How many ATOMS of sulfur are present in 5.21 grams of sulfur dichloride? ________atoms of sulfur

How many GRAMS of chlorine are present in 5.86 * 10 raised 22 molecules of sulfur dichloride?

__________grams of chlorine .

Answer:

the amount of time he takes to react is the dependent variable

Explanation:

the independent variable is what you intentionally change in an experiment, and the dependent variable is what is changing based off of your independent variable. In this case, the IV is the sounds being played, and the DV is the amount of time it took Robert to react

Option C. Sodium metal is soft and malleable is an example of a physical property.

A physical property can be defined as any feature of a substance that can be really observed and also measured without changing its chemical composition such as for example, the color, density of a metal, boiling point, conductivity, etc.

Therefore, with this data, we can see that physical properties have a significant impact on the performance and use of a given chemical product and they are associated with intrinsic features of the chemical material that forms molecules.

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The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to find out the concentration of a binary solution. Here the molarity is 0.67 M. The correct option is D.

The molarity of a solution is defined as the number of moles of the solute dissolved per liter of the solution. It is represented by the letter 'M' and it is expressed in the unit mol / L.

Molarity = Number of moles of solute  / Volume of solution in liters

M = 0.500 / 0.75 = 0.66 mol / L ≈ 0.67 M

Thus the correct option is D.

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The order of a reaction is determined experimentally and describes the relationship between the rate of a reaction and the concentration of reactants, whereas the molecularity of a reaction is a theoretical concept that describes the number of molecules that participate in the rate-determining step of a reaction.

The order of a reaction is the mathematical representation of the relationship between the rate of a reaction and the concentration of reactants. It describes how the rate of a reaction changes with respect to the change in concentration of reactants.

The order of a reaction is determined experimentally by observing how the rate of a reaction changes as the concentration of reactants is varied while keeping the concentration of other reactants and conditions constant. The order of a reaction can be 0, 1, 2, or even a fraction.

The molecularity of a reaction ​is the number of reactant molecules that collide in a single step to form the product. The molecularity of a reaction can be unimolecular (1), bimolecular (2), or termolecular (3). It is important to note that not all reactions have a molecularity, as some reactions have multiple steps and multiple reactants involved.

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Answer:

The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

C(s) + H2O(g) -> CO(g) + H2(g)

According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.

First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.

Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles

As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.

The molar mass of hydrogen (H2) is approximately 2 grams/mole.

So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams

Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.

Explanation:

Approximations followed for answer.

In the ground state, it should be noted that the the number of valence electrons the K-42 isotope has is only one valence electron.

In the first group of the periodic table is potassium. It has a valence shell with one electron.

We can assume that potassium only has one electron on its valence shell because it belongs to group 1. The isotope is irrelevant because the only distinction between isotopes is the number of neutrons present in their nuclei.

In summary, it should be noted that K-42 only possesses one valence electron.

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Two isotopes of potassium are K-37 and K-42. How many valence electrons are in an atom of K-42 in the ground state?

Based on the Law of Conservation of Mass, the mass of products form when baking soda decomposes is 168 g/mole.

The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed.

From the equation of NaHCO3 → Na₂CO3 + H₂O + CO₂ , we have

Mass of baking soda = 2 x molar mass

Molar mass of NaHCO₃ = 84.007 g/mole

Mass of baking soda = 2 x 84.007 g/mole

Mass of baking soda =  168.014 g/mole=  168 g/mole

Therefore, based on the Law of Conservation of Mass, the mass of products form when baking soda decomposes is 168 g/mole.

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Answer:

\(T_f=25.0\°C\)

Explanation:

Hello.

In this case, considering that the sample of hot copper is submerged into the water and the container is isolated, the heat lost by the copper is gained by the water so we can write:

\(Q_{Cu}=-Q_w\)

In terms of mass, specific heat and temperature we write:

\(m_{Cu}C_{Cu}(T_f-T_{Cu})=-m_wC_w(T_f-T_w)\)

Whereas the final temperature is the same for both copper and water because they are in contact until thermal equilibrium is reached. In such a way, the required maximum temperature no more than the equilibrium temperature and is computed as shown below:

\(T_f=\frac{m_{Cu}C_{Cu}T_{Cu}+m_wC_wT_w}{m_{Cu}C_{Cu}+m_wC_w}\)

Thus, plugging the given data in the formula, we obtain:

\(T_f=\frac{10.3g*0.385\frac{J}{g\°C}*100\°C +47.0g*4.184\frac{J}{g\°C}*23.5\°C }{10.3g*0.385\frac{J}{g\°C}+47.0g*4.184\frac{J}{g\°C}}\\\\T_f=25.0\°C\)

Which is a small change considering the initial one, because the mass of water is greater than the mass of copper as well as for the specific heats.

Best regards!

The maximum temperature of the water in the insulated container after the copper metal is added is 25 °C

From the question given above above, the following data were obtained:

Mass of water (Mᵥᵥ) = 47 g

Temperature of water (Tᵥᵥ) = 23.5°C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Mass of copper (M꜀) = 10.3 g

Temperature of copper (M꜀) = 100 °C

Specific heat capacity of copper (C꜀) = 0.385 J/gºC

The equilibrium temperature of the mixture can be obtained as follow:

Heat loss by copper = Heat gained by water

Q꜀ = Qᵥᵥ

M꜀C꜀(M꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ– Mᵥᵥ)

10.3 × 0.385 (100 – Tₑ) = 47 × 4.184 (Tₑ – 23.5)

3.9655 (100 – Tₑ) = 196.648 (Tₑ – 23.5)

Clear bracket

396.55 – 3.9655Tₑ = 196.648Tₑ – 4621.228

Collect like terms

396.55 + 4621.228 = 196.648Tₑ + 3.9655Tₑ

5017.778 = 200.6135Tₑ

Divide both side by 200.6135

Tₑ = 5017.778 / 200.613

Thus, the equilibrium temperature of the mixture is 25 °C. Therefore, the maximum temperature of the water in the insulated container is 25 °C

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The pH of a 0.00150 M HNO3 solution is 2.82

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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Answer:

In Thomas Cole's painting "The Oxbow," Thomas Cole, the artist, shows himself sitting in the landscape while painting it.

Explanation:

In the painting called "The Oxbow" by Thomas Cole, the artist actually put himself in the picture. He's sitting right in the middle of the landscape, just like he placed himself in the painting, as if taking a selfie while working on it. It's like he took a snapshot of himself while he was working on the painting. This shows how much he cared about creating the artwork and how he felt a personal connection to the beautiful scenery. It's really fascinating because it gives us a glimpse into how he saw himself as an artist and how he wanted to capture the incredible beauty of nature through his art.

Answer:

D

Explanation:

Have a nice day

Among the following observations which is usually not evidence of a chemical change is change of a shape.

Chemical changes will occur when the composition of the substance is changes internally or converted into any new product.

So, change of shape is not a chemical change.

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Answer:

0.21 atm

Explanation:

Step 1: Given data

Step 2: Calculate the partial pressure of oxygen

The air is a gaseous mixture formed mainly by nitrogen, oxygen and argon. The total pressure is equal to the sum of the partial pressures of the gases.

P = pN₂ + pAr + pO₂

pO₂ = P - pN₂ - pAr

pO₂ = 1 atm - 0.78 atm - 0.01 atm

pO₂ = 0.21 atm

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

We can use the principle of conservation of energy to solve this problem. The heat lost by the metal is equal to the heat gained by the water:

Q metal = -Q water

where Q metal is the heat lost by the metal, and Q water is the heat gained by the water.

The heat lost by the metal can be calculated using the formula:

Q metal = m metal * c metal * ΔT metal

where m metal is the mass of the metal, c metal is its specific heat, and ΔT metal is the change in temperature of the metal.

The heat gained by the water can be calculated using the formula:

Q water = m water * c water * ΔT water

where m water is the mass of the water, c water is its specific heat, and ΔT water is the change in temperature of the water.

We know the values of all the variables except c metal, so we can solve for it. We can start by calculating the values of Q metal and Q water:

Q metal = -Q water

m metal * c metal * ΔT metal = -m water * c water * ΔT water

Substituting the given values, we get:

5.4 g * c metal * (100.0 °C - T) = -142 g * 4.18 J/(g*°C) * (T - 24.2 °C)

Simplifying and solving for c metal, we get:

c metal = [142 g * 4.18 J/(g*°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

Multiplying out, we get:

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

To solve for c metal, we need to find the value of T that satisfies the equation. We can do this by substituting the given value of ΔT water = 0.9 °C into the equation and solving for T:

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

c metal = [593.56 J/(°C) * (T - 24.2 °C)] / [540 g - 5.4 g * T]

