How many aluminum atoms are in 2.26 g of aluminum?

Answer:

oxygen

Explanation:

plants use oxygen

The total heat energy required is expressed according to the formula:

where:

Qvap is the heat energy absorbed by the vapor

Qw is the heat energy absorbed by the water

Get the heat energy absorbed by the vapor at 100 degrees

Given the following parameters;

Mass of water = 100g

Molar mass of water (H2O) = 18.015g/mol

Hvap,w = 2259 J/g = 40.8 kJ/mol

Substitute the given parameters into the formula to have:

Get the heat absorbed by the water from 30 to 100 degrees and from 100 to 110 degrees using the formula below. Note that the water vapor is being heated without any phase changes, so we will be utilizing the specific heat capacity of water vapor.

Get the total heat energy required;

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

\(2Ca+O_2\rightarrow 2CaO\)

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

\(mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa\)

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

\(mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa\)

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

\(m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO\)

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

Answer:

69.9 g of CaO will be produced. ≅ 70 g

Explanation:

First of all you need to make the reaction:

2Ca + O₂ → 2 CaO

Determine the moles of each reactant:

10 g Ca / 40.08 g/mol = 0.25 moles

4 g O₂ / 32 g/mol = 0.125 moles

There is no limiting reagent in this reaction, we can use both elements.

Ratio between Ca and CaO, is 2:2. For 0.25 moles of Ca I would make 0.25 moles of CaO. We convert the moles to mass:

0.25 mol . 56.08 g / 1mol = 14 g

Let's think when you have the same mass of reactant:

50 g Ca/ 40.08 g/mol = 1.24 moles

50 g O₂ / 32 g/mol = 1.56 moles

For 1 mol of oxygen I need 2 moles of calcium, so If I have 1.56 moles, I would need the double, 3.12. Notice that Ca is the limiting reagent (we need 3.12 moles of reactant, but we only have 1.24). Now we need to work with it. If 2 moles of Ca, makes 2 moles of CaO, then 1.24 moles, will produce the same amount of oxide. We finally convert the moles to mass: 1.24 mol . 56.08 g/mol = 69.9 g

Answer:

Gabriella is slowing down at the same rate that Kendall is speeding up, and Franklin is not accelerating.

Gabriella is slowing down at the same rate that Kendall is speeding up, and Franklin is not accelerating. Hence option B is correct.

Acceleration is defined as the speed at which an object's velocity changes over time. The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating. Acceleration can be expressed as

Acceleration = Displacement / Time

Velocity is defined as the pace at which an item changes position while moving in one direction, as seen from a certain point of view and as measured by a specific unit of time. Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path.

Thus, Gabriella is slowing down at the same rate that Kendall is speeding up, and Franklin is not accelerating. Hence option B is correct.

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Answer: Wind energy, mechanical energy, electrical energy, and thermal energy.

Explanation:

In this example, the following forms of energy are occurring in order of first to last:

So, the forms of energy occurring in this example are wind energy, mechanical energy, electrical energy, and thermal energy.

Answer:

B

Explanation:

Answer:

OK i see

Explanation:

A Mind Map is  described as an easy way to brainstorm thoughts organically without worrying about order and structure which allows you to visually structure your ideas to help with analysis and recall.

A mind map may transform a large list of uninteresting facts into a vivid, memorable, and meticulously structured diagram that corresponds to the way your brain naturally processes information.

We have two types of Combustion which are the complete combustion and incomplete combustion.

Complete Combustion is said to occur when there is sufficient oxygen, resulting in the complete oxidation of the fuel. It produces carbon dioxide and water as the primary products.

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The pressure of atmospheres of the argon gas in  the given incandescent light bulb is 1. 1 .

The pressure of atmospheres can be found by the formula :

= ( Number of moles x Universal gas constant x Temperature in Kelvin ) / Volume of gas

Number of moles = 3.4 x 10 ⁻³

Universal gas constant = 0. 082

Temperature in Kelvin = 20 + 273. 15 = 293. 15 K

Volume of gas : 75 x 10 ⁻³

The pressure of atmospheres of the argon gas is:

= ( 3.4 x 10 ⁻³ x 0. 082 x 293. 15 ) / 75 x 10 ⁻³

= 1. 1 atm

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4LiBr + Co(SO₄)₂ ----> 2Li₂SO₄ + CoBr₄ is the balanced equation.

