How many days during one year is the sun directly overhead at noon in new york city?.

Answer:

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The answer is:Area=1/2×b×h

Answer:

A= b×h ÷ 2

Explanation:

The Area of a triangle formula is the Base multiplied by the Height, then divided by 2

Answer:

The right option is;

d) Both technicians A and B

Explanation:

High-intensity discharge (HID) headlights is an electrical gas-discharge light that gives a very bright light when an arc is formed between the tungsten electrodes that have a transparent or translucent housing

The light is ideal for night driving due to its brightness and appear to have a bluish tint at night although the light produced by HID headlight is actually more similar to Sunlight around noon

A turn signal bulb is a flashing light indicator that shows that a vehicle is about to turn or change lanes

An issue with the wiring, a broken connection at the bulb socket or a burnt bulb can result in a condition of "no turn signal" in which the turn signal stops flashing or blinking. Therefore both technicians A and B are correct.

The power loss due to friction per meter of the pipe is approximately 0.00393 W/m.

We can use the Darcy-Weisbach equation to determine the pressure drop per metre of the pipe:

ΔP = f * (L/D) * (ρ/2) * V^2

where: f = friction factor and P = pressure drop

L stands for pipe length.

Pipe diameter is given by D.

= the water's density.

V = water's speed

In order to ascertain the type of flow, we can first compute the Reynolds number (Re):

Re = (ρ * V * D) / μ

where: = the water's viscosity

Water has a density of 1000 kg/m3 and a viscosity of 1.002 x 10-3 Pa.

Re is equal to (1000 kg/m3 x 0.1 m/s x 0.2 m) / (1.002 x 10-3 Pa/s) 199,203.

1 / f is equal to -2.0 * log10((/D)/3.7 + (2.51/(Re * f)))

where is the pip's roughness height.

We can now determine the pressure drop:

P = f (L/D) * (L/D) * (L/D) * (L/D) * (/2) * V2 = 0.025 * (1 m / 0.2 m) * (1000  kg/m³ / 2) * (0.1 m/s)^2

≈ 1.25 Pa/m

Therefore, the pressure drop per meter of the pipe is approximately 1.25 Pa/m.

P = ΔP * Q

where:

P = power loss

Q = flow rate (volume flow rate)

Assuming the pipe is completely filled with water, the flow rate can be calculated as:

Q = (π/4) * D^2 * V

Q = (π/4) * (0.2 m)^2 * (0.1 m/s) ≈ 0.00314 m³/s

Now we can calculate the power loss:

P = ΔP * Q

= 1.25 Pa/m * 0.00314 m³/s

≈ 0.00393 W/m

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Hi! When you drag the ball to the maximum starting position (10 m) and initiate the motion, you are setting up a scenario similar to simple harmonic motion.

In simple harmonic motion, an object oscillates back and forth around an equilibrium point due to a restoring force proportional to its displacement from that point.

Comparing the motion you described to simple harmonic motion, we can observe the following similarities:

1. Both motions involve an object moving back and forth around an equilibrium point.

2. Both motions have a starting position, where the object is at its maximum displacement from the equilibrium point.

3. The restoring force in both motions tries to bring the object back to its equilibrium position.

In summary, the motion you set up by dragging the ball to the maximum starting position (10 m) and hitting play shares several key characteristics with simple harmonic motion, such as oscillation around an equilibrium point and a restoring force acting on the object.

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(a) Leak before break is a concept of designing the system or structure to minimize the risk of sudden catastrophic failure due to cracks.

The concept is to create a design that allows the development of cracks, and before the crack gets to a critical size, the system or structure should be able to detect the crack or leak. There are three stages in a leak-before-break condition:

First stage - Crack initiation: In this stage, cracks start to develop, but there is no effect on the system or structure's performance.

Second stage - Slow Crack Growth: In this stage, the crack's growth is slow, and the crack's effects on the system or structure are minimal.

Third stage - Rapid Crack Propagation: In this stage, the crack grows rapidly, and it could cause a catastrophic failure of the system or structure.  

(b) Longitudinal stress, σl = (pi x di^2)/4tσl = (28.75 x 10^6 x (0.08^2))/4 x 0.01σl = 58000000 Pa Hoop stress, σH = (pi x di x p)/2tσH = (28.75 x 10^6 x 0.08)/2 x 0.01σH = 11500000 Pa

(c) Critical crack size can be calculated as; ac = ((KIc^2 x Y)/(σpi))^(1/2)ac = ((23^2 x 0.7)/(28.75 x 10^6 x pi))^(1/2)ac = 1.6 x 10^-3 m

The crack is stable since the size of the crack is less than the critical crack size.

(d) Yes, the condition corresponds to a 'leak before break since the hemispherical crack's growth is slow, and the cylinder could detect it and initiate repairs before the cylinder fails catastrophically.

(e) No, the design will not be 'leak before break since the cheaper aluminum alloy's critical crack size is smaller than the crack's size. Therefore the cylinder will fail catastrophically.

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Answer:

Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.

Explanation:

Raw shell eggs must be held in refrigerated equipment that maintains an ambient temperature of 45°F or below.

This is because eggs are a potentially hazardous food that can harbor harmful bacteria such as Salmonella. These bacteria can multiply rapidly at temperatures between 45°F and 140°F, which is known as the "danger zone".

By keeping the raw shell eggs in refrigerated equipment at 45°F or below, the growth of any harmful bacteria is slowed down or prevented, which helps to ensure the safety of the food. It is also important to properly store and handle eggs to prevent any cross-contamination with other foods.

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Zero

Explanation

they can only be kinetic energy when the body is in motion.The body was travelling at a rate of 50m/s but however, kinetic energy became Zero upon hitting the bottom of the hill

Answer:

1250000J

Explanation:

Given parameters:

Mass of coaster  = 1000kg

Velocity  = 50m/s

Unknown:

K.E at the bottom of the hill  = ?

Solution:

The kinetic energy of a body is the energy due to the motion of the body. It is expressed as;

     K.E  = \(\frac{1}{2}\) m v²

m is the mass

v is the velocity

At the bottom of the hill, the kinetic energy is at its maximum.

So, insert the parameters and solve;

        K.E  =  \(\frac{1}{2}\)  x 1000 x 50²  = 1250000J

The measure of the angle EFD = 34°. That is option A.

The radii of the given circle are CE and CD.

The measure of the given angle of the arc is = 68°

But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.

Therefore, the measure of angle of an intercepted arc is 68/2 = 34°

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Answer:

34

Explanation:

edge 2023

We will determine the work as follows:

So:

So, the work done by the force of gravity is of 78.4 J.

Answer: It is important to make a prediction

Explanation:

It is important to make a prediction before you  do an experiment because you would have an idea of what would happen befor you do it.

The amount of upward force each support exert on the beam is  751.33 N and 1012.67 N.

Force can be defined as the product of mass and acceleration of a body.

To calculate the upward force exerted by the beam, we apply the principle of moment.

From the diagram attached,

Taking our moment about N₂,

Where:

From the question,

Substitute these values into equation 1 and solve for N₂

To calculate the First support N₁, we use the formula below.

Hence, the upward force from each support is 751.33 N and 1012.67 N respectively.

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Answer:

a

Explanation:

because a

Answer:

There are two main types of OTC pain medicines: acetaminophen (Tylenol) and nonsteroidal anti-inflammatory drugs (NSAIDs). Aspirin, naproxen (Aleve), and ibuprofen (Advil, Motrin) are examples of OTC NSAIDs. If OTC medicines don't relieve your pain, your doctor may prescribe something stronger

Answer:

blue

Explanation:

blue is the only color being reflected, meaning it's the only one that will be visible

Explanation:

logo

Light

Light > Ask Question to Alfie

cee

Hi

Differentiate between luminous and non luminous objects.user

cee

The difference between luminous and non-luminous objects are -:

1. Luminous objects are the objects which emit light energy by themselves are called luminous objects. Whereas, non-luminous objects are the objects which does not emit light energy by themselves. 2) Luminous objects cause the sensation of light. Whereas, non-luminous objects do not cause the sensation of light. 3) Luminous objects are seen on their own. Whereas, non-luminous objects are seen due to luminous objects. 4) Examples of luminous objects are sun, candle, electric bulb. Whereas, examples of non-luminous objects are the moon, chair, plants.

Answer:

Explanation:

Objects that can emit light energy by themselves are known as luminous objects.  These objects can cause the sensation of light.Objects that cannot emit light energy by themselves are known as non-luminous objects.These objects do not cause the sensation of light.