0.9 g * [593.56 J/(°C) * (T - 24.2 °C)] = [540 g - 5.4 g * T] * c metal

535.2044 J/(°C) * (T - 24.2 °C) = 540 g * c metal - 5.4 g * T * c metal

535.2044 J/(°C) * T - 12931.7808 J = 540 g * c metal - 5.4 g * c metal * T

5.4 g * c metal * T + 535.2044 J/(°C) * T = 540 g * c metal + 12931.7808 J

T * (5.4 g * c metal + 535.2044 J/(°C)) = 540 g * c metal + 12931.7808 J

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

Substituting the given values, we get:

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

T = [540 g * c metal + 12931.7808 J] / [5.4 g * c metal + 535.2044 J/(°C)]

T ≈ 23.3 °C

Therefore, the specific heat of the metal is:

c metal = [142 g * 4.18 J/(g°C) * (T - 24.2 °C)] / [5.4 g * (100.0 °C - T)]

c metal ≈ 0.39 J/(g°C)

So the specific heat of the metal is approximately 0.39 J/(g*°C).

A 5.4 g sample of the metal is heated to the 100.0 °C and is placed in the beaker containing 142 g of the water at 24.2 °C. The specific heat of the metal is 1.322 J/ g °C.

The mass of the metal = 5.4 g

The final temperature = 25.1 °C

The initial temperature = 100 °C

The specific heat capacity of metal = x

The mass of the water = 142 g

The final temperature = 25.1 °C

The initial temperature = 24.2 °C

The specific heat capacity of water = 4.184 J/ g °C

Loss of Heat of Metal = Gain of Heat by Water

-q metal = + q metal

- 5.4 × x × ( 25.1 - 100 ) = 142 × 4.184 ( 25.1 - 24.2 )

404.46 x = 534.71

x = 1.322 J/ g °C

The specific heat capacity of metal is  1.322 J/ g °C.

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Answer:

-1

Explanation:

Electrons have a negative charge, so when you add an electron to an element their charge goes down by 1.

Explanation:

Separatory funnels can be used to separate immiscible liquids. Immiscible liquids are those which won't mix to give a single phase. Oil and water are examples of immiscible liquids. This is because water is more dense than oil, and two layers will thus form. A water layer, and above that, an oil layer.

A separatory funnel has two main components:

A separatory funnel is also usually held above a beaker or flask, with a retort stand and ring clamp.

Consider the separation of water and oil.

The solution is poured into the separatory funnel with the stopcock CLOSED. Due to the immiscible nature and density of the two liquids, they will eventually separate and form two layers.

The stopcock is slowly and carefully opened, allowing the bottom layer to flow out. Make sure stopcock is closed JUST before the end of the bottom layer, to ensure there is no contamination of oil with the water in the beaker.

Stopcock is opened again, with a new beaker underneath, to allow the little bit of water and a little bit of oil out, to ensure ONLY oil remains in the separatory funnel. Stopcock is closed after this.

Stopcock is opened again, with a third clean beaker underneath, to allow ALL of the oil to pass through.

Therefore, you have separated water and oil. See the attached image for a diagram of the setup.

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The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

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smoke

Explanation:

carbon dioxide is introduced into the atmosphere by burning of fossil fuels and forests

the heat energy required to take it to the melting point is 420J.

The heat capacity, abbreviated Cp, is the amount of heat needed to elevate a mole of a substance's heat content by precisely one degree Celsius.

A material has more thermal energy the hotter it is, says basic thermodynamics. Additionally, when a chemical is present in greater concentrations at a particular temperature, it will have a higher total thermal energy.

Mathematically,

Q = mc∆T

Where,

Q = quantity of heat absorbed by a body

m = mass of the body

∆t = Rise in temperature

C = Specific heat capacity of a substance depends on the nature of the material of the substance.

S.I unit of specific heat is J kg-1 K-1.

Given,

An ice cube of mass = m=25g

initial temperature = T1 = -8°C

final temperature = T2 = 0°C

Heat capacity for solid water = c = 2.1J/g°C

According to heat energy required to take it to the melting point,

Q = mc∆T

Q = 25g×2.1J/g°C × (0+8) °C

Q = (25×2.1×8) J

Q = 420J

Hence, the heat energy required to take it to the melting point is 420J.

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Answer:

a) IUPAC Names:

                   1) (trans)-but-2-ene

                   2) (cis)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

The mass of 7m chain is 15.12 kg.

It states that in order to tow a car, 7m of grade 70 tow chain with a 3/8" diameter is needed.

Chain length is therefore 7m.

Given that the chain weighs 2.16 kg per meter,

Thus, the mass of 1 m of chain equals 2.16 kg of chain's weight.

In this case, weight and mass are equivalent because both are measured in kilograms (kg).

Therefore, we must increase the mass of a 1 m chain by the chain's length to obtain the mass of a 7 m chain.

Consequently, the weight of a 7-meter chain = 7 x 2.16 kilograms = 15.12 kilograms.

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Answer:

Explanation:

Here, we want to get the maximum volume of solution that can be produced

Given:

Molarity = 1.8 M

Number of Moles = 0.9 moles

Find:

Volume

Equation Used:

Number of moles = molarity * volume

Answer:

To convert this to mL, we multiply the volume by 1000 since 1 L = 1000 mL

Thus, we have it that:

Considering the definition of molar mass, the correct answer is option c): the mass of 1.85 moles H₂O₂ is 62.9 grams.

The molar mass of substance is a property defined as the amount of mass that a substance contains in one mole.

The molar mass of a compound is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the elements is:

So, the molar mass of the compound H₂O₂ is calculated as:

H₂O₂= 2× 1 g/mole + 2× 16 g/mole

Solving:

H₂O₂= 34 g/mole

You can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 34 grams, 1.85 moles of the compound contains how much mass?

mass= (1.85 moles× 34 grams)÷ 1 mole

mass= 62.9 grams

Finally, the mass of 1.85 moles H₂O₂ is 62.9 grams.

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Answer:

These are the nonmetals.

Answer:

first choice

Explanation:

energy is written on the left side is its absorbed

2 elements came together so bonds are formed.

Answer: 20.179 grams

I had to do a project on this recently, so here is your answer!

Hope this is helpful!

Answer:

2.894 x 10²⁴ atoms Ne

Explanation:

To find the amount of neon atoms, you need to (1) convert grams to moles (using the atomic mass) and then (2) convert moles to atoms (using Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator of the ratios in this case). The final answer should have 4 sig figs like the given value (100.0 = 4 sig figs).

Atomic Mass (Ne): 20.180 g/mol

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

 100.0 g Ne             1 mole             6.022 x 10²³ atoms
--------------------  x  -----------------  x  -------------------------------  =  2.894 x 10²⁴ atoms
                               20.180 g                    1 mole

Tthe initial temperature of the polystyrene sample is 39.4°C.

Given: Mass of polystyrene sample = 54.2 gSpecific heat of polystyrene = 1.880 J-g°CWater mass = 100.0 g Initial water temperature = 21.0°CWater final temperature = 34.3°CPressure remains constant at 1 atmFormula used:Heat gained by water = heat lost by polystyreneHence,Heat lost by polystyrene = Heat gained by water=> mcΔT = mcΔTwhere,m = mass of polystyrene or waterc = specific heat capacityΔT = change in temperatureThe temperature change is ΔT = 34.3°C - 21.0°C = 13.3°CNow we can use this temperature change to calculate the initial temperature of the polystyrene.Taking the water's specific heat capacity, c = 4.184 J/g°CHeat gained by water = (100.0 g)(4.184 J/g°C)(13.3°C) = 5574 JHeat lost by polystyrene = 5574 JTaking the polystyrene's specific heat capacity, c = 1.880 J/g° ) = 13.3°C Now let's calculate the mass of polystyrene using the specific heat capacity formula.5574 J = (54.2 g)(1.880 J/g°C)(13.3°C - Ti)Ti = 39.4°C

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The advantage of using telescopes launched into orbit around Earth or sent out into deep space is that the images gathered are usually clearer because they do not have to look through our atmosphere.

What is an atmosphere?

The atmosphere can distort and blur images, making it difficult to observe distant objects with high precision. By placing telescopes in space, scientists can avoid this problem and obtain much clearer and more detailed images of objects in the universe. Additionally, space telescopes can observe a wider range of the electromagnetic spectrum, including ultraviolet and infrared radiation, which are absorbed by Earth's atmosphere.

What is telescopes?

A telescope is an instrument used to observe and study distant objects in space by collecting and focusing electromagnetic radiation. Telescopes can be used to study visible light, infrared radiation, ultraviolet radiation, X-rays, and other forms of electromagnetic radiation. They are important tools in astronomy and have helped scientists make many discoveries about the universe. There are many different types of telescopes, including refracting telescopes, reflecting telescopes, and radio telescopes.

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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