First write the complete equation

LiBr + Co(SO₄)₂ ----> Li₂SO₄ + CoBr₄

Now balance the given equation

LiBr + Co(SO₄)₂ ----> Li₂SO₄ + CoBr₄

Reactant Side Product side

Li= 1 Li = 2

Br = 1 S = 1

Co = 1 Co = 1

S = 2 S = 1

O = 8 O = 4

We can see that there are 8 oxygen atom in yhe Reactant side and 4 in the product side. So multiply by 2 in the product side to balance the Oxygen atoms.

4LiBr + Co(SO₄)₂ ----> 2Li₂SO₄ + CoBr₄

We can see that the given equation is now balanced.

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QUESTION: Write the complete equation and also balanced the equation.

_LiBr + _ Co(SO₄)₂ --> _ + _

Answer:

follow the steps

Explanation:

First make a circle and write 17p and 18n below 17 p.Now again make another circle bigger than previous one and make two small circle .Again make another bigger circle and fill it with 8 small circles .Again make another bigger circle than previous ones and make 7 small circles in it .Now write e in small circles .Then write

Chlorine

Atomic number=17

Atomic weight =35

Shell k l m n

no.of e .2 1 × ×

After 20 minutes, there would be 0.75 kilograms of salt in the tank.

1. Let's derive the differential equation that y(t) satisfies. The rate at which salt is added to the tank is given by the concentration of the solution (0.5 kg/L) multiplied by the rate at which the solution is added (6 L/min). The rate at which salt is drained from the tank is given by the concentration of salt in the tank (y(t) kg/L) multiplied by the rate at which the solution is drained (4 L/min). Therefore, the differential equation is:

dy/dt = (0.5 kg/L * 6 L/min) - (y(t) kg/L * 4 L/min)

Simplifying further, we have:

dy/dt = 3 - 4y(t)

2. To find the amount of salt in the tank after 20 minutes, we can solve the differential equation. One approach is to find the particular solution by assuming y(t) takes the form of a constant, y. Substituting this into the differential equation, we have:

dy/dt = 3 - 4y

Setting dy/dt to zero (since y is constant), we can solve for y:

0 = 3 - 4y

4y = 3

y = 3/4

y = 0.75 kg

Therefore, after 20 minutes, there would be 0.75 kilograms of salt in the tank.

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Answer:

Ans C is the correct one.

As the element with 15 proton 15 electrons and 16 neutron is phosphorus

Answer:

True

Explanation:

A hand weavers would take much more time in their craft than large factories did, their industry began to decline and be replaced by industrial machines.

The rate constant of the first-order half-life reaction is 0.023 / sec or ln(2)/30 sec.

The formula for a first-order half-life reaction is t = (1/k) [ ln (initial concentration/final concentration)].

For determining the rate constant k, we can easily substitute the given t=30.0s to the formula. As for the initial and final concentration, we will be using 1/2 of the initial concentration as the final concentration. With this, the ratio of initial and final concentration would be equal to 1/(1/2) or 2. The exact value of the concentration is not important for this problem.

t= (1/k) * ln(2)

30.0 seconds = (1/k) * ln(2)

k = (ln (2)) / 30 seconds

k = ln (2) / 30 or 0.023/sec

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The partial pressures of ch4, n2, and o2 were found to be 155, 435, and 122 mmhg in a sample of gas. Metha has a mole fraction of 0.1610.

The definition of pressure is force applied per unit area. It can be calculated mathematically using P=FA, where F is the force acting perpendicular to surface area A. The pascal (Pa), or one newton per square meter (N/m 2), is the common unit of pressure.

In order to calculate pressure (P), divide the total force of all gas particle/wall collisions by the surface area of the wall. A fundamental measurable quality of this phase of matter, pressure is something that all gases produce.

The force applied physically to an object is referred to as pressure. Per unit area, the force is applied perpendicularly to the surfaces of the objects. The fundamental pressure formula is F/A. (Force per unit area). The Pascal unit of pressure (Pa). The four different types of pressure are gauge, absolute, atmospheric, and differential.

Pressure overall is 712 mmHg.

n2partial pressure is 435 mmHg.

n2mole fraction  = ?