Answer:

466J

Explanation:

Given parameters:

Mass of steel  = 1kg  = 1000g

Initial temperature  = 21°C

Final temperature  = 22°C

Unknown:

Amount of heat required for this temperature increase  = ?

Solution:

To solve this problem, we use the expression below:

  So;

Heat absorbed  = mass x specific heat of steel x change in temperature

Specific heat of steel  = 0.466J/g°C  

Therefore;

 Heat absorbed  = 1000 x 0.466 x (22  - 21)  = 466J

Answer:2.7 X 10₁₀W = 27 GW

Explanation:

W=1.4 X 10₁₃ J

ΔT=8.5 mins

P=W/ΔT=

1.4 x 10₁₃J/(8.5 mins)(60s/min)=2.7 x10₁₀W=27GW

The block is in equilibrium, so the net forces parallel and perpendicular to the surface are

∑ F[para] = F[normal] - mg = 0

∑ F[perp] = F[pull] - F[friction] = 0

where mg is the weight of the block. It follows that

F[normal] = mg = (5 kg) (9.8 m/s²) = 49 N

and so the frictional force has magnitude

F[friction] = 0.25 F[normal] = 12.25 N ≈ 12 N

Answer:Since most of air is made of nitrogen and oxygen, which have heavier molecular weights than hydrogen, air is denser than the hydrogen-filled balloon (the atmosphere is denser than the hydrogen-filled balloon). This results in the balloon floating in the air!

Explanation:

the net impulse that acted on the ball =500 N.s if 100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ba velocity to 15 m/s .

The normal force acts in a direction normal to the surface interaction between objects. Friction is a force that opposes motion on surfaces. Other examples of non-fundamental forces include the elastic force, tension, and frame-dependent forces .

to make someone do something that they do not want to do, for example by using or threatening to use violence. force someone to do something: He claims that police officers forced him to sign a confession.

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Therefore, the absolute value of the electric potential difference, VA – VB is 1.0 × 10³ V.

The distance between the point charges is given by the distance formula d = [(x₂ - x₁)² + (y₂ - y₁)²]¹/².

Substituting the values given in the formula, the distance between the point charges q and Q is
d = [(3 - 0)² + (1 - 0)²]¹/²
= √(9 + 1)
= √10 m
The electric potential difference, VA – VB can be calculated by the formula VA – VB = k(Q/d₂ - q/d₁), where k = Coulomb's constant, Q = charge on point charge Q, q = charge on point charge q, d₁ and d₂ are the distances of point charges q and Q from point A respectively.
Let us calculate the distances d₁ and d₂ first.
d₁ = [(x₂ - x₁)² + (y₂ - y₁)²]¹/²
   = [(0 - 0)² + (1 - 0)²]¹/²
   = 1 m
d₂ = [(x₂ - x₁)² + (y₂ - y₁)²]¹/²
   = [(3 - 0)² + (1 - 0)²]¹/²
   = √10 m
Substituting the values of k, Q, q, d₁ and d₂ in the formula, we have
VA – VB = k(Q/d₂ - q/d₁)
       = (9 × 10⁹ Nm²/C²)(-2 × 10⁻⁹ C/√10 m - 1 × 10⁻⁹ C/1 m)
       ≈ - 1.0 × 10³ V
Taking the absolute value of VA – VB, we have
|VA – VB| = |-1.0 × 10³ V|
             = 1.0 × 10³ V
Therefore, the absolute value of the electric potential difference, VA – VB is 1.0 × 10³ V.

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Answer:

Explanation:

V_{1} = first volume

V_{2} = second volume

T_{1} = first temperature

T_{2} = second temperature

Answer:

33 hours

Explanation:

7.5 + 6.5 = 13 + 1

14 + 10 = 24

9= 6+3

24 + 6 = 30

30+3= hours

The spectral line from hydrogen gas near a black hole's event horizon would be visible at a wavelength longer than 656 nm. Gravitational redshift is the term used to describe this phenomenon.

General relativity states that light leaving a gravitational environment, such as one found close to a black hole, undergoes a gravitational redshift. This indicates that the light's wavelength is distorted, giving the impression that it has been shifted towards longer wavelengths.

The observed spectral line would be redshifted in the case presented, when the hydrogen gas close to the event horizon is not travelling in our direction or away from it. As a result, the line would be visible at a wavelength greater than the 656 nm value determined in the lab.

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