How many atoms are in 25.00 g of B.

1.393 x 10^24 atoms of B


1.333 x 10^23 atoms of B


2.16 x 10^26 atoms of B


2.17 x 10^24 atoms of B

Thiocyanate is a frequently utilized ligand because it offers valuable precursors for a variety of coordination complexes and has multiple bonding mechanisms to one or more transition metal ions.

Thiocyanate typically forms terminal bonds with first row transition metals via the nitrogen.

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Answer:Plasma is highest energy state of matter.It consists of electrons,protons and neutral particles.

Explanation:(1) Plasma has a very high electrical conductivity .

(2) The motion of electrons and ions in plasma produces it's own electric and magnetic field

(3)It is readily influenced by electric and magnetic fields .

(4)It produces it's on electromagnetic radiations.



Answer:

19.5%

Explanation:

the air required for human breathing is 19.5 percent.

A film inside a box can be exposed by beta particles but not alpha particles due to their different penetration capabilities

Alpha particles are much larger and heavier than beta particles, which means that they cannot penetrate through materials as easily as beta particles.

When a film is kept in a box, the box acts as a shield that blocks alpha particles from reaching the film, as the particles cannot pass through the material of the box. However, beta particles are smaller and have less mass, which makes them more capable of passing through materials. Therefore, if there is a source of beta particles outside the box, they can penetrate through the material of the box and reach the film, potentially exposing it.

In summary, the ability of particles to penetrate through materials is dependent on their size and mass, with alpha particles being too large to penetrate through the box and beta particles being small enough to pass through it.

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The spontaneity of a reaction can be determined by calculating the Gibbs free energy change (∆G) of the reaction. The equation for ∆G is:
∆G = ∆H - T∆S
Where ∆H is the change in enthalpy, T is the temperature in Kelvin, and ∆S is the change in entropy.

In this case, the reaction is 2 NO(g) + O2(g) −−→ 2 NO2(g). The standard enthalpy change (∆H°) and standard entropy change (∆S°) for this reaction can be found in thermodynamic tables.
∆H° = -114.1 kJ/mol
∆S° = -146.6 J/mol·K
At 298 K and 1 atm, the Gibbs free energy change for this reaction can be calculated as:
∆G = ∆H° - T∆S°
∆G = (-114.1 kJ/mol) - (298 K)(-146.6 J/mol·K)
∆G = (-114.1 kJ/mol) - (-43.7 kJ/mol)
∆G = -70.4 kJ/mol

Since ∆G is negative, the reaction is spontaneous at 298 K and 1 atm.

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The mass of the chlorine needed to react with 0.175g of gold is 94.6mg. This is calculated with the help of Mole concept.

The mass of Au is 0.175g

The atomic mass of Au is 197g

Atomic mass of chlorine atom= 35.5 g

The number of moles of gold is calculated by the expression,

        Number of moles= given mass/ molar mass

Putting all the values in the expression of moles we get,

number of moles of gold =  0.175 g/ 197 g/ mole

                                         = 0.000888 mole

From the balanced equation 2Au + 3 → 2AuC, if 2 moles of gold readily react with 3 moles of Cl.

0.000888 moles of gold will react will be,

             = 3/2 x 0.000888 x 35.5

Number of moles of Cl will be = 0.001332 moles

So, the mass of Cl that will react with Au is:

Mass of Cl = 0.01332 x 71

                  = 0.0946 g

we can convert the gram into milligram by multiplying 1000.

so it becomes, 0.0946 g  x 1000= 94.6mg

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Based on concepts you learned in the lesson, Barrett who says he can’t wait until we discover element 120 in our environment is correct because we discover new elements everyday.

This is referred to as a chemical substance that cannot be broken down into other substances and examples include sodium , hydrogen etc.

We can infer from this argument that Barrett is correct because new elements are being discovered by scientists from time to time so it is false to say they won't be discovered anymore,.

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Compare between a static discharge and a current flowing via a circuit, A voltage source provides a constant current to a circuit. In a static discharge, the transfer of charge happens very quickly and discontinuously.

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If the solution contains 120.0 g of naoh and has a volume of 6000 ml, the molarity of the solution is 0.50 mol/L.

Molarity is defined as the number of moles of solute per liter of solution. To determine the molarity of a solution, we need to first find the number of moles of the solute, which can be calculated using the formula:

moles = mass/molar mass

For sodium hydroxide (NaOH), the molar mass is 40.00 g/mol (22.99 g/mol for Na, 15.99 g/mol for O, and 1.01 g/mol for H).

Using the given mass of NaOH, we can calculate the number of moles:

moles = 120.0 g / 40.00 g/mol = 3.00 mol

Next, we need to convert the volume of the solution from milliliters to liters:

volume = 6000 ml / 1000 ml/L = 6.00 L

Finally, we can use the equation for molarity:

Molarity = moles / volume

Molarity = 3.00 mol / 6.00 L = 0.50 mol/L

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Answer:

What are the two animals?

Explanation:

The  electron distribution in the Si atom : D. 2,8,4

The maximum number of electrons that can be filled in the nth electron shell is 2n²(n=shell)

Electron configuration of Si : 1s² 2s2²2p6⁶3s²3p² = 14 electron

The electron distribution :

K shell = 2

L shell = 8

M shell = 4

Answer:

What do you want answered?

Explanation:

The most important winemaking grape varietal is not Vitis Zinfandel. The actual grape varietal is Vitis vinifera. Vitis vinifera is a species of grapevine that is widely grown for wine production globally.

Zinfandel, also known as Primitivo, is a variety of black-skinned wine grape that is widely cultivated in the United States. It is also grown in Italy, Croatia, and other areas, but it is primarily known for being grown in California, particularly in the Napa and Sonoma Valleys. Globally, Vitis vinifera is the most widely planted grape variety for wine production, accounting for the majority of wine made today. Cabernet Sauvignon, Merlot, Pinot Noir, Chardonnay, and Sauvignon Blanc are among the most popular Vitis vinifera grape varieties used to make wine. Zinfandel is a relatively small grape variety in comparison to these major grapes.

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Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

The energy change when the temperature of 0.750 kg of water decreased from 123 °C to 23.0 °C is  -313.5 kJ.

In this problem, we are dealing with specific heat which is referred to as the sum of heat per unit mass required to raise the temperature by one degree Celsius.Since we know the boiling point of water is 100°C, at 123°C, the water is steam.

The formula we are referring to for  calculating the heat energy Q

Q= m C ΔT

where m is the mass of water which is equal to 0.750  Kg, then

C is the specific heat of water equal to  4180 J/Kg °C and

ΔT is the change in temperature which is (23-123)= -100°C

So, assembling those desired values on the formula we get,

Q= 0.750 (4180) (-100)

Q=-313500

 = -313.5 kJ

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The mass of water that vaporizes is approximately 0.000163 kg, or 0.163 g.

we can use the heat gained by the mercury to calculate the amount of water that vaporizes. The heat gained by the mercury is equal to the heat lost by the water, so we can use the equation:

Q = m·C·ΔT

where Q is the heat gained or lost, m is the mass of the substance, C is the specific heat capacity of the substance, and ΔT is the change in temperature.

For the water:

Q = (0.111 kg) x (4.18 J/g°C) x (-81.6°C) = -368 J

Note that the heat lost by the water is negative because it is losing heat to the environment.

For the mercury:

Q = (4.14 kg) x (0.14 J/g°C) x (217°C - 100°C) = 1,246 J

where the specific heat capacity of mercury is 0.14 J/g°C.

Since the heat gained by the mercury is equal to the heat lost by the water, we can set the two equations equal to each other and solve for the mass of water that vaporizes:

Q_water = Q_mercury

-368 J = m_water·L_vaporization

m_water = -368 J / (2.26 x 10^6 J/kg) ≈ 0.000163 kg

where the specific latent heat of vaporization of water is 2.26 x 10^6 J/kg.

Therefore, the mass of water that vaporizes is approximately 0.000163 kg, or 0.163 g.

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The ratio for [C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺] if the solution has the following pH values 4.50 is 6.30.

A buffer is indeed a solution that resists pH fluctuations and contains either a weak acid as well as its salt or perhaps a weak base as well as its salt. To put it another way, a buffer is indeed an aqueous solution that includes a weak base as well as its conjugate acid, or a weak acid as well as its conjugate base.

A buffer may also be referred to as a buffer solution, hydrogen ion buffer, and pH buffer.

pOH =PKb+log[salt]/[base]

pOH =14-pH= 14-4.50=9.5

pKb= -logKb

     =-log(1.7×10⁻⁷)

     =8.7

9.5 =8.7+log[salt]/[base]

9.5 -8.7=log[salt]/[base]

0.8=log[salt]/[base]

[salt]/[base] =10^0.8=6.30

[C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺]=6.30

Therefore, 6.30 is the value for [C\(_5\)H\(_5\)N]/[C\(_5\)H\(_5\)NH⁺].

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Answer:

what are the gas samples

The answer is that the forces you are referring to are known as Van der Waals forces.

Van der Waals forces arise from an attraction between molecules caused by a distortion in the electron cloud, which leads to an uneven distribution of negative charge.

This type of attraction is often seen between nonpolar molecules, such as those found in hydrocarbons. The explanation for this phenomenon lies in the fact that all atoms have electron clouds, which can be distorted by the presence of nearby atoms. This distortion leads to temporary dipoles, or areas of partial positive and negative charges, which can then attract other nearby molecules. In conclusion, Van der Waals forces are an important type of intermolecular attraction, which play a key role in determining the physical and chemical properties of many materials.

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To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas.

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Since we are dealing with the same gas (oxygen) at the same temperature and pressure, we can assume that the value of R is constant. Therefore, we can write:

PV/n = RT

The ratio PV/n is known as the molar volume of the gas, and is constant for a given temperature and pressure. We can use this relationship to find the volume of oxygen gas that corresponds to 5.00 g.

First, we need to calculate the number of moles of oxygen gas in 1.9 g:

n = m/M

where m is the mass of the gas and M is the molar mass of oxygen, which is 32 g/mol.

n = 1.9 g / 32 g/mol

n = 0.059375 mol

The molar volume of oxygen gas at the given temperature and pressure is:

PV/n = RT/n

V/n = RT/P

Substituting the given values, we get:

V/n = (0.0821 L·atm/mol·K) x (273 K) / (1 atm)

V/n = 22.414 L/mol

Therefore, the volume of 1.9 g of oxygen gas is:

V1 = n x V/n = 0.059375 mol x 22.414 L/mol = 1.331 L

Now we can use the molar volume to find the volume of 5.00 g of oxygen gas:

n = m/M = 5.00 g / 32 g/mol = 0.15625 mol

V2 = n x V/n = 0.15625 mol x 22.414 L/mol = 3.51 L

Therefore, 5.00 g of oxygen gas will occupy a volume of 3.51 L at the same temperature and pressure as 1.9 g of oxygen gas.

No, the rates are not equivalent. Simplifying the first rate, we can say that 1 kilometer is covered in every 40 minutes. In the second rate, we can say that 1 kilometer is covered in every 2 minutes.

To determine if two rates are equivalent, we need to simplify the rates and compare the time it takes to cover one unit of distance. In the first rate, 0.75 kilometers are covered in 30 minutes. To simplify, we can divide both the numerator and denominator by 0.75, resulting in 1 kilometer covered in 40 minutes.

In the second rate, 25 kilometers are covered in 50 minutes. Simplifying by dividing both numerator and denominator by 25, we get 1 kilometer covered in 2 minutes.

Comparing the simplified rates, we see that it takes 40 minutes to cover 1 kilometer in the first rate, while it only takes 2 minutes in the second rate. Since the time required to cover the same distance differs, the rates are not equivalent.

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Increasing the temperature increase the rate of a reaction because it increases the number of collisions.

What is collision model?

According to the collision model, chemical reaction can occur only when reactant molecules, atoms, or ions collide with more than a particular amount of kinetic energy and in the right direction. The collision model explains why most molecular collisions do not result in a chemical reaction.

What is the effect of temperature on collision model?

Temperature influences both the rate of collision and the energy of molecules during collisions, according to collision theory. As the temperature rises, so does the amount of energy in the system, and therefore more molecules will have energy greater than the activation barrier. This accelerates the reaction.

Increasing the temperature increase the rate of a reaction because it increases the number of collisions.

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164 g of H₃PO₃ (phosphorus acid) would require 3 moles of H₂O for the reaction.

Given information,

Mass of H₃PO₃ = 164g

Moles of H₃PO₃ = 82 g/mol

The balanced chemical equation:

P₂O₃ + 3H₂O → 2H₃PO₃

For every 2 moles of H₃PO₃ produced, 3 moles of H₂O are required.

The number of moles of H₃PO₃:

Moles of H₃PO₃ = mass of H₃PO₃ / molar mass of H₃PO₃

Moles of H₃PO₃ = 164 g / 82 g/mol

Moles of H₃PO₃ = 2 mol

The number of moles of H₂O:

Moles of H₂O = (3/2) × moles of H₃PO₃

Moles of H₂O = (3/2) × 2 mol

Moles of H₂O = 3 mol

Therefore, 164 g of H₃PO₃ would require 3 moles of H₂O for the reaction.

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Pages 218–219 of the discussion give the example of an imperfect octet using the element boron. By generally forming three covalent bonds, the valence shell of the element boron is reduced from the usual eight to just six.

An example of an incomplete octet employing boron is provided in the topic of incomplete octets on pages 218–219 of a chemistry textbook (not specified in the question) (B). By generally forming three covalent bonds, the valence shell of the element boron is reduced from the usual eight to just six. This is due to the fact that boron's valence shell only has three electrons and thus creating covalent bonds cannot produce the additional energy needed to add five more electrons to fill the octet. As a result, molecules like diborane (B2H6) and boron trifluoride (BF3) contain incomplete octets.

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Answer:

2H2O2 + NaClO → NaClO3 + 2H2O

Group 13 in the periodic table consists of the elements boron (B), aluminum (Al), gallium (Ga), indium (In), and thallium (Tl).

The periodic table is rows and columns arrangement of chemical elements.

The general trends for the properties mentioned:

Density: The density of elements generally increases from boron to thallium. Boron has low density of 2.34 g/cm³ while thallium has a higher density of 11.85 g/cm³.

Boiling point: The boiling point of the elements generally decreases down the group. Boron has the highest boiling point at 4275°C, and thallium has the lowest boiling point at 1457°C.

Melting point: The melting point of elements decreases down the group. Boron has the highest melting point at 2075°C, and thallium has the lowest melting point at 303°C.

Reactivity: The elements in Group 13 have three valence electrons and can lose these electrons to form +3 ion. Reactivity of elements increases down the group, with boron being the least reactive and thallium being  most reactive.

Atomic radius: The atomic radius of elements increases down the group. This is because number of energy levels increases down the group, and  outer electrons are further from the nucleus.

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