Full pressure / partial pressure = mole fraction.

n2 mole fraction is = 435/712

n2 mole fraction is 0.6109

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Answer:

92.01 g/mol

Explanation:

So first you need to find the empirical formula by the percents. That would be, assuming that you have 100 grams of the the sample, divide each quantity of each element found by its respective molar mass.

30.4 g of N ÷ 14 g/mol N= 2.17 mol of N

69.6 g of O ÷ 16g/mol= 4.35 mol of O

You can establish now the empirical formula.

N2.17O4.35,

but since you can't have a decimal subscript, you divide each subscript by the minimum subscript

NO2

So then you're said that the molecular formula derived from that empirical formula has 2 nitrogen, so you multiply all the subscripts, by 2:

N2O4

-Dinitrogen Tetraoxide

-Nitrogen oxide (IV)

Then all you have to do is find the molecular mass of the compound using the periodic table and what you obtain is the molar mass.

remember: molecular mass is correspondent to molar mass.

Answer:

Critical thinking initiates the act of hypothesis.

Critital thinking initiates the hypothesis. By thinking you will come across a question you want to answer. In the conculsion crititcal thinking is used again to validate the hypothesis.

If the unknown solid were not dried before analysis, the calculated percent KHP would be too high. This is because the solid would contain some amount of water molecules, which would add to the mass of the solid.

Since the percent KHP is calculated as the mass of KHP divided by the total mass of the sample, including water molecules, the calculated percent KHP would be higher than the actual percent KHP.

During the titration process, water molecules could also react with KHP and cause a decrease in the concentration of KHP. This would lead to an underestimation of the true concentration of KHP, and as a result, the calculated percent KHP would be higher than the actual percent KHP.

Therefore, it is important to dry the unknown solid before analysis to remove any water molecules and ensure accurate results in the determination of percent KHP.

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The limiting reactant is H₂ because it has a lower yield. The correct option is A.

Limiting reactants in a reaction are the reactants that are used up in a given reaction in the presence of excess reactants.

Limiting reactants determine the amount of a product that can be formed in a reaction.

Limiting reactants result in the formation of the smallest amount of a product in a reaction.

Considering the given equation of reaction:

N₂ + 3 H₂ → 2 NH₃

The mole ratio of the reactants in the reaction is 1 : 3 for nitrogen and hydrogen.

10.1 g N₂ produces 0.72 moles NH₃.

1.2 g H₂ produces 0.39 moles NH₃.

The least amount of product that is formed is from hydrogen. Hence, hydrogen is the limiting reactant.

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Answer: Wowwwww

Explanation:yes

If the salt thermally decomposes, yielding a volatile product, then the reported percent water in the original sample may be affected.

This is because the water content in the sample may be overestimated due to the presence of the volatile product, which may also be driven off during the heating process. As a result, the reported percent water may be higher than the actual value.

In order to accurately determine the water content of the original sample, the volatile product must be accounted for in the analysis. This can be done by measuring the mass loss of the sample during the heating process, taking into account the mass of the volatile product that is released. Alternatively, the volatile product can be captured and weighed separately, allowing for the accurate determination of the water content in the original sample.

It is important to note that the effect of the volatile product on the reported percent water will depend on the amount and volatility of the product, as well as the analytical method used for determining the water content. Careful consideration and validation of the analytical method is therefore important when analyzing samples that may yield volatile products during thermal decomposition.

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 The coefficient tells you how many molecules of that substance there is. 

Answer:

The Milky Way

Explanation:

Answer:

The Milky Way

Explanation:

Jess set up an experiment to test the outcomes of different potting soils protected with paper mulch on bean plants: An test changed into set up to test the hypothesis that every one plants will develop faster in a "first rate soil" versus ordinary potting soil. A based variable is a variable being examined in a scientific test.

An experiment is a manner executed to support or refute a speculation or determine the efficacy or likelihood of something previously untried. Experiments offer insight into cause-and-impact by way of demonstrating what final results take place when a specific element is manipulated.

An experiment is an investigation in which speculation is scientifically tested. The test manipulates a biasing variable (motive) and measures a fixed variable (effect). All external variables are controlled. The bonus is that the experiment should be the goal. Experiments can provide clues about the form or mathematical form of a principle, as well as provide evidence about the lifestyle of the individuals considered in our theory.

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Answer:

calcium is the correct answer to the question

Answer: Physics is about

how things move and why things move

Explanation:

Answer:

They breathe

Explanation: