0 m/s)² = mg(0) + 1/2mv"²

1.67mg + 0 = 0 + 1/2mv"²

1.67mg = 1/2mv"²

1.67g = 1/2v"²

v"² = 2(1.67g)

v" = √[2(1.67g)]

v" = √[2(1.67 m × 9.8 m/s²)]

v" = √[2(16.366 m²/s²)]

v" = √[32.732 m²/s²)]

v" = 5.72 m/s

(c) Explain your choice of reference level for parts (a) and (b).

i. For part (a), I chose the hand as the reference level since the penny was thrown from the hand and the height of the penny at the hand is zero and also, it is easier to calculate from a zero reference level.

ii. For part (b), I chose the ground as the reference level since the height of the penny above the ground is positive and the height of the penny when the penny hits the ground is zero and also, it is easier to calculate from a zero reference level.

(d) Choose a different reference level and repeat part (b)

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy when the penny stops in the air, E'  equals the total mechanical energy on the ground, E"

E' = E"

U' + K' = U" + K" where U' = initial potential energy at stopping level = mgh' where h' = height at stopping level = 0.41 m, K = initial kinetic energy at stopping level = 1/2mv'² where v' = speed at stopping level = 0 m/s (since the penny momentarily stops), U = final potential energy at ground level = mgh₁ where h₂ = height of hand above the ground level = height of ground below hand = -1.26 m(it is negative since the ground is below the hand), K = final kinetic energy at ground level = 1/2mv"² where v = speed at ground level,

So, U' + K' = U' + K'

mgh' + 1/2mv'² = mgh₂ + 1/2mv"²

substituting the values of the variables into the equation, we have

mg(0.41 m) + 1/2m(0 m/s)² = mg(-1.26 m) + 1/2mv"²

0.41mg + 0 = -1.26 mg + 1/2mv"²

0.41mg + 1.26mg = 1/2mv"²

1.67mg = 1/2mv"²

1.67g = 1/2v"²

v"² = 2(1.67g)

v" = √[2(1.67g)]

v" = √[2(1.67 m × 9.8 m/s²)]

v" = √[2(16.366 m²/s²)]

v" = √[32.732 m²/s²)]

v" = 5.72 m